A) The prediction equation for a Poisson loglinear model is: ln(y) = β₀ + β₁x ; B) The estimated mean number of satellites for female crabs of average weight 2.44 kg.
A. To fit a Poisson loglinear model with x = weight and y = number of satellites, we first need to calculate the logarithm of the mean of y for each value of x. This is the log-linear relationship between x and y.
The prediction equation for a Poisson loglinear model is:
ln(y) = β₀ + β₁x
where ln(y) is the natural logarithm of the mean of y, β₀ is the intercept, and β₁ is the slope of the line.
To estimate the parameters of the model, we can use maximum likelihood estimation. This involves finding the values of β₀ and β₁ that maximize the likelihood function, which is the probability of observing the data given the model.
Once we have estimated the parameters, we can use the prediction equation to predict the mean number of satellites for a given weight of crab.
B. To estimate the mean of y for female crabs of average weight 2.44 kg, we can simply plug this value into the prediction equation:
ln(y) = β₀ + β₁x
ln(y) = β₀ + β₁(2.44)
We can then exponentiate both sides to get the predicted mean number of satellites:
y = exp(β₀ + β₁(2.44))
This gives us the estimated mean number of satellites for female crabs of average weight 2.44 kg.
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A downhill skier reaches the steepest part of a trail. Her speed increases from 9 m/s to 18 m/s in 3 seconds. What is her average acceleration
Answer:
3m/s²
Explanation:
final velocity - initial velocity
______________________ = Acceleration
elapsed time
A downhill skier reaches the steepest part of a trail. Her speed increases from 9 m/s to 18 m/s in 3 seconds. Her average acceleration is 3 m/sec².
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
Average acceleration = (18 -9)/3 = 3 m/sec²
A downhill skier reaches the steepest part of a trail. Her speed increases from 9 m/s to 18 m/s in 3 seconds. Her average acceleration is 3 m/sec².
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which answer is it??
Answer:
hmm...
Explanation:
Answer: wave a has the higher ampllitude while wave b has the lower amplitude.
Explanation:
wave a has the amplitude of 4 while wave b has the amplitude of one
what must be the pressure difference between the two ends of a 1.6km section of pipe, 29 cm in diameter, if it is to transport oil (p= 950 kg/m3 ,n = 0.20 Pa. s) at a rate of 650 cm3/s?
Answer:
The pressure difference required between the two ends of the 1.6 km pipe section, with a diameter of 29 cm, to transport the oil at a rate of 650 cm^3/s, is approximately 0.398 Pa.
Explanation:
To calculate the pressure difference between the two ends of a pipe, we can use the Poiseuille's Law equation, which relates flow rate, viscosity, pipe length, diameter, and pressure difference.
The formula is as follows: ΔP = (8 * n * L * Q) / (π * r^4)
Where:
ΔP is the pressure difference,
n is the viscosity of the fluid,
L is the length of the pipe section,
Q is the flow rate,
and r is the radius of the pipe (half of the diameter).
Given:
L = 1.6 km = 1600 m (convert to meters)
Diameter = 29 cm
Radius (r) = 29 cm / 2 = 14.5 cm = 0.145 m (convert to meters)
Q = 650 cm^3/s = 650 * 10^-6 m^3/s (convert to cubic meters per second)
n = 0.20 Pa.s (viscosity)
p = 950 kg/m^3 (density)
ΔP = (8 * 0.20 * 1600 * 650 * 10^-6) / (π * (0.145)^4)
ΔP ≈ 0.398 Pa
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10 cm^3 of iron have a smaller
mass then 115 cm^3 of wood.
(density of iron 7.9 g/cm^3)
(density of wood 0.7 g/cm^3)
true or false
Explanation:
Mass of iron = (7.9)(10) = 79g
Mass of wood = (115)(0.7) = 80.5g
Therefore iron has a smaller mass than the wood, which is true.
What is conceptual definition of terms in research?
Research is the systematic and objective analysis and recording of controlled data used for the purpose of discovering, interpreting, or revising facts, theories, applications, or laws. It is used to gain knowledge and increase understanding of a subject or phenomenon.
