A uniformly charged disk has radius 2.50 cm and carries a total
charge of 5.0×10−12 C
A-
Find the magnitude of the electric field on the xx-axis at xx =
20.0 cmcm
Express your answer in newtons per

Answer:

Variable- not consistent or having a fixed pattern; liable to change

Data- facts and statistics collected together for reference or analysis

Control- a group or individual used as a standard of comparison for checking the results of a survey or experiment

Technology- the application of scientific knowledge for practical purposes, especially in industry

Hypothesis- a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation

Physical Science- the sciences concerned with the study of inanimate natural objects, including physics, chemistry, astronomy, and related subjects

Experiments- a scientific procedure to make a discovery, test a hypothesis, or demonstrate a known fact

Explanation:

Answer:

You can make an electromagnet stronger by doing these things: wrapping the coil around a piece of iron (such as an iron nail) adding more turns to the coil. increasing the current flowing through the coil.

Explanation:

The slope of the line in the velocity versus time plot is equal to the acceleration of the object.

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Ampere's law used to find bound current density. Symmetry considered. Magnetic field outside cylinder = µ₀M/2 + µ₀Mr²/2R³.

To find the magnetic field due to the uniform magnetization M inside and outside an infinitely long circular cylinder, follow these steps:
1: Apply Ampere's law
Ampere's law states that the integral of the magnetic field B around a closed loop is equal to the product of the permeability of free space (µ₀) and the current enclosed by the loop.
2: Determine the bound current density
For a uniformly magnetized cylinder, the bound current density Jb can be found by taking the cross product of M and the normal vector n to the surface: \(Jb = M × n\).
3: Consider the symmetry of the problem
Since the cylinder is infinitely long and uniformly magnetized along its axis, the magnetic field will be cylindrically symmetric. This means that the magnetic field will only have an azimuthal component (B_phi), and it will not depend on the azimuthal angle (phi).
4: Calculate the magnetic field inside the cylinder
Inside the cylinder, there is no bound current enclosed by the Amperian loop, so the magnetic field B_inside is zero.
5: Calculate the magnetic field outside the cylinder
Outside the cylinder, the bound current enclosed by the Amperian loop is given by the product of the magnetization M and the cylinder's cross-sectional area (A = πR², where R is the cylinder's radius).

Thus, the magnetic field B_outside can be calculated using Ampere's law:

\(B_{outside} * 2πr = µ₀ * M * πR²,\)

where r is the distance from the cylinder's axis.

Step 6: Solve for the magnetic field outside the cylinder
\(B_{outside}= (µ₀ * M * R²) / (2 * r),\)

where R is the cylinder's radius and r is the distance from the cylinder's axis.

In conclusion, the magnetic field due to the uniform magnetization M inside the infinitely long circular cylinder is zero (B_inside = 0), and the magnetic field outside the cylinder is given by \(B_{outside} = (µ₀ * M * R²) / (2 * r).\).

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Answer:

I believe 650 or C

Explanation:

plz mark brainnlyist :)

The equilibrium constant (Keeq) for a reaction at 25 °C can be calculated using the equation  Keeq = e^(−ΔG°/RT)

The equilibrium constant (Keeq) for a chemical reaction can be calculated using the equation Keeq = e^(−ΔG°/RT), where ΔG° represents the standard free-energy change, R is the gas constant, and T is the temperature in Kelvin.

In this case, the given standard free-energy change is −12.50 kJ mol−1 (−2.988 kcal mol−1). To calculate the equilibrium constant at 25 °C, we need to convert the temperature to Kelvin by adding 273.15 (25 °C + 273.15 = 298.15 K). Then, we substitute the values into the equation to find the equilibrium constant.

Keeq = e^(−12.50 kJ mol−1 / (8.314 J K−1 mol−1 × 298.15 K))

By evaluating the expression, we can determine the equilibrium constant (Keeq) for the given reaction at 25 °C.

The relationship between standard free-energy change and equilibrium constant in chemical reactions to understand the thermodynamic aspects of chemical equilibria

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Answer:

Explanation:

The amount of force needed needs to be greater than all the forces acting in the opposite direction that the bowling ball was thrown. This includes air resistance, floor friction, gravity, and any other force involved. As long as the force acting on the bowling ball that is causing it to go in the direction of the pins is slightly greater than the opposite acting forces then it will continue in that direction. Since no values are provided we cannot calculate the actual precise value of force needed.

