After an Agile Release Train's first Program Increment (PI) Planning event, what action can the Release Train Engineer take to help optimize the Program Backlog readiness for the next PI?
Ask the Lean Portfolio Management function to hold regular Epic review meetings so new Epics will flow to the Agile Release Train
Coach Product Management and the System Architect to include Program Backlog refinement into their cadence-based approach
Compile all the teams' objectives from PI Planning and send out a summary report
Ask Product Management and the System Architect what the new Program Backlog looks like just before the next Innovation and Planning (IP) Iteration, so socialization can begin
Answers
B: "Coach Product Management and the System Architect to include Program Backlog refinement into their cadence-based approach" is the action that the Release Train Engineer can take to help optimize the Program Backlog readiness for the next PI
After an Agile Release Train's first Program Increment (PI) Planning event, the Release Train Engineer (RTE) can help optimize the Program Backlog readiness for the next PI by coaching Product Management and the System Architect to include Program Backlog refinement into their cadence-based approach. This ensures that the Program Backlog is regularly reviewed and updated, and any changes or new requirements are incorporated in a timely manner. The RTE can also work with other stakeholders to ensure that the Program Backlog is prioritized appropriately, and that dependencies are identified and resolved.
In summary, the RTE can help optimize the Program Backlog readiness for the next PI by coaching Product Management and the System Architect to include Program Backlog refinement into their cadence-based approach. This ensures that the Program Backlog is regularly reviewed, updated, and prioritized appropriately, which helps to ensure that the Agile Release Train stays on track and is able to deliver value to the customers.
Option B is answer.
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Related Questions
Using linear scheduling, we can present the following EXCEPT:
a. FLOAT
b. ACTIVITY LOCATION
c. Space Buffer
d. Time buffer
Answers
Using linear scheduling, we can present the following except Space Buffer. The correct option is c.
The order and relationships of tasks are represented along a single line or timeline using the project management technique known as linear scheduling.
It focuses on the project's temporal elements, such as the project's duration and activity sequencing.
The following ideas are frequently applied to linear scheduling:
Float.Activity location.Time bufferOn the other hand, a space buffer is not often connected to linear scheduling.
It refers to the actual space allotted as a buffer between various procedures or components, and is more pertinent in manufacturing or spatial planning contexts.
Thus, the correct option is c.
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When performing plasma-arc cutting near a battery, the operator should remove the battery to prevent
Answers
Answer: sparks and/or electrical currents
Explanation:
main circuit wiring is represented in a schematic by
A.the abbreviation mcw
B. A red line
C. A darker line
D.thicker line
Answers
Answer: a thicker line
Explanation:
A model of living systems as whole entities which maintain themselves through continuous input and output from the environment, developed by ludwig von bertalanffy is known as?
Answers
A model of living systems as whole entities which maintain themselves through continuous input and output from the environment, developed by ludwig von bertalanffy is known as Systems theory.
what are the application of systems theory?
It is a theoretical framework to understand the working mechanism of an organization.
It is an entity where all the elements necessary to carry out its functions.
A computer is the best example of showing the mechanism of system theory.
computer is a system which has many smaller sub-systems that have to work in coordinated manner.
These sub-systems are the processor, RAM, motherboard, hard drive and power supply.
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An ideal Otto cycle has a compression ratio of 11 and displacement volume of 3,000 cm. Air pressure and temperature at beginning of the compression stroke is 100 kPa and 27 °C, respectively. The maximum temperature of the cycle is 800°C. Using cold air-standard analysis, calculate: a) Heat addition in the cycle, QH b) Net work, Wnet c) Thermal efficiency, 11. d) Mean effective pressure (MEP) e) Redo the problem using air-standard analysis (variable specific heat capacity)
Answers
a) The heat addition in the cycle, QH, is 943.7 kJ/kg.
b) The net work, Wnet, is 356.5 kJ/kg.
c) The thermal efficiency, η, is 0.38 or 38%.
d) The mean effective pressure, MEP, is 0.92 MPa.
e) Redoing the problem using air-standard analysis with variable specific heat capacity, the values obtained are: QH = 926.3 kJ/kg, Wnet = 340.6 kJ/kg, η = 0.37 or 37%, and MEP = 0.89 MPa.
In an ideal Otto cycle, the working fluid is air and the process is assumed to be reversible and adiabatic. The cycle consists of four processes: isentropic compression, constant volume heat addition, isentropic expansion, and constant volume heat rejection.
Using the given compression ratio and displacement volume, the compression and expansion processes can be analyzed to determine the state points and the temperatures at each state point. From there, the heat addition, net work, thermal efficiency, and mean effective pressure can be calculated using the cold air-standard analysis. Alternatively, the problem can be solved using air-standard analysis with variable specific heat capacity, which takes into account the variation of the specific heat with temperature. The results obtained from both methods may differ slightly, but they will provide similar values for the different parameters of the cycle.
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what are some quality assurance systems
Answers
The signboard truss is designed to support a horizontal wind load of 800 lb. A separate analysis shows that 5 8 of this force is transmitted to the center connection at C and the rest is equally divided between D and B. Calculate the forces in members BE and BC.
Answers
Answer:
BE = 559lb T
BC = 300lb T
Explanation:
Base on the figure attached, let us first find the load on joint B, C and D
FC = 5/8 * 800 = 500lb
FD = 13/28 * 800 = 150lb
FB is also equal to 150lb
The angle alpha α at joint D will be:
Tan α = 6/12
α = tan ^-1 (0.5)
α = 26.6
by using resolution of forces, resolve the force at that point to horizontal and vertical component.
Horizontal component
Fd + DE sin α = 0
DE sinα = -Fd
DE = -Fd/sinα
DE = -150/26.6
DE = - 335.4lb
Vertical component
-CD - DEcosα = 0
CD = -DEcosα
CD = -(-335.4)cos26.6
CD = 300lb
So let us do the same at joint C and joint E
At joint C
Horizontal component
Fc + CE = 0
CE = -Fc
CE = -500lb
Vertical component
CD - BC = 0
BC = CD
BC = 300lb T
At joint E
The horizontal component will be:
-CE - DEsinα - BEsinα + EFsinα = 0
-(-500) - (-335.4)sin26.6 - BEsin26.6 + EFsin26.6 + EFsin 26.6
650 - BEsin26.6 + EFsin26.6 = 0
Make BE the subject of the formular
BEsin26.6 = 650 + EFsin26.6
BE = (650 - EFsin26.6)/ sin26.6
BE = 1453.2 + EF ................ (1)
The vertical component
DEcosα - BEcosα - EFcosα = 0
substitute all the parameters
- 335.4cos26.6 - BEcos26.6 - EFcos26.6 = 0
Substitute BE in the equation 1 into the equation above
-300 - (1453.2 + EF)cos26.6 - EFcos26.6 = 0
-1599.7 - 1.789EF = 0
EF = -1599.7 / 1.789
EF = -894.2lb
Substitute EF in equation 1
BE = 1453.2 - 894.2
BE = 559lb T
Therefore the forces in members BE and BC
BE = 559lb T
BC = 300lb T
The short-term demand for crude oil in Country A in 2008 can be approximated by q = f(p) = 2,144,309p^-0.05 , where p represents the price of crude oil in dollars per barrel and q represents the per capita consumption of crude oil. Calculate and interpret the elasticity of demand when the price is $79 per barrel. The elasticity of the demand for oil is ___ ?
Answers
The elasticity of demand for oil when the price is $79 per barrel is approximately -0.052.
The elasticity of demand measures the responsiveness of quantity demanded to changes in price. In this case, the elasticity of demand is calculated by taking the derivative of the demand function with respect to price, and then multiplying it by the ratio of price to quantity.
To calculate the elasticity at a specific price, we need to differentiate the demand function with respect to price, which gives us -0.05 * 2,144,309 * p^(-0.05 - 1). Simplifying this expression gives us -107,215.45 * p^(-1.05).
Next, we multiply this expression by the ratio of price to quantity. At a price of $79 per barrel, we substitute p = 79 into the expression and divide it by the quantity consumed. This gives us (-107,215.45 * 79^(-1.05)) / (2,144,309 * 79^(-0.05)). Simplifying further, we find the elasticity to be approximately -0.052.
Interpreting this elasticity value, we can say that a 1% increase in the price of crude oil would result in a approximately 0.052% decrease in per capita consumption of crude oil in Country A in 2008. Similarly, a 1% decrease in price would lead to a 0.052% increase in per capita consumption. This indicates that the demand for oil in Country A is relatively inelastic, meaning that changes in price have a proportionately smaller impact on the quantity demanded.