Conceptual definition of terms in research is the process of defining concepts and terms used in a research study. This process involves developing a clear understanding of the concepts and terms used in the study so that the research is consistent and meaningful. Conceptual definitions can be used to ensure that all participants in a research study understand the same concepts and terms and are using the same language. They can also help to ensure that the research is accurate and valid.
It is a way of understanding the meaning of the research topic, and provides a framework for the researcher to use when interpreting the data from the research. Conceptual definitions help to ensure that the researcher is using the same language and understanding when discussing the research topic, and allows for a more accurate interpretation of the results.
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(figure 1) shows two blocks sliding on a frictionless surface. eventually the smaller block overtakes the larger one, collides with it, and sticks. suppose that m
The final speed after the collision of the blocks is 5u/4. The final speed is given in terms of initial velocity.
Given:
Mass of the first block, m
Mass of the second block, 3 m
The initial velocity of the first block, 2u
The initial velocity of the second block, u
The momentum can be determined from the product of mass and velocity.
From the conservation of momentum:
initial momentum = final momentum
2mu + 3mu = (3 m+m) v
The final speed is:
5mu = 4mv
v = 5u/4
Hence, the final speed after the collision of the blocks is 5u/4. The final speed is given in terms of the initial speed.
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#Complete question is:
shows two blocks sliding on a frictionless surface. eventually, the smaller block overtakes the larger one, collides with it, and sticks. suppose that m
What is the speed of the two blocks after the collision?
Which of the following would not be considered as projectile?a. A cannonball rolling down a slope.b. A cannonball thrown through the air.c. A cannonball rolling off the edge of a table.d. All of the above.
A cannonball rolling off the edge of a table would not be considered as a projectile. Hence the correct option is C.
A projectile is an object that is launched into the air and moves under the influence of gravity.
It typically follows a parabolic trajectory.
In options a and b, the cannonball is either rolling down a slope or thrown through the air, both of which involve the cannonball being launched and moving under the influence of gravity.
However, in option c, the cannonball is simply rolling off the edge of a table, which does not involve any launch or initial velocity. It is just rolling due to the force of gravity acting upon it. Therefore, option c would not be considered as a projectile.
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Kundan who weighs 200N and bijaya who weighs 500N are playing sea saw.If Bijaya is 1m away from the fulcrum,how far should kundan sit to lift bijaya
Answer:
Kundan should sit at more that 2.5 meters from the location of the fulcrum on the side opposite to the side where Bijaya sits
Explanation:
The given parameters are;
The weight of Kundan, F₁ = 200 N
The weight of Bijaya, F₂ = 500 N
The distance of Bijaya from the fulcrum, d₂ = 1 m
Therefore, for Kundan to lift Bijaya, Kundan should sit at a location further than the point where both the moment of Bijaya and Kundan about the fulcrum are equal
Moment of a force, M = The magnitude of the force, F × The perpendicular distance to the point at which the force acts, d
At equilibrium, the sum of the clockwise moment = The sum of the anticlockwise moment
Taking the moment of Kundan as being in the anticlockwise direction and the moment of Bijaya as acting in the clockwise direction, we have;
F₁ × d₁ = F₂ × d₂
∴ 200 N × d₁ = 500 N × 1 m
d₁ = 500 N·m/(200 N) = 2.5 m
Therefore, when Kundan sits at the point d₁ = 2.5 m, away from the fulcrum on one side of the sea saw and Bijaya sits at the point 1 m from the fulcrum on the other side of the sea saw, both Kundan and Bijaya will have the same moment
For Kundan to lift Bijaya, therefore, Kundan as to sit at a point further than 2.5 m from the fulcrum on the opposite side of the fulcrum from Bijaya.
If the force exerted by the intern is doubled and the distance is haived, does the work done by the intern increase, decrease, or remain the same.I want the answer asap
Answer:
The work remains the same
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if 12V battery maintains a 4.5A current through a resistor what is the resistance of the resistor?
Answer:
2.7ohms
Explanation:
Given parameters:
Voltage of the battery = 12V
Current = 4.5A
Unknown:
Resistance of the resistor = ?