The magnitude of the net force on the block while it is sliding is 9.8 N.

The angle of inclination of the plane is calculated by applying the principle of trigonometry ratio.

Considering the vertical height (10 m) and length of the incline (20 m);

sin θ = 10 m / 20 m

sin θ = 1/2

sin θ = 0.5

θ = arc sin(0.5)

θ  = 30⁰

The magnitude of the net force on the block while it is sliding is calculated as follows;

F(║) = F(net) = mg sinθ

where;

F(net) = (2 x 9.8) x sin(30)

F(net) = 9.8 N

Thus, the net force on the block is the parallel component of the weight of the block.

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Answer:

2Ca+ O2 ------> 2CaO

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The cycle time of the entire line is 30.00528 minutes per part.

To calculate the cycle time of the entire line, we need to consider the processing times, failures, and repairs of both the milling machine and the turning machine.

For the milling machine:

Mean processing time (t0) = 15 mins

Standard deviation of processing time (sigma0) = 3 mins

Mean time to failure (MTTF) = 750 mins

Mean time to repair (MTTR) = 200 mins

For the turning machine:

Mean processing time (t0) = 15 mins

Standard deviation of processing time (sigma0) = 3 mins

Mean time to failure (MTTF) = 110 mins

Mean time to repair (MTTR) = 38 mins

We also know that the arrival rate to the milling machine is 1.2 parts/hr, with a coefficient of variation (CV) of 1.

To calculate the cycle time, we can use the following formula:

Cycle time = Processing time + Failure time + Repair time

Processing time:

The processing time is the sum of the mean processing times of the milling machine and the turning machine:

Processing time = t0 (milling machine) + t0 (turning machine) = 15 mins + 15 mins = 30 mins

Failure time:

The failure time is the inverse of the MTTF, considering the arrival rate:

Failure time = 1 / (MTTF * Arrival rate) = 1 / (750 mins * (1.2 parts/60 mins)) = 0.00111 parts/min

Repair time:

The repair time is the inverse of the MTTR, considering the coefficient of variation (CV):

Repair time = 1 / (MTTR * CV) = 1 / (200 mins * 1.2) = 0.00417 parts/min

Cycle time:

Cycle time = Processing time + Failure time + Repair time = 30 mins + 0.00111 parts/min + 0.00417 parts/min

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The final velocity will be \(\rm V= \sqrt{\frac{4gh}{3} }\ m/sec\). Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The change of distance with respect to time is defined as speed.

From the law of conservation of energy:

\(\rm KE_i + PE_i = KE_f+PE_f \\\\ 0+mgh = \frac{1}{2} mV^2 +\frac{1}{2} I\omega^2\)

The moment of inertia of the disc;

\(\rm I= mr^2\)

It can also be found as;

\(\rm I = \frac{V}{r} \\\\\)

Put the obtained values;

\(mgh = \frac{1}{2} mv^2+\frac{1}{2} mv^2=mv^2\\\\ mgh = mv^2 \\\\ v=\sqrt{gh}\)

if a disk of the same mass and radius as the hoop rolled down the hill;

\(mgh= \frac{1}{2} M+\frac{mr^2}{2r^2} V^2 \\\\ gh = \frac{3}{4} V^2 \\\\ V= \sqrt{\frac{4gh}{3} }\ m/sec\)

Hence the final velocity will be \(\rm V= \sqrt{\frac{4gh}{3} }\ m/sec\).

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Answer:

The coefficient of friction between m₂ and the table is approximately 0.2703

The magnitude of the tension in cable is 28.737 N

Explanation:

The given parameters are;

The mass of the block on the table, m₂ = 5.8 kg

The mass of the hanging block, m₁ = 4.5 kg

The distance in which the block has moved = 0.317 m

The speed after the block moves = 1.33 m/s

The acceleration due to gravity, g = 9.8 m/s²

The coefficient of friction between m₂ and the table = μ

The acceleration, a, of the blocks is given from the formula of speed, v, of a body at a given distance, s, from rest as follows;

v² = 2 × a × s

Where;

v = 1.33 m/s

s = 0.317 m

Substituting the values gives;

1.33² = 2 × a × 0.317

a = 1.33²/(2 × 0.317) ≈ 2.79

The acceleration, a ≈ 2.79 m/s²

Therefore, we have the force acting on the system given as follows;

Weight of m₁ - Frictional force of m₂ = (m₁ + m₂) × a

4.5 × 9.8 - 5.8 × 9.8 × μ = (4.5 + 5.8) × 2.79

4.5 × 9.8 - 5.8 × 9.8 × μ = 28.737 N

(4.5 × 9.8)N -  28.737 N = 5.8 × 9.8 × μ

44.1 N -  28.737 N =56.84 N × μ

15.363 N = 56.84 N × μ

μ =  15.363 N/(56.84 N) ≈ 0.2703

The coefficient of friction between m₂ and the table = μ ≈ 0.2703

The coefficient of friction between m₂ and the table ≈ 0.2703

The magnitude of the tension in cable = (m₁ + m₂) × a = 28.737 N.

The magnitude of the tension in cable = 28.737 N

Note that this is a trick question. It is true that the mass of a star affects its life cycle but all stars must go through the stages listed below. Note that the larger the solar mass of a star, the shorter its life cycle. Hence, in each of the stages given here is what will occur:

Prenatal Stage

Birth Stage

Adolescence/Adulthood

Middle age

Old age

Death

The solar mass is a unit of mass used to measure the masses of objects in the solar system, including stars. It is defined as the mass of the Sun, which is approximately 1.989 x 10³⁰ kilograms, or about 333,000 times the mass of the Earth.

Hence, since the earth's sun is 1.989 x 1010³⁰ kilograms, a star described as having 1 solar mass is simply a star equivalent of the Earth's sun.

Note however that the solar mass is often used as a standard unit of mass for comparing the masses of objects in the universe, such as planets, asteroids, and stars.

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Full Question:

Compare the following stages in the lives of a human being and a star: prenatal, birth, adolescence/ adulthood, middle age, old age, and death. What does a star with a solar mass of 1 solar mass do in each of these stages?

The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.

The freezing point is the temperature at which the substance changes its phase from liquid to solid.

The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.

Answer:

it g hope it helps you out

stopping distance = 4.52m

stopping distance when speed is doubled = 18.09m

The stopping distance of a sled depends on several factors, including its initial speed, the surface on which it is sliding,

kinetic friction and the resistance provided by the sled's runners or skis.

The stopping distance of the sled can be found using the formula:

stopping distance = (initial speed^2)/(2*coefficient of kinetic friction*acceleration due to gravity)

(a) Plugging in the given values, we get:

stopping distance = (3.50^2)/(2*0.135*9.81) = 4.52 m

Therefore, the sled moves 4.52 meters before it comes to a complete stop.

(b) If the initial speed is doubled to 7.00 m/s, the stopping distance can be calculated as:

stopping distance = (7.00^2)/(2*0.135*9.81) = 18.09 m

Therefore, the stopping distance for the sled would be 18.09 meters if its initial speed is doubled.

This shows that the stopping distance increases significantly as the initial speed increases.

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Answer:C.3

Explanation:

Answer:

yes

Explanation:

Answer:Doubling the mass or doubling the speed will have a greater effect on the kinetic energy of the ball. Because doubling the mass would have a greater effect on the kinetic energy of the ball because you are dividing the mass by velocity.

Explanation:

The wild offers more natural structures and temperatures that keep animals adapted to their surroundings. However, in captivity animals tend to differ from their wild counterparts. For one thing, the wild cultivates an animal's hunting skills but, when or if they are releasing into the wild, they do not know what to do whereas they have been sheltered their entire life. They don't know how to find natural structures to keep warm in, what places are safe or even survival strategies. The conditions in the wild teach an animal to survive while the conditions from man-made structures just give them an easy survival.

Hope this helps and have a nice day.

-R3TR0 Z3R0

Answer:

the answer is 4m/ s²

hope this helps love!! <3

The magnetic field inside the solenoid has a magnitude of 5.74*10^-3 T.  A 105 cm long solenoid with 1090 turns of winding and a 2.83 cm radius.

The greatest size and direction of an object are referred to as its magnitude. Both vector and scalar values use magnitude as a common factor. We know that scalar quantities are those that have magnitude and nothing else by definition. An electric charge, an electric current, and magnetic materials are all affected magnetically by a magnetic field, which is a vector field. Is called as magnetic field.

Given: length l = 1,05 m,

radius r = 2,83*10-2 m,

number of revolutions N = 1090,

current I = 4,

B = 4*3.14*10^-7*1090*4.4/1.05

B = 5.74*10^-3 T is the magnetic field inside the solenoid.

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The amount of energy required to warm 125 g of iron from 23.5 to 78.0 degrees Celsius is approximately 192.7 kilojoules.

To calculate the amount of energy required to warm a substance, we can use the formula:

Q = m * c * ΔT

where Q represents the energy (in joules), m is the mass of the substance (in grams), c is the specific heat capacity of the substance (in joules/gram·degree Celsius), and ΔT is the change in temperature (in degrees Celsius).

The specific heat capacity of iron is typically around 0.45 joules/gram·degree Celsius. Converting the mass of iron to kilograms (125 g = 0.125 kg) and the temperature change to Kelvin (ΔT = 78.0 - 23.5 = 54.5 °C = 54.5 K), we can plug the values into the formula:

Q = 0.125 kg * 0.45 J/g°C * 54.5 K = 3.04125 joules

Converting joules to kilojoules (1 kilojoule = 1000 joules), we get:

\(Q = \frac{3.04125 joules }{ 1000}\\ Q= 0.00304 kilojoules\)

Therefore, the amount of energy required to warm 125 g of iron from 23.5 to 78.0 degrees Celsius is approximately 0.00304 kilojoules or approximately 192.7 kilojoules when rounded to three significant figures.

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Answer:

Subduction, Trench, Mantle

Explanation:

Answer: subduction, trench, and mantle

Explanation:

Answer:

I=0.3 A

R=25 Ohm

V=?

V=IR

0.3X25=7.5

Answer:

7.5 V

Explanation:

current × resistance = voltage

The relative humidity at the surface  is 63.55%. Relative Humidity (RH) refers to the measure of the degree of water vapor present in the atmosphere as compared to the maximum amount of water vapor required for saturation at that temperature.

In order to determine the relative humidity at the surface of the given problem, we will first need to determine the saturation vapor pressure at

-16.9°C.1.

Using the Tetens formula, we get;

es = \(6.11 × 10 ^ ((7.5T)/(T + 237.3))\)

Here,

T = -\(16.9°Ces = 6.11 × 10 ^ ((7.5(-16.9))/( -16.9 + 237.3))= 1.07 kPa2\).

Using the Clausius-Clapeyron relation, we get;

e = \(es × e^[-L/R (1/T - 1/T0)]\)

Here, L is the latent heat of vaporization of

water = \(2.45 × 10 ^ 6 J/kg\)

R is the specific gas constant for water

vapor = 461.5 J/kg K.1/T

is the Kelvin temperature at which es occurs,

i.e. (-16.9 + 273) = 256 K.1/T0

is the Kelvin temperature of the surface dew point temperature,

i.e. \((12 + 273) = 285 K.e = 1.07 kPa × e^[-(2.45 × 10 ^ 6 / 461.5)(1/256 - 1/285)]= 0.68 kPa3.\)

The relative humidity at the surface is given by;

RH = (e/es) × 100RH = (0.68/1.07) × 100= 63.55%

Therefore, the relative humidity at the surface of the given problem is 63.55%.

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The true of an image produced by this mirror will be 2.5 times smaller and virtual. Option C is correct.

When light beams from an object reflect off a mirror, they intersect with the picture of that thing called an image. Real and virtual images are the two sorts of images.

The ratio of xi to xo for a certain mirror is 2.5;

\(\rm \frac{x_i}{x_0} =2.5 \\\ x_i=2.5 x_0\)

Where,

\(\rm x_0\) is the true of an image produced by this mirror.

The true of an image produced by this mirror will be 2.5 times smaller and virtual.

Hence,option C is correct.

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The main reason a person weighs less at the equator than at the poles is due to the Earth's rotation, which causes a centrifugal force at the equator due to law of planet motion.

This centrifugal force is caused by the Earth's rotation around its axis, which is faster at the equator than at the poles. As a result, objects at the equator are moving faster and experience a weaker gravitational pull towards the Earth's center compared to objects at the poles due to law of planet motion.

The difference in gravitational force between the equator and the poles is relatively small, around 0.5%, but it is still measurable. The gravitational force at the poles is stronger because the Earth's rotation is slower there, so there is less centrifugal force pushing objects away from the Earth's center.

The influence of the Sun, Moon, and planets on a person's weight is much smaller than the effect of the Earth's rotation. These celestial bodies do have an effect on the Earth's gravitational field, but their impact is relatively minor compared to the Earth's rotation.

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Answer:

w=f×s

w = 16000 J, hope this helps