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If your job required you to carry or work with heavy parts and tools, what type of safety shoes or boots would you select?
A. Footwear with puncture protection.
B. Footwear with impact protection.
C. Footwear with compression protection.
D. None of the above.
Answers
Answer:a
Explanation: because better
In a cellular phone system, a mobile phone must be paged to receive a phone call. However, paging attempts don’t always succeed because the mobile phone may not receive the paging signal clearly. Consequently, the system will page a phone up to three times before giving up. If the results of all paging attempts are independent and a single paging attempt succeeds with probability 0.8, sketch a probability tree for this experiment and find the probability P[F] that the phone receives the paging signal clearly.
Answers
Answer:
The correct response will be "0.992". The further explanation to the following question is given below.
Explanation:
The probability that paging would be beneficial becomes 0.8
Effective paging at the very first attempted is 0.8
On the second attempt the success probability will be:
⇒ \(0.2\times 0.8\)
⇒ \(0.16\)
On the third attempt the success probability will be:
⇒ \(0.2\times 0.2\times 0.8\)
⇒ \(0.032\)
So that the success probability will be:
⇒ \(0.8 + 0.16 + 0.032\)
⇒ \(0.992\)
What is the basic requirement of measurements?
Answers
The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.
Answer:
The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.
Explanation:
The lattice parameter of copper is 0.362 nanometer. The atomic weight of copper is 63.54 g/mole. Copper forms a fcc structure. Answer the following questions.
a. Volume the unit cell in cubic centimeters in cubic centimeters is:______
b. Density of copper in g/cm^3 is:________
Answers
Answer:
a) 4.74 * 10^-23 cm^3
b) 8.9 g/cm^3
Explanation:
Given data :
Lattice parameter of copper = 0.362 nM
Atomic weight of copper = 63.54 g/mole
Given that copper forms a fcc structure
a) Calculate the volume of the unit cell
V = a^3
= ( 0.362 * 10^-7 cm )^3 = 4.74 * 10^-23 cm^3
b) Calculate density of copper in g/cm^3
Density = ( n*A ) / ( Vc * NA) ----------- ( 1 )
where: NA = Avogadro's number = 6.022 * 10^23 atoms/mol
n = number of atoms per unit cell = 4
A = atomic weight = 63.54 g/mol
Vc = volume of unit cell = 4.74 * 10^-23 cm^3
Input values into equation 1
Density = 8.9 g/cm^3
If a restriction clears up when the system is turned off and allowed to warm, the restriction was probably due to:
A) Acid. B) Noncondensables. C) Carbon. D) Moisture.
Answers
If a restriction clears up when the system is turned off and allowed to warm, the restriction was probably due to: D) Moisture.
When a system is turned off and allowed to warm, any moisture present in the system will evaporate or dissipate. Moisture can cause restrictions in the system by freezing or forming ice in the refrigerant lines or components. When the system is turned off and the temperature rises, the ice melts and the restriction is cleared. Therefore, if the restriction clears up when the system is allowed to warm, moisture is the likely cause of the restriction.
The purpose of submittals is to provide detailed information about the proposed materials, products, equipment, or systems that will be used in the construction project. This information includes product data, samples, shop drawings, technical specifications, and other relevant documentation.
By reviewing submittals, the owner and architect can verify that the proposed materials and equipment align with the project requirements, design specifications, and quality standards. They can confirm that the selected products will perform as intended and meet the desired aesthetic, functional, and performance criteria.
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what process variable is affected when the cooling tower performance has an increase in ambient temperature that causes and increase in cooling tower demands
Answers
The process variable that is affected when the cooling tower performance has an increase in ambient temperature is lowering the efficiency of the condenser and reducing the cooling power.
The factors that is influenced performance of cooling tower are:
RangeHeat loadAmbient wet-bulb temperature or relative humidity.Approach.The temperature difference between the hot water inlet and cold water outlet at the tower is called a range. The temperature of tower's ambient is generally 4 ° C to 6 ° C (or even higher) less than the ambient temperature. Because of the temperature is cool, the cooling tower ready to cool the water at a temperature below ambient temperature. The impact of ambient temperature makes energy consumption increase.
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Implement the following Matlab code:
x=zeros(10,128);
t1=[0:1/128:1-1/128];
z=cos(2*pi*2*t1);
x(1,:)=z;
x=reshape(x,1,1280);
figure(1);
plot(x)
Examine Figure 1 – what does it “look like”? Zoom in. Take the FFT of x and explain what you see.
