Answer:
22.3 work is left to be done
2.4 work are done
A cat runs along a straight line (the x-axis) from point A to point B to point C, as shown in the figure. The distance between points A and C is 5.00 m, the distance between points B and C is 10.0 m, and the positive direction of the x-axis points to the right. The time to run from A to B is 20.0 s, and the time from B to C is 8.00 s. As the cat runs along the x-axis between points A and C. What is the magnitude of its average velocity?
The cat travels with an average speed to the right of 0.179 m/s.
How can you calculate the separation between the following locations and the x-axis?Simply add up the squares of the other two coordinates to determine the distance between any point and an axis, and then square root the result. We square the y- and z-coordinates, discover their sum, and then square root our result to determine the distance from the x-axis.
The total time elapsed is the sum of the time to run from A to B and the time to run from B to C, which is:
total time = 20.0 s + 8.00 s = 28.0 s
The average velocity is defined as the displacement divided by the elapsed time, so we have:
average velocity = displacement / elapsed time
average velocity = 5.00 m / 28.0 s
average velocity = 0.179 m/s.
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The same type of engine is placed in 2 different planes
Answer:
you didnt finish the question but im guessing the answer is matters what each airplane is built out of even though they have the same engine they will perfrom diffrently depending on the material their made out of.
Light of wavelength 519 nm passes through two slits. In the interference pattern on a screen 4.6 m away, adjacent bright fringes are separated by 4.0 mm. What is the separation of the two slits
Answer:
The appropriate solution is "0.597 mm".
Explanation:
Given that:
Wavelength,
\(\lambda = 519 \ nm\)
or,
\(=519\times 10^{-9}\)
Distance,
\(D=4.6 \ m\)
Separated by,
\(\beta = 4.0 \ mm\)
or,
\(=4.0\times 10^{-3}\)
As we know,
⇒ \(\beta=\frac{\lambda D}{d}\)
or,
The separation of two slits will be:
⇒ \(d=\frac{\lambda D}{\beta}\)
By putting the values, we get
\(=\frac{(519\times 10^{-9})(4.6)}{4.0\times 10^{-3}}\)
\(=5.97\times 10^{-4}\)
or,
\(=0.597 \ mm\)
A rocket fires two engines simultaneously. One produces a thrust of 725Ndirectly forward while the other gives a 513N thrust at 32.4° above the forward direction. Find the magnitude and direction (relative to the forward direction) of the resultant force which these engines exert on the rocket.
The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.
What is the resultant force the two engines exert on the rocket?The resultant force on the rocket is calculated thus:
The 513N thrust is resolved into vertical and horizontal components;
Horizontal component: 513N cos(32.4°) = 433.14 N
Vertical component: 513N sin(32.4°) = 274.88 N
Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N
Total force at right angles:
0 + 274.88 N = 274.88 N
The resultant force (F) is then given as follows:
F² = a² + b²
F² = (1158.14 N)² + (274.88 N)²
F = √1,416,847.27
F = 1,190.3
To find the direction:
tan X 274.88 N / 1,158.14 N
X = tan⁻¹ 0.237346089419241
X = 13.35°
Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.
In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.
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report of "fan made of plastic bottle" with string
Fan made of plastic bottle is an innovative way to reuse plastic bottles and can be easily made at home. This can be done by following simple steps, and a few materials are required to make it. The fan can be created by using a plastic bottle, scissors, string, a ruler, and a marker.
First, the bottle needs to be cut into half, and the upper part needs to be cut into three equal sections, then fold each section to make a blade. With the help of a ruler and marker, make a mark on each section, then make a hole in the center of each blade. Insert a string through the holes and tie the ends of the strings. The fan is ready to use by holding the string and swinging it back and forth.
The use of plastic bottle fans can significantly reduce the number of plastic waste and provide a practical solution to avoid environmental pollution. Besides, it is easy to make, and the materials are readily available, which can be used for various occasions, such as picnics, camping, or any outdoor activities.
In conclusion, the creation of a fan made of plastic bottle with string is an excellent way to reuse plastic bottles and can be made with simple steps. This project encourages everyone to contribute to environmental protection by utilizing what is available at home and reducing the number of plastic wastes.
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On a still water, a speedboat decreases its speed uniformly from 30 m/s to 20 m/s. How long does it take the boat to travel a distance of 200m?
a. -8 s
b. 8 s
c. -200 s
d. 200 s
Answer:
t=8
Explanation:
u have solution I give solution also
don't mark plzz follow y
QUESTION 3 (Start on a new page.)
