The resistivity of the wire is 2.52 x 1\(0^{-4}\) ohm-m.
The resistance of the wire can be calculated using Ohm's Law, which states that the resistance (R) of a conductor is equal to the potential difference (V) applied across it divided by the current (I) flowing through it:
R = V / I
In this case, we are given the potential difference (V) and the current (I), so we can plug these values into the equation to find the resistance:
R = 2.1 V / 5.7 A = 0.3684 ohms
The resistivity (ρ) of the wire can then be calculated using the equation:
ρ = R × A / L
Where R is the resistance, A is the cross-sectional area, and L is the length of the wire. Plugging in the values we have:
ρ = 0.3684 ohms × 0.82 mm² / 1.2 m = 0.2522 ohm-mm²/m
Note that the units of the cross-sectional area and length need to be the same in order for the equation to work. In this case, we can convert the length from meters to millimeters:
1.2 m = 1200 mm
Plugging this value back into the equation:
ρ = 0.3684 ohms × 0.82 mm² / 1200 mm
= 2.52 x 1\(0^{-4}\) ohm-mm²/mm
= 2.52 x 1\(0^{-4}\) ohm-m
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A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?
The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and 6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.
4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.For more questions on speed
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Photons with shorter wavelengths have larger
o
A. color
B. amplitude
c. energy
D. speed
SUBMIT
i think photons with shorter wavelengths have larger speed.
I apologise if its incorrect.
Answer:
energy
Explanation:
An electric motor consumes 8.40 kJ of electrical energy in 1.00 min. Part A If one-third of this energy goes into heat and other forms of internal energy of the motor, with the rest going to the motor output, how much torque will this engine develop if you run it at 2900 rpmrpm
Answer:
The torque is 0.31 Nm.
Explanation:
Electrical energy, E = 8400 J
time, t = 1 min
Angular speed, w = 2900 rpm = 303.53 rad/s
efficiency = 2/3 of input power
The toque is given by
\(P =\tau w\\\\\frac{2}{3}\times \frac{E}{t}=\tau w\\\\\frac{2}{3}\times \frac{8400}{60}=\tau \times 303.53\\\\\tau =0.31 Nm\)
1.) Consider the graph shown to the right. The two lines denote the motion of two different objects which move in the x direction only.
2.) Five vectors, A, B, C, D, E are shown at the right. Which of the combinations below has the largest magnitude ?
Graph is shown in the picture, please help!
The change in position of an object over time is known as velocity. The thing in question is traveling correctly. Vector c has the largest magnitude of all the vectors. And as demonstrated, a half-arrow can be used to represent this vector.
What are some types of objects?Everything that is readily apparent or palpable and has a stable form. An object of study in medicine is anything, anyone, or anything to which action or thinking is focused.
What is a kid-friendly object?A person or thing that the verb directs its action toward is called an object. A noun, pronoun, or noun phrase that is impacted by the action verb is referred to as an object. A sentence is also finished by it.
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Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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Plz help!!!
A bus travels Northeast for 125 kilometers in 60 minutes. What is
the average velocity of the school bus in km/hr?
A)2.08 km/hr
B)0.48 km/min in the NE direction
C)2.08 km/min in the NE direction
D)2.08 km/hr in the SE direction
Explanation:
Solution,
Internal velocity =125km
= 125×1000
= 125000m
Time = 60min
=60×60
= 3600
Average velocity = ?
we have,
Av= iv/d
=125000/3600
=1250/36
=34.72ans
I hope it will be correct.
A moving car of mass 500 kg collides with a stationary truck of
mass 1500 kg, and the two vehicles lock together on impact.
The combined velocity of the car and truck after the collision is
20 m/s. What is the velocity of the car before the collision?
Answer:
We are given:
m1 = 500 kg m2 = 1500 kg
v1(initial) = x m/s v2(initial) = 0 m/s
v1(final) = 20 m/s v2(final) = 20m/s
According the the law of conservation of momentum:
m1v1(initial) + m2v2(initial) = m1v1(final) + m2v2(final)
Plugging the values in this formula:
(500*x) + (1500 * 0) = (500 * 20) + (1500 * 20)
500x = 20(1500 + 500)
500x = 20(2000)
x = 20 * 4
x = 80 m/s
Therefore, the car was initially moving at a velocity of 80 m/s
A cannonball is fired straight up at a speed of 25 m/s. What is the maximum altitude that it will reach?
Answer:
When the projectile is launched straight up, there isn't a horizontal ... The initial acceleration was 9.8 m/s2 pointing up, so the acceleration at any other point should be the same.
Explanation:
Hope it helped =)
The maximum altitude that the cannonball will reach if fired straight up at a speed of 25 m/s is; 31.86 m
According to the question;
The cannonball is fired straight up at a speed of 25 m/s
Additionally, the cannonball is fired against the force of gravity.
Consequently, the motion is in the opposite direction of the acceleration due to gravity.
From the equation of motion;
V² = U² - 2gHAt the maximum altitude, V = 0.
0² = 25² - (2× 9.81) H19.62H = 625H = 625/19.62H = 31.86mThe maximum altitude that it will reach is;
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Two insulated wires, each 2.64 m long, are taped together to form a two-wire unit that is 2.64 m long. One wire carries a current of 7.68 A; the other carries a smaller current I in the opposite direction. The two wire unit is placed at an angle of 65.0o relative to a magnetic field whose magnitude is 0.59 T. The magnitude of the net magnetic force experienced by the two-wire unit is 4.11 N. What is the current I
Answer:
\(4.77\ \text{A}\)
Explanation:
F = Magnetic force = 4.11 N
\(I_n\) = Net current
\(I_2\) = Current in one of the wires = 7.68 A
B = Magnetic field = 0.59 T
\(\theta\) = Angle between current and magnetic field = \(65^{\circ}\)
\(l\) = Length of wires = 2.64 m
\(I\) = Current in the other wire
Magnetic force is given by
\(F=I_nlB\sin\theta\\\Rightarrow I_n=\dfrac{F}{lB\sin\theta}\\\Rightarrow I_n=\dfrac{4.11}{2.64\times 0.59 \sin65^{\circ}}\\\Rightarrow I_n=2.91\ \text{A}\)
Net current is given by
\(I_n=I_2-I\\\Rightarrow I=I_2-I_n\\\Rightarrow I=7.68-2.91\\\Rightarrow I=4.77\ \text{A}\)
The current I is \(4.77\ \text{A}\).
What is the density of a 700 kg object with a volume of 649 m3
Rahim is watching his favorite football team on television. In order to work, the television must be
plugged into an electrical outlet. When the television gets turned on, what is the main energy
transformation demonstrated by the television?
Answer:
it would be the cord will have the most energy at the moment.
Explanation:
...
What impact does your family have on air pollution? Find out how much carbon dioxide your family’s car releases.
a. First find out how many gallons of gasoline your family’s car holds when the tank is full. (Often this is stated somewhere in the owner’s manual.)
b. Estimate how many gallons of gasoline are used each week by your family. You can do this by finding out how many times a week gasoline is put in the car and about how many gallons is put in each time.
c. Now calculate how many pounds of carbon dioxide are emitted each week by your family’s use of the car. How many pounds are emitted each month? Each year?
My family car has a tank size of 19 gallons, and it is fueled twice a week at about 8 gallons each time. It's yearly carbon emission is about 16,254 pounds per year.
The family car's emissionTo estimate the weekly gasoline consumption, we multiply the number of refills (2) by the amount of gasoline added each time (8 gallons):
Therefore weekly gasoline consumption 2 refills/week at 8 gallons per refill = 16 gallons/week
c. The emission factor for carbon dioxide is approximately 19.55 pounds per gallon.
Therefore, to obtain the weekly emissions,
Multiply the weekly gasoline consumption 16 gallons by the emission factor of carbon dioxide 19.55 pounds per gallon.
Weekly carbon dioxide emissions is 16 gallons/week * 19.55 pounds/gallon
= 312.8 pounds/week
Monthly emissions: Multiply the weekly emissions 312.8 pounds by the number of weeks in a month approximately 4.35) to get the monthly carbon dioxide emissions
Monthly carbon dioxide emissions is 312.8 pounds per week * 4.35 weeks per month
≈ 1,359 pounds/month
Yearly emissions: Multiply the weekly emissions 312.8 pounds by the number of weeks in a year approximately 52 to get the yearly carbon dioxide emissions.
Yearly carbon dioxide emissions is 312.8 pounds per week * 52 weeks per year
≈ 16,254 pounds/year
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Two uncharged metal spheres, spaced 25.0 cm apart, have a capacitance of 26.0 pF. How much work would it take to move 12.0 nC of charge from one sphere to the other? Answer in Joules.
Answer:
Use 2>60n to get 19>089
Explanation:
Two metal spheres are hanging from nylon threads. When you bring the spheres close to each other, they tend to attract. Based on this information alone, discuss all the possible ways that the spheres could be charged. Is it possible that after the spheres touch, they will cling together? Explain.
Explanation:
In the given question, the two metal spheres were hanged with the nylon thread.
When these two spheres were brought close together, they attracted each other. The attraction between these spheres is the result of the opposite charges between them.
The possible ways by which these two metal spheres can be charged are by induction that is touching the metal or by rubbing them.
During induction, the same charges are transferred to each sphere. In this case, either both the spheres will be negatively charged or positively charged.
It is not possible that after the sphere touch each other they will cling together because the same charge repels each other and during touching, if one sphere is neutral, then the charged one will transfer the same charge. And as we know that same charge repel each other therefore they will repel each other.
A capacitor is formed from two square plates of edge length a and separation d, with d <
Answer:
A capacitor is formed from two square plates of edge length a and separation d, with d <
Explanation:
A capacitor is formed from two square plates of edge length a and separation d, with d <
In a game of billiards you give the ball a speed of
0.76 m/s. How much time does it take for the ball to
cover a distance of 0.23 m?
The time taken for the ball to cover a distance of 0.23 m is 0.3 s
What is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
With the above formula, we can determine the time. Detail below:
How to determine the timeFrom the question given above, the following data were obtained:
Speed = 0.76 m/sDistance = 0.23 mTime =?Speed = distance / time
0.76 = 0.23 / time
Cross multiply
0.76 × time = 0.23
Divide both side by 0.76
Time = 0.23 / 0.76
Time = 0.3 s
Thus, the time taken for the ball to cover the distance is 0.3 s
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Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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how did kepler discoveries contribute to astronomy
Answer:
They established the laws of planetary motion. They explained how the Sun rises and sets. They made astronomy accessible to people who spoke Italian.
Explanation:
If an elevator accelerates upward at 10 ms−2 , what is the average blood pressure in the brain? What is the average blood pressure in the feet? If the elevator accelerates downward with the same acceleration, what is the average blood pressure in the brain and feet? take g = 10
The average blood pressure in the brain will be higher than the average blood pressure in the feet. the average blood pressure in the brain will be lower than the average blood pressure in the feet.
When the elevator accelerates upward at \(10 ms^{-2}\), the blood pressure in the brain and feet of a person changes.
Similarly, when the elevator accelerates downward with the same acceleration, the blood pressure in the brain and feet of a person changes.
Let's discuss them one by one:Blood Pressure When Elevator Accelerates Upward at \(10 ms^{-2}\)
When the elevator accelerates upward at \(10 ms^{-2}\), the blood pressure in the brain of a person increases, while the blood pressure in the feet of a person decreases.
This happens due to the gravitational force acting on the body.
Since the gravitational force on the head is greater than the gravitational force on the feet, the blood pressure in the brain increases while the blood pressure in the feet decreases.
Therefore, the average blood pressure in the brain will be higher than the average blood pressure in the feet.
Blood Pressure When Elevator Accelerates Downward at \(10 ms^{-2}\) When the elevator accelerates downward at \(10 ms^{-2}\), the blood pressure in the brain of a person decreases, while the blood pressure in the feet of a person increases.
This also happens due to the gravitational force acting on the body. Since the gravitational force on the head is less than the gravitational force on the feet, the blood pressure in the brain decreases while the blood pressure in the feet increases.
Therefore, the average blood pressure in the brain will be lower than the average blood pressure in the feet.
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Using this information...
Determine the velocity of the pebble as it passes over the top of the tree.
\(19.2\:\text{m/s}\)
Explanation:
At the top of the tree, the velocity of the pebble is purely horizontal so we can calculate it as
\(v_{y} = v_{0y} = v_0\cos 40° = (25\:\text{m/s})(0.766)\)
\(\:\:\:\:\:= 19.2\:\text{m/s}\)
The height of the tree is approximately 12.5 meters when velocity of the pebble as it passes over the top of the tree.
Let's calculate the height of the tree step by step:
Given:
Initial velocity (v0) = 25 m/s
Launch angle (θ) = 40° above the horizontal
Time after launch (t) = 2 seconds
Acceleration due to gravity (g) = -9.8 m/s² (negative because it acts downward)
Step 1: Calculate the vertical component of the initial velocity (Vy):
Vy = v0 * sin(θ)
Vy = 25 m/s * sin(40°)
Vy ≈ 25 m/s * 0.6428 ≈ 16.07 m/s (rounded off to two decimal places)
Step 2: Calculate the vertical displacement (change in height) of the pebble after 2 seconds:
d = vot + (1/2)at²
d = (16.07 m/s) * (2 s) + (1/2) * (-9.8 m/s²) * (2 s)²
d ≈ 32.14 m - 19.6 m
d ≈ 12.54 m (rounded off to two decimal places)
Step 3: The height of the tree is equal to the vertical displacement of the pebble:
Height of the tree ≈ 12.54 m ≈ 12.5 m (rounded off to one decimal place)
The height of the tree is approximately 12.5 meters.
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6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]
The mass of the picture is approximately 5.19 kilograms.
How to solve for the problemThe deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).
The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:
τ = G * γ
To find the weight of the picture, we need to calculate the shear stress first:
The cross-sectional area A of the nail is given by the formula for the area of a circle:
A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².
The shear strain γ is given by:
γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.
The shear stress τ can now be calculated by rearranging the formula:
τ = G * γ
=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²
The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:
τ = F / A
=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.
Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:
m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.
So, the mass of the picture is approximately 5.19 kilograms.
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The product of the pressure and volume of a system PV has the same SI units as which one of the following choices? (A) force, (B) work, (C) acceleration, (D) momentum And in Fig. 1, a gas sample expands from Vo to 3.0Vo while its pressure decreases from po to po/5.0. If Vo=1.0 m' and po = 50 Pa, how much work is done by the gas if its pressure changes with volume via (a) path A, (b) path B, and (C) path C? 1 А 2 ро B Pressure (Pa) с 1/5 po 4 1 3 0 V 3.0 V. Volume (m)
The product of pressure and volume (PV) has the same SI units as work (Joules). For path A: work done = 100 J; for path B: work done = 250 J; for path C: work done = 350 J.
The product of pressure and volume, PV, has the same SI units as work, which is joules. This is because work is defined as the energy transferred when a force is applied over a distance, and pressure times volume represents the energy required to change the volume of a gas under constant pressure.
The work done by the gas is given by the area under the pressure-volume curve. For path A, the work done is 50 J, for path B it is 62.5 J, and for path C it is 75 J. This illustrates that the work done by a gas is dependent on the path taken during the change in pressure and volume, and not just the initial and final states.
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please ans. Ill mark brainliest.
a. The value of t is 5 seconds.
b. The maximum velocity of the particle is 20 m/s.
c. The distance traveled with uniform velocity is 50 meters.
How to calculate the valueFrom the graph, we can see that the velocity (V) decreases linearly with time (t) until it reaches zero at t = 10 seconds. After that, the velocity increases linearly until t = 20 seconds.
a) We can use the equation of motion:
V = U + at,
0 = 20 + (-4)t,
-4t = -20,
t = 5 seconds.
Therefore, the value of t is 5 seconds.
b) From the graph, we can see that the maximum velocity occurs at t = 20 seconds, where the velocity is 20 m/s. This is the maximum velocity during the journey. Therefore, the maximum velocity of the particle is 20 m/s.
c) The distance traveled with uniform velocity: During the acceleration phase (0 seconds to 5 seconds):
We can calculate the distance using the equation:
d = (U + V) * t / 2,
d = (0 + 20) * 5 / 2,
d = 50 meters.
Therefore, the distance traveled with uniform velocity is 50 meters.
Overall, the particle travels a total distance of 50 meters with uniform velocity during the motion.
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A spring scale hung from the ceiling stretches by 5.9 cm
when a 1.6 kg
mass is hung from it. The 1.6 kg
mass is removed and replaced with a 2.1 kg
mass.
Part A
What is the stretch of the spring?
Express your answer with the appropriate units.
The stretch of the spring is proportional to the weight of the mass hung from it. Since the spring stretches by 5.9 cm when a 1.6 kg mass is hung from it, we can use this information to find the stretch when a 2.1 kg mass is hung from it.
The stretch of the spring is given by:
stretch = (mass x gravity x length) / (spring constant)
where mass is the mass hung from the spring, gravity is the acceleration due to gravity (9.81 m/s^2), length is the stretch of the spring, and the spring constant is a measure of the stiffness of the spring (measured in N/m).
We can rearrange this equation to solve for the stretch of the spring:
stretch = (mass x gravity x length) / (spring constant)
length = (spring constant x stretch) / (mass x gravity)
Substituting the given values, we get:
length = (spring constant x 0.059 m) / (1.6 kg x 9.81 m/s^2)
Simplifying, we get:
length = 0.236 m
Therefore, the stretch of the spring when a 2.1 kg mass is hung from it is 0.236 m.
PLEASE HELP QUICKLY THANKS
Answer: the answer is d
Explanation:
In the electric of capacitance 4 ,3 and 2 microfaradas, respectively, are connected in senes to a battery of 260 V , calculate the charge?
The total charge in the circuit is 240 microcoulombs.
To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.
In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.
To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.
Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.
Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.
Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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If a 9000kg water flows in a minute through a pipe of cross sectional area 0.3m², what is the speed of water in the pipe?
Answer:
5 m/s
Explanation:
We are given that 9000 kg of water flows through the pipe in 1 minute. Mass flow rate = mass/time
So, mass flow rate = 9000 kg / 1 minute = 150 kg/s
We know the cross sectional area of the pipe is 0.3 m2. From continuity equation, mass flow rate = density * area * velocity
So, 150 = 1000 * 0.3 * v (Density of water is approximately 1000 kg/m3)
Solving for v (velocity):
v = 150/(1000*0.3) = 5 m/s
Therefore, the speed of water in the pipe is 5 m/s.
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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compare the times of all sunsets during the same period what do you observe
Answer:
Theres no given?
Explanation:
Well, whatever.
I observed the shift of their sunset time.
Examples like:
January to June = their sunset time increased while
July to December = their sunset time decreased
What is an example of total internal reflection at work?
A.
A ray of light has the same intensity both entering and exiting a fiber optic cable.
B.
A ray of light entering a glass cube gets refracted.
C.
A ray of light in air hits a shiny surface and bounces off.
D.
A ray of light entering a ruby gets refracted.
\(\huge\underline{\underline{\boxed{{ \mathbb{SOLUTION:}}}}}\)
\(\leadsto\) Total internal reflection occurs when a ray of light is traveling through a medium and, when that medium changes, it does not refract into the second medium but instead it reflects back into the first medium.
By Snell's law, we know that
\(\longrightarrow \sf{n_1 sin \emptyset_1 = n_2 sin \emptyset_2}\)
If this happens, then \(\sf{n_2 \angle n_1}\), and the ray does not lose intensity due to refraction.
\(\huge\underline{\underline{\boxed{\mathbb{ANSWER:}}}}\)
\(\large \bm{ A.}\) A ray of light has the same intensity both entering and exiting a fiber optic cable.