A truck bed can carry up to 1,000 pounds. Which inequality describes the number of boxes, b, the truck can carry if each box weighs 35 pounds?

Answer: I got d :)

Step-by-step explanation:

Answer:

x<5

Step-by-step explanation:

x/2-7/6<4/3

x/2<4/3+7/6

x/2<8/6+7/6

x/2<15/6

x<15/6*2

x<30/6

x<5

Answer:

B is the answer. It keeps going up by 3 every time.

Step-by-step explanation:

Answer:

\(\large\boxed{\tt -10y + 10.2 }\)

Step-by-step explanation:

\(\textsf{We are asked to simplify the given expression.}\)

\(\textsf{Note that we can't simplify this expression down to 1 term.}\)

\(\large\underline{\textsf{Why?}}\)

\(\textsf{This is due to 2 numbers having the variable y, and 2 other numbers without y.}\)

\(\textsf{Consider these terms Unlike Terms, as they have a difference in which we can't}}\)

\(\textsf{combine them.}\)

\(\textsf{Even though there are some Unlike Terms, there is a few Like Terms.}\)

\(\textsf{Let's identify the Like Terms, and the Unlike Terms in our expression.}\)

\(\large\underline{\textsf{Like Terms;}}\)

\(\tt 4 \ and \ 6.2 \ are \ like \ terms. \ (Both \ don't \ have \ any \ variables)\)

\(\tt -2y \ and \ -8y \ are \ like \ terms. \ (Both \ have \ the \ same \ variable)\)

\(\large\underline{\textsf{Unlike Terms;}}\)

\(\tt 4 \ and \ -2y \ are \ Unlike \ Terms.\)

\(\tt 6.2 \ and \ -8y \ are \ Unlike \ Terms.\)

\(\tt 4 \ and \ -8y \ are \ Unlike \ Terms.\)

\(\tt 6.2 \ and \ -2y \ are \ Unlike \ Terms.\)

\(\textsf{We know what the Unlike Terms, and Like Terms are for our expression.}\)

\(\large\underline{\textsf{Solving;}}\)

\(\textsf{Solve by combining Like Terms in the expression.}\)

\(\large\underline{\textsf{Combine Like Terms;}}\)

\(\tt 4-2y + (-8y) + 6.2\)

\(\textsf{When we add a negative term, we are actually subtracting with that term.}\)

\(\tt 4-2y -8y + 6.2\)

\(\underline{\textsf{Our final answer should be;}}\)

\(\large\boxed{\tt -10y + 10.2 }\)

Answer:

\( \sf \: -10y + 10.2\)

Step-by-step explanation:

Now we have to,

→ Simplify the given expression.

The expression is,

→ 4 - 2y + (-8y) + 6.2

Let's simplify the expression,

→ 4 - 2y + (-8y) + 6.2

→ 4 - 2y - 8y + 6.2

→ -2y - 8y + 6.2 + 4

→ (-2y - 8y) + (6.2 + 4)

→ (-10y) + (10.2)

→ -10y + 10.2

Hence, answer is -10y + 10.2.

1/3 of the volunteers can complete the 8-hour workday

Total number of volunteers = 10

If it takes 1 volunteer = 24 hours = 1 day

It would take x number of volunteers = 8 hours

To find 'x' , cross multiply

We have,
x * 24 hours = 8 hours * 1

24x = 8

Make 'x' the subject of formula

x = 8/ 24

x = 1/3

Therefore, 1/3 of the volunteers can complete the 8-hour workday

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∑Hey , jillianwagler ⊃

Answer:

x=2,y=5

Step-by-step explanation:

Given:

Solve the system below using substution

{2x-3y= -11}

{2x+y=9}

Solution~:

\(\begin{bmatrix}2x-3y=-11\\ 2x+y=9\end{bmatrix}\)

Isolate x for 2x-3y = -11 : \(x=\frac{-11+3y}{2}\)

Substitute \(x=\frac{-11+3y}{2}\) to:

\(\begin{bmatrix}2\cdot \frac{-11+3y}{2}+y=9\end{bmatrix}\)

= \(\begin{bmatrix}-11+4y=9\end{bmatrix}\)

Isolate y for  -11 + 4y = 9 : y = 5

Substitute y = 5

\(x=\frac{-11+3\cdot \:5}{2}=2\)

x = 2

Hence, the solutions for \(\begin{bmatrix}2x-3y=-11\\ 2x+y=9\end{bmatrix}\) are:

\(x=2,\:y=5\)

xcookiex12

8/19/2022

Option B) George's arrival changes the mood because he complains that Beneatha is giving them a lecture on their African past

In Act 2 of A Raisin in the Sun, George Murchison's arrival changes the mood of the scene as he complains that Beneatha is giving them a lecture on their African past. George's comments create tension and conflict among the characters, particularly with Beneatha, who is exploring her African heritage. His attitude towards Beneatha's interest in her roots is dismissive and condescending, which generates discomfort and disagreement among the characters. George's arrival highlights the cultural differences between him and the Younger family and demonstrates the generational and ideological divides within the African American community. Thus, his presence is a catalyst for revealing deeper tensions and conflicts within the play.

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Complete question:

How does the arrival of George Murchison change the mood of the scene?

A) George's arrival changes the mood because he doesn't take part in the dance

B) George's arrival changes the mood because he complains that Beneatha is giving them a lecture on their African past

C) George's arrival changes the mood because he was rich, and they didn't like that a rich white person was in their house

D) George's arrival changes the mood because he had a gun

The auditing software can identify 63.7% of misreporting issues in accounting ledgers. The probability that no misreported transactions are found is 1 - 63.7% = 36.3%. The probability that at least half of the transactions are misreported is 1 - P(X  25) = 1 - P(X  24) P(X  24) = _(i=0)24 (50C_i) (0.363)i (1 - 0.363)(50 - i)  0.0001. The expected monetary gain is approximately -$49.8.

Given that an auditing software can identify 63.7% of misreporting issues in accounting ledgers. Let X be the number of accounting misreporting transactions identified by the software among 50 randomly selected transactions for the last 3 months.Probability that no misreported transactions are found:X follows a binomial distribution with n = 50 and p = 1 - 63.7% = 36.3%.P(X = 0) = (1 - p)^n = (1 - 0.637)^50 ≈ 0.0002Probability that less than 10 misreported transactions are found:

P(X < 10) = P(X ≤ 9)P(X ≤ 9)

= P(X = 0) + P(X = 1) + P(X = 2) + ... + P(X = 9)P(X ≤ 9)

= ∑_(i=0)^9 (50C_i ) (0.363)^i (1 - 0.363)^(50 - i) ≈ 0.99

Probability that at least half of the transactions are misreported:

P(X ≥ 25)P(X ≥ 25)

= P(X > 24)P(X > 24)

= 1 - P(X ≤ 24)P(X ≤ 24)

= ∑_(i=0)^24 (50C_i ) (0.363)^i (1 - 0.363)^(50 - i) ≈ 0.0001

Expected monetary gain:Let Y be the amount of money that the firm gets to earn or pay. The probability distribution of Y can be shown below:Outcomes: $200, -$50, -$100

Probabilities: P(X = 0), P(0 < X < 10), P(X ≥ 25)P(X = 0)

= 0.0002P(0 < X < 10)

= 0.99 - 0.0002 = 0.9898P(X ≥ 25)

= 0.0001E(Y)

= ($200 x P(X = 0)) + (-$50 x P(0 < X < 10)) + (-$100 x P(X ≥ 25))E(Y)

= ($200 x 0.0002) + (-$50 x 0.9898) + (-$100 x 0.0001)≈ -$49.8

Therefore, the expected monetary gain is approximately -$49.8.

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Answer:

PLEASE READ EXPLANATION

1. \(x = 7\)

2. \(b = 3\)

3. \(n = 6\)

4. \(b = 1\)

Step-by-step explanation:

I’m going to assume the equations are as following - you made it a bit hard to read.

\(x - 7 = 0\)

\(-15 = b - 18\)

\(4 = n-2\)

\(b-(-16) = 17\)

I’m just shooting guesses here, if I said an equation wrong PLEASE let me know.

We can solve each equation by isolating x on one side.

Number 1:

\(x - 7 = 0\\\\x - 7 + 7 = 0 + 7\\\\x = 7\)

Number 2:

\(-15 = b - 18\\\\-15 + 18 = b - 18 + 18\\\\3 = b\)

Number 3:

\(4 = n-2\\\\4 + 2 = n - 2 + 2\\\\n = 6\)

Number 4:

\(b-(-16) = 17\\\\b+16=17\\\\b + 16 - 16 = 17 - 16\\\\b = 1\)

Hope this helped!

Answer:

It is true

Step-by-step explanation:

the area of the rectangle is

72•66=4752

the area of the semi circle is

π33^2= 3421.19/2= 1710.595

4752-1710.595= 3041.405

rounded to nearest tenth

3041.4

John's study aims to determine if exercise frequency has an effect on pulse rate. Statistical analysis can be used to verify the alternate hypothesis.

John wants to determine whether the frequency of exercise affects pulse rate. To investigate this, he randomly selects individuals at a local gym who agree to participate in his research. John divides the 55 individuals who agree into three exercise frequency categories: high, moderate, and low.

Following their exercise, he calculates their pulse rates. Is there a difference in pulse rates among those who exercise frequently, moderately, and infrequently?The null hypothesis for this research question would be that there is no relationship between the frequency of exercise and pulse rate. The alternate hypothesis would be that there is a correlation between frequency of exercise and pulse rate. Statistical tools like ANOVA or T-test can be used to test the hypothesis.

In conclusion, John's study aims to determine if exercise frequency has an effect on pulse rate. Statistical analysis can be used to verify the alternate hypothesis.

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\(m\angle E=\sin \dfrac{\sqrt{10}}{2\sqrt5}=\sin \dfrac{\sqrt2}{2}=45^{\circ}\)

Throughout her time in high school, Carmen maintained a cumulative GPA of \(6, 9, 12, and 15\)  , respectively.

Generally, secondary school science in the US has been shown in the grouping of Variable based math 1, Calculation, and Variable based math 2.

Coordinated science reconsiders these courses as Math 1, Math 2, and Math 3, where logarithmic, mathematical, and measurable reasoning are installed all through every one of the three courses.

Therefore, We must enter the values of t into the provided formula to complete the table and determine the corresponding GPA values:

Year, t 0 1 2 3

GPA 6 9 12 15

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Answer:

47.21

Step-by-step explanation:

a=47.4

b=0.19

a – b

47.4 – 0.19

=47.21

The net operating income for the Night & Day Guitar company for the period is a loss of $1,980. This means that the company's total costs exceeded its revenue, resulting in a negative net operating income.

To calculate the net operating income for the Night & Day Guitar company, we need to subtract all of the costs associated with producing and selling the guitars from the revenue generated by selling the guitars. Let's break down the costs and revenue components:

Revenue:

Selling price per guitar: $1,004

Number of guitars sold during the period: 102

Total revenue = Selling price per guitar x Number of guitars sold = $1,004 x 102 = $102,408

Costs:

1. Direct materials cost per guitar: $291

2. Direct labor cost per guitar: $435

3. Variable overhead cost per guitar: $33

4. Variable selling expenses per guitar: $52

5. Variable shipping costs per guitar: $86

6. Total variable cost per guitar: $291 + $435 + $33 + $52 + $86 = $897

7. Total variable cost for all guitars sold: $897 x 102 = $91,494

8. Fixed manufacturing costs: $9,838

9. Fixed selling expenses: $1,597

10. Remaining fixed period costs: $1,459

Total costs = Total variable cost + Fixed manufacturing costs + Fixed selling expenses + Remaining fixed period costs

= $91,494 + $9,838 + $1,597 + $1,459 = $104,388

Net operating income = Total revenue - Total costs = $102,408 - $104,388 = -$1,980

The net operating income for the Night & Day Guitar company for the period is a loss of $1,980. This means that the company's total costs exceeded its revenue, resulting in a negative net operating income. It's important for companies to track their costs and revenue to ensure they are profitable and to make adjustments as needed to improve their financial performance.

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Answer:

y = mx + b

Step-by-step explanation:

so you first put the points on the graph and connect them with a slanted line.

Next, for your equation start of with y =

then, your going to find your slope, after you find it put it in front of x (slope x) (Ex; if the slope was 3 then it would look like this 3x)

finally you write + and the y intercept (at which point the line goes through the y axis)

the equation together should look like y = slope x + y intercept

The formula for logistic growth can be expressed as P(t) = K / (1 + A * e^(-rt)), where P(t) is the population at time t, K is the carrying capacity, r is the growth rate, A is the initial population.

Logistic growth is a type of population growth that considers a carrying capacity, which is the maximum population size that an environment can sustain. The formula for logistic growth takes into account the carrying capacity (K), the growth rate (r), and the initial population (A) to describe how the population changes over time.

In this case, the carrying capacity is given as 1500, and the growth rate is 0.25 per year. Let's denote the population at time t as P(t).

The formula for logistic growth can be written as:

P(t) = K / (1 + A * e^(-rt))

Plugging in the given values, we have:

P(t) = 1500 / (1 + A * e^(-0.25t))

The value of A is not explicitly given, so it represents the initial population. If the initial population is known, it can be substituted into the formula. If not, A can be left as a variable.

The term e^(-0.25t) represents the exponential decay component, which approaches 0 as t increases. It is multiplied by A, allowing the population to approach the carrying capacity over time.

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Over the last half-century, time-use data has shown that married American women have significantly reduced their housework time, cutting it roughly in half.

This change can be attributed to various factors such as advancements in home appliances, shifting gender roles, and increased participation of women in the workforce. On the other hand, men have gradually increased their contributions to housework during this period.
This shift in housework responsibilities can be attributed to societal changes that promote a more equitable distribution of domestic tasks between partners. As gender norms have evolved, men are increasingly taking on roles that were once predominantly associated with women, leading to a more balanced approach to housework within households. Additionally, the rise in dual-income families has necessitated a more equal division of domestic responsibilities.
In summary, over the past 50 years, married American women have seen a considerable decrease in housework time, while men have increased their contributions. This change reflects evolving gender roles and societal expectations, promoting a more equal division of labor within households.

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Answer:

$551

Step-by-step explanation:

Given the amount of profit, y, made by the company, is related to the selling price of each widget, x, by the equation y=-x^2+62x-410

The company make the maximum profit at when dy/dx = 0

dy/dx = -2x + 62

Since dy/dx = 0

0 = -2x + 62

2x = 62

x = 62/2

x = 31

substitute x = 31 into the expression y=-x^2+62x-410

y=-x^2+62x-410

y=-31^2+62(31)-410

y = -961+1922-410

y  = 551

Hence the maximum profit the company can make is $551

Answer:

3/7

Step-by-step explanation:

7/7 - 4/7 = 3/7

3/7 is in its simplest form!

Answer:

pppppp lo hehehe

Step-by-step explanation:

hehehe

Answer:

f(x) =1/3 × 4^x

f(4) = 1/3 × 4⁴

= 1/3 × 256

= 256/3

Hope this helps

Answer:

i. x = -0.5 and 1.5; ii. x = 1.5

Step-by-step explanation:

For part i, we can take a look at the x-intercepts of the parabola. When a quadratic equation equals 0, this means that we are taking a look at its roots, or solutions.

The parabola intersects the x-axis at approximately -0.5 and 1.5. We can say this is an estimate to the solutions.

For part ii, the question is asking the x value that makes the function equal 2. We just look at the point where y = 2, which happens to be 1.5. So when x = 1.5, y = 2, which is what we want.

I hope this helps!

The teacher's goal in introducing students to a card game where they must find the missing addend could be to develop and enhance their algebraic reasoning skills.

By presenting the problem as a puzzle or game, the teacher aims to engage the students in a fun and interactive way while fostering their ability to think critically and solve mathematical problems. The game helps students practice identifying the missing addend and applying algebraic thinking to find the solution. Additionally, it promotes the development of problem-solving strategies, logical reasoning, and the ability to generalize mathematical patterns, which are foundational skills in algebraic reasoning.

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a. To determine the necessary sample size with a 90% confidence level and an estimate within 1% of the population proportion, we can use the formula:

n = [(Z^2 * p * (1-p)) / E^2]

Where:
n = necessary sample size
Z = z-score for the desired confidence level (in this case, 1.645 for 90%)
p = estimated proportion from past surveys (in this case, 0.3)
E = allowable error (in this case, 0.01)

Plugging in the values, we get:

n = [(1.645^2 * 0.3 * (1-0.3)) / 0.01^2]
n = 610.09

Rounding up to the next whole number, the necessary sample size is 611.

b. To reduce the sample size, we can increase the allowable error. If we allow for an error of 0.05 instead of 0.01, we can recalculate the sample size using the same formula:

n = [(Z^2 * p * (1-p)) / E^2]

Where:
n = necessary sample size
Z = z-score for the desired confidence level (in this case, 1.645 for 90%)
p = estimated proportion from past surveys (in this case, 0.3)
E = allowable error (in this case, 0.05)

Plugging in the values, we get:

n = [(1.645^2 * 0.3 * (1-0.3)) / 0.05^2]
n = 98.19

Rounding up to the next whole number, the necessary sample size is 99. Therefore, by increasing the allowable error, we can reduce the sample size to 99. However, it's important to note that increasing the allowable error also increases the margin of error in the estimate.

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Using implicit differentiation, it is found that the radius is increasing at a rate of 0.0081 cm per minute.

The volume of a sphere of radius r is given by:

\(V = \frac{4\pi r^3}{3}\)

Applying implicit differentiation, the rate of change is given by:

\(\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}\)

In this problem, we have that:

\(\frac{dV}{dt} = 500, r = 70\)

Hence the rate of change of the radius is given as follows:

\(\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}\)

\(19600\pi\frac{dr}{dt} = 500\)

\(\frac{dr}{dt} = \frac{500}{19600\pi}\)

\(\frac{dr}{dt} = 0.0081\)

The radius is increasing at a rate of 0.0081 cm per minute.

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Answer:

2\(\sqrt{5}\)

Step-by-step explanation:

using the rule of radicals

\(\sqrt{a}\) × \(\sqrt{b}\) ⇔ \(\sqrt{ab}\)

simplifying

\(\sqrt{45}\)

= \(\sqrt{9(5)}\)

= \(\sqrt{9}\) × \(\sqrt{5}\)

= 3\(\sqrt{5}\)

Then

\(\sqrt{45}\) - \(\sqrt{5}\)

= 3\(\sqrt{5}\) - \(\sqrt{5}\)

= 2\(\sqrt{5}\)