Let's find the horizontal distance the arrow has traveled first;We know that the arrow lands 40 meters away from the archer. Therefore, the horizontal distance the arrow has traveled is 40 meters.
Now we need to find the vertical distance the arrow has fallen which is 1.5 meters.
To calculate the initial velocity (speed) of the arrow, we will use the formula:
v² = u² + 2as
Where; v = final velocity = 0
u = initial velocity
s = displacement (vertical distance) = 1.5 meters
a = acceleration = 9.81 m/s²
Substitute the values in the formula:
0² = u² + 2(-9.81)(1.5)
0 = u² - 29.43
u² = 29.43
u = √29.43
u = 5.43 m/s
Therefore, the arrow was going 5.43 m/s horizontally at the moment of launch.
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Molly is pulling a cart down the hallway. She stops at each classroom and collects a stack of books from each teacher. After stopping at 5 classrooms, she can no longer move the cart by herself and her friend Regan needs to help her pull the cart. How does this SHOW Newton's 3rd Law? Do NOT just state the law!!
Answer:
His third law states that for every action or force in nature there is an equal and opposite reaction.
Explanation:
The heavier the books get, the harder it is for Molly to exert enough force to move the cart.
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If an 800 kg roller coaster is at the top of its 50 high trackwill have a potential energy 392,000 J and a energy of This means the total mechanical energy is 392,000 the cart drops down to where its kinetic energy is now 92, 000J how high off the ground is the cart now?
Given data:
* The mass of the roller coaster is m = 800 kg.
* The total mechanical energy is E = 392000 J.
* The kinetic energy at the particular height (let h') is K = 92000 J.
Solution:
The potential energy of the roller coaster at h' is,
\(\begin{gathered} U=E-K \\ U=392000-92000 \\ U=300000\text{ J} \end{gathered}\)The potential energy in terms of height and mass is,
\(U=\text{mgh}\)where g is the acceleration due to gravity,
Substituting the known values,
\(\begin{gathered} 300000=800\times9.8\times h \\ 300000=7840\times h \\ h=\frac{300000}{7840} \\ h=38.3\text{ m} \end{gathered}\)Thus, the height of the roller coaster from the ground is 38.3 meters.
Which mathematical representation correctly identifies impulse? (1 point)
impulse=forcetimeimpulse is equal to force over time
impulse=force×timeimpulse is equal to force times time
impulse=acceleration×timeimpulse=acceleration×time
impulse=velocitytime
Answer:
Impulse = Force × Time
Explanation:
Answer:
The Moment of Impact Quick Check
1. B. Impulse = Force × Time
2. A. The momentum of each ball changes, and the total momentum stays the same
3. D. -55 kg·m/s
4. B. 3.5 kg
5. C. 6.3 m/s
Explanation:
I got a 100. You're Welcome.
A = 10x - 2y B = 5x + 4y C=2A + B What is the magnitude of the vector C? Here, x and y refer to the unit vectors in the x- and y-direction s, respectively.
Therefore, the magnitude of vector C is 25.
Given:A = 10x - 2yB = 5x + 4yC=2A + BNow we have to calculate the magnitude of vector C.Let's calculate each part of the vector C first;2A = 2(10x-2y) = 20x - 4yB = 5x + 4yC = 2A + B= (20x-4y)+(5x+4y)=25xNow we can calculate the magnitude of vector C by using the formula;|C| = √(Cx²+Cy²+Cz²)Here, we only have two dimensions, so the formula becomes;|C| = √(Cx²+Cy²)|C| = √(25²) = 25. Therefore, the magnitude of vector C is 25.
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A person whose eye has a lens-to-retina distance of 2.0 cm, can only clearly see objects that are closer than 1.0 m away. What is the strength S of the person's eye lens? (Note: Use the thin lens formula 1/O + 1/I = S)
A) -50 D
B) -10 D
C) 51 D
D) 55 D
51D is the strength S of the person's eye lens
Define lens's strength
The lens's construction material and the angle at which its curved surface is ground together define the lens's strength. Diopters (D), a unit of measurement for lens strength, represent how much light is bent. The strength of the lens increases with the diopter.
The optical component known as the objective is what collects light from the object under observation and concentrates it to create an actual image.
1/O + 1/I = S
O = 2cm
I = 100cm
S = 1/2 + 1/100
S = 51D
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Two long parallel wires are a center-to-center distance of apart and carry equal anti-parallel currents of. Find the magnitude of the magnetic field at the point which is equidistant from the wires. .
