A target glider, whose mass m2 is 360 g, is at rest on an air track, a distance d = 53 cm from the end of the track. A projectile glider, whose mass m1 is 550 g, approaches the target glider with velocity v1i = -75 cm/s and collides elastically with it (see the figure). The target glider rebounds elastically from a short spring at the end of the track and meets the projectile glider for a second time. How far from the end of the track does this second collision occur ( cm)?
Answers
The second collision occurs 159.279 cm from the end of the track.
How do we calculate?We will use conservation of momentum and conservation of kinetic energy to solve for the velocities:
Conservation of momentum:
we have:
-41.25 kg*cm/s = 0.55 kg v1f + 0.36 kg v2f ... equation 1
conservation of kinetic energy :
1729.69 kg*cm^2/s^2 = 0.3025 kg v1f^2 + 0.162 kg v2f^2 ...equation 2
Solving for both velocities, we have:
v1f = -45 cm/s
v2f = 58.636 cm/s
Now we will use the time it takes for the target glider to travel from its initial position to the end of the track and back to find the distance from the end of the track where the second collision occurs:
The distance the target glider travels during this time is:
d2 = v2f t = (58.636 cm/s)(1.815 s) = 106.279 cm
in conclusion, the distance from the end of the track where the second collision occurs is:
53 cm + d2 = 159.279 cm from the end of the track.
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Related Questions
An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
Answers
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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A steel ball moves from a position of +125 meters to a position of -75 meters. This motion takes 90.0 seconds. What is the velocity of the steel ball?
Answers
Answer:
2.22m/s to the left
Explanation:
Given parameters:
Initial position = +125m
Final position = -75m
Motion time = 90s
Unknown:
Velocity of the steel ball = ?
Solution:
The velocity of the steel ball is given as the displacement divided by the time;
Velocity = \(\frac{displacement}{time}\)
The net displacement of the ball = 125- (-75) = 200m to the left
Input the parameters and solve for the velocity;
Velocity = \(\frac{200}{90}\) = 2.22m/s to the left
34. [8 Marks] A spring is compressed with a 5.0 kg mass by 20.0 cm from its equilibrium position. When the spring is released, the 5.0 kg mass travels along a smooth horizontal surface and then up a frictionless plane at 30° to the horizontal. Calculate the distance it would travel up the inclined plane before coming back down again.
Answers
Answer and Explaination:
To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.
1. Gravitational force:
The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.
2. Force exerted by the spring:
The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.
Given:
Mass (m) = 5.0 kg
Compression of the spring (x) = 20.0 cm = 0.20 m
Angle of the inclined plane (θ) = 30°
First, let's find the force exerted by the spring (F_spring):
F_spring = -kx
To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.
Next, let's calculate the gravitational force components:
Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ
Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ
Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.
At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).
Therefore, we have:
F_perpendicular = F_spring
mg * cosθ = -kx
Now, let's substitute the known values and solve for k:
(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m
49.0 N * 0.866 = -k * 0.20 m
42.426 N = -0.20 k
k = -42.426 N / (-0.20 m)
k = 212.13 N/m
Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:
PE_spring = (1/2) * k * x^2
PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2
PE_spring = 4.243 J
The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.
KE_max = PE_spring = 4.243 J
Next, we can calculate the height (h) the mass reaches on the inclined plane:
KE_max = m * g * h
4.243 J = 5.0 kg * 9.8 m/s^2 * h
h = 4.243 J / (5.0 kg * 9.8 m/s^2)
h = 0.086 m
The height the mass reaches on the inclined plane is 0.086 m.
Now, we can calculate the distance traveled.
A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.
