A water-skier is being pulled by a tow rope attached to a boat. As the driver pushes the throttle forward, the skier accelerates. A 79.4-kg water-skier has an initial speed of 6.2 m/s. Later, the speed increases to 12.3 m/s. Determine the work done by the net external force acting on the skier.

Answer:

The plague and the london fires.

Explanation:

Lots of war happened after that. They had an outbreak as we known called the Plague. After the Comet, lots of fires were set in London.

Answer:

η₁ = 2.6

Explanation:

Here, we will use snell's law to calculate the refractive of the substance:

\(\frac{\eta_2}{\eta_1} = \frac{Sin\theta_1}{Sin\theta_2}\)

where,

η₁ = refractive index of first substance = ?

η₂ = refractive index of second substance = 1.5

θ₁ = angle of incidence = 30°

θ₂ = angle of refraction = 60°

Therefore,

\(\frac{1.5}{\eta_1} = \frac{Sin\ 30^0}{Sin\ 60^0}\)

η₁ = 2.6

Answer:

\(0.741\ \text{m/s}^2\)

Explanation:

v = Velocidad final = \(40\ \text{km/h}=\dfrac{40}{3.6}\ \text{m/s}\)

u = Velocidad inicial = 0

t = Tiempo empleado = 15 s

a = Aceleración

De las ecuaciones cinemáticas tenemos

\(v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{40}{3.6}-0}{15}\\\Rightarrow a=0.741\ \text{m/s}^2\)

La aceleración del camión en el primer intervalo de tiempo es \(0.741\ \text{m/s}^2\).

The acceleration of the rock thrown with the velocity of 15 m/s and taking 20 seconds to come back is 2.97 \(m/s^2\),  and the direction of acceleration is downward.

When an item is moving, its velocity indicates how quickly its location is changing as seen from a specific point of view and as measured by a specific unit of time. When time is constant, speed and distance are directly proportional, when the distance is constant,

Given:

The velocity of the rock, v = 15 m/s,

The time taken to go and return t = 20 seconds,

Now, calculate the distance traveled by the rock,

d = v/t

d = 15/10  (Time taken to go upward is half of the total time)

d = 1.5 meters

So, calculate the acceleration by the second equation of motion,

\(s = vt + 1/2at^2\)

Substitute the values,

\(1.5 = 15*10 + 1/2 * a * 10^2\)

\(a = -2.97 \ m/s^2\)

Therefore, the acceleration of the rock thrown with the velocity of 15 m/s and taking 20 seconds to come back is 2.97 \(m/s^2\) And the direction of acceleration is downward.

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The tension in the cord is equal to centripetal force which is 32 newton.

We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is

Fc = m . v²/R

where Fc is the centripetal force, m is mass, v is velocity and R is the radius.

From the question, we know that

m = 2 kg

v = 4 m/s

R = 1 m

The tension in the cord is equal to centripetal force

T = Fc

T = m . v²/R

T = 2 . 4² / 1

T = 32 N

Hence, the tension in the cord is 32 newton.

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The ratio of the volumes of gases B and D is b/a. If we are given that 1 liter of gas D is produced, the volume of gas B required would be b/a liters.

To determine the ratio of the volumes of gases B and D, we can use the principles of stoichiometry and the ideal gas law.

According to Avogadro's Law, equal volumes of gases at the same temperature and pressure contain an equal number of molecules. Therefore, the ratio of the volumes of gases B and D is the same as the ratio of the number of moles of gases B and D.

Let's assume that the balanced chemical equation for the reaction between gases B and D is:

aB(g) → bD(g)

In this case, we can write the following ratio:

Volume of B / Volume of D = Moles of B / Moles of D = b / a

Therefore, the ratio of the volumes of gases B and D is b/a.

If we are given that 1 liter of gas D is produced, the volume of gas B required would be b/a liters.

Please note that the specific values of a and b will depend on the balanced chemical equation for the reaction between gases B and D.

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An object with a mass of 15 kilograms on Earth weighs approximately 147.15 Newtons (N).

