The statement that a teacher sitting in her rolling chair pushes against the wall and moves in the opposite direction exemplifies the third law of motion by Newton.
What is Newton's third law of motion?Newton's third law of motion states that for every action, there is an equal and opposite reaction.
This law describes the nature of a force as the result of a mutual and simultaneous interaction between an object 1 and a second object 2.
According to Newton's third law of motion, whenever two objects A and B interact with each other, they both exert equal but opposite forces upon each other.
Therefore, the statement that a teacher sitting in her rolling chair pushes against the wall and moves in the opposite direction exemplifies the third law of motion by Newton.
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what are the limiting and excess reactants to CO(g) + 2H2 - CH3OH if 1.55 moles of CO react with 1.22 moles of H2
CO + 2(H2) ----- CH3OH, this is the reaction we obtaine, now based on moles we have to find what hapen if we change the moles
1.55(CO) + 1.22(H2) ---- n(CH3) + m(OH)
We have:
1.55 C
1.55 O
2.44 H
And we need:
1 C
1 O
4 H
The difference are:
0.55 C, excess
0.55 O, excess
1.56 H, limiting
Your friend asks you for a glass of water and you bring her 5 millilitersof water. Is this more or less than what she was probably expecting?Explain your reasoning
how many pattern block hexagons would 2 trapezoids create
To make two hexagons out of pattern blocks, you need 12 trapezoids.
Explain about the term hexagons?A closed, two-dimensional polygon containing six sides is what is known as a hexagon. Six vertices and six angles make up a hexagon.
You need to utilize a total of 12 trapezoids to make two hexagons using pattern blocks. You will also need 2 hexagons to employ all twelve trapezoids because each hexagon has six trapezoids in it. Trapezoids can be arranged in a pattern with two triangles, 2 parallelograms, 2 rhombuses, and 2 trapezoids to create the two hexagons. These 12 trapezoids can be used to form two full hexagons.Thus,
You need 12 trapezoids to build two hexagons out of pattern blocks.Six trapezoids form each hexagon.Since you require two hexagons, a total of 12 trapezoids are required.To know more about the hexagons, here
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The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
A sled plus passenger with total mass m = 53.1 kg is pulled a distance d = 25.3 m across a horizontal, snow-packed surface for which the coefficient of kinetic friction with the sled is μk = 0.155. The pulling force is constant and makes an angle of φ = 28.3 degrees above horizontal. The sled moves at constant velocity.
Required:
a. Write an expression for the work done by the pulling force in terms of m, g (acceleration due to gravity), φ, μk, and d.
b. What is the work done by the pulling force, in joules?
c. Write an expression for the work done on the sled by friction in terms of m, g (acceleration due to gravity), φ, μk, and d.
d. What is the work done on the sled by friction, in joules?
Answer:
Explanation:
Force of friction
F = μ mg
μ is coefficient of friction , m is mass and g is acceleration due to gravity .
If f be the force applied to pull the sled , the horizontal component of force should be equal to frictional force
The vertical component of applied force will reduce the normal force or reaction force from the ground
Reaction force R = mg - f sin28.3
frictional force = μ R where μ is coefficient of friction
frictional force = μ x (mg - f sin28.3 )
This force should be equal to horizontal component of f
μ x (mg - f sin28.3 ) = f cos 28.3
μ x mg = f μsin28.3 + f cos 28.3
f = μ x mg / (μsin28.3 + cos 28.3 )
a )
work done by pulling force = force x displacement
f cos28.3 x d
μ x mg d cos28.3 / (μsin28.3 + cos 28.3 )
b ) Putting the given values
= .155 x 53.1 x 9.8 x 25.3 cos28.3 / ( .155 x sin28.3 + cos 28.3 )
= 1796.76 / (.073 + .88 )
= 1885.37 J
c )
Work done by frictional force
= frictional force x displacement
= - μ x (mg - f sin28.3 ) x d
= - μ x mgd + f μsin28.3 x d
= - μ x mgd + μsin28.3 x d x μ x mg / (μsin28.3 + cos 28.3 )
d )
Putting the values in the equation above
- .155 x 53.1 x 9.8 x 25.3 +
.155 x .474 x 25.3 x .155 x 53.1 x 9.8 /( .155 x .474 + .88)
= -2040.67 + 149.92 / .95347
= -2040.67 + 157.23
= -1883.44 J .
