The maximum height of the pumpkin is 5.0 m.
The derivative of a function (its slope) is zero at maxima and minima of the function. This means that in order to find the horizontal position of the pumpkin where its height is at a maximum, we need to find the value of x that makes the derivative of the function y(x) equal to zero.
The derivative of y(x) is given by:
dy/dx = a
Substituting the value of a = -8.0 x 10 m, we get:
dy/dx = -8.0 x 10
Setting this derivative equal to zero, we get:
-8.0 x 10 = 0
This equation has no solution, which means that there is no horizontal position where the height of the pumpkin is at a maximum. Instead, the maximum height is achieved at the point where the pumpkin reaches its maximum vertical position, which occurs when x = -b/2a. Substituting the values of a and b, we get:
x = -1.0 / (-16.0 x 10) = 6.25 x 10^-2 m
To find the maximum height, we substitute this value of x into the original equation for y(x):
y(6.25 x 10^-2 m) = -8.0 x 10 m x 6.25 x 10^-2 m + 1.0 = 5.0 m
Therefore, the maximum height of the pumpkin is 5.0 m.
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So if any of ya got like, screenshots of all the answers for Edge, 2020. Lab-Kinetic Energy-student guide, That would be really helpful. If you could help me, then I will mark you brainliest. And for you trollers out there who just want the points, could you not steal them for this one? Anyways, thanks ya'll!
Answer:
has any one finished the lab yet?????
Explanation:
Using a _____ microscope, cells appear as translucent objects against a bright background
Cells can be observed under a brightfield microscope as translucent objects against a vivid background.
By translucent items, what do you mean?Objects that are translucent allow some light to pass through them. Translucent materials include certain polymers and frosted glass. Only a portion of the light that strikes transparent materials goes through. It takes the materials some time for the light to flow through them. Waxed paper, thin plastic sheets, butter paper, and vegetable oil are a few examples of translucent materials. This mnemonic should help you remember when to use transparent because transparent objects are clear and light may readily pass through them. The thing would be translucent if light still enters it, but it is less noticeable. An opaque object is one through which no light can flow.
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A 28 cm hammer is used to pull a nail. If 28.5N of force is
applied to it at a 65° angle, how much torque is applied?
Answer:
7.23 Nm
Explanation:
What net force is required to horizontally accelerate a 90 kg person from rest to 66 m/s in
1.3?
The net force required to horizontally accelerate a 90 kg person from rest to 66 m/s is 4596.3 N.
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector quantities. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Given;
mass = 90 kg
initial velocity = 0
final velocity = 66 m/s
time = 1.3 sec
V = u + at
66 = 0 + a × 1.3
a = 66/1.3
a = 50.77 m/s²
F = ma
= 90 × 50.77 N
= 4596.3 N
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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The Aswan High Dam on the Nile River in Egypt is 111 m high. What is the gauge pressure in the water at the foot of the dam
The gauge pressure in the water at the foot of the dam is 1.09 * 10^6 Pa.
Pressure is a measure of the force exerted per unit area on the boundaries of a substance. The standard unit for pressure in the SI system is the Newton per square meter or pascal (Pa)The pressure of a fluid of density ρ, at a depth h is:
p = ρ.g.h
Where g is the acceleration due to gravity.
h is height = 111 m,
the fluid is water so its density is ρ = 1000 kg/m³ and
we can use for the gravity g = 9.8 m/s².
The pressure at the foot of the dam is: p = 1000 * 111 * 9.8 = 1.09* 10^6 Pa
When pressure is measured relative to atmospheric pressure (14.7 psi), it is called gauge pressure (psig). The term gauge pressure is applied when the pressure is greater than the atmospheric pressure, patm.To know more about pressure visit:
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A metal rod 800mm long is heated from 10°C to 95°C.If it expands by 1.36mm,the linear expansivity of the metal is?
Answer:
2 x 10^(-5)
Explanation:
The linear expansivity α can be calculated using the following equation:
\(\Delta L=\alpha\cdot\Delta T\cdot L\)Where ΔL is the change in length, ΔT is the change in temperature and L is the original length of the metal. So, replacing the values, we get:
\(\begin{gathered} 1.36=\alpha(95-10)(800) \\ 1.36=\alpha(85)(800) \end{gathered}\)Then, solving for α, we get:
\(\begin{gathered} 1.36=\alpha(68000) \\ \frac{1.36}{68000}=\frac{\alpha(68000)}{68000} \\ 2\times10^{-5}=\alpha \end{gathered}\)Therefore, the linear expansivity of the metal is 2 x 10^(-5)
the diagram below represents the orbits of earth, comet temple-tuttle, and planet x, another planet in out solar system. arrows on each orbit represent the direction of movement. which objects orbit would have and eccentricity close to 1?
Answer:
the most elliptical orbit is that of COMETA
Explanation:
The eccentricity of a curve in defined as the ratio between lacia to the focus, called c and the value of the axis greater than
ε = c / a
if we use Pythagoras' theorem
c = \(\sqrt{a^2 - b^2}\)
substituting
ε = \(\sqrt{1 - (b/a)^2 }\)
if ε = 0 we have a circumference
In the diagram presented the orbit of the comet is an ellipse a> b
ε=\(\sqrt{1- x} \\ x = (\frac{b}{a} )^2\)
if we expand in series
ε = 1 - x/2
ε= \(1 - \frac{1}{2} \ (\frac{ b}{a} )^2\)
if we neglect the non-linear terms
ε = 1
Earth's orbit is a small ellipse
b / a = 149 10⁶ / 151 10⁶
b / a = 0.98675
ε = \(\sqrt{1- 0.98675^2}\)
ε = 0.16
a very small ellipse
Planet X, despite not having data, it seems that the sun is in the scepter of the orbit, so b = a
therefore both the semi-axes of the curve
e = a / b
Consequently, the most elliptical orbit is that of COMETA.
name 1 newton’s law and explain how airbags/seatbelts are important in saving lives.
One of Newton's laws is the law of inertia, which states that an object at rest will remain at rest, and an object in motion will remain in motion unless acted upon by an external force.
Airbags and seatbelts are important in saving lives because they act as the external force that can stop the motion of an object in the event of a collision. Without these safety measures, the body would continue to move forward at the same speed as the vehicle, causing serious injuries or even death upon impact. By quickly inflating and creating a cushion, airbags reduce the force of impact and prevent the head and chest from hitting hard surfaces inside the car. Seatbelts, on the other hand, prevent passengers from being thrown out of the car or hitting the dashboard or windshield.
Seatbelts restrain this motion, while airbags provide a cushion to reduce the impact force. Both safety features work together to prevent injuries and save lives.
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Suppose high tide is at midnight, the water level at midnight is 3 m, and the water level at low tide is 0.5 m. Assuming the next high tide will occur 12 hours later (at noon), find the time, to the nearest minute, when the water level is at 1.125 m for the second time after midnight.
We have that the time, to the nearest minute, when the water level is at 1.125 m for the second time after midnight is
\(t=10.0hours\)
From the Question we are told that
Maximum height \(h_{max}=3m\)
Minimum height \(H_{min}=0.5m\)
Time for next high tide will occur\(T=12 hours =>720 min\)
Generally Average Height
\(h_{avg}=\frac{3+0.5}{2}\\\\h_{avg}=1.75\)
Therefore determine Amplitude to be
\(A=h_{max}=j_{avg}\\\\A=3-1.75\\\\A=1.25\)
Generally, the equation for Time is mathematically given by
At t=0
\(h(x)=Acos(Bx)+h_{avg}\)
Where
\(B=\frac{2\pi}{P}\\\\B=\frac{2\pi}{720}\\\\B=8.73*10^{-3}\)
Therefore
\(h(t)=Acos8.73*10^{-3}(t)+h_{avg}\)
Hence the Time at \(T=1.125\) is
\(1.125(t)=1.25cos(8.73*10^{-3})(t)+1.75\)
\(-0.1249t=1.75\)
\(t=10.0hours\)
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What is the acceleration of a 50kg object pushed with a force of 500 newtons?
Answer:
10
Explanation:
Acceleration = Force / Mass
500 N / 50 Kg = 10
Which element forms the skeleton of this polymer? O carbon O copper O hydrogen O oxygen
Answer:
its carbon
Explanation:
I'm doing to questions right now
Answer:
Carbon
Explanation:
Got it right on edg
a young boy with a broken leg is undergoing traction. assuming the weight of the leg is 27.7 n and the weight hanging from the traction apparatus is also 27.7 n, what is the magnitude of the force exerted on the femur by the lower leg?
