Ammonia is essential to so many industries that, on a molar basis, it is the most heavily produced substance in the world. Calculate P_IGL and P_VDW (in atm) of 51.1 g of ammonia in a 3.000-L container at 0°C and 400.°C, the industrial temperature. (See Table 5.4 for the values of the van der Waals constants.)
Answers
\(P_{\text{IGL}}\) at 0°C is 22.42 atm and \(P_{\text{IGL}}\) at 400°C is 55.24 atm. \(P_{\text{VDW}}\) at 0°C is 19.12 and \(P_{\text{VDW}}\) at 400°C is 53.22 atm of 51.1 g of ammonia in a 3.000-L container.
What is Ideal Gas Law ?The law which states that the pressure of gas is directly commensurable to the volume and temperature of the gas is known as ideal gas law.
It is expressed as
PV = nRT
where,
P = Pressure
V = Volume in liters
n = number of moles of gas
R = Ideal gas constant
T = Temperature in kelvin
Now put the values in above equation
PV = nRT
PV = \(\frac{m}{M} RT\)
\(P = \frac{mRT}{MV}\)
At 0°C pressure is
\(P_{\text{IGL}} = \frac{(51.1\ g) \times (0.0821\ \text{L. atm/mol.K}) \times (0 + 273.15\ K)}{17.04\ \text{g/mol} \times 3.000\ L}\)
= 22.42 atm
At 400°C pressure is
\(P_{\text{IGL}} = \frac{(51.1\ g) \times (0.0821\ \text{L. atm/mol.K}) \times (400 + 273.15\ K)}{17.04\ \text{g/mol} \times 3.000\ L}\)
= 55.24 atm
The value of a and b for ammonia are 4.17 and 0.0371
\(\left(P + \frac{n^2a}{V^2} \right ) (V - nb) = nRT\)
\(n = \frac{51.1\ g}{17.04\ \text{g/mol}}\)
n = 3.00
At 0°C pressure is
\(\left (P_{\text{VDW}} + \frac{(3.00)^2 (4.17)}{(3.000)^2} \right ) (3.000 - (0.037) (3.00)) = (3.00)(0.0821) (0 + 273.15\ K)\)
\((P_{\text{VDW}} + 4.17) = 23.28723\)
\(P_{\text{VDW}} =19.12\)
At 400°C pressure is
\(\left (P_{\text{VDW}} + \frac{(3.00)^2 (4.17)}{(3.000)^2} \right ) (3.000 - (0.037) (3.00)) = (3.00)(0.0821) (400 + 273.15\ K)\)
\((P_{\text{VDW}} + 4.17) = 57.38897\)
\(P_{\text{VDW}} = 53.22\)
Thus from the above conclusion we can say that \(P_{\text{IGL}}\) at 0°C is 22.42 atm and \(P_{\text{IGL}}\) at 400°C is 55.24 atm. \(P_{\text{VDW}}\) at 0°C is 19.12 and \(P_{\text{VDW}}\) at 400°C is 53.22 atm of 51.1 g of ammonia in a 3.000-L container.
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Related Questions
A mixture of 0.5940 M CO and 0.3950 M Cl2 is enclosed in a vessel and heated to 1000 K . CO(g)+Cl2(g)↽−−⇀COCl2(g)c=255.0 at 1000 K Calculate the equilibrium concentration of each gas at 1000 K
Answers
Answer:
[CO] = 0.2064M
[Cl2] = 0.0074M
[COCl2] = 0.3876M
Explanation:
Based on the reaction, Kc at 1000K is:
Kc = 255.0 = [COCl2] / [CO] [Cl2]
Where [] are concentrations at equilibrium
As the reaction is 1:1, the concentrations at equilibrium are:
[CO] = 0.5940M - X
[Cl2] = 0.3950M - X
[COCl2] = X
Where X is reaction coordinate
Replacing:
255.0 = [X] / [0.5940 - X] [0.3950 - X]
255.0 = X / 0.23463 - 0.989 X + X²
59.8307 - 252.195 X + 255 X² = X
59.8307 - 253.195 X + 255 X² = 0
Solving for X:
X = 0.605M. False solution because produce negative answers
X = 0.3876M. Right solution.
Replacing:
[CO] = 0.5940M - 0.3876M
[Cl2] = 0.3950M - 0.3876M
[COCl2] = 0.3876M
[CO] = 0.2064M
[Cl2] = 0.0074M
[COCl2] = 0.3876M
The concentration at equilibrium of CO is 0.2064 M, \(\rm Cl_2\) is 0.0074 M, and \(\rm COCl_2\) is 0.3876 M.
The initial concentration of CO = 0.5940 M
\(\rm Cl_2\) = 0.3950 M
At equilibrium,
Let the concentration of formed \(\rm COCl_2\) = x
Concentration of CO = 0.5940 - x M
Concentration of \(\rm Cl_2\) = 0.3950 - x M
\(\rm K_c\) = 255
\(\rm K_c\) = \(\rm \dfrac{[COCl_2]}{[CO]\;[Cl_2]}\)
255 = \(\rm \dfrac{x}{[0.5940-x]\;[0.3950-x]}\)
(151.47 - 255x) (100.727-255x) = x
15,256 - 65,025 \(\rm x^2\) = x
0 = 65,025 \(\rm x^2\) +x - 15,256
x = \(\rm\dfrac{-b\;\pm\;\sqrt{b^2\;-\;4ac} }{2a}\)
a = 65,025
b = 1
c = -15,256
x = 0.38 M
Thus, the concentration at equilibrium of CO is 0.2064 M, \(\rm Cl_2\) is 0.0074 M, and \(\rm COCl_2\) is 0.3876 M.
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when the exact composition and amounts of carbon and nitrogen in the media ingredients are unknown, these media are called?
Answers
When the exact composition and amounts of carbon and nitrogen in the media ingredients are unknown, these media are called complex media.
In microbiology and cell culture, media refers to the nutrient-rich solutions or mixtures used to support the growth and propagation of microorganisms or cells. These media typically contain various components such as carbon, nitrogen, minerals, vitamins, and other essential nutrients.
When the exact composition and amounts of carbon and nitrogen in the media ingredients are unknown, the media are referred to as complex media. Complex media are usually made from natural sources, such as yeast extract, beef extract, or peptone, which contain a mixture of nutrients in undefined proportions.
Complex media are commonly used in laboratory settings when the precise requirements of the microorganisms or cells being cultured are not well-defined or understood. They provide a broad range of nutrients that support the growth of a wide variety of organisms.
Contrastingly, defined or synthetic media have a precisely known composition, with the exact amounts and sources of carbon, nitrogen, and other nutrients specified. These media are used when researchers need precise control over the nutrients provided to the microorganisms or cells, allowing for specific growth conditions and experiments.
When the composition and amounts of carbon and nitrogen in the media ingredients are unknown, the media are called complex media. Complex media are used when the precise requirements of the microorganisms or cells are not well-defined, providing a mixture of nutrients that can support the growth of various organisms.
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1. If a sample of nitrogen gas is collected over water at 70°C has a total pressure of 2590 mm Hg,
what would be the pressure of the nitrogen alone?
Vapor pressure of water at 70'C = 233.7 mm Hg
2. Find the total pressure for a mixture that contains four gases with partial pressures of 5.00 atm,
4.65 atm, 3.01 atm, and 121.56 kPa.
3. A flask contains a mixture of the three following gases: 1 mol N₂ at 460 mm Hg, 1 mol Ne at 275
mm Hg, and 1 mol O₂ at 520 mm Hg. What is the total pressure in the flask?
4. A mixture of helium and neon gases is collected over water at 28.0 C and 745 mmHg. If the
partial pressure of helium is 368 mmHg, what is the partial pressure of neon? The vapor pressure
of water at 28 °C is 28.3 mm Hg.
5. A mixture of three gases, oxygen, nitrogen, and helium, is at a total pressure of 6.11 atm. The
partial pressure of the oxygen is 1780 mmHg, the nitrogen is at 174.1 kPa, and the partial
pressure of the helium is unknown. What is the partial pressure of helium in atm?