A small disc, C, is thrown vertically upwards at a speed of 15 m-s¹ from the edge of
the roof of a building of height 30 m. AFTER 0,5 s, a small ball B is shot vertically
upwards from the foot of the building at a speed of 40 m-s in order to hit disc C.
Ignore the effects of air resistance.
3.1
3.2
3.3
15 m-s¹
30 m
Explain the term projectile.
Calculate the:
40 m-s¹
B
3.2.1
Time taken by disc C to reach its maximum height
3.2.2
Maximum height above the ground reached by disc C
Calculate the time from the moment that disc C was thrown upwards until
the time ball B hits the disc..
(2)
(3)
(4)
(6)
A projectile is an object thrown into the air and subject only to gravity and, if applicable, air resistance. The time taken by disc C to reach its maximum height is approximately 1.53 seconds, and its maximum height above the ground is around 11.48 meters. The time from when disc C was thrown upwards until ball B hits the disc is roughly 1.29 seconds.
3.1 Explanation of the term projectile:
A projectile refers to an object that is launched or thrown into the air and is subject only to the forces of gravity and air resistance (if applicable). The motion of a projectile can be analyzed independently of its mass, shape, or any other physical property. The key characteristic of a projectile is that it follows a curved path known as a trajectory.
When a projectile is launched, it moves along a parabolic trajectory due to the combination of its initial velocity and the force of gravity acting vertically downward. The horizontal motion of a projectile remains constant and unaffected by gravity, while the vertical motion is influenced by the acceleration due to gravity.
The path of a projectile can be described mathematically by considering its initial velocity, angle of projection, and the acceleration due to gravity. Projectile motion finds applications in various fields, such as sports, engineering, and physics, where objects are launched or thrown.
3.2.1 Time taken by disc C to reach its maximum height:
To determine the time taken by disc C to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:
vf = vi + at
Where:
vf = final velocity (which is zero at the maximum height)
vi = initial velocity
a = acceleration (in this case, acceleration due to gravity, -9.8 m/s²)
t = time
Since the disc is thrown vertically upwards, its initial velocity is 15 m/s. We want to find the time it takes for the disc to reach its maximum height, so we'll use the equation and solve for time (t):
0 = 15 + (-9.8)t
Rearranging the equation, we get:
9.8t = 15
t = 15 / 9.8
Calculating this, we find:
t ≈ 1.53 seconds
Therefore, it takes approximately 1.53 seconds for disc C to reach its maximum height.
3.2.2 Maximum height above the ground reached by disc C:
To determine the maximum height reached by disc C, we can use another kinematic equation for vertical motion:
vf² = vi² + 2ad
Where:
vf = final velocity (which is zero at the maximum height)
vi = initial velocity
a = acceleration (in this case, acceleration due to gravity, -9.8 m/s²)
d = displacement (maximum height)
Since we know the initial velocity (vi) and acceleration (a), we can solve for the displacement (d), which represents the maximum height:
0² = 15² + 2(-9.8)d
Rearranging the equation, we get:
0 = 225 - 19.6d
19.6d = 225
d = 225 / 19.6
Calculating this, we find:
d ≈ 11.48 meters
Therefore, the disc C reaches a maximum height of approximately 11.48 meters above the ground.
Calculating the time from the moment that disc C was thrown upwards until the time ball B hits the disc:
To find the time it takes for ball B to hit disc C, we need to calculate the time it takes for both objects to reach the same height.
Since disc C was thrown upwards from the edge of the roof and ball B was shot vertically upwards from the foot of the building, we need to consider the additional height of the building (30 meters).
The time it takes for disc C to reach the ground is the same as the time it takes for ball B to reach a height of 30 meters above the ground.
Using the kinematic equation for vertical motion, we can calculate the time for ball B:
d = vit + 0.5at²
Where:
d = displacement (30 meters)
vi = initial velocity (40 m/s)
a = acceleration (acceleration due to gravity, -9.8 m/s²)
t = time
30 = 40t + 0.5(-9.8)t²
Rearranging the equation, we get:
4.9t² + 40t - 30 = 0
Solving this quadratic equation, we find:
t ≈ 1.29 seconds or t ≈ -5.82 seconds
Since time cannot be negative in this context, we discard the negative solution.
