A uniform plank AB of mass 20kg is supported horizontally at 20cm and 70cm marks from A the plank is in equilibrium when massese 50kg and 70kg are suspended at A and B respectively and the weight of 100N is suspended at the 40cm Mark from B
Answers
The equilibrium of the plank is maintained: when the net torque and net force are both equal to zero.
In this scenario, we have a uniform plank AB with a mass of 20 kg. It is supported horizontally at points 20 cm and 70 cm from point A. The plank is in equilibrium when additional masses of 50 kg and 70 kg are suspended at points A and B, respectively. Furthermore, a weight of 100 N is suspended at the 40 cm mark from point B.
To maintain equilibrium, the net torque and the net force on the plank must be zero. The torque produced by each mass and weight on the plank can be calculated as the product of the force and the distance from the pivot point. The force due to the mass of the plank and the suspended masses can be calculated using the formula F = mg, where m is the mass and g is the acceleration due to gravity (approximately 9.81 m/s^2).
The torque balance equation will involve the torques produced by the 20 kg plank, the 50 kg and 70 kg suspended masses, and the 100 N weight. By calculating these torques and setting the net torque to zero, we can analyze the equilibrium state of the plank. Additionally, we need to ensure that the net force acting on the plank is also zero, which can be confirmed by summing the forces due to each mass and weight and setting the total equal to zero.
In summary, the equilibrium of the plank is maintained when the net torque and net force are both equal to zero. This involves balancing the torques produced by the 20 kg plank, the 50 kg and 70 kg suspended masses, and the 100 N weight, as well as the forces acting on the plank.
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Related Questions
Two double bonds means that the total number of electrons being shared in the molecule is
Answers
One double bond consists 4 electrons, so 2 double bonds means 8 electrons
Answer: 8 electrons
Explanation:edg
If an electron vibrates back and forth in an clean wire with a frequency of 60.0 Hz, how many cycles make in 1.0 h?
a. 8.1 x 10^5
b. 6.0 x 10^2
c. 3.7 x 10^3
d.2.2 x 10^5
e. 4.6 x 10^4
Plz Help
Answers
If an electron vibrates back and forth in an clean wire with a frequency of 60.0 Hz, then it will make 2.2×10⁵ cycles. in 1.0 h. Hence option D is correct.
What is electric charge ?Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C
Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.
Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.
Frequency is nothing but the number of oscillation in a unit time.
Given,
frequency f = 60.0 Hz.
time t = 1.0 h = 60*60 = 3600s
F = number of cycles/time
number of cycles = F×time
The number of cycles in 1 Hr is
60*3600 = 2.2×10⁵ cycles.
Hence option D is correct.
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In recent years, assistive technologies have been developed to give people with disabilities access to resources. Examples include wheelchair ramps, voice recognition software, and screen readers. Which statement best explains how government regulations guided the development of these technologies?
A. After laws were enacted to mandate equal access for people with disabilities, consumers began to demand that all businesses provide assistive technologies.
B. As the public need for equal access for people with disabilities became understood, laws were enacted to mandate assistive technologies' inclusion in almost all public spaces.
C. Engineers recognized the lack of equal access and decided to put pressure on the government to enact laws mandating the use of assistive technologies.
D. As businesses became aware of the demand for assistive technologies, they requested money from the government to help with research and development.
Answers
The statement that best explains how government regulations guided the development of assistive technologies for people with disabilities is B
What is Disability?
Disability is a term used to describe a physical, mental, or sensory impairment that can affect a person's ability to perform daily activities or participate fully in society. Disabilities can be either visible or invisible, and they can range in severity from mild to severe. Examples of disabilities include mobility impairments, visual impairments, hearing impairments, intellectual disabilities, and mental health conditions.
The development of assistive technologies for people with disabilities was guided by government regulations aimed at ensuring equal access to resources and public spaces. These regulations were enacted as a response to the public need for equal access and were not primarily driven by consumer demand or pressure from engineers.
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An object has an acceleration of 12.0 m/s/s. If the NetForce was tripled and the mass was doubled, then the new acceleration would be _____ m/s/s
Answers
Answer: that would be New acceleration would be 12 m/s²
Explanation:
1. A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N
opposing the motion. Calculate the acceleration of the object.
Answers
The acceleration of the block is 6.4 m/s².
To calculate the acceleration of the block, we need to consider the forces acting on it.
The applied force is 40 N, and since it is the only horizontal force in the direction of motion, it is the net force acting on the block.
The frictional force opposing the motion is 8 N.
The acceleration, we can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).
The net force is the difference between the applied force and the frictional force:
40 N - 8 N = 32 N.
Now, we can plug the values into Newton's second law:
32 N = 5 kg × a.
Solving for the acceleration (a), we get
a = 32 N / 5 kg
a = 6.4 m/s².
Therefore, the acceleration of the block is 6.4 m/s².
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Electrons surround the nucleus in orbitals.
True or False
Answers
Answer:
true
hope this helps !
) Elasticity Elasticity measures the of one thing to another. In every elasticity, there is a tion and a tion. (fill in the 1st part of the words) In every elasticity formula, the tion goes on the bottom of the fraction and the tion goes on the top. 3) 4) If the tion is bigger than the situation sensitive or tion, we call the 5) If the tion is bigger than the situation insensitive or tion, we call the 6) In elasticities, we measure changes in percentages. To get a percentage change for elasticity purposes, you take the 7) Price Elasticity of Demand elasticity measures the sensitivity of to 8) If price goes up from $4 to $12 and quantity demanded goes down from 5 to 3, what is the price elasticity of demand. Is it elastic or inelastic? Total revenue has gone from to Notice that the direction of total revenue has followed the stronger effect, which was the effect. 9) If price goes down from $11 to and the quantity demanded increases from 10 to 30, what is the price elasticity of demand. Is it elastic or inelastic? Total revenue has gone from to Notice that the direction of total revenue has followed the stronger effect, which was the effect
Answers
Total revenue has gone from $110 to $150. Notice that the direction of total revenue has followed the stronger effect, which was the price decrease.
Elasticity measures the sensitivity of one thing to another. In every elasticity, there is a numerator and a denominator. In every elasticity formula, the denominator goes on the bottom of the fraction and the numerator goes on the top. If the denominator is bigger than the numerator, we call the elasticity insensitive or inelastic. If the numerator is bigger than the denominator, we call the elasticity sensitive or elastic. In elasticities, we measure changes in percentages.
To get a percentage change for elasticity purposes, you take the difference and divide it by the original amount, and then multiply by 100. Price Elasticity of Demand elasticity measures the sensitivity of quantity demanded to price. If the price goes up from $4 to $12 and quantity demanded goes down from 5 to 3, the price elasticity of demand is -1. It is elastic because the elasticity value is greater than one. Total revenue has gone from $20 to $36. Notice that the direction of total revenue has followed the stronger effect, which was the price increase. If the price goes down from $11 to $5 and the quantity demanded increases from 10 to 30, the price elasticity of demand is 1.1. It is elastic because the elasticity value is greater than one.
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A player throws a javelin at an unknown angle with a horizontal velocity 20 m/s and vertical velocity 60 m/s. Find its angle and resultant velocity.
Answers
Answer:
63º~64º
Explanation:
so imagine a graphic with a triangle. The distance between the zero and the horizontal (x) is 20 and the distance between 0 and vertical (y) is 60
20 = base
60 = height
hypotenuse = L
tg = cato/cata
tg = 60/20
tg = 2
I give up
A bottle with a volume of 187 u. s. fluid gallons is filled at the rate of 1.7 g/min. (water has a density of 1000 kg/m3, and 1 u.s. fluid gallon = 231 in.3.) how long does the filling take?