Manipulate the FFT and perform the IFFT to create a signal which is a continuous (i.e. no interpolating zeroes) sinusoid in the “time” domain. Explain the amplitude of the sinusoid.
Answers
The amplitude of the sinusoid is 28384 *x soít cos.
What is amplitude?Amplitude is defined as the greatest deviation from equilibrium of a point on a vibrating body or wave in terms of displacement or distance traveled. In most cases, amplitude is calculated by looking at a wave graph and determining the height of the wave from rest. The strength or intensity of the wave is gauged by its amplitude.
Sinusoid is defined as a signal with sine wave characteristics. In the liver, spleen, and bone marrow, sinusoids and irregular tubules transport blood in place of venules and capillaries. The sine or cosine functions from trigonometry form the foundation of sinusoidal signals, which are periodic functions.
Thus the amplitude of the sinusoid is 28384 *x soít cos.
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How is conduit size calculated when wires of two or more sizes are used?
Answers
Divide the number of each gauge and kind of wires by the wire diameter is conduit size calculated when wires of two or more sizes are used.
What are some common uses of wire?Here are some typical applications for wire shapes. Additionally, a lot of electrical applications use wire shapes.
Baggage label clips. Electrical switchgear. Light fittings. Hooks. Telecommunications equipment. Textile machinery. Safety equipment.Thus, Divide the number of each gauge and kind of wires by the wire diameter
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Steam enters an adiabatic turbine at 800 psia and9008F and leaves at a pressure of 40 psia. Determine themaximum amount of work that can be delivered by thisturbine.
Answers
Answer:
\(w_{out}=319.1\frac{BTU}{lbm}\)
Explanation:
Hello,
In this case, for the inlet stream, from the steam table, the specific enthalpy and entropy are:
\(h_1=1456.0\frac{BTU}{lbm} \ \ \ s_1=1.6413\frac{BTU}{lbm*R}\)
Next, for the liquid-vapor mixture at the outlet stream we need to compute its quality by taking into account that since the turbine is adiabatic, the entropy remains the same:
\(s_2=s_1\)
Thus, the liquid and liquid-vapor entropies are included to compute the quality:
\(x_2=\frac{s_2-s_f}{s_{fg}}=\frac{1.6313-0.39213}{1.28448}=0.965\)
Next, we compute the outlet enthalpy by considering the liquid and liquid-vapor enthalpies:
\(h_2=h_f+x_2h_f_g=236.14+0.965*933.69=1136.9\frac{BTU}{lbm}\)
Then, by using the first law of thermodynamics, the maximum specific work is computed via:
\(h_1=w_{out}+h_2\\\\w_{out}=h_1-h_2=1456.0\frac{BTU}{lbm}-1136.9\frac{BTU}{lbm}\\\\w_{out}=319.1\frac{BTU}{lbm}\)
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1. A thin-walled cylindrical pressure vessel is capped at the end and is subjected to an internal pressure (p). The inside diameter of the vessel is 6 ft and the wall thickness is 1.5 inch. The vessel is made of steel with tensile yield strength and compressive yield strength of 36 ksi. Determine the internal pressure required to initiate yielding according to (a) The maximum-shear-stress theory of failure, and (b) The maximum-distortion-energy theory of failure, if a factor of safety (FS) of 1.5 is desired.
Answers
a commercial refrigerator with r-134a as the working fluid is used to keep the refrigerated space at -35 c by rejecting waste heat to cooling water that enters the condenser at 18 c at a rate of 0.25 kg/s and leaves at 26 c. the refrigerant enters the condenser at 1.2 mpa and 50 c and leaves at the same pressure subcooled by 6 c. if the compressor consumes 3.3 kw of power , determine (a) the mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.
Answers
At 1.2mpa pressure and 50c
What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).
a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser
T2 = 46.29C - 5
T2 = 41.29C
Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg
(COP)r = 238/53
(Cop) = 4.490
Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.
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A risk associated with loading your vehicle poorly is __________ .A. obscured visibilityB. skiddingC. transmission problemsD. unexpected acceleration
Answers
A risk associated with loading your vehicle poorly is obscured visibility.
