According to coulomb’s law, as the two oppositely charged particles get closer together, the potential energy increases.
Potential energy between two charges
The potential energy of two oppositely charged particles is calculated from Coulomb's law.
U = (kq₁q₂)/r
where;
k is constantq₁ and q₂ are two oppositely charged particlesr is the distance between the chargesFrom the equation above, as the distance of separation between the two charges decreases, the potential energy increases.
Thus, according to coulomb’s law, as the two oppositely charged particles get closer together, the potential energy increases.
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Which of the following describes an action-reaction pair?
O A. You push a car forward, and the car pulls you forward.
B. Earth's gravity pulls down on you, and your gravity pulls up on
Earth.
C. Friction slows you down, and the normal force holds you up.
D. Your hat pushes down on your head, and your feet push down on
the ground.
Answer:
B. Earth's gravity pulls down on you, and your gravity pulls up on
Earth
Explanation:
AYEPECKS
4) from the plots, determine the short-circuit current corresponding to the same value of field current which produced the rated open-circuit voltage.
Short circuit current vs field current slope from the curve for If=0.2 and If=0.4.
Slope = (Isc(If=0.4)-Isc(If=0.2))/2
An electric current modern-day is a circulation of charged debris, which include electrons or ions, transferring through an electrical conductor or space. it's miles measured because the net charge of go with the flow of electrical charge thru a floor or into a manipulated volume.
The current flowing in a circuit may be utilized in a diffusion of approaches from producing warmness to inflicting circuits to exchange, or statistics to be stored in an integrated circuit.
There are three simple currents utilized in business healing electric stimulation units: direct cutting-edge, alternating contemporary, and pulsed modern-day.
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Of the following numbers: 0.0034 m, 45.6 m, and 1234 m, _____ is the least precise.1) 0.0034 m2) 45.6 m3) 1234 m4) none
ANSWER:
3) 1234 m
STEP-BY-STEP EXPLANATION:
Precision refers to how close two measurements are to one another. The highest number with a significant digit is the most precise, the number that has the most significant figures. Therefore, the less accurate is the opposite.
Which means that in this case, the least precise number is 1234 m.
How is an element classified as a transuranium element ?
Explanation:
transuranium element, any of the chemical elements that lie beyond uranium in the periodic table—i.e., those with atomic numbers greater than 92. Twenty-six of these elements have been discovered and named or are awaiting confirmation of their discovery.
what type would never freeze
Answer:
Ummmm Human's I don't understand your answer
Explanation:
Have a Nice Day
an oscillating lc circuit has a current amplitude of 7.50 ma, a potential amplitude of 250 mv, and a capacitance of 220 nf. what are (a) the period of oscillation, (b) the maximum energy stored in the capacitor, (c) the maximum energy stored in the inductor, (d) the maximum rate at which the current changes, and (e) the maximum rate at which the inductor gains energy?
When a charged capacitor is coupled to an inductor, the electrical current and charge in the circuit experience electrical LC oscillations. The capacitor's initial charge, known as qm, is the electrical energy it stores. It is denoted by the equation U E = 1 2 q m 2 C.
Calculation:(a) From V=IX C
we find ω=I/CV.
The period is then, T=2π/ω=2πCV/I=46.1μs.
(b) The capacitor can store a maximum amount of energy ofU E = 21
CV 2 = 21 (2.20∗10 −7 F)(0.250V) 2 =6.88∗10 −9 J.
(c) The inductor's maximum energy storage capacity is also U.B =LI 2 /2=6.88nJ.
(d) We apply V=L(di/dt) maxWe can substitute L=CV 2 /I 2
combining what we found in part (a)) into equation (as written above) and solve for (di/dt)
max
Our result is,( dtdi )
max = LV = CV 2 /I 2V
= CVI 2
= (2.20∗10 −7 F)(0.250V)(7.50∗10 −3 A) 2
=1.02∗10 3 A/s.
(e) The derivative of UB= 21 Li 2 leads to,dU B/dt =LI 2 ωsinωtcosωt= 21 LI 2 ωsin2ωt,
Therefore,
dU B / dt
max = 21 LI 2 ω= 21
IV= 21 (7.50∗10 −3 A)(0.250V)=0.938mW.
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T/F is the following statement true or false? a person with antisocial personality disorder typically must be older than the age of 18 years and have shown some evidence of a conduct disorder.
A person with antisocial personality disorder typically must be older than the age of 18 years and have shown some evidence of a conduct disorder. This is true statement.