Given data: Mass of the object, m = 5.0 kg, Displacement of the spring, x = 20.0 cm = 0.20 mAngle of the inclined plane, θ = 30°Calculating the spring constant, k. Using Hooke’s Law; F = -kx Where F is the restoring force required to bring the spring back to its equilibrium position.From the equation, F = ma For the object attached to the spring,m * a = -kx. On integrating,∫ma dt = -∫kx dt .On integrating the left side with limits from 0 to t and right side with limits from 0 to x, where the limits on the left are for acceleration and the right are for the displacement of the spring; mv - mu = -½ kx²At maximum compression, the velocity of the mass is zero, i.e., v = 0 and the initial velocity is also zero. Therefore, mv - mu = -½ kx²0 - 0 = -½ k (0.20)²∴ k = 25 N/mWork done on the spring in compressing it, W = ½ kx² = 0.5 * 25 * (0.20)² = 0.5 JSince the inclined plane is frictionless, the only force acting on the object will be the component of its weight acting along the plane. Hence, it will move up the incline with an acceleration of, a = g sin θ = 9.8 * sin 30° = 4.9 m/s²When the object has reached its maximum height, its velocity will be zero. Using the equation of motion; v² - u² = 2as0 - u² = 2as∴ s = u² / 2a. Now, the initial velocity of the object up the incline is,u = √(2gH)Where H is the height to which it climbs, and is given by, H = W / m g Where W is the work done on the object in lifting it to height H, and m is the mass of the object. W = 0.5 J, m = 5 kg. So, H = 0.5 / (5 * 9.8) = 0.0102 m∴ u = √(2gH) = √(2 * 9.8 * 0.0102) = 0.4525 m/sNow, the distance traveled by the object up the incline is,s = u² / 2a = (0.4525)² / (2 * 4.9) = 0.0214 m. When the object comes back down, it will travel the same distance down the incline, before coming to rest. Therefore, the total distance travelled up and down the incline is,2s = 2 * 0.0214 = 0.0428 m.For more questions on the spring constant
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A block having a mass of 0.8 kg is given an initial velocity v = 1.2 m/s to the right and collides
with a spring of negligible mass and force constant k = 50 N/m. Assuming the surface to be
frictionless, calculate the maximum compression of the
spring after the collision.
Answers
Answer:
The maximum compression of the spring after the collision is 0.15 m
Explanation:
Given data
Mass of the block (m) = 0.80 kg
Initial velocity (v) = 1.2 m/s
Spring constant (k) = 50 N/m
Find the maximum compression of the spring (x) after compression
Potential energy of the spring = Kinetic energy of the block
Kinetic energy of the block = 0.5 × (mv)²
Kinetic energy of the block = 0.5 × (0.80 × 1.2)²
Kinetic energy of the block =0.5 × 0.9216
Kinetic energy of the block = 0.4608 ---------->(1)
Potential energy of the spring = 0.5 × k × x²
Potential energy of the spring = 0.5 × 50 × x²
Potential energy of the spring = 25 x² ---------> (2)
Equate (1) and (2)
25 x² = 0.4608
x² = 0.018432 m²
x =0.1357 = 0.15 m
Therefore the maximum compression of the spring after collision is 0.15 m
Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and a market economy? E.1.2
How Economic Decisions are Made
By the Government,
command
economy
By the Consumers
mixed
economy
market.
economy
O Consumers make all economic decisions in a mixed economy, while the government makes all economic decisions in a market economy.
Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
Government makes all economic decisions in a mixed economy, while consumers make all economic decisions in a market economy.
O Consumers make economic decisions in a mixed economy, while consumers and government make economic decisions in a market economy.
Answers
Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
How do we explain?In a mixed economy, economic decisions are made by both the government and consumers.
The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.
In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.
The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.
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An object travels 7.5 m/s toward the west . Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s. What is its mass?
Answers
Answer:
m = 2218.67 kg
Explanation:
It is given that,
Initial velocity, u = 7.5 m/s
Final speed of an object, v = 0 (at rest)
Force, F = 5.2 kN
Time, t = 3.2 s
We need to find the mass of the object. Force acting on an object is given by :
F = ma
m is mass, a is acceleration
\(F=\dfrac{m(v-u)}{t}\\\\m=\dfrac{Ft}{v-u}\\\\m=\dfrac{5.2\times 10^3\times 3.2}{0-7.5}\\\\m=2218.67\ kg\)
So, the mass of the object is 2218.67 kg
The force is always equal to the product of mass and acceleration. The mass of the object is 2218.7 Kg.