Therefore, it takes approximately 1.29 seconds from the moment that disc C was thrown upwards until ball B hits the disc.
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Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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a girl pushes an 18.15 kg wagon with a force of 3.63 N. what is the acceleration?
A. 0.06 m/s2
B. 5 m/s2
C. 0.2 m/s2
Answer:0.2 m/s^2
Explanation:
mass=18.15kg
Force=3.63N
Acceleration=force ➗ mass
Acceleration=3.63 ➗ 18.15
Acceleration=0.2 m/s^2
A girl pushes a wagon of mass 18.15 kg with a force of 3.63 N, so the acceleration of the wagon will be 0.2 m/s².
What is acceleration?In mechanics, acceleration is the measure of how rapidly an object's velocity changes over time. Accelerations as a vector quantity. An object's acceleration depends on the direction of the net force exerted on it.
A vector quantity, acceleration, is something that has both a magnitude and a direction. As a vector quantity, velocity is also. The ratio of the velocity vector change over a time interval to that interval is the definition of acceleration.
Mass, m =18.15 kg
Force, f = 3.63 N
Force = m × a
a= f / m
a =3.63 / 18.15
a = 0.2 m/s²
Hence, the acceleration of the wagon will be 0.2 m/s².
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What is the average velocity of a car that travels 12 kilometers in 0.20 hours?
Answer:
60 km/hr
Explanation:
Looking for km / hr
12 km / (.20 hr) = 60 km/hr
Which processes result in the release of carbon? Select three options.
Animals break down food molecules to obtain energy.
The remains of producers are broken down by decomposers.
The remains of consumers are broken down by soil decomposers.
Producers take in carbon dioxide.
Producers make sugars and starches.
Answer:
The remains of producers are broken down by decomposers.
The remains of consumers are broken down by soil decomposers.
Animals break down food molecules to obtain energy.
Explanation:
Answer:
It is A. B. and C.
Explanation:
Hope this helps
A 28-g rifle bullet traveling at 300 m/s embeds itself in a3.1-kg pendulum hanging on a 2.8-m-long string, whichmakes the pendulum swing upward in an arc. Determinethe vertical components of the pendulum’smaximum displacement.
Given:
The mass of the bullet, m=28 g=0.028 kg
The speed of the bullet, v=300 m/s
The mass of the pendulum, M=3.1 kg
The length of the string, l=2.8 m
To find:
The vertical component of the pendulum's maximum displacement.
Explanation:
The law of conservation of energy states that energy can neither be created nor be destroyed. Thus the kinetic energy of the bullet will be transferred into the kinetic energy of the bullet and the pendulum. Which will be converted into its potential energy when it reaches the maximum height, i.e, the vertical component of its maximum displacement.
Thus,
\(\frac{1}{2}mv^2=(m+M)gh\)Where g is the acceleration due to gravity and h is the vertical component of the pendulum's maximum displacement.
On rearranging the above equation,
\(h=\frac{mv^2}{2(m+M)g}\)On substituting the known values,
\(\begin{gathered} h=\frac{0.028\times300^2}{2(0.028+3.1)\times9.8} \\ =41.1\text{ m} \end{gathered}\)Final answer:
Thus the vertical component of the maximum displacement of the pendulum is 41.1 m
A child blows a leaf from rest straight up in the air. the leaf has a constant upward acceleration of magnitude 1.0 m by s square. how much time does it take the leaf to displace 1.0m upwards?
Answer:
√2
Explanation:
From the question, we're given that the
Acceleration of the leaf is 1 m/s²
Change in displacement of the leaf is 1 m/s.
Again, from the question, we can tell that the initial velocity u = 0, since the object starts at rest
Now, to solve this, we don't the equation of motion to ur
S = ut + 1/2at², substituting the whole parameters, we then have
1 = 0 * t + 1/2 * 1 * t²
1 = 1/2 * t²
t²/2 = 1
t² = 2
t = √2 seconds
Therefore the time it takes the leaf to dislodge is 2 seconds
PLEASE HELP ME WITH THIS ONE QUESTION
What is the rest energy of a proton? (c = 2.9979 x 10^9 m/s, mp = 1.6726 x 10^-27)
Answer:
Energy = 1.5032*10^(-10) Joules
Explanation:
By Einstein's relativistic energy equation, we know that the energy of a given particle is given by:
Energy = rest energy + kinetic energy.
= m*c^2 + (γ - 1)*mc^2
Where γ depends on the velocity of the particle.
But if the proton is at rest, then the kinetic energy is zero, and γ = 1
Then the energy is just given by:
Energy = m*c^2
Where we know that:
mass of a proton = 1.67*10^(-27) kg
speed of light = c = 2.9979*10^(8) m/s
Replacing these in the energy equation, we get:
Energy = ( 1.6726*10^(-27) kg)*( 2.9979*10^(8) m/s)^2
Energy = 1.5032*10^(-10) kg*m^2/s^2
Energy = 1.5032*10^(-10) J
A car is driving 12m/sec, has to stop suddenly because a pedestrian dashes out in front of the car. If the coefficient of kinetic friction between the tires and parking lot is ∪=60
what is the time, after the breaks are applied, before the car comes to a stop? Sketch the velocity time graph for the car's motion from the instant the breaks are applied until the car comes to a stop.
Answer:
Approximately \(2\; \rm s\), assuming that the floor of this parking lot is level, \(\mu_{\rm k} = 0.60\), and \(g = 9.81\; \rm m\cdot s^{-2}\).
Explanation:
Let \(m\) denote the mass of this vehicle. Weight of this vehicle: \(m\, g\).
If the floor of this parking lot is level, the normal force on this vehicle would be equal to its weight: \(N = m \, g\).
Given that \(\mu_{\rm k}\), the kinetic friction between this vehicle and the ground would be consistently \(\mu_{\rm k} \, N = \mu_{\rm k} \, m \, g\) until the vehicle comes to a stop.
Assuming that all forces on this vehicle other than friction are balanced. The net force of this vehicle during braking would be \((-\mu_{\rm k} \, m \, g)\) (negative because this force is opposite to the direction of the motion.)
By Newton's second law of motion, the acceleration of this vehicle would be:
\(\begin{aligned}a &= \frac{F_\text{net}}{m} \\ &= \frac{-\mu_{\rm k} \, m \, g}{m} \\ &= -\mu_{\rm k}\, g \\ &= -0.60 \times 9.81\; \rm m\cdot s^{-2} \\ &= -5.886\; \rm m\cdot s^{-2}\end{aligned}\).
In other words, braking would reduce the velocity of this vehicle by a constant \(5.886\; \rm m\cdot s^{-1}\) every second until the vehicle comes to a stop. Calculate the time it would take to reduce the velocity of this vehicle from \(v_{0} = 12\; \rm m\cdot s^{-1}\) to \(v_{1} = 0\; \rm m\cdot s^{-1}\):
\(\begin{aligned}t &= \frac{v_{1} - v_{0}}{a} \\ &= \frac{0\; \rm m\cdot s^{-1} - 12\; \rm m\cdot s^{-1}}{-5.886\; \rm m \cdot s^{-2}} \\ &\approx 2.0\; \rm s \end{aligned}\).
Acceleration is the slope of the velocity-time graph. Since the acceleration here is constant, the velocity-time graph of this vehicle would be a line with a negative slope.
A 0.060 kg tennis ball moving with the speed of 2.50 m/s, collides head-on with a 0.090 kg ball initially moving away from it at a speed of 1.15 m/s. Assuming a perfectly inelastic collision, what are the speed and direction of each ball after the collision?
a
1.50 m/s same direction of the tennis ball's initial motion
b
1.69 m/s same direction of the tennis ball's initial motion
c
2.25 m/s opposite direction of the tennis ball's initial motion
d
1.85 m/s opposite direction of the tennis ball's initial motion
The speed of each ball after the collision is 1.69 m/s and direction is same of the tennis ball's initial motion.
What is principle of momentum conservation?According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.
According to principle of momentum conservation:
the velocity of the two ball mass after the perfectly inelastic collision is
= (0.060 kg × 2.50 m/s + 0.090 kg × 1.15 m/s) ÷ ( 0.060 kg + 0.090 kg)
= 1.69 m/s
Hence, the speed of each ball is 1.69 m/s.
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PLEASE ANSWER FAST I WILL GIVE BRAINLIEST
In which scenario is gravitational potential energy present?
A rabbit looks out of a hole in the ground.
A squirrel runs up the trunk of a tree.
A deer runs across a grassy field.
A cat pins a mouse to the ground.
Explanation:
The answer is:
A squirrel runs up the trunk of a tree.
Answer:
its b
Explanation:
the one with the squirrel :p
The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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Which of the following use electromagnetic energy.
