An airplane of mass 13300 kg is flying in a straight line at a constant altitude and with a speed of 560.0 km/hr. The force that keeps the airplane in the air is provided entirely by the aerodynamic lift generated by the wings. The direction of this force is perpendicular to the wing surface. Calculate the magnitude of the lift generated by the wings of this airplane.

The required period remains the same when mass is doubled, if the length is doubled, the time period becomes 4.95 s, if the length is halved, period becomes 2.475 s and the period of the oscillation is independent of the amplitude.

The period of oscillation is given as 3.5 s.

The period is independent of mass.

So, the period remains the same 3.5 s when mass is doubled.

We know the expression for period and length as,

T = 2π √(l/g)

T₁/√l₁ = T₂/√l₂

T₂ = T₁ √l₂/l₁ = 3.5 √2l₁/l₁ = 3.5 √2 = 4.95 s

So, if the length is doubled, the time period becomes 4.95 s.

When the length is halved, the period becomes,

l₂ = l₁/2

T₂ = T₁ √l₂/l₁ = 3.5 √l₁/2l₁ = 3.5 × 1/√2 = 2.475 s

So, if the length is halved, period becomes 2.475 s.

The oscillation's period is independent on its magnitude.

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The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Generally, the relationship between temperature, density and rate of vertical pressure is given as;

\(\rho = \frac{PM}{RT}\)

\(\frac{dP}{dz} = -\rho g\\\\\)

where;

Thus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

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As the book fell through the air and eventually hit the ground, the energies  of the system were converted from one form to another.

Option D is correct.

Energy is described as  the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.

The forms of energy includes:

Chemical energy.

Electrical Energy.

Mechanical Energy.

Thermal energy.

Nuclear energy.

Gravitational Energy.

In conclusion, When the book fell through the air and hit the ground, the potential energy it possessed due to its position above the ground was converted into kinetic energy as it accelerated towards the ground.

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To find the magnitude of the velocity, we can use the law of cosines. The law of cosines states that in a triangle, the square of one side (c) is equal to the sum of the squares of the other two sides (a and b), minus twice the product of the two sides (a and b) multiplied by the cosine of the included angle (θ).

In this case, we have a triangle with sides a, b, and c, and angles θ1 and θ2.

Given:

Sum of velocities (c) = 4.5 m/s

Angle θ1 = 32.4°

Angle θ2 = 22.4°

We can write the equation for the law of cosines as follows:

c² = a² + b² - 2ab * cos(θ)

We want to find the magnitude of the velocity, which is equivalent to the length of side c.

Plugging in the given values, we have:

(4.5 m/s)² = a² + b² - 2ab * cos(θ)

Simplifying and rearranging the equation, we have:

a² + b² - 2ab * cos(θ) = 20.25

Now, we need to find the values of a and b. We can use trigonometric relationships to express a and b in terms of the given angles and the magnitude of the velocity.

a = c * cos(θ1)

b = c * cos(θ2)

Plugging in the given values, we have:

a = 4.5 m/s * cos(32.4°)

b = 4.5 m/s * cos(22.4°)

Now, substitute the values of a and b back into the rearranged equation:

(4.5 m/s * cos(32.4°))² + (4.5 m/s * cos(22.4°))² - 2 * (4.5 m/s * cos(32.4°)) * (4.5 m/s * cos(22.4°)) * cos(θ) = 20.25

Simplify the equation and solve for cos(θ):

cos(θ) = (20.25 - (4.5 m/s * cos(32.4°))² - (4.5 m/s * cos(22.4°))²) / (2 * (4.5 m/s * cos(32.4°)) * (4.5 m/s * cos(22.4°)))

Calculate the value of cos(θ) using a calculator.

Finally, calculate the magnitude of the velocity by taking the square root of both sides of the equation:

velocity = √(a² + b² - 2ab * cos(θ))

Evaluate the expression to find the numeric value of the magnitude of velocity in meters per second.

Two identical metal spheres carry charges of + q and - 2q respectively.

It is given that initially sphere has different charges and momentarily brought in contact with each other.

When the spheres are touched then charge is equally redistributed among spheres such that now they possess the equal amount of charges.

When they are suspended from the thread their separation increases compared to previous situation because now the value of force increases because of the change in the product of charges.

For example, Suppose initially they possess 15 C and 17 C charge and after redistribution they both possess 16 C  of charge.

Product of charges=15*17=255

Final Product of charges=16*16=256

As force depends upon the Product of the charges so there will be more repulsive force.    

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Answer:

v₁ = √[ 2gh / ((A₁ / A₂)² − 1) ]

Explanation:

Use Bernoulli's equation:

P₁ + ½ ρ v₁² + ρgz₁ = P₂ + ½ ρ v₂² + ρgz₂

Since there's no elevation change between points 1 and 2, z₁ = z₂.

P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²

Assuming incompressible fluid, the volumetric flow rate is the same at points 1 and 2.

Q₁ = Q₂

v₁ A₁ = v₂ A₂

v₂ = v₁ A₁ / A₂

Substituting:

P₁ + ½ ρ v₁² = P₂ + ½ ρ (v₁ A₁ / A₂)²

P₁ + ½ ρ v₁² = P₂ + ½ ρ v₁² (A₁ / A₂)²

P₁ − P₂ = ½ ρ v₁² (A₁ / A₂)² − ½ ρ v₁²

P₁ − P₂ = ½ ρ v₁² ((A₁ / A₂)² − 1)

v₁² = 2 (P₁ − P₂) / (ρ ((A₁ / A₂)² − 1))

v₁² = 2 (ρgh) / (ρ ((A₁ / A₂)² − 1))

v₁² = 2gh / ((A₁ / A₂)² − 1)

v₁ = √[ 2gh / ((A₁ / A₂)² − 1) ]

Answer:

True

Explanation:

Opposites point in opposite directions

Answer: 1. B, 2. A, 3. C, 4. D

Answer:

1 = B

2 = A

3 = C

4 = D

I hope this helps

Answer:

Mass and Acceleration

Explanation:

The typical Force equation is:

F = ma

where m = mass, and a=acceleration.

Answer:

Gravity is the main force responsible for mass movements. Gravity is a force that acts everywhere on the Earth's surface, pulling everything in a direction toward the center of the Earth

Explanation:

Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.

Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:

1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.

2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.

3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.

4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.

These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.

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Explanation:

When hot water is poured on the can in a bucket of cold water, the can crushes off means it gets unshaped

Answer:

8m/s^2

Explanation:

hope it helps........

Explanation:

you're supposed to know the formula of acceleration which is velocity of a time then you can solve the question

About 3.9 x 10⁴ N/C is the size of the electric field caused by the two fixed charges at point P, option D.

To find the magnitude of the electric field at point P, use the formula for electric field:

Electric field = k × (Q₁/r₁² + Q₂/r₂²)

where k = Coulomb's constant, Q₁ and Q₂ = charges, and r₁ and r₂ = distances between the point P and the charges Q₁ and Q₂, respectively.

First calculate the distance r₁ as follows:

r₁ = √[(3.0 m)² + (130 m)²] = 130.8 m

Similarly, calculate the distance r₂ as follows:

r₂ = √[(3.0 m)² + (130 m + 5.0 m)²] = 135.2 m

Now substitute the values into the formula and get:

Electric field = (9.0 x 10⁹ N×m²/C²) × [(5.0 x 10⁻⁶ C)/(130.8 m)² + (8.0 x 10⁻⁶ C)/(135.2 m)²]

Electric field = 3.9 x 10⁴ N/C (approximately)

Therefore, the magnitude of the electric field at point P due to the two fixed charges is approximately 3.9 x 10⁴ N/C.

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Answer:

a circular path

Explanation:

In a magnetism field if a charged particle having a charge of magnitude '' enters  such that its velocity vector V is 90° to the direction of the magnetic field "B'', then it will experience a force, called Lorentz force F

\(F = V\times B\)

According to the property of cross-product, the Lorentz force (F) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path.

The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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a) The angular velocity of the turntable after 0.200 s is 0.430 rev/s. b) the turntable has spun through 0.0088 revolutions in this time interval. c) the tangential speed of a point on the rim of the turntable at t = 0.002 s is 0.094 m/s.

The coefficient of kinetic friction between the object and the rough surface is 0.083. We can use the work-energy principle to solve this problem. According to the principle, the work done by all forces acting on an object is equal to the change in its kinetic energy.

The work done by the force of friction is given by W_friction = -f_k * d, where f_k is the force of kinetic friction and d is the distance traveled. The change in kinetic energy of the object is given by ΔK = K_f - K_i = (1/2) * m * v_\(f^2\) - (1/2) * m * v_\(i^2.\)

Since the object is moving on a horizontal surface, the work done by gravity is zero. Therefore, we have W_friction = ΔK.

Substituting the given values, we get:

-f_k * d = (1/2) * m * v_f^2 - (1/2) * m * v_\(i^2\)

-f_k * 8.0 m = (1/2) * m * (2.0 \(m/s)^2\) - (1/2) * m * (9.0\(m/s)^2\)

Simplifying and solving for f_k, we get:

f_k = (m/8.0 m) * [(1/2) * (2.0 \(m/s)^2\)- (1/2) * (9.0 \(m/s)^2\)]

f_k = 0.813 \(m/s^2\)

The coefficient of kinetic friction is given by μ_k = f_k / N, where N is the normal force. Since the object is moving horizontally, the normal force is equal to the weight of the object, which is N = m * g, where g is the acceleration due to gravity.

Substituting the value of f_k and N, we get:

μ_k = f_k / N = 0.813 \(m/s^2\) / (m * g)

The value of g is approximately 9.8 \(m/s^2\). Therefore, the coefficient of kinetic friction is:

μ_k = 0.083

Therefore, the coefficient of kinetic friction between the object and the rough surface is 0.083.

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Answer:

mmmm im going to say B but i’m not sure

Explanation:

Electromagnetic waves can travel through air and unlike ocean waves or sound waves they do not need physical molecules for like a medium to travel

Answer:

The correct answer is option A: 3.00 × 10^(-11) m.

Explanation:

To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:

wavelength = speed of light / frequency

Given:

Speed of light (c) = 3.00 × 10^8 m/s

Frequency (f) = 10^19 s^(-1)

Substituting the values into the equation:

wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))

To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:

wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s

To divide by a fraction, we multiply by its reciprocal:

wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)

Applying the properties of exponents, we can add the exponents when multiplying with the same base:

wavelength = 3.00 × 10^(-11) m

Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.

Answer:

0.56rad/s²

Explanation:

Using the equation of motion

wf = wi + αt

wf is the final angular velocity

wi is the initial angular velocity

α is the angular acceleration

t is the time

Given

wf = 11.0rad/s

wi =2.0rad/s

t = 5.5secs

Substitute into the formula and get α

11.0 = 2.0+5α

11.0-2.0 = 5α

9.0 = 5α

α = 5/9.0

α ≈ 0.56rad/s²

Hence the wheel's average angular acceleration is 0.56rad/s²

The wheel's average angular acceleration is equal to 1.64 \(rad/s^2\).

Given the following data:

To determine the wheel's average angular acceleration, we would apply the first equation of kinematics:

Mathematically, the angular acceleration of an object is given by the formula:

\(\alpha = \frac{\omega_f - \omega_i}{t}\)

Where:

Substituting the given parameters into the formula, we have;

\(\alpha =\frac{11.0\;-\;2.0}{5.5} \\\\\alpha =\frac{9.0}{5.5}\)

Angular acceleration = 1.64 \(rad/s^2\)

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Answer:

The net torque will be "1366.33 Nm".

Explanation:

The given values are:

Length of ladder,

\(\tau_{242N} = 9.83 \ m\)

then,

\(\tau=4.92\)

Mass,

= 20.3 kg

Now,

The net torque will be:

⇒  \(\tau_{net}=\tau_{mg}+\tau_{242}\)

On putting the given values, we get

⇒         \(=4.92\times (-mg)+9.83\times (+242)\)

⇒         \(=4.92\times (-21\times 9.8)+9.83\times 242\)

⇒         \(=-1012.53+2378.86\)

⇒         \(=1366.33 \ Nm\)

Answer:

Average speed = 2.22m/s

Velocity = 0.89 m/s west

Explanation:

(i) Since speed is a scalar quantity, the direction of movement by the person is irrelevant. Therefore,

Average speed = total distance traveled / time taken

Where;

Total distance = 70m + 30m = 100m

Time taken = 45 seconds

Average speed = 100 / 45 = 2.22m/s

(ii) However, velocity is a vector quantity and so the direction of movement by the person is of utmost importance. Therefore,

Velocity = displacement / time taken

Where;

displacement = -70m + 30m    [West direction is taken as negative and east is taken as positive]

displacement = -40m     [The negative sign just means that the net displacement is in the direction of the West].

Thus, displacement can be written as 40m west.

Therefore,

Velocity = 40 / 45 = 0.89m/s west

Answer:

below

Explanation:

Force is needed to cause a change in the motion or shape of an object. In physics, force is defined as any influence that causes an object to undergo a certain change. This can include pushing, pulling, twisting, stretching, compressing, or any other type of action that alters the state of an object. Forces are typically measured in units of Newtons (N) and are represented by vectors, which indicate both the direction and magnitude of the force. Some common examples of situations where force is needed include lifting an object, accelerating a vehicle, compressing a spring, or bending a beam.

Answer:

Force can be used in many different ways to small stuff like flicking a bug away or picking up your pencil you use force all the time even when typing just to press down on those little keys.

Force can also be used to move heavy objects such as boulders, tables, cinder blocks, and brick stones. So force can be used in many different ways the strongest man “ Ben Weider “ known as the strongest man lifting 500 pounds in 1995 - 2000. He uses force to lift up the things that he carries.

Force can be used in many ways like I said typing something out or bench pressing. But force can be limited due to your strength.

Thus the answer to your problem is, ↑↑↑↑

The particles that are considered nucleons are neutrons and protons. Option B.

Nucleons are particles found in the nucleus of an atom, specifically protons and neutrons.

Protons have a positive charge, while neutrons have no charge, and together they make up the majority of the mass of an atom.

Electrons, on the other hand, are much smaller than protons and neutrons, and they orbit around the nucleus in shells. Since they are not found in the nucleus, electrons are not considered nucleons.

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Answer: B

Explanation: I think its B or A but mostly B

Answer:

The enthalpy of a reaction does not depend on the reactant path taken

Explanation:

i just took the test on a pex :)

Answer:

a) The diagrams can be seen in the picture attached

(b) By comparing the diagrams we can conclude that the resultant R₁ = R₂ = R₃

Further explanation

Vector is quantity that has magnitude and direction.

One example of a vector is acceleration.

Acceleration is rate of change of velocity.

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

This problem is about Vector and Vector Diagram.

Given:

Vector A = -200 j

Vector B = -250 i

Vector C = (150 sin 30.0°) i + (150 cos 30.0°) j = 75 i + 75√3 j

Unknown:

R₁ = A + B + C = ?

R₂ = B + C + A = ?

R₃ = C + B + A = ?

Solution:

R₁ = A + B + C  = (-200 j) + (-250 i) + (75 i + 75√3 j)

R₁ = -175i + (75√3 - 200)j

R₂ = B + C + A = (-250 i) + (75 i + 75√3 j) + (-200 j)

R₂ = -175i + (75√3 - 200)j

R₃ = C + B + A  = (75 i + 75√3 j) + (-250 i) + (-200 j)

R₃ = -175i + (75√3 - 200)j

From the results above, it can be concluded that the resultants above produce the same results. This can be confirmed from the diagrams in the attachment.

Explanation:

Explanation:

The negative value of the packing fraction indicates that the actual isotopic mass is less the mass number.

Answer:

The fraction of the object that is below the surface of the water is ¹⁷/₂₀

Explanation:

Given;

specific gravity of the object, γ = 0.850

Specific gravity is given as;

\(specific \ gravity = \frac{density \ of the \ object}{density \ of \ water}\\\\0.85= \frac{density \ of the \ object}{1000 \ kg/m^3} \\\\density \ of the \ object = 850 \ kg/m^3\)

Fraction of the object's weight below the surface of water is calculated as;

\(= \frac{850}{1000} \ \times\ 100\%\\\\= 85 \% \\\\= \frac{17}{20}\)

Therefore, the fraction of the object that is below the surface of the water is ¹⁷/₂₀