Solution:
From Ohm's law, we know that;
V = IR
V is the voltage
I is the current
R is the resistance
So;
R = \(\frac{V}{I}\) = \(\frac{12}{4.5}\) = 2.7ohms
Calculate the probability of an antiproton, of energy E, crossing a potential energy barrier Vo(x), where E < Vo(x). The probability of an electron of the same energy E passing through the above potential energy barrier is equal to 0.2.
The probability of an antiproton, of energy E, crossing a potential energy barrier Vo(x), where E < Vo(x). The probability of an electron of the same energy E passing through the above potential energy barrier is equal to 0.2.\(exp\ [-\sqrt{[\frac{h\ ln (0.2)^2}{32 m (Vo(x)-E)}} ]]\)
The probability of an antiproton crossing an electric potential energy barrier (Vo(x)), where E < Vo(x) is given by:
\(P(E) = exp(-2\sqrt{[2m\frac{(Vo(x)-E)}{h}]})\)
Where, h is the Planck constant and m is the mass of the particle. To calculate the probability of an electron passing through the same energy barrier, we are given that P(E) = 0.2. The probability of an antiproton crossing the same energy barrier is:
\(P(E) = exp(-2\sqrt{[2m\frac{(Vo(x)-E)}{h}]})\)
The energy of the antiproton is given as E. Therefore, substituting this value in the above expression, we have:
\(P(E) = exp(-2\sqrt{[2m\frac{(Vo(x)-E)}{h}]})\)
As per the given condition, the probability of an electron passing through the same energy barrier is 0.2. Therefore, substituting this value in the above expression, we have:
\(P(E) = exp(-2\sqrt{[2m\frac{(Vo(x)-E)}{h}]})\)
Taking the natural logarithm on both sides, we have:
\(ln0.2 = -2\sqrt{[2m\frac{(Vo(x)-E)}{h}]}\)
Taking the square of both sides, we have:
\(4\ ln 0.2 = 8 [2m\frac{(Vo(x)-E)}{h}]\)
Simplifying, we get:
\(Vo(x) - E = (\frac{h}{8m}) \frac{[ln 0.2]^2}{2}\)
\(Vo(x) = E + (\frac{h}{8m}) \frac{[ln 0.2]^2}{2}\)
Therefore, the probability of an antiproton crossing the electric potential energy barrier \((Vo(x))\), where is given by:
\(P(E) = exp(-2\sqrt{[2m\frac{(Vo(x)-E)}{h}]})\)
Substituting the value of Vo(x), we get:
\(P(E) = exp(-2\sqrt{[2m\frac{(h)}{8m}\frac{[ln 0.2]^2}{2h}{(Vo(x)-E)}]})\)
Simplifying, we get:
\(P(E) = exp[-\sqrt{[\frac{(h ln 0.2)^2}{32m}(Vo(x)-E)]}]\)
Therefore, the required probability is \(exp[-\sqrt{[\frac{(h ln 0.2)^2}{32m}(Vo(x)-E)]}]\).
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In one word, what is it that moves from source to receiver in wave motion?
The thing that moves from source to receiver in wave motion is energy.
How do waves transfer energy?In wave motion, energy is transferred from a source to a receiver. Waves can be defined as disturbances that propagate through space and time, carrying energy with them. Depending on the type of wave, the energy can be carried by different physical quantities, such as the displacement of particles in a medium, the electric and magnetic fields in an electromagnetic wave, or the pressure variations in a sound wave. Waves can be classified according to their properties, such as wavelength, frequency, amplitude, and speed. They can also be reflected, refracted, diffracted, or absorbed when they encounter different media or obstacles, which leads to various phenomena such as interference, resonance, and polarization.
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A car travelling 10m/s increases its speed to 20m/s over a time of 4s. What is the acceleration of the car? A car is traveling at a speed of 15m/s. It experiences an acceleration of -3m/s^2, that lasts for 4 seconds. What is the final velocity of the car? I need an expanation on HOW to solve this.
Answer:
Explanation:
Acceleration is the change in velocity with respect to time.