Answers
To fill the volume of 187 u. s. fluid gallons at a rate of 1.7 g/min will take: 416215.8 min
To solve this problem the we have to do the conversion of units with the given information and the following formulas:
t = x/vd = m/vWhere:
x = distancet = timev = velocityv= volumed= densitym= massInformation about the problem:
x ( volume capacity) = 187 u. s. fluid gallonsv(fill rate) = 1.7 g/mind = 1000 kg/m³1 u.s. fluid gallon = 231 in³t = ?By converting the density unit from (kg/m³) to (g/in³)and then to (g/u.s. fluid gallon) we have:
d = 1000 kg/m³ * 1000 g/ 1 kg * 1 m³/61020 in³
d =16.380 g/in³ * 231 in³ /1 u.s. fluid gallon
d = 3783.78 g/u.s. fluid gallon
Applying the density formula and clearing the mass (m), we get:
m = d * v
m = 3783.78 g/u.s. fluid gallon * 187 u. s. fluid gallons
m = 707566.86 g
Applying the time formula we have that:
t = x/v
t = 707566.86 g / 1.7 g/min
t = 416215.8 min
What is unit conversion?It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.
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A 2.0-kg object experiences a force of 12.0 N for a time of 0.30 seconds. What is the momentum change experienced by the object?
Answers
The momentum change experienced by the object is 3.6 Ns.
Change in momentum:
This can be defined as the product of mass and change in velocity. change in momentum from newton's second law of motion is also the product of force and time.
To calculate the change momentum of the object, we apply the formula below.
Formula:
ΔM = Ft................... Equation 1Where:
ΔM = Change in momentumF = Force experienced by the objectt = time.From the question,
Given:
F = 12.0 Nt = 0.30 secondsSubstitute these values into equation 1
ΔM = 12(0.3)ΔM = 3.6 Ns.Hence, the change in momentum of the object is 3.6 Ns
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A small car of mass M travels along a straight,horizontal track. As suggested in the figure, the track then bendsinto a vertical circle of radius R.
What is the minimum acceleration that the car must have at the topof the track if it is to remain in contact with the track?
A) 4. 9 m/s2,upward
B) 9. 8 m/s2,downward
C) 4. 9 m/s2,downward
D) 9. 8 m/s2,upward
E) 19. 6 m/s2,upward
Answers
According to the given statement the correct answer will be option ( D ) 9.8 m/s², upward.
The minimum acceleration that the car must have at the top of the track in order to remain in contact with the track can be determined by considering the forces acting on the car.
When the car is at the top of the track, it is in circular motion and experiences two forces:
its weight (mg) acting downward and the normal force (N) exerted by the track acting upward.
To remain in contact with the track, the net force acting on the car must be directed towards the center of the circle.
This means that the net force should be the difference between the normal force and the weight, and it should be directed downward.
The net force is given by:
Net force = N - mg
At the top of the track, the net force is equal to the centripetal force required to keep the car moving in a circle of radius R.
The centripetal force is given by:
Centripetal force = mv² / R
where m is the mass of the car and v is its velocity.
Setting the net force equal to the centripetal force, we have:
N - mg = mv² / R
Solving for v², we get:
v² = gR
where g is the acceleration due to gravity.
The minimum acceleration at the top of the track is when v is at its maximum value, which is when v = √(gR).
Therefore, the minimum acceleration that the car must have at the top of the track is:
a = v² / R = (gR) / R = g
The minimum acceleration that the car must have at the top of the track in order to remain in contact with the track is equal to the acceleration due to gravity (g).
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question 1 explain how sound is amplified by a resonance tube.
Answers
The phenomenon of sound amplification by a resonance tube is explained by the concept of resonance.
About the concept of resonanceResonance is the ability of an object to absorb energy from a vibrating object when it is subjected to the same frequency as that of the vibrating object.
The following is the process through which sound is amplified by a resonance tube:
A tuning fork is used to generate sound waves of a specific frequency. The sound waves are generated when the tuning fork is struck against a surface, which causes it to vibrate. This vibration produces sound waves of a particular frequency that travel through the air and into the resonance tube.
As the sound waves travel through the resonance tube, they encounter the closed end of the tube. At the closed end, the air molecules are forced to move back and forth in a short distance, causing a buildup of pressure at the closed end of the tube.
This causes the sound waves to reflect back towards the open end of the tube, where they encounter another set of air molecules that are in motion in the same direction as the sound wave.This causes the air molecules to move more vigorously, which in turn increases the amplitude of the sound wave.
The amplitude of the sound wave is the measure of the amount of energy carried by the sound wave. The sound wave is now amplified and the resonance tube resonates at the same frequency as that of the sound wave produced by the tuning fork.
The length of the resonance tube can be adjusted to produce different frequencies of resonance. This can be achieved by changing the length of the tube or by altering the properties of the air molecules within the tube. This is the working principle of sound amplification by a resonance tube.
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B. What types of energy conversions took place in your body that allowed you to complete the laboratory activity
Answers
Answer:
See the explanation below
Explanation:
Energy can neither be created nor destroyed but can be transformed from one form to another.
When we eat food the chemical energy in the food is transformed to kinetic energy that enables us to do work in the laboratory
Consider an airplane flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. Calculate the pressure at this point. Assume incompressible flow. Given: p _1 =7.01×10^4 N/m^2 and rho=0.909kg/m^3 . The pressure at a point on the wing is ×10 ^4 N/m^2
Answers
An airplane is flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. The pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\).
To calculate the pressure at a point on the wing, we can use Bernoulli's equation, which relates the pressure, velocity, and density of a fluid in steady, incompressible flow.
The equation is as follows:
P + 1/2 * ρ * \(V^2\) = constant
where P is the pressure, ρ is the density of the fluid, and V is the velocity of the fluid.
Given:
\(P_1 = 7.01 * 10^4 N/m^2\) (pressure at standard altitude)
ρ = \(0.909 kg/m^3\) (density of the fluid)
\(V_1 = 42 m/s\) (velocity of the airplane)
\(V_2 = 88 m/s\) (velocity at the point on the wing)
To find the pressure at the point on the wing, we can use Bernoulli's equation for the standard altitude and the point on the wing, and then solve for P:
\(P_1 + 1/2\) * ρ * \(V_1^2\) = \(P + 1/2\) * ρ * \(V_2^2\)
Substituting the given values:
\(7.01 * 10^4 + 1/2 * 0.909 * 42^2 = P + 1/2 * 0.909 * 88^2\)
Simplifying the equation:
\(7.01 × 10^4 + 1/2 * 0.909 * 1764 = P + 1/2 * 0.909 * 7744\)
7.01 × 10^4 + 804.906 = P + 3526.242
\(P + 4329.148 = 7.01 *10^4\)
\(P = 7.01 * 10^4 - 4329.148\)
\(P = 6.96 * 10^4 N/m^2\)
Therefore, the pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\)
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At highway speeds, anautomobileis capable of an acceleration of about 1.6m/s2. at this rate, how long does it take to accelerate from 80km/hto 110km/h?
Answers
At highway speeds, an automobile is capable of an acceleration of about 1.6m/s2. at this rate, it take to accelerate from 80km/h to 110km/h is 5.2084s.
What is velocity?Velocity is the directional speed of a object in motion as an indication of its rate of change in the position as observed from a particular frame of reference and as measured by a particular standard of the time (e.g. 60 km/h northbound). Velocity is a fundamental concept in kinematics, the branch of classical mechanics that describes the motion of the bodies.
Velocity is a physical vector quantity; both the magnitude and direction are needed to define it. The scalar absolute value (magnitude) of velocity is called the speed, being a coherent derived unit whose quantity is measured in the SI (metric system) as meters per second (m/s or m⋅s−1). If there is a change in the speed, direction or both, then the object is said to be undergoing an acceleration
Therefore,
v = v0 + at, where v is the final velocity, v0 is initial velocity, a is acceleration and t is time, solve for t:
t = (v - v0) / a,
note that all the variables must be in the same units, we want m/s which is a:
110 km / hour = (110 * 1000) / (60 * 60) = 30.5556 m/s:
80 km / hour = (80 * 1000) / (60 * 60) = 22.2222 m/s:
t = (30.5556 - 22.2222) / 1.6 = 5.2084 s
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What type of electrical signal is an all-or-none response?
a. action potential
b. local potential
Answers
The type of electrical signal that exhibits an all-or-none response is action potential. So, option A is accurate.
An action potential is a rapid and brief reversal of the electrical potential across a cell membrane, which occurs in excitable cells such as neurons and muscle cells. It is characterized by an all-or-none response, meaning that once the threshold stimulus is reached, the action potential is generated at full strength regardless of the strength of the initial stimulus.
In an all-or-none response, the action potential either occurs fully or does not occur at all. If the stimulus reaches the threshold level, the cell membrane depolarizes and generates an action potential that propagates along the length of the neuron or muscle fiber. However, if the stimulus does not reach the threshold, no action potential is generated.
This property of all-or-none response ensures the consistency and reliability of signal transmission in the nervous system. It allows for the generation of precise and rapid electrical signals that can propagate over long distances without losing their strength or information content.
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Un avión se mueve horizontalmente a 50 m/s y a una altura de 2.0 km. Desde el avión se dé deja caer un objeto denso. (use g= 9.8 m/s 2). Calcule. A) ¿tres segundos después de haber soltado el objeto. ¿Este habrá descendido? B) la distancia horizontal recomienda por el objeto a los 3 segundos? C) ¿Qué tiempo emplea el objeto en llegar al suelo? D) la distancia horizontal recorrida por el objeto desde que fue soltado hasta llegar al suelo?
Answers
Answer:
Haz tu mejor esfuerzo, ok
Explanation:
HEYYYY!! PLEASE HELP!!! Describe three machines that humans have designed and explain how the mechanical advantage is used.!!
Answers
Answer:
Three machines that humans have created are the lever, the wheel, and the axle, and also a pulley. even though there's actually more. A lever is A rigid bar that is free to move around a fixed point, such as a screwdriver. The wheel and axle, everyone should know what that is and what it does, it lifts heavy objects, moves people quickly, and moves parts of a complex machine. Pulleys are used to lift things, pulleys can be used singly or with many pulleys working together in order to transport people or things. They can also be used to provide power from one shaft to another. ... Construction pulleys are used in order to lift and place heavy materials.
A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2. What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2 . What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
–1.6 × 103 N
–1.63 × 103 N
–2.4 × 103 N
–5.27 × 104 N
Answers
The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N
How do I determine the gravitational force?The gravitaional force between two objects can be obtained by using the following formula:
F = GM₁M₂ / r²
Where
F is the gravitaional force G is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apartThe following data were obtained from he question:
Mass of satellite (M₁) = 5400 = 5.4×10³ KgHeight (h) = 30000 km = 30000 × 1000 = 30000000 mMass of Earth (M₂) = 6.0×10²⁴ KgRadius of Earth (R) = 6400 km = 6400 × 1000 = 6400000 mDistance apart (r) = R + h = 6400000 + 30000000 = 36400000 mGravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²Gravitational force (F) =?The gravitaional force can be obtained as shown below:
F = GM₁M₂ / r²
F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²
F = 1.63×10³ N
Thus, the gravitational force is 1.63×10³ N
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what is my real name
Answers
Answer:
Probably Trent or something like that
Answer:
Trent or tranthjhikjhjhuiivd
A 10 kg box slides down a lane inclined at an angle θ = 30 . The plane has a friction of coefficient 0.1. The box starts from the rest and slides down the plane for 2.0 s. What is the distance that the box travels down the plane?
Answers
Answer:
The distance the box traveled down the plane is 19.28 m
Explanation:
The angle of repose, α, is given by the relation;
tan⁻¹(μ) = α
tan⁻¹(0.1) = 5.7°
Therefore, we have;
M·g·sin(θ) - μ·N = M·a
Where:
M = Mass of the box = 10 kg
g = Acceleration due to gravity = 9.81 m/s²
θ = Angle of inclination of the plane = 30°°
μ = Coefficient of friction = 0.1
a = Acceleration of the box along the incline plane
N = Normal force due to the weight of the box = M·g·cos(θ)
10 × 9.81 × sin30 - 0.1 × 9.81 × cos(30) = 10 × a
48.2 = 10 ×a
a = 48.2/10 = 4.82 m/s²
The distance, s, traveled by the box is given by the relation;
s = u·t + 1/2×a·t²
Where:
u = Initial velocity = 0 m/s
t = Time of motion = 2.0 s
∴ s = 0×2 + 1/2 × 4.8 × 2² = 19.28 m
The box traveled 19.28 m down the plane.
The distance that the box travels down the plane is 8.1 m.
The given parameters;
mass, m = 10 kgangle, θ = 30⁰coefficient of friction, μ = 0.1time of motion of the box, t = 2 sThe acceleration of the box is calculated as follows;
\(\Sigma F_{net} = ma\\\\mgsin\theta - \mu mg cos\theta = ma\\\\gsin\theta - \mu g cos\theta = a\\\\g(sin\theta - \mu cos \theta ) = a\\\\9.8(sin30 \ - \ 0.1\times cos 30) = a\\\\9.8(0.413) = a\\\\4.05 \ m/s^2 = a\)
The distance traveled by the box down the plane is calculated as follows;
\(s= ut + \frac{1}{2} at^2\\\\s = 0 + \frac{1}{2} \times 4.05 \times 2^2\\\\s = 8.1 \ m\)
Thus, the distance that the box travels down the plane is 8.1 m.
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assuming a typical efficiency for energy use by the body, if a 75 kg person were to use the energy in this candy bar to climb stairs, how high could she go?
Answers
The person can go high up to 685.71 m. The principle of energy conservation is applied in this question. First , use the term of efficiency to estimate the available energy. Finally, use energy conservation to calculate the person's height.
What is potential energy?The following formula can be used to calculate an object's potential energy.
PE = mgh
Here, m denotes mass, g denotes gravitational acceleration, and h denotes body height.
Step 1:
The average efficiency of energy utilised by the body is 25%. As a result, climbing the stairs consumes 25% of the person's entire energy. The following formula is used to determine available energy:
E' = E(25/100)
In the above equation, replace E with 480 Cal.
E' = (480 Cal) (25/100) ((4.2 * 10^3 J)/1 Cal)
= 504 * 10^3 J
Step 2:
The body's initial energy is the energy needed to execute the task. The following is the initial energy:
TE = E'
Substitute 504 * 10^3 J in the above equation.
TE = 504 * 10^3 J
The available energy is used to complete the task of climbing the steps. As a result, the starting energy equals the end energy.
Replace mgh with TE in the above expression and find the height h.
mgh = 504 * 10^3 J
h = (504 * 10^3 J)/mg
Substitute 75 kg for m and 9.8 m/s^2 for g in the above expression.
h = (504 * 10^3 J)/(75 kg)*(9.8m/s^2)
= 685.71 m.
Thus, the height covered by the person is 685.71 m.
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a belt is placed around a pulley 41 cm in diameter and rotating at 242 rpm, what is the linear speed in m/s of the belt
Answers
Given
d: diameter
d = 41 cm
We need radius information so we will calculate it:
r: radius
r = d/2
r = 41/2
r = 20.5 cm
Rotating speed
w = 242 rpm
Procedure
At a distance r from the center of the rotation, a point on the object has a linear speed equal to the angular speed multiplied by the distance r. The units of linear speed are meters per second, m/s.