Oxygen gas was collected over water at a barometric pressure of 732.0 mmHg and 23 °C. What is
the partial pressure of the oxygen? The vapor pressure of water at 23°C = 21.1 mm Hg.
Answers
Answer:
Explanation: To find the pressure of the nitrogen alone, we need to subtract the vapor pressure of water at 70°C from the total pressure. Therefore, the pressure of nitrogen alone would be:
2590 mm Hg - 233.7 mm Hg = 2356.3 mm Hg
To find the total pressure of the mixture, we simply add the partial pressures of the individual gases:
Total pressure = 5.00 atm + 4.65 atm + 3.01 atm + 121.56 kPa
= 12.53 atm
Note that we need to convert the partial pressure of the fourth gas from kPa to atm before adding it to the other partial pressures.
The total pressure in the flask is the sum of the partial pressures of each gas:
Total pressure = 460 mm Hg + 275 mm Hg + 520 mm Hg
= 1255 mm Hg
To find the partial pressure of neon, we need to subtract the vapor pressure of water at 28.0°C from the total pressure, and then subtract the partial pressure of helium from the result:
Partial pressure of neon = Total pressure - Vapor pressure of water - Partial pressure of helium
= 745 mmHg - 28.3 mmHg - 368 mmHg
= 348.7 mmHg
The partial pressure of helium can be found by subtracting the partial pressures of oxygen and nitrogen from the total pressure:
Partial pressure of helium = Total pressure - Partial pressure of oxygen - Partial pressure of nitrogen
= 6.11 atm - 1780 mmHg - 174.1 kPa
= 0.273 atm
Note that we need to convert the partial pressure of nitrogen from kPa to atm before subtracting it from the total pressure.
To find the partial pressure of oxygen, we need to subtract the vapor pressure of water at 23°C from the total pressure:
Partial pressure of oxygen = Total pressure - Vapor pressure of water
= 732.0 mmHg - 21.1 mmHg
= 710.9 mmHg
an archaeologist finds that the 14c in a 3.10 g sample of a material to be decaying at 107 counts per second. a modern 1.00-g sample of the same material decays at 151 counts per second. the half-life of 14c is 5730 y. how old is the sample?
Answers
The age of the sample is approximately 1996 years.
How to determine the age of the sample?To determine the age of the sample, we can use the concept of radioactive decay and the formula for exponential decay:
N(t) = N₀ * (1/2)^(t/T)
Where:
N(t) is the current number of radioactive atoms,
N₀ is the initial number of radioactive atoms,
t is the time elapsed,
T is the half-life of the radioactive material.
Let's denote the initial number of radioactive atoms in the 3.10 g sample as N₀1 and in the 1.00 g modern sample as N₀2.
Given:
N₀1/N₀2 = (3.10 g) / (1.00 g) = 3.10
We can set up the ratio of the decay rates:
R = (107 counts per second) / (151 counts per second) = 0.7086
Using the formula for exponential decay, we have:
N(t1)/N₀1 = (1/2)^(t1/T)
N(t2)/N₀2 = (1/2)^(t2/T)
Since N(t1)/N(t2) = N₀1/N₀2 = 3.10, we can rewrite it as:
(1/2)^(t1/T) / (1/2)^(t2/T) = 3.10
Taking the logarithm of both sides and using the properties of logarithms, we get:
t1/T - t2/T = log₂(3.10)
Now we substitute the ratio of the decay rates R = 0.7086:
(t1/T) / (t2/T) = 0.7086
t1/t2 = 0.7086
Using the given information that the half-life (T) is 5730 years, we can solve for t2:
t2 = t1 / 0.7086
Now we substitute t2 = t1 / 0.7086 into the equation t1/T - t2/T = log₂(3.10):
t1 / T - (t1 / 0.7086) / T = log₂(3.10)
Simplifying the equation:
0.2914 * t1 / T = log₂(3.10)
Solving for t1:
t1 = (log₂(3.10) / 0.2914) * T
Now we can substitute the value of T = 5730 years:
t1 = (log₂(3.10) / 0.2914) * 5730
Calculating this expression, we find:
t1 ≈ 1996 years
Therefore, the age of the sample is approximately 1996 years.
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if the density of a bar of gold is 19.3g/cm^3and you cut it into four pieces , what is its density of each piece of gold
Answers
So if the density of gold is 19.3 g/cm³, the density of a bar of gold and the pieces into which the bar is cut would all be 19.3 g/cm³.
Considering the definition of density and intensive and extensive properties, the density of each piece of gold is 19.3 \(\frac{g}{cm^{3} }\)
Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space. In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
Intensive properties are those that will remain unchanged even though the amount of matter varies, while extensive properties vary depending on the amount of matter in a body.
Density is an intensive property, so it is independent of the sample size. This is because the solute will be present in a certain proportion with respect to the solvent. That ratio will not change unless more solute or more solvent is added. Consequently, the concentration remains constant (concentration is an intensive property) and density too.
Finally, the density of each piece of gold is 19.3 \(\frac{g}{cm^{3} }\)
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When 15 gram Calcium oxide is treated with 2ogram nitric acid then limiting reactant find. What mass of calcium nitrate is formed?
Answers
Explanation:
Without even doing any calculations I would say that the 20 g HNO3 is limiting
But let us check if my opinion is correct
Balanced equation:
CaO(s) + 2HNO3 (aq) → Ca(NO3)2 (aq) + H2O(l)
1 mol CaO reacts with 2 mol HNO3
Molar mass CaO = 56 g/mol
Mol CaO in 615 g = 615 g / 56 g/mol = 10.98 mol
This will react with 10.98 * 2 = 21.96 mol HNO3
Molar mass HNO3 = 63 g/mol
Mol HNO3 in 20 g = 20 g / 63 g/mol = 0.317 mol
Clearly - my original idea correct - HNO3 is limiting .
The reaction stoichiometry can be used to determine the precise quantity of reactant that will be required to react with another element. The limiting agent is determined by the mole ratio rather than the mass of the reactants. Here the mass of calcium nitrate formed is 16.82 g.
What is limiting reagent?Reagents that are entirely consumed by a chemical reaction are known as limiting reagents. They are additionally known as limiting reactants or limiting agents. A predetermined quantity of reactants are necessary for the reaction to be completed, according to the stoichiometry of chemical reactions.
The limiting reactant determines the maximum amount of product that can be formed from the reactants when reactants are not present in stoichiometric quantities.
Here the equation is:
CaO + 2HNO₃ → Ca (NO₃)₂ + H₂O
'n' of CaO = 15 / 56 = 0.267 mol
n of HNO₃ = 20 / 63 = 0.317 mol
1 mol of CaO 2 moles of HNO₃
0.267 mol = 0.267 × 2 = 0.534 mol
So HNO₃ is the limiting reactant.
0.267 mol CaO gives 0.267 mol Ca (NO₃)₂
Mass of HNO₃ = 0.267 × 63.01 = 16.82 g
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2) How many kilojoules of energy is needed to decompose 10.8 grams of N₂Os gas? (SOLO)
2 N₂O5 (g) + 110 kJ—->4 NO2(g) + O2(g)
Answers
The energy needed to decompose 10.8 grams of N₂O5 is 110 kJ.
It takes 110 kJ of energy to decompose 2 moles of N₂O5 (the molecular weight of N₂O5 is 108 g/mol). Since 10.8 grams of N₂O5 is equal to 0.1 moles, it takes 110 kJ of energy to decompose 0.1 moles of N₂O5, which is the same as decomposing 10.8 grams of N₂O5.
a pollutant decays with a first-order rate constant of 0.726 min-1. calculate the half-life of the pollutant (in minutes).
Answers
A pollutant decays with a first order rate constant of 0.726 min⁻¹ . The half life of the pollutant will be 0.95 minutes.
Half -life of a chemical reaction is defined as , " the time taken for the concentration of a given reactant to reach half or 50% of its initial concentration" .
