Answer:
18 mol NH₃
General Formulas and Concepts:
Chemistry - Stoichiometry
Using Dimensional AnalysisExplanation:
Step 1: Define
RxN: N₂ (g) + 3H₂ (g) → 2NH₃ (g)
Given: 27 moles H₂
Step 2: Stoichiometry
\(27 \ mol \ H_2(\frac{2 \ mol \ NH_3}{3 \ mol \ H_2} )\) = 18 mol NH₃
Step 3: Check
We are given 2 sig figs.
Since our final answer is in 2 sig figs, we do not need to round.
what type of bonding is occuring in the compound below?
Answer:
D.Metallic
Explanation:
The metallic model is often characterized as a "sea of electrons". This is because the electrons delocalize from the ion's orbitals, allowing them to roam freely around the substance. This is what the model is showing.
If this helped, a brainliest would be greatly appreciated!
NO LINKS PLS HELP I WILL MARK THE BRAINIEST ANSWER
Answer:
Option a
Explanation:
simple
Answer:
The two solutions do not react with each other unless the water is boiled off, then the two will decompose.
Explanation:
How far can a S-wave travel in 16 minutes?
Answer:
1500 meters per second
Explanation:
which is 15 football fields
Answer:
1 to 8 km per second.
Determine the equilibrium constant for the following reaction at 298 K. CIO(g) + O2(g) → Cl(g) + O3(8) AG° = 34.5 kJ/mol 0.986 4.98 x 10-4 8.96 x 10-7 5.66 x 105 1.12 x 106
the equilibrium constant for the given reaction at 298 K is 8.96 x 10^-7.
The equilibrium constant for the given reaction, CIO(g) + O2(g) → Cl(g) + O3(g), at 298 K can be determined using the Gibbs free energy of the reaction and the following equation:ΔG° = - RT lnK
where ΔG° is the standard Gibbs free energy change, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.
The equation can be rearranged to solve for K:K = e^(-ΔG°/RT)where e is the natural logarithmic base, and all other variables are the same as in the previous equation.Substituting the given values,
we have:ΔG° = 34.5 kJ/molR = 8.314 J/(mol·K)T = 298 K
Using these values, we get:-
ΔG°/RT = (-34.5 × 10^3 J/mol) / (8.314 J/(mol·K) × 298 K)
= -13.19e^(-ΔG°/RT) = e^(-13.19) = 8.96 × 10^-7
Therefore, the equilibrium constant for the given reaction at 298 K is 8.96 x 10^-7.
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What type of system is a home, school, or room?
Answer:
room
Explanation:
because it'd in your house and u go there everyday and sleep and live there
what is the molarity of a solution consisting of 6.0 moles of nacl dissolved in a total 3.0l of solution
The molarity of a solution consisting of 6.0 moles of nacl dissolved in a total 3.0l of solution is 2.0 M.
The molarity of the solution is calculated by dividing the moles of solute by the volume of solution in liters. In this case, we have 6.0 moles of NaCl dissolved in a total volume of 3.0 liters of solution.
Therefore, the molarity of the solution is:
Molarity = moles of solute / volume of solution in liters
Molarity = 6.0 moles / 3.0 liters
Molarity = 2.0 M
So, by calculating the molarity of the solution, the result is 2.0 M (M stands for molar, which is a unit of concentration).
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Write one equation each for the decomposition reactions where energy is supplied in the form of (a) electricity and
Answer:
Electrolysis of water
Explanation:
The electrolysis of water is a decomposition reaction in which electricity is used to break down a compound into simpler molecules.
Decomposition of water is carried out in the Hofman Voltameter.
This process is achieved by passing current through an acidified water.
The expression is given as:
2H₂O → 2H₂ + O₂
Calculate ∆G° for a reaction for which ∆H° = 24. 6 kJ and ∆S° = 132 J/K at 298 K. Is the reaction spontaneous under these conditions?
The reaction of ∆G° is -14,736 J. A negative ∆G° indicates that the reaction can proceed spontaneously without the input of external energy.
To calculate ∆G° (standard Gibbs free energy change) for a reaction, we can use the equation:
∆G° = ∆H° - T∆S°
Given:
∆H° = 24.6 kJ
∆S° = 132 J/K
T = 298 K
First, we need to convert the units of ∆H° to match the units of ∆S° (kJ to J):
∆H° = 24.6 kJ = 24,600 J
Now, we can substitute the values into the equation to calculate ∆G°:
∆G° = 24,600 J - (298 K) * (132 J/K)
∆G° = 24,600 J - 39,336 J
∆G° = -14,736 J
Since ∆G° is negative (-14,736 J), the reaction is spontaneous under these conditions. A negative ∆G° indicates that the reaction can proceed spontaneously.
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Which of the following best describes an ethogram?
1) a graphical way to display the behaviour of an animal
2) a description of the behaviour performed by an animal at one point in time
3) an inventory of the behaviour of a particular species
4) the behaviour observed in response to an experimental intervention
Option 3 accurately represents the essence of an ethogram as an inventory of species-specific behaviors.
An ethogram can be best described as an inventory of the behavior of a particular species. It is a systematic catalog or list of behaviors exhibited by a specific animal species.
An ethogram provides a comprehensive overview of the behaviors displayed by the animals under study, documenting various activities, actions, and patterns of behavior.
While options 1 and 2 are related to visual representations or descriptions of behavior, they do not capture the comprehensive nature of an ethogram. Option 4 refers specifically to behaviors observed in response to an experimental intervention, which is more narrow in scope compared to an ethogram. Therefore, option 3 accurately represents the essence of an ethogram as an inventory of species-specific behaviors.
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1. Consider the generic reaction:A + 2BC AH = -55 kJDetermine the amount of heat emitted when each amountof reactant completely reacts (assume that there is morethan enough of the other reactant).(a) 1 mol A(b) 2 mol A(c) 1 mol B(d) 2 mol B
Answer:
(a) 55 kJ of heat are released when 1 mol of reactant A is used;
(b) 110 kJ of heat are released when 2 moles of reactant A are used;
(c) 27.5 kJ of heat are released when 1 mol of reactant B is used;
(d) 55 kJ of heat are released when 2 moles of reactant B are used.
Explanation:
The question requires us to determine the amount of heat released when the given amounts of reactants are used, considering the following balanced chemical equation:
\(A+2B\rightarrow C\text{ }\Delta H=-55kJ\)When the enthalpy change for a reaction (or heat of reaction, ΔH) is given in units of energy, such as kilojoules (kJ), and not units of energy per mol (such as kJ/mol), we can consider that ΔH corresponds to the heat absorbed or released for the molar quantities of reactants as given in the balanced chemical equation. In the case given by the question, for example, we can say that 55 kJ of energy are released when 1 mol of A reacts with 2 moles of B.
Therefore, we can use the molar quantitites from the balanced chemical equation as a reference to determine the amount of heat released when different amounts of reactants are used.
Considering the information above, we can calculate:
(a) heat released when 1 mol of A reacts:
Note that 1 mol of A corresponds to the amount of reactant A given by the balanced chemical equation. Therefore, 55kJ of energy are released when 1 mol of A is used.
(b) heat released when 2 moles of A reacts:
Note that 2 moles of A corresponds to the double of the amount of reactant A given by the balanced chemical equation. Thus, we must multply ΔH by 2: 55 kJ x 2 = 110 kJ of energy are released when 2 moles of A are used.
(c) heat released when 1 mol of B reacts:
Note that 1 mol of B corresponds to half of the amount of reactant B given by the balanced chemical equation. Thus, we must divide ΔH by 2: 55 kJ / 2 = 27.5 kJ of energy are released when 1 mol of B is used.
(d) heat released when 2 moles of B reacts:
Note that 2 moles of B corresponds to the amount of reactant B as given by the balanced chemical equation. Therefore, 55 kJ of energy are released when 2 moles of B are used.
how would you describe the different types of polymerization techniques and how do they produce different properties of polystyrene?
Emulsion polymerization is a radical polymerization technique that uses a monomer, emulsion-containing water, and a surfactant. Polystyrene for general use is transparent, rigid, and brittle.Per unit weight, it is a reasonably priced resin.
What methods are used to prepare polymers?However, a number of techniques, including desolvation, hemodialysis, ionic gelation, holding the other variables, solvent extraction, salting out, spray drying, and supercritical fluid, are employed to create polymeric nanoparticles.However, a number of considerations must be taken into consideration while choosing a strategy.
What equipment is employed in polymerization?Twin-screw extruders were created primarily to make mixing and compounding procedures easier, but they are also used as polymerization reactors.
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Compare the atomic and ionic radius of chlorine
Answer:
Explanation:
vdW radius (nm) ionic radius of X- (nm)
Cl 0.175 0.181
Br 0.185 0.196
I 0.198 0.220
Select all of the HOMOGENEOUS mixtures from this list (click all that apply).
A. Paint
B. Chili
C. Blood
D. Soil
E. Salt water
Answer:
E is answer
Explanation:
salt water is the answer
Answer:
E.Salt water
Explanation:
Salt water is a homogeneous because the dissolved salt is evenly distributed throughout the entire salt water sample. The amount of salt in the salt water can vary from one sample to another.
Hex-1-yne is a hydrocarbon with a terminal H-CEC-(alkyne) group. The remaining part of the molecule contains CH2 groups and a terminal CH, group. The IR spectrum of hex-1-yne, shows relatively strong absorptions at 3311, 2962, 2937, 2876 and 2120 cm-1 as well as absorptions below 1500 cm 1. Which bands are assigned to the CEC and terminal - C(alkyne) stretches? * O CEC, 3311 cm; H-C(alkyne), 2120 cm O C=, 2962 cm"1; H-C(alkyne), 3311 cm C=C, 2120 cm1; -C(alkyne), 2876 cm O CEC, 2120 cm; H-C(alkyne), 3311 cm
Based on the given information, the bands assigned to the CEC and terminal -C (alkyne) stretches are CEC, 3311 cm-1 and H-C(alkyne), 2120 cm⁻¹.
The given hydrocarbon, hex-1-yne, has a terminal H-CEC-(alkyne) group and the remaining part of the molecule contains CH2 groups and a terminal CH group. The IR spectrum of hex-1-yne exhibits several absorptions, and we need to determine which bands are assigned to the CEC and terminal -C(alkyne) stretches.
The absorptions provided in the IR spectrum are as follows:
3311 cm⁻¹2962 cm⁻¹2937 cm⁻¹2876 cm⁻¹2120 cm⁻¹Absorptions below 1500 cm⁻¹To assign the bands correctly, we need to analyze the stretching vibrations of the different functional groups in the molecule.
1. CEC (Carbon-Carbon Triple Bond) Stretch:
The stretching vibration of the CEC group typically appears in the region of 3300-3500 cm-1 in the IR spectrum. In this case, we have a relatively strong absorption at 3311 cm-1, which is within the expected range for a CEC stretch. Therefore, we can assign this band to the CEC stretch.
2. Terminal -C(alkyne) Stretch:
The stretching vibration of the terminal -C(alkyne) group, which is the carbon atom directly attached to the alkyne, is typically observed in the region of 2100-2300 cm-1. In the given spectrum, we have a relatively strong absorption at 2120 cm-1, which falls within this range. Thus, we can assign this band to the terminal -C(alkyne) stretch.
To summarize, the correct assignments for the CEC and terminal -C(alkyne) stretches in the given IR spectrum of hex-1-yne are as follows:
CEC Stretch: 3311 cm-1Terminal -C(alkyne) Stretch: 2120 cm-1Learn more about IR spectrum at:
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Activation energy is required to allow a reaction to progress.
Which circumstance lowers the activation energy increasing the reaction rate?
Responses
increasing the temperature
increasing the temperature
adding a catalyst
adding a catalyst
increasing the surface area of the particles
increasing the surface area of the particles
adding more reactant molecules
Activation energy is the energy required to allow a reaction to proceed. In order to increase the rate of a reaction, the activation energy must be lowered. The activation energy is by adding a catalyst to the reaction. A catalyst is a substance that increases the rate of a reaction without being consumed in the process. The correct option is b.
Firstly, increasing the temperature of the reaction can lower the activation energy required for the reaction to proceed. This is because increasing the temperature causes the particles in the reaction to move faster and collide more frequently, which increases the likelihood of successful collisions. This increase in energy can overcome the activation energy barrier and allow the reaction to proceed more quickly. Another way to lower the activation energy is by adding a catalyst to the reaction.
A catalyst is a substance that increases the rate of a reaction without being consumed in the process. Catalysts work by providing an alternative pathway with a lower activation energy for the reaction to proceed. Increasing the surface area of the particles involved in the reaction can also lower the activation energy. This is because a larger surface area means there are more particles available to collide and react with each other, which increases the likelihood of successful collisions and reduces the activation energy required for the reaction to proceed.
Finally, adding more reactant molecules to the reaction can also lower the activation energy. This is because an increase in the number of particles in the reaction increases the likelihood of successful collisions, which reduces the activation energy required for the reaction to proceed. The correct option is b.
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How do I determine the final temperature of the solution?
To calculate the final heat of your substance, add the temperature difference to its initial temperature. If your water started out at 24 degrees Celsius, the ultimate temperature would be 24 Plus 6, or 30 degrees Celsius.
What is relationship between temperature and pressure?The connection between atmospheric pressure and a location's temperature is exactly proportional to each other. The warmth of a location raises as the atmospheric pressure climbs.
Calculate the pressure-temperature ratio: k = p1/T1. By multiplying any temperature by k, you can calculate the equivalent pressure in the same container: p2 = k T2. T2 = p2/k is the temperature calculated by dividing each pressure number by k.
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which of the following atomic symbols is not correctly named? group of answer choices ge - germanium mn - manganese s - sodium se - selenium all of the answers are correct
The following incorrect atomic symbol is s - sodium where the correct atomic symbol of sodium is Na.
The stable isotope of sodium, sodium-23, has a nuclear spin of 3/2, a nuclear abundance of 100%, and a relative atomic mass of 22.989770. an elemental metal from the alkali group. Its atomic weight is 23, atomic number 11, and atomic symbol are Na. Na, derived from the sodium synonym natrium, is the chemical symbol for sodium. Sodium is a chemical element with the atomic symbols Na, 11, and 23. An alkali metal atom is one like sodium. In order to determine whether a person's sodium uptake levels are within normal ranges, sodium 24 is employed as an electrolyte tracer, whereas sodium 22 is used in nuclear medicine imaging for positron emission tomography. There are non-medical uses for sodium-24 as well.
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Plsssssssssssssssssssss answerrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr
The finding of the ocean clams in the rocks of the Appalachian Mountains most likely indicates that: A. These mountains were once under the ocean.
What are imprint fossils?Imprint fossils are remains of dead plants and animals that are indicative of the existence of some species and the ways these animals existed.
The imprint fossils of the ocean clams that were found close to the Appalachian mountains indicate that the mountains were once under the oceans and carried the clams with them as they erupted.
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if 3.97 g ar are added to 2.29 atm he in a 2.00 l cylinder at 27.0 °c, what is the total pressure of the resulting gaseous mixture?
To solve this problem, we need to use the ideal gas law equation:
PV = nRT
where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature.
First, we need to calculate the number of moles of each gas in the cylinder. We can use the formula:
n = m/M
where n is the number of moles, m is the mass of gas, and M is the molar mass of the gas. The molar mass of helium (He) is 4.00 g/mol, and the molar mass of argon (Ar) is 39.95 g/mol.
For helium:
n = 2.29 atm x 2.00 L / (0.0821 L·atm/mol·K x 300 K)
n = 0.182 mol
For argon:
n = 3.97 g / 39.95 g/mol
n = 0.0994 mol
Now, we can calculate the total number of moles of gas:
n_total = n_He + n_Ar
n_total = 0.182 mol + 0.0994 mol
n_total = 0.281 mol
Next, we can use the ideal gas law equation to calculate the total pressure:
P_total = n_total x R x T / V
where R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin (27.0 °C + 273 = 300 K).
P_total = 0.281 mol x 0.0821 L·atm/mol·K x 300 K / 2.00 L
P_total = 10.5 atm
Therefore, the total pressure of the resulting gaseous mixture is 10.5 atm.
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PLEASE ANSWER SOON THIS IS DUE IN LIKE, 5-10 MINS
Which pair have the same electron configuration? You may use the periodic chart
Cl- and Ar
Cl and Ar
Cl- and Ar-
Cl+ and Ar
This landscape region is best classified as an eroded
A. Plain
B. Plateau
C. Domed mountain
D. Folded lowland
The landscape region is best classified as an eroded Plain. plateaus are elevated flat areas with steep sides, often created by volcanic activity or tectonic forces.
An eroded landscape refers to a landform that has been worn down and shaped by natural forces such as water, wind, and ice over a long period of time. A plain is a flat or gently rolling landform that has undergone extensive erosion, resulting in a smooth and relatively featureless surface.
Plains are often characterized by their low elevation, wide expanses, and lack of significant topographical variations. They are typically found in areas where erosion has removed layers of rock or soil, leaving behind a level surface. Examples of plains include the Great Plains in North America and the Pampas in South America.
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12.42 m +421.0 m + 9.28 m -
Answer:
442.7m
Explanation:
12.42m+421.0m+9.28
442.7m
Determine the required heat in BTU, for the water at 50 deg celcius
to become ice at -50 deg celcius.
4 decimals please. ty
The required heat in BTU, for the water at 50°C to become ice at -50°C is 209 BTU/lb.
To determine the required heat in BTU, for the water at 50°C to become ice at -50°C, we need to calculate the heat of fusion and the heat of cooling of water. We can use the following formula to calculate the required heat.
Q = mL
Where:Q is the required heat in BTU.
m is the mass of water in pounds.L is the specific heat of water at the desired temperature.
Lf is the heat of fusion of water.
Lc is the specific heat of ice.
Using the above formula, we get;
Q = mLf + mL + mLc
The heat of fusion of water is 144 BTU/lb
The specific heat of water at 50°C is 1.00 BTU/lb °F.
The specific heat of ice is 0.5 BTU/lb°F.
We know that: 1°C = 1.8°F.
So,50°C = 122°F and -50°C = -58°F
Also, the mass of water is not given, so let us assume that the mass of water is 1 lb.
Thus;
Q = mLf + mL + mLc
Q = 1(144) + 1(1.00)(122-32) + 1(0.5)(-50-0)
Q = 144 + 90 + (-25)
Q = 209 BTU/lb
Therefore, the required heat in BTU, for the water at 50°C to become ice at -50°C is 209 BTU/lb.
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Help me plz I don’t know what it’s mean
Answer:
1 has the highest density because it has the most amount of circles in the least amount of space- it is the most densely filled with circles; it is the most dense.
Answer:
image 1 would have the highest density
Explanation:
the closer the molecules are the more solid an object is. if the molecules are far apart and rarely bump into eachother, it is more gaseous. the object in the middle (2) is a liquid
water contributes to mass movement in of all of the following ways except to group of answer choices fill pore spaces between particles which disrupts cohesion reduce friction between particles cement particles together add weight to the mass of the material
3) Cement particles together: Water does not physically or chemically bind particles together.
Instead of binding particles together, it weakens the cohesion between them, making them more likely to move under the influence of gravity in processes such as landslides, mudflows, and creep.
When water enters the pore spaces between particles, it can increase the pore pressure and reduce the friction between particles, making them less stable.
This can cause soil particles to become saturated and start to move, resulting in the mass movement. Additionally, water adds weight to the mass of the material, making it more susceptible to mass movement.
Hence, the correct choice is to Cement particles together.
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What subatomic particles cause the mass of the atom to change?
Subatomic particles that cause the mass of an atom to change are called isotopes. Isotopes are atoms of the same element that have an unequal number of neutrons in their nuclei.
This difference in the number of neutrons causes the mass of the atom to vary. For example, the most common form of carbon is Carbon-12, which has an atomic mass of 12 and contains 6 protons and 6 neutrons, while Carbon-14 has an atomic mass of 14 and contains 6 protons and 8 neutrons. The extra two neutrons make Carbon-14 slightly heavier than Carbon-12. The number of neutrons in an atom is determined by the number of protons and the element's atomic number, so when the number of neutrons changes, the mass of the atom changes as well. Isotopes can be naturally occurring or artificially created, and their properties may vary depending on the number of neutrons in the nucleus. Overall, isotopes are subatomic particles that cause the mass of the atom to change.
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Place the following in increasing atomic radius:
Least to most
Explanation:
least= Li,F,N,He,Ca,O
medium=N,Br,K,Ne,Zn,Fr
most= F,I,K,Kr,Br,Ga
he nucleus of an atom is small compared to the size of the atom. why is this consistent with rutherford's nuclear theory? the nucleus of an atom is small compared to the size of the atom. why is this consistent with rutherford's nuclear theory? rutherford's nuclear theory states that most of the mass of an atom and all of its electrons are contained in a small core called the nucleus. rutherford's nuclear theory states that the nucleus of an atom is small compared to the size of the atom, and, therefore, the nucleus has a relatively low mass compared to the mass of an atom. rutherford's nuclear theory states that the nucleus is small but contains about half of the mass of an atom. rutherford's nuclear theory states that most of the mass of an atom and all of its positive charge are contained in a small core called the nucleus. request answer
The nucleus of an atom is small compared to the size of the atom because of Rutherford's nuclear theory. Rutherford's nuclear theory states that most of the mass of an atom and all of its positive charge are contained in a small core called the nucleus.
This statement is consistent with the fact that the nucleus of an atom is small compared to the size of the atom. Rutherford's nuclear theory states that the nucleus of an atom is small compared to the size of the atom, and, therefore, the nucleus has a relatively low mass compared to the mass of an atom.
Rutherford's nuclear theory states that the nucleus is small but contains about half of the mass of an atom. The nuclear theory was discovered by Ernest Rutherford in 1911.
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What is the temperature and pressure at STP?
Answer:
Since 1982, STP is defined as a temperature of 273.15 K (0 °C, 32 °F) and an absolute pressure of exactly 105 Pa (100 kPa, 1 bar).
Explanation:
I hope I helped
Which statement defines the heat capacity of a sample?
the temperature of a given substance
the temperature that a given sample can withstand
the quantity of heat that is required to raise the sample’s temperature by 1°C (or Kelvin)
the quantity of heat that is required to raise 1 g of the sample by 1°C (or Kelvin) at a given pressure
Answer:
b
Explanation:
Answer:
D. the quantity of heat that is required to raise 1 g of the sample by 1°C (or Kelvin) at a given pressure
Explanation: