A table is made using the following two patterns.
Pattern x: Starting number: 1, Rule: add 1
Pattern y: Starting number: 5, Rule: add 5
Complete the table for the given patterns.
x y
1 5

Answer:

Step-by-step explanation:

2 meters = 200 cm

200 cm × (1 block)/(50 cm) = 4 blocks

4 blocks by 4 blocks = 16 blocks

Answer:

16 paving stones

Step-by-step explanation:

1 m = 100 cm

The square has sides 200 cm long

Its area is 200(200) = 40000 sq cm

Each paving stone has an area of 50(50) = 2500 sq cm

So 40000/2500 = 16 paving stones

Answer:

it is  82.13

Step-by-step explanation:

you can add the 57.52+24.88

i. α = 56°

ii. adj =  4.1

iii. opp = 2.79

We have to recall that what makes the right angle triangle unique is the fact that one of the angles that we find in the triangle is 90 degrees. We have to recall that the sum of the angles that we have in a triangle is 180°.

Hence we have;

α = 180 - (90 + 34)

α = 56°

Then;

Cos 34 = adj/5

adj = 5 cos 34

= 4.1

Sin 34 = opp/5

opp = 5 * sin 34

= 2.79

These are the parts of the right angled triangle required.

Learn more about triangle:https://brainly.com/question/2773823

#SPJ1

Answer:

The volume of the cylinder is \(112\ \text{units}^3\).

Step-by-step explanation:

We have,

Radius of the cylinder is 4 units

Height of the cylinder is 7 units

It is required to find the volume of the cylinder. The formula of the volume of the cylinder is given by :

\(V=\pi r^2 h\)

Plugging all the values, we get :

\(V=\pi \times (4)^2\times 7\\\\V=112\ \text{units}^3\)

So, the volume of the cylinder is \(112\ \text{units}^3\). The correct option is (b).

Answer:

\(m_{perpendicular}\) = 6

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

x + 6y = - 24 ( subtract x from both sides )

6y = - x - 24 ( divide through by 6 )

y = - \(\frac{1}{6}\) x - 4 ← in slope- intercept form

with slope m = - \(\frac{1}{6}\)

given a line with slope m then the slope of a line perpendicular to it is

\(m_{perpendicular}\) = - \(\frac{1}{m}\) = - \(\frac{1}{-\frac{1}{6} }\) = 6

Let's draw a picture of the problem:

From the picture above, we can see that the difference (x) between the second and third position is

which gives

How many degrees forward must the swing go to return to its starting position? ​Answer: 45 degrees forward

well, let's first off find out how many actually do favor it in the first place.

\(\stackrel{total}{4000}\cdot \cfrac{3}{8}\implies \stackrel{seniors}{\text{\LARGE 1500}}\hspace{12em}\stackrel{total}{4000}-1500=\stackrel{not~seniors}{\text{\LARGE 2500}} \\\\[-0.35em] ~\dotfill\)

\(\stackrel{seniors}{\text{\LARGE 1500}}\cdot \cfrac{1}{6}\implies \stackrel{in~favor}{\text{\LARGE 250}}\hspace{11em} \stackrel{not~seniors}{\text{\LARGE 2500}}\cdot \cfrac{3}{5}\implies \stackrel{in~favor}{\text{\LARGE 1500}} \\\\[-0.35em] ~\dotfill\\\\ 250+1500\implies \stackrel{in~favor}{\text{\LARGE 1750}}\hspace{15em}\boxed{\underset{\textit{do not favor it}}{\stackrel{4000~~ - ~~1750}{\text{\LARGE 2250}}}}\)

Given statement solution is :- The present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.

To calculate the present value of an investment with compound interest, we can use the formula for the present value of an annuity:

PV = A *\((1 - (1 + r)^(-n)) / r\)

Where:

PV = Present value

A = Annual payment or cash flow

r = Interest rate per period

n = Number of periods

In this case, the annual payment (A) is R13,000, the interest rate (r) is 10% per year, and the investment is made for 8 years (n).

Using the formula and substituting the given values, we can calculate the present value:

PV = \(13000 * (1 - (1 + 0.10)^(-8)) / 0.10\)

Calculating this expression:

PV = \(13000 * (1 - 1.10^(-8)) / 0.10\)

= 13000 * (1 - 0.46318) / 0.10

= 13000 * 0.53682 / 0.10

= 6977.66 / 0.10

= 69776.6

Therefore, the present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.

For such more questions on present value

https://brainly.com/question/30390056

#SPJ8

Answer:

6mm

Step-by-step explanation:

A rectangle with all sides equal is a square

Area=a

36=a

a=6mm

Answer:

3

Step-by-step explanation:

\(\sqrt{9}=\sqrt{3*3} = 3\)

The statement about both functions that is true is:

The domain of a function is the set of values of input for which the function is valid.

The range is the dependent variable of a set of values for which the function is defined.

