The standard deviation in the first sample was $20,00 and the standard deviation in the second sample is $18,000 so the agent's claim cannot be rejected at the 0.05 level of significance.
To test the agent's claim, we can perform a two-sample t-test with a significance level of 0.05. The null hypothesis is that there is no difference in the mean salaries of safeties and linebackers, while the alternative hypothesis is that there is a difference.
We can calculate the t-statistic using the formula:
t = (x1 - x2) / sqrt(s1²/n1 + s2²/n2)
where x1 and x2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.
Plugging in the given values, we get:
t = (501580 - 513360) / sqrt((20000²/15) + (18000²/15))
t = -1.2605
Using a t-distribution table with 28 degrees of freedom (15 + 15 - 2), we find that the critical value for a two-tailed test at a significance level of 0.05 is approximately ±2.048.
Since the absolute value of the calculated t-statistic (1.2605) is less than the critical value (2.048), we fail to reject the null hypothesis. Therefore, there is not enough evidence to conclude that there is a difference in the mean salaries of safeties and linebackers in the NFL.
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Heather and Jerry both bought rose bushes and geraniums at the same store. - Heather spent \( \$ 74.50 \) on 4 rose bushes and 3 geraniums. - Jerry Spent 99.50 on 7 rose bushes and 2 geraniums
What is the cost of one Bush?
What is the cost of one Geranium?
The cost of one Rose bush is $11.5 and cost of one Geranium is $9.5
What is Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given:
let the cost of rose bushes be x and y be the cost of Geraniums.
So, the system of Equation is
4x + 3y= 74.5
and, 7x+ 2y= 99.5
Solving above Two Equation
x= 11.5 and y= 9.5
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The first term in a geometric series is 555 and the common ratio is 222. Find the sum of the first 101010 terms in the series.
The first 10 terms sum in the geometric series is 5115.
The first term of geometric series = 5
Common ratio = 2
First, let us discuss how to calculate the sum of n terms of GP. Assume the sum of the first n terms of a GP with first term a and common ratio r. Then the first 'n' terms of GP are of form a, ar, ar², ... ar^(n-1). Let S be the sum of the GP of n terms. Then:
Sₙ = a + ar + ar² + ... + ar^(n-1) ... (1)
Multiply both sides by r:
rSₙ = ar + ar² + ... + arⁿ ... (2)
Subtracting equation (1) from equation (2):
rSₙ - Sₙ = (ar + ar² + ... + arⁿ) - [a + ar + ar² + ... + ar^(n-1)]
Sₙ (r - 1) = arⁿ - a
Sₙ (r - 1) = a(rⁿ - 1)
Sₙ = a(rⁿ - 1)/(r - 1)
Note that, here, r ≠ 1.
Sₙ = -a(1 - rⁿ)/(-(1 - r)) = a(1 - rⁿ)/(1 - r).
Sₙ = a[1-rⁿ]/[1-r]
S₁₀ = 5[1-2¹⁰]/[1-2]
S₁₀ = 5[1023]
S₁₀ = 5,115
--The given question is incorrect, the correct question is
"The first term in a geometric series is 5 and the common ratio is 2. Find the sum of the first 10 terms in the series."--
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An ash borer is an invasive pest whose larvae eat the pulp of ash trees as they mature. A park ranger has a tree that is infested with ash borers. She estimates they have eaten approximately 40% of the tree's pulp. If the ash tree's trunk has a radius of 2 feet and a height of 15 feet, what was the total volume of the tree trunk before the ash borers started eating it?
Answer:
\(188.6\) cubic feet
Step-by-step explanation:
Let r, h denotes radius and height of the tree's trunk.
Radius of the tree's trunk = 2 feets
Height of the tree's trunk = 15 feets
The tree's trunk is in the shape of a cylinder.
Volume of cylinder (tree's trunk) \(=\pi r^2h\)
Put \(r=2\,,\,h=15\)
Volume of the tree's trunk \(=\pi (2)^2(15)=60\pi\) cubic feet
Put \(\pi=\frac{22}{7}\)
So,
Volume of the tree's trunk \(=60(\frac{22}{7})=\frac{1320}{7}=188.6\) cubic feet
What are the solutions for the equation 2x^2+36=0.
