Addison works at a pet store. She worked less than 40 hours last week. Create an inequality that represents the number of hours n Addison worked last week

Answer:

She will type 650 words in 10 minutes

Step-by-step explanation:

390 divided by 6 is 65. Anita types 65 words per min. 65 times 10 is 650. Therefore she will type 650 words in 10 minutes.

Answer:

42 degrees

Step-by-step explanation:

The measure of the inscribed angle is half of the angle of the measure bc

1/2 * 84 = 42

Answer:

108 miles

Step-by-step explanation:

54 miles per hour and she traveled for 2 hours so:

54*2 = 108 miles per 2 hours

Answer:  assuming g(x) is the inverse of f(x)

domain of g(x) = range of f(x)

range of g(x) = domain of f(x)

Answer:

120

Step-by-step explanation:

5*4*3*2*1

Answer:

C. the number f books read and the size of someone's vocabulary

Step-by-step explanation:

causation is the action of causing something, thats the only one that makes sense lol

Answer:

2.09 is the 6% sales tax so the total will be 36.94

Step-by-step explanation:

Answer:

36.94100 US$ hope this helps

The number of ways the ribbons can be awarded in a race with "x" runners is x * (x-1).

The number of ways the ribbons can be awarded depends on the total number of runners participating in the 100-meter dash.

If there are "x" runners participating, the winner can be any one of the x runners, and the second-place runner can be any one of the remaining (x-1) runners.

Therefore, the number of ways the ribbons can be awarded is equal to the number of possible choices for the winner multiplied by the number of possible choices for the second-place runner.

Mathematically, this can be expressed as:

Number of Ways = x * (x-1)

For example, if there are 5 runners in the race, there are 5 ways to choose the winner. After selecting the winner, there are 4 remaining runners from which we can choose the second-place runner. So, in this case, the number of ways the ribbons can be awarded is:

Number of Ways = 5 * 4 = 20

In general, the number of ways the ribbons can be awarded in a race with "x" runners is x * (x-1).

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Answer: Total amount earned by Laney in 4hour=$138

Total amount earned by Maka in 4hours=$134

Difference =$4

Step-by-step explanation:

Since

Maka charges can be modeled by the equation F=30h+14,

where h =number of hours that Maka tutors

F = the total amount earned. Following same model

With 14 being the charge in dollar for travel expenses.

Laney charging $10 for travel expenses plus $32 per hour of tutoring can also be represented as

F= 32h +10

Such that total amount earned by

Maka in 4hours gives

F=30h+14

F=30x4 +14

F=120+14=$134

In the same vein the total amount earned by Laney in 4hours gives

F=32h+10

F= 32x4+10

F=128+10=$138

The difference in money earned by Laney and Maka = $138-$134= $4

The 95% confidence interval for the mean internet speed is approximately (34.986 Mbps, 37.414 Mbps).

To determine if the claim is supported by the data, we can perform a hypothesis test. We'll set up the following hypotheses:

Null hypothesis (H0): The mean speed of the internet connection is 35 Mbps.

Alternative hypothesis (H1): The mean speed of the internet connection is greater than 35 Mbps.

Since we have a sample mean and standard deviation, we can use a one-sample t-test. Assuming a significance level (α) of 0.05, we can calculate the t-value and compare it to the critical value from the t-distribution.

The t-value can be calculated using the formula: t = (sample mean - population mean) / (sample standard deviation / √(sample size))

t = (36.2 - 35) / (4.32 / √(30))

t ≈ 1.653

For a one-tailed test at a 95% confidence level, the critical value (t-critical) with (n-1) degrees of freedom is approximately 1.699. Since the calculated t-value is less than the critical value, we fail to reject the null hypothesis. Therefore, the data does not provide sufficient evidence to support the claim that the mean speed of your internet connection is more than 35 Mbps.

What is the margin of error for the estimate of the mean internet speed?

The margin of error can be calculated using the formula:

Margin of Error = t-critical ×(sample standard deviation / √(sample size))

Using the t-critical value from the previous question (1.699) and the sample standard deviation (4.32) and sample size (30) provided in the information:

Margin of Error = 1.699× (4.32 / √(30))

Margin of Error ≈ 1.214 Mbps

Therefore, the margin of error for the estimate of the mean internet speed is approximately 1.214 Mbps.

What is the 95% confidence interval for the mean internet speed?