Given that:

f(x) = 4 - x

For function g(x) = -1 ×\(\mathbf{\sqrt{x-4}}\)

Therefore, from the given options, the statement about both functions that is true is:

Learn more about the domain of a function here:

https://brainly.com/question/1369616

#SPJ1

Answer:

Both f(x) and g(x) include domain values of [4, ∞), and both functions decrease over the interval (4, ∞).

Step-by-step explanation:

I got it right on the test.

The equation of the line that passes through the point (7, 6) with slope 0 is y = 6

Given,

The points which the line passes, (x₁, y₁) = (7, 6)

Slope of the line, m = 0

We have to find the equation of the line:

We know that,

y - y₁ = m(x - x₁)

So,

y - 6 = 0(x - 7)

y - 6 = 0

y = 6

That is,

The equation of the line that passes through the point (7, 6) with slope 0 is y = 6

Learn more about equation of line here:

https://brainly.com/question/25789778

#SPJ1

The function f(x) = -2(4)ˣ⁺¹ +140 represents the number of tokens a child has x hours after arriving at an arcade. The practical domain and range of the function are x ≥ 0 and The practical range of the situation is [140, ∞).

The given function is f(x) = -2(4)ˣ⁺¹+ 140, which represents the number of tokens a child has x hours after arriving at an arcade.

To determine the practical domain and range of the function, we need to consider the constraints and limitations of the situation.

For the practical domain, we need to identify the valid values for x, which in this case represents the number of hours the child has been at the arcade. Since time cannot be negative in this context, the practical domain is x ≥ 0, meaning x is a non-negative number or zero.

Therefore, the practical domain of the situation is x ≥ 0.

For the practical range, we need to determine the possible values for the number of tokens the child can have. Looking at the given function, we can see that the term -2(4)ˣ⁺¹represents a decreasing exponential function as x increases. The constant term +140 is added to shift the graph upward.

Since the exponential term decreases as x increases, the function will have a maximum value at x = 0 and approach negative infinity as x approaches infinity. However, due to the presence of the +140 term, the actual range will be shifted upward by 140 units.

Therefore, the practical range of the situation will be all real numbers greater than or equal to 140. In interval notation, we can express it as [140, ∞).

To summarize:

- The practical domain of the situation is x ≥ 0.

- The practical range of the situation is [140, ∞).

Know more about the domain here:
https://brainly.com/question/30096754

#SPJ8

Answer:

first and third expressions

Step-by-step explanation:

using the rule of exponents

\(\frac{a^{m} }{a^{n} }\) = \(a^{m-n}\)

then

\(\frac{3^{\frac{4}{9} } }{3^{\frac{2}{9} } }\)

= \(3^{\frac{4}{9}-\frac{2}{9} }\) ← first expression

= \(3^{\frac{2}{9} }\) ← third expression

Step-by-step explanation:

Using rules of logs :

9 loga x =  loga x^9

Then using another rule:

loga x^9 + loga y =   loga (x^9 * y )

The sum of the angles of the triangle expressed in two ways are x + 1/2x + 3/2x and 2x + x + 3x/2

It is important to note that the sum of the angles of a triangle is equal or equivalent to 180 degrees.

We have the angle measurements as;

Substitute the values

x + 1/2 x + 3/2x = 180

Find the lowest common multiple

2x + x + 3x /2 = 180

Add the numerators

6x/2 = 180

cross multiply

6x = 360

x = 60

Hence, the expression is x + 1/2x + 3/2x and 2x + x + 3x/2

Learn more about triangles here:

https://brainly.com/question/14285697

#SPJ1

Answer:

that's easy she ran 4 every day

Step-by-step explanation:

4x5 equals 20 for the first day she ran 4 second day 8 third 12 fourth 16 fifth 20

Answer:

Answer is the first one :)

Step-by-step explanation:

√(-7-5)² + (-7-9)²

answer is 20

hope this helps

Answer:

A.

Step-by-step explanation:

In the attached file

Answer: To solve for x in the equation x/9 = 7/15, we can cross-multiply to get:

15x = 9 * 7

Simplifying the right side, we get:

15x = 63

To solve for x, we can divide both sides by 15:

x = 63/15

Simplifying the fraction on the right side, we get:

x = 4 3/5 or x = 4.2 (rounded to one decimal place)

Therefore, the solution to the equation x/9 = 7/15 is x = 4.2 or x = 4 3/5.

Step-by-step explanation: kinda easy ngl lol but hope this helps :D

Answer:

(a) The earliest time that Ferdo can be back at Juno station is 12:15

Step-by-step explanation:

From the given table, we have;

The starting time for train departure from Juno = 07:15

The frequency of train departures from Juno = Every 20 minutes

The time of departure, 't₁' of first train that departs from Juno after 08:30 is given as follows;

The train departure times from Juno = 07:15, 07:35, 07:55, 08:15, 08:35

Therefore;

The time at which the first train departs from Juno after 08:30 = 08:35

The time it takes a train to travel from Juno to Odiham = 0:805 - 07:15 = 50 minutes

The time of arrival of the train Ferdo takes from Juno at Odiham = 08:35 + 50 minutes = 09:25

The number of hours Ferdo spends at Odiham = 2 hours

The time after which Ferdo departs from Odiham = 09:25 + 02:00 = 11:25

The time of departure of the train from Odiham after 11:25 = 08:05 + 20 minutes × 10

Therefore, the time of departure of the train from Odiham after = 11:25

The time it takes on the trip back to Juno from Odiham = 50 minutes

The earliest time that Ferdo can be back at Juno station = 11:25 + 50 minutes = 12:15

Answer:

Step-by-step explanation:

e = 61°, f = 119°, and d = 90°

We know that vertically opposite angles are equal.

So, e = 61° [Vertically opposite angles]

We know that linear pair of angles are supplementary (180°).

So, f + 61° = 180° [Linear pair of angles]

=> f = 180° - 61°

=> f = 119°

and d + 90° = 180° [Linear pair of angles]

=> d = 180° - 90°

=> d = 90°

The tangent line to f(x) = e ˣ at the point x = 2 has slope equal to f ' (2):

f(x) = e ˣ   →   f '(x) = e ˣ   →   f ' (2) = e ²

At x = 2, the function takes on a value of f (2) = e ². Use the point-slope formula to get the equation of the tangent line:

y - e ² = e ² (x - 2)

Solve for y :

y = e ² x - e ²

The missing variables on item 2 are given as follows:

The three trigonometric ratios are the sine, the cosine and the tangent of an angle, and they are obtained according to the formulas presented as follows:

For the angle of 60º, we have that:

Hence the length o is given as follows:

tan(60º) = o/12.

\(\sqrt{3} = \frac{o}{12}\)

\(o = 12\sqrt{3}\)

Applying the Pythagorean Theorem, the length i is given as follows:

i² = 12² + \((12\sqrt{3})^2\)

i² = 576

i² = 24²

i = 24.

A similar problem, also about trigonometric ratios, is given at brainly.com/question/24349828

#SPJ1

Answer:

o = 12√3

i = 24

Step-by-step explanation:

From observation of the given right triangle, we can see that two of its interior angles measure 60° and 90°. As the interior angles of a triangle sum to 180°, this means that the remaining interior angle must be 30°, since 30° + 60° + 90° = 180°. Therefore, the triangle is a special 30-60-90 triangle.

The side lengths in a 30-60-90 triangle have a special relationship, which can be represented by the ratio formula a : a√3 : 2a, where "a" represents a scaling factor that can be any positive real number.

In triangle #2, the shortest leg is 12 units.

As "a" is the shortest leg, the scale factor "a" is 12.

The side labelled "o" is the longest leg opposite the 60° angle. Therefore:

\(o = a\sqrt{3}=12\sqrt{3}\)

The side labelled "i" is the hypotenuse of the triangle. Therefore:

\(i= 2a = 2 \cdot 12=24\)

Therefore:

The correct answer is A: 600 <= money <= 2822.4.

This represents the range of possible values that Pankaj's accumulated money could fall into, given the specified conditions of the 3% interest rate compounded weekly for a maximum of 2 years. The lower bound, 600, represents the initial deposit amount, while the upper bound, 2822.4, represents the maximum amount of money Pankaj could earn after 2 years, assuming that interest is compounded every week.

Answer:

207,314

Step-by-step explanation:

V = πr2h =π  · 52·3 ≈ 235.61945 m^3

because 1m^3 = 1000 L, (27,535 / 1000) = the amount of added water in m^3. As this is equal to 27.535, we can substract this from 235.62.

235.62 - 27.535  is about 208.085, or 207.314 because of rounding. As this is in m^3, we multiply by liters to arrive at the answer of 207,314, or option D.

Hey there! I'm happy to help!

Let's call this number n. Here is the equation we can write.

(n-2)/3=30

We multiply both sides by 3.

n-2=90

We add 2 to both sides.

n=92.

Have a wonderful day! :D

Answer:

B, 6 inches

Step-by-step explanation:

The formula for area is width * height. If the area is the same in both times, increasing height means you must be decreasing width. B has a taller height so must have a shorter width.

7 and 1/2 = 15/2

45 / (15 / 2) = 45 * 2 / 15 = 6 inches

The art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper for proper distribution.

To determine the largest number of identical kits the art teacher can make using all the crayons and drawing paper, we need to find the greatest common divisor (GCD) of the quantities.

The GCD represents the largest number that can divide all the quantities without leaving a remainder.

The GCD of the quantities of crayons can be found by considering the prime factorization:

72 = 2³ × 3²

48 = 2⁴ × 3

48 = 2⁴ × 3

48 = 2⁴ × 3

The GCD of the crayons is 2³ × 3 , which is 24.

Now, we need to find the GCD of the quantity of drawing paper:

120 = 2³ × 3 × 5

The GCD of the drawing paper is also 2³ × 3 , which is 24.

Since the GCD of both the crayons and drawing paper is 24, the art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper.

Each kit would contain an equal distribution of crayons and drawing paper.

Learn more about distribution here:

brainly.com/question/30034780

#SPJ1