(Select all that apply)
Answer:
B. medical imaging, C. communication technology, and D. air conditioner.
what is the centripetal acceleration of an air plug on a car tire 250 rpm raduius of 0.45 m
The magnitude of the centripetal acceleration of the air plug on a car tire is 308.43 m/s².
What is centripetal acceleration?
Centripetal acceleration of an object is the rate of change of object's velocity with time, and it is directed inwards.
The magnitude of the centripetal acceleration of the air plug on a car tire is calculated as follows;
ac = ω²r
where;
ω angular speed (rad/s)r is radius of the tireAngular speed in radian per second\(\omega = 250 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} \\\\\omega = 26.18 \ rad/s\)
ac = (26.18)² x 0.45
ac = 308.43 m/s²
Thus, the magnitude of the centripetal acceleration of the air plug on a car tire is 308.43 m/s².
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A steam engine takes in superheated steam at 270 °C and discharges condensed steam from its cylinder at 50 °C. The engine has an efficiency of 30%, and taken in 50 kJ from the hot steam per cycle. If a Carnot engine takes in the same amount of heat per cycle and operates at these temperatures, the work it can turn into is most likely to be:a) 15 kJ. b) 20 kJ. c) 10 kJ. d) 50 kJ.
Answer:
b) 20 kJ
Explanation:
Efficiency of carnot engine = (T₁ - T₂ ) / T₁ Where T₁ is temperature of hot source and T₂ is temperature of sink .
T₁ = 270 + 273 = 543K
T₂ = 50 + 273 = 323 K
Putting the given values of temperatures
efficiency = (543 - 323) / 543
= .405
heat input = 50 KJ
efficiency = output work / input heat energy
.405 = output work / 50
output work = 20.25 KJ.
= 20 KJ .
Electric potential is defined as the _________________________.1) potential energy per unit distance 2) charge per unit voltage 3) voltage per unit charge 4) potential energy per unit charge
Electric potential is defined as the potential energy per unit charge. Potential difference change in potential energy of a charge moved from one point to another, divided by the charge.
Thus, the given option (4) is correct.
A grasshopper is an insect that goes through three distinct stages during its life cycle. The life cycle of a grasshopper is an example of which one of the following?
A. Quick metamorphosis
B. Slow metamorphosis
C. Complete metamorphosis
D. Incomplete metamorphosis
Answer:
B is the answer bc it's no way c an a and d can maybe c
why aeroplanes cannot travel in space
Answer:
- They need oxygen to burn fuel
- Aerodynamics
- Extreme temperatures
- Radiation
- Pressure issues
Explanation:
A airplane is a heavier-than-air aircraft kept aloft by the upward thrust exerted by the passing air on its fixed wings and driven by propellers, jet propulsion, etc.
Aeroplanes cannot travel in space for several reasons:
They need oxygen to burn fuel - Aeroplane engines rely on the oxygen in the atmosphere to burn fuel and generate thrust. In space, there is no atmosphere so there is no oxygen for the engines to work.
Aerodynamics - Aeroplane wings generate lift by interacting with the air. In space, there is no air so wings would be unable to generate any lift. Aeroplanes rely on aerodynamics to fly which does not work in space.
Extreme temperatures - In space, temperatures can range from -150 degrees Celsius to 150 degrees Celsius. Aeroplanes are designed to operate within a much narrower temperature range. The extreme cold and heat of space could damage aeroplane components.
Radiation - In space, there are high levels of radiation from the Sun and cosmic rays. Aeroplane bodies are not designed to shield against this type of radiation and it could damage electronics and affect aeroplane systems.
Pressure issues - Aeroplanes are designed to withstand air pressures at altitudes up to around 12 kilometers. In low-Earth orbit and beyond, the air pressure is essentially zero. This extreme change in pressure could cause structural damage to the aeroplane.
In summary, while aeroplanes are designed to fly through the Earth's atmosphere, they lack the key features needed to operate in the extreme environment of outer space like spaceships. Aeroplanes require things like oxygen, aerodynamics and being able to withstand changes in pressure - all of which do not exist or work the same way in space.
Explanation:
The wing is pushed up by the air under it. Large planes can only fly as high as about 7.5 miles. The air is too thin above that height. It would not hold the plane up.
When you push a box with 20N of force what force does the box apply back on you ?
When you push a box with 20 N of force. With a force of 20 N, the box applies back to you.
What is Newton's third law of motion?According to Newton's third law of motion, every action has an equal and opposite reaction. As well as the action and reaction are always acted in pairs.
When the student jumps off a sled toward the west after it stops at the bottom of an icy hill.
Based on the law of action-reaction, In the East direction will the sled move as the student jumps off.
Forces always act in pairs. When the person pushes a box with 20N of force. In that condition, the box will apply some reaction that is equal to 20 N.So that the static equilibrium must be balanced.
Hence with a force of 20N the box applies back to you
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Please help me on this
Answer:
Explanation:
read the assignment and use this
Topic sentence
Evidence from the text
Thoughts in your own words
Opinion
Wrap up sentence
T
E
T
O
W
and 2 of those make 2 paragraphs
Scientists observe an approaching asteroid that is on a collision course with
Earth. They devise a plan to launch a rocket that will collide with the asteroid
inelastically and stop it. The mass of the asteroid is 9000 kg, and it is
approaching Earth at 45 m/s. If the rocket has a mass of 1800 kg, what
velocity must it have to completely stop the asteroid after collision?
OA. - 225 m/s
B. 306 m/s
OC. 45 m/s
D. - 116 m/s we
The velocity of the rocket must be -225 m/s (negative indicating opposite direction) to completely stop the asteroid after the collision.
To completely stop the asteroid after collision, we can apply the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
The momentum of an object is given by the product of its mass and velocity:
momentum = mass * velocity
For the asteroid before collision:
momentum_asteroid = mass_asteroid * velocity_asteroid
For the rocket before collision:
momentum_rocket = mass_rocket * velocity_rocket
Since the rocket collides inelastically with the asteroid, they stick together after the collision. The final velocity of the combined system (rocket and asteroid) will be zero since they come to a complete stop. Therefore, the total momentum after the collision is zero:
momentum_after_collision = (mass_asteroid + mass_rocket) * 0
Using the principle of conservation of momentum, we can set the initial momentum equal to the final momentum:
momentum_asteroid + momentum_rocket = momentum_after_collision
mass_asteroid * velocity_asteroid + mass_rocket * velocity_rocket = 0
Substituting the given values:
9000 kg * 45 m/s + 1800 kg * velocity_rocket = 0
Simplifying the equation, we can solve for the velocity of the rocket (velocity_rocket):
velocity_rocket = - (9000 kg * 45 m/s) / 1800 kg
velocity_rocket = - 225 m/s
Therefore, the velocity of the rocket must be -225 m/s (negative indicating opposite direction) to completely stop the asteroid after the collision.
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PLEASE HELP ON QUESTION ASAP !!!!!!
Hi please help on question . If answer is correct I'll rate you five stars a thanks and maybe even brainliest!!!
Topic btw is electric circuits
Why is it important to represent components with symbols?
What type of increase either in frequency, intensity, time, type, or any combination of the FITT Principle categories should occur as a safe way to apply the principles of overload and progression?
Either in frequency, intensity, or time, or a combination of all three, it is a gradual increase.
What is intensity and example?According to the definition, intensity is the quality of being extremely powerful, concentrated, or difficult, or the strength or difficulty level of anything. Intensity can be demonstrated by being able to run at your maximum capacity for extended distances. An example of intensity is the speed a treadmill is moving at.
How do you measure intensity?A quick method to gauge relative intensity is the conversation test. In general, you can converse but not sing while engaging in moderate-intensity exercise. In general, you won't be able to speak for more than a few words without pausing to take a breath if you're engaging in vigorous-intensity activities.
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Please help me do this. Study the scenario.
A lever is used to lift a heavy weight. The length of the input arm of the lever is 3 m, the length of output arm is 1 m.
What is the mechanical advantage of the lever?
A.) 3
B.) 0.33
C.) 1
The mechanical advantage of the lever is 3 and the right option is A.) 3.
What is mechanical advantage?Mechanical advantage can be defined as the ratio of load to effort in a machine.
To calculate the mechanical advantage of the lever, we use the formula below.
Formula
M.A = y/x................ Equation 1Where:
M.A = mechanical advantage of the levery = distance moved by effort (input arm)x = distance moved by load (output arm)From the question,
Given:
y = 3 mx = 1 mSubstitute these values into equation 1
M.A = 3/1 M.A = 3.Hence, The mechanical advantage of the lever is 3 and the right option is A.) 3.
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