Alan hits a hockey puck of mass 0.3kg across a hockey rink with a speed of 23m/s to the south

Answer:

Explanation:

Isaac Newton argued that the geometric nature of reflection and refraction of light could only be explained if light were made of particles, referred to as corpuscles, because waves do not tend to travel in straight lines.

Answer:(:

Explanation:

Ignoring air resistance, both will hit at the same time.

1.06 is the maximum refractive index that the liquid may have for the light to be totally reflected.

Only when a light source passes from a denser to a rarer medium can it completely reflect.

When the angle of incidence surpasses a specific critical value, specular reflection occurs in the more highly refractive of the two mediums at their interface, and this reflection is known as total reflection.

sin \(i_{c}\) = μ\(_{r}\) / μ\(_{d\)

From the diagram

Angle of incidence = 60°

sin60°  ≥ sin\(i_{c}\) = μ\(_{r}\)/μ\(_{d}\)

μ\(_{r}\) ≤ μ\(_{d}\) sin60°

μ\(_{r}\) ≤ √1.5 × √3/2

   = 1.06

Hence, the maximum index that the liquid may have for the light to be totally reflected is 1.06

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Given the data from the question, the total output of non-useful energy from the heat engine is 150 J

A heat engine is a device / equipment that can convert or transfer thermal energy into useful-work. Some examples of heat engines include

From the question given above, the following data were obtained:

Output (non-useful) = Input – Output (useful)

Output (non-useful) = 300 – 150

Output (non-useful) = 150 J

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Answer:

0.67m/s due east

Explanation:

Given parameters:

Displacement of the man  = 8m east

Time taken  = 12s

Unknown:

Velocity of the man  = ?

Solution:

The velocity of a body is the rate of displacement per time;

         Velocity  = \(\frac{Displacement}{time}\)  

       Velocity  = \(\frac{8}{12}\)   = 0.67m/s due east

Answer:

When an object is thrown, the thrower pushes the object. This causes the object to move in a  

Explanation:

Answer:

3980.89 ohms

Explanation:

The capacitive reactance is expressed as;

\(X_c = \frac{1}{2 \pi fC}\)

f is the frequency

C is the capacitance of the capacitor

Given

f = 60H

C = C1+C2 (parallel connection)

C = 15μF + 25μF

C = 40μF

C = \(40 * 10^{-6}F\)

Substitute into the formula:

\(X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c = \frac{1}{0.0002512}\\X_c = 3,980.89\)

Hence the  total capacitive reactance is 3980.89 ohms

Answer:

a has a faster period

Explanation:

Period only depends on the length, irrelevant to the mass.

a has a shorter length, so has a small period, or faster.

Answer:

If you know the current and voltage across the whole circuit, you can find total resistance using Ohm's Law: R = V / I.

Explanation:

Answer:

A. the motion of an object along a curved path

Explanation:

Solution,

We know that,

Hence,the mass of the body is 2.4 kg.

Explanation:

Answer:

12g/cm³

Explanation:

Given parameters:

Mass of the metal  = 1200g

Volume of water in the measuring cylinder  = 150cm³

Volume of the metal  = 100cm³

Unknown:

Density of the metal  = ?

Solution:

Density is the mass per unit volume of a substance;

  Density  = \(\frac{mass}{volume}\)

Now insert the parameters and solve;

    Density  = \(\frac{1200}{100}\)   = 12g/cm³

Answer:

Two cars of equal weight and braking ability are travelling along the same road but combined with other factors it could mean the difference between life.

Answer:

clear out the junk, and plant some stuff

Explanation:

clear out all of the nasties, unless it is biodegradable, or you could get some mushrooms to break everything down, then you can go and plant some stuff or do whatever. You could turn it into a playground, park, whatever.

(a) Calculate the displacement r :

r = (8.5 i + 13 j + 8.2 k) m - (1.5 i + 1.75 j + 1.2 k) m

r = (7 i + 11.25 j + 7 k) m

The work W done by F in the direction of this displacement is

W = F • r = (2 i + 4 j + 6 k) N • (7 i + 11.25 j + 7 k) m

W = (2×7 + 4×11.25 + 6×7) Nm = 101 J

(b) The average power P of the machine is then

P = W / ∆t = (101 J) / (12 s)

P = 101/12 J/s ≈ 8.42 W

The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.

First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:

ΣFy = R − 7 kN − 3 kN

ΣFy = 0

This gives:

R = 10kN

Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:

ΣFx = L

ΣFx = 0

This indicates that there is no horizontal force acting on the structure.

Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

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Answer:

The Correct Answer Is b.

The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.

Hooke's law states that the force applied to an elastic material is directly proportional to its extension, provided its elastic limit is not exceeded.

To calculate the amount of work done by Hooke's law, first, we need to find the force constant of the spring.

Formula:

Where:

make k the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Finally, To find the work done in stretching the spring from 50 cm to 80 cm, we use the formula below.

Where:

Also, From the question,

Given:

Substitute these values into equation 3

Hence, The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.

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ANSWER

25 N

EXPLANATION

Given:

• The spring constant, k = 75 N/m

• The distance the spring is stretched, x = 0.333 m

Find:

• The ,weight, that hangs from the spring, Fg

If we draw a free-body diagram for this situation, we can see that the forces acting on the mass hanging from the spring are the spring force and its weight,

If the weight hangs motionless, it means that it is in equilibrium and the two forces are equal and opposite,

So the weight is equal to the spring force,

Hence, the weight is 25 N.

To find the kinetic energy at position B, we need to know the height or the velocity at position B. Without this information, we cannot calculate the exact value of the kinetic energy.

To determine the kinetic energy of the ball at position B, we need to consider the m conservation of Mechanical energy. Since the ball is released from position A, we can assume that there is no initial kinetic energy (velocity is zero), and the total mechanical energy at position A is equal to the potential energy.

The potential energy at position A can be calculated using the formula:

Potential energy at A = mass * gravitational acceleration * height

Potential energy at A = 20 kg * 9.8 m/s² * height

Now, at position B, all the potential energy is converted into kinetic energy. The kinetic energy at position B is given by the formula:

Kinetic energy at B = 1/2 * mass * velocity²

Since the ball is released from rest, the velocity at position B can be determined using the conservation of mechanical energy:

Potential energy at A = Kinetic energy at B

20 kg * 9.8 m/s² * height = 1/2 * 20 kg * velocity²

Simplifying the equation, we get:

9.8 m/s² * height = 1/2 * velocity²

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Answer:

The answer should be True

Explanation:

Answer:

False

Explanation:

Took the test and got it right

In order to find the magnitude of the vector sum, proceed as follow:

First, take into account that the vertical and horizontal components of A are (by considering each grid square is 9.00N):

Ax = 3*9.00N = 27.00N

Ay = 4*9.00N = 36.00N

Now, consider that B vector only has a vertical component:

By = -4*9.00N = -36.00N

and the C vector only has a horizontal component:

Cx = -2*9.00N = -18.00N

By and Cx are negative because these component are in the negative part of the y and x axis respectively.

Now, simplify all vertical and horizontal components. It determines the x and y components of the sum vector S:

Sx = Ax+Cx = 27.00N - 18.00N = 9.00N

Sy = Ay+By = 36.00N - 36.00N = 0.00N

Finally, the magnitude of the sum vector is:

The magnitude is 9.00N

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

We can use the kinematic equation for constant acceleration to solve this problem .The mass of the bin is 40 kg.

Kinematics is the study of how points, objects, and groups of objects move without considering the factors that generate those motions. The part of classical mechanics known as kinematics addresses the motion of points, objects, and systems made up of collections of items.

\(x = 1/2 * a * t^2 + v0 * t\)

\(a = 2(x - v0 * t) / t^2\)

In this case, x = 100 m, t = 10 s, v0 = 0, and the net force acting on the bin is:

F_net = F_applied - F_friction

F_net = 0

Therefore, we can solve for the mass of the bin:

F_applied - F_friction = ma

100 N - 20 N = m * a

Simplifying, we get:

80 N = m * a

\(a = 2(x - v0 * t) / t^2\)

\(= 2(100 m - 0) / (10 s)^2\)

\(= 2 m/s^2\)

Substituting this value into the previous equation, we get:

\(80 N = m * 2 m/s^2\)

Simplifying, we get:

m = 40 kg

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In an electrical circuit, a capacitor is a component that is used to hold charges.

A capacitor operates under the principle that when an earthed conductor is moved close to a conductor, its capacitance increases noticeably. As a result, a capacitor contains two plates with equal and opposing charges that are spaced apart.

Two metal plates, a substance known as a dielectric, and other components make up a capacitor.

The dielectric is positioned between the parallel metal plates, which are positioned very near to one another, to prevent them from touching.

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The kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

The total energy of the system is conserved. The initial energy of the system is the electrostatic potential energy, which is given by:

U = k × (Q₁ × Q₂) / r

where:

U = potential energy in joules

k = Coulomb's constant (8.988 x 10⁹ N m²/C²)

Q₁ and Q₂ = charges in coulombs

r = distance between the charges in meters

In this case:

U = 8.988 x 10⁹ N m²/C² × (12 C × 5 Q) / (1.0 m) = 5.375 x 10⁻⁷ J

The final energy of the system is the kinetic energy of particle B. The kinetic energy is given by:

KE = 1/2 × m × v²

where:

KE = kinetic energy in joules

m = mass in kilograms

v = velocity in meters per second

Solve for the velocity of particle B using the conservation of energy equation:

KE = U

Substituting the expressions for KE and U gives:

1/2 × m × v² = 5.375 x 10⁻⁷ J

Solving for v gives:

v = √(2 × 5.375 x 10⁻⁷ J / m)

= 1.53 m/s

The kinetic energy of particle B is then:

KE = 1/2 × m × v²

= 1/2 × m × (1.53 m/s)²

= 4.32 J

Therefore, the kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

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The scenario that is an example of the transfer of thermal energy by conduction is D. Warm water ascends inside a tea pot as cooler water sinks.

Conduction is the transfer of heat through a material without the bulk motion of matter. In the case of a tea kettle, the heat source (such as a stove) heats the metal of the kettle, which then conducts the heat to the water inside the kettle.

The hot water molecules transfer their thermal energy to the cooler water molecules through direct contact, which causes the cooler water to become denser and sink while the warmer water becomes less dense and rises.

This creates a convection current, which further distributes the thermal energy within the water.

Option A describes the transfer of thermal energy by radiation, where electromagnetic waves (such as infrared light) transfer energy from the source to the eggs without any direct contact.

Option B describes the transfer of thermal energy by convection, where the cooler water in the pool sinks to the bottom and is replaced by warmer water rising to the surface.

Option C describes the transfer of thermal energy by radiation and convection, where the hot sidewalk radiates heat to the surrounding air, which then rises and is replaced by cooler air.

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