To calculate the confidence interval, we use the formula:

Confidence Interval = sample mean ± (margin of error)

Using the sample mean (36.2) and the margin of error (1.214) calculated in the previous questions:

Confidence Interval = 36.2 ± 1.214

Confidence Interval ≈ (34.986, 37.414)

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Answer:

45 its easy brainliest

Step-by-step explanation:

jayfeather friend me

Answer:

45

Step-by-step explanation:

6x+9

6(6)+9

36+9

45

the answer is 45

Answer: B. Commutative Property

(～￣▽￣)～

a) If two points on a line are A(-5,7) and B(-2,1), the rise -6, the run is of 3, and then the slope is of -2.

b) If two points on a line are A(10,-3) and B(12,9), the rise 12, the run is of 2, and then the slope is of 6.

c) If two points on a line are A(4,6) and B(8,-8), the rise -14, the run is of 4, and then the slope is of -3.5.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

For which the parameters are given as follows:

As the slope represents the rate of change of the output relative to the input, it is calculated as the change in the output y divided by the change in the input x, that is, the rise divided by the run.

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The solution to the expression 2 1/2 + 3 1/5 x 5 5/8 is 223/2

fractions are represented as a numerical value, which defines a part of a whole. A fraction can be a portion or section of any quantity out of a whole, where the whole can be any number, a specific value, or a thing.

2 1/2 + 3 1/5 x 5 5/8 can be solved by converting all the mixed fraction to improper fraction

2 1/2 = 5/2

3 1/5 = 16/5

5 5/8 = 45/8

which reduces it to

5/2 + 45/8 x 16/5

using BODMAS we taking care of the multiplication section first

45/8 x 16/5 = 18

5/2 + 18

18 can be writen as a fraction which is 36/2

5/2 + 36/2 = 41/2

in conclusion the simplified form of the expression is 41/2

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Answer:

The answer to this question is x= 51/4

Answer: Figure B is 2x bigger on all sides

Explanation: You can see that each of the numbers times 2 would equal all of the numbers on B.

Answer:

here we can go for two solution

Answer:

1 1/12

Step-by-step explanation:

You take 2 3/4 and subtract it by 1 2/3

Make them into improper fractions 11/4 - 5/3

you multiply 11/4 by 3 and 5/3 by 4 to get a common denominator

you get 33/12 - 20/12 and get 13/12

then make it a mixed number

hope this helps :)

A doubling equation in exponential growth can be used to solve the question. The amount after 30 years will be $3911.22

The growth rate is governed by exponential equation. Doubling equation means to the time needed to make the initial amount double. If the number of years and doubling time given, then the doubling equation is,

 P = P₀\((2)^{t/d}\)

P is the final amount

P₀ is the initial amount

t is the time in years

d is the doubling time

P₀ = 790  t= 30  d= 13

P = 790 \((2)^{30/13}\)

  = 3911.21506157

So the amount after 30 years will be $3911.22

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Answer:the last one is right, because you cannot control when rain happens, or where at that matter.

Answer:

( \(\frac{1}{4}\), 8 )

Step-by-step explanation:

y = 8x + 6 → (1)

y = 32x → (2)

substitute y = 32x into (1)

32x = 8x + 6 ( subtract 8x from both sides )

24x = 6 ( divide both sides by 24 )

x = \(\frac{6}{24}\) = \(\frac{1}{4}\)

substitute this value into either of the 2 equations and solve for y

substituting into (2)

y = 32 × \(\frac{1}{4}\) = 8

solution is ( \(\frac{1}{4}\), 8 )

Answer:

Hello your handwriting is bad I don't understand

Answer:

(1,3)

Step-by-step explanation:

It is the intercept of the two lines

A systematic random sample is obtained by choosing a random starting point and then selecting every kth individual from a population to participate in the study. The number of random numbers that must be produced to recognize individuals who are part of the sample is determined by the following formula:n/k is the number of random numbers required to identify the sample population of size n drawn from a population of size N by systematic random sampling.

To provide an example, consider a population of size N= 1000 and a sample of size n= 50. Assume that we must use systematic random sampling with a k=20. The population should be numbered, and the first random number between 1 and 20 is selected. The kth person after the first random number is chosen. This process is repeated for the entire population, with every kth person included in the sample. The number of random numbers generated would be 1000/20= 50. Therefore, to obtain a sample of 50 individuals, we must generate 50 random numbers to recognize each individual who will be included in the sample.