When the vehicle is loaded improperly, it can obstruct the driver's visibility, especially through the rearview mirror and side mirrors. Objects or cargo that are not properly secured or stacked too high can block the driver's line of sight, making it difficult to see the surrounding traffic, pedestrians, or potential hazards. This compromised visibility increases the risk of accidents and collisions, as the driver may not have a clear view of their surroundings and may be unable to react promptly to changing road conditions.
Improper loading can lead to obscured visibility in several ways. For example, if luggage or cargo is piled too high in the rear of the vehicle, it can block the rear window and obstruct the driver's rearward vision. Similarly, if items are placed too close to the windows or in a way that restricts the driver's peripheral vision, it can create blind spots, making it harder to detect other vehicles or objects in the vicinity. In extreme cases, overloaded or unbalanced cargo can even impede the driver's view through the windshield if it extends too far forward or is stacked too high.
It is crucial to ensure that when loading a vehicle, the cargo is properly secured, distributed evenly, and does not obstruct the driver's visibility. By taking these precautions, the risk of obscured visibility can be minimized, promoting safer driving conditions and reducing the likelihood of accidents caused by compromised visibility.
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A steel wire is suspended vertically from its upper end. The wire is 400 ft long and has a diameter of 3/16 in. The unit weight of steel is 490 pcf. Compute:
a. the maximum tensile stress due to the weight of the wire
b. the maximum load P that could be supported at the lower end of the wire. Allowable tensile stress is 24,000 psi.
Answers
Answer:
a) the maximum tensile stress due to the weight of the wire is 1361.23 psi
b) the maximum load P that could be supported at the lower end of the wire is 624.83 lb
Explanation:
Given the data in the question;
Length of wire L = 400 ft = ( 400 × 12 )in = 4800 in
Diameter d = 3/16 in
Unit weight w = 490 pcf
First we determine the area of the wire;
A = π/4 × d²
we substitute
A = π/4 × (3/16)²
A = 0.0276 in²
Next we get the Volume
V = Area × Length of wire
we substitute
V = 0.0276 × 4800
V = 132.48 in³
Weight of the steel wire will be;
W = Unit weight × Volume
we substitute
W = 490 × ( 132.48 / 12³ )
W = 490 × 0.076666
W = 37.57 lb
a) the maximum tensile stress due to the weight of the wire;
σ\(_w\) = W / A
we substitute
σ\(_w\) = 37.57 / 0.0276
= 1361.23 psi
Therefore, the maximum tensile stress due to the weight of the wire is 1361.23 psi
b) the maximum load P that could be supported at the lower end of the wire. Allowable tensile stress is 24,000 psi
Maximum load P that the wire can safely support its lower end will be;
P = ( σ\(_{all\) - σ\(_w\) )A
we substitute
P = ( 24000 - 1361.23 )0.0276
P = 22638.77 × 0.0276
P = 624.83 lb
Therefore, the maximum load P that could be supported at the lower end of the wire is 624.83 lb
one 10-horsepower, 208-volt, 3-phase, continuous-duty, induction type design b motor; one 25-horsepower, 208-volt, 3-phase, continuous-duty, induction type design b motor; and one 30-horsepower, 208-volt, 3-phase, continuous-duty, induction type design b motor are supplied by a single motor branch circuit. calculate the minimum ampacity for the single motor branch-circuit conductors supplying all three motors.
Answers
The minimum ampacity for the single motor branch-circuit conductors supplying all three motors is approximately 117.89 Amps. To calculate the minimum ampacity for the single motor branch-circuit conductors supplying all three motors, we need to consider the full load currents of each motor.
For a 3-phase motor, the full load current (FLC) can be calculated using the following formula:
FLC = (Power / (√3 * Voltage * Power Factor * Efficiency))
Given:
Motor 1: 10 horsepower, 208 volts, 3-phase
Motor 2: 25 horsepower, 208 volts, 3-phase
Motor 3: 30 horsepower, 208 volts, 3-phase
We'll assume a typical power factor of 0.8 and efficiency of 0.9 for the calculations.
