A water tank is filled with up to 3.5 m height.Calculate the pressure given by the tank at its bottom​

Answer:

Earth’s gravitational force is stronger

Explanation:

Earth’s gravitational force is stronger than the moon because of the presence of more massive objects in earth; on the flip side, the moon’s gravity is weaker than the earth due to smaller in size as compared to the earth. Earth gravity is denoted by g; conversely, moon gravity is denoted by gm

Answer: The greater an object's mass, the more gravitational force it exerts. So, to begin answering your question, Earth has a greater gravitational pull than the moon simply because the Earth is more massive. That's why the moon isn't pulled out of Earth's orbit by the gravity of larger planets or by the sun.

Explanation:

Answer:

the answer is

The last one D.) 17.5

Hope it helps ya(:

~Aiden~

Answer:

D.)

Hope it helps ya((::\\

~Aiden~

Answer:

planisphere

Explanation:

The sound wave took 1.2 seconds to travel from one whale to the other.

Velocity is a physical quantity that describes the rate of change of an object's position with respect to time and includes both the speed and direction of motion. It is a vector quantity, meaning it has both magnitude and direction and is typically measured in meters per second (m/s) or other appropriate units.

The time it took for the sound wave to travel from one whale to the other can be calculated using the formula:

time = distance/velocity

In this case, the distance between the whales is 1,800 meters and the velocity of sound in water is 1,500 meters per second. Therefore:

time = 1,800 meters / 1,500 meters per second

time = 1.2 seconds

Hence, The distance between the two whales was covered by the sound wave in 1.2 seconds.

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Answer:

11.023 lb

Explanation:

The angular velocity of the ISS is 0.012 rad/s. the height above the Earth's surface at which the ISS orbits is 408 km. the tangential speed of the ISS is 7 km/s.

a) Calculate the angular velocity of the ISS.

The angular velocity of the ISS can be calculated using the following formula:

ω = v / r

where:

ω is the angular velocity in radians per second

v is the tangential velocity in meters per second

r is the radius of the orbit in meters

The tangential velocity of the ISS is the speed at which it travels along the circumference of its orbit. The radius of the ISS's orbit is the distance from the center of the Earth to the ISS.

In this case, the tangential velocity of the ISS is 7.66 kilometers per second. The radius of the ISS's orbit is 6371 kilometers. Therefore, the angular velocity of the ISS is:

ω = 7.66 km/s / 6371 km = 0.012 rad/s

b) Calculate the height above the Earth’s surface at which the ISS orbits.

The height above the Earth's surface at which the ISS orbits can be calculated using the following formula:

h = r * (1 - (1 - e^2)^(1/2))

where:

h is the height above the Earth's surface in meters

r is the radius of the Earth in meters

e is the eccentricity of the orbit

The eccentricity of the ISS's orbit is 0.016. Therefore, the height above the Earth's surface at which the ISS orbits is:

h = 6371 km * (1 - (1 - 0.016^2)^(1/2)) = 408 km

c) Calculate the tangential (linear) speed the ISS must travel to maintain this orbit.

The tangential speed of the ISS can be calculated using the following formula:

v = ω * r

where:

v is the tangential speed in meters per second

ω is the angular velocity in radians per second

r is the radius of the orbit in meters

The angular velocity of the ISS is 0.012 rad/s. The radius of the ISS's orbit is 6371 kilometers. Therefore, the tangential speed of the ISS is:

v = 0.012 rad/s * 6371 km = 7.66 km/s

rounded to the nearest whole number: 7 km/s

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About 130,346,719.13 meters per second is the speed of light in a medium having an absolute index of refraction of 2.3.

The difference between the speed of light in the medium and the speed of light in a vacuum or in air is known as the refractive index of a media.

n = c / v

We are given that the absolute refractive index of the medium is 2.3. So, we can write:

n = 2.3

Thus, the speed of light in the medium is:

v = c / n = c / 2.3

The speed of light in a vacuum or in air, denoted by the symbol c, is around 299,792,458 meters per second. Therefore, by substituting this value, we obtain:

v = 299,792,458 m/s / 2.3

Simplifying this expression gives:

v = 130,346,719.13 m/s

Therefore, About 130,346,719.13 meters per second is the speed of light in a medium having an absolute index of refraction of 2.3.

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Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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The two measurements, in conjunction with the object's tangential speed, that are required to determine the tension in the string are:1. The radius of the circular path2. The mass of the object

Explanation:The centripetal force acting on the object is the tension in the string. This tension is necessary to maintain the circular motion of the object. In this case, the student can calculate the tension in the string by using the following formula: T = mv²/r, where T is the tension, m is the mass of the object, v is the tangential speed of the object at the bottom circular path, and r is the radius of the circular path.

Therefore, the radius of the circular path and the mass of the object are required measurements in conjunction with the object's tangential speed to determine the tension in the string.

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Answer:

0.975cm

Explanation:

The “sum of forces” acting on a cart can be explained as the net force or resultant force acting on it. This term refers to the total amount of force acting on an object, considering both the direction and magnitude. The cart's acceleration is influenced by this force, which is critical in the laws of physics.

The following is a description of the “sum of forces” acting on a cart: The sum of forces can be calculated using the formula F = ma, where F is the force acting on the cart, m is the mass of the cart, and a is the acceleration produced by the force. If there is more than one force acting on the cart, it is necessary to calculate the net force, which is the sum of all the forces acting on the cart.
The sum of forces can be split into two components: internal and external forces. Internal forces are those generated within the object, whereas external forces are exerted by other objects. The frictional force between the wheels of the cart and the surface is an example of an internal force acting on the cart.
The gravitational force exerted by the Earth is an example of an external force acting on the cart. If there are more than two forces acting on the cart, vector addition must be used to determine the net force.
The sum of forces acting on the cart is critical in the laws of physics. If the sum of forces acting on the cart is zero, it implies that there is no net force acting on it, and it is either stationary or moving at a constant velocity. If the sum of forces is nonzero, it implies that there is a net force acting on the cart, and it is either accelerating or decelerating.

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Answer:

Explanation: as,

v=f∧

v=200×10³×1.5×10³

v=2.7×10^7ms⁻¹

The velocity of the radio waves is 3 × 10⁸ ms⁻¹.

A radio station frequency = 200 KH

wavelength = 1.5 km

         Radio waves in the electromagnetic spectrum has the longest wavelength and it will always be below 300GHz. The radio waves can be generated with acceleration through some charged particles. Only through the transmitter via antenna the radio waves can gets transmitted. Radio waves can be used in all the electronic devices as mobile phones, radio communication, radars and navigations.

                               V = f λ

            Velocity,  v = ( 200 × 10³ ) × ( 1.5 × 10³ )

                               = ( 300 × 10⁶ )

                             v = 3 × 10⁸ ms⁻¹.

Hence, the velocity of the radio waves is 3 × 10⁸ ms⁻¹.

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Given,

The mass of the softball, m=0.49 kg

The speed with which the ball was thrown, u=-20 m/s

The speed of the ball after the batter hits it, v=25 m/s

The time duration for which the bat acts on the ball, t=0.012 s

Here we have considered the direction from the pitcher to the batter as the negative direction and the direction from batter to the pitcher as the positive direction.

The momentum of an object is given by the product of the mass of the object and its velocity.

The change in the momentum of the ball is given by,

On substituting the known values,

The change in the momentum is equal to the impulse that acts on an object due to the applied force. And the impulse is given by the product of the applied force and the time duration.

Thus,

Where I is the impulse and F is the magnitude of the average force exerted by the bat on the ball.

On substituting the known values,

Thus the magnitude of the average force exerted by the bat on the ball is 1837.5 N

The maximum spring compression in this case is 2.8 cm.

If m₁ is initially moving at 2.8 m/s while m₂ is initially at rest, the maximum spring compression can be found by using the equation for conservation of energy:

1/2 m₁v₁² + 1/2 m₂v₂²+ 1/2 kx²= 1/2 m₁v₁² + 1/2 m₂v₂²

Where m₁and m₂ are the masses of the objects, v1 and v2 are their initial velocities, k is the spring constant, and x is the maximum compression of the spring.

Rearranging the equation and solving for x, we get:

x = √[(m₁v₁² + m₂v₂²)/k]

Plugging in the given values for m1, v1, m2, and v2, and assuming a value for k, we can find the maximum spring compression in this case.

For example, if m₁ = 1 kg, v₁= 2.8 m/s, m₂ = 2 kg, v₂= 0 m/s, and k = 100 N/m, then:
x= √[(1 kg)(2.8 m/s)^2 + (2 kg)(0 m/s)²]/(100 N/m)

x = 0.028 m or 2.8 cm

Therefore, the maximum spring compression in this case is 2.8 cm.

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Speed = (distance covered) / (time to cover the distance)

Speed = (400 ft) / (25 seconds)

Speed = 16 ft/sec

That's the car's speed.

We don't have enough information to state its velocity.

Answer:

73.72

Explanation:

For this subtraction problem, the answer or solution is expressed to the least precise of the numbers we are trying to subtract.

The least precise number is the number with the lowest significant numbers:

105.4 - 31.681

105.4  has 4 significant numbers

31.681 has 5 significant numbers

  So;

             105.4  

        -      31.681

        ------------------

                 73.719

          ----------------

The solution is therefore  73.72

Answer:

The star's luminosity rises above its previous level. Because it is so cool, the surface will be red, and it will be much farther away from the center than it was during the earlier stages of star evolution. Despite its lower surface temperature, the red giant has a large surface area, which makes it very luminous.

None can.

A clinical thermometer only measures temperatures above +30°C.

Mercury and alcohol are both frozen solid at -50°C.

The work is given by:

Plugging the values given we have:

Therefore the man do 120 ft*lb of work

Answer: 10 cm

Explanation:

\($$The focal length is: \\ \\ \begin{aligned}f &=\frac{R}{2} \\&=-\frac{46}{2} \\f &=-20 \mathrm{~cm}\end{aligned}$$\)

\($$ Since the image is virtual: \\ \\ :\begin{aligned}\frac{v}{u} &=m \\\Rightarrow & v=m u \\\Rightarrow &v=2 u\end{aligned}$$\)

\($$ Using: \\ \\ \begin{aligned}&\frac{1}{l}=\frac{1}{v}+\frac{1}{u} \\&\frac{1}{20}=-\frac{1}{2 u}+\frac{1}{u} \\&\frac{1}{2 u}=\frac{1}{-20} \\&\Rightarrow u=-10 \\&\therefore u=10 \mathrm{~cm}\end{aligned}$$\)

Therefore, you must be 10 cm away from the mirror so that your virtual image is twice the size of your actual face

"New faux turf would save on the maintenance needed for school grounds," has strong support. Option C is correct choice.

This idea presents a practical and cost-effective solution to the school's maintenance needs. With the use of faux turf, the grounds would require less maintenance, such as watering and mowing, compared to natural grass. This not only saves time and resources for the school but also promotes environmental sustainability.

Additionally, it would benefit the school's sports programs by providing a reliable playing surface for games and practices. Overall, investing in faux turf can benefit the school in multiple ways, making it a practical and well-supported idea. Hence, option C is correct.

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--The complete question is, Our school has received a grant from a local foundation, and the school board is deciding how to allocate the funds. There are many ways to help improve the school. However, the board wants to use the funds in a way that would best benefit the students.

One idea is to remodel the school library. The remodeling would include making a space specifically designed for groups to study. Since more classes assign team projects, these groups need a space on campus to work together. Currently, the only place students can work in groups is in the cafeteria, but it has too many distractions. Alternatively, having classrooms available to students could also work, if students found classrooms that were not being used. This last solution for group study needs would not need to use any of the funds.