\(v=\omega r\)But before using the formula we need to have all the units in the same system. So we need to go from rpm to rad/s and from cm to m
\(\begin{gathered} 242\cdot\frac{\text{rev}}{\min}\cdot\frac{2\text{ pi rad }}{1\text{ rev}}\cdot\frac{1\text{ min}}{60\text{ s}} \\ 25.34\text{ rad/s} \\ \\ 20.5\text{ cm}\cdot\frac{1m}{100\operatorname{cm}} \\ 0.205\text{ m} \end{gathered}\)Now we can calculate the linear velocity of the belt.
\(\begin{gathered} v=\omega r \\ v=25.34\text{ rad/s}\cdot0.205\text{ m} \\ v=5.1947\text{ m/s} \end{gathered}\)Answer
The linear velocity of the belt would be 5.2 m/s.
If a rock has a speed of 12 m/s as it hits the ground, from what height did it
fall, assuming its initial speed was zero? Its mass is 50 kg.
A. 600 m
B. 4.2 m
C. 12 m
D. 7.3 m
Answers
Answer:
To find the height the following formula should be used:
v 2 = u 2 + 2aH
Explanation:
Assuming this occurs on earth, a= 9.8 ms -2
-2 2
12=0+2 x9.8 x H
144
_______ =H
2 x 9.8
H= 7.35m
Jimmy can travel 550 miles South in 10 hours. Jimmy's velocity is____
Answers
Answer:
The answer is
55 miles/hrExplanation:
The velocity or speed of an object can be found by using the formula
\(velocity \: = \frac{distance}{time} \)
From the question
time taken to travel = 10 hours
distance covered = 550 miles
Substitute the values into the above formula and solve for the velocity
That's
\(velocity = \frac{550}{10} \)
We have the final answer as
55 miles/hrHope this helps you
Let’s say you could go swimming on the moon. How would the pressure at the bottom of a 3-m deep swimming pool compare with the pressure at the bottom of the same pool on earth?.
Answers
The pressure at the bottom of a 3-meter deep swimming pool on the moon would be significantly lower compared to the pressure at the bottom of the same pool on Earth.
How does the pressure at the bottom of a 3-meter deep swimming pool on the moon compare to Earth?The pressure at the bottom of a swimming pool on the moon would be much lower than on Earth. This is because the pressure in a fluid depends on the depth and the density of the fluid. The moon has a much lower gravitational force compared to Earth, resulting in a lower density of the moon's atmosphere and water. Therefore, the pressure exerted by the moon's atmosphere or water at a given depth is significantly lower than on Earth. As a result, the pressure at the bottom of a 3-meter deep swimming pool on the moon would be much less than the pressure at the bottom of the same pool on Earth.
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Jorge Masvidal weighs 77.1107 how many grams?
Answers
A box slides down a frictionless ramp, with no initial velocity. If the height of the ramp is 83 meters high, how fast will the box be traveling at the bottom?
How do i solve this?
Answers
At the base of the ramp, the box will be moving at a speed of roughly 40.5 m/s.
How do you calculate the rate of acceleration down a smooth ramp?Acceleration on a ramp is equal to the product of gravitational acceleration and the height to length ratio of the ramp. Acceleration on a ramp is equal to gravity acceleration times the sine of the ramp angle.
Due to its height above the ground at the top of the ramp, the box contains potential energy, as determined by:
PE = mgh
where m is the box's mass, g is gravity's acceleration (9.81 m/s2), and h is the ramp's height (83 meters).
This potential energy is changed into kinetic energy when the box descends the ramp by:
KE = (1/2)mv²
where v denotes the box's speed at the base of the ramp.
Energy is conserved, hence we may compare these two statements:
PE = KE
mgh = (1/2)mv²
Solving for v, we get:
v = √(2gh)
Plugging in the given values, we get:
v = √(29.8183) = 40.5 m/s (rounded to two decimal places)
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A 7.0 kg mass is lifted 4.0 m above the ground. Find the change in gravitational energy.
Answers
\(\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}\)
Actually Welcome to the concept of Graviatoonal Energy.
P = mgh
hence,
E = (7)*(9.8)*(4) = 274.4 joules
==> Energy = 274.4 J
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