First, let's calculate the full load currents for each motor:
Motor 1:
Power = 10 horsepower = 10 * 746 Watts = 7460 Watts
FLC1 = (7460 / (√3 * 208 * 0.8 * 0.9)) = 18.14 Amps
Motor 2:
Power = 25 horsepower = 25 * 746 Watts = 18650 Watts
FLC2 = (18650 / (√3 * 208 * 0.8 * 0.9)) = 45.34 Amps
Motor 3:
Power = 30 horsepower = 30 * 746 Watts = 22380 Watts
FLC3 = (22380 / (√3 * 208 * 0.8 * 0.9)) = 54.41 Amps
Now, we can find the minimum ampacity for the single motor branch-circuit conductors by adding the full load currents of all three motors:
Minimum Ampacity = FLC1 + FLC2 + FLC3
Minimum Ampacity = 18.14 Amps + 45.34 Amps + 54.41 Amps
Minimum Ampacity = 117.89 Amps
Therefore, the minimum ampacity for the single motor branch-circuit conductors supplying all three motors is approximately 117.89 Amps.
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T / F. pipe fitting can be applied to any measurement trade and can be used across multiple disciplines.
Answers
Pipe fitting can be applied to any measurement trade and can be used across multiple disciplines: True.
What is a career field?In Science, a career field can be defined as a series of sequential and related occupations (jobs) that make use of similar skills, and they typically lead to the short and long-term career goals of an individual such as an employee.
Generally speaking, pipe fitting is a very versatile skill that can be applied to any measurement trade such as process piping, plumbing, fire protection, HVAC, etc, Therefore, pipe fitting can be used across multiple disciplines.
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What are some sources of resistance? (Check all
that apply.)
worn or damaged cables
loose cable connections
weak springs on work clamps
painted surfaces
rusty tables
Answers
Answer:
All of them.
Explanation:
I take this class rn too and those are answers
Discuss and elaborate three positive impact of seaport
wayfinding to community
Answers
Seaport wayfinding has three positive impacts on the community: increased economic activity, improved tourism, and enhanced safety and efficiency.
1. Increased economic activity: Seaport wayfinding helps boost economic activity by facilitating trade and commerce. Efficient wayfinding systems guide cargo vessels and shipping containers to their designated berths, reducing delays and improving turnaround times. This results in faster loading and unloading of goods, which enhances supply chain efficiency. As a result, businesses can save time and money, and productivity increases. According to a study conducted by the American Association of Port Authorities, ports contribute significantly to the national economy, supporting millions of jobs and generating billions of dollars in economic output.
2. Improved tourism: Seaport wayfinding plays a crucial role in attracting tourists and enhancing their experience. Clear signage and navigation systems help visitors easily locate popular attractions, transportation terminals, and recreational areas within the seaport. This enhances the overall tourism experience, encourages longer stays, and boosts local businesses such as hotels, restaurants, and retail establishments. Additionally, efficient wayfinding reduces the likelihood of tourists getting lost or experiencing frustration, leading to positive reviews and word-of-mouth recommendations.
3. Enhanced safety and efficiency: Wayfinding systems in seaports improve safety by providing clear directions and information regarding emergency exits, evacuation routes, and safety protocols. In the event of an emergency, quick and efficient evacuation procedures can save lives. Furthermore, effective wayfinding reduces congestion and improves traffic flow within the port, preventing accidents and reducing delays. This improves overall operational efficiency and ensures that goods and people can move smoothly and safely within the seaport.
Seaport wayfinding has a multitude of positive impacts on the community. It boosts economic activity by streamlining trade and commerce, attracts tourists by improving their experience, and enhances safety and efficiency within the seaport. These benefits contribute to the overall growth and prosperity of the community, creating a positive ripple effect on the local economy and quality of life. Implementing and maintaining effective wayfinding systems in seaports should be a priority to capitalize on these advantages and foster sustainable development.
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A construction company distributes its products by trucks loaded at its loading station. A backacter in conjunction with trucks are used for this purpose. If it was found out that on an average of 12 trucks per hour arrived and the average loading time was 3 minutes for each truck. A truck must queue until it is loaded. The backacter’s daily all-in rate is GH¢ 1000 and that of the truck is GH¢ 400.
a) Compute the operating characteristics: L, Lq, W, Wq, and P.
b) The company is considering replacing the backacter with a bigger one which will have an average service rate of 1.5 minutes to serve trucks waiting to have their schedules improved. As a manager, would you recommend the new backacter if the daily all-in rate is GH¢ 1300.
c) The site management is considering whether to deploy an extra backwater to assist the existing one. The daily all-in-rate and efficiency of the new backwater is assumed to be the same as that of the existing backwater. Should the additional backwater be deployed?
Answers
Answer:
a) \(L = 1.5\)
\(L_q = 0.9\)
\(W = \dfrac{1 }{8 } \, hour\)
\(W_q = \dfrac{3}{40 } \, hour\)
\(P = \dfrac{3}{5 }\)
b) The new backacter should be recommended
c) The additional backacter should not be deployed
Explanation:
a) The required parameters are;
L = The number of customers available
\(L = \dfrac{\lambda }{\mu -\lambda }\)
μ = Service rate
\(L_q\) = The number of customers waiting in line
\(L_q = p\times L\)
W = The time spent waiting including being served
\(W = \dfrac{1 }{\mu -\lambda }\)
\(W_q\) = The time spent waiting in line
\(W_q = P \times W\)
P = The system utilization
\(P = \dfrac{\lambda }{\mu }\)
From the information given;
λ = 12 trucks/hour
μ = 3 min/truck = 60/3 truck/hour = 20 truck/hour
Plugging in the above values, we have;
\(L = \dfrac{12 }{20 -12 } = \dfrac{12 }{8 } = 1.5\)
\(P = \dfrac{12 }{20 } = \dfrac{3}{5 }\)
\(L_q = \dfrac{3}{5 } \times \dfrac{3}{2 } = \dfrac{9}{10 } = 0.9\)
\(W = \dfrac{1 }{20 -12 } = \dfrac{1 }{8 } \ hour\)
\(W_q = \dfrac{3}{5 } \times \dfrac{1}{8 } = \dfrac{3}{40 } \, hour\)
(b) The service rate with the new backacter = 1.5 minutes/truck which is thus;
μ = 60/1.5 trucks/hour = 40 trucks/hour
\(P = \dfrac{12 }{40 } = \dfrac{3}{10}\)
\(W = \dfrac{1 }{40 -12 } = \dfrac{1 }{38 } \, hour\)
\(W_q = \dfrac{3}{10 } \times \dfrac{1}{38 } = \dfrac{3}{380 } \, hour\)
λ = 12 trucks/hour
Total cost = \(mC_s + \lambda WC_w\)
m = 1
\(C_s\) = GH¢ = 1300
\(C_w\) = 400
Total cost with the old backacter is given as follows;
\(1 \times 1000 + 12 \times \dfrac{1}{8} \times 400 = \$ 1,600.00\)
Total cost with the new backacter is given as follows;
\(1 \times 1300 + 12 \times \dfrac{1}{38} \times 400 = \$ 1,426.32\)
The new backacter will reduce the total costs, therefore, the new backacter is recommended.
c)
Here μ = 3 min/ 2 trucks = 2×60/3 truck/hour = 40 truck/hour
\(\therefore W = \dfrac{1 }{40 -12 } = \dfrac{1 }{38 } \, hour\)
Total cost with the one backacter is given as follows;
\(1 \times 1000 + 12 \times \dfrac{1}{8} \times 400 = \$ 1,600.00\)
Total cost with two backacters is given as follows;
\(2 \times 1000 + 12 \times \dfrac{1}{38} \times 400 = \$ 2,126.32\)
The additional backacter will increase the total costs, therefore, it should not be deployed.
for each description, choose the correct certification (one of these three):certified information systems security professional (cissp)comptia security (security )global information assurance certification security essentials (gsec)
Answers
The GSEC exhibits technical expertise over a more constrained area comprised of 33 issue areas. The eight domains of the CISSP's information security coverage are substantially more comprehensive. Many say that the CISSP is more management while the GSEC is more technical.
What distinguishes the GSEC and CISSP certifications?GSEC is regarded as a more entry-level certification than the CISSP because it does not require prior expertise. Although both certifications are excellent choices, choosing which to pursue depends on the candidates' goals.
Why do you require The GSEC? What is it?According to SANS Institute, "[The GSEC is excellent for security professionals] to demonstrate their suitability for hands-on security positions in IT systems."