A) x=+/- 6
B) x=+/- 6i
C) x=+/- 3 sqrt 2
D) x= +/- 3i sqrt 2
Answer:
the answer is x=+/- 3 sqrt 2
- x/7 − 8 = 17
Show work
And check
Answer:
x = -175
Step-by-step explanation:
Given:
⇒ \(-\frac{x}{7}-8=17\)
Solution:
Work:
\(-\frac{x}{7}-8=17\)
\(-\frac{x}{7}-8+8=17+8\) ⇒ Add 8 to both sides
\(-\frac{x}{7}=25\)
\(7\left(-\frac{x}{7}\right)=25\cdot \:7\) ⇒ Multiply both sides by 7
-x = 175
\(\frac{-x}{-1}=\frac{175}{-1}\) ⇒ Divide both sides by -1
x = -175
Check:
Since, x = -175. We can substitute into the equation to check.
\(-\frac{-175}{7}-8=17\)
\(-\frac{-175}{7}=25\)
\(25-8=17\) ⇒ Statement = True (25 minus 8 is 17.
Hence, x = -175
Lenvy~
Il. John bought two t-shirts and a pair of shorts at the mall. Each t-shirt cost the same amount. The pair of shorts cost $12.50. Which inequality could be used to find the cost, x, of the t-shirts if James did not spend more than $50? A 2x + 12.50 < 50 B. +12.50 > 50 C. 50 >x + 12.50 D. 2x + 12.50 > 50
ANSWER
C. 50 > x + 12.50
EXPLANATION
We have that the price of each t-shirt is the same and the pair of shorts cost $12.50.
Let the price of the t-shirts John bought be x.
We have that John did not speand more than $50.
This means that, if we add the prices of the t-shirts and the pair of shorts, it must be less than $50.
Therefore, the inequality is:
x + 12.50 < 50
This is not among the options, but we can rewrite it as:
50 > x + 12.50
That is the answer. Option C.
21 500 ml + 31 650 ml
Answer:
53,150 ML
Simply add both of the numbers and you have your answer.
Members of a lacrosse team raised $1352.50 to go to a tournament. They rented a bus for $802.50 and budgeted $25 per player for meals. Write and solve an equation which can be used to determine p, the number of players the team can bring to the tournament.
Answer: 22
Step-by-step explanation:
From the question the, we are informed that members of a lacrosse team raised $1352.50 to go to a tournament and that they rented a bus for $802.50 and budgeted $25 per player for meals.
The equation which can be used to determine p, the number of players the team can bring to the tournament would be calculated as:
802.50 + 25p = 1352.50
25p = 1352.50 - 802.50
25p = 550
p = 550/25
p = 22
They can bring 22 players to the tournament
Answer:22
Step-by-step explanation:
Select the correct answer. For what purpose are goods and services produced in a socialist economy? A. profits B. their usefulness C. to create demand D. to meet all consumer needs
Answer: B. their usefulness
Step-by-step explanation: A socialist economy may be described as a system whereby factors of production including goods and services are generally explored and processes in other to serve and benefit the people. In socialism, resources are deemed to be owned by all members of the public and as such total control resides with the government who makes decision on production, processing and sales of the resources to serve useful benefit for the people. The socialist econmoy opposes the capitalist form of government whereby goods and services are generated in other to yield profit.
please help will mark brainlest!!
Answer:
11
Step-by-step explanation:
The angles will equal 180.
Thus, the equation is 9x-5+6x+20=180.
15x+15=180.
15x=165.
divide by 15 on both sides, x = 11.
74.55 divided by 5
I’m not sure of the answer I need some help
Answer:
14.91
Step-by-step explanation:
Have a good day :)
Answer:
The answer is 14.91
Step-by-step explanation:
To find the answer we must first see how many times 5 can go into 74.55. Since 5 x 14.91 = 74.55, then it means that our answer is 14.91.
HEEEEEELLLLLLPPPPPPPPP
Answer:
Side JL corresponds with FG
Step-by-step explanation:
because they are both the same length. it is just turned.
Find the missing value so
that the two points have a
slope of 2/7.
(-1,-1) and (x,1)
Answer:
x = 6
Step-by-step explanation:
Slope = (y(2) - y(1))/(x(2) - x(1))
(-1 - 1) / (-1 - x)
If the slope is 2/7, it would be (-2/-1-x, where x would have to be 6)
(-2)/(-7) = 2/7, so x = 6
Check:
(-1 - 1) / (-1 - 6)
(-2)/(-7)
2/7 (Correct :))
Hope it helps :D
On the line that passes through point C, mark a point D that is distinct from point C. Use the slope formula along with coordinates of points to find the slopes of and . Show your work.
Answer:
PLATO
Step-by-step explanation:
Answer:
The coordinates of point D will vary based on the point location, but the resulting slope of the line through points C and D will be the same.
A = (-3, 3), B = (-1,-1)
Slope of AB = (YB−YA) / ( XB –XA) =−1−3 / −1−(−3)= − 4 / 2= −2
D = (-1,6), C = (1,2)
Slope of DC = (YC−YD) / (XC−XD)= 2 – 6 / 1−(−1)=−4 / 2=−2
Step-by-step explanation:
two number cubes are rolled. Deterimine the number of ways that you could get a sum that is less than 5. The number cube is out of 6
Answer: six ways
Step-by-step explanation: The pairs when the cube is rolled that are less than five would be; (1,1), (1,2), (1,3), (2,1), (2,2), (3,1) since each cube is out of six.
You are working with a satellite image of Anchorage, AK (∼150
∘
W) with the time stamp 0300Z, Dec. 3 2011. This means that it was 3AM on Dec. 3 at the Prime Meridian when the image was taken. What was the local time and day in Anchorage when the image was taken?
the local time in Anchorage when the image was taken was 5:00 PM, and the local day was Dec. 2, 2011.
To determine the local time and day in Anchorage when the satellite image was taken, we need to consider the time difference between the Prime Meridian (0 degrees longitude) and Anchorage, Alaska (approximately 150 degrees west longitude).
Each time zone is approximately 15 degrees wide, representing a one-hour difference in local time. Anchorage is in the Alaska Standard Time (AKST) zone, which is typically UTC-9 (nine hours behind UTC) during standard time.
Given that Anchorage is about 150 degrees west of the Prime Meridian, we can calculate the time difference as follows:
150 degrees / 15 degrees per hour = 10 hours
Therefore, when the image was taken at 0300Z (3:00 AM), Dec. 3, 2011, at the Prime Meridian, the local time and day in Anchorage were:
3:00 AM - 10 hours = 5:00 PM, Dec. 2, 2011
So, the local time in Anchorage when the image was taken was 5:00 PM, and the local day was Dec. 2, 2011.
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Find the Lowest Common Multiple (LCM) of 35 and 33.
Answer:
Step-by-step explanation:
LCM of 35 and 33 is 1125.
The numbers 33 and 35 do not have any common divisors, they are not divided by any numbers.
so they get multiple i.e 33*35=1125.
Members of a school sports team are raising money by selling custom water bottles at school activities. They plan to sell each bottle for $13. Each bottle costs them $6. They spend $40 for advertising. Use n to represent the number of bottles they sell. Multiply this by the money they make for each bottle, then subtract the advertising cost. Which expression represents the money that the group raises? O A. 40 - (13 - 6)n O B. (13 - 6) n - 40 O C. 13n - 6 - 40 D. 13-on-40
Answer:
B. (13 - 6)n - 40
Step-by-step explanation:
If each bottle costs them $6 and they are selling each one for $13, the amount of money they make for each bottle can be represented by (13 - 6)n
This is because this finds the profit per bottle, then multiplies it by n, which is the number of bottles they sell.
Then, since they spent $40 on advertising, subtract 40 from this.
The expression will be (13 - 6)n - 40.
The correct answer is B. (13 - 6)n - 40
The expression represents the money that the group raises is (13-6)n - 40
What is expression?An expression is a combination of terms that are combined by using mathematical operations such as subtraction, addition, multiplication, and division.
According to the question
Members of a school sports team are raising money by selling custom water bottles at school activities.
Let number of bottle they sell = n
Selling price of a bottle = $13
Now ,
Selling price of n bottle = $13n
Cost price of a bottle = $6
Now ,
Cost price of n bottle = $6n
Money spent on advertising = $40
Total they spent on bottles = $6n + $40
Therefore,
Money they raise in expression = 13n - 6n - 40
= (13-6)n - 40
Hence, The expression represents the money that the group raises is (13-6)n - 40
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what is the slope of the blue line and the green line simplified
Answer:
1
Step-by-step explanation:
The slope can be found using the RISE/RUN equaton.
Looking at both graphs we see that they are parallel so that tells us that they have the same slope.
We can count how many boxes up and then how many boxes right this line goes to find the slope.
We also know that the slope is positive because the lines are increasing from left to right.
If you have a hypotenuse that measures 13 inches, what do the side lengths need to be to create a right
triangle?
13 inches and 1 inch
12 inches and 10 inchas
12 inches and 5 inches
6 inches and 5 inches
Answer:
12 and 5 inches since squaring them would equal 144+25, which is 169, and ✓169=13. the two legs have to equal the hypotenuse when combined to be a right triangle.
I’ll give brainliest to anyone who can help me with this. Basically you have to state whether or not the number is a solution to the given inequality.
Answer:
-4/9 IS a solution
Step-by-step explanation:
-2/3 = -6/9
-4/9 is greater than -6/9
Therefor -4/9 IS a solution to the inequality
1. (8 points) Find the function \( f \) provided \( f^{\prime \prime}(x)=12 x^{2}-12 x+3, f^{\prime}(1)=3 \), and \( f(1)=5 \).
The function \(f(x) = x^4 - 2x^3 + (3/2)x^2 + 2x - 1/2\) satisfies the given conditions f(1) = 5 by integrating functions twice f(x) given \(f''(x) = 12x^2 - 12x + 3, f'(1) = 3,\) and \(f(1) = 5\)
The function f(x) given \(f''(x) = 12x^2 - 12x + 3, f'(1) = 3,\) and \(f(1) = 5\) is\(f(x) = x^4 - 2x^3 + (3/2)x^2 + 2x - 1/2.\)
To find the function f(x), we need to integrate the given second derivative twice.
By integrating \(f''(x) = 12x^2 - 12x + 3\) gives,
\(f'(x) = 4x^3 - 6x^2 + 3x + C_1.\)
Using the initial condition \(f'(1) = 3\), solve for the constant of integration. Plugging in x = 1, gives
\(4(1)^3 - 6(1)^2 + 3(1) + C_1 = 3.\)
Simplifying, we find
\(C_1 = 2.\)
Integrating \(f'(x) = 4x^3 - 6x^2 + 3x + 2\), gives
\(f(x) = x^4 - 2x^3 + (3/2)x^2 + 2x + C_2.\)
Substituting the initial condition f(1) = 5, solve for \(C_2\). Substituting x = 1, gives,
\((1)^4 - 2(1)^3 + (3/2)(1)^2 + 2(1) + C_2 = 5.\)
Simplifying, we find
\(C_2 = -1/2.\)
Therefore, the function \(f(x) = x^4 - 2x^3 + (3/2)x^2 + 2x - 1/2\) satisfies the given conditions by integrating functions twice f(x) given \(f''(x) = 12x^2 - 12x + 3, f'(1) = 3,\) and \(f(1) = 5\)
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What is the probability that either event will occur?
15
A
17
B
2
P(A or B) = P(A) + P(B)
P(A or B) = [?]
The probability that either event will occur is 0.83
What is the probability that either event will occur?From the question, we have the following parameters that can be used in our computation:
Event A = 18
Event B = 12
Other Events = 6
Using the above as a guide, we have the following:
Total = A + B + C
So, we have
Total = 18 + 12 + 6
Evaluate
Total = 36
So, we have
P(A) = 18/36
P(B) = 12/36
For either events, we have
P(A or B) = 30/36 = 0.83
Hence, the probability that either event will occur is 0.83
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If a food item with an original (AP) weight of 4 pounds at a cost of $1.10 per pound yields a servable weight of 2 pounds, what is the cost per servable pound for this food item? a. $0.50 b. $1.50 c. $2.20 d. $4.40
Given that the cost is $1.10 per pound, we can calculate the cost per servable pound by dividing the total cost ($1.10 * 4 pounds) by the servable weight (2 pounds). Therefore, the correct option is c. $2.20.
The original weight of the food item is 4 pounds, and the cost per pound is $1.10. Therefore, the total cost of the food item is 4 pounds * $1.10 = $4.40.
The servable weight of the food item is 2 pounds. To find the cost per servable pound, we divide the total cost ($4.40) by the servable weight (2 pounds):
Cost per servable pound = Total cost / Servable weight = $4.40 / 2 pounds = $2.20.
Hence, the cost per servable pound for this food item is $2.20. Therefore, the correct option is c. $2.20.
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And here is another question. Thanks for the help y'all
Answer:
Multiply 3.75 times 1.5
Step-by-step explanation:
What did I do wrong here in my answer?
Answer:
please see the attached I put the answer
Step-by-step explanation:
you answer were correct but you change the sign one of them will be positive.
Graph of triangle ABC in quadrant 3 with point A at negative 8 comma negative 4. A second polygon A prime B prime C prime in quadrant 4 with point A prime at 4 comma negative 8. 90° clockwise rotation 180° clockwise rotation 180° counterclockwise rotation
The rotation rule used in this problem is given as follows:
90º counterclockwise rotation.
What are the rotation rules?The five more known rotation rules are given as follows:
90° clockwise rotation: (x,y) -> (y,-x)90° counterclockwise rotation: (x,y) -> (-y,x)180° clockwise and counterclockwise rotation: (x, y) -> (-x,-y)270° clockwise rotation: (x,y) -> (-y,x)270° counterclockwise rotation: (x,y) -> (y,-x).The equivalent vertices for this problem are given as follows:
A(-8,-4).A'(4, -8).Hence the rule is given as follows:
(x,y) -> (-y,x).
Which is a 90º counterclockwise rotation.
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70 pupils in a sports centre are surveyed. The pupils can only use the swimming pool and the gym. 28 pupils use the swimming pool and the gym. 48 pupils use the swimming pool. 39 pupils use the gym. Find the probability to select a pupil that uses neither the swimming pool nor the gym.
The probability that a pupil uses neither pool nor gym is 11/70
What is Probability?Probability is the likelihood that an event will happen. This can range from an event being impossible to some likelihood to being absolutely certain. In math terms, probability is on a scale from 0 to 1. Zero means the event is impossible, like rolling a seven on a die that only has digits from 1 to 6.
Number of pupil that can use pool and gym = 28
Number of people that can use pool = 48
Number of people that can use gym = 39
Number of people that can use pool only = 48 - 28 which is 20
Number of people that can use gym only = 39 - 28 = 11
Total number of persons that can use either pool, gym or both = 20 + 11 + 28 which is 59
Number of people that cannot use either or both of the facilities = 70 - 59 which is 11.
Probability = required outcome / possible outcome
Required outcome = 11
possible outcome = 70
Probability = 11/70
In conclusion, the probability that a pupil uses neither swimming pool nor gym is 11/70
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The lengths, in minutes, of the movies currently showing at a movie theater are shown in the data set. Create a histogram that represents the data. Drag the top of each bar to the correct height.
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the required lengths are not given.
I will use the following data set to answer the question.
\(Dataset: 35, 51, 39, 42, 68, 62, 32, 59\)
First, is to determine the range of the dataset
\(Range = Highest - Least\)
\(Range = 68 - 32\)
\(Range = 36\)
Next, we will make use of 4 classes. So, we divide range by 10 to get the number of class. 10 represents the interval
\(Class= Range/10\)
\(Class = 36/10\)
\(Class = 3.6\)
\(Class \approx 4\)
So, we use 4 classes
Plot the frequency distribution table as follows:
\(\begin{array}{ccc}{Intervals} & {Observations} & {Frequency} & {31-40} & {32,35,39} & {3} & {41-50} & {42} & {1} & {51-60} & {51,59} & {2} & {61-70} & {62,68} & {2}\ \end{array}\)
See attachment for histogram
you want to find the median weight of the apples in a barrel. what do you need to do
To find the median weight of the apples in a barrel, you need to follow a specific process. You would need to sort the weights of all the apples in ascending order and then determine the middle value.
In more detail, here's how you can find the median weight:
1. Collect the weights of all the apples in the barrel.
2. Arrange the weights in ascending order, from the smallest to the largest.
3. If the number of apples is odd, the median weight is the weight of the apple in the middle of the sorted list.
4. If the number of apples is even, the median weight is the average of the two middle weights.
5. Calculate the median weight using the appropriate method based on the number of apples.
6. Round the median weight to the desired precision if necessary.
By following these steps, you can determine the median weight of the apples in the barrel, providing you with a measure of the central tendency for the apple weights.
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