The strength of the magnetic field in the center of the system, which is equally spaced from the wires. . B = μ0I/(2πr) for the magnetic field's strength.
How can the magnetic field of a magnet be calculated?And this is where the second important characteristic comes into play. The equivalent surface current density I = dI/ds =B = μ0I/(2πr), which is proportional to the magnetic field Br of the permanent magnet material, may be used to compute the magnetic field of permanent magnets. In this case, the permeability of open space is μ = 4 107 A/Tm.
How does one locate a wire's magnetic field?The magnetic field lines encircle a long, straight wire when it is carrying a current I. You may find the magnetic field direction by circling the wire with your fingers while pointing your right thumb in the direction of the current.
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6th grade science I mark as brainliest.
Answer:
2m 13\(\frac{1}{3}\)s
Explanation:
1.5m = 1s
200m = \(\frac{200}{1.5}\) × 1s
= 133\(\frac{1}{3}\)s
= 2m 13\(\frac{1}{3}\)s
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Can you please help me on all of these!!!! Please
Answer:
differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through the air and solid materials but also through the vacuum of space.
Explanation:
This means that electromagnetic waves can travel not only through the air and solid materials but also through the vacuum of space.
hi the picture attached is my question on my homework
ANSWER:
Sphere B
STEP-BY-STEP EXPLANATION:
The time of the air depends on the mass, initial velocity and the height of the object, having the same mass and the same height, it depends only on the initial velocity.
The higher the initial velocity, the shorter the time in the air, therefore in this case the sphere B that has a lower velocity will be the one that will spend the longest time in the air.
ball is thrown upward from a window that is 12 m above the ground. The ball reaches a maximum height of 4 m above the window before falling all the way down to the ground. What distance did the ball travel?
Answer:
20 m
Explanation:
The ball travels 4 m up, then 16 m down. It travels a total distance of 20 m.
calculate the wavelength (in m) of a 650.00 hz sound in air at room temperature and pressure, where the velocity of sound is 344 m/s.
The wavelength of a 650.00 Hz sound in air at room temperature and pressure, where the velocity of sound is 344 m/s, is approximately 0.529 m.
What is the wavelength of a 650.00 Hz sound in air at room temperature and pressure?Sound waves travel through a medium by creating compressions and rarefactions. The wavelength of a sound wave is the distance between two consecutive points that are in phase, such as two compressions or two rarefactions. To calculate the wavelength, we can use the formula: wavelength = velocity of sound / frequency.
In this case, the frequency of the sound is 650.00 Hz, and the velocity of sound in air at room temperature and pressure is 344 m/s. Plugging these values into the formula, we get: wavelength = 344 m/s / 650.00 Hz = 0.529 m.
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A coin is made of ______
Answer:
coins made with the combination of copper zinc and Nickel
A cloth is made of fabrics
A towel is made from cotton
an umbrella is made up of fiberglass
a sweater is made up of wool
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The potential-energy function U(x) is zero in the interval 0≤x≤L and has the constant value U0 everywhere outside this interval. An electron is moving past this square well. The electron has energy E=4U0.
What is the ratio of the de Broglie wavelength of the electron in the region x>L to the wavelength for 0
The ratio of the de Broglie wavelength of the electron in the region x > L to the wavelength for 0 < x < L can be determined by comparing their respective momenta.
Since the energy E of the electron is 4U0, its momentum p can be found using the relation E = p^2/2m, where m is the mass of the electron.
In the region x > L, the potential energy U(x) is constant, so the total energy is E = U0 + p^2/2m. The momentum p can be determined as p = sqrt(2m(E - U0)).
In the region 0 < x < L, the total energy is E = p^2/2m. The momentum p for this region is simply p = sqrt(2mE).
Taking the ratio of the de Broglie wavelengths λ1 and λ2 for the two regions, we have:
\(λ1/λ2 = p1/p2 = (sqrt(2m(E - U0))) / (sqrt(2mE))\)
Simplifying this expression, we get:
\(λ1/λ2 = sqrt((E - U0)/E)\)
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please help me !!!!!!
Answer:
the correct answer to your problem I believe would be B
if scientists were able to stop the techonic plates from moving,people on earth would no longer have
Answer: Earthquakes
The movement of the tectonic plates causes earthquakes. There are different kinds of plate interactions, but basically it's like a rubber band being stretched then the energy is released in the form of the ground shaking.
The following graphs display the exact function solution y = ex and the three numerical solutions Euler, Improved Euler (Heun) and Runge-Kutta at different intervals (iterations). Analyze each set of graphs (there are a total of four) noticing the Relative Deviation on the right. Write at least 3 - 5 sentence paragraph describing your observation.
The graphs display the function solution y = ex and three numerical solutions -Euler, Improved Euler, and Runge-Kutta- at different intervals. The Relative Deviation on the right measures the difference between the numerical solutions and the exact function solution.
The analysis of each set of graphs involves comparing the numerical solutions (Euler, Improved Euler, and Runge-Kutta) with the exact function solution y = ex. The Relative Deviation provides an indication of how closely the numerical solutions approximate the exact solution.
To analyze each set of graphs, follow these steps:
Examine the shape of the graphs: Compare the curves of the numerical solutions -Euler, Improved Euler, and Runge-Kutta-with the exact function solution. Look for similarities and differences in terms of how well they capture the shape and behavior of the function.Evaluate the Relative Deviation: Focus on the Relative Deviation values displayed on the right side of the graphs. The Relative Deviation measures the percentage difference between the numerical solutions and the exact function solution. Higher values indicate larger deviations and less accuracy in approximating the true solution.Compare the performance of the numerical methods: Assess the performance of each numerical method -Euler, Improved Euler, and Runge-Kutta-based on their respective graphs and Relative Deviation values. Look for trends and patterns in how the deviation changes with each iteration or interval.Determine the most accurate numerical method: Based on the analysis of the graphs and Relative Deviation values, identify the numerical method that provides the closest approximation to the exact function solution. A lower Relative Deviation indicates better accuracy and a closer match to the true solution.By examining the graphs and assessing the Relative Deviation, one can analyze the accuracy and performance of the numerical solutions -Euler, Improved Euler, and Runge-Kutta- in approximating the exact function solution y = ex at different intervals or iterations.
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Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100. 0 m each. If Margy is walking at 1. 4 m/s and accelerates at 0. 20 m/s2 during one of the running portions, what is her final velocity at the end of the 100. 0 m? Round your answer to the nearest tenth. M/s.
The final velocity of Margy at the end of 100m is 4.5 m/s We are given:Initial velocity of Margy = 1.4 m/sAcceleration = 0.20 m/s²Distance covered by Margy = 100 mWhen Margy is running, her acceleration is given by a = 0.20 m/s², and the distance covered is d = 100 m.
Therefore, we can use the following equation:vf² = vi² + 2adHere, vi is the initial velocity, vf is the final velocity, a is the acceleration, and d is the distance.So,vf² = vi² + 2advf² = (1.4)² + 2(0.20)(100)vf² = 1.96 + 40vf² = 41.96vf = √41.96 ≈ 6.5 m/sHowever, Margy is only running for part of the distance. For the rest of the time, she is walking at a constant speed of 1.4 m/s.
To find her average velocity for the entire distance, we can use the following formula:average velocity = total distance / total timeThe total distance is 100 m, and the total time is 100 m / 1.4 m/s + 100 m / 6.5 m/s = 71.4 sTherefore, the average velocity of Margy for the entire distance is 100 m / 71.4 s ≈ 1.4 m/s.To summarize, Margy's final velocity at the end of 100 m is 6.5 m/s, but her average velocity for the entire distance is 1.4 m/s.
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can you describe briefly how to slice a silicon wafer? 1-2 sentences
Silicon wafers are sliced using a wire saw, which employs a thin wire coated with abrasive particles.
A silicon wafer is a material essential for manufacturing semiconductors, which are found in all kinds of electronic devices that enrich our lives.
Few of us have a chance to encounter an actual silicon wafer in daily life.
This ultra-flat disk is polished to a mirror-like surface, and made as free as possible of tiny surface irregularities, making it the flattest object in the world. It is also ultra-clean, virtually free of microparticles and other impurities.
These qualities are necessary so it can be used as the substrate material of today's state-of-the-art semiconductors.
Silicon wafers are sliced using a wire saw, which employs a thin wire coated with abrasive particles.
The wire is moved back and forth over the silicon crystal, gradually cutting through it to produce thin wafers of the desired thickness.
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6. Why might a small increase in the dimensions of an object cause a large change in
volume?
Answer:
Because volume is determined as the product of length and width as well as height of an object.So change in any dimension can change the other two dimensions as well which brings about a greater change in volume by carrying out the product of the dimensions .
Explanation:
Length x width x height = Volume of a regular shaped object
Student A states that when she sits down on a chair, she is exerting a force on the chair and that is all that happens. Student B states that when she sits on a chair, the chair is actually exerting a force back on her in reaction to her force exerted upon the chair. Which student is correct and why?
A.
Student A is correct because Newton’s 1st Law of Motion states that if the chair exerted a force on the student, her motion would change.
B.
Student A is correct because Newton’s 3rd Law of Motion states that for every action there is an equal and opposite action and the chair does not show any action.
C.
Student B is correct because Newton’s 1st Law of Motion states that if the chair were to be exerting a force on the student, her motion would change.
D.
Student B is correct because Newton’s 3rd Law of Motion states that for every action there is an equal and opposite action and the chair’s action counteracts the student’s so that neither move.
Answer:
C
Explanation:
I got it right on the test !!
The student that is correct is C. Student B is correct because Newton’s 1st Law of Motion states that if the chair were to be exerting a force on the student, her motion would change.
According to Newton's third law of motion, there's an equal and opposite reaction force for every action force. It should be noted that when an individual sits on a chair, the chair is actually exerting a force back on her in reaction to the force exerted upon the chair.
Student A is incorrect because when she sits down on a chair, the force that she's exerting on the chair is not the only thing that happens because the chair exerts a force back. Therefore, as the chair were to be exerting a force on the student, her motion would change.
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an object placed 6 cm from a concave spherical mirror produces a virtual image 7.5 cm behind the mirror. if the object is moved back to 15 cm from the mirror, where is the image located?
The image is located 1.43 cm behind the concave mirror when the object is moved to a distance of 15 cm from the mirror.
To solve this problem, we can use the mirror formula:
1/f = 1/do + 1/di
where f is the focal length of the mirror, do is the object distance, and di is the image distance.
We know that the mirror is concave, so its focal length is negative. We also know that the image produced is virtual, so di is negative.
Using the given information for the first case:
do = 6 cm
di = -7.5 cm
f = ?
1/f = 1/do + 1/di
1/f = 1/6 + (-1/7.5)
1/f = -0.0333
f = -30 cm
Now, we can use the mirror formula again to find the image distance when the object is moved to a new position:
do = 15 cm
di = ?
f = -30 cm
1/f = 1/do + 1/di
1/-30 = 1/15 + 1/di
-1/30 = 1/di - 1/15
-1/30 = (15 - di)/15di
di(-1/30) = (15 - di)/15
-1.5 + 0.05di = di
1.05di = 1.5
di = 1.43 cm
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How does the change in the state of matter occur? Write with example
Answer:
When matter changes from one state to another, it either absorbs energy—as when chocolate melts—or loses energy. For example, if you were to place the melted chocolate in a refrigerator, it would lose energy to the cold air inside the refrigerator. As a result, the liquid chocolate would change to a solid again.
Explanation:
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Choose the incorrect statement.
Report an
question 1
O Heat is a measure of how hot or how cold an
object is
O Heat flows from a substance of higher
temperature to a substance with a cooler
temperature.
O Heat is measured in units of calories or joules.
O Heat is the energy flow from two substances at
different temperatures.
Answer:
first one,heat is a measure of.........
What would the products of a double-replacement reaction between Na2S
and MgF2 be?
A. NaF and MgS
B. MgF and Nas
C. F2S and MgNa2
D. MgF2 and Nas
Answer:
A. NaF and MgS
Explanation:
The reaction equation is given as:
Na₂S + MgF₂ → 2NaF + MgS
The product of this reaction is NaF and MgS.
In a double displacement reaction there is an actual exchange of partners to form new compounds. This reaction takes place between ionic compounds.
The driving force for the reaction is:
formation of an insoluble precipitateformation of water or any other non-ionizing compound liberation of a gaseous product.If a t-shirt gun can fire t-shirts with an initial speed of 15 m/s, what is the maximum distance (along horizontal, flat ground) a t-shirt can be fired?
Answer:
h = 11.47 m
Explanation:
Initial speed pf the t-shirt gun is 15 m/s
We need to find the maximum distance covered by the t-shirt. It is based on the conservation of energy. The maximum distance covered is given by :
\(h=\dfrac{u^2}{2g}\\\\h=\dfrac{(15)^2}{2\times 9.8}\\\\h=11.47\ m\)
So, it will cover a distance of 11.47 m.
COULOMB’S LAW PhET LAB SIMULATION GUIDED QUESTIONSDirections:
TYPE ALL of YOUR ANSWERS IN A DIFFERENT COLOR (not black!)
PART 1: DATA COLLECTION
Go to this link: Coulombs Law PhET Lab
Once you are in the simulation, which looks like the image below, follow the instructions as you go through each question in order to work your way through the simulation and answer the questions.
Identify the three variables in the simulation...remember, variables are things that can be changed or tested. There are 3 things in the simulation that can be changed directly or indirectly…..
Fill in the blank, highlight one choice:
Variable 1 is and it is : (Independent OR Dependent)
Variable 2 is and it is: (Independent OR Dependent)
Variable 3 is and it is: (Independent OR Dependent)
a. Which variable(s) do you change to increase force? (list them)
b. What do you do to the variable(s) listed above to increase the force? (describe what you change to make the force go up) decrease distance and/or increase charge.
a. Which variable(s) do you change to decrease force? (list them)
b. What do you do to the variable(s) listed above to decrease the force? (describe what you change to make the force go down)
Variable 1 is distance and it is Independent.
Variable 2 is charge and it is Independent.
Variable 3 is force and it is Dependent.
a. To increase force, you need to change distance and/or charge.
b. To increase the force, you need to decrease the distance between the charges and/or increase the magnitude of the charges.
a. To decrease force, you need to change distance and/or charge.
b. To decrease the force, you need to increase the distance between the charges and/or decrease the magnitude of the charges.
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The second image !!!!!!
Answer:
Explanation:
No, not any of these substance will float in Methanol , simply because Methanol has a density of 0.79 g, if you put any substance that weighs more than 0.79 g, it will sink, it all depends on the weight if it is more or less than methanol
2: D=m/v
D=135/50 = 2.7 g/cm³ ( Aluminum)
D=M/V
if two objects has the same mass but one has larger volume, then te one with larger volume has less density
example : 2 objects
mass of both=350
volume of the first one=500 and the other 750
D1=M1/V1 = 350/500 =0.7
D2 = M2/V2 = 350/750 = 0.4666
D1 is larger than D2( with larger volume )
Which direction will thermal energy flow if you pick up a snowball with your bare hand? Thermal energy will flow from the snowball to your hand. Thermal energy will flow from your hand to the snowball. Thermal energy will not flow between your hand and the snowball.
Answer:
b. Thermal energy will flow from your hand to the snowball.
Explanation:
Answer:
B
Explanation:
The beam is supported by the three pin-connected suspender bars, each having a diameter of 0.5 in. and made from A-36 steel. The dimensions are a = 9.5 in and b = 6.85 in.
A) Determine the greatest uniform load w that can be applied to the beam without causing AB or CB to buckle.
To determine the greatest uniform load w that can be applied to the beam without causing AB or CB to buckle, we need to calculate the critical load for each suspender bar.
The critical load for a pin-connected suspender bar can be calculated using the following formula:
Pcr = (π²EI)/(KL)²
Where Pcr is the critical load, E is the modulus of elasticity of the material, I is the moment of inertia of the cross-section, K is the effective length factor, and L is the length of the bar between the pins.
Assuming the suspender bars are all identical, we can calculate the critical load for one bar and multiply by three to get the total critical load for all three bars.
Using the given dimensions and properties of A-36 steel, we can calculate the moment of inertia of the cross-section:
I = (1/12)bh³ = (1/12)(6.85 in)(0.5 in)³ = 0.044 in⁴
We can also calculate the effective length factor using the following formula:
K = 1.0 for pinned-pinned bars
Using these values and assuming a length of 9.5 in between the pins, we can calculate the critical load for one bar:
Pcr = (π²E(0.044 in⁴))/((1.0)(9.5 in))²
Pcr = (9.87²)(29,000 ksi)(0.044 in⁴)/(90.25 in²)
Pcr = 7,080 lb
Multiplying by three, we get the total critical load for all three bars:
Pcr,total = 3Pcr = 3(7,080 lb) = 21,240 lb
Therefore, the greatest uniform load w that can be applied to the beam without causing AB or CB to buckle is 21,240 lb.
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