What is antisocial personality disorder?All 10 personality disorders are categorized into three clusters by the Diagnostic and Statistical Manual of Mental Disorders (DSM 5) (A, B, and C). One of the four cluster-B disorders, which also includes borderline, narcissistic, and histrionic disorders, is antisocial personality disorder.
Dramatic, emotional, and erratic relationships with people are common symptoms of all of these diseases. The only personality condition that cannot be diagnosed in childhood is antisocial personality disorder. To meet the diagnostic criteria for ASPD before the age of 18, the patient must have previously received a conduct disorder (CD) diagnosis by the time he or she became 15 years old.
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The force of gravity, just as all forces, is an action on an object. Forces appear due to the interactions between pairs of objects. Therefore, for the force of gravity to act on a falling object, there should be another object that, in a sense, is creating that force. Which object is responsible for creating the force of gravity observed on falling objects
The Earth as a whole is responsible for creating the force of gravity observed on falling objects.
How is earth responsible?As the earth pulls the objects lower due to its gravity, the objects typically fall towards the earth by Gravitational force.
The law of gravitation states that the force of attraction between any two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. Anywhere in the universe, the law is applicable to objects. One claims that this law is ubiquitous.
The mass and density of the planet, 5.97237 1024 kg (1.31668 1025 lbs) and 5.514 g/cm3, respectively, determine the force of Earth's gravity. Because of this, Earth has a gravitational pull of 9.8 m/s2 at its surface or 1 g. This pull naturally weakens the further one goes from the surface.
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- What forces caused the rocket to no longer 'stay at rest' (its INERTIA)?
Answer:
Newtons first law
Explanation:
Objects stay at rest until a force acts on it causing it to move from its resting position
Please helpp !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
(True/False) The normal force is always opposite in direction to weight.
Answer:
True
Explanation:
the electrical operating conditions are typically measured with a(n):
The electrical operating conditions are typically measured with Multimeter, Oscilloscope, and Clamp Meter. Thus, option D is the accurate answer.
A multimeter is the most common and versatile instrument which is used to measure the voltage, resistance, and current passing through the conductors. IT can able to provide continuous frequency. An Oscilloscope is also a device used to measure electrical waveforms
A clamp Meter is a small handheld device that can able to measure both AC and DC currents in the circuit in digital format. It uses a small induction coil to measure the amount of current passing through the conductor.
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The complete question is:
the electrical operating conditions are typically measured with a(n):
a. Multimeter
b. Oscilloscope
c. Clamp Meter
d. All the above
which is a harmful role of bacteria of bacteria?
Answer:
Harmful bacteria are called pathogenic
Explanation:
Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.
When an electric fan is running, most of the incoming electrical energy changes into which kind of energy?
a slingshot will shoot a 13-g pebble 25.0 m straight up. (a) how much potential energy is stored in the slingshot's rubber band?
The potential energy stored in the slingshot's rubber band can be calculated by considering the mass of the pebble and the height it reaches.
To determine the potential energy stored in the slingshot's rubber band, we can use the formula for gravitational potential energy, which is given by the equation PE = mgh. In this case, the mass of the pebble is 13 grams, which is equivalent to 0.013 kilograms. The height it reaches is 25.0 meters.
By substituting these values into the formula, we can calculate the potential energy stored in the slingshot's rubber band. PE = (0.013 kg) x (9.8 m/s^2) x (25.0 m) = 3.185 J.
Therefore, the potential energy stored in the slingshot's rubber band is 3.185 Joules. This indicates the amount of energy that the rubber band possesses when stretched and ready to launch the pebble upward.
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Godric and Savos are a few meters apart, at one end of the football field. Peter is at the other end of the field. Godric and Savos starts moving towards Peter at a speed of 4m/s. From Savos point of view how is Godric moving?
Answer:
From Savos point of view, Gadros appear not to be moving
Explanation:
The given parameters are;
The distance between Godric and Savos = A few meters
The location of Godric and Savos = One end of the field
The location pf Peter = The other end pf the field
The speed with which Godric and Savos are moving towards Peter = 4 m/s
Let the positive x-direction be the direction in which Godric and Savos are moving
Therefore;
The speed and direction with which Godric is moving = The speed and direction with which Savos is moving = 4·i m/s
From Savos point of view, the relative speed with which Godric is moving = (The speed and direction in which Godric is moving) - (The speed and direction in which Savos is moving) = 4·i m/s - 4·i m/s = 0 m/s
Therefore, from Savos point of view, the relative speed with which Godric is moving = 0 m/s or Gadros appears stationary or not to moving.