 Mass is the amount of matter that an object contains, whereas weight is the force of gravity on that object. The formula for calculating weight is:F = m × gwhere:F is weightm is massg is the acceleration due to gravityOn Earth, the acceleration due to gravity is approximately 9.81 meters per second squared (m/s²). Therefore, the weight of an object with a mass of 15 kg on Earth would be:F = 15 kg × 9.81 m/s²F = 147.15 NThus, an object with a mass of 15 kilograms on Earth weighs approximately 147.15 Newtons (N).

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Answer:

Crude oils

Explanation:

The correct word should be crude oils.

Crude oil is a non-renewable resource that is geologically formed and found deep in the ground. It is a naturally occurring mixture of hydrocarbons and usually fractionated to serve different purposes for the use of man. Crude oils are non-renewable because the rate at which humans exploit them is quite faster than the rate at which they are being naturally replenished deep in the ground.

The charges of the delta baryons with the given quark structures are:

A with structure uuu: +4/3

A with structure uud: +1

A with structure udd: 0

A with structure ddd: -1

Based on the quark structure of each delta baryon, we can determine their charges as follows:

Delta baryon with structure uuu: This baryon has three up quarks, each with a charge of +2/3. Therefore, the total charge of this delta baryon is +2/3 + 2/3 + 2/3 = +4/3.

Delta baryon with structure uud: This baryon has two up quarks and one down quark. Each up quark has a charge of +2/3, and the down quark has a charge of -1/3. Therefore, the total charge of this delta baryon is +2/3 + 2/3 - 1/3 = +1.

Delta baryon with structure udd: This baryon has one up quark and two down quarks. The up quark has a charge of +2/3, and each down quark has a charge of -1/3. Therefore, the total charge of this delta baryon is +2/3 - 1/3 - 1/3 = 0.

Delta baryon with structure ddd: This baryon has three down quarks, each with a charge of -1/3. Therefore, the total charge of this delta baryon is -1/3 - 1/3 - 1/3 = -1.

So, the charges of the delta baryons with the given quark structures are:

A with structure uuu: +4/3

A with structure uud: +1

A with structure udd: 0

A with structure ddd: -1

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Answer:

parallel combination of cell

The density of mercury is approximately 13.6 g/mL.

To calculate the density of mercury in grams per milliliter, we'll first need to convert the given weight from pounds to grams and the volume from quarts to milliliters.

1 pound = 453.592 grams
1 quart = 946.353 milliliters

First, convert 28.4 pounds to grams:
28.4 pounds * 453.592 g/pound ≈ 12882.5 grams

Next, convert 1 quart to milliliters:
1 quart * 946.353 mL/quart ≈ 946.353 milliliters

Now, calculate the density using the formula density = mass/volume:
Density = 12882.5 grams / 946.353 milliliters ≈ 13.6 g/mL

Therefore, the density of mercury is approximately 13.6 g/mL.

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The wavelength of the given radar signal in free space is 1.3783 cm.

The relation between wavelength \(\lambda\) and frequency \(\nu\) of a wave is given as:

\(\boxed{\lambda = \frac{c}{\nu}} \qquad (1)\)

\(c\) → Speed of light

Now as per the question:

\(\nu=21.75 \cdot 10^9 Hz\\c=2.9979\cdot10^8\)

Putting the values in equation (1) we get:

\(\lambda=\frac{2.9979\cdot 10^8}{2.75\cdot10^9} \;m\\\\\Rightarrow \boxed{\lambda=0.013783\;m\;or\;\lambda=1.3783\;cm}\)

So the wavelength of the given radar signal in free space is 1.3783 cm

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To find the wavelength of the radar signal in free space, we can use the formula:

wavelength = speed of light/frequency

Substituting the given values, we get:

wavelength = 2.9979 x 10^8 m/s / 21.75 x 10^9 Hz
wavelength = 0.0138 meters

Rounding off to four significant figures, the wavelength of the radar signal is 0.0138 meters or 13.8 millimeters. The appropriate units for wavelength are meters or millimeters.
To calculate the wavelength of a radar signal, use the formula:

Wavelength (λ) = Speed of light (c) / Frequency (f)

Given the frequency (f) of the radar signal is 21.75 × 10^9 Hz and the speed of light (c) is 2.9979 × 10^8 m/s:

Wavelength (λ) = (2.9979 × 10^8 m/s) / (21.75 × 10^9 Hz)

λ ≈ 1.378 × 10^-2 m

Expressed to four significant figures, the wavelength of the radar signal in free space is 1.378 × 10^-2 meters.

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Answer:

The baseball was falling during 1.733 seconds.

Explanation:

The baseball experimented a free fall, which is a particular case of uniformly accelerated motion, in which object is accelerated by gravity. In this case, we need to determine the time spent by the ball before hitting the ground (\(t\)), measured in seconds, which is determined by the following kinematic formula:

\(t = \frac{v-v_{o}}{g}\) (1)

Where:

\(v_{o}\), \(v\) - Initial and final speeds of the baseball, measured in meters per second.

\(g\) - Gravitational acceleration, measured in meters per square second.

If we know that \(v_{o} = 0\,\frac{m}{s}\), \(v = 17\,\frac{m}{s}\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the time spent by the baseball is:

\(t = \frac{17\,\frac{m}{s}-0\,\frac{m}{s} }{9.807\,\frac{m}{s^{2}} }\)

\(t = 1.733\,s\)

The baseball was falling during 1.733 seconds.

The zinc anode is oxidized while the copper cathode is reduced.

An electrochemical cell is a cell that produces energy by chemical reactions. It contains an anode and a cathode.

1) Once the two half cells are connected, the bulb lights up.

2) At the anode, the zinc atoms are converted to zinc ions thereby releasing electrons.

3) At the copper cathode, electrons are accepted as follows;

Cu^2+(aq) + 2e -----> Cu(s)

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To calculate the resultant force acting on the car, we must first find the acceleration at which the car is moving.

We can do this using the acceleration formula,\(a = (v_f - v_i) / t\), where \(v_f\) is the final velocity, \(v_i\) is the initial velocity, and t is time. \(a = (100 km/h - 60 km/h) / 20 s = 2 m/s*2\). Then we can use Newton's second law, \(F = m * a\), where F is the resultant force, m is the mass of the car, and a is the acceleration calculated above. \(F = 2200 kg * 2 m/s*2 = 4400 N\). To calculate the space traveled in that time, we can use the distance formula,\(d = v_i * t + 0.5 * a * t*2. d = 60 km/h * (20 s) + 0.5 * 2 m/s8*2 * (20 s)*2 = 500 m\). In short, the resultant force acting on the car is 4400 N and the distance covered in 20 seconds is 500 meters.

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Answer:

the correct answer is False

Explanation:

i hope its right

Required answer :-

Given :-

We know that,

↠ W = P × t

↠ W = V × I × t

↠ W = V × Q/t × t

↠ W = V × Q

On substituting values, we get

↠ 40 = 20 × Q

↠ Q = 40/20

↠ Q = 2 c

↠ ne = q

↠ n = q/e

↠ n = 2/ 1.6 × 10^- 19

↠ n = 1.25 × 10^19

Hence,

Answer:

the third one

Explanation:

she is using a card instead of paper

Answer:

velocity= 135m/s

Explanation:

velocity = 300×0.45

= 135m/s²

Explanation:

Hey there!!

Hope it helps...

The maximum potential energy stored in the spring is 0.018 J. It is given that the force F (in N) and the displacement x (in m) of the springs and we are asked to use Hooke’s law to compute the potential energy stored in the spring U (in J) and then compute the vectors of the spring constants and the potential energies using MATLAB.

Computing the spring constant k from the given data: We know that F = kx ⇒ k = F/x. Here, F and x are vectors: F = [14, 18, 8, 9, 13] N and x = [0.013, 0.020, 0.009, 0.010, 0.012] m. We can compute k as follows: k = F./x = [14/0.013, 18/0.020, 8/0.009, 9/0.010, 13/0.012] kN/mk = [1076.92, 900, 888.89, 900, 1083.33] N/m (rounded off to 2 decimal places)2.

Computing the potential energy stored in the spring U from the given data: We know that U = (1/2)kx². We can compute U as follows: U = (1/2)k.*x² = [(1/2)1076.92(0.013)², (1/2)900(0.020)², (1/2)888.89(0.009)², (1/2)900(0.010)², (1/2)1083.33(0.012)²] JU = [0.009, 0.018, 0.004, 0.005, 0.007] J (rounded off to 3 decimal places).

Determining the maximum potential energy using the max function: We can determine the maximum potential energy using the max function as follows: maxU = max(U) = 0.018 J. Therefore, the maximum potential energy stored in the spring is 0.018 J.

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Answer:

320 m/s

Explanation:

40 miles per second and 8 seconds makes 40 times 8

Answer:Because of their strong winds, jet streams play an important role in the economy of the aviation industry. When an airplane flies into a jet stream for any period of time, extra fuel must be used. Not only is the fuel expensive, but it takes up room where either passengers or cargo could be. Just the opposite occurs when an airplane flies with a jet stream at its back. Fuel and money are saved because the wind pushes the plane along.

Explanation:

The airplane pilots check to find the location of the jet stream before every flight because of the strong winds to save the fuel.

It is a very strong current of air thousands of miles long, hundreds of miles wide and miles deep with a large amount of force-carrying with itself.

When an airplane is flying through a jet stream, it requires more fuel must be used. Being the fuel expensive these days, avoid the extra power required to run the airplane.

When an airplane flies with a jet stream at its back, both the fuel and money are saved.

Thus, airplane pilots check to find the location of the jet stream before every flight because of the strong wind.

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Answer:

A continuous and closed path of an electric current is called an electric circuit. An electric circuit consists of electric devices, a source of electricity and wires that are connected with the help of a switch.

Explanation:

All switches do the same thing: Connect wires to allow electric current to flow or disconnect wires to stop electric current from flowing. ... With the switch in the closed position, you've connected the wire (and completed the circuit), and current can flow.

Answer:

Use Measuring Cups?

Explanation:

Answer:

Generally, a solute dissolves faster in a warmer solvent than it does in a cooler solvent because particles have more energy of movement. For example, if you add the same amount of sugar to a cup of hot tea and a cup of iced tea, the sugar will dissolve faster in the hot tea.

The bird with a mass of 26 g perches in the middle of a stretched telephone line. The tension in the wire is 0.12753 N.

To determine the tension when the bird is perching:

Tension is the force that stretches a string or a telephone line. The bird's weight will cause the wire to stretch by a certain amount. The weight of the bird can be calculated as follows:

Weight = mass × gravity

The weight of the bird is:

Weight = 26 g × 9.81 m/s2 = 255.06 g · m/s2 = 0.25506 N

This force will be evenly distributed across the wire, causing it to stretch evenly in all directions.

As a result, the tension in the telephone wire will be the weight of the bird divided by two. This is due to the fact that the weight of the bird is evenly distributed over the length of the wire. The tension formula is given as:

Tension = weight of the bird/2

Tension = 0.25506 N / 2 = 0.12753 N

Therefore, when the bird is perching in the middle of a stretched telephone line, the tension in the wire is 0.12753 N.

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the force between the two wires if they are separated by 2.50 cm is 0.525 N.

Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.

Let the initial force be F₁ and the initial distance be d₁.

Therefore, we can write the relationship between force and distance as;

F₁d₁ = F₂d₂

Where

;F₁ = 0.750 N (initial force)

d₁ = 1.75 cm (initial distance)

F₂ = ? (force at new distance)

d₂ = 2.50 cm (new distance)

Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂

Now substitute the values we know;

F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N

Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.

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Answer:

560J

Explanation:

Given parameters:

Mass of the man = 70kg

Velocity  = 4m/s

Unknown:

The amount of energy the man has = ?

Solution:

Energy is the ability to do work by a body. A body in motion is said to have kinetic energy and this can be derived using the expression below:

  K.E  = \(\frac{1}{2}\) m v²

m is the mass

v is the velocity

Insert the parameters and solve;

      K.E  =  \(\frac{1}{2}\) x 70 x 4²  = 560J

Answer:

all distant galaxies are moving away from the Milky Way galaxy and the whole universe is expanding

Explanation: