Answer:
Weight = 105 Newton
Explanation:
Given the following data;
Mass = 70kg
Force of gravity = 1.5N/kg
To find the weight;
Weight = mass * force of gravity
Substituting into the equation, we have;
Weight = 70 * 1.5
Weight = 105 Newton
Therefore, the weight of the astronaut when they are on the Moon is 105 Newton.
Five balls labeled A, B, C, D, and E are placed in front of a plane mirror as shown in the figure. Which ball(s) will the observer, in the position shown, see reflected in the mirror?C onlyA, B, C, D and EA onlyA and BA, B, D and E
In order to find which balls will be shown in the mirror, we need to draw light rays going from the eye of the observer into the ends of the mirror.
Then, the reflected rays will create a region, and every ball inside this region can be observed in the mirror.
So we have:
We can see that only ball A is inside the reflected region, therefore only ball A will be seen in the mirror.
Therefore the answer is the third option: A only.
A series of four different cylinders were each subjected to a force by placing four different masses on top of them. The mass placed on each cylinder
and dimensions of each cylinder are shown below. Rank the stress on these cylinders from least to greatest.
Mass (kg) Diameter (cm) Height (cm)
Case
A
B
С
D
5.2
3.6
4.7
2.9
2.6
2.3
2.7
32.2
32.5
27.3
16.9
Answer:
C, B, D, A
Explanation:
Stress is F/A, where F = 9.8*mass and A = pi(d/2)^2
Do the math for each and the stress from least to greatest is C, B, D, A.
The height column is unnecessary information.
When four different cylinders(A,B,C,D) were each subjected to a force by placing four different masses on top of them. the Rank of stress on these cylinders from least to greatest is D, C, B, A.
What is Stress ?Stress is defined as applied force(F) per unit cross sectional area(A) on which force is applied. it I.e. Stress = F/A. its SI unit is N/m². More force on small area leads to higher stress.
Given,
For A
Mass m = 5.2 kg
Diameter = 2.6 cm
Radius r = 1.3 cm = 0.013 m
Height = 32.5
Stress on A = Force ÷ A = mg ÷ πr²
Stress = (5.2×9.8) ÷ (3.14×0.013²)
Stress = 96031 N/m²
For B
Mass m = 3.6 kg
Diameter = 2.3 cm
Radius r = 1.15 cm = 0.011 m
Height = 27.3
Stress on B = Force ÷ A = mg ÷ πr²
Stress = (3.6 ×9.8) ÷ (3.14×0.011 ²)
Stress = 92856 N/m²
C
Mass m = 4.7 kg
Diameter = 2.7 cm
Radius r = 1.35 cm = 0.0135 m
Height = 16.9
Stress on C= Force ÷ A = mg ÷ πr²
Stress = (4.7 ×9.8) ÷ (3.14×0.0135²)
Stress = 80487 N/m²
D
Mass m = 2.9 kg
Diameter = 32.2 cm
Radius r = 16.1 cm = 0.16 m
Stress on D = Force ÷ A = mg ÷ πr²
Stress = (2.9×9.8) ÷ (3.14×0.16²)
Stress = 353 N/m²
Hence Rank of stresses on the 4 cylinders are D, C, B, A
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A tank circuit in a radio transmitter is a series RCL circuit connected to an antenna. The antenna broadcasts radio signals at the resonant frequency of the tank circuit. Suppose that a certain tank circuit in a shortwave radio transmitter has a fixed capacitance of 1.6 x 10-11 F and a variable inductance. If the antenna is intended to broadcast radio signals ranging in frequency from 4.8 MHz to 9.0 MHz, find the (a) minimum and (b) maximum inductance of the tank circuit.