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(a) The real discrete Fourier transform (DFT) is calculated for the given data set to analyze the helicopter's acoustic signature.

(b) To obtain the ck values and illustrate the relative size of each term in the Fourier series, we calculate the magnitude of each coefficient and plot their amplitudes on a bar graph against the corresponding frequency component, k.

To analyze the helicopter's acoustic signature, the real DFT is computed for the provided data set. The DFT transforms the time-domain measurements of acoustic pressure into the frequency domain, revealing the different frequencies present and their corresponding amplitudes. This analysis helps in understanding the spectral characteristics of the helicopter's acoustic signature and identifying prominent frequency components.

Using the Fourier series representation, the amplitudes (ck's) of the different frequency components in the Fourier series are determined. These amplitudes represent the relative sizes of each term in the series, indicating the contribution of each frequency component to the overall acoustic signature. By plotting the amplitudes on a bar graph, the relative strengths of different frequency components become visually apparent, enabling a clear comparison of their importance in characterizing the helicopter's acoustic signature.

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To find the union and intersection of the intervals I₁ = (-2, 2] and I₂ = [1, 5), let’s consider the overlapping values and the combined range.

The union of two intervals includes all the values that belong to either interval. Taking the union of I₁ and I₂, we have:

I₁ U I₂ = (-2, 2] U [1, 5)

To find the union, we combine the intervals while considering their overlapping points:

I₁ U I₂ = (-2, 2] U [1, 5)
= (-2, 2] U [1, 5)

So the union of the intervals I₁ and I₂ is (-2, 2] U [1, 5).

Now let’s find the intersection of the intervals I₁ and I₂, which includes the values that are common to both intervals:

I₁ ∩ I₂ = (-2, 2] ∩ [1, 5)

To find the intersection, we consider the overlapping range between the two intervals:

I₁ ∩ I₂ = [1, 2]

Therefore, the intersection of the intervals I₁ and I₂ is [1, 2].


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Divide sale price by (1 - percent of discount):

15.75 / (1- 0.15) =

15.75 / 0.85 = 18.53

Answer = $18.53

Answer:

18.53

Step-by-step explanation:

18.53*0.15≈2.7795

Rounded = 2.78

18.53-2.78=15.75

Jane can select 80 different types of dinner consisting of 3 different items from 5 different vegetarian items and 4 different meat items available.

For finding the various combination of dinners available which has atleast one vegetarian item we will apply combination formula with the given data i.e., \(^{n} C_{r} = \frac{n!}{(n-r)!.r!}\)

A combination is a way of selecting items from a collection where the order of selection does not matter.

We will have to apply the formula separately for vegetarian and meat items.

Combinations available

A. 1 vegetarian item and 2 meat items              

    \(^{5} C_{1} and ^{4} C_{2}\)                                 (In combination "and" means to multiply)                                                                                        

   = \(\frac{5!}{(5-1)!.1!} . \frac{4!}{(4-2)!.2!}\)

   = \(\frac{5!}{(4)!.1!} . \frac{4!}{(2)!.2!}\)

   = \(\frac{5.4.3.2.1}{(4.3.2.1).(1)}. \frac{4.3.2.1}{(2.1).(2.1)}\)

   = 5.3.2

   = 5.6

   = 30

B. 2 vegetarian items and 1 meat item

    \(^{5} C_{2} and ^{4} C_{1}\)

   = \(\frac{5!}{(5-2)!.2!} . \frac{4!}{(4-1)!.1!}\)

   = \(\frac{5!}{(3)!.2!} . \frac{4!}{(3)!.1!}\)

   = \(\frac{5.4.3.2.1}{(3.2.1).(2.1)}. \frac{4.3.2.1}{(3.2.1).(1)}\)

   = 5.2.4

   = 10.4

   = 40

C. 3 vegetarian items and no meat item

   = \(^{5} C_{3} and ^{4} C_{0}\)

   = \(\frac{5!}{(5-3)!.3!} . \frac{4!}{(4-0)!.0!}\)

   = \(\frac{5.4.3.2.1}{(2.1).(3.2.1)}. 1\)

   = 5.2

   = 10

Now, we will add all the different combination

Total combinations = 30+40+10

                                = 80 different type of dinners

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