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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An engineer wants to design a go-kart that can reach an acceleration of 20 m/s2. If the cart has a mass of 75 kg and can hold one person with a mass of 80 kg, the engineer must design an engine that can produce a force of
newtons.
The engineer must design an engine that can produce a force of over 3,100 Newtons.
What is a Force?A force is an energy that can cause change of motion. It can be a push or a pull. It also has both magnitude and direction, making it a vector quantity.
From the question;
total mass = mass of person + mass of cart
total mass = 80kg + 75kg
total mass = 155kg
acceleration = 20m/s²
The formula to be used;
F = m x a
F = 155kg x 20m/s²
F = 3,100N
In conclusion, the engineer needs a minimum force of 3,100 N in the engine to be able to power the cart.
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How much is 813 in grams
I Math
To convert 813 into grams if it is already in grams, then the value remains as 813 grams. If it is in pounds, 813 pounds would be approximately 368,646.696 grams. If it is in kilograms, 813 kilograms would be equal to 813,000 grams.
To convert 813 into grams, we need to know the unit of measurement you're referring to. Grams are typically used to measure the weight of objects, but without additional context, it's difficult to provide an accurate answer.
If you are referring to 813 grams, then the conversion is straightforward, as it is already in grams.
If you are referring to another unit, such as pounds or kilograms, we can convert it to grams:
If you meant 813 pounds, one pound is approximately equal to 453.592 grams. Therefore, 813 pounds would be approximately 368,646.696 grams.
If you meant 813 kilograms, one kilogram is equal to 1,000 grams. Therefore, 813 kilograms would be equal to 813,000 grams.
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An organ pipe of length L has one end closed but the other end open. What is the wavelength of the fundamental node emitted?
a. Slightly smaller than 4 L
b. Slightly larger than 4 L c. Roughly equal to 3/2
d. Slightly larger than 2 L
Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores
Explanation:
What is the acceleration of a car with the mass of 1,980 kg with
a net horizontal force of 1,000 N?
The acceleration of a car with the mass of 1,980kg with a net horizontal force of 1,000 N is 0.51m/s².
HOW TO CALCULATE ACCELERATION?The acceleration of a body can be calculated using the following formula:
a = F ÷ m
Where;
a = acceleration (m/s²)F = Force (N)m = mass (kg)According to this question, a car has a mass of 1980kg and horizontal force of 1000N. The acceleration is as follows:
a = 1000/1980
a= 0.51m/s²
Therefore, the acceleration of a car with the mass of 1,980kg with a net horizontal force of 1,000 N is 0.51m/s².
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A 3.0-kilogram object initially at rest explodes and splits into three fragments. One fragment has a mass of 0.50 kg and flies off along the negative x axis at a speed of 2.8 m/s, and another has a mass of 1.3 kg and flies off along the negative y axis at a speed of 1.5 m/s.
Required:
What are the speed and direction of the third fragment?
Answer:
The speed and direction of the third fragment are 2 meters per second and 54.316º, respectively.
Explanation:
The object is not under the influence of any external force, meaning that Principle of Momentum Conservation to calculation of the velocity of the third fragment:
\((m_{1}+m_{2}+m_{3})\cdot \vec {v}_{o} = m_{1}\cdot \vec v_{1} + m_{2}\cdot \vec v_{2} + m_{3}\cdot \vec v_{3}\) (1)
Where:
\(m_{1}\), \(m_{2}\), \(m_{3}\) - Masses of the first, second and third fragments, in kilograms.
\(\vec v_{o}\) - Initial velocity of the object, in meters per second.
\(\vec v_{1}\), \(\vec v_{2}\), \(\vec v_{3}\) - Velocities of the first, second and third fragments, in meters per second.