a. The minimum inductance of the tank circuit is 56.85 H
b. The maximum inductance of the tank circuit is 199.86 H
Resonant frequency
The resonant frequency of a series RLC circuit is given by
f = 1/2π√LC where
L = inductance and C = capacitanceMaking L subject of the formula, we have
L = (2πf)²/C
a. Minimum inductance in the tank circuit
The minimum inductance of the tank circuit is 56.85 H
To find the minimum inductance, we substitute the value of
f = frequency = 4.8 MHz = 4.8 × 10⁻⁶ Hz and C = capacitance = 1.6 × 10⁻¹¹ F into the equation, we haveL = (2πf)²/C
L = (2π × 4.8 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F
L = (9.6π × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F
L = (30.159 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F
L = 909.583 × 10⁻¹² Hz²/1.6 × 10⁻¹¹ F
L = 568.489 × 10⁻¹ H
L = 56.8489 H
L ≅ 56.85 H
The minimum inductance of the tank circuit is 56.85 H
b. Maximum inductance in the tank circuit
The maximum inductance of the tank circuit is 199.86 H
To find the maximum inductance, we substitute the value of
f = frequency = 9.0 MHz = 9.0 × 10⁻⁶ Hz and C = capacitance = 1.6 × 10⁻¹¹ F into the equation, we haveL = (2πf)²/C
L = (2π × 9.0 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F
L = (18π × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F
L = (56.549 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F
L = 3197.75 × 10⁻¹² Hz²/1.6 × 10⁻¹¹ F
L = 1998.59 × 10⁻¹ H
L = 199.859 H
L ≅ 199.86 H
The maximum inductance of the tank circuit is 199.86 H
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Determine the node voltages in the circuit in Fig. 3.67 using nodal analysis. 30 V
The node voltages in the circuit using nodal analysis determined as v1= 30V ; v2=v3= 60V.
What does "nodal analysis" mean?Any electrical network may be solved using nodal analysis, which is what it is called. the formula used to determine how much voltage is shared across circuit nodes. Since the node voltages are with respect to the ground, this method is also referred to as the node-voltage method.
Nodal analysis : the node voltage was determined.
At node 2,
=> v2-v1/2 + v2-v3/2 - 15=0
=> -0.5v1 + v2 -0.5v3=15
At super node,
v2-v1/2 + v2-v3/2 -v1/4 -v3/8 =0
=> 2v1+v3 = 120
v1+30 = v3
Hence, solving all equation we get
v1= 30V ; v2=v3= 60V
Why do we employ nodal analysis?We can solve for voltage and current in a circuit using numerous KCL equations that we acquire from nodal analysis of the circuits. There are one fewer KCL equations needed than there are nodes in a circuit.
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a wind turbine is an example of what kind of device
a. a generator
b. a transformer
c. a motor
d. an electromagnet
Answer:
it’s an example of a generator.
Explanation:
Answer:
Generator
Explanation:
valid
A negative correlation___
is not a very considerate way to compute your numbers
means that as one variable goes up, the other goes down
is only used in experiments that test topics like depression or agression.
has no relationship among the variables
An aluminum wire having a cross-sectional area equal to 2.90 10-6 m2 carries a current of 4.00 A. The density of aluminum is 2.70 g/cm3. Assume each aluminum atom supplies one conduction electron per atom. Find the drift speed of the electrons in the wire.
The drift speed of electrons in the aluminum wire is approximately 4.61 × 10^(-5) m/s.
To find the drift speed of electrons in the wire, we can use the equation v = I / (nAe), where v is the drift speed, I is the current, n is the number of conduction electrons per unit volume, A is the cross-sectional area of the wire, and e is the charge of an electron.
First, let's calculate the number of conduction electrons per unit volume. The density of aluminum is given as 2.70 g/cm^3. We can convert it to kg/m^3 by multiplying by 1000.
Since each aluminum atom supplies one conduction electron, the number of conduction electrons per unit volume is equal to the number of aluminum atoms per unit volume. Using the atomic mass of aluminum (26.98 g/mol) and Avogadro's number (6.022 × 10^23 mol^(-1)), we can calculate the number of aluminum atoms per unit volume.
Next, we substitute the values into the formula v = I / (nAe) to find the drift speed. The current is given as 4.00 A, the cross-sectional area is 2.90 × 10^(-6) m^2, and the charge of an electron is 1.60 × 10^(-19) C. After substituting the values, we can calculate the drift speed, which is approximately 4.61 × 10^(-5) m/s.
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What differentiates baseline actives from health enhancing activities?
A. The intensity of the activity
B. The cost of the activity
C. The participant in the activity
D.The frequency of the activity
5) Sally has a mass of 50 kg. She ran with a velocity of 20 m/s.
What was her KE as she crossed the finish line?
Answer:
10,000 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\ \)
m is the mass
v is the velocity
From the question we have
\(k = \frac{1}{2} \times 50 \times {20}^{2} \\ = 25 \times 400 \\ = 10000\)
We have the final answer as
10,000 JHope this helps you
A solid cylinder with mass M. radius R, and rotational inertia 1/2MR² rolls without slipping down the inclined plane
shown above. The cylinder starts from rest at a height H. The inclined plane makes an angle with the horizontal.
Express all solutions in terms of M, R, H, theta, and g.
a. Determine the translational speed of the cylinder when it reaches the bottom of the inclined plane.
b. Show that the acceleration of the center of mass of the cylinder while it is rolling down the inclined plane is (2/3)g sin theta.
c. Determine the minimum coefficient of friction between the cylinder and the inclined plane that is required for the cylinder to roll without slipping.
a. The translational speed of the cylinder at the bottom of the inclined plane is v = sqrt(2gh); b. a = (2g sin(theta) / R) R = 2g sin(theta) is the acceleration of the center of mass of the cylinder down the inclined plane. Rolling Cylinder on Inclined Plane; c. The minimum coefficient of friction required for the cylinder to roll without slipping is equal to the tangent of the angle of the inclined plane.
Translational speed and frictional.The potential energy of the cylinder at the top of the inclined plane is Mgh, where g is the acceleration due to gravity. At the bottom of the inclined plane, all of this potential energy has been converted to kinetic energy, so:
1/2 M v^2 = Mgh
where v is the translational speed of the cylinder at the bottom of the inclined plane.
Solving for v, we get:
v = sqrt(2gh)
b. The force of gravity acting on the cylinder down the inclined plane has two components: one parallel to the plane, Mg sin(theta), and one perpendicular to the plane, Mg cos(theta).
The net torque on the cylinder is due to the parallel component of the force of gravity, which acts at a distance R from the center of mass of the cylinder. The torque is therefore:
τ = (Mg sin(theta)) R
The rotational inertia of the cylinder is 1/2MR^2, so the angular acceleration of the cylinder is:
α = τ / I = (Mg sin(theta)) R / (1/2MR^2) = 2g sin(theta) / R
The linear acceleration of the center of mass of the cylinder is
a = αR, so:a = (2g sin(theta) / R) R = 2g sin(theta)
This is the acceleration of the center of mass of the cylinder down the inclined plane.
c. In order for the cylinder to roll without slipping, the force of friction between the cylinder and the inclined plane must provide enough torque to prevent the cylinder from slipping.
The maximum force of friction is μN, where μ is the coefficient of friction and N is the normal force on the cylinder. The normal force is equal to the weight of the cylinder, Mg cos(theta). The torque due to the force of friction is:
τ_friction = μN R = μMg cos(theta) R
The torque due to the force of gravity parallel to the inclined plane is still Mg sin(theta) R. The net torque is therefore:
τ_net = Mg sin(theta) R - μMg cos(theta) R
For the cylinder to roll without slipping, this net torque must be equal to the torque due to the angular acceleration, which is (1/2)MR^2 α. Setting these two torques equal, we get:
Mg sin(theta) R - μMg cos(theta) R = (1/2)MR^2 (2g sin(theta) / R)
Solving for μ, we get:
μ = tan(theta)
So the minimum coefficient of friction required for the cylinder to roll without slipping is equal to the tangent of the angle of the inclined plane.
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the physical structure of a(n) ? consists of two conducting surfaces separated by an insulating material.
The physical structure of capacitor consists of two conducting surfaces separated by insulating material.
What is capacitor?Capacitor is a device that stores electrical energy in an electric field by the virtue of accumulating electric charges on two close surfaces insulated from each other. It is a passive electronic component with two terminals and the effect of capacitor is known as capacitance
Capacitor works on the principle that the capacitance of a conductor increases when earthed conductor is brought near it. Therefore, capacitor has two plates that are separated by a distance having equal and opposite charges. The properties of capacitors are: working voltage, tolerance, working temperature and temperature coefficient.
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WILL GIVE BRAINLIEST!!!! PLEASE HELP!!!!
What is the name of the organic molecule modeled below?
A - Propane
B - Propene
C - Propine
D - Propyne
Answer:
the correct objective is C
Kim won a 300 m race in 40 s. What was her rate of speed?
Answer:
7.5 meters per second
Hope This Helps!!