What energy transformations take place from the outlet charger to the ringing phone?
Explain how the Law of Conservation of Energy applies to the energy
transformations that occur from the outlet charger to the ringing phone.
Answer:
Chemical energy transformations take place from the outlet charger to the ringing phone.
Explanation:
chemical energy
While charging the mobile electrical energy gets transformed into chemical energy. Most of the contemporary mobile phone batteries are lithium-ion batteries where the power is saved by the chemical transformations in the ionic structure of the battery. When the power gets into the mobile phone it is transformed and collected as chemical energy inside of the battery and when we utilize the mobile the earlier saved chemical energy is again transformed into electrical energy.
The energy transformation that takes place from the outlet charger to the
ringing phone is electrical energy from the outlet is converted to chemical
energy and back to electrical energy and sound energy when the phone is
being used and ringing.
The charger provides a source of electrical energy which gets converted to
chemical energy stored in the battery. During use, the chemical energy gets
converted to electrical energy to power the phone and to sound energy
when it rings with heat energy being dissipated also.
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Taylor kicks a soccer ball with a force of 5 N. The soccer ball moves away from Taylor with a force _____.
greater than 5 N
less than 5 N
equal to 5 N
Answer:
greater then five
Explanation:
Answer:
Equal to 5
Explanation:
Newton's third law. Hit the baseball or kick the soccer ball with a small amount of force. The ball will not travel very far. Then, hit or kick the ball with a large amount of force and watch what happens. The ball will have an equal and opposite reaction to the amount of force it his hit with.
7. A car is
speeding up
with a force of
a
120 N, heading
East. The
force of
friction acts
against the car
with a force of
80 N West.
What is the net
force?
Answer:Fricition
Explanation: It is fricition in the net force
A car is speeding up with a force of 120 mph and heading east. The force of friction acts against the car with a force of 80 N westward, and the net force acting on the car is 40 N eastward, which means the car is accelerating eastward with a force of 40 N.
What is the calculation of net force?To calculate the net force acting on the car, one needs to consider the direction and magnitude of the forces acting on it. A force of 120 N to the east is acting to accelerate the car in that direction, and a force of 80 N to the west is acting to oppose the motion of the car.
Net force = force of acceleration -force of friction.
Net force = 120 N east- 80 N west.
Net force = 40 N East
Hence, the net force acting on the car is 40 N eastward, which means the car is accelerating eastward with a force of 40 N.
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Consider the case in which the clay is launched along Path Y. The sphere of clay is launched with an initial velocity of v0 and collides with the rod at a distance of l from the pivot. The length of the rod is L. The rotational inertia of the rod about the joint is IR, and the mass of the clay is mc. The clay is considered a point mass. What is the angular speed f of the clay-rod system immediately after the collision
Answer:
w = \(\frac{m}{ml^2 + I R^2 }\) v l
Explanation:
Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved
initial instant. Before the crash
L₀ = m v l
Final moment. After the collision with the clay stuck to the rod
L_f = I_{total} w
angular momentum is conserved
L₀ = L_f
m v l = I_total w
w = \(\frac{m}{I_{total} }\) v l
the total moment of inertia is the sum of the moments of inertia of the two bodies
the moment of inertia of the rod is
I_rod = I R²
I_total = m l² + IR²
we substitute
w = \(\frac{m}{ml^2 + I R^2 }\) v l
The angular speed f of the clay-rod system immediately after the collision
\(w=\dfrac{m}{ml^2+IR^2}VI\)
What is angular speed?Angular speed is defined as the rate of change of angular displacement,Angular Speed (ω) is the scalar measure of rotation rate. In one complete rotation, angular distance travelled is 2π and time is time period (T)
Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved
initial instant. Before the crash
\(L_o=mvl\)
Final moment. After the collision with the clay stuck to the rod
\(L_o = L_f m v l = I_{total} w\)
\(w=\dfrac{m}{I_{total}} Vl\)
the total moment of inertia is the sum of the moments of inertia of the two bodies
the moment of inertia of the rod is
\(I_rod = I R^2 I_{total} = m l^2 + IR^2\)
we substitute
\(w=\dfrac{m}{ml^2+IR^2}VI\)
Hence the angular speed f of the clay-rod system immediately after the collision
\(w=\dfrac{m}{ml^2+IR^2}VI\)
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The paths of the alpha particles depend on the forces on them in the metal.
Describe the model of the atom which is used to explain the paths of alpha particles aimed at thin sheets of metal foil.
Answer:
During the experiment, alpha particles bombarded a thin piece of gold foil. The alpha particles were expected to pass easily through the gold foil. ... The discovery of the nucleus was a result of Rutherford's observation that a small percentage of the positively charged particles bombarding the metal's surface...
Explanation:
jayfeather friend me
Rutherford's model of atoms describes the atom as a tiny, dense particle which contains a positively charged nucleus with electrons which are negative charged moving in orbitals.
What is Rutherford's model?Rutherford's model of atoms described the atom as a tiny, dense, positively charged core particle which is called a nucleus, in which nearly all the mass of the atom is concentrated, around within the nucleus which the light, negative constituents, called electrons, circulate at some specific distance, much like the planets which are revolving around the Sun.
During the Rutherford's experiment, the alpha particles are bombarded on the thin piece of gold foil. The alpha particles were expected to pass easily through this gold foil. The discovery of the nucleus of atom was a result of the Rutherford's observation in which a small percentage of the positively charged particles that is protons bombarding on the metal's surface.
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7. A 1000-kg car comes to a stop without skidding. The car's brakes do 50,000 J of work
to stop the car. Which of the following was the car's velocity when the brakes were
initially applied?
Answer:
10 m/s
Explanation:
An object rotates describing a horizontal circumference when subjected to a centripetal force F. What centripetal force will act on the object if the radius of the circle is doubled and the kinetic energy of the object is halved? A) F/4 B) F/2 C) F D) 4F please explain this to me : (
Answer:
Option A: F/4
Explanation:
Centripetal force, \(F = \frac{mv^{2} }{r}\)
Where v = speed
r = radius
Since Kinetic Energy, \(E_{k} = 0.5 mv^{2}\)
Writing centripetal force in terms of kinetic energy, \(F = \frac{2 E_k}{r}\)
If the initial radius of the circle, r₁ =r
The doubled radius, r₂ = 2r
If the initial kinetic energy, \(KE_1 = E_{k}\)
The halved kinetic energy, \(KE_2 = 0.5E_{k}\)
Therefore, the new Centripetal force becomes:
\(F_{2} = \frac{2(0.5 E_k)}{2r} \\F_{2} = \frac{0.5 E_k}{r}\\F_{2} =\frac{1}{4} * \frac{2 E_k}{r}\\Since, F = \frac{2 E_k}{r} \\F_{2} =\frac{1}{4} * F\\F_{2} =\frac{F}{4}\)
Your friends sit in a sled in the snow. If you apply a force of 95N to them they have an acceleration of 0.8 m/s2. What is their mass
a heat engine exhausts 8200 j of heat while performing 2600 j of useful work.what is the efficiency of this engine?
The efficiency of a heat engine is defined as the ratio of useful work output to the heat input. The efficiency of this heat engine is approximately 0.3171 or 31.71%.
Efficiency = (\(\frac{Useful work }{Heat}\))
Given that the heat input is 8200 J and the useful work output is 2600 J, we can substitute these values into the efficiency formula:
Efficiency = \(\frac{2600}{8200}\)
Calculating this expression:
Efficiency = 0.3171
Therefore, the efficiency of this heat engine is approximately 0.3171 or 31.71%.
A heat engine is a device used in thermodynamics and engineering to transform heat into useable energy, notably mechanical energy, which can subsequently be used to do mechanical labour.
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The first major failure of the ptolemaic theory to predict the results of observations was?
Galileo’s telescopic discoveries of the moons of Jupiter are often mentioned. But they did not amount to proof that the Ptolemaic system was incorrect.
It's hard to tell you how big a shakeup this caused in astronomy at the time. Thanks to Galileo, we now knew that planets weren't perfect, ethereal lights in the sky. That things could orbit them, same as (most astronomers thought) things did around Earth, making Earth less special, and providing evidence that maybe that heliocentric theory wasn't that out there.
Basically, before Galileo, astronomers were looking at an unchanging, heavenly firmament, separate from Earth by its very heavenly nature.
After, they were studying planets - actual worlds like ours - and moons and the physical (as opposed to heavenly) reality of their place in the universe.
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find the volume of the solid obtained by rotating the region
To find the volume of the solid obtained by rotating the region, we will need some more information, such as the function or shape of the region, the axis of rotation, and the interval of rotation. The terms you should be familiar with are:
1. Volume: The measure of the amount of space occupied by a solid figure.
2. Solid: A three-dimensional geometric figure.
3. Rotation: Turning a shape around a fixed point or axis.
4. Region: An area enclosed by a curve or boundaries.
5. Axis of rotation: The line around which the region is rotated to form the solid.
Once you provide these details, I'd be happy to help you find the volume of the solid obtained by rotating the region.