Acceleration = change in velocity/Time
Acceleration = final velocity - initial velocity/Time
Given initial velocity = 10m/s
Final velocity = 20m/s
Time taken = 4s
Acceleration = 20-10/4
Acceleration = 10/4
Acceleration =2.5m/s²
For the second part of the question:
Given parameters
initial velocity = 15m/s
acceleration = -3m/s²
time = 4seconds
a = v-u/t
-3 = v-15/4
cross multiply
-12 = v-15
add 15 from both sides
-12+15 = v-15+15
3 = v
Hence the final velocity of the car is 3m/s
a thin film of thickness 280 nm and index of refraction 1.4 coats a plate of glass having index of refraction 1.65. if light is perpendicularly incident on the glass, at what wavelength is the reflected light minimal?
If a thin layer with an index of refraction of 1.4 and a thickness of 280 nm coats a glass plate with an index of refraction of 1.65, the minimum wavelength of the reflected light is 182 nm.
What is the wavelength, exactly?When a waveform signal travels across space or down a wire, its wavelength is the distance between two identical locations (adjacent crests) in adjacent cycles. The standard units of measurement for this length in wireless systems are meters (m), centimeters (cm), or millimeters (mm) (mm).
Light is coming from a medium with a lower refractive index (n 1 = 1.50) into a medium with a higher index (n 2 = 1.60), so the net path difference in the reflected rays from the two interfaces will be equal to 2t (where t is the thickness of the thin film), because when that happens, light will enter the higher index medium.
When light travels from air to a thin film, the reflected ray's path shift equals 2; when it travels from a thin film to glass, the reflected ray's path shift equals 2′ /2+2t for constructive interference; 2t=m or 2t=m/n 1 where is the wavelength in the thin film, =546nm (given) wavelength in vacuum, and m=0 (minimum); thus, t
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how many moons are in our galaxy if u count all the other planets moons?
teacher holds a book in her hand. She slowly tilts her hand forward but the book does not slide off her hand. Why?
The reason why the book does not slide off the teacher's hand when she tilts her hand forward is because of the force of friction between the surfaces of the book and the teacher's hand.
How does force of friction prevent the motion of the book?
Friction is a force that resists the motion between two surfaces that are in contact. When the book is resting on the teacher's hand, the surfaces of the book and the hand are in contact with each other. When the teacher tilts her hand forward, the force of gravity tries to pull the book downward, but the force of friction between the book and the hand acts in the opposite direction, preventing the book from sliding off the hand.
The amount of friction between two surfaces depends on a few factors, such as the type of materials in contact, the roughness of the surfaces, and the force pressing the surfaces together. The force of friction increases as the force pressing the surfaces together increases. In this case, the weight of the book pressing down on the teacher's hand increases as the hand tilts forward, which increases the force of friction between the book and the hand, keeping the book in place.
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5. A new technique called adaptive optics allows astronomers to: a. change the eyepieces of their telescopes much more quickly than ever before b. compensate for changes in the Earth's atmosphere and achieve better resolution c. increase the aperture of their telescopes by connecting several telescopes d. change the region of the electro-magnetic spectrum in which their telescope is able to detect radiation e. use the observatory shop to make better eye-glasses for their graduate students
Answer:
b. compensate for changes in the Earth's atmosphere and achieve better resolution.
Explanation:
The adaptive optic is a technology that is used to enhance the application of optical system in reducing the impact from the incoming distractions. It is dine to reduce the optical abbrebrivation. It is also used for correcting the tip-tilt correction by using the segmented mirrors.Which of the following expressions is correct for the transmitted intensity of an unpolarized beam of light with an intensity I_i passing through a polarizer? A) I_t = I_i B) I_t = 2 I_i C) i_t = 4 I_i E) I_t = (1/4) I_i A cordless phone operates at 900 MHz. What is the associated wavelength of this cell phone signal? A) 30 m B) 3.0 m C) 0.33 m D) 3.0 mm E) 0.33 mm The distance between the two planets is 1.6 times 10^6 m. How much time would the light signal lake to go from one planet to the other? A) 0.53 times 10^-2 s B)1.9 times 10^2 s C) 1.9 times 10^-2 s D) 1.3 times 10^2 s E) 0.45 times 10^-2 s
A) I_t = I_i, C) 0.33 m, A) 0.53 times 10^-2 s
Which expression is correct for the transmitted intensity of an unpolarized beam of light passing through a polarizer? What is the wavelength associated with a cordless phone operating at 900 MHz? How much time does a light signal take to go from one planet to another that are 1.6 times 10^6 m apart?For the first question:
The correct expression for the transmitted intensity of an unpolarized beam of light passing through a polarizer is:
A) I_t = I_i
When an unpolarized light beam passes through a polarizer, the transmitted intensity is equal to the incident intensity. This means that the intensity of the light remains unchanged after passing through the polarizer.
For the second question:
The associated wavelength of a cell phone signal operating at 900 MHz can be calculated using the formula: wavelength = speed of light / frequency.
The speed of light is approximately 3.0 x 10^8 m/s.
Calculating the wavelength:
wavelength = (3.0 x 10^8 m/s) / (900 x 10^6 Hz)
wavelength = 3.33 x 10^-1 m
Therefore, the correct answer is:
C) 0.33 m
The wavelength of the cell phone signal is 0.33 meters.
For the third question:
To calculate the time it takes for a light signal to travel from one planet to another, we need to divide the distance between the two planets by the speed of light.
Calculating the time:
time = distance / speed of light
time = (1.6 x 10^6 m) / (3.0 x 10^8 m/s)
time = 5.33 x 10^-3 s
Therefore, the correct answer is:
A) 0.53 times 10^-2 s
The time for the light signal to travel from one planet to the other is 0.53 times 10^-2 seconds.
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I WILL GIVE BRAINLIEST!!! PLEASE, URGENT HELP! PLEASE PLEASE PLEASE!!!
A gas has an initial volume of 0.9 L, an initial pressure of 32 atm and a temperature of 24.80 K. The temperature is decreased to 10.01 K. At this new temperature the volume is 744 mL. What is the new pressure?
Answer:
The new pressure will be 12 atm
Two sunbathers were sitting on a raft. One noted that the raft bobbed up and down at a frequency of 0.20 Hz. The other observed that a crest took 5.0 s to cover the 15.0 m to shore. How far apart are the crests of the wave?
Answer:
15 m
Explanation:
We'll begin by calculating the speed of the wave. This can be obtained as follow:
Time = 5 s
Distance = 15 m
Speed =?
Speed = distance / time
Speed = 15 / 5
Speed = 3 m/s
Finally, we shall determine the distance between the crests of the wave. This can be obtained as follow:
Speed (v) = 3 m/s
Frequency (f) = 0.2 Hz
Distance between the crest (λ) =?
v = λf
3 = λ × 0.2
Divide both side by 0.2
λ = 3 / 0.2
λ = 15 m
Therefore, the distance between the crests of the wave is 15 m
When considering the wavelength of a radio wave – like the kind you hear when listening to music as you drive along – you would be correct to think that the size is this wave is about as long as:.
The size of the wavelength of a radio wave is in the order of millions of meters.
What is a radio wave?Radio wave is part of the electromagnetic spectrum. The radio wave is known to travel across a long distance because it has a long wavelength. This means that it has a low energy.
Hence, the size of the wavelength of a radio wave is in the order of millions of meters.
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Answer: Building
Explanation: took a quiz :)
Suppose line L goes lhrough the point (1,2) and has a slope of -3. Find parametric equations for the line that goes through the same point; but is perpendicular to L, xlt) - [+1,Mt) = .3t+2 x(u) - t+1, Ylt) - (1/3)t+2 xlt) = -(1/3)t+1,YU - (+2 x(t) = -(1/3)t-1.Ylt) = t-2 x(t) = t-1,Ylt) = (1/3)t -2
The equation of the line that is perpendicular to L and passes through the point (1,2) is y = (1/3)x + 5/3.
The equation of the perpendicular line can be written as y = (1/3)x + b, where b is the y-intercept.
we can use the fact that the line passes through the point (1,2). Substituting these values into the equation, we get:
2 = (1/3)(1) + b
b = 5/3
The term "y-intercept" typically refers to the point at which a graph or plot of two variables intersects the y-axis, which represents the vertical axis. The y-intercept is the value of the dependent variable (usually denoted as "y") when the independent variable (usually denoted as "x") is equal to zero.
For example, consider the graph of a straight line with the equation y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept b represents the value of y when x is equal to zero. In physics, this can be used to interpret the physical meaning of the equation. For instance, in the context of a position-time graph, the y-intercept represents the initial position of an object, since it is the position when time is equal to zero.
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If the device is kept reverse biased, we know that the voltage across the device will remain roughly constant at the zener voltage. If d5 is carrying a minimum current of 5ma (down) and d6 is carrying a current of 5ma (down), what is the minimum current through r1?
The minimum current through R1 will be 10mA.
Using Ohm's Law (V = IR), we can find the minimum current through R1 as follows:
Vr1 = Vz5 + Vz6
where Vr1 is the voltage across resistor R1.
Therefore, the minimum current through R1 is:
Ir1 = Vr1 / R1
Assuming that R1 is a standard value resistor (e.g., 1kΩ), and the Zener voltages are each 5V, the voltage across R1 will be:
Vr1 = Vz5 + Vz6 = 5V + 5V = 10V
Therefore, the minimum current through R1 will be:
Ir1 = Vr1 / R1 = 10V / 1kΩ = 10mA
Current is the flow of electric charge through a conductor or material. It is defined as the rate of flow of electric charge, measured in units of amperes (A). One ampere is equivalent to the flow of one coulomb of electric charge per second.
Electric current is caused by the movement of charged particles, typically electrons, in a circuit. When a voltage is applied to a conductor, it creates an electric field that causes electrons to move through the conductor. This flow of electrons constitutes an electric current.
The direction of electric current is defined as the direction of flow of positive charges, even though the actual charges that move are electrons, which are negatively charged. Electric current can be direct current (DC), where the flow of charge is in one direction, or alternating current (AC), where the direction of flow periodically changes.
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Describe the differences between metals, nonmetals, and metalloids
Answer:
A metal is an element which is typically hard, shiny, fusible, malleable, and ductile, with good electrical and thermal conductivity. A nonmetal is an element that does not have the properties of a metal. A metalloid is an element having intermediate properties of both metals and nonmetals.
Create 5 Examples about Problem Solving about Speed
(MUST APPLY GRESA METHOD)
Given
Required
Equation
Solution
Answer
Answer:
Explanation:
Sure, here are five examples of problem-solving using the GRESA method for speed:
Example 1:
Given: A car travels 240 km in 4 hours.
Required: What is the average speed of the car?
Equation: Speed = Distance / Time
Solution: Speed = 240 km / 4 hours = 60 km/hour
Answer: The average speed of the car is 60 km/hour.
Example 2:
Given: A train travels at a speed of 100 km/hour for 2 hours, and then at a speed of 80 km/hour for the next 3 hours.
Required: What is the total distance traveled by the train?
Equation: Distance = Speed x Time
Solution: Distance = (100 km/hour x 2 hours) + (80 km/hour x 3 hours) = 200 km + 240 km = 440 km
Answer: The total distance traveled by the train is 440 km.
Example 3:
Given: A cyclist travels at a speed of 30 km/hour for 2 hours, and then at a speed of 40 km/hour for the next 3 hours.
Required: What is the average speed of the cyclist for the entire journey?
Equation: Average speed = Total distance / Total time
Solution: Total distance = (30 km/hour x 2 hours) + (40 km/hour x 3 hours) = 60 km + 120 km = 180 km
Total time = 2 hours + 3 hours = 5 hours
Average speed = 180 km / 5 hours = 36 km/hour
Answer: The average speed of the cyclist for the entire journey is 36 km/hour.
Example 4:
Given: A boat travels upstream at a speed of 10 km/hour, and downstream at a speed of 20 km/hour. The speed of the current is 5 km/hour.
Required: What is the speed of the boat in still water?
Equation: Speed of boat in still water = (Speed downstream + Speed upstream) / 2
Solution: Speed downstream = 20 km/hour, Speed upstream = 10 km/hour
Speed of current = 5 km/hour
Speed of boat in still water = (20 km/hour + 10 km/hour) / 2 = 15 km/hour
Answer: The speed of the boat in still water is 15 km/hour.
Example 5:
Given: A car travels a distance of 90 km in 2 hours. If the speed of the car had been 10 km/hour more, it would have taken 1 hour less to cover the same distance.
Required: What is the original speed of the car?