Half life of a first order reaction is given as
t(1/2) = 0.693/ K
where K is the rate constant.
given,
here, rate constant is k= 0.726 min⁻¹
therefore, half life of the pollutant:
t(1/2) = 0.693/ 0.726 min⁻¹
t(1/2) =0.95 min
Thus, the half-life of the pollutant is 0.95 minutes
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An atom of a certain element has 19 protons, 19 electrons, and a mass number of 39. This element is very reactive. How many neutrons are in this atom?
Record your answer and fill in the bubbles on your answer document. Be sure to use the correct place value.
Answers
Answer:
There are 20 neutrons in this atom.
Explanation:
A shopper in a supermarket pushes a cart with a force of 35 N directed at
an angle of 25° downward from the horizontal. Find the work done by the
shopper on the cart as the shopper moves along a 50. 0 m length of aisle.
Answers
The shopper does approximately 1580.5 Joules of work on the cart as they move along the 50.0 m length of the aisle.
To find the work done by the shopper on the cart, we can use the formula: work = force * distance * cos(angle).
Given:
Force (F) = 35 N
Angle (θ) = 25° downward from the horizontal
Distance (d) = 50.0 m
First, we need to determine the horizontal component of the force, which is F_horizontal = F * cos(θ).
F_horizontal = 35 N * cos(25°) ≈ 31.61 N
The work done by the shopper on the cart is then:
Work = F_horizontal * distance
Work = 31.61 N * 50.0 m = 1580.5 Joules
Therefore, the shopper does approximately 1580.5 Joules of work on the cart as they move along the 50.0 m length of the aisle.
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One third of a bottle of water fills one sixth of a fish tank how much water is needed for the whole tank?
Answers
Answer: 1/2
Explanation:
It’s really all in the question so if 1/3 = 1/6
1/3 x 3 = 3 ( mind you were dealing with isolation)
So after you do that 3 x 1/6 = 1/2
(This maybe wrong but like I’m in middle school so what do expect like what am I doing on brainless a 3 am )
what is the 1h nmr chemical shift value (in ppm) of the indicated hydrogen? group of answer choices 4.06 2.06 1.06 3.06
Answers
The chemical shift of the hydrogen is 4.06 option A from the image shown.
What is chemical shift in NMR?In NMR, the chemical shift is a measure of the resonance frequency of a nucleus relative to a standard compound. The chemical shift is influenced by the electron density around the nucleus being studied. When the electron density around a nucleus decreases, it leads to a deshielding effect, resulting in a higher chemical shift value.
Conversely, when the electron density increases, it leads to a shielding effect, resulting in a lower chemical shift value.
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What is the noble gas configuration for Cobalt?
a
[Ar] 4s2 3d7
b
[Ar] 4s2 4d7
c
[Kr] 4s2 4d7
d
[Kr] 4s2 3d7
Answers
Answer:
a. [Ar] 4s2 3d7
Explanation:
Determine the volume (mL) required to prepare each of the following. 665 mL of a 0.350 M MgCl2 solution using a 4.00 M MgCl2 solution.
Answers
To answer this question we have to use the rule of dilutions:
\(V1\cdot C1=V2\cdot C2\)Where V1 is the initial volume, C1 is the initial concentration, V2 is the final volume and C2 is the final concentration. In this case we need to find V1.
Solve the equation for V1 and replace C1 for 4.00M, V2 for 665mL and C2 for 0.350M
\(\begin{gathered} V1=\frac{V2\cdot C2}{C1} \\ V1=\frac{665mL\cdot0.350M}{4.00M}=58.2mL \end{gathered}\)It means that the volume required is 58.2mL.
32.5 g to fluid ounces
Answers
can someone help me with it
Answers
Answer:
false, it is theory of how the universe started
Answer:
it's answer is false you can write it
According to the quantum theory, the size of an atomic orbital is most directly associated with?a) the principle quantum number(n)b) the angular momentum quantum number(I)c) the magnetic quantum number(ml)d) the spin quantum number(ms)e) the angular momentum and magnetic quantum numbers, together
Answers
According to quantum theory, the size of an atomic orbital is most directly associated with the principle quantum number (n). The correct option is a).
The principle quantum number describes the energy level of an electron in an atom, and as the value of n increases, the electron's energy and distance from the nucleus also increase. This means that the larger the value of n, the larger the size of the orbital.
The other quantum numbers, such as the angular momentum quantum number (l), the magnetic quantum number (ml), and the spin quantum number (ms), are all related to other properties of the electron, such as its shape, orientation, and spin, but they do not directly influence the size of the orbital.
Therefore, the principle quantum number is the most important factor in determining the size of an atomic orbital according to quantum theory.
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The part of an atom that has an overall positive charge is called
A. an electron
B. the nucleus
C. a neutron
D. energy level
Answers
a fossil was found and determined by radiometric dating to be 11,400 years old. what is the ratio of carbon-14 to carbon-12 in this fossil compared to its environment? a fossil was found and determined by radiometric dating to be 11,400 years old. what is the ratio of carbon-14 to carbon-12 in this fossil compared to its environment? 25% 37.5% 50% 12.5%
Answers
The ratio of carbon-14 to carbon-12 in this fossil compared to its environment.The answer would be 25%
Carbon 14 is radioactive material with 5700 year of half-time which will change it into carbon-12, a more stable substance. If the age of the fossil is 11,400 years old, then the amount of half-time passed would be: 11,400 years/ (5,700 years/ half-time)= 2 half-time.
How far back in time may some things be dated using the C 14 to C 12 ratio?
An artefact up to 40,000 years old can be dated using carbon-14. Carbon is absorbed by living things through breathing and feeding. Scientists burn a little piece of an artefact to establish its age by comparing the amount of Carbon-14 to the amount of Carbon-12.
Since it undergo 2 half-time, the percentage should be: 100% × \((\frac{1}{2} )^{2}\)= 25%.
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Question 4(Multiple Choice Worth 3 points)
(01.04 LC)
Which property describes a material's ability to conduct heat?
Electrical conductivity
Boiling point
Thermal conductivity
ting
O Melting point
Answers
Answer:
Thermal conductivity :)
Explanation:
Thermal conductivity is the ability of a material to conduct heat with a given temperature difference.
Which of the following elements would have the largest electronegativity value?
O cesium
Olithium
O carbon
O sodium
Answers
Describe the unique properties of water and how they affect the following:
phase changes
physical properties
This is my answer. Is it ok? Do you have suggestions to make it better?
Unique properties of water are polarity, solvency, cohesion, adhesion, high boiling point, density and the ability to dissolve other substances. The three phases of water are solid (frozen), liquid and gas and are changed by temperature. Water molecules don't change between the phases, the molecules just interact differently to make the change.
Answers
Unique properties of water
Water molecules have a bent overall structure, partial positive charges on the hydrogens, partial negative charges on the oxygen, and are polar. This is due to the fact that oxygen is more electronegative than hydrogen, making it more effective at drawing electrons. Excellent solvents include water.
Temperature alters the three states of water, which are solid (frozen), liquid, and gas. Although the interactions of the water molecules change, the molecules themselves do not alter between the phases.
Water quality's physical characteristics
Color: Polluted water may be coloured; pure water is colourless.
Turbidity: Clear, light-unabsorbing water is the opposite of pure water.
Taste and odour: Pure water never has a taste or an odour.
How many distinct characteristics does water have?Given their polar nature, water molecules form hydrogen bonds. This gives water its distinctive properties, including polarity, solvency, cohesion, adhesion, high specific heat, and the capacity to act as a buffer. A solute that has dissolved in a solvent creates a homogeneous mixture known as a solution.
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Katie wants to do an experiment to test what factors affect the growth rate of sunflowers. She plants two groups of sunflower seeds in identical pots, gives them the same amount of fertilizer, and lets them sit in the sun for the same amount of time every day. She gives one group of seeds 10 mL of water a day. She gives the other group 1 mL of water a day. The group that receives 10 mL of water grows the fastest. Katie analyzes and publishes her results.
Based on the results of Katie's experiment, what question could she ask next to continue her research on sunflower growth rate?
A. Will sunflowers grow to a larger maximum size in rocky mountain soil or in sandy soil from the beach?
B. Will sunflower petals be a brighter yellow if Katie adds yellow dye into the water that she gives them every day?
C. Will the growth rate of the sunflowers change if Katie increases the amount of water given to 20 mL a day?
Answers
Answer: C
Explanation:
We can research about the growth rate of plant that the water has been given, since we already did 10 mL. It would be best if we research more to see if 20 mL is enough water for the plant or will it make the plant go turgid and flaccid!
30 treadmills to 36 elliptical machines
Answers
Answer:
what? that's 66 total, 6 more elliptical machines, a 1 to 1.2 ratio
but I don't know what else you would mean
Answer:
5:6
Explanation:
Hope You Enjoy !
85 grams of BF3 and 195.0 grams of LiSO3 react according. To the chemical equation below. Use the BCA table to help you answer the questions.2BF3+3LiSO3=B2(SO3)3+6LiFWhat mass of LiF do we expect to produce
Answers
Explanation:
First, let's write the chemical equation:
\(2BF_3+3LiSO_3\rightarrow B_2(SO_3)_3+6LiF.\)Now, let's find what is the limiting reactant seeing which reactant will produce less product, but first, let's find what is their number of moles using its molar mass. The molar mass of BF3 is 67.8 g/mol and the molar mass of LiSO3 is 86.9 g/mol (you can calculate the molar mass of a compound using the periodic table). The conversion will look like this:
\(85\text{ g BF}_3\cdot\frac{1\text{ mol BF}_3}{67.8\text{ g BF}_3}=1.25\text{ moles BF}_3.\)\(195.0\text{ g LiSO}_3\cdot\frac{1\text{ mol LiSO}_3}{86.9\text{ g LiSO}_3}=2.24\text{ moles LiSO}_3.\)So, we're going to have 1.25 moles of BF3 and 2.24 moles of LiSO3 reacting.
Now, let's see how many moles of B2(SO3)3 produce each reactant.
You can see in the equation that 2 moles of BF3 reacted produces 1 mol of B2(SO3)3:
\(1.25\text{ moles BF}_3\cdot\frac{1\text{ mol B}_2(SO_3)_3}{2\text{ moles BF}_3}=0.625\text{ moles B}_2(SO_3)_3.\)And 3 moles of LiSO3 reacted produces 1 mol of B2(SO3)3:
\(2.24\text{ moles LiSO}_3\cdot\frac{1\text{molB}_2(SO_3)_3}{\text{3 moles LiSO}_3}=0.747\text{ moles B}_2(SO_3)_3.\)You can realize that the limiting reactant is BF3, but we need to know what is the leftover LiSO3, so let's calculate how many moles of LiSO3 are being used to produce 0.625 moles of B2(SO3)3:
\(0.625\text{ moles B}_2(SO_3)_3\cdot\frac{3\text{ moles LiSO}_3}{1\text{ mol B}_2(SO_3)_3}=1.88\text{ moles LiSO}_3.\)The leftover LiSO3 is 0.36 moles.
The next step is to find the number of moles of LiF that are being produced. You can see that 2 moles of BF3 reacted produces 6 moles of LiF:
\(1.25\text{ moles BF}_3\cdot\frac{6\text{ moles LiF}}{2\text{ moles BF}_3}=3.75\text{ moles LiF.}\)Answer:
So, finally, we can complete the BCA table:
Now, let's find the mass of 3.75 moles of LiF using its molar mass which is 25.9 g/mol:
\(3.75\text{ moles LiF}\cdot\frac{25.9\text{ g LiF}}{1\text{ mol LiF}}=97.13\text{ g LiF.}\)We expect to produce 97.13 g of LiF.
When you leave a wine exposed to the air, the ethanol in it reacts to form what?
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Answer:
(ethanol) into acetic acid or vinegar. When wine is exposed to the air, Oxygen in the air interacts with the wine. The wine changes colour and turns both white and red wines brown.
Explanation:
The hybridization scheme employed by a central atom when forming more than four bonds is.
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The sp3d hybridization scheme allows the central atom to form more than four bonds.
The hybridization scheme employed by a central atom when forming more than four bonds is sp3d
Hybridization is the mixing of orbitals of different energies to give hybrid orbitals of the same energy.
The hybridization sp3d employs five orbitals which can be paired to give the corresponding compound.
It involves the mixing of 1s orbital, 3p orbitals, 3p orbital, and 3d orbital to form orbitals of equal energy.
An example is PCl5 and it follows trigonal bipyramidal geometry.
It has axial and equatorial bonds.
It takes place in the presence of weak field ligands.
The complex formed by sp3d hybridization is known as the outer orbital complex.
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Biodiversity is important for the sustainability of ecosystems. However, many of the human actions that are aimed at growing communities are decreasing the biodiversity of these areas, leaving populations and ecosystems vulnerable. As human populations grow, the terrestrial and aquatic ecosystems they use may be transformed by the efforts of human beings and biodiversity losses typically accompany these processes. Which of these actions decrease biodiversity and threaten sustainability? Select ALL that apply.
A Invasive (non-native) species may outcompete native species for food and habitat. Invasive (non-native) species may outcompete native species for food and habitat.
B Regulated hunting seasons artificially decrease hunted populations, often leading to extinctions. Regulated hunting seasons artificially decrease hunted populations, often leading to extinctions.
C Pollution from building and commercialization can create health problems in exposed organisms. Pollution from building and commercialization can create health problems in exposed organisms.
D Decreased use of pesticides and fertilizers can allow for increased damage to plant life. Decreased use of pesticides and fertilizers can allow for increased damage to plant life.
E Habitat destruction reduces or eliminates the food resources and living space for most species. Habitat destruction reduces or eliminates the food resources and living space for most species.
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The actions by humans that decrease biodiversity and threaten sustainability are;
Regulated hunting seasons artificially decrease hunted populations, often leading to extinctions.Pollution from building and commercialization can create health problems in exposed organisms.Habitat destruction reduces or eliminates the food resources and living space for most species.What is biodiversity?The term biodiversity has to do with the existence of different species that exist in an ecosystem. In a given ecosystem, there could be several species that exist together. This biodiversity is very much important for the continuity of balance in nature.
The actions by humans that decrease biodiversity and threaten sustainability are;
Regulated hunting seasons artificially decrease hunted populations, often leading to extinctions.Pollution from building and commercialization can create health problems in exposed organisms.Habitat destruction reduces or eliminates the food resources and living space for most species.Learn more about biodiversity:https://brainly.com/question/13073382
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Which two Real gases will devote the least from an ideal gas explain
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The ideal gas equations of state express most real gases at low pressure but do not yield rational results at higher pressures
What is an ideal gas?An ideal gas is defined as a hypothetical gaseous material whose behavior is bold of ideal gas attractive and revolting forces and can be the Presence of electrons large in sulfur dioxide and hence greater van der Waals interplay. Due to greater intermolecular force, this gas has a high boiling point and essential high temperature to behave ideally. Hence sulfur dioxide act as the least ideal gas at low temperatures. It is also good to know that the ideal gas law takes that the gas molecules have negligible. Keeping that in mind, Xe is the largest of the bunch.
So we can conclude that an ideal gas is a theoretical gas controlled by many randomly moving point particles that are not subject to interparticle interactions.
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In what ratio would carbon bond with fluorine to form a stable compound? (Consider how many additional electrons each element needs, and how many of those elements would need to be present in a compound to satisify those needs.)
A.2:1
B.2:4
C.41
D.1:4
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The ratio of carbon bond with fluorine to form a stable compound is 1:4.
What is Carbon–fluorine bond?All organofluorine compounds have the polar covalent bond between fluorine and carbon known as the carbon-fluorine bond. Due to its partly ionic nature, it is one of the chemical world's strongest single bonds and is also relatively short.
It is a covalent bond between a carbon atom and a fluorine atom in a molecule. It is one of the strongest single bonds found in organic chemistry due to the high electronegativity of fluorine, which attracts electrons away from the carbon atom and makes the bond very polar.
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