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how much work is done on an electron by the electric field as the electron moves from the -12 v painteed circle to the painted circle that is at grounds potential
Work = (-1.6 × 10^-19 C) × (-12 V) = 1.92 × 10^-18 J
The work done on an electron by an electric field is given by the equation:
Work = Charge × Potential Difference
Potential difference, also known as voltage, is the difference in electric potential between two points in an electrical circuit. It is a measure of the work done per unit charge in moving a charge from one point to another.
In practical terms, potential difference is what drives the flow of electric current in a circuit. It is typically measured in volts (V) and is represented by the symbol "V". When there is a potential difference between two points in a circuit, charges will move from the higher potential (positive terminal) to the lower potential (negative terminal) in order to equalize the difference
Since the charge of an electron is -1.6 × 10^-19 C and the potential difference is (-12 V - 0 V) = -12 V, the work done on the electron is:
Work = (-1.6 × 10^-19 C) × (-12 V) = 1.92 × 10^-18 J
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PLS HELP ME ASAPPPP. 50 POINTSSS
What is the amount of energy needed to raise the temperature of a mercury in glass thermometer of mass
300g though 10 OC, given that the mass of the mercury is 60g?
Given that the specific heat capacity of mercury is130 J/kg K.
Answer:
1.8 kj
Explanation:
Explanation:
A substance's specific heat tells you how much heat is required to increase the mass of
1 g
of that substance by
1
∘
C
.
The equation that establishes a rel;ationship between heat absorbed and change in temperature looks like this
q
=
m
⋅
c
⋅
Δ
T
, where
q
- heat absorbed
m
- the mass of the sample
c
- the specific heat of the substance
Δ
T
- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample
You have all the information needed to find the amount of heat required to increase the temperature of your sample of mercury by that many degrees Celsius, so just rearange the above equation and solve for
q
q
=
250.0
g
⋅
0.14
J
g
∘
C
⋅
(
62
−
10
)
∘
C
=
1820 J
I'll leave the answer rounded to two sig figs and expressed in kilojoules
q
=
1.8 kJ
Answer Explanation:
A substance's specific heat tells you how much heat is required to increase the mass of
1 g
of that substance by
1
∘
C
.
The equation that establishes a rel;ationship between heat absorbed and change in temperature looks like this
q
=
m
⋅
c
⋅
Δ
T
, where
q
- heat absorbed
m
- the mass of the sample
c
- the specific heat of the substance
Δ
T
- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample
You have all the information needed to find the amount of heat required to increase the temperature of your sample of mercury by that many degrees Celsius, so just rearange the above equation and solve for
q
q
=
250.0
g
⋅
0.14
J
g
∘
C
⋅
(
62
−
10
)
∘
C
=
1820 J
I'll leave the answer rounded to two sig figs and expressed in kilojoules
q
=
1.8 kJ
Answer link
Answer:
1.8 kj
Explanation:
If you start with a sample containing 10^10 nuclei that have half-life 2.5 hours, what is the activity of the sample after 5 hours?
The activity of the sample after 5 hours is 2.5 * 10^9 dps or 2.5 * 10^9 Bq
The activity of a radioactive sample refers to the rate at which its nuclei decay, and it is typically measured in units of disintegrations per second (dps) or becquerels (Bq).
To determine the activity of the sample after 5 hours, we need to consider the concept of half-life. The half-life of a radioactive substance is the time it takes for half of the nuclei in a sample to decay.
Given that the half-life of the nuclei in the sample is 2.5 hours, we can calculate the number of half-lives that occur within the 5-hour period.
Number of half-lives = (Time elapsed) / (Half-life)
Number of half-lives = 5 hours / 2.5 hours = 2
This means that within the 5-hour period, two half-lives have occurred.
Since each half-life reduces the number of nuclei by half, after one half-life, the number of nuclei remaining is (1/2) * (10^10) = 5 * 10^9 nuclei.
After two half-lives, the number of nuclei remaining is (1/2) * (5 * 10^9) = 2.5 * 10^9 nuclei.
The activity of the sample is directly proportional to the number of remaining nuclei.
Therefore, After 5 hours, the sample has an activity of 2.5 * 109 dps or 2.5 * 109 Bq.
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