The magnitude of the force exerted on the femur by the lower leg while undergoing traction is 55.4 N
The magnitude of the force exerted on the femur by the lower leg is equal to the sum of the weight of the leg and the weight hanging from the traction apparatus.
What is traction?Traction is a treatment method in which a patient's limb is pulled by weights and pulleys to stretch and strengthen the soft tissues and joint structures around the bone. Traction may be used to treat broken bones, dislocated joints, or muscle or ligament strains.
The weight of the leg = 27.7 N
The weight hanging from the traction apparatus = 27.7 N
The magnitude of the force exerted on the femur by the lower leg
= Weight of the leg + Weight hanging from the traction apparatus
= 27.7 N + 27.7 N= 55.4 N
Therefore, the magnitude of the force exerted is 55.4 N.
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A rope exerts a 35N force on an object at an angle of 12N degrees above the horizontal. What horizontal and vertical components of the force?
Answer:
The horizontal component of the force, \(F_x= 34.24 \ N\)
The vertical component of the force, \(F_y=7.28 \ N\)
Explanation:
Given;
Force on the rope, F = 35 N
angle between the rope and the horizontal = 12 °
The horizontal component of the force is given by;
\(F_x = Fcos \theta\\\\F_x = 35cos(12^0)\\\\F_x = 34.24 \ N\)
The vertical component of the force is given by;
\(F_y = Fsin\theta\\\\F_y = 35sin(12^0)\\\\F_y = 7.28 \ N\)
a bucket weighing 100 n is supported by a rope. what is the force of tension in the rope when the bucket is accelerated upward at a rate of 3 m/s2?
There is a rope supporting a pail that weighs 100 N. the upward acceleration of the bucket's bucket causes tension to be applied to the rope.
What three things help the process move along more quickly?Average acceleration, non-uniform acceleration, and uniform acceleration are the three categories into which accelerated motions can be separated. when something starts moving straight and then starts accelerating in equal-interval steps.
What relationship does acceleration have to speed?In terms of velocity, the displacement change is quantified. Acceleration is a unit used to measure how quickly something changes speed. Velocity is an illustration of a vector quantity because it has a magnitude and a direction.
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The primary circuit of a transformer has a voltage of 80 V and 300 windings. The secondary circuit has a voltage of 240. How many windings are there in the secondary circuit? *
Answer:
900 windings
Explanation:
Applying,
Vs/Vp = Ns/Np............. Equation 1
Where Vs = Secondary voltage, Vp = primary voltage, Ns = Number of turns in the secondary circuit, Np = number of turns in the primary circuit
make Ns the subject of the equation
Ns = VsNp/Vp........... Equation 2
From the question,
Given: Vs = 240 V, Np = 300 windings, Vp = 80 V
Substitute these values into equation 2
Ns = (240×300)/80
Ns = 900 windings
Two friction less blocks, having masses of 8.0 kg and 2.0 kg, rest on a horizontal surface. If a force applied to the 8.0 kg block gives it an acceleration of 3.0 m/s2, then the same force will give the 2.0 kg block an acceleration of ________
The acceleration that is produced by the 2 Kg force is 12 m/s^2.
What is the force?We know that from the Newton first law, it is the magnitude of the force that is imparted to a body that produces the given acceleration. It is now safe to say that the force that is exerted on a body is directly proportional to the acceleration of the body. This is the fall out that we can take from the Newton law as stated above.
In this case, we have seen that the Two friction less blocks, having masses of 8.0 kg and 2.0 kg, rest on a horizontal surface.
Now;
F = ma
F = force
m = mass
a = acceleration
F = 8.0 kg * 3.0 m/s2
F = 24 N
We are told that the same force was applied to the 2 Kg mass
a = F/m
a = 24 N/2 Kg
a = 12 m/s^2
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what is the answer
to this question
What is the volume of a box that is 3 meters long, 0.5 meters high, and 2 meters wide?
Answer:
V = 3 m³
Explanation:
V = lwh
Step 1: Define
l = 3 m
h = 0.5 m
w = 2 m
Step 2: Substitute and Evaluate
V = 3(0.5)(2)
V = 1.5(2)
V = 3 m³
Answer: 3 meters^3
Explanation: 3*2*0.5=3
Some vehicles, like _____, have different rules for registration and renewal. A. trailers B. coupes C. sedans D. pickup trucks
Answer:
trailers
Explanation:
Some vehicles, like trailers, have different rules for registration and renewal
What is the registration process for trailers?Before registering a trailer, you will generally need to submit a signed title to verify your ownership. Alternately, you might be able to use a manufacturer’s statement of origin.
You will also need to sign and submit an application for the license and title of the trailer, along with receipts of applicable property taxes. Finally, you will need to pay the registration fees.
Before you make a trip to the DMV, make sure to have two forms of photo ID on hand to verify your identity when you speak with an agent. For example, your driver’s license might serve as the primary form of ID, and a passport could serve as the second.
If you do not have a passport, you could use a military identification card instead. If your only form of photo ID is your driver’s license, be sure to have other forms of identification on hand, such as your birth certificate and the card with your Social Security number.
Hence Some vehicles, like trailers, have different rules for registration and renewal.
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A system is at rest. The mass of each object is shown. Neglecting the mass of the strings, how many forces are acting on the 9 kg block?
A. There is 1 force.
B. There are 2 forces.
C. There are 3 forces.
D. There are 4 forces,
When the system is at rest, there are 2 forces acting on the 9 kg block.
Describe a force.An object experiences a push or pull as a result of interaction with another object. A force is exerted on each object when two of them come into contact. The newton, represented by the letter N, is the SI unit of force.
What different kinds of forces exist in physics?There are two different types of forces: contact forces and non-forces. A few examples of forces are nuclear force, gravitational force, frictional force, magnetic force, electrostatic force, spring force, and others.
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What is equilibrium?
Answer:
Balance is the ability to maintain body balance when placed in various positions.
----------------------------------------
\( \green{ \boxed{ \boxed{ \sf{Lusi \: Adriana} } } } \)
Hope it is Useful..Answer:
A state of physical balance.
I hope this helps you!!!
A thin wire was wound 30 times closely over a boiling tube .The total length of the windings was found to be 9.3 mm .Calculate the radius of the wire?
The radius of the wire is 0.0156 mm.
Radius of a wireTo calculate the radius of the wire, we need to use the following formula:
Total length of wire = (2 x π x r) x number of turns
where r is the radius of the wire.
Substituting the given values, we have:
9.3 mm = (2 x π x r) x 30r = 9.3 mm / (2 x π x 30) = 0.0156 mmTherefore, the radius of the wire is 0.0156 mm.
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how does the relatrinihip between temprature and destiny help to explain why the drop in pressure betweem 2 km and 4km was greater at fairbanks than at key west
The drop in pressure is greater at Fairbanks than at Key West between 2 km and 4 km. This can be explained by the relationship between temperature and density.
The relationship between temperature and density can be described as follows: as temperature increases, the density of a substance decreases. The same is true in reverse: as temperature decreases, the density of a substance increases. This relationship between temperature and density helps to explain why the drop in pressure between 2 km and 4 km was greater at Fairbanks than at Key West.
This is because Fairbanks is located in a colder climate than Key West. Therefore, the air is colder in Fairbanks than in Key West. Since the air in Fairbanks is colder, it is denser than the air in Key West. As a result, when the air in Fairbanks rises to a higher altitude, it expands and cools, causing it to become even denser. This increase in density results in a greater drop in pressure between 2 km and 4 km at Fairbanks than at Key West.
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long solenoid has a diameter of 12.0 cm.when a current i exists in its windings, a uniform magnetic field of magnitude b 30.0 mt is produced in its interior. by decreasing i, the field is caused to decrease at the rate of 6.50 mt/s. calculate the magnitude of the induced electric field (a) 2.20 cm and (b) 8.20 cm from the axis of the solenoid.
a) Point at which we are evaluating field is inside the solenoid = 7.15 *10^-5 V/m b)point at which we are evaluating field is outside the solenoid ; E = 1.43 *10^-4 V/m.
What is solenoid?A solenoid is a type of electromagnet formed by helical coil of wire whose length is greater than its diameter and which generates a controlled magnetic field.
a) Point at which we are evaluating field is inside the solenoid,
E= r/2 * (dB/dt)
= 1/2 * (dB/dt)*0.022) r
= 1/2* (6.5 *10^-3 T/s) * ( 0.022m)
E = 7.15 *10^-5 V/m
b) point at which we are evaluating field is outside the solenoid ;
E= R²/2r *(dB/dt)
= 1/2 * dB/dt * R²/r
= 1/2* (6.5 *10^-3 T/s) *(0.060/0/0.082)
E = 1.43 *10^-4 V/m.
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Student A states that when she sits down on a chair, she is exerting a force on the chair and that is all that happens. Student B states that when she sits on a chair, the chair is actually exerting a force back on her in reaction to her force exerted upon the chair. Which student is correct and why?
A.
Student A is correct because Newton’s 1st Law of Motion states that if the chair exerted a force on the student, her motion would change.
B.
Student A is correct because Newton’s 3rd Law of Motion states that for every action there is an equal and opposite action and the chair does not show any action.
C.
Student B is correct because Newton’s 1st Law of Motion states that if the chair were to be exerting a force on the student, her motion would change.
D.
Student B is correct because Newton’s 3rd Law of Motion states that for every action there is an equal and opposite action and the chair’s action counteracts the student’s so that neither move.
Answer:
C
Explanation:
I got it right on the test !!
The student that is correct is C. Student B is correct because Newton’s 1st Law of Motion states that if the chair were to be exerting a force on the student, her motion would change.
According to Newton's third law of motion, there's an equal and opposite reaction force for every action force. It should be noted that when an individual sits on a chair, the chair is actually exerting a force back on her in reaction to the force exerted upon the chair.
Student A is incorrect because when she sits down on a chair, the force that she's exerting on the chair is not the only thing that happens because the chair exerts a force back. Therefore, as the chair were to be exerting a force on the student, her motion would change.
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Four forces are acting on an object. Force A is 50 N up. Force B is 30 N down. Force C is 25 N up, and Force D is 10 N
down. What is the net force on the object?
Answer:
The net force on the object is 35 N directed up.
Explanation:
Net Force
The force is a vector because it has magnitude and direction. The net force is the sum of all the individual forces acting on an object.
Let's assume the forces directed upward are positive and the forces directed down are negative.
Force A: +50 N
Force B: -30 N
Force C: +25 N
Force D: -10 N
Net Force= 50 - 30 + 25 - 10 = 35 N
The net force on the object is 35 N directed up.
A corona is a circle of light that can be seen around the Moon during a solar eclipse.
O True
False
When the Moon orbits Earth, what is the centripetal force?
A. Nuclear force
B. Air resistance
C. Gravity
O O
D. Friction
Answer:
Gravity is the centripetal force when the moon orbits the earth.
Match the volcano type with its correct plate tectonic setting Cinder Cone Composite (Stratovolcano) Shield Volcano Large Igneous Provinces (LIPS) Seafloor Volcanism Question 24 [Choose ] [Choose ] [Choose ] [Choose ] [Choose ] [Choose ] Mostly Spreading Ridges, some Mantle Plumes Super mantle plumes Various tectonic settings Subduction Zones (Convergent Margins) Mostly Mantle Plumes, some Spreading Ridges Match the volcano type with its correct magma composition Cinder Cone Composite/Stratovolcano Shield Volcano Large Igneous Provinces (LIPs) Seafloor Volcanism [Choose ] [Choose ] Mafic Intermediate, varies from felsic to mafic Pillow Lava, Mafic [Choose ] [Choose ] [Choose ]
Match the volcano type with its correct
1. Cinder Cone:
Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes
2. Composite/Stratovolcano:
Plate Tectonic Setting: Subduction Zones (Convergent Margins)
3. Shield Volcano:
Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges
4. Large Igneous Provinces (LIPs):
Plate Tectonic Setting: Various tectonic settings
Volcano types can be associated with specific plate tectonic settings and magma compositions. Let's match the volcano types with their correct plate tectonic settings and magma compositions:
1. Cinder Cone:
Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes
Magma Composition: Mafic
Cinder cones are typically small, steep-sided volcanoes that form from the eruption of basaltic magma. They are commonly found in volcanic regions associated with spreading ridges, where tectonic plates are moving apart, or in areas influenced by mantle plumes, such as hotspot volcanism.
2. Composite/Stratovolcano:
Plate Tectonic Setting: Subduction Zones (Convergent Margins)
Magma Composition: Intermediate, varies from felsic to mafic
Composite or stratovolcanoes are characterized by their steep slopes and alternating layers of lava flows and pyroclastic materials. They are commonly found in subduction zones, where an oceanic plate is being subducted beneath continental plate. The magma composition of these volcanoes varies, ranging from felsic (high silica content) to mafic (lower silica content).
3. Shield Volcano:
Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges
Magma Composition: Mafic
Shield volcanoes are large, broad, and gently sloping volcanoes that form from the eruption of basaltic magma. They are often associated with mantle plumes, such as those found in hotspot regions, as well as in volcanic areas influenced by spreading ridges.
4. Large Igneous Provinces (LIPs):
Plate Tectonic Setting: Various tectonic settings
Magma Composition: Mafic
Large Igneous Provinces (LIPs) are extensive regions of volcanic and intrusive rock formations that are associated with massive outpourings of mafic magma. They can occur in various tectonic settings, including continental rifts, hotspot regions, and flood basalt provinces.
5. Seafloor Volcanism, Pillow Lava:
Plate Tectonic Setting: Mostly Spreading Ridges
Magma Composition: Mafic
Seafloor volcanism is primarily associated with spreading ridges, where magma wells up and creates new oceanic crust. The lava erupted underwater cools rapidly, forming pillow-shaped structures known as pillow lavas. The magma composition is typically mafic, dominated by basaltic lavas.
These associations between volcano types, plate tectonic settings, and magma compositions provide insights into the geological processes and Earth's dynamics that shape the Earth's surface.
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A 0.0500-kg ice cube at −30.0ºC is placed in 0.400 kg of 35.0ºC water in a very well-insulated container. What is the final temperature?
The amount of heat that is gained by water is equal to the amount of heat loss by the ice. Therefore, we have the following relationship:
\(-Q_w=Q_i\)Where "Qw" is the heat of water and "Qi" is the heat of ice. The heat of water is given by:
\(Q_w=m_wC_w(T_f-T_{0w})\)The amount of heat of ice must be calculated for the two states, solid and liquid. For the solid-state the temperature will be from -30 degrees to 0 degrees, therefore, we have:
\(Q_i=m_iC_i(T_f-T_{0i})\)Where Ci is the specific heat of ice in solid-state and is equal to:
\(C_i=2090\frac{kJ}{\operatorname{kg}}\)Replacing the values:
\(Q_i=(0.05\operatorname{kg})(2090\frac{kJ}{\operatorname{kg}K})(0-(-30C))\)Solving the operations we get:
\(Q_i=3135J\)Now we need to determine the amount of heat that needs the ice to convert into liquid. This is given by:
\(Q_{i-l}=m_iL_f\)Lf is the latent heat of ice and is equal to:
\(L_f=334\frac{kJ}{\operatorname{kg}}\)Replacing the values we get:
\(Q_{i-l}=(0.05\operatorname{kg})(334\frac{kJ}{\operatorname{kg}})\)Solving the operations:
\(Q_{i-l}=16.7kJ=16700J\)Now we need the amount of heat of liquid ice to its final temperature, this is given by:
\(Q_l=m_iC_l(T_f-0)\)Applying the relationship:
\(-m_wC_w(T_f-T_{0w})=m_iC_i(T_f-T_{0i})+m_iL_f+m_iC_w(T_f-0)\)Cw is the specific heat of water and is equal to:
\(C_w=4184\frac{J}{\operatorname{kg}K}\)And the specific heat of ice is:
\(C_i=4184\frac{J}{\operatorname{kg}K}\)Replacing the values. The first two terms on the right side we already calculated and the final temperature is the same for both:
\(-(0.4\operatorname{kg})(4184\frac{kJ}{\operatorname{kg}K})(T_f-35)=3135J+16700J+(0.05)(4184\frac{kJ}{\operatorname{kg}K})(T_f)\)Solving operations:
\(-1673.6\frac{kJ}{K}(T_f-35)=19835J+209.2\frac{kJ}{K}T_f\)Now we solve for the final temperature:
\(-1673.6T_f+58576=19835+209.2T_f\)Subtracting 19835 to both sideS:
\(\begin{gathered} -1673.6T_f+58576-19835=209.2T_f \\ -1673.6T_f+38741=209.2T_f \end{gathered}\)Now we add 1673Tf to both sides:
\(\begin{gathered} 38741=209.2T_f+1673.6T_f \\ 38741=1882.8T_f \end{gathered}\)Now we divide both sides by 1882.2
\(\frac{38741}{1882.8}=T_f\)\(20.57=T_f\)Therefore, the final temperature is 20.57 °C. This value can be converted into Kelvin using the following relationship:
\(T_K=T_C+273.15\)Replacing the temperature:
\(T_K=20.57+273.15=293.72\)Therefore, the final temperature is 293.72 K.