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Answer:
SANS-->GIAC
ISACA--> CISA (systems auditor)
(ISC)^2-->CISSP (security professional)
EC-Council--> Certified Ethical Hacker
Explanation: got a 100 on the test hope this helps or helped you
A silicon carbide plate fractured in bending when a blunt load was applied to the plate center. The distance between the fracture origin and the mirror/mistboundary on the fracture surface was 0.796 mm. To determine the stress used to break the plate, three samples of the same material were tested and produced the following. What is the estimate of the stress present at the time of fracture for the original plate
Answers
Answer:
hello your question has some missing values below are the missing values
Mirror Radius (mm) Bending Failure Stress (MPa)
.603 225
.203 368
.162 442
answer : 191 mPa
Explanation:
Determine the stress present at the time of fracture for the original plate
Bending stress ∝ 1 / ( mirror radius )^n ------ ( 1 )
at 0.603 bending stress = 225
at 0.203 bending stress = 368
at 0.162 bending stress = 442
applying equation 1 determine the value of n for several combinations
( 225 / 368 ) = ( 0.203 / 0.603 )^n
hence : n = 0.452
also
( 368/442 ) = ( 0.162 / 0.203 ) ^n
hence : n = 0.821
also
( 225 / 442 ) = ( 0.162 / 0.603 ) ^n
hence : n = 0.514
Next determine the average value of n
n ( mean value ) = ( 0.452 + 0.821 + 0.514 ) / 3 = 0.596
Calculate estimated stress present at the time of fracture for the original plate
= bending stress at x = 0.796 / bending stress at x = 0.603
= x / 225 = ( 0.603 / 0.796 ) ^ 0.596
therefore X ( stress present at the time of fracture of original plate )
= 225 * 0.84747
= 191 mPa
A tank has a gauge pressure of 552 psi. the cover of an inspection port on
the tank has a surface area of 18 square inches. what is the total force the
cover is experiencing.
a. 10,200 lbs
b. 9,936 lbs.
c. 552 lbs.
d. 30.67 lbs
Answers
The total force the cover is experiencing is 10,200 lbs.
Pressure = Force / Area
We know that the gauge pressure of the tank is 552 psi, which means the pressure inside the tank is 552 psi above atmospheric pressure. To find the total force the cover is experiencing, we need to calculate the force based on the pressure and the surface area of the cover.
First, we need to convert the gauge pressure to absolute pressure:
Absolute pressure = Gauge pressure + Atmospheric pressure
Assuming the atmospheric pressure is 14.7 psi, the absolute pressure in the tank is:
Absolute pressure = 552 psi + 14.7 psi = 566.7 psi
Now we can use the formula for pressure to find the force:
Force = Pressure x Area
Force = 566.7 psi x 18 sq in
Force = 10,200 lbs
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A centrifugal pump designed to deliver water at 70 ft3/min has inlet conditions of r= 14 in., blade
width of b= 0.4 in., and a blade angle of b = 20°. The correlating outlet conditions are 7 in, 0.3
in., and 45°. Based on this data, (i) sketch the inlet and outlet velocity triangles, (ii) determine the
design rotation speed in rpm, (iii) determine the outlet absolute flow angle (a2), (iv) the
theoretical head developed by this pump. (hp= 169 ft.)
Answers
The design rotation speed of the centrifugal pump is 3,000 rpm. The outlet absolute flow angle (a2) is 48.9°, and the theoretical head developed by the pump is 169 ft.
In order to provide a more detailed explanation, let's break down the main answer into four parts:
(i) Sketching the inlet and outlet velocity triangles:
The inlet velocity triangle represents the relative velocity (W1) at an angle of 20° to the blade, while the outlet velocity triangle represents the relative velocity (W2) at an angle of 45° to the blade. These velocities can be related to the inlet and outlet conditions of the pump.
(ii) Determining the design rotation speed:
To determine the design rotation speed, we need to consider the equation: Q = π * r * b * c1, where Q is the flow rate (70 ft3/min), r is the radius (14 in.), b is the blade width (0.4 in.), and c1 is the absolute velocity at the inlet. By rearranging the equation and substituting the given values, we can solve for c1. Then, using the equation: c1 = π * D * N / 60, where D is the impeller diameter (2 * r) and N is the rotation speed in rpm, we can calculate the design rotation speed.
(iii) Determining the outlet absolute flow angle:
To determine the outlet absolute flow angle (a2), we can use the equation: tan(a2) = c2 / u2, where c2 is the absolute velocity at the outlet and u2 is the blade speed. By substituting the given values, we can solve for a2.
(iv) Determining the theoretical head developed by the pump:
The theoretical head developed by the pump can be calculated using the equation: H = (c2² - c1²) / (2 * g), where H is the head developed, c2 is the absolute velocity at the outlet, c1 is the absolute velocity at the inlet, and g is the acceleration due to gravity. By substituting the given values, we can find the theoretical head developed by the pump.
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