all values of x by factoring.
X
x2
x² - 9x - 20 = -2x - 2

Answer:

Option B

Step-by-step explanation:

Proportion of number of defective pieces to the number of microchips in a batch can be represented by the ratio = \(\frac{\text{Number of microchips not in good condition}}{\text{Total numbers of microchips}}\)

If 3 microchips are defective in a batch of 750 microchips,

Proportion = \(\frac{3}{750}\)

If 'x' chips are defective in a batch of 10000 microchips,

Proportion = \(\frac{x}{10000}\)

If both the proportions are equal,

\(\frac{3}{750}=\frac{x}{10000}\)

Therefore, Option B will be the answer.

Answer:

x = 6

Hope this helps!

Answer:

1/ Point slope form is more efficient for determining the Slope

2/ Standard form is more efficient for determining x-intercept and

y-intercept

3/ If you want to use your calculator to graph an equation, the Point slope form is more efficient

Step-by-step explanation:

1/ I say point slope form because the slope in this form is a point on the line, and he if knows the point on the graph and slope, he can graph the line easily.

2/ I say standard form because x​ and ​y​ intercepts ​ of a graph, that is, the point where the graph crosses the ​ x-axis and the point where it crosses the ​ y ​-axis. So, it is the easiest form to find the x and y intercepts.

3/ If he knows a point and the slope he can graph it easily.

corresponding (option D)

Since the lines are parallel and a tranversal line cuts the two lines:

The angle 2 at the top of the first line correspods to angle 6 at the top of the second line.

Angle 2 and angle 6 are equal.

Hence. we say angle 2 and angle 6 are corresponding angles (option D)

Answer:

Therefore, the book value of the equipment at the end of year four (including year four) is $2,880.

Step-by-step explanation:

To calculate the book value of the equipment at the end of year four using the MACRS method with GDS recovery period of five years, we can use the following steps in Excel:

1. Open a new Excel spreadsheet and create the following headers in row 1: Year, Cost, Depreciation Rate, Annual Depreciation, Cumulative Depreciation, and Book Value.

2. Fill in the Year column with the years 1 through 6 (since the truck has a life of six years).

3. Enter the cost of the truck, $12,000, in cell B2.

4. Use the following formula in cell C2 to calculate the depreciation rate for each year:

=MACRS.VDB(B2, 5, 5, 1, C1)

This formula uses the MACRS.VDB function to calculate the depreciation rate for each year based on the cost of the truck (B2), the GDS recovery period of five years, the useful life of six years, the salvage value of $2,000, and the year (C1).

5. Copy the formula in cell C2 and paste it into cells C3 through C7 to calculate the depreciation rate for each year.

6. Use the following formula in cell D2 to calculate the annual depreciation for each year:

=B2*C2

This formula multiplies the cost of the truck (B2) by the depreciation rate for each year (C2) to get the annual depreciation.

7. Copy the formula in cell D2 and paste it into cells D3 through D7 to calculate the annual depreciation for each year.

8. Use the following formula in cell E2 to calculate the cumulative depreciation for each year:

=SUM(D$2:D2)

This formula adds up the annual depreciation for each year from D2 to the current row to get the cumulative depreciation.

9. Copy the formula in cell E2 and paste it into cells E3 through E7 to calculate the cumulative depreciation for each year.

10. Use the following formula in cell F2 to calculate the book value of the equipment for each year:

=B2-E2

This formula subtracts the cumulative depreciation for each year (E2) from the cost of the truck (B2) to get the book value.

11. Copy the formula in cell F2 and paste it into cells F3 through F7 to calculate the book value for each year.

12. The book value of the equipment at the end of year four (including year four) is the value in cell F5, which should be $2,880.

The given equation is:

375 = x - 28

To solve the equation:

Collect like terms

The -28 crosses the equality sign to the left and becomes 28

The equation then becomes:

375 + 28 = x

x = 403 (correct answer)

The students error is that when he collected like terms, he did not change the "-" sign in -28 to +

He did 375 - 28 = x

x = 347 (wrong)

Answer:

Step-by-step explanation:

kaja

Step-by-step explanation:

v = u + at

v-u = at

a = (v -u)/t

When t = 4, u=10, v=50

a = (50-10)/4

a= 40/4

a = 10

Answer:

the item now costs $63.21

When receiving ammunition, unit personnel perform three tasks: ensuring items requested match item numbers on DA Form 3151-R, loading and securing the ammunition, and placarding the vehicle.

The first task performed by unit personnel when receiving ammunition is to ensure that the items requested match the item numbers on DA Form 3151-R. This form serves as a record of the types and quantities of ammunition being received. By comparing the requested items with the item numbers on the form, personnel ensure accuracy and prevent any discrepancies or errors in the delivery.

The second task involves the loading and securing of the ammunition. Unit personnel are responsible for safely and efficiently loading the ammunition onto the designated vehicle or storage area. This includes following proper handling procedures, using appropriate equipment, and adhering to safety protocols. The ammunition must be securely stored and arranged to prevent shifting or damage during transportation.

The final task is to placard the vehicle. Placarding involves visibly displaying the necessary warning signs or labels on the vehicle that indicate the presence of ammunition. This step is crucial for safety and compliance purposes, as it alerts other personnel and drivers to exercise caution when approaching or handling the vehicle. Clear and prominent placarding helps prevent accidents and ensures that everyone involved is aware of the potential hazards associated with transporting ammunition.

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A one-sample t-test was conducted to determine if the temperature increased in the first week of October 2019 compared to the average temperature from the previous 10 years. The result showed a p-value of 0.032, indicating a significant increase in temperature.

To determine if there is evidence to show that the temperature has increased this year compared to the average temperature data from the previous 10 years, we can conduct a one-sample t-test with a null hypothesis that the population mean temperature this year is equal to the average temperature data from the previous 10 years (75) and an alternative hypothesis that the population mean temperature this year is greater than 75.

Using a statistical software, the calculated t-value is 2.17 with a corresponding p-value of 0.032. Since the p-value is less than the significance level of 0.05, we can reject the null hypothesis and conclude that there is evidence to show that the temperature has increased this year compared to the average temperature data from the previous 10 years. The p-value of 0.032 indicates that the probability of observing a sample mean temperature as extreme as 79.29 (the calculated sample mean temperature this year) or greater, assuming that the population mean temperature is equal to 75, is 0.032.

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The chance that the hospital will run out of sleeping pills on any given day is 0.5000 (or 0.5000 with four decimal places).

To calculate the chance that the hospital will run out of sleeping pills on any given day, we can use the normal distribution and Z-score.

First, let's calculate the Z-score using the formula:

Z = (X - μ) / σ

Where:

X = consumption rate per day (1,155 pills)

μ = average consumption rate per day (1,155 pills)

σ = standard deviation (81 pills)

Z = (1,155 - 1,155) / 81

Z = 0

Now, we need to find the probability associated with this Z-score. However, since the demand for sleeping pills can be considered continuous and not discrete, we need to calculate the area under the curve from negative infinity up to the Z-score. This represents the probability of not running out of sleeping pills.

We discover that the region to the left of a Z-score of 0 is 0.5000 using a basic normal distribution table or statistical software.

To find the probability of running out of sleeping pills, we subtract this probability from 1:

Probability of running out of sleeping pills = 1 - 0.5000

Probability of running out of sleeping pills = 0.5000

Therefore, on any given day, the hospital has a 0.5000 (or 0.5000 with four decimal places) chance of running out of sleeping tablets.

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Answer:

prime numbers between 20-30 are 23,29

prime numbers between 10-20 are 11,13,17,19

No,Steve is not right

Reason-there are two prime numbers between 20 to 30.Whereas there are 4 prime numbers between 10 to 20.

Answer:

○ \(\displaystyle 12,9\)

Step-by-step explanation:

Use the Law of Sines to find the length of the second edge:

Solving for Angles

\(\displaystyle \frac{sin\angle{C}}{c} = \frac{sin\angle{B}}{b} = \frac{sin\angle{A}}{a}\)

Use \(\displaystyle sin^{-1}\)towards the end or you will throw your result off!

Solving for Edges

\(\displaystyle \frac{c}{sin\angle{C}} = \frac{b}{sin\angle{B}} = \frac{a}{sin\angle{A}}\)

Let us get to wourk:

\(\displaystyle \frac{a}{sin\:40} = \frac{10}{sin\:30} \hookrightarrow \frac{10sin\:40}{sin\:30} = x; 12,855752194... \\ \\ \boxed{12,9 \approx x}\)

I am joyous to assist you at any time.

The inequalities that represent the constraints in this situation are r+c≥80 and 1.45R +0.75c≤200 respectively

The amount with victor = $200

Let the number of roses purchased by Victor be R,

Also, Rose cost $1.45 each

Therefore cost of rose = 1.45R

A;so, let the number of carby Victor be C at a cost of $0.65 each nation purchased by victor be $0.65 each

Therefore, cost of carnation = $0.65c

1) The inequality to represent the constraint that every person takes home at least one rose is r+c≥80 and

2) the inequality to represent the cost constraint is 1.45R + 0.65≤200

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The optimal values of these parameters are:

a. β₁ = 0

b. β₂ = 0

The linear regression y = β1 + β2x + e, assuming that the sum of squared errors (SSE) takes the following form:

SSE = 382 + 681 + 382 + 18β1β2

Derive the partial derivatives of SSE with respect to β1 and β2 and solve the optimal values of these parameters.

Given that SSE = 382 + 681 + 382 + 18β1β2 ∂SSE/∂β1 = 0 ∂SSE/∂β2 = 0

Now, we need to find the partial derivative of SSE with respect to β1.

∂SSE/∂β1 = 0 + 0 + 0 + 18β2 ⇒ 18β2 = 0 ⇒ β2 = 0

Therefore, we obtain the optimal value of β2 as 0.

Now, we need to find the partial derivative of SSE with respect to β2. ∂SSE/∂β2 = 0 + 0 + 0 + 18β1 ⇒ 18β1 = 0 ⇒ β1 = 0

Therefore, we obtain the optimal value of β1 as 0. Hence, the partial derivative of SSE with respect to β1 is 18β2 and the partial derivative of SSE with respect to β2 is 18β1.

Thus, the optimal values of β1 and β2 are 0 and 0, respectively.

Therefore, the answers are: a. β₁ = 0 b. β₂ = 0

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Answer:

Zero

Step-by-step explanation:

Answer:

Answer: C. Zero

Step-by-step explanation:

The Slope of a Line

Suppose we know a line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

\(\displaystyle m=\frac{y_2-y_1}{x_2-x_1}\)

The line shown in the image is horizontal, i.e. all of its points have the same y-coordinate regardless of their x-coordinate.

Take two random points on the line like (0,-2) and (2,-2), the slope is:

\(\displaystyle m=\frac{-2+2}{2-0}=0\)

The slope is zero

Answer: C. Zero

Answer:

No, because for each input, there is not exactly one output.

The total distance traveled by Wyatt is 21.6 feet. To find the total distance traveled by Wyatt, we need to calculate the distances between the different locations and then sum them up.

From the given information:

Distance from tire swing to slide = 6 feet (west)

Distance from slide to monkey bars = 7.8 feet (south)

Distance from monkey bars back to tire swing = 7.8 feet (north)

To calculate the total distance traveled, we need to find the sum of these three distances.

Distance traveled from tire swing to slide = 6 feet

Distance traveled from slide to monkey bars = 7.8 feet

Distance traveled from monkey bars back to tire swing = 7.8 feet

Total distance traveled = Distance from tire swing to slide + Distance from slide to monkey bars + Distance from monkey bars back to tire swing

Total distance traveled = 6 feet + 7.8 feet + 7.8 feet

Total distance traveled = 21.6 feet

Therefore, the total distance traveled by Wyatt is 21.6 feet.

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Answer:

42.75 pounds

i think :))

Step-by-step explanation:

Answer:

7

Step-by-step explanation

The first thing you do is plug in zero for y the you solve it

The given equation when you plug 0 in for y is

0=-5x²+25x+70

we can solve the equation using the inverse of A:\(\[x = A^{-1}v = \begin{bmatrix} -1 & 2 & -5 \\ 5 & -9 & 20 \\ -1 & 2 & -4 \end{bmatrix} \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix} = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]Therefore, the four vectors:\[u_1 = \begin{bmatrix} 1 \\ -1 \\ 2 \end{bmatrix} , \; u_2 = \begin{bmatrix} 2 \\ 1 \\ 0 \end{bmatrix} , \; u_3 = \begin{bmatrix} -1 \\ 3 \\ -1 \end{bmatrix} , \; v = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]\)form a basis of .

To do that, we will solve the equation:\[Ax = v\]where x is a column vector of three unknowns. We want v to be linearly independent from the columns of A, so we need the equation to have a unique solution. We can achieve that by taking v to be any vector that is not in the column space of A. For example, we can take:\\([v = \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix}\]\)Then, we can solve the equation using the inverse of A:\(\[x = A^{-1}v = \begin{bmatrix} -1 & 2 & -5 \\ 5 & -9 & 20 \\ -1 & 2 & -4 \end{bmatrix} \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix} = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]Therefore, the four vectors:\[u_1 = \begin{bmatrix} 1 \\ -1 \\ 2 \end{bmatrix} , \; u_2 = \begin{bmatrix} 2 \\ 1 \\ 0 \end{bmatrix} , \; u_3 = \begin{bmatrix} -1 \\ 3 \\ -1 \end{bmatrix} , \; v = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]\)form basis of .

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Madison figures out the average and range of chloride readings from wells close to the ocean. Other than a query, she has carried out an operation. The answer id option (d).

The standard deviation is a measure of variance from the mean that takes spread, dispersion, and dispersion into account. The standard deviation displays a "typical" divergence from the mean. It is a well-liked measure of variability since it retains the primary units of measurement from the data set.  A minor variation occurs when the numbers are close to the mean, while a high variation occurs when they are far from the mean.

The standard deviation describes the degree to which the results deviate from the mean. The average deviation, which depends on all values, is the most often used metric for measuring dispersion. Consequently, the standard deviation's value can be altered even by a slight change in one value.

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Step-by-step explanation:

do you mean 6.70 because if you do I think it is 7 but I am not sure

We need to calculate the coordinates of the center of mass using the formula for a two-dimensional object.

First, let's rewrite the equation 2y^2 - x^3 = 0 in terms of y to find the boundaries of the curve. Solving for y, we have y = ±(x^3/2)^(1/2) = ±(x^3)^(1/2) = ±x^(3/2).

Since the curve is symmetric about the x-axis, we only need to consider the positive portion of the curve, which is y = x^(3/2).

To find the center of mass, we need to calculate the area of each segment between x = 0 and x = 2. The area can be found by integrating the function y = x^(3/2) with respect to x:

A = ∫[0, 2] x^(3/2) dx = [(2/5)x^(5/2)]|[0, 2] = (2/5)(2)^(5/2) - (2/5)(0)^(5/2) = (4/5)√2.

Next, we need to calculate the x-coordinate of the center of mass (Xcm) and the y-coordinate of the center of mass (Ycm):

Xcm = (1/A)∫[0, 2] (x * x^(3/2)) dx = (1/A)∫[0, 2] x^(5/2) dx = (1/A)[(2/7)x^(7/2)]|[0, 2] = (1/A)((2/7)(2)^(7/2) - (2/7)(0)^(7/2)) = (8/35)√2.

Ycm = (1/2A)∫[0, 2] (x^2 * x^(3/2)) dx = (1/2A)∫[0, 2] x^(7/2) dx = (1/2A)[(2/9)x^(9/2)]|[0, 2] = (1/2A)((2/9)(2)^(9/2) - (2/9)(0)^(9/2)) = (32/45)√2.

Therefore, the center of mass is approximately (Xcm, Ycm) = (8/35)√2, (32/45)√2).

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The ratio of corresponding sides for the given similar triangles is 2/5.

In the given options, the ratio of corresponding sides is provided for each set of similar triangles. Let's analyze each option to determine the correct ratio:

a. 10

This option only provides a single number and does not specify the ratio of corresponding sides. Therefore, it is not the correct answer.

b. 4/5

This option provides the ratio 4/5 for the corresponding sides of the similar triangles. However, the ratio can be simplified further.

To simplify the ratio, we divide both the numerator and denominator by their greatest common divisor (GCD). In this case, the GCD of 4 and 5 is 1.

Dividing 4 and 5 by 1, we get:

4 ÷ 1 = 4

5 ÷ 1 = 5

Therefore, the simplified ratio is 4/5.

c. 10/85

This option provides the ratio 10/85 for the corresponding sides of the similar triangles. However, this ratio cannot be simplified further, as 10 and 85 do not have a common factor other than 1.

Therefore, the correct ratio of corresponding sides for the given similar triangles is 2/5, as determined in option b.

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Answer:

(8.47,0) (-0.47,0)

Step-by-step explanation:

y = a(x - h)² + k

y = a(x - 4)² - 20

-4 = a(0 - 4)² - 20

16 = 16a

a = 1

y = (x - 4)² - 20

x-intercepts: y = 0

(x - 4)² = 20

x - 4 = +/- 4.47..

x = 4.47+4, -4.47+4

x = 8.47, -0.47

Answer:

( 5, 2)

Step-by-step explanation:

solve by subrtaction

x -2y = 1

-x -4y = -13

-6y = -12 divide both sides by -6

y=2

x-2y=1

x -2*2 =1

x=1+4=5

Answer:

(5,2)

Step-by-step explanation:

x=1+2y and x+4y=13

1+2y+4y=13

y=2

x=1+2*2

x=5

(x,y)=(5,2)

You're welcome!

Answer:

$2.89

Step-by-step explanation:

9 pounds = 26.01

1 pound = 26.01 ÷ 9 = 2.89

The expected value of the continuous random variable V is 5. The expected value of V is 5, indicating that, on average, we expect the value of V to be around 5.

To calculate the expected value of a continuous random variable V with a given probability density function (PDF), we integrate the product of V and the PDF over its entire range.

The PDF of V is defined as:

f(v) = 6/24 = 0.25 for 3 ≤ v ≤ 7, and 0 otherwise.

The expected value of V, denoted as E(V), can be calculated as:

E(V) = ∫v * f(v) dv

To find the expected value, we integrate v * f(v) over the range where the PDF is non-zero, which is 3 to 7.

E(V) = ∫v * (0.25) dv, with the limits of integration from 3 to 7.

E(V) = (0.25) * ∫v dv, with the limits of integration from 3 to 7.

E(V) = (0.25) * [(v^2) / 2] evaluated from 3 to 7.

E(V) = (0.25) * [(7^2 / 2) - (3^2 / 2)].

E(V) = (0.25) * [(49 / 2) - (9 / 2)].

E(V) = (0.25) * (40 / 2).

E(V) = (0.25) * 20.

E(V) = 5.

Therefore, the expected value of the continuous random variable V is 5.

The expected value represents the average value or mean of the random variable V. It is the weighted average of all possible values of V, with each value weighted by its corresponding probability. In this case, the expected value of V is 5, indicating that, on average, we expect the value of V to be around 5.

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