Answer:
it is 7.5 m\s
tell me if it's right
The sputnik one satellite orbiting earth mass equals 5.98×10 to the 24th power kilograms in a circle of radius 6.96×10 to the six power meters what was its orbital velocity
Answer:
7572 m/s
Explanation:
The force between two masses separated by a distance r is given as:
\(F=G\frac{m_1m_2}{r^2}\)
Where F is the attractive force between 2 masses, m1 and m2, r is the distance between the centres of the masses and G is the universal gravitation constant, which is \(6.674*10^-11 Nm^2/kg^2\)
The mass of the earth (\(m_1\)) is far greater than the mass of the sputnik (\(m_2\)). Therefore \(m_1m_2=m_1\). The mass of the sputnik is neglected, therefore:
\(F=G\frac{m_1}{r^2}=\frac{(6.674*10^{-11})(5.98*10^{24})}{(6.96*10^6)^2} = 8.2389N\)
But F is actually centripetal acceleration, a = v²/r
\(8.2389 = v^2 / 6.96*10^6\\v=7572m/s\)
Water travels, in a 2km long pipeline at a maximum flow rate of 0.12 m/s. The internal diameter of the pipe is 300 mm, pipe wall thickness is 5 mm, and is manufactured from steel with a Young's modulus of 210x109 Pa. The pipeline is constructed within an excavated trench and surrounded by backfill material. A control valve on the downstream end of the pipeline uniformly closes in 12 seconds. (a) Calculate the pressure transients at the mid-point of the pipeline (b) How does friction in pipeline effect the calculated (in Q6 (a)) pressure transients
(A) The pressure transients at the mid-point of the pipeline are approximately 1,208,277 Pa.
(B) Friction in the pipeline affects the calculated pressure transients by increasing the overall resistance to flow
(a) The pressure transients at the mid-point of the pipeline can be calculated using the water hammer equation. Water hammer refers to the sudden changes in pressure and flow rate that occur when there are rapid variations in fluid flow. The equation is given by:
ΔP = (ρ × ΔV × c) / A
Where:
ΔP = Pressure change
ρ = Density of water
ΔV = Change in velocity
c = Wave speed
A = Cross-sectional area of the pipe
First, let's calculate the change in velocity:
ΔV = Q / A
Q = Flow rate = 0.12 m/s
A = π × ((d/2)^2 - ((d-2t)/2)^2)
d = Internal diameter of the pipe = 300 mm = 0.3 m
t = Pipe wall thickness = 5 mm = 0.005 m
Substituting the values:
A = π × ((0.3/2)^2 - ((0.3-2(0.005))/2)^2
A = π × (0.15^2 - 0.1495^2) = 0.0707 m^2
ΔV = 0.12 / 0.0707 = 1.696 m/s
Next, let's calculate the wave speed:
c = √(E / ρ)
E = Young's modulus of steel = 210x10^9 Pa
ρ = Density of water = 1000 kg/m^3
c = √(210x10^9 / 1000) = 4585.9 m/s
Finally, substituting the values into the water hammer equation:
ΔP = (1000 × 1.696 × 4585.9) / 0.0707 = 1,208,277 Pa
Therefore, the pressure transients at the mid-point of the pipeline are approximately 1,208,277 Pa.
(b) Friction in the pipeline affects the calculated pressure transients by increasing the overall resistance to flow. As water moves through the pipe, it encounters frictional forces between the water and the pipe wall. This friction causes a pressure drop along the length of the pipeline.
The presence of friction results in a higher effective wave speed, which affects the calculation of pressure transients. The actual wave speed in the presence of friction can be higher than the wave speed calculated using the Young's modulus of steel alone. This higher effective wave speed leads to a reduced pressure rise during the transient event.
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The brain is not a muscle, like the heart, that can be worked and built. Which BEST explains why a consistent exercise regime has a positive
impact on the brain?
ОА. .
Exercise generally requires a lot of thinking.
ОВ.
Exercise can eliminate all of the impact of stress.
OC.
Exercise helps maintain and create pathways in the brain.
OD.
Exercise is the only way to moderate the hormones that control the brain.
Regular exercise has a positive impact on the brain, and the best explanation for this is that exercise helps maintain and create pathways in the brain (Option C).
1. The brain is a complex organ composed of billions of nerve cells called neurons. These neurons communicate with each other through pathways, forming a vast network.
2. When we engage in physical exercise, it increases blood flow to the brain. This enhanced blood flow delivers more oxygen and nutrients to the brain cells, promoting their overall health and functioning.
3. Exercise also stimulates the release of various chemicals in the brain, such as neurotransmitters and growth factors. These substances play a crucial role in the growth, development, and maintenance of brain cells.
4. Additionally, regular exercise has been found to promote the formation of new connections between neurons, a process known as neuroplasticity. These connections, also called synapses, are essential for learning, memory, and overall cognitive function.
5. By engaging in consistent exercise, individuals can enhance neuroplasticity, allowing their brains to adapt and reorganize in response to new experiences and challenges.
6. Moreover, exercise has been shown to reduce the risk of age-related cognitive decline and neurodegenerative diseases, such as Alzheimer's disease. It may also help improve mood, reduce stress, and enhance mental well-being.
7. In summary, while the brain is not a muscle that can be directly exercised, regular physical exercise positively impacts the brain by promoting neuroplasticity, improving blood flow, releasing beneficial chemicals, and reducing the risk of cognitive decline.
Therefore, the best explanation for why a consistent exercise regime has a positive impact on the brain is that exercise helps maintain and create pathways in the brain (Option C).
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Would you rather be hit by a 1-kg mass traveling at 10m/s or a 2-kg mass traveling at 5m/s? Why?
Support your answer.
Answer:
a 2 kg mass traveling at 5ms
Explanation:
because it wouldnt go so fast or be so heavy
Adiabatic cooling.....
A© Results from a change in volume
B© Results from the expansion of the air
C. Does not involve the addition or subtraction of heat from the environment
D• Meteorologists agree that adiabatic cooling is the most important factor in the formation of most atmospheric clouds
Adiabatic cooling refers to the cooling of a parcel of air as a result of its expansion due to a decrease in pressure or an increase in volume. This process occurs without the addition or subtraction of heat from the environment.
As the parcel of air rises in the atmosphere, it encounters lower atmospheric pressure, causing it to expand. The expansion leads to a decrease in temperature within the parcel, resulting in adiabatic cooling.
Adiabatic cooling plays a crucial role in the formation of atmospheric clouds. When warm, moist air rises, it undergoes adiabatic cooling due to expansion. As the air cools, it reaches its dew point, where the air becomes saturated with water vapor, leading to the formation of tiny water droplets or ice crystals. These tiny particles then condense on aerosols, such as dust or pollutants, to form visible clouds.
Meteorologists widely acknowledge that adiabatic cooling is a fundamental factor in cloud formation. Understanding the principles of adiabatic cooling helps predict cloud types, atmospheric stability, and weather patterns. It is essential for meteorologists to consider adiabatic processes to accurately forecast and study the behavior of clouds, precipitation, and other atmospheric phenomena.
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Plz answer will give brainliest answer to whoever does
Answer:A gas heater working
Explanation:because from the system of it it could be coal or just air being heated up it takes energy to make it hot! In other words convection
a hurricanes energy comes from?
Answer:
a or b
Explanation:
Answer:
The answer is C, condensation or large amounts of water vapor and the second question is correct too.
Explanation:
in hubble's classification, which type of galaxy has a small bulge and loose, widely spread, poorly defined spiral pattern?
The "d" in "Scd" signifies a small bulge, while the "c" indicates a relatively loose and poorly defined spiral pattern.
Which type of galaxy that has a small bulge and a loose in Hubble's classification system?In Hubble's classification system, the type of galaxy that has a small bulge and a loose, widely spread, and poorly defined spiral pattern is classified as a "Scd" galaxy.
Hubble's classification scheme categorizes galaxies into different types based on their visual appearance, particularly the structure of their spiral arms, the size of their central bulge, and the overall shape of the galaxy. The scheme ranges from elliptical galaxies (labeled E) to spiral galaxies (labeled S), with further subdivisions denoted by additional letters and numbers.
Within the spiral galaxy category, the classification progresses from tightly wound and well-defined spiral arms (Sa type) to intermediate spiral arms (Sb type) and finally to loosely wound and poorly defined spiral arms (Sc type). The "d" in "Scd" signifies a small bulge, while the "c" indicates a relatively loose and poorly defined spiral pattern.
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A magnetic field is oriented at an angle of 37° the normal of arectangular area 6.2 cm 7.5cm. If the magnetic flux through this surface has a magnitude of 4.7×10^−5Tm^2, what is the strength of the magnetic field?Express your answer using two significant figures.B=____ mT
The strength of the magnetic field is approximately 2.8 mT.
The equation is:
Φ = B × A × cos(θ)
You are given the magnetic flux (Φ = 4.7 × \(10^-^5\) \(Tm^2\), the angle (θ = 37°), and the dimensions of the rectangular area (6.2 cm x 7.5 cm). First, we need to calculate the area (A):
A = length × width = 6.2 cm × 7.5 cm = 46.5 \(cm^2\)
= 0.00465 \(m^2\)
Next, rearrange the magnetic flux equation to solve for the magnetic field (B):
B = Φ / (A × cos(θ))
Now, plug in the given values and calculate the magnetic field:
B = (4.7 ×\(10^-^5\) \(Tm^2\)) / (0.00465\(m^2\)× cos(37°)) ≈ 0.00283 T
Finally, convert the magnetic field strength to milli tesla (mT) and express it using two significant figures:
B = 0.00283 T × 1000 mT/T ≈ 2.8 mT
So, the strength of the magnetic field is approximately 2.8 mT.
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A collection of a fixed number of elements (called components) arranged in n dimensions ( n >= 1) is called a(n) ____.
A collection of a fixed number of elements (called components) arranged in n dimensions ( n >= 1) is called a(n) n- dimensional array
an array of dimensions gives Information about the material composition for each point in the heterogeneous part is stored in N.
Similar to a one-dimensional array, a two-dimensional array is represented graphically as a grid (or table) with rows and columns.
A big gathering of objects or people is referred to as a "array," especially one that is eye-catching, inspires admiration, or has been arranged in a particular way: The spread of food on the table was magnificent. They were seated in front of numerous microphones and cameras. Related words and phrases are part of the SMART Vocabulary. Things in groups and collections
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A typical microwave oven produces radiation at a frequency of 2.0 × 10^10 hertz. What is the wavelength of this microwave radiation?
Answer:
0.120m
Explanation:
What is the acceleration of a 50 kg object pushed with a force of 500 newtons?
F=ma
a=F/m
a=500N/50kg
a=10m/s2
Answer:
Explanation:
m=1000kg and a=3m/s2 . hence, the force needed to accelerate the 1000kg car by 3m/s2 is 3000N
what is the mass of a hiker 350m above the ground if her GPE is 120,200 J?
Given:
The height from the ground is h = 350 m
The gravitational potential energy is GPE = 120,200 J
To find the mass of the hiker.
Explanation:
The mass of the hiker can be calculated by the formula
\(\begin{gathered} GPE\text{ =mgh} \\ m\text{ =}\frac{GPE}{gh} \end{gathered}\)Here, g =9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the mass of the hiker will be
\(\begin{gathered} m\text{ =}\frac{120200}{9.8\times350} \\ =35.044\text{ kg } \end{gathered}\)Thus, the mass of the hiker is 35.044 kg
Can you find the net force of one vertical force and one horizontal force, such as in the picture below? Yes or no, and why?
Answer:
jwuwhisbuebeu said that good morning and private s the
Answer:
the answer to this question is a⁵/c²
the major factor in the development of a constitution is
Answer:
Below are some of the important dates that led to the creation of the Constitution: 1775 — The Revolutionary War between the Colonies and Britain begins. ... 1781 — The last battle of the Revolutionary War takes place; the 13 states set up a federal government under laws called the Articles of Confederation.
Explanation:
please give me a heart
a wheel barrow has a weight of 80N. It needs an upforce of 20N to keep the handles horizontal. from the handle to the wheel it is 1.5m. 1: what is the moment of 20N about the wheel? 2: what is the distance of the wheel to the centre of mass of the wheelbarrow?
(1) The moment of 20N about the wheel is 30 Nm. (2) The distance of the wheel to the center of mass of the wheelbarrow is 1.2m.
1. The moment of 20N about the wheel can be calculated using the formula:
Moment = Force x Distance
Moment = 20N x 1.5m
Moment = 30 Nm
2. To find the distance of the wheel to the center of mass of the wheelbarrow, we can use the principle of moments, which states that the sum of the clockwise moments about a point is equal to the sum of the anticlockwise moments about the same point. Let the distance from the wheel to the center of mass be x.
Clockwise moment = Weight x Distance
Clockwise moment = 80N x (1.5m - x)
Anticlockwise moment = Upforce x Distance
Anticlockwise moment = 20N x x
Using the principle of moments:
80N x (1.5m - x) = 20N x x
Simplifying and solving for x:
120m = 100x
x = 1.2m
Therefore, the distance of the wheel to the center of mass of the wheelbarrow is 1.2m.
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When animals such as fox, deer and bears eat fruits from plants, the seeds are typically completely digested. True False
Answer:
False.
Explanation:
The plants rely on animals to spread their seeds, thats why they make fruits so the animals eat em, the seeds are strong enough to survive the animals stomach and come out the other end.