If we know that \(m_{1} = 0.5\,kg\), \(m_{2} = 1.3\,kg\), \(m_{3} = 1.2\,kg\), \(\vec v_{o} = (0,0)\,\left[\frac{m}{s} \right]\), \(\vec v_{1} = \left(-2.8, 0\right)\,\left[\frac{m}{s} \right]\) and \(\vec v_{2} = \left(0,-1.5\right)\,\left[\frac{m}{s} \right]\), the velocity of the third fragment is:
\((-1.4,0) + (0,-1.95) + 1.2\cdot \vec v_{3} = (0,0)\)
\(1.2\cdot \vec v_{3} = (1.4,1.95)\)
\(\vec v_{3} = (1.167, 1.625)\,\left[\frac{m}{s} \right]\)
The speed of the third fragment is the magnitude of the result found above:
\(v_{3} = 2\,\frac{m}{s}\)
And the direction of the third fragment is:
\(\theta_{3} = \tan^{-1} \left(\frac{1.625}{1.167}\right)\)
\(\theta_{3} \approx 54.316^{\circ}\)
The speed and direction of the third fragment are 2 meters per second and 54.316º, respectively.
To better understand crash dynamics we have to look at "__________."
A. the law of gravity
B. Bernoulli's principle
C. the laws of motion
D. Archimedes' principle
To better understand crash dynamics we have to look at "the laws of motion."
The laws of motion
The laws of motion were introduced by Sir Isaac Newton in 1687 in his book Philosophiæ Naturalis Principia Mathematica ("Mathematical Principles of Natural Philosophy"), which defined the laws of motion, or three fundamental laws that govern the movement of bodies. The laws of motion, according to Newton, govern the motion of an object or a system of objects that interact.
It defines the concepts of force and mass, and the fundamental dynamics of motion.The following are the laws of motion:Every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. The velocity of an object changes proportional to the force applied to it, and the acceleration of an object is proportional to both its force and its mass. For every action, there is an equal and opposite reaction.
Therefore, these laws are necessary to fully grasp crash dynamics because they explain how objects respond to outside forces that cause them to accelerate or decelerate.
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A 150kg diver jumps off a diving board and hits the water at 40 m/s
What is the kinetic energy of the diver entering the water?
This is an exercise in kinetic energy, which is a form of energy associated with the movement of an object and its speed. It is important in many areas of physics, from classical mechanics to modern physics. This form of energy can be transformed into other forms of energy, such as thermal energy, sound energy or electrical energy. The formula for calculating kinetic energy is KE = m * v^2/2, where m is the mass of the object and v is its speed.
Kinetic energy is a fundamental concept in classical mechanics. It is used to analyze the movement of objects and calculate the amount of work required to stop them. When an object is in motion, it has kinetic energy, which is equal to half its mass times its speed squared. If the object collides with another object, some of its kinetic energy is transferred to the second object in the form of work or heat.
Kinetic energy is also important in modern physics. In Einstein's theory of special relativity, the mass of a moving object increases with its speed, which means that its kinetic energy also increases. In fact, the kinetic energy of a moving object is a form of energy that is included in Einstein's famous equation E=mc^2, where E is the energy, m is the mass of the object, and c is the speed of light. . This equation shows how the mass of an object and its energy are related.
Kinetic energy is also important in quantum physics. In quantum mechanics, particles have a property called momentum, which is a measure of their motion. Momentum and kinetic energy are related, and experiments in quantum physics often measure the momentum and kinetic energy of particles.
It tells us that the diver has a mass of 150 kg, and that he jumps from a diving board into the water at a speed of 40 m/s.
They ask us what is the kinetic energy of the diver who enters the water?We know that the formula for kinetic energy is:
KE = m * v^2/2. We should not do the formula clearance, because we are going to calculate the kinetic energy.
We already know our data from the formula, now we substitute and solve, then
KE = (m × v²)/2
KE = (150 kg × (40 m/s)²)/2
KE = (150 kg × 1600 m²/s²)/2
KE = 120000 J
When the diver enters the water, the kinetic energy is 120,000 J.
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Answer:
The kinetic energy of the diver entering the water is 120,000 Joules.
Explanation:
The kinetic energy (KE) of an object is given by:
\(\sf\qquad\dashrightarrow KE = \dfrac{1}{2} * m * v^2\)
where:
m is the mass of the objectv is its velocity.Plugging in the given values, we get:
\(\sf\qquad\dashrightarrow KE = \dfrac{1}{2} * 150\: kg * (40\: m/s)^2\)
\(\sf\qquad\dashrightarrow KE = \dfrac{1}{2} * 150\: kg * 1600\: m^2/s^2\)
\(\sf\qquad\dashrightarrow KE = \boxed{\bold{\:\:120,000\: J\:\:}}\)
Therefore, the kinetic energy of the diver entering the water is 120,000 Joules.
An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the
right. What is the displacement of the object?
1
5
7
13
Answer: 5
Explanation: If you use a real graph it could be easier to check, but here’s it the easy way.
You start at 0, add 3 as you are going right on the right , subtract 4 as you are going left, then again add 6 as you are going right, and you should get 5.
0+3= 3
3-4= -1
-1+6= 5
What is the relationship between MASS and DENSITY?
As well as VOLUME and DENSITY?
Let’s say you have a cart of some mass and when pushed with 10N of force, the cart accelerates at 5.0 m/s/s. If you were to push the same cart with a 20N force:
a. The acceleration would increase
b. The acceleration would decrease
c. The acceleration would remain the same
Answer:
a. The acceleration would increase.
Explanation:
because we know that
F=ma
m= mass and a= acceleration
so Mass is same for the cart in any situation that's why only acceleration could increase.
Answer:
A
Explanation:
because when the cart is pushed at 10N it at 5.0 the when u increase the N it will keep on increasing...
A car starts from rest and accelerates uniformly over a time of 5 second and reaches a velocity of 122 m/s. Determind the acceleration of the car.
Answer:
23.44444444
Explanation:
Name two examples of conservative forces
I’n a miracle of modern physics a 20.0-kg frictionless…
The acceleration of the lawn mower is 1.25 m/s².
The velocity of the lawn mower at the given time is 6.25 m/s.
What is the acceleration of the lawn mower?
The acceleration of the lawn mower is calculated by applying Newton's second law of motion as shown below.
Fx = ma
where;
Fx is the horizontal component of the forcem is the mass of the lawn mowera is the acceleration of the lawn mowerF cosθ = ma
where;
θ is the inclination of the force.a = ( F cosθ ) / m
a = ( 50 N x cos60 ) / 20 kg
a = 1.25 m/s²
The velocity of the lawn mower at the given time is calculated as;
v = at
v = 1.25 m/s² x 5 s
v = 6.25 m/s
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When monochromatic light passes through the interface between two unknown materials at an angle θ where 0∘<θ<90∘, no changes in the direction of propagation of light are observed. What can be said about the two materials? Check all that apply. View Available Hint(s) Check all that apply. The two materials have matching indexes of refraction. The second material through which light propagates has a lower index of refraction. The second material through which light propagates has a higher index of refraction. The two materials are identical.
Answer:
the correct one is the first, the refractive index of the two materials must be the same
Explanation:
When a beam of light passes through two materials, it must comply with the law of refraction
n₁ sin θ₁ = n₂ sin θ₂
where n₁ and n₂ are the refractive indices of each medium.
In this case, it indicates that the light does not change direction, so the input and output angle of the interface must be the same,
θ₁ = θ₂ = θ
substituting
n₁ = n₂
therefore the refractive index of the two materials must be the same
When reviewing the answers, the correct one is the first
The equation of a transverse wave is
y(x, t) = 0.02 cos(10(pi)x - 400(pi)t)
where the units are SI.
The velocity of the wave is
a. 0.20 m/s
b. 8 m/s
C. 40 m/s
d. 0.20 km/s
e. 0.407 km/s
Answer:
C 40 m/s the velocity of WAve
How much thermal energy is required for liquid water to turn in to a gas on
Mars?
O 100°C
O 10°C
0 212°C
O 50°C
Answer:
thanks you too for boys sweater in parallel and remember word on mangal I can do a few
Explanation:
free download in every way you are you sure about my experience with the same you for the following information to facilitate this answer and I can do the same to your email program I was not understand you want with you on Monday to Thursday morning I was speaking and listening at a later flight andTwo unknown materials have a coefficient of kinetic friction of 1.3. Without
any further information, which of the following options is most likely to be the
coefficient of static friction?
A. 1.2
B. 1.7
C. O
D. -1.3
Answer:c
Explanation:
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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a method of reducing friction
Answer:
Lubrication
Explanation:
People oil/lubricate bicycle chains because the chain turns around the cogs and rub together so this help with friction.
Hope this helps :)
Answer:
The method of reducing friction are :
i) In moving parts of machine friction can be reduced by using a ball bearing between the moving surfaces
ii) The bodies of aeroplane ,ship ,boat etc are made streamlined to reduce friction.
iii) Friction can be reduced by polishing rough surfaces. For example : carrom boards are highly polished to reduce friction.
I hope this help you:)
A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s direction 5° north of east for an hour. What is the magnitude of the boat's resultant velocity? Round your answer to the nearest whole number. m/s What is the direction of the boat's resultant velocity? Round your answer to the nearest whole degree. • north of east
The boat’s resultant velocity is v = 31.0 m/s, and the direction of the boat is 23.2 degrees north of east.
A resultant velocity is calculated using the formula below.
Vm equals Sum Sqrt(Vxi2 + VYj2)
where Vm is the resulting magnitude of velocity.
All x-component velocities are denoted by the letters Vxi.
The y-component of all velocities is called Vyj.
Add all of the values for the x-components together, square that number to get the magnitude of the resultant velocity. Add this to the earlier value after doing the same operation for the y-components. Finally, to determine the magnitude, square the result.
Tan-1 (Vx/Vy) = Va
where Va is the resultant velocity's angle.
Vx is the size of the resultant velocity's x-component.
Vy is the size of the resultant velocity's y-component.
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In a 2-dimensional Cartesian coordinate system the y-component of a given vector is equal to that vector's magnitude multiplied by which trigonometric function, with respect to the angle between vector and y-axis?
a. sine
b. cosine
c. tangent
d. cotangent
Answer:
Option b, cosine.
Explanation:
Below you can see an image that illustrates this situation.
Remember that for a triangle rectangle with a given angle θ, we have:
Cos(θ) = (adjacent cathetus)/(hypotenuse)
In the image, you can see a vector of magnitude M, and the angle θ defined between the vector and the positive y-axis.
In this case, the y-component is the adjacent cathetus and the hypotenuse is the magnitude of the vector.
Then we will have:
Cos(θ) = (adjacent cathetus)/(hypotenuse) = y/M
solving that for y, we get:
y = Cos(θ)*M
Then the y-component is the vector's magnitude multiplied by the cosine of the angle between the vector and the y-axis.
The correct option is b.
Answer:
(b) cosine
Explanation:
In a 2-dimensional Cartesian coordinate system, a vector has a x-component and/or a y-component. To get these components, the magnitude of the vector is resolved with respect to the x-axis and the y-axis by multiplying it (the magnitude) by some trigonometric function with respect to the angle between the vector and the x or y axis.
For example, given a vector A of magnitude A which makes an angle α with the x-axis and an angle β with the y-axis, the x and y components of the vector A can be found as follows;
i. x-component is given by \(A_{x}\)
\(A_{x}\) = A cos α (with respect to the angle between A and the x-axis) or
\(A_{x}\) = A sin β (with respect to the angle between A and the y-axis)
ii. y-component is given by \(A_{y}\)
\(A_{y}\) = A sin α (with respect to the angle between A and the x-axis) or
\(A_{y}\) = A cos β (with respect to the angle between A and the y-axis)
Therefore, the y-component of a vector in a 2-dimensional Cartesian coordinate is given by the product of the magnitude of the vector and the cosine of the angle between the vector and the y-axis.
Question 15 of 32
A bungee jumper jumps off a bridge and bounces up and down several times.
She finally comes to rest 30 m below the bridge from which she just jumped.
If her mass is 50 kg and the spring constant of the bungee cord is 10 N/m,
how much energy was lost due to air resistance while she was bouncing?
(Recall that g = 9.8 m/s²)
A. 7330 N
B. 9200 N
C. 10,200 N
D. 8605 N
C. 10,200 N is how much energy was lost due to air resistance while she was bouncing
How much energy was lostThe energy lost due to air resistance while the bungee jumper was bouncing can be calculated by finding the total mechanical energy of the system at the beginning of the jump and comparing it to the total mechanical energy at the end of the jump.
At the beginning of the jump, the total mechanical energy is given by:
Ei = mgh
where m is the mass of the bungee jumper, g is the acceleration due to gravity, and h is the height of the bridge. Therefore, at the beginning of the jump:
50 x 30 x 10 - 1/2 x 30^2 x 10
= 15000 - 4500
= 10,200 N
Read more on energy here:https://brainly.com/question/13881533
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