Answer:
\(V_{f}\) = 6 cm/s
Explanation:
Given:
Acceleration = a = 2 cm/s²
Time = t = 3s
Initial Velocity = \(V_{i}\) = 0 cm/s
Required:
Velocity = \(V_{f}\) = ?
Formula:
a = \(\frac{V_{f}-V_{i}}{t}\)
Solution:
2 = \(\frac{V_{f}-0}{3}\)
=> \(V_{f}\) = 2*3
=> \(V_{f}\) = 6 cm/s
In our solar system, which celestial object is known as the dwarf planet?
Answer:
unfournatletly
Explanation:
i have no clue sorry to waste ur time ill rather not say a answer that will be incorrect.
Answer:
Pluto
Explanation:
Pluto was part of our solar system till 2006In 2006 international scientific committee removed it from planets listIt's known as dwarf planet nowWhat is the function of the metal case cover in a thermos flask?
Answer:
The metal case cover reduces heat loss by radiation
HELP PLS LIKE RIGHT NOW PLSSSSSS
Why was the geocentric model of our solar system widely accepted until the 16th century?
A.
The model was considered to work in tandem with the ancient Aztec calendar.
B.
Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.
C.
The star catalogue matched the movement of constellations.
D.
No one had yet sailed entirely around Earth to disprove the geocentric model.
The correct answer is B. Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.
The geocentric model, which placed Earth at the center of the universe with the Sun, Moon, and stars revolving around it, was widely accepted until the 16th century for several reasons. One of the primary reasons was that observations seemed to support this view. For example, it was observed that the stars appeared to move across the sky in a circular path, and it was assumed that this was due to their motion around Earth. Similarly, the Sun and Moon appeared to rise and set each day, which was consistent with their motion around Earth.
The geocentric model was consistent with the prevailing philosophical and religious beliefs of the time, which held that Earth was a special and unique place at the center of the universe. It was not until the development of the heliocentric model, which placed the Sun at the center of the solar system, and the refinement of astronomical observations, that the geocentric model was gradually abandoned.
The correct option is B. Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.
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A spring oscillates with a frequency of 2.09 Hz. What is its period?
(Unit=s)
Time period of a wave is the inverse of its frequency. The period of the wave with a frequency of 2.09 Hz is 0.47 seconds.
What is frequency ?Frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of the time period of the wave. Hence, it has the unit of s⁻¹ which is equivalent to Hz.
The higher frequency of a wave indicates more number of wave cycles in a short time. Frequency is directly proportional to the energy and inversely proportional to the wavelength.
Given the time period of the wave = 2.09 Hz
then frequency = 1/2.09 Hz = 0.47 s.
Therefore, the time period of the wave is 0.47 seconds.
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A coin is placed next to the convex side of a thin spherical glass shell having a radius of curvature of 17.0 cm. Reflection from the surface of the shell forms an image of the 1.5-cm-tall coin that is 6.50 cm behind the glass shell.
a) Where is the coin located?
b) Determine the size of the image.
(a) The position of the coin placed next to the convex side of a thin spherical glass shell is 3.68 cm.
(b) The size of the image is 1.8.
Position of the coinThe position of the coin placed next to the convex side of a thin spherical glass shell is calculated as follows;
1/d = 1/f - 1/d'
where;
d' is the position of the coin's imaged position of the coinf is focal lengthFocal length = r/2 = 17 cm / 2 = 8.5 cm
1/d = 1/8.5 - (-1/6.5)
1/d = 1/8.5 + 1/6.5
1/d = 0.1176 + 0.1538
1/d = 0.2714
d = 1/0.2714
d = 3.68 cm
Size of the imageMagnification, M = d'/d
M = (6.5)/(3.68)
M = 1.8
Thus, the position of the coin placed next to the convex side of a thin spherical glass shell is 3.68 cm.
The size of the image is 1.8.
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Resistance between opposite faces of a unit cube. Expressed in ohm-centimeters or ohms per cubic centimeter.
Resistivity is the resistance between opposite faces of a unit cube.
The electrical resistance of a conductor with a unit cross-sectional area and unit length is called resistivity. Resistivity is a distinctive attribute of any material that may be used to compare different materials based on how well they conduct electric currents. Low conductivity is indicated by high resistance.
The Greek letter rho is frequently used to represent resistance, which is numerically equivalent to the resistance R of a wire-like specimen, multiplied by its cross-sectional area A, and divided by its length l; RA/l. The ohm is the measurement of resistance. Units of ohm-centimeter can be used to represent resistance when lengths are measured in centimeters. The temperature of the material also affects the value of resistivity.
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Two persons on ice skates stand face to face and then push each other away (see figure below). Their masses are 80 and 95 kg.
Find the ratio of their speeds immediately afterward.
v80 kg
v95 kg
=
Which person has the higher speed?
80-kg skater
95-kg skater
This question involves the concepts of the law of conservation of momentum.
The ratio of their speeds will be "-1.19".
"80-kg skater" has the higher speed.
LAW OF CONSERVATION OF MOMENTUM:According to the Law of Conservation of Momentum, the total momentum of an isolated system always remains constant. Therefore,
\(Total\ Momentum\ Before\ Collision =Total\ Momentum\ After\ Collision \\\\m_1u_1+m_2u_2=m_1v_1+m_2v_2\)
where,
m₁ = mass of skater 1 = 80 kgm₂ = mass of skater 2 = 95 kgu₁ = speed of skater 1 before collision = 0 m/su₂ = speed of skater 2 before collision = 0 m/sv₁ = v₈₀ = speed of skater 1 after collisionv₂ = v₉₅ = speed of skater 2 collisionTherefore,
\((80\ kg)(0\ m/s)+(95\ kg)(0\ m/s)=(80\ kg)(v_{80})+(95\ kg\ kg)(v_{95})\\\\\frac{v_{80}}{v_{95}}=-\frac{95\ kg}{80\ kg\ kg}\\\\\frac{v_{80}}{v_{95}}=-1.19\)
It is clear that the speed of skater A (80 kg skater) will be higher.
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A dynamite blast at a quarry launches a chunk of rock straight upward, and 2.0s later it is risinv at a speed of 15m/s. Assuming air resistance has no effect on the rock, calculate its speed (a) at launch and (b) 5.0s after launch
Answer:
(a) To solve for the initial speed of the rock at launch, we can use the kinematic equation:
v = v0 + at
Where:
v = final velocity (15m/s)
v0 = initial velocity (what we're solving for)
a = acceleration due to gravity (-9.8m/s^2)
t = time (2.0s)
Plugging in the values, we get:
15m/s = v0 - 9.8m/s^2 (2.0s)
v0 = 34.6m/s
Therefore, the initial speed of the rock at launch was approximately 34.6m/s.
(b) To solve for the speed of the rock 5.0s after launch, we can use the same kinematic equation:
v = v0 + at
But this time, we need to add the additional time and distance that the rock traveled after the initial 2.0s. To do this, we'll use the equation:
d = v0t + 1/2at^2
Where:
d = distance traveled
v0 = initial velocity (34.6m/s)
a = acceleration due to gravity (-9.8m/s^2)
t = time (5.0s - 2.0s = 3.0s)
Plugging in the values, we get:
d = (34.6m/s)(3.0s) + 1/2(-9.8m/s^2)(3.0s)^2
d = 103.8m - 44.1m
d = 59.7m
So, the rock traveled 59.7m in the additional 3.0s after the initial 2.0s. Now we can find its speed using the kinematic equation:
v = v0 + at
Where:
v0 = final velocity from before (15m/s)
a = acceleration due to gravity (-9.8m/s^2)
t = time (3.0s)
Plugging in the values, we get:
v = 15m/s - 9.8m/s^2 (3.0s)
v = -12.6m/s
Note that the velocity is negative because the rock is now moving downward. Therefore, the speed of the rock 5.0s after launch is approximately 12.6m/s.
A mineral oil has a density of 0.875 g/cm3. Suppose you spread 0.60 g of this oil over the surface of water in a large dish with an inner diameter of 21.6 cm. How thick is the oil layer
With a density of 0.875 g/cm³, a sample of 0.60 g of this oil would have a volume V such that
0.875 g/cm³ = (0.60 g)/V ==> V ≈ 0.686 cm³
If the oil is spread out uniformly over the water's surface, then it forms a cylinder whose diameter is equal to that of the dish, 21.6 cm. Then the thickness d of the oil cylinder is such that
V = π ((21.6 cm)/2)² d ==> d ≈ 0.0202 cm
What is the mechanical energy after the rock has fallen for 2 s?
Without additional information about the situation, it's impossible to determine the mechanical energy after the rock has fallen for 2 seconds. The mechanical energy depends on factors such as the mass of the rock, its height above the ground, and the presence or absence of any external forces acting on the system.
When a single high-resistance (long) bulb is connected to a 1.5 V battery, the current through the battery is about 80 mA. If you add another high-resistance (long) bulb in parallel, the battery current of course increases to 160 mA. Select all of the true statements given this situation.
a. The battery is ohmic.
b. The battery is not ohmic.
c. Current through the battery is proportional to ΔV across the battery.
d. Current through the battery is not proportional to ΔV across the battery.
e. The battery always puts out the same current.
Answer:
a) True. The battery obeys ohm's law, it is formed by an ideal source with a fixed internal resistance
c) True. Ohm's law is V = iR therefore voltage and current are proportional
Explanation:
In this problem let's analyze the load of the system, when a resistance is placed the current is 80 mA, if we place two resistors in parallel the voltage remains the same, but the current is divided between each resistance (bulb), therefore the current in the battery it must be 160 mA
Let's analyze the answers
a) True. The battery obeys ohm's law, it is formed by an ideal source with a fixed internal resistance
b) false
c) True. Ohm's law is V = iR therefore voltage and current are proportional
d) False
e) False. The current coming out of the battery is proportional to the load placed
A set of four capacitors are attached to a 12V battery in the circuit shown below. All capacitances are measured in milli-Farads. Find the amount of electric charge that resides on each capacitor once it is fully charged.
The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.
Total capacitance of the circuit
The total capacitance of the circuit is calculated as follows;
Capacitors in series;
1/Ct = 1/8 + 1/7.5
1/Ct = 0.25833
Ct = 3.87 mF
Capacitors is parallel;
Ct = 3.87 mF + 12 mF + 15 mF
Ct = 30.87 mF
Ct = 0.03087 F
Charge in each capacitorQ = CV
Q = 0.03087 x 12
Q = 0.37 C
Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.
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An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?
Answer:
Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.
Explanation:
To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.
Given:
m1 = 8 kg
x1 = 3 m
x_cm = unknown (to be found)
m2 = 10 kg
y_cm = 4.5 m
Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.
To solve for x2, we can rearrange the formula as follows:
x2 = (x_cm * (m1 + m2) - m1 * x1) / m2
Substituting the given values:
x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg
Simplifying:
x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg
Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:
4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)
Simplifying:
4.5 m = (24 kg + 10 kg * x2) / 18 kg
Multiplying both sides by 18 kg:
81 kg*m = 24 kg + 10 kg * x2
Subtracting 24 kg from both sides:
10 kg * x2 = 81 kg*m - 24 kg
Dividing both sides by 10 kg:
x2 = (81 kg*m - 24 kg) / 10 kg
Simplifying:
x2 = 8.1 m - 2.4 m
x2 = 5.7 m
(brainlest?) ples:(
Answer:
the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.
Explanation:
To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.
The center of mass of a system is given by the equation:
x_cm = (m1x1 + m2x2) / (m1 + m2),
where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.
Given:
m1 = 8 kg,
x1 = 3 m,
m2 = 10 kg,
y_cm = 4.5 m.
To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:
y_cm = (m1y1 + m2y2) / (m1 + m2),
where y1 and y2 are the positions along the y-axis.
Rearranging the equation and substituting the given values:
4.5 = (83 + 10y2) / (8 + 10).
Simplifying the equation:
4.5 = (24 + 10*y2) / 18.
Multiplying both sides by 18:
81 = 24 + 10*y2.
Rearranging the equation:
10*y2 = 81 - 24,
10*y2 = 57.
Dividing both sides by 10:
y2 = 5.7.
Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.
To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:
x_cm = (m1x1 + m2x2) / (m1 + m2).
Substituting the given values:
x_cm = (83 + 10x2) / (8 + 10).
Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:
0 = (83 + 10x2) / (8 + 10).
Rearranging the equation:
83 + 10x2 = 0.
24 + 10*x2 = 0.
10*x2 = -24.
Dividing both sides by 10:
x2 = -2.4.
Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 10^8/ (this is the speed of light in vacuum). How far (in meters) into space did the signal travel during the first 10 minutes?
Answer:
Explanation:
we know that
s=vt here v is the speed and s is distance covered by the signals
given data
v=3*10^8
t=10 min we have to convert it into seconds
1 minute=60 seconds
so
10 minutes =10*60/1 =600 seconds
now putting the value of v and t we can find the value of s
s=vt
s=3*10^8*600
s=1.8*10^11m
i hope this will help you
Speed is the rate of distance over time.
The signal will travel \(1.8 \times 10^{11}\) meters in the first 10 minutes
The given parameters are:
\(s = 3 \times 10^8\ ms^{-1}\) ---the speed of light
\(t = 10\ min\) -- the time of travel
The relationship between speed, distance (d) and time is:
\(s = \frac dt\)
Make d the subject
\(d = s \times t\)
Substitute values for t and s
\(d = 3 \times 10^8\ ms^{-1} \times 10\ min\)
Convert minutes to seconds
\(d = 3 \times 10^8\ ms^{-1} \times 10 \times 60s\)
So, we have:
\(d = 3 \times 10^8\ m \times 10 \times 60\)
\(d = 18 \times 10^{10}m\)
Rewrite as:
\(d = 1.8 \times 10^{11}m\)
Hence, the signal will travel \(1.8 \times 10^{11}\) meters in the first 10 minutes
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It's important to match your exercise shoes with the type of exercise in which you will be participating, Please select the best answer from the choices provided OT
Answer:
the answer is true
Explanation:
●
Dean is skateboarding. He starts at a speed of 0.5 m/s and speeds up to 4.0 m/s
to go off a ramp over a time of 5.0 seconds. What is Dean's acceleration?
Answer:
\(\huge\boxed{\sf a = 0.7 \ m/s^2}\)
Explanation:
Given Data:Initial velocity = \(V_i\) = 0.5 m/s
Final velocity = \(V_f\) = 4 m/s
Time = t = 5 s
Required:Acceleration = a = ?
Formula:\(\displaystyle a =\frac{V_f-V_i}{t}\)
Solution:Put the givens in the formula.
\(\displaystyle a=\frac{4-0.5}{5} \\\\a = \frac{3.5}{5} \\\\a = 0.7 \ m/s^2\\\\\rule[225]{225}{2}\)
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The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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12 Rajiv made a model of a boat. When he places it in water, it sinks. According to
Archimedes' principle, why does the boat sink?
A The boat is too small.
B The buoyant force is less than the boat's weight.
C The buoyant force is equal to the boat's weight.
D The buoyant force is greater than the boat's weight.
Answer:
the answer is .D
Explanation:
force is greater than the boats weight
Answer: The buoyant force is less than the boats weight.
5) You are visiting Norway for the winter and driving on a highway where the speed
limit is 80 km/hr. Your car indicates that you are going at a speed of 55 mi/hr. Will
you be arrested? (1 mi = 1.6 km)
A wire has resistivity of 0.12 homes per metre.
a)Find the resistance of 25m of wire.
b)Find the length of this wire that has resistance 22ohms
Answer:
(a) The resistance of 25m of wire is 3 ohms
(b) the length of this wire that has resistance 22 ohms is 183.33 m
Explanation:
Given;
resistivity of the wire, ρ = 0.12 ohms per meter
(a) The resistance of 25m of wire is calculated as follows;
\(R = \rho L\\\\R = 0.12 \ \frac{ohms}{m} \times 25\ m\\\\R = 3 \ ohms\)
(b) the length of this wire that has resistance 22 ohms is calculated as;
\(L = \frac{R}{\rho} \\\\L = \frac{22 \ ohms }{0.12 \ ohms/m} = 183.33 \ m\)
you are driving at 18m/s down Lyndale avenue. A car backs out a driveway 25 meters in front of you. You continue at that speed while your brain processes the danger which takes 0.25 seconds. You then slam on the brakes and your car has an acceleration of -5.4m/s^2. Do you stop before reaching the driveway(and hitting the car)? Show your work. This is a two-part problem with constant speed and braking.
Hello!
For this, first let's calculate time of stop:
t = (V - Vi) / a
Replacing:
t = (0 m/s - 18 m/s) / -5,4 m/s^2
Resolving:
t = -18 m/s / -5,4 m/s^2
t = 3,33 s + 0,25 s = 3,58 s
Now lets calculate distance traveled, with formula:
d = Vi*t + (a*t^2)/2
Replacing:
d = 18 m/s * 3,58 s + (-5,4 m/s^2 * (3,58 s)^2) /2
Resolving:
d = 64,44 m + (-34,604 m)
d = 29,83 m
Then, the vehicle will CRASH
A source of voltage v maintains a current I in a circuit. The power (p) input to the cicuit by the source is given by 1. P = v I 2. P – v/I 3. P = i/v 4. P= 1/(v/i)
The power (p) input to the circuit by the source is given by 1) P = v I.
Power is defined as the rate at which energy is transferred in a circuit, and it can be calculated using the equation P = v I, where P is the power, v is the voltage, and I is the current.
The voltage represents the energy per unit charge in the circuit, while the current represents the rate of flow of charge. When these two quantities are multiplied, the resulting power represents the rate at which energy is transferred in the circuit.
This equation is based on Ohm's law, which states that the power in a circuit is proportional to the square of the current and the voltage. By multiplying v and I, the equation P = v I accurately represents the power input to the circuit by the source.
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How do supersonic flights create sonic boom? Please explain in detail.
Supersonic flights are moving with speed greater than that of sound. This speed through air will combine the pressure waves and creates shock waves. Continuation of shock waves leads to sonic boom in air.
What is sonic boom ?Sonic booms are sound created on the ground by overpressure in the air generated by fastly moving objects. Similar to someone dumping goods from a moving car, an aircraft travelling at supersonic speeds continuously produces shock waves that cause sonic booms to travel throughout its flight path.
The boom seems to be swept rearward as it moves away from the aeroplane from its point of view. The boom will strike the ground in front of the aircraft if the aircraft makes a rapid turn or pulls up.
The abrupt start and release of pressure following the building by the shock wave or "peak overpressure" is what is heard as a "sonic boom" on the ground. Only a few pounds per square foot change in pressure results from a sonic boom, which is about equivalent to the pressure shift we experience in an elevator.
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9. Rob Colley set a record in “pole-sitting" when he spent 42 days in a barrel at the
top of a flagpole with a height of 43 m. Supposed a friend wanting to deliver an ice-
cream sandwich to Colley throws the ice cream straight up with just enough speed
to reach the barrel. How long does it take the ice-cream sandwich to reach the
barrel?
Answer:
3 sec
Explanation:
T=squareroot((2*-43)/-9.81)
Which of the following is the best explanation of work?
A. Work occurs when energy acts on an object.
B. Work occurs when a force acts on an object.
C. Work occurs when energy is exerted.
D. Work occurs when a force acts on an object and causes a displacement of that
object.
E. Work occurs when force acts to hold an object in place.
Answer:
D
Explanation:
Can someone explain what is loss of seismic energy ?
Answer:
Seismic attenuation describes the energy loss experienced by seismic waves as they propagate. It is controlled by the temperature, composition, melt content, and volatile content of the rocks through which the waves travel.
Explanation:
What has the least potential energy in this world
Answer:
Anything that has the most kinetic has the least potential energy.
Explanation:
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What is the peak wavelength (in nm) of a neutron star's luminosity if its temperature is
107 K?
The peak wavelength of a neutron star's luminosity if its temperature 10⁷ K is equal to 0.2898 nm.
What is Wein's law?Wien's displacement law can be described as the black-body radiation curve for various temperatures that will peak at different wavelengths. These wavelengths of radiation are inversely proportional to their temperature.
The shift of that peak is described by the Planck radiation law, which states that the intensity of black-body radiation is a function of wavelength at a given temperature.
The peak wavelength at a given temperature can be calculated from the formula as follows:
\(\lambda_{peak}=\frac{2.898\times 10^{-3}m.K}{T}\)
Given the temperature of a neutron star's luminosity, T = 10⁷K
Substitute the value of temperature in the above formula:
\(\lambda_{peak}=\frac{2.898\times 10^{-3}m.K}{10^7K}\)
\(\lambda_{peak} = 0.2898\; nm\)
Therefore, the peak wavelength of the given star is 0.2898 nm.
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Give reasons for the following:
a. Knives and swords are supposed to have extremely thin blades.
b. Lorries and trucks carrying heavy loads have 8 tires instead of four, and the
tires are broader.
c. Camels can walk easily in desserts but humans cannot.
d. In a flight, the human ear pain during take-off and landing.
e. A suction cup does not stick on a rough surface.
Answer:
a. lower surface area, less resistence
b. more surface area, the load is split so no single tire overstrained
c. more surface area, more resistance against the sand. human steps sink down in the sand.
d. rapid change in air pressure on eardrums lead to somewhat-painful tension
e. air would always find its way in so no pressure difference can be achieved
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