An object travels 7.5 m/s toward the west.
Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s.
Now,
The initial velocity of the object is 7.5 m/s.
The final velocity of the object is 0 m/s.
The object comes to the rest position in 3.2 seconds.
The formula for finding the acceleration of the object is mentioned below:
\(v=u+at\\0=7.5+a \times 3.2\\a= -2.34375\;\rm m/s^2\)
The formula for finding the force is mentioned below:
\(F=ma\\-5.2 \times 10^3=m \times 2.34375\\m=2218.7 \ \;kg\)
Hence, the mass of the object is 2218.7 Kg.
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UASING THE SAME PICTURE FROM QUESTION 1: At which of the following sites would activity result in volcanoes, island arcs, and mountains?
answer choices
A
B
C
D
Answers
The site from above in which its activities would definitely result in island arcs, volcanoes and mountains is plate 2.
The correct answer choice is option b.
How the plate result in the formation of volcanic island arcsA volcanic arc simply refers to plates of volcanoes which are produced directly above a subducting oceanic tectonic plate. This belt or plate of volcanic arc is ultimately arranged an arc shape. This goes to say that it is formed when two different plates in the site of action collide against each other.
That being said, when two different pieces of plates collide against each other or it's smashing of plates together. It results in the formation of tectonic plates which at the end of the activities forms a mountain.
In conclusion, it can be deduced from the explanation given above that the smashing of plates with one another leads to the formation of volcanic island arcs.
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Which ray diagram demonstrates the phenomenon of absorption?
An illustration with a vector pointed right going through an opening in a boundary and splitting into 3 vectors. One up and to the right, one straight and one down to the right.
An illustration with a vector pointed right going through an opening in a boundary and turning into a transverse wave on the other side.
An illustration with a vector striking a boundary at an angle and a second vector coming off the boundary at the exact same angle.
Answers
Answer:
B
Explanation:
on edge
The illustration with a vector pointed right going through an opening in a boundary and turning into a transverse wave on the other side demonstrates the phenomenon of absorption, so, option B is correct.
What is absorption?Absorption, in wave motion, is the process by which a wave's energy is transferred to matter when the wave travels through it. The energy of an electromagnetic, acoustic, or other wave is related to the square of its amplitude, which is the maximum displacement or movement of a point on the wave.
The amplitude of a wave continuously diminishes as it travels through a substance. The medium is described as being transparent to a specific type of radiation if just a tiny portion of the energy is absorbed, whereas it is described as opaque if all the energy is lost.
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Please help me, it’s due tonight and I’m very confused!! THANK YOU
Answers
Explanation:
If your reaction time is 1 second, then the new reaction time for each is:
Alcohol: 0.30 × 1 + 1 = 1.30
Drugs: 0.50 × 1 + 1 = 1.50
Cell phone: 0.20 × 1 + 1 = 1.20
A machine has a velocity ratio of 5 and the efficiency is 80% what effort would be needed to lift a load of 200N
Answers
Explanation:
To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:
Efficiency = (Output Work / Input Work) * 100
Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.
Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.
Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."
Using the velocity ratio, we have the following relationship:
dE / dL = 5
Now, we can calculate the input work (Wi) and the output work (Wo):
Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)
Output Work (Wo) = Load (L) * Distance moved by the load (dL)
Given that the efficiency is 80%, we can rewrite the formula for efficiency as:
0.80 = (Wo / Wi) * 100
Now, let's solve for the effort (E) using the given values:
Load (L) = 200N
Efficiency = 0.80
Velocity Ratio = 5
First, calculate the output work (Wo):
Wo = Load (L) * Distance moved by the load (dL)
Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):
dL = (1/5) * dE
Wo = L * (1/5) * dE
Wo = 200N * (1/5) * dE
Wo = 40N * dE
Next, calculate the input work (Wi):
Wi = Effort (E) * Distance moved by the effort (dE)
Wi = E * dE
Now, substitute the values into the efficiency formula:
0.80 = (Wo / Wi) * 100
0.80 = (40N * dE) / (E * dE) * 100
0.80 = 40 / E * 100
0.80 * E = 40
E = 40 / 0.80
E = 50N
Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.
A 1.35 kg block is pulled across a flat, frictionless floor with a 3.07 n force at 32.0 above horizontal. What is the acceleration of the block
Answers
1. Calculating the horizontal component of the applied force:
Horizontal component = 3.07 N * cos(32.0°)
Horizontal component ≈ 2.597 N
2. Calculating the acceleration of the block:
Acceleration = Horizontal component / Mass
Acceleration = 2.597 N / 1.35 kg
Acceleration ≈ 1.925 m/s²
Therefore, the acceleration of the block is approximately 1.925 m/s².
A few years ago, the legal speed limit on the Turner Turnpike between Tulsa and Oklahoma City was changed from 55.0 mi/h to 75.0 mi/h. How much time was saved on the 86.0 mile trip for someone traveling at the legal speed limit? May I have help solving this?
Answers
Given
Speed one:
v1 = 55 mi/h
Speed two:
v2 = 75 mi/h
Distance:
x = 86 mi
Procedure
Let's calculate the times for each of the speeds.
\(\begin{gathered} t_1=\frac{x}{v_1} \\ t_1=\frac{86mi}{55mi/h} \\ t_1=1.56h \end{gathered}\)\(\begin{gathered} t_2=\frac{86mi}{75mi/h} \\ t2=1.14h \end{gathered}\)Saving time:
\(\begin{gathered} t_s=t_1-t_2 \\ t_s=1.56h-1.14h \\ t_s=0.42h \end{gathered}\)The total time saved is 0.42h (25.2min) by increasing the speed limit.
A mimibus drives with a constant speed of 39 km/h. how far can it travel in 1.94 hours?
Answers
Answer:
The minibus traveled 75.66 km
Explanation:
Motion with Constant Speed
An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.
The formula to calculate the speed is:
\(\displaystyle v=\frac{d}{t}\)
Where
v = Speed of the object
d = Distance traveled
t = Time taken to travel d.
From the equation above, we solve for d:
d = v . t
The minibus has a constant speed of v=39 km/h and it's required to find the distance it travels in t=1.94 hours.
Calculating the distance:
d = 39 km/h * 1.94 h
d = 75.66 km
The minibus traveled 75.66 km
1.2 Determine the total displacement of the diagram in FIGURE 1. 123 m 20⁰ (3) 72 m
Answers
The total displacement of the diagram in the velocity-time graph is 55 m.
What is the total displacement?To find total displacement from a velocity-time graph, the area under the curve of the graph is calculated.
Considering the given figure:
The area under the velocity-time graph is composed of two triangles ABF & DCE having area A₁ & A₂ respectively, and a rectangle BEIF having area A3.
The area of A₁ = (2- 0) × (5 - 0)/2 = 5 m
The area of A₂ = (10 - 5) × (10 - 6)/2 = 10 m
The area of A₃ = (5 - 0) * (10 - 2) = 40 m
The total area under the curve = A₁ + A₂ + A₃
The total area under the curve = 5 + 10 + 40 =
The total area under the curve = 55 m
Therefore, the total displacement is 55 m.
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Air currents escape room level 3 how to do it
Answers
Answer:
just do it. it's simple be smart friends
A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
Answers
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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Which is a similar theme in both "The Stag at the Pool" and "Hans in Luck"? O A. The things we think are valuable sometimes turn out not to be valuable after all. 0 B. It is important to know whom we can trust and whom we cannot O C. By working hard, we will end up with possessions that will make us feel successful. 0 D. The best things come in small packages.
Answers
A similar theme in both "The Stag at the Pool" and "Hans in Luck" is A. The things we think are valuable sometimes turn out not to be valuable after all.
In "The stag at the pool", a thirsty stag went to the pool to drink. As he bent over, he admired his antlers but despised his legs. He saw a lion and ran but his antlers got stuck in a tree and he was caught by the lion.
The theme in "Hans in Luck" shows that one doesn't need possessions to be happy. The character in the story had several possessions but was still unhappy. Both themes showed that the things we think are valuable sometimes turn out not to be valuable after all.
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If you drop an egg off of the Empire State Building, which of the following things will happen first?
O The egg will appear to hover
O Gravity and drag will fall into balance
O Drag will increase
O The net force will be zero
Answers
O Gravity and drag will fall into balance.
Explanation:
When an object, such as an egg, is dropped from a height, the force of gravity causes it to accelerate downwards. As the egg falls, it experiences air resistance, which opposes its motion and slows it down. This air resistance is called drag. As the speed of the falling egg increases, so does the force of drag, until it eventually becomes equal to the force of gravity. At this point, the egg will stop accelerating and will fall at a constant speed.
So, the first thing that will happen is that gravity and drag will fall into balance. The egg will continue to fall at a constant speed until it reaches the ground, at which point it will experience a sudden stop and likely break due to the impact.
Which statements correctly describe the effect of distance in determining the gravitational force and the electrical
force? Check all that apply.
The gravitational force has an infinite reach.
The electrical force has an infinite reach.
The gravitational force is inversely proportional to the distance.
U The electrical force is inversely proportional to the distance.
O The gravitational force is inversely proportional to the square of the distance.
O The electrical force is inversely proportional to the square of the distance.
Answers
The statements 1,4 and 5 accurately describe the influence of distance on gravitational and electrical forces.
What is Newton's law of gravity?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
Decreasing the distance would increase the gravity of the planet.
The following statements accurately describe the influence of distance on gravitational and electrical forces.
1. The gravitational force has an infinite reach.
4. The gravitational force is inversely proportional to the square of the distance.
5. The electrical force is inversely proportional to the square of the distance.
Hence, options 1,4 and 5 are correct.
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Raju completes one round of a circular track of diameter 200m in 30s. Calculate
a. The distance travelled by Raju
b. The magnitude of displacement travelled by Raju at the end of 30 s.
Answers
Explanation:
Given:
Diameter = 200 m
Radius, r = 200/2 = 100 m
Time taken, t = 30 seconds
Formula to be used:
Distance traveled, = circumference of circle = 2πr
Answer:
Putting all the values, we get
Distance traveled = 2πr
Distance traveled = 2 × 22/7 × 100 Distance traveled = 4400/7 Distance traveled = 628.57 mSo, the distance traveled by Raju is 628.57 m.
Now, magnitude of the displacement,
At the end of 30 seconds, Raju will come to starting position or initial position, so displacement is zero.
A hot air balloon is rising upward with a constant speed of 3.80m/s. When the balloon is 4.25m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground
Answers
We can calculate the time taken by the compass to hit the ground by using kinematic equations of motion. The motion of the compass is a free-fall motion since it is only under the influence of gravity. When the compass is dropped, it is initially at rest.
After that, it falls down to the ground with the acceleration due to gravity. Given that the balloon is rising upward with a constant speed of 3.80m/s. Hence, the velocity of the compass when it is dropped will be equal to the velocity of the balloon, which is 3.80m/s. The acceleration due to gravity is 9.81m/s². We can use the following kinematic equation of motion to calculate the time taken by the compass to hit the ground: `y = vi * t + 0.5 * a * t²`, where `y` is the height, `vi` is the initial velocity, `a` is the acceleration, and `t` is the time taken.We know that the initial height of the compass is 4.25m, the initial velocity is 3.80m/s, and the acceleration due to gravity is 9.81m/s². We need to find the time taken by the compass to hit the ground. Using the above kinematic equation, we get:`0 = 3.80t + 0.5 * 9.81 * t²`Simplifying the equation, we get:`4.905t² + 3.80t = 0`Factorizing the equation, we get:`t(4.905t + 3.80) = 0`Solving for `t`, we get:`t = 0` (since time cannot be negative)`t = -3.80/4.905 = -0.776s`We ignore the negative value of time since time cannot be negative. Hence, the time taken by the compass to hit the ground is `t = 0.776s`.Answer: `0.776s`For such more question on acceleration
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In hiking, what fitness component is required of you
Answers
Select the correct answer.
A Kelvin (K) is a unit of measurement in the International System of Units. Which quantity is measured in Kelvin?
Group of answer choices
length
electric current
mass
temperature
weight
Answers
Answer: Temperature
Explanation:
How is it possible for man made things to move?
Answers
Explanation:
Natural things are all the elements present in the world. Whatever is there because of nature, like petrolium and coal which is developed over thousands and millions of year process. There are many more, like even living things do come inside the circle of natural things, because man can not make life we can alter it examples can be found on your dining table, fruits and vegetables. Over the period of time humans have altered the genes of fruits and vegetables to grow the way they want example seedless grapes, seedless banana etc.
8. Combine the ice and the room-temperature water. Stir the mixture until the thermometer stays at the
same temperature for at least 1 minute. This means the thermometer is at the same temperature as the
mixture.
9. Record the temperature.
10. Stir the ice-water mixture occasionally for another 5 minutes. Then, record its temperature.
Table B: Part 2 Observations
Initial temperature (in "C) of the room-temperature water
Initial temperature (in "C) of the warm water
Temperature (in "C) of mixed warm water and room-temperature water
Temperature (in "C) of mixed warm water and room-temperature water after 5 min
Temperature (in "C) of mixed warm water and room-temperature water after 10 min
Initial temperature (in "C) of the ice
Temperature (in °C) of mixed ice and room-temperature water
Temperature (in "C) of mixed ice and room-temperature water after 5 min
Physical Science page
Answers
The answer for the experiment is obtained by the principle of Newton's law of cooling. The initial temperature of the Room is taken as 32°C.
The ice cubes are mixed with room-temperature water, the ice starts to melt and the water becomes cold. This is because the ice and water have two different temperatures and when they are mixed there is an exchange of heat is taken place. When the ice cubes mixed with water the room temperature is decreases from 32°C. After stirring the mixture because of the heat released, the temperature increases.
When the ice-water mixture is stirred, the heat energy is evolved which melts the ice in the mixture, and therefore the temperature increases gradually. And stirring of water for every 5 minutes leads ice cubes to melt completely to form water and the level of water increases in the final stage. This was given by Newton's law of cooling.
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A penny sinks to the bottom of a wishing well
What type of frictional force is that?
Answers
The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.
2. List down the following:
(a) The next four odd numbers after 107.
(b) Four consecutive even numbers between 2008 and 2030
(c) All odd numbers between 993 and 1007.
3. State whether the following will be odd or even.
(a) The sum of two odd numbers.
(b) The sum of two even numbers. I
(c) The sum of an odd and an even number.
Answers
Answer:
2
a) 109, 111, 113, 115
b) An odd number always follows an even number. So there can't be four consecutive even numbers. 2009, 2011, 2013, 2015 are the next odd numbers between 2008 and 2030.
c) 995, 997, 999, 1001, 1003, 1005, 1007
3
a) The sum of two odd numbers will result in an even number.
b) The sum of two even numbers will result in an even number.
c) The sum of an odd and an even number will result in an odd number.
When you move your muscles, chemical energy in the cells is converted into mechanical and thermal energy. What is this an example of? (2 points)
Answers
Answer:
Law of conservation of energy
Explanation:
In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. This law means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.
Answer:
Law of consevation of energy
Explanation:
This is because you are transforming the energy as well as conserving it in diffrent ways.
How does the paddle and water in this photo demonstrate newtons third law? The action force is the __ against the __. The reaction force is the __ pushing back against the ___.
Answers
The action force is the oar against the water.
The reaction force is the water pushing back agrains the oar.