Equation: Distance = Speed x Time
Solution: Let the original speed of the car be x km/hour
Distance traveled at original speed = 90 km
Time taken at original speed = 2 hours
Distance traveled at increased speed = 90 km
Time taken at increased speed = 2 - 1 = 1 hour
Using the equation Distance = Speed x Time, we get:
90 = x * 2
90 = (x + 10) * 1
Solving these equations simultaneously, we get:
x = 40 km/hour
Answer: The original speed of the car is 40 km/hour.
a container of water is open to the atmosphere. what is the gauge pressure profile of the water against a section of the container? arrow lengths against the wall indicates pressure magnitude.
The pressure as compared to atmospheric pressure is known as gauge pressure. Gauge pressure is positive for pressures higher than atmospheric pressure. Gauge pressure is negative for pressures below atmospheric pressure.
Pg denotes gauge pressure, which is related to absolute pressure as follows: Pa is the local atmospheric pressure, and pg is equal to p - pa. Example: 32.0 psi is the tire pressure as measured by an automobile tire gauge. 14.2 psi is the atmospheric pressure in the area.
Two objects that are in contact with one another are under pressure. The pressure distribution across the entire contact area is known as the pressure profile.
This type of reading is simply known as "gauge pressure" since the majority of gauges measure pressure relative to atmospheric pressure, which serves as the zero point. However, anything that is not a complete vacuum is considered to be under some type of pressure.
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A train travels at a speed of 24 m/s. Then it slows down uniformly at 0.065 m/s² until it stops. What distance does the train travel while slowing down?
A train travels at a speed of 24 m/s. Then it slows down uniformly at 0.065 m/s² until it stops the distance does the train travel while slowing down are 4430.75 m.
What is distance?Distance measures length. For example, the gap of a street is how lengthy the street is. In the metric gadget of size, the maximum not unusualplace devices of distance are millimeters, centimeters, meters, and kilometers.
It takes 24/.065 = 369.23 sec to slow down to zero.In that point it travels s = half of at^2 = half of (.065)(369.23^2) = 4430.75m.Read more about distance:
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where on earth can you stand and, over the entire year, see the entire sky?
Answer: Both the north and south pole
In a domestic electric circuit (220.V),an electric kettle of 3kW power rating is operatedthat has a current rating of 4A. What result do you expect? Explain.ii)In our homes there are two separate circuits one for high power rating appliances and other for low power rating appliances.Why?Givereasons.
Answer:
(i) It will take longer (75/22 times) the time to boil a given quantity of water compared to when the current is working at its rated capacity
(ii) The reasons are;
(1) For economy; most of the appliances in the home only require low power circuitry with thinner wire while a separate high power circuitry is created directly from the main supply for the high electric power rated appliances
(2) For safety; to prevent the over heating of the electric circuits when an high electric power appliance needs to be connected an high power electric power outlet has to be specified
Explanation:
(i) The power rating of the kettle = 3 kW
The voltage rating of the circuit, V = 220 V
The current rating, I = 4 A
The formula for electric power = I² × R = I × V
Therefore, we have;
Power produced = 220 V × 4 A = 880 V·A = 800 W
Hence, since the power produced is below the power rating of the electric kettle, it will take a longer time to boil a given amount of water than specified by the kettle manufacturer
The energy supplied H = V×I×t
Where:
t = Time in seconds
Therefore, we have;
3 kW = 3000 W;
3000 × t₁ = 880 × t₂
t₂/t₁ =3000/880 = 75/22
Hence the kettle will take 75/22 multiplied by the time it takes when working at rating capacity to boil a given quantity of water
(ii) This is so because the power consumption already factored in the electrical installation as well as the type of appliances utilized in the home allow for several low power rating consumption and few high power rating consumption
Therefore, for both economy and safety the electrical circuit are split to allow for the use of very thick copper or aluminium electric cables in the high power rating electric circuits to which can be plugged high electric power consuming devices such as the water heater and electric cooker
The low electric power consuming devices, such as the electric bulb and fans are connected to the low or "regular" power rating electric circuit outlets
The current required for high power and low power appliances is different and also the fuse rating required for both the appliances different, so two separate circuits are used for high power and low power appliances.
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Perform the following conversion.
0.09 km to dam
Answer:9
Explanation: