A system with input r(t) and output y(t) is described by y" (t) + y(y) = x(t) This system is 1) over-damped 2) under-damped 3) critically damped 4) undamped

Answers

Answer 1

The given system is described as y''(t) + y(t) = x(t). Now, let's solve this equation and find whether it is over-damped, under-damped, critically damped or undamped.

Differentiating the given equation, we get:y''(t) + y(t) = x(t)......(1)Differentiating again, we get:y'''(t) + y'(t) = x'(t)......(2)Putting (2) in (1), we get:y'''(t) + y'(t) + y(t) = x(t)......(3)The characteristic equation of the given system is: m³ + m = 0Solving the above equation, we get: m(m² + 1) = 0Therefore, m = 0 or ±j.So, the general solution of the given differential equation is:y(t) = c1cos(t) + c2sin(t) + c3where c1, c2, and c3 are constants.

To find the type of system, let's use the value of the damping ratio. We know that the damping ratio is given by the ratio of the coefficient of damping to the critical damping coefficient. For the given system, the damping coefficient is zero.Therefore, the damping ratio is zero, which implies that the given system is undamped.Therefore, the correct answer is option 4) undamped.

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Related Questions

A major portion of the energy consumption in households can be attributed to home heating and cooling.
True
False

Answers

The statement it's true, as a significant amount of energy consumption in homes is typically linked to heating and cooling, particularly in countries with extreme temperatures.

According to the U.S. Energy Information Administration, heating and cooling account for nearly half of the energy used in the average American home. Proper insulation, efficient HVAC systems, and other measures can help reduce energy consumption and costs associated with home heating and cooling.

What is energy consumption?

Energy consumption refers to the amount of energy used, converted, or transformed in a given period of time. It is often measured in units such as kilowatt-hours (kWh) or British thermal units (BTUs). Energy consumption can be related to various forms of energy, such as electricity, natural gas, oil, and renewable sources like wind or solar power.

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Can you answer what is attached.

Can you answer what is attached.

Answers

29.4 bro I hope that helps

engineers please help im not good when it comes to drawing​

engineers please help im not good when it comes to drawing

Answers

Answer:

I'm good at drawing and computer-animated design

Explanation:

engineers please help im not good when it comes to drawing

Block A has mass of mA = 58kg and rests on a flat surface. The coefficient of static friction between the block and the surface is 0.300. The coefficient of static friction between the rop and the fixed peg B is 0.310. The width of the block is d = 0.290m. Find the greatest mass, mC, that weight C can have such that block A does not move.​

Block A has mass of mA = 58kg and rests on a flat surface. The coefficient of static friction between

Answers

Answer:

The greatest mass, that the weight C can have such that block A does not move is approximately 23.259 kg

Explanation:

The given parameters are;

The mass of the block A= 58 kg

The coefficient of static friction between the block and the surface, \(\mu _s\) = 0.300

The coefficient of static friction between the rope and the fixed peg, B \(\mu _B\) = 0.310

Let T represent the tension in the rope

Therefore, when the rope is static, T = The normal reaction at the peg, B, \(N_B\)

The angle of inclination of the rope holding the block A = arctan(3/4) ≈ 36.87°

The length of the rope = √(0.4² + 0.3²) = 0.5

∴ sin(θ) = 3/5 = 0.6

cos(θ) = 4/5 = 0.8

The vertical component of the tension in the rope = T × sin(θ) = 0.6·T

The horizontal component of the tension in the rope = T × cos(θ) = 0.8·T

The friction force = μ×(W - 0.6·T) = 0.300×(58×9.8 - 0.6·T) = 170.52 - 0.18·T

The block will start to move when we have;

The horizontal component of the tension in the rope = The friction force

∴ 0.8·T = 170.52 - 0.18·T

0.8·T + 0.18·T = 170.52

0.98·T = 170.52

T = 170.52/0.98 = 174

Therefore, the tension in the rope = T = 174 N = The normal reaction at the peg, B \(N_B\)

The frictional force at the peg, \(F_B\) = \(\mu _B\) × \(N_B\) = 0.310 × 174 N = 53.94 N

The weight of the mass, \(m_c\), \(W_c\) = The frictional force at the peg, \(F_B\)  + The tension in the rope

∴ The weight of the mass, \(m_c\), \(W_c\) = 53.94 N + 174 N = 227.94 N

Weight, W = Mass, m × The acceleration due to gravity, g, from which we have;

m = W/g

Where;

g = 9.8 m/s²

∴ \(m_c\) = \(W_c\)/g = 227.94 N/(9.8 m/s²) ≈ 23.259 kg.

The greatest mass, that the weight C can have such that block A does not move = \(m_c\) ≈ 23.259 kg.








What is the most inexpensive and slow transportation mode? Air Carriers Water Carriers Rail Carriers Motor Carriers

Answers

Among the transportation modes mentioned, the most inexpensive and slow transportation mode is typically water carriers. Water carriers, such as ships, barges, and boats, offer the advantage of being able to transport large volumes of goods at a relatively low cost per ton-mile.

Water transportation is well-suited for bulk cargo and long-distance shipments. The cost-effectiveness of water carriers is primarily due to their ability to handle large volumes and take advantage of economies of scale.

However, water transportation is generally slower compared to other modes. Ships and barges have lower speeds compared to air, rail, or motor carriers. The speed of water carriers can be influenced by factors such as the size and type of vessel, the distance traveled, and the water conditions. It can take several days, weeks, or even months for goods to be transported by water carriers, depending on the specific route and circumstances.

In contrast, air carriers are the fastest mode of transportation but are also the most expensive due to high fuel costs, maintenance expenses, and limited cargo capacity. Air transportation is typically used for high-value and time-sensitive goods that require quick delivery.

Rail carriers offer a balance between cost and speed. They are generally more affordable than air carriers but faster than water carriers for long-distance transportation. Rail transportation is particularly suitable for moving heavy goods, bulk commodities, and intermodal shipments.

Motor carriers, such as trucks and trailers, provide flexibility and convenience for transportation. They are commonly used for short-distance and regional shipments. However, motor carriers tend to have higher costs per ton-mile compared to water and rail carriers.

In summary, water carriers are often the network of most inexpensive but slow transportation mode, offering cost advantages for long-distance bulk cargo shipments. The choice of transportation mode depends on factors such as the nature of the goods, distance, time constraints, and cost considerations.

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Liquid water at 20°C is heated in a chamber by mixing it with saturated steam. Liquid water enters the chamber at the steam pressure at a rate of 4.6 kg/s and the saturated steam enters at a rate of 0.19 kg/s. The mixture leaves the mixing chamber as a liquid at 45°C. If the surroundings are at 20°C, determine:
a. the temperature of saturated steam entering the chamber,
b. the exergy destruction during this mixing process,
c. the second-law efficiency of the mixing chamber.

Answers

To solve this problem, we will use the conservation of mass and energy, as well as the definition of exergy and second-law efficiency.

a. The temperature of saturated steam entering the chamber can be found by using the steam tables. At the pressure of the steam entering the chamber, which is not given in the problem, the saturation temperature is slightly above 100°C. Since the mixture leaves the chamber as a liquid at 45°C, we can assume that the steam is also at 45°C, which is the final temperature of the mixture. Therefore, the temperature of the saturated steam entering the chamber is 45°C.

b. The exergy destruction during this mixing process can be calculated as the difference between the inlet exergy and the outlet exergy of the system. The inlet exergy can be calculated as the sum of the exergy of the liquid water and the exergy of the saturated steam, which are both at the same temperature of 45°C. The outlet exergy can be calculated as the exergy of the liquid water at 45°C, assuming that there is no exergy transfer to the surroundings. The exergy destruction is then:

ΔE = (m_water * e_water + m_steam * e_steam) - m_outlet * e_outlet

where m_water and m_steam are the mass flow rates of the liquid water and saturated steam, respectively, and e_water, e_steam, and e_outlet are the specific exergies of the liquid water, saturated steam, and outlet liquid water, respectively.

Using the steam tables, we can find that the specific exergies of the liquid water and saturated steam at 45°C are 199.23 kJ/kg and 2513.9 kJ/kg, respectively. Therefore, the exergy destruction is:

ΔE = (4.6 kg/s * 199.23 kJ/kg + 0.19 kg/s * 2513.9 kJ/kg) - 4.79 kg/s * 199.23 kJ/kg
ΔE = 6253.7 kW

c. The second-law efficiency of the mixing chamber can be defined as the ratio of the actual work output (which is zero in this case) to the maximum possible work output, which is the inlet exergy minus the exergy destruction. Therefore, the second-law efficiency is:

η_II = 0 / (m_water * e_water + m_steam * e_steam - ΔE)
η_II = 0 / (4.6 kg/s * 199.23 kJ/kg + 0.19 kg/s * 2513.9 kJ/kg - 6253.7 kW)
η_II = 0

This means that the mixing process is not reversible, and there is no useful work output.

Activity 1. Fill the blank with the correct answer. Write your answer on the blank. 1. ___________________ is a regular pattern of dots displayed on the screen which acts as a visual aid and also used to define the extent of your drawing. 2. Ortho is short for ___________________, which means either vertical or horizontal. 3. Tangent is a point where two _______________________ meet at just a single point. 4. If you want to create a new drawing, simply press ___________________ for the short cut key. 5. There are _______________Osnap that can help you performs your task easier.

Answers

Answer:

1. Drawing grid.

2. Orthogonal.

3. Geometries.

4. CTRL+N.

5. Thirteen (13).

Explanation:

CAD is an acronym for computer aided design and it is typically used for designing the graphical representation of a building plan. An example of a computer aided design (CAD) software is AutoCAD.

Some of the features of an AutoCAD software are;

1. Drawing grid: is a regular pattern of dots displayed on the screen of an AutoCAD software, which acts as a visual aid and it's also used to define the extent of a drawing.

2. Ortho is short or an abbreviation for orthogonal, which means either vertical or horizontal.

3. Tangent is a point where two geometries meet at just a single point.

4. If you want to create a new drawing, simply press CTRL+N for the short cut key.

5. There are thirteen object snaps (Osnap) that can help you perform your task on AutoCAD easily. The 13 object snaps (Osnap) are; Endpoint, Midpoint, Apparent intersect, Intersection, Quadrant, Extension, Tangent, Center, Insert, Perpendicular, Node, Parallel, and Nearest.

A wood pole with a diameter of 10 in. has a moisture content of 5%. The fiber saturation point (FSP) for this wood is 30%. The wood shrinks or swells 1% (relative to the green dimensions) in the radial direction for every 5% change in moisture content below FSP. a. What would be the percent change in the wood's diameter if the wood's moisture is increased to 55%? b. Would the wood swell or shrink? c. What would be the new diameter?

Answers

Answer:

a) Δd(change in wood diameter) = 5%

b) The wood would swell since the moisture content is increasing which will also led to increase in the wood's diameter

C) new diameter (D2) = 10.5 in

Explanation:

Wood pole diameter = 10 inches

moisture content = 5%

FSP = 30%

A) The percentage change in the wood's diameter

note : moisture fluctuations from 5% to 30% causes dimensional changes in the wood but above 30% up to 55% causes no change. hence this formula can be used to calculate percentage change in the wood's diameter

Δd/d = 1/5(30 - 5)

Δd/d = 5%  

Δd = 5%

B) would the wood swell or shrink

The wood would swell since the moisture content is increasing which will also led to increase in the wood's diameter

C) The new diameter of the wood

D2 = D + D( \(\frac{M1}{100}\) )

D = initial diameter= 10 in , M1 = initial moisture content = 5%

therefore D2 = 10 + 10( 5/100 )

new diameter (D2) = 10.5 in

The change in the diameter of the wood would be 5%

the new diameter would be 10.5 inches

Wood pole diameter = 10 inches

Moisture content = 5%

Fiber saturation point = 30 %

The change in  diameter would be

\(\frac{1}{5} (30-5)\)

= 25/5

= 5%

The percentage change in the diameter of the wood would be 5%

b. This wood is going to rise up instead of shrinking. This is due to the fact that the moisture content that it has has gone up by 55%

c. The new diameter that this wood would have

diameter = 10

moisture = 5%

D = D+D(m)

= 10 + 10(5%)

= 10.5 inches

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A work part with starting height h = 100 mm and diameter = 55 mm is compressed to a final height of 50 mm. During the deformation, the relative speed of the platens compressing the part = 200 mm/s. Determine the strain rate at (a) h = 100 mm, (b) h = 75 mm, and (c) h = 51 mm.

Answers

The strain rate remains constant at 200 mm/s regardless of the height of the work part during the deformation process.

To determine the strain rate at different heights during the deformation process, we can use the formula:

Strain rate = (change in height) / (change in time)

Given:

Starting height (h1) = 100 mm

Final height (h2) = 50 mm

Relative speed of the platens (v) = 200 mm/s

(a) At h = 100 mm:

Change in height = h1 - h2 = 100 mm - 50 mm = 50 mm

Strain rate = (change in height) / (change in time) = 50 mm / (50 mm / 200 mm/s) = 200 mm/s

(b) At h = 75 mm:

Change in height = h1 - h = 100 mm - 75 mm = 25 mm

Strain rate = (change in height) / (change in time) = 25 mm / (25 mm / 200 mm/s) = 200 mm/s

(c) At h = 51 mm:

Change in height = h1 - h = 100 mm - 51 mm = 49 mm

Strain rate = (change in height) / (change in time) = 49 mm / (49 mm / 200 mm/s) = 200 mm/s

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2. for CPU, the predominant package type is called: A. BGB B. BCC C. BGA D. None of the above 3. RAM capacity is measured in: A. Bit B. byte C. Bps D. None of the above 4. The power supply takes standard 220-volt AC power and converts it into: A. 10-volt, 4-volt, and 3.3-volt DC power B. 120-volt, 5-volt, and 3.3-volt DC power C. 12-volt, 5-volt, and 3.3-volt DC power D. 12-volt, 8-volt, and 7-volt DC power 5. example of optical media: A. floppy disc B. hard disc C. CD D. USB 6. Example of portable computer? A. PC B. Deskiop C. tablet D. None of the abowe 7. Mainframes is designed to meet the need for: A. Medium organization B. Small organization C. Big organization D. None of the above

Answers

The predominant package type for CPUs is BGA. RAM capacity is measured in bytes. The power supply converts standard 220-volt AC power into 12-volt, 5-volt, and 3.3-volt DC power. An example of optical media is a CD. Portable computers include tablets. Mainframes are designed to meet the needs of big organizations.

The predominant package type for CPUs is C. BGA (Ball Grid Array). It is a type of integrated circuit packaging in which the processor chip is mounted directly onto the motherboard using an array of solder balls.

RAM capacity is measured in B. bytes. A byte is a basic unit of storage in computer memory and represents 8 bits. RAM (Random Access Memory) stores data that can be accessed quickly by the computer's processor.

The power supply takes standard 220-volt AC power and converts it into C. 12-volt, 5-volt, and 3.3-volt DC power. These are commonly used voltage levels in computer systems to provide power to different components.

An example of optical media is C. CD (Compact Disc). Optical media uses lasers to read and write data on a reflective surface. CDs can store various types of data, such as audio, video, and computer files.

An example of a portable computer is C. tablet. Tablets are lightweight and compact devices that offer touchscreen functionality and are designed for easy portability. They typically have built-in batteries and can be used for various tasks, including browsing the internet, watching videos, and running applications.

Mainframes are designed to meet the needs of C. big organizations. Mainframe computers are powerful, high-performance machines that are capable of handling large-scale computing and data processing tasks. They are commonly used in industries such as finance, healthcare, and government, where massive amounts of data and high processing power are required. Mainframes offer robust reliability, security, and scalability to support the operations of large organizations.

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A cylindrical work part has a diameter and a height of both as 6cm. The coefficient of friction at the die work interface is 0.10. The work metal has a strength coefficient of 270MPa, yield strength of 110MPa, and a strain hardening exponent of 0.15. Determine the instantaneous force in N at a height of 4cm

Answers

the answer to this question: 4.50

It is proposed to absorb acetone from air using water as a solvent. Operation is at 10 atm and is isothermal at 20°C. The total flow rate of entering gas is 10 kmol /h. The entering gas is 1.2 mol% acetone. Pure water is used as the solvent. The water flow rate is 15 kmol/h. The desired outlet gas concentration should be 0.1 mol % acetone. For this system, Henry's law holds and Ye = 1.5 X where Ye is the mol fraction of acetone in the vapour in equilibrium with a mol fraction X in the liquid.
KGa = 0.4 kmol*m^-3*s^-1
1. Draw a schematic diagram to represent the process.
2. Determine the mole fraction of acetone in the outlet liquid.

Answers

Answer:

The meole fraction of acetone in the outlet liquid is \(x_1 = 0.0072\)

Explanation:

1.

The schematic diagram to represent this process is shown in the diagram attached below:

2.

the mole fraction of acetone in the outlet liquid is determined as follows:

solute from Basis Gas flow rate \(G_s = 10(1-0.012) =9.88 kmol/hr\)

Let the entering mole be :\(y_1 = 1.2\) % = 0.012

\(y_1 =(\dfrac{y_1}{1-y_1})\)

\(y_1 =(\dfrac{0.012}{1-0.012})\)

\(y_1 =0.012\)

Let the outlet gas concentration be \(y_2\) = 0.1% = 0.001

\(y_2 = 0.001\)

Thus; the mole fraction of acetone in the outlet liquid is:

\(G_s y_1 + L_s x_2 = y_2 L_y + L_s x_1\)

\(9.88(0.012-0.001)=15*x_1\)

\(9.88(0.011) = 15x_1\)

\(x_1 = \dfrac{0.10868}{15}\)

\(x_1 = 0.0072\)

The mole fraction of acetone in the outlet liquid is \(x_1 = 0.0072\)

It is proposed to absorb acetone from air using water as a solvent. Operation is at 10 atm and is isothermal

______ is the intentional insertion in any manner of electromagnetic energy into transmission paths

Answers

Electromagnetic Interference (EMI) is the intentional insertion in any manner of electromagnetic energy into transmission paths.

Electromagnetic Interference (EMI) is the deliberate insertion of electromagnetic energy into transmission paths in order to disrupt the proper functioning of an electronic system.EMI can be caused by a variety of sources, including radio and television broadcasts, cell phones, computers, electric motors, and power lines. Because EMI can disrupt the proper functioning of an electronic device, it is a significant issue that must be addressed by designers and manufacturers of electronic equipment.

There are a number of ways to reduce the effects of EMI. The first is to use shielding, which is the process of enclosing the electronic device in a metal box or casing to block electromagnetic signals. Another option is to use filters, which are devices that remove unwanted frequencies from a signal. Additionally, proper grounding and circuit design can help to reduce the effects of EMI.

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The intentional insertion in any manner of electromagnetic energy into transmission paths is called "Electromagnetic Interference" (EMI).

EMI refers to the disturbance caused by the presence of unwanted electromagnetic signals in the transmission paths or electronic systems. It can result from various sources such as electronic devices, power lines, radio signals, or other electromagnetic sources.

EMI can negatively impact the performance and functionality of electronic devices and communication systems. It can cause signal degradation, data corruption, malfunctions, or even complete system failures.

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assume an fm system has a frequency deviation of 10 khz when the modulating signal has an amplitude of 4 volts and a frequency of 2 khz. determine the frequency deviation if the modulating signal is (hint: this info will give the modulator sensitivity (khz/volt):

Answers

The frequency deviation of the modulating signal is given by: Frequency deviation, Δf = βVm = 5 x 1.2 = 6 kHz.

Assuming that an FM system has a frequency deviation of 10 kHz when the modulating signal has an amplitude of 4 volts and a frequency of 2 kHz, let us determine the frequency deviation if the modulating signal is given below.

Therefore, we can say that the modulating signal is given by 1.2sin(2πft), where f is the frequency of the modulating signal. Let us first find the modulator sensitivity (km/Volt). Given, amplitude of modulating signal, Vm = 4 V. Frequency of modulating signal, fm = 2 kHz Frequency deviation, Δf = 10 kHzWe know that Modulation index, β = Δf/fm = 10/2 = 5 km/Volt

From the given question, we are given that the modulator's sensitivity (km/volt) is 5 km/Volt. Therefore, the answer is 6 kHz.

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After cutting a PVC pipe you should use a
to debure the pipe

Answers

Answer:

Deburring Tool

Explanation:

A deburring tool is used in order to debur the PVC pipes. They are mostly used for the plastic pipes.

After the PVC pipes are cut, there are burrs on the pipe surface. To remove these burrs, a deburring tool is used. It removes the burrs form the edges of the PVC pipes that results from grinding, cutting, milling, drilling, etc.

The deburring tools are made from high speed steels.

PLEASE HELP!!!
What was Amelia Earhart was the first woman to accomplish?
A Flying around the world
B Flying solo across the Atlantic
C Inventing a jumpsuit for female pilots
D Flying across the English Channel

Answers

Answer:

B!

Explanation:

Answer:

B. Flying solo across the atlantic

Explanation:

history class

2. Local governments, communities, and the individuals that live there don't have an implied right to know about
the hazards around them.
A) True
B)False

Answers

False

This is an implied right according to civil law in the United States.

Leather palm gloves can protect your hands from what hazards

Answers

Answer:

They protect the entire hand from abrasion and punctures, and are a dependable, comfortable glove for a wide variety of jobs. Drivers' gloves are available in various types of leathers and can be unlined or lined for cold weather. Leather palm gloves provide maximum protection against abrasive and puncture hazards.

Gloves with leather palms offer the best defense against abrasive and puncture risks. They have leather palms and fingers and are constructed of dependable cotton or canvas.

What is abrasive?

Abrasive is defined as a substance, sometimes a mineral, used to shape or polish a product by rubbing, which causes some of the workpiece to be removed due to friction. Abrasives are a particular kind of extremely hard material that are utilized in a variety of residential, industrial, and technological applications. A portion of the work piece is worn away when the abrasive is rubbed against it.

These leather gloves each offer particular levels of comfort, protection, and durability. Some of these leather gloves are suitable for use by those handling dangerous chemicals and sparks. Some can provide cut protection to an extreme degree. For workers who handle heat and water, certain types of leather gloves are recommended.

Thus, gloves with leather palms offer the best defense against abrasive and puncture risks. They have leather palms and fingers and are constructed of dependable cotton or canvas.

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a heat engine would have 100% efficiency if its low-temperature reservoir were ____

Answers

A heat engine would have 100% efficiency if its low-temperature reservoir were at absolute zero. This is known as the Carnot efficiency limit and is a theoretical maximum for the efficiency of a heat engine.

A heat engine is a device that converts thermal energy into mechanical energy. It operates by using a temperature difference between a hot reservoir and a cold reservoir to do work. The efficiency of a heat engine is defined as the ratio of the work output to the heat input, and it is always less than 100% due to losses in the system.

The Carnot efficiency limit is a theoretical maximum for the efficiency of a heat engine. It is based on the idea of a reversible engine that operates in a cycle between two heat reservoirs, with no heat loss to the surroundings. The efficiency of a Carnot engine depends only on the temperatures of the two reservoirs and is given by the formula:

efficiency = 1 - (T low / T high)

where T low is the temperature of the low-temperature reservoir, and T T T high is the temperature of the high-temperature reservoir.

If the low-temperature reservoir were at absolute zero (0 Kelvin or -273.15 Celsius), the efficiency of the Carnot engine would be 100%, which is the theoretical maximum for any heat engine. However, achieving absolute zero is impossible in practice, so real-world heat engines will always have less than 100% efficiency.

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Can someone help with this please?

Answers

Answer:

with what

Explanation:

Sidney wants to make an electric circuit. She gathers the items shown below.

Light bulb, wire, metal screw

What additional item does Sidney need to make a complete circuit?

A: a battery

B: a switch

C: an insulator

D: a conducter

Answers

A battery

you need a power source to complete the circuit.

Answer:

A: a battery.

Explanation:

Sidney needs a battery to make a complete circuit. The battery will provide the electrical energy needed to power the light bulb. Without a battery, the circuit will be incomplete, and the light bulb will not light up. Therefore, the correct answer is A

A steel plate of width 120mm and thickness of 20mm is bent into a circular arc radius of 10. You are required to calculate the maximum stress induced and the bending moment which will give the maximum stress. You are given that E=2*10^5​

A steel plate of width 120mm and thickness of 20mm is bent into a circular arc radius of 10. You are

Answers

Answer:

Hence the magnitude of the pure moment m will be \(2\times 10^5.\)

Explanation:

 Width of steel fleet = 120 mm   The thickness of steel fleet = 10 mm   Let the circle of radius = 10 m  

Now,

We know that,

\(\frac{M}{I} = \frac{E}{R}\)

Thus, \(M =\frac{EI}{R}\)

Here

R = 10000 mm  

\(I=\frac{1}{12}\times 120\times 10^{3}\\= 10^{4} mm^{4}\)

\(E=2\times 10^{5}n/mm^{2}\\\\E=2\times 10^{5}n/mm^{2}\\\\M={(2\times 10^{5}\times 10^{4})/{10000}}\\\\M=2\times 10^{5}\)

 

Hence, the magnitude of the pure moment m will be \(2\times 10^5.\)

explain the working principles of a rotary engine​

Answers

Answer:

The rotary engine works on the same basic principle as the piston engine: combustion in the power plant releases energy to power the vehicle. However, the delivery system in the rotary engine is wholly unique. The piston engine performs four key operations: intake, compression, combustion, and exhaust.

Explanation:

a long cylindrical pressure vessel of length l, radius r, and thickness t is subject simultaneously to an internal pressure p and an axial force f. find the relationship between f and p such that the axial stress and hoop stress are equal in the main part of the vessel

Answers

The relationship between the axial force (F) and internal pressure (P) in the main part of the pressure vessel is \(F = P * r^2 * π * t.\)

It is important to note that this relationship holds true only in the main part of the vessel and may not be applicable to other regions.To find the relationship between the axial force (F) and internal pressure (P) such that the axial stress and hoop stress are equal in the main part of the pressure vessel, we need to consider the equilibrium conditions and stress distribution.

1. Axial stress (σa) is the stress acting parallel to the axis of the cylinder, while hoop stress (σh) is the stress acting circumferentially around the cylinder.
2. In the main part of the vessel, the axial stress and hoop stress are equal, which means σa = σh.
3. Axial stress (σa) can be calculated using the formula

\(σa = F / (π * r^2),\)

where r is the radius of the cylinder.
4. Hoop stress (σh) can be calculated using the formula

\(σh = P * r / t,\)

where t is the thickness of the cylinder.
5. Equating σa and σh, we get

\(F / (π * r^2) = P * r / t.\)
6. Rearranging the equation, we find that the relationship between F and P is given by

\(F = (P * r^2 * π * t).\)

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-Why is it said that using faulty PPE could be just as dangerous as using no PPE at all?

Answers

Answer:

Explanation:

"Safety helmet" redirects here. It is not to be confused with hard hat.

Drug Enforcement Administration (DEA) agents wearing Level B hazmat suits

Personal protective equipment (PPE) is protective clothing, helmets, goggles, or other garments or equipment designed to protect the wearer's body from injury or infection. The hazards addressed by protective equipment include physical, electrical, heat, chemicals, biohazards, and airborne particulate matter. Protective equipment may be worn for job-related occupational safety and health purposes, as well as for sports and other recreational activities. "Protective clothing" is applied to traditional categories of clothing, and "protective gear" applies to items such as pads, guards, shields, or masks, and others. PPE suits can be similar in appearance to a cleanroom suit.

The purpose of personal protective equipment is to reduce employee exposure to hazards when engineering controls and administrative controls are not feasible or effective to reduce these risks to acceptable levels. PPE is needed when there are hazards present. PPE has the serious limitation that it does not eliminate the hazard at the source and may result in employees being exposed to the hazard if the equipment fails.[1]

Any item of PPE imposes a barrier between the wearer/user and the working environment. This can create additional strains on the wearer; impair their ability to carry out their work and create significant levels of discomfort. Any of these can discourage wearers from using PPE correctly, therefore placing them at risk of injury, ill-health or, under extreme circumstances, death. Good ergonomic design can help to minimise these barriers and can therefore help to ensure safe and healthy working conditions through the correct use of PPE.

Practices of occupational safety and health can use hazard controls and interventions to mitigate workplace hazards, which pose a threat to the safety and quality of life of workers. The hierarchy of hazard controls provides a policy framework which ranks the types of hazard controls in terms of absolute risk reduction. At the top of the hierarchy are elimination and substitution, which remove the hazard entirely or replace the hazard with a safer alternative. If elimination or substitution measures cannot apply, engineering controls and administrative controls, which seek to design safer mechanisms and coach safer human behavior, are implemented. Personal protective equipment ranks last on the hierarchy of controls, as the workers are regularly exposed to the hazard, with a barrier of protection. The hierarchy of controls is important in acknowledging that, while personal protective equipment has tremendous utility, it is not the desired mechanism of control in terms of worker safety.rly PPE such as body armor, boots and gloves focused on protecting the wearer's body from physical injury. The plague doctors of sixteenth-century Europe also wore protective uniforms consisting of a full-length gown, helmet, glass eye coverings, gloves and boots (see Plague doctor costume) to prevent contagion when dealing with plague victims. These were made of thick material which was then covered in wax to make it water-resistant. A mask with a beak-like structure which was filled with pleasant-smelling flowers, herbs and spices to prevent the spread of miasma, the prescientific belief of bad smells which spread disease through the air.[2] In more recent years, scientific personal protective equipment is generally believed to have begun with the cloth facemasks promoted by Wu Lien-teh in the 1910–11 Manchurian pneumonic plague outbreak, although many Western medics doubted the efficacy of facemasks in preventing the spread of disease.[3]

Types

Personal protective equipment can be categorized by the area of the body protected, by the types of hazard, and by the type of garment or accessory. A single item, for example boots, may provide multiple forms of protection: a steel toe cap and steel insoles for protection of the feet from crushing or puncture injuries, impervious rubber and lining for protection from water and chemicals, high reflectivity and heat resistance for protection from radiant heat, and high electrical resistivity for protection from electric shock. The protective attributes of each piece of equipment must be compared with the hazards expected to be found in the workplace. More breathable types of personal protective equipment may not lead to more contamination but do result in greater user satisfaction.[4]

The use of a faulty PPE could be just as dangerous as not using any PPE at all because the user is still exposed to potential hazards and harm.

What is PPE?

PPE is an acronym for personal protective equipment and it can be defined as a terminology that is used to denote any piece of equipment which offer protection to different parts of the body while working in a potentially hazardous environment.

Some examples of personal protective equipment (PPE) used to protect the different parts of the body are:

RespiratorsFace maskFace shieldGlovesBootsHelmet

According to OSHA, the use of a faulty PPE could be just as dangerous as not using any PPE at all because the user is offered little or no protection at all.

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Let the function fun be defined as int fun(int *k) { *k += 4; return 3 * (*k) - 1; } Suppose fun is used in a program as follows: void main() { int i = 10, j = 10, sum1, sum2; sum1 = (i / 2) + fun(&i); sum2 = fun(&j) + (j / 2); } What are the values of sum1 and sum2 ? ( a. if the operands in the expressions are evaluated left to right? b. if the operands in the expressions are evaluated right to left?

Answers

The values of sum1 and sum2 if the operands in the expressions are evaluated left to right are; sum1 = 46 and sum2 = 48

How to use Operand in Programming?

In computer programming, the term operand is defined as the object of a mathematical operation or it is the object or quantity that is operated on.

A) If the operands in the expressions are evaluated left to right, then the values of sum1 and sum2 are;

sum1 = (10/2) + 41 = 46

sum2 = 41 + (14/2) = 48

B) If the operands in the expressions are evaluated right to left, then the values of sum1 and sum2 are;

sum1 = (14/2) + 41 = 48

sum2 = 41 + (10/2) = 46

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What are the 3 types of irony and examples?.

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The three types of irony are Verbal Irony, Situational Irony, and Dramatic Irony.

Example of Verbal Irony:

When a statement's intended meaning differs from what is actually said, it is said to be verbally ironic.In Shrek, Donkey asks Shrek if he can stay with him. Shrek replies, "Of course," when he really means, "No, not really."

Example of Situational Irony:

Situational irony occurs when a situation's conclusion is completely unanticipated. For instance, everyone in Emerald City believes that Oz is strong and impressive in the book The Wonderful Wizard of Oz. Oz, however, turns out to be the exact opposite—an aged guy devoid of any supernatural abilities.

Example of Dramatic Irony:

Dramatic irony occurs when characters are unaware of information that the audience is aware of.When the readers are aware that a deadly shark is present in the water but the carefree beachgoers are unaware that they are being pursued.

What is Irony?

When something unexpected occurs, it is ironic. The thing opposite to what we anticipate usually occurs, and this is either humorous or dramatic.

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tech a says that small vacuum leaks can be found with a vacuum gauge. tech b says that the catalytic converter is typically located after the muffler. who is correct?

Answers

Both are true. Tech A claims that a vacuum gauge can be used to locate tiny vacuum leaks. According to tech B, the catalytic converter is usually placed behind the muffler.

Which of the following links the catalytic converter to the exhaust manifold?

Tailpipe. The catalytic converter has cleaned up the exhaust gases, which are then sent out of the car and into the atmosphere via the tailpipe, the last link in the exhaust system.

Which of the following exhaust system parts aids in lowering exhaust emissions?

Hazardous pollutants from engine exhaust are decreased by the catalytic converter. The converter, which is situated between the exhaust manifold and the muffler, works with heat and metals that serve as catalysts.

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Throw a rangeerror exception if any of the numbers is greater than 50. Throw an error exception if the parameter has less than 2 elements.

Throw a RangeError exception if any of the numbers is greater than 75. Throw an Error exception if the parameter has less than 4 elements 1 function processNumbers (numList) // Code will be tested with different values of numList var result = 0; 4 for (var indexindex

Answers

The javascript code that satisfies the given question that throws a range error exception if any of the numbers is greater than 50.  is given below

The Program

function processNumbers(numList) {

   var result = 0;

   if (numList.length < 4)

       throw new Error();

   for (var index = 0; index < numList.length; index++) {

       if (numList[index] > 75)

           throw new RangeError();

       result += numList[index] * 1.3 * index;

   }

   return result;

}

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you cant mix conventional and synthetic oil fact or myth

Answers

Answer:

Explanation:

myth

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