The angular magnification of the telescope can be calculated by dividing the focal length of the objective lens by the focal length of the eyepiece. In this case, the angular magnification is 24,000 times.
The angular magnification of a telescope is determined by the ratio of the focal length of the objective lens to the focal length of the eyepiece.
In this case, the focal length of the objective lens is given as 1200 mm, which can be converted to meters by dividing by 1000, resulting in 1.2 m. The focal length of the eyepiece is given as 0.050 m.
To calculate the angular magnification, we divide the focal length of the objective lens by the focal length of the eyepiece: 1.2 m / 0.050 m = 24. Thus, the angular magnification of the telescope is 24,000 times. This means that the telescope will make objects appear 24,000 times larger than they would be when observed with the eye.
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It is diffult to measure the volume of gas.Why?
Answer:
The volume of a gas is dependent on pressure and temperature.
Explanation:
Pressure and temperature affect different gases differently giving varied conclusions to the exact volume of that gas.
:-befrank
a basketball rolling across a flat floor has___ energy. PLZ HELP
Answer:
kinetic energy
Explanation:
I know the answer because Im built differen
energy a moving object has because of its motion it’s called ?
Kinetic or potential energy....
Explain what effect greenhouse gasses have on climate. How do they have this effect?
Answer:
Greenhouse gases have far-ranging environmental and health effects. They cause climate change by trapping heat, and they also contribute to respiratory disease from smog and air pollution. Extreme weather, food supply disruptions, and increased wildfires are other effects of climate change caused by greenhouse gases.
Explanation:
:) YW
Answer:
according to scientists greenhouse gasses, include co2 which can heat up the climate. cars and factorys creat co2 admission which cause global warming
as manifold pressure increases in a reciprocating engine, the
As manifold pressure increases in a reciprocating engine, the the density of the air being taken into the cylinders increase.
What is manifold pressure?The air pressure inside a reciprocating engine's induction system is measured in absolute terms by the manifold pressure. The density of the air being drawn into the cylinders increases with increasing manifold pressure.
The power output of an aviation engine is gauged by manifold pressure. It is the difference between the pressure in the engine's intake manifold and the pressure in the atmosphere. The manifold pressure indicates the amount of power the engine is producing. In a reciprocating engine, the density of the air entering the cylinders rises as manifold pressure rises.
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The water from a fire hose follows a path described by y=4.0+0.8x-0.40x^(2) (units are in meters ). If v_(x) is constant at 5.0(m)/(s), find the resultant velocity at the point (2.0.4.0). Find velocity of water
The velocity of the water at the given points (2.0, 4.0) is approximately 5.06 m/s.
To find the velocity of the water at the point (2.0, 4.0), we need to calculate its components: the horizontal velocity (v_x) and the vertical velocity (v_y).
Given that v_x is constant at 5.0 m/s, the horizontal velocity component remains the same regardless of the position.
To find the vertical velocity component, we can differentiate the equation for the path of the water with respect to x:
y = 4.0 + 0.8x - 0.40x^2
Differentiating both sides with respect to x:
dy/dx = d/dx (4.0 + 0.8x - 0.40 \(x^2\))
= 0 + 0.8 - 0.80x
Now, substitute the x-coordinate of the point (2.0, 4.0) into the derivative:
dy/dx at x = 2.0 = 0.8 - 0.80(2.0)
= 0.8 - 1.6
= -0.8 m/s
Therefore, the vertical velocity component (v_y) at the point (2.0, 4.0) is -0.8 m/s.
To find the resultant velocity (v) at that point, we can use the Pythagorean theorem:
v = \(\sqrt{v_x^2 + v_y^2}\)
\(= \sqrt{5.0^2 + (-0.8)^2}\)
\(= \sqrt{25.0 + 0.64}\)
\(= \sqrt{25.64}\)
\(\approx 5.06 , \text{m/s}\)
Hence, the velocity of the water at the point (2.0, 4.0) is approximately 5.06 m/s.
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I have to finish this by 6 am today please somebody help me
A golf ball with a speed of 8m/s rebounds at 45 degrees with a speed of 6m/s. What is the magnitude of the ball's change in velocity?
The magnitude of the ball's change in velocity is approximately 2.2 m/s.
The change in velocity of the golf ball can be calculated using the vector subtraction of the initial velocity vector from the final velocity vector.
Initial velocity = 8 m/s at an angle of 0 degrees (since it is not specified in which direction the ball is traveling)
So, the initial velocity vector can be written as:
vi = 8 m/s [0 degrees]
Final velocity = 6 m/s at an angle of 45 degrees (since it rebounds at 45 degrees)
So, the final velocity vector can be written as:
vf = 6 m/s [45 degrees]
Now, we can calculate the change in velocity vector:
Δv = vf - vi
To do this, we need to resolve the velocity vectors into their x and y components:
vi = (8 cos 0) i + (8 sin 0) j = 8i
vf = (6 cos 45) i + (6 sin 45) j = (6/√2)i + (6/√2)j
Now we can calculate the change in velocity vector as:
Δv = vf - vi = [(6/√2) - 8]i + [(6/√2)]j
To find the magnitude of the change in velocity, we use the Pythagorean theorem:
|Δv| = √[(6/√2 - 8)²+ (6/√2) ²] ≈ 2.2 m/s
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Venn diagrams show the similarities and differences between two items being compared. Similarities are listed where the circles overlap, and differences are listed where the circles are not overlapping. This Venn diagram is looking at different kinds of technologies.
Which titles best describe this diagram?
Title 1 should be Microtechnology, and Title 2 should be Nanotechnology.
Title 1 should be Nanotechnology, and Title 2 should be Microtechnology.
Title 1 should be Quantum Mechanics, and Title 2 should be Traditional Physics.
Title 1 should be Traditional Physics, and Title 2 should be Quantum Mechanics.
Venn diagram should be titled traditional physics
Based on the Venn Diagram, Title 1 should be Quantum Mechanics, and Title 2 should be Traditional Physics.
What is a Venn Diagram?A Venn Diagram is a diagram which shows the similarities as well as differences between two or more items.
Overlapping points show similarities while non-overlapping points show differences.
The Venn Diagram above illustrates Traditional physics and quantum mechanics.
Title 1 is quantum mechanics and Title 2 is Traditional physics.
Therefore, the Venn Diagram illustrates the difference and similarities between quantum physics and traditional physics.
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a car starts from rest and increases its velocity at constant rate until it reaches a speed of 20 m/s in 5 seconds what is the acceleration of the car
Answer:
4m/s²
Explanation:
initial velocity(u)=0m/s
final velocity (v)=20m/s
time taken(t)=5 sec
Acceleration of car(a)=(v-u)/t
=(20-0)/5
= 20/5
=4m/s²
I WILL MARK YOU THE BRAINLIEST NO LINKS
There are 4 springs stretched by the same mass. Spring A stretches 25 cm. Spring B stretches 10 cm. Spring C stretches 100 cm. Spring D stretches 1 cm. Which spring is strongest?
A
B
C
D
yeah definitely spring c
A packing crate slides down an inclined ramp at a constant velocity. Thus we can deduce that
a) a frictional force is acting on it
b) a net downward force is acting on it
c) it may be accelerating
d) it is not acted on by appreciable gravitational force with a constant velocity.
The correct answer is a) a frictional force is acting on it.
When a packing crate slides down an inclined ramp at a constant velocity, it implies that the forces acting on the crate are balanced. In this case, the force of gravity pulling the crate downward is counteracted by an equal and opposite frictional force acting in the opposite direction. The frictional force opposes the motion of the crate and prevents it from accelerating or decelerating.
Option b) a net downward force is acting on it is incorrect because if there was a net downward force, the crate would be accelerating, not moving at a constant velocity.
Option c) it may be accelerating is also incorrect because the scenario described states that the crate is sliding down at a constant velocity, which means there is no acceleration.
Option d) it is not acted on by appreciable gravitational force with a constant velocity is incorrect as gravity is still acting on the crate, but it is balanced by the frictional force.
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Once the offense comes to the line of scrimmage in one formation, it cannot change to another formation true or false
Answer:
False.
Explanation:
This question refers to the rules of American Football. Thus, the line of scrimmage is an imaginary boundary that is established between both teams, to which the offensive line and the defensive line go to start the play.
In this situation, the offensive team must have 7 players in its formation, but within this some players can perform certain movements, with which it is incorrect to say that the formation cannot be modified, since it is constantly seen as some players, such as wide receivers, for example, move during scrimmage formation.
Where is the south pole of the bar magnet, based on the magnetic field lines
shown?
A. On the right end
B. On the bottom edge
C. On the left end
D. On the top edge
SUBMIT
it would be on the right end I believe. Forgive me if I am incorrect.
A student pulls a 60. -newton sled with a force having a magnitude of 20. Newtons. What is the magnitude of the force that the sled exerts on the student?.
According to Newton's Third Law, the sled's force on the student is equivalent to 20 N.
How is it possible to state Newton's third law clearly?For every action, there's an equal and opposing response, according to Newton's third law. According to the assertion, there are always two forces working on the two objects involved in an interaction. The first object's first and second objects' respective forces are of equal magnitude.
what is Newton's fourth law?Known as the fourth law of Newton, the law of gravitation. According to it, a loads exerted along a line that intersects both points with all masses at a point are drawn toward one another.
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a water tank measures in 14m by 80cm by 60cm .find it capacity the volume of water it hold in liters
Answer:
V = 6720 [Lt]
Explanation:
The volume of a paralepiped can be found by means of the following expression:
V = L*W*H
where:
L = length = 14 [m]
W = width = 80 [cm] = 0.8 [m]
H = heigth = 60 [cm] = 0.6 [m]
V = volume [m³]
V = 14*0.8*0.6
V = 6.72 [m³]
Now we must apply the conversion factor of cubic meters to liters, this factor tells us that 1000 liters is equal to one cubic meter.
\(6.72[m^{3}]*1000\frac{lt}{1m^{3} } \\\)
V = 6720 [Lt]
How do you find the component form of the vector V when given two points in a graph?
The component form of the vector V when given two points in a graph is by getting the horizontal displacement between the initial and terminal points, and the vertical displacement between the initial and terminal points.
What is a Graph?This is referred to the pictorial representation of data or variables in an organized manner.
The component form of a vector →v is written as →v=⟨vx,vy⟩
v → = ⟨ v x , v y ⟩ , where vx represents the horizontal displacement between the initial and terminal points, and vy represents the vertical displacement between the initial and terminal points.
On the graph, the points are located which represents the component form of the vector V thereby making it the most appropriate choice.
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Two identical charges exert a force of 4.5 x 10-2 N and each have charges of 2.5 x 10-6 C, what is the radius?
1.18 x 10-5 m
1.12 m
1.25 m
707.11 m
Water at 10°C and 81.4 percent quality is compressed isentropically in a closed system to 3 MPa. How much work does this process require in kJ/kg? Use steam tables. The work required by the process is_____kJ/kg.
The work required by the process is _____ kJ/kg.
How much work is needed per kilogram in kJ for the compression process from 10°C and 81.4 percent quality to 3 MPa?The work required to compress water isentropically from 10°C and 81.4 percent quality to 3 MPa can be determined using steam tables. The first step is to locate the initial state of water at 10°C and 81.4 percent quality in the steam tables. From the tables, we find the specific enthalpy (h1) and specific entropy (s1) values for the given state.
Next, we find the specific enthalpy (h2) at the final state of 3 MPa from the steam tables.
Using the isentropic compression process, we assume that the entropy remains constant (s2 = s1).
The work required (W) can be calculated using the equation:
W = h1 - h2
Substituting the values obtained from the steam tables, we can find the work required per kilogram in kJ.
Steam tables provide a comprehensive set of data for water and steam properties, including enthalpy, entropy, and other thermodynamic parameters. These tables are essential for engineers and scientists working with steam and thermal systems. By utilizing steam tables, it becomes possible to accurately calculate various processes involving water and steam, such as compression, expansion, and phase changes. They are widely used in fields like power generation, HVAC systems, and industrial processes. Understanding and effectively utilizing steam tables are crucial skills for professionals in these domains.
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Water at 10°C and 81.4 percent quality, when compressed isentropically in a closed system to 3 MPa, requires a work of _______ kJ/kg.
What is the magnitude of the work, in kJ/kg, necessary for this process?The work required for this process can be determined by considering the initial and final states of the water percent quality and applying the principles of thermodynamics. At the given initial condition of 10°C and 81.4 percent quality, we can use steam tables to find the specific enthalpy and entropy values.
By applying the isentropic compression process, we can determine the final state of the water at a pressure o f 3 MPa. The difference in specific enthalpy between the initial and final states givesus the work required per unit mass.To calculate the specific enthalpy at te initial state, we use the steam tables to find the enthalpy of water at 10°C, which is h1. Similarly, the specific entropy at the initial state is obtained from the steam tables as s1.
By assuming an isentropic process, the specific entropy at the final state, s2, remains the same as s1. Using the final pressure of 3 MPa, we find the specific enthalpy of water at this state, h2, from the steam tables.
The work required per unit mass (w) cn be calculated using the equation:
w = h2 - h
Substituting the values obtained from the steam tables, we can determine the work required for this process in kJ/kg.
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A person is drawing water from a well, pulling up a bucket that weighs 4.50 kg, at a constant speed. What is the force exerted on the bucket by the rope?
Answer:
44.13015
Explanation:
use the 9.8067 newtons to 1 kg conversion
The force exerted on the bucket by the rope is 44.1 N.
What is force?
The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. A spring balance can be used to calculate the Force. The Newton is the SI unit of force.
Given parameters:
weighs of the bucket: M = 4.50 kg.
We know that acceleration due to gravity: g = 9.8 m/s².
Hence, gravitational force acting on the bucket in downwards = Mg
= 4.50 kg × 9.8 m/s²
= 44.1 N.
Hence, pulling up a bucket at a constant speed, the person have to exert 44.1 N force on the bucket by the rope so that it can nullify gravitational force acting on the bucket in downwards.
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A paleontologist estimates that when a particular rock formed, it contained 12 mg of the radioactive isotope potassium-40. The rock now contains 3 mg of potassium-40. The half-life of potassium-40 is 1.3 billion years. About how old is the rock?
Answer:
2.6 billion yrs old
Explanation:
3 = 12 (1/2)^n n=2 half lives
2 * 1.3 bln = 2.6 bln
If we know the mass of an object in kilograms, and we know the
acceleration that an object experiences then we can calculate the force
exerted on that object by multiplying the
force, mass
mass, acceleration
O acceleration, force
chino
none of the above
Answer:
Mass, acceleration
Explanation:
Force= Mass (kg) *acceleration (m/s^2)
6. Calculate the mass of mass A in the diagram. The frame joining
the masses is massless.
A
centre of mass
15 cm
30 cm
15 cm
3 kg
8 kg
40 cm
Figure 4.36
Answer:
calculate the mass of mass A i the diagram .the frame joining the mass is massless
Explanation:
The mass of mass A the diagram .the frame joining the mass is massless.
What is Mass?The unique location in an object or system that can be used to describe how the system reacts to outside forces and torques is referred to as the "center of mass" or "center of gravity" in a uniform gravity field.
The idea of the center of mass is that it is the average of all the masses divided by the distances between them. With regard to the torques produced, that is comparable to balancing a seesaw around a pivot point in one plane.
Therefore, The mass of mass A the diagram .the frame joining the mass is massless.
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A heater marked 60W evaporates
6x10-³ kg
of boiling water in 60 seconds. What is the
specific latent heat of vaporization of water in
Jkg
Answer:
L = E / M energy input / water evaporated (J/kg)
E = 60 J / s 60 J input in 1 sec
L = 60 J / (.006 / 60) kg = 600,000 J / kg
The specific latent heat of the vaporization of water is 6×10⁵ J/kg.
The amount of heat required to evaporate a certain mass of water can be calculated using the formula:
Q = ml
where Q is the heat required, m is the mass of water evaporated, and l is the specific latent heat of vaporization of water.
In this problem, we know that a heater with a power output of 60W evaporates 6x10⁻³ kg of boiling water in 60 seconds. We can calculate the amount of heat supplied by the heater using the formula:
Q = Pt
where P is the power of the heater and t is the time for which it is operating. Substituting the given values, we get:
Q = 60 W × 60 s
Q = 3600 J
We can now calculate the specific latent heat of the vaporization of water by rearranging the formula:
l = Q/m
Substituting the given values, we get:
l = 3600 J / (6×10⁻³kg)
l = 6×10⁵ J/kg
Therefore, the specific latent heat of the vaporization of water is equal to 6×10⁵J/kg.
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After rubbing on the apparatus, your pith pall became negatively charged. What type of charge does the apparaTapus now have
The apparatus must be Positively Charged.
Charge interaction:
As from the charge interaction we came to know that when we rub two objects together then there will be three possibility.1. opposite charge objects attract each other
2. like charge object repel each other
3. neutral object with any charges will attract each other.
These happens due to friction generated on rubbing of object which in reverse create electron and get transfer.So, In the question it said that after rubbing on apparatus pith ball
become negative charge which means it has gained the electron.
Thus, the apparatus must have lose electron and would be
positively charged.
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Most ozone is found in a region of Earth’s
atmosphere between 10 and 20 miles above
Earth’s surface. This temperature zone of the
atmosphere is known as the
(1) thermosphere (3) stratosphere
(2) mesosphere (4) troposphere
Answer:
It’s stratosphere
Explanation:
Most ozone is found in a region of Earth’s atmosphere between 10 and 20 miles above Earth’s surface. This temperature zone of the atmosphere is known as the stratosphere.
What is ozone?Ozone is an allotrope of oxygen. It is blue in color and it is found in Earth's atmosphere. It protects the Earth from ultraviolet rays from the Sun.
Most ozone is found in the following layer of the Earth's atmosphere:The ozone subcaste is centered at an altitude between 10-15 country miles (15-25 km). Close to 90% of the ozone found in the atmosphere is in the stratosphere. Ozone that is found in this region is about 10 parts per million by volume (ppmv) to the troposphere's 0.04 ppmv.
Therefore, we have determined that Most ozone is found in a region of Earth’s atmosphere between 10 and 20 miles above Earth’s surface. This temperature zone of the atmosphere is known as the stratosphere.
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python
Write a NumPy program to create random vector of size 15 and replace the maximum value by \( -1 \). Print the original array and the one with maximum replaced by - ?
import numpy as np:
random_vector = np.random.rand(15)
modified_vector = np.where(random_vector == np.max(random_vector), -1, random_vector)
print("Original Array:", random_vector)
print("Modified Array:", modified_vector)
A NumPy program that creates a random vector of size 15, replaces the maximum value with -1, and prints both the original array and the modified array:
```python
import numpy as np
# Create a random vector of size 15
random_vector = np.random.rand(15)
# Find the maximum value in the vector
max_value = np.max(random_vector)
# Replace the maximum value with -1
modified_vector = np.where(random_vector == max_value, -1, random_vector)
# Print the original and modified arrays
print("Original Array:")
print(random_vector)
print("\nModified Array:")
print(modified_vector)
```
When you run this program, it will generate a random vector of size 15 and display the original array. Then, it will replace the maximum value in the array with -1 and display the modified array.
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g For a given a projectile, the drag acceleration is represented by vector a of magnitude 8.14 m/sec2 and direction 58.5 degrees (measured from the x-axis, counter-clockwise). If the gravitational acceleration is represented by vector b of magnitude of 10 m/sec2. The y-component of the Sum vector, sy (m/sec2) is:
The y-component of the Sum vector, sy, is 3.97 m/sec².
In what direction does the Sum vector point?The y-component of the Sum vector represents the combined effect of drag acceleration and gravitational acceleration in the vertical direction. To determine the y-component, we need to consider the magnitude and direction of both vectors.
Given that the drag acceleration, represented by vector a, has a magnitude of 8.14 m/sec² and a direction of 58.5 degrees measured counter-clockwise from the x-axis, we can find its y-component using trigonometry. By taking the sine of the angle, we get the vertical component of a, which is 8.14 m/sec² * sin(58.5°) = 6.99 m/sec².
The gravitational acceleration, represented by vector b, has a magnitude of 10 m/sec² and acts vertically downward. Therefore, its y-component is -10 m/sec².
To find the y-component of the Sum vector, we sum the y-components of vectors a and b: sy = 6.99 m/sec² + (-10 m/sec²) = -3.01 m/sec². However, since the question asks for the magnitude, we take the absolute value of the result, giving us a y-component of 3.01 m/sec².
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A 15 kg block rests on a roof that is at an angle of 40° to the horizontal. What is the component of the force into the surface of the roof
9. 6N
11. 5N
94. 4N
112. 6N
The component of the force into the surface of the roof is approximately 94.4 N.
To find the component of the force into the surface of the roof, we need to calculate the gravitational force acting on the block and then determine its vertical component.
The gravitational force on the block can be calculated using the formula:
Force_gravity = mass * acceleration_due_to_gravity
Given that the mass of the block is 15 kg and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the gravitational force:
Force_gravity = 15 kg * 9.8 m/s^2 = 147 N
Next, we need to find the vertical component of the gravitational force. This component can be found by multiplying the force of gravity by the sine of the angle between the roof and the horizontal. In this case, the angle is 40°.
Vertical component = Force_gravity * sin(angle)
Vertical component = 147 N * sin(40°) ≈ 94.4 N
Therefore, the component of the force into the surface of the roof is approximately 94.4 N.
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which type of heat transfer causes a spoon to become warm when it is placed in a cup of hot water?
Heat transfer describes the flow of heat (thermal energy) due to temperature differences and the subsequent temperature distribution and changes.
What is Heat transfer?The study of transport phenomena concerns the exchange of momentum, energy, and mass in the form of conduction, convection, and radiation. These processes can be described via mathematical formulas.
The fundamentals for these formulas are found in the laws for conservation of momentum, energy, and mass in combination with constitutive laws, relations that describe not only the conservation but also the flux of quantities involved in these phenomena.
For that purpose, differential equations are used to describe the mentioned laws and constitutive relations in the best way possible.
Therefore, Heat transfer describes the flow of heat (thermal energy) due to temperature differences and the subsequent temperature distribution and changes.
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