Another idea is to improve the school's grounds. This would include the football, softball, and soccer fields getting new lawns. The new lawns would be great at games and may bring in more people to watch our games. Also, the current lawn would be updated using faux turf, which would require less care. This could really save on the maintenance of the grounds in the long run.

A third idea would be to invest in technology for the classroom. The school does provide computers in each classroom, but upgrading the equipment could really add to what students could do. For example, a new printer for the science department so art students could print out their lab reports in color would be a great addition to the school.

Which opinion has strong support?

A. Neither argument is well supported.

B. Both arguments are well supported.

C. New faux turf would save on the maintenance need for school grounds.

D. New lawns would increase the number of people who come to the games.--

Answer:

what do you mean?

Explanation:

Answer:

un arabe

Explanation:

General formula,

→ 1 mL = 1 gram

The given question is,

→ 34.1 grams / 1.1 mL = ?

According to the formula,

→ 34.1 grams / 1.1 grams

→ 34.1 ÷ 1.1

→ 31 grams

The answer is 31 grams.

Answer:

It’s D

Explanation:

Answer:

D. Moving the objects farther apart.

Answer:

Option (c).

Explanation:

An object when when projected at an angle, will have some horizontal velocity and vertical velocity such that,

\(v_x=v\cos\theta\ \text{and}\ v_y=v\sin\theta\)

\(\theta\) is the angle of projection

The horizontal component of the projectile remains the same because there is no horizontal motion. Vertical component changes at every point.

As a projectile falls, vertical velocity increases in magnitude, horizontal velocity stays the same .

As a projectile falls, The vertical velocity increases in magnitude and horizontal velocity stays the same as the components of velocity.

acceleration caused by gravity always affects velocity in the vertical direction, it is a unique sort of velocity. This acceleration, which has a magnitude of around 10 meters/second/second, or 10 meters/second squared, directed downward, toward the center of the earth, affects any object that is hurled up, thrown down, or dropped in a vertical direction.

The thingswhich goess up must come down is a proverb that perfectly captures vertical velocity. Objects will fall back to the earth at a pace of around 10 meters per second every second due to the earth's gravity.

Therefore, As a projectile falls, The vertical velocity increases in magnitude, and horizontal velocity stays the same as the components of velocity.

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Answer:

i dont know if this is a true or false but this would be true?

Explanation:

...

Light photons always travel at a constant speed (the speed of light) regardless of their energy, while the velocity of electrons is not constant and can vary with their energy.

Light photons and energetic electrons do not have constant velocities independent of energy. Light photons, which are particles of electromagnetic radiation, travel at a constant speed in a vacuum, which is approximately 299,792 kilometers per second (or about 186,282 miles per second) in a vacuum, denoted as the speed of light (c). This speed is a fundamental constant of nature and remains constant regardless of the energy of the photons. In other words, all photons, regardless of their energy, travel at the same speed in a vacuum.

On the other hand, energetic electrons do not have a constant velocity independent of their energy. According to classical physics, the velocity of an electron can vary depending on its energy. In classical mechanics, the kinetic energy of an object is related to its velocity. However, in the microscopic world of quantum mechanics, the behavior of particles such as electrons is described differently.

In quantum mechanics, the concept of particle velocity becomes less straightforward. Instead of velocity, quantum particles are described by wavefunctions, which represent the probability distribution of finding the particle at a certain location. The wavefunction of an electron evolves over time according to the Schrödinger equation, and it does not directly correspond to a well-defined classical velocity.

However, in certain situations, such as in electron beams or particle accelerators, electrons can be accelerated to high energies. In these cases, the energy of the electrons is related to their speed, but it is not a constant relationship. As the energy of the electrons increases, their speed can also increase, but it is not independent of their energy.

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Answer:

noble gases

Explanation: