A triangle with constant base b and height h is changing with time where h(t)=3t +1. What is the rate of change of the area of the triangle when t=1?

The perimeter of the figure is 58 m.

To find the perimeter of the given figure we can divide the figure in three rectangles.

Rectangle 1:

Perimeter= 2 (l + w)

= 2(5 + 2)

= 2 x 7

= 14 m

Rectangle 2:

Perimeter= 2 (l + w)

= 2(5 + 1)

= 2 x 6

= 12 m

Rectangle 3:

Perimeter= 2 (l + w)

= 2(14 + 2)

= 2 x 16

= 32 m

So, the perimeter of the figure is

= 14 + 12 + 32

= 58 m

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Answer: He will need to mow 7 lawns.

Step-by-step explanation:

He already has $20

90-20=70

70/10=7

The modulus value function is solved and the minimum value of d is 5 more than the maximum value of c

Given data ,

Let the modulus function d be represented as d ( x )

where the value of d ( x ) is plotted on the graph

The function c ( x ) is represented by the table of values as

x = { -5 , -4 , -3 , -2 , -1 }

And , the output is c ( x ) = { -4 , -3 , -4 , -5 , -6 }

So, the maximum value of the function c ( x ) = -3

And , the modulus function on the graph is d ( x )

So, the minimum value of the function is d ( x ) = 2

And , d = 5 + c

2 = 5 + -3 = 2

Therefore , the minimum value of d is 5 more than the maximum value of c

Hence , the modulus function is solved.

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The prοbability οf exactly 3 successes in 6 trials οf a binοmial experiment with a prοbability οf success οf 75% is 31.1%, rοunded tο the nearest tenth οf a percent.

Prοbability is the study οf the chances οf οccurrence οf a result, which are οbtained by the ratiο between favοrable cases and pοssible cases.

Tο find the prοbability οf exactly 3 successes in 6 trials οf a binοmial experiment, we use the fοrmula:

The prοbability οf r successes in n trials is \(\rm _nC_r(p)^r(q)^{n-r\), where p is the prοbability οf success οn a given trial and q = 1-p.

In this prοblem, n = 6, r = 3, p = q = 0.75

Sο, P(3 successes in 6 trials) = \(\rm _6C_3(0.75)^3(0.75)^3\) =  0.13184 ≈ 13.2%

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The maximum volume of the cylinder is approximately 1257 cubic centimeters.

The volume V of a right circular cylinder with radius r and height h is given by:

V = πr²h

Substituting the given expressions for the radius and height of the cylinder, we get:

V = πx²(800/πx - x)

Simplifying the expression, we get:

V = 800x - πx³

To find the maximum value of V, we need to find the value of x that maximizes V. We can do this by taking the derivative of V with respect to x, setting it equal to zero, and solving for x:

dV/dx = 800 - 3πx² = 0

3πx² = 800

x² = 800/3π

x ≈ 6.43

Substituting this value of x back into the expression for V, we get:

V ≈ 1257

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Answer:

Step 2: Missy did not multiply the area of each face by 2 before adding.

Step-by-step explanation:

I took the test :)

Therefore, the rate of change, in cm per minute, of the height when the height is 6 cm is approximately -6 cm/min.

Given,The width of the box = 10 cm Length of the box = 17 cmThe volume of the box = 527 cubic cm/minWe need to find the rate of change, in cm per minute, of the height when the height is 6 cm.We know that the volume of the box is given as:V = l × w × h where, l, w and h are length, width, and height of the box respectively.It is given that the width and length are being held constant.

Therefore, we can write the volume of the box as

:V = constant × h Differentiating both sides with respect to time t, we get:dV/dt = constant × dh/dtNow, it is given that the volume of the box is decreasing at a rate of 527 cubic cm per minute.

Therefore, dV/dt = -527.Substituting the given values in the above equation, we get:

527 = constant × dh/dt

We need to find dh/dt when h = 6 cm.To find constant, we can use the given values of length, width and height.Substituting these values in the formula for the volume of the box, we get:

V = l × w × hV = 17 × 10 × hV = 170h

We know that the volume of the box is given as:V = constant × hSubstituting the value of V and h, we get:

527 = constant × 6 cm

constant = 87.83 cm/minSubstituting the values of constant and h in the equation, we get

-527 = 87.83 × dh/dtdh/dt = -6.0029 ≈ -6 cm/min

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The variables 8 observations have x2 values of 2 or greater.

Two variables, x1 and x2, are present in the supplementary data set. There are a total of 20 observations in this data set. The x2 values for 8 of these 20 observations are equal to 2. Thus, x2 values of two were present in eight out of twenty observations, or 40%. The following 12 observations' x2 values do not add up to 2. Thus, 8 of the 20 observations in the data set have x2 values of 2 or higher.8 of these 20 observations have x2 values that are equal to 2. Thus, eight out of twenty observations, or 40 percent, had x2 values equal to two. The x2 values for the next 12 observations are not equal to 2. Consequently, 8 of the data set's 20 observations have x2 values of 2 or above.

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Answer and Step-by-step explanation:

Divide both sides by 2 to get y.

2y > 4

y > 2

y > 2 is the answer.

#teamtrees #PAW (Plant And Water)

Answer:

8

Step-by-step explanation:

16=x

16 square root is 4

16=4

x2

(4)2= 8

Answer:

x2 or 2x=8

Step-by-step explanation:

the square root of 16 is 4

since the other term is 2*x you plug-in numbers and get 2*4=8

Answer:

C

Step-by-step explanation:

 2

+2

-----

 4

For your data, the regression equation for Y is:

Y = 2.09697X - 0.55152

A linear function in mathematics is one that has either one or two variables and no exponents. It is a function with a straight line as its graph.

Given, a data set

x: -5, -3, 4, 1, -1, -2, 0, 2, 3, -4

y: -10, -8, 9, 1, -2, -6, -1, 3, 6, -8

Sum of X = -5

Sum of Y = -16

Mean X = -0.5

Mean Y = -1.6

Sum of squares (SSₓ) = 82.5

Sum of products (SP) = 173

Regression Equation = Y = bX + a

b = SP/SSₓ = 173/82.5 = 2.09697

a = Mₓ - bMₓ = -1.6 - (2.1*-0.5) = -0.55152

Y = 2.09697X - 0.55152

For x = 2.5 the value of y:

y = 2.09697* 2.5 - 0.55152

y = 4.69

Therefore, For your data, the regression equation for Y is:

Y = 2.09697X - 0.55152

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Answer: 3.8

Step-by-step explanation:

The equation of the function f(x) is f(x) = 2 sin(π/2(x + 6)) - 3

A sine function is represented as:

f(x) = A sin(B(x + C)) + D

Where

A = Amplitude

Period = 2π/B

C = Phase shift

D = Vertical shift

The requirements in the question are:

So, we can use the following assumptions

A = 2

Period = 4

C = 6

D = -3

So, we have:

f(x) = 2 sin(B(x + 6)) - 3

The value of B is

4 = 2π/B

This gives

B = π/2

So, we have:

f(x) = 2 sin(π/2(x + 6)) - 3

Using the representations in (a), we have:

See attachment for the graph of f(x)

Let θ = 3π

So, we have:

cos(3π)

This is calculated as:

cos(3π) = cos(2π + π)

Expand

cos(3π) = cos(2π) *cos(π) - sin(2π) *sin(π)

Evaluate

cos(3π) = -1

Let θ = 3π

So, we have:

sin(3π)

This is calculated as:

sin(3π) = sin(2π + π)

Expand

sin(3π) = sin(2π) *cos(π) + cos(2π) *sin(π)

Evaluate

sin(3π) = 0

Let θ = 3π

So, we have:

tan(2 * 3π)

tan(6π)

This is calculated as:

tan(6π) = tan(3π + 3π)

Evaluate

tan(3π) = 0

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Check the picture below.

so hmm we have a 6x6 square atop and a triangle with base of 6 and a height of "h", let's get "h".

\(\sin( 42^o )=\cfrac{\stackrel{opposite}{h}}{\underset{hypotenuse}{2}} \implies 2\sin(42^o)=h \implies 1.34\approx h \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ \textit{\LARGE Areas} }{\stackrel{triangle}{\cfrac{1}{2}(\underset{b}{6})(\underset{h}{1.34})}~~ + ~~\stackrel{ square }{(6)(6)}} ~~ \approx ~~ 4.02+36~~ \approx ~~ \text{\LARGE 40.0}\)

Answer: x<4

Step-by-step explanation:

If we break this down as

-2+4x<14 and we add 2 to both sides

4x+<16 and divide by 4

and you get x<4

Answer:

5880 ways

Step-by-step explanation:

For selections like this, we solve using the combination theory. Recall that

nCr = n!/(n-r)!r!

Hence given to find the number of ways 6 gentleman and 4 ladies can be choosen out of 10 gentleman and 8 ladies,

= 10C6 * 8C4

= 10!/(10-6)!6! * 8!/(8-6)!6!

= 10 * 9 * 8 * 7 * 6!/4 *3 *2 * 6! * 8 * 7 * 6!/2 * 6!

= 210 * 28

= 5880 ways

The arrangement can be done in 5880 ways

Answer:

Your answer is : 0.7748

Step-by-step explanation:

Use bernoulli probability

Answer:

70 square inches

Step-by-step explanation:

Answer:

We are given order pairs  (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.

We need to remove in order to make the relation a function.

Step-by-step explanation:

Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.

In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.

So, we need to remove any one (0, –2) or (0, 8) to make the relation a function. hope this helps you :) god loves you :)

Answer:

182.353745455

Answer:180

Step-by-step explanation:

Answer:consumer surplus

Step-by-step explanation:

Answer:

Its B consumer

Step-by-step explanation:

Answer:

90 degree rotation clockwise

Step-by-step explanation:

answer A

Answer:

a. 90 clockwise

Step-by-step explanation: edge 2023

Answer: umm Combine − 1 5 x and 1 2 x to get − 3 x. 4 (x-5)=14 One solution was found : x = 17/2 = 8.500 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation

Step-by-step explanation:

Turn me into a superhero

The coordinates of polygon A'B'C'D' after the rotation of 180º are given as follows:

A'(0,0), B'(-5,-2), C'(-5,5), D'(0,3).

The five more known rotation rules are given as follows:

The original coordinates for this problem are given as follows:

A(0,0), B(5,2), C(5,-5), D(0,-3).

Exchanging the sign of each of the coordinates, the coordinates after the rotation are given as follows:

A'(0,0), B'(-5,-2), C'(-5,5), D'(0,3).

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The series of rigid motion transformations that map polygon A to Polygon A''' are;

A rigid transformation is a transformation in which the distance between all pairs of points on the pre-image is preserved following the transformation.

The series of rigid motion transformations that map polygon A to polygon A''' are;

Transformation from A to A'

Transformation from A' to A''

Transformation from A'' to A'''

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The correct option that indicates the quadrant that contains the translation of the shaded figure is the option B

B. III

A translation is a transformation in which the size, relative position of the points on the pre-image, are preserved but the location of the pre-image changes to obtain the image.

The shape of the shaded figure is an L-shape

The geometric figure in quadrant II and IV are a reflection of the shaded figure, across the y-axis and across the x-axis, respectively which is not a translation transformation.

The geometric figure in quadrant III can be obtained from the shaded figure by a translation 4 units to the left and 5 units downwards, which can be expressed as <-4, -5>, which is a translation transformation, therefore;

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