Answer:
Specific gravity of other fluid = .854 (Approx)
Explanation:
Given:
Mass of water = 35 g
Mass of filled bottle with water = 98.44 g
Mass of filled bottle with fluid = 89.22 g
Computation:
Mass of water = 98.44g - 35g = 63.44g
Density of water = 1000 g/L
Volume of bottle = 63.44/1000 = 0.06344L
Mass of other liquid = 89.22g - 35g = 54.22g
Density of other liquid = 54.22g/0.06344L = 854.665826 g/L
Water has a specific gravity = 1
So , specific gravity of other fluid
1000 / 854.665826 = 1 / specific gravity of other fluid
Specific gravity of other fluid = .854 (Approx)
Choose the true statement(s) about binary fission in prokaryotic cells. There may be more than one correct answer.
1. Binary fission is a type of sexual reproduction which introduces genetic variation from parent to offspring.
2. Binary fission frequency differs between species and is affected by environmental conditions.
3. Binary fission is a type of asexual reproduction that is simpler than mitosis.
4. Binary fission results in offspring, which are genetically identical to the parent cell.
Answer:
2. Binary fission frequency differs between species and is affected by environmental conditions
4. Binary fission results in offspring, which are genetically identical to the parent cell.
Explanation:
Binary fission is the process of asexual reproduction of single-celled organisms that consists of dividing a cell into two by mitosis, each with the same genome as the "mother cell" (with the same DNA or genetic material as the "mother cell" ).
The binary fission process is directly affected by genetics, that is, it varies from species to species. In addition, binary fission occurs depending on specific environmental conditions (such as water, optimal temperatures and also pH).
Which image best illustrates diffraction
Answer:
There is no image
Explanation:
Answer: Send me image than I will be able to help
Explanation:
A capacitor is formed from two square plates of edge length a and separation d, with d <
In an electrical circuit, a capacitor is a component that is used to hold charges.
A capacitor operates under the principle that when an earthed conductor is moved close to a conductor, its capacitance increases noticeably. As a result, a capacitor contains two plates with equal and opposing charges that are spaced apart.
Two metal plates, a substance known as a dielectric, and other components make up a capacitor.
The dielectric is positioned between the parallel metal plates, which are positioned very near to one another, to prevent them from touching.
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Like geothermal energy, solar heat is another clean and sustainable source of energy. Under ideal conditions (midday, no
clouds) photovoltaic cells, often called solar panels, can produce as much as 200 watts per square meter. Even though geothermal produces less energy than this, what advantage does geothermal energy have over solar energy?
Answer:It is known that geothermal vitality has numerous preferences compared with sun oriented and wind frameworks. These points of interest incorporate climate confirmation, base stack, incredible steadiness, and tall warm effectiveness. The entire introduced capacity of geothermal power, be that as it may, is much less than sun powered and wind.
Answer:
The amount of sunlight received depends on time of day and weather. So, the amount of solar energy produced can be inconsistent. However, heat flows out of Earth all the time, so the supply of geothermal energy is more reliable and consistent.
Explanation:
PLATO
The gravitational energy of a swimmer on a driving board at different heights is shown in the table below. What is the driver's gravitational energy at 5m high? (A) 5500 J (B) 2750 J (C) 8800 J (D) 3300 J
Answer:
E = 2750 J at h = 5 m
Explanation:
The gravitational potential energy is given by :
\(E=mgh\)
In this case, m is the mass of swimmer is constant at every heights. So,
At h = 1 m, E = 550 J
\(550=m\times 10\times 1\\\\m=55\ kg\)
So, at h = 5 m, gravitational potential energy is given by :
\(E=55\times 10\times 5\\\\E=2750\ J\)
So, the correct option is (B).
examples of ohmic conductors
The examples of ohmic conductors are :
Silver(Ag), copper(Cu), aluminium(Al) etc.
How can we conclude that these are ohmic conductors?Ohmic conductors means which conductors strictly obey the Ohm's law, are known as Ohmic conductors.
Resistance= \(\frac{Voltage}{Current}\)
In other words there is a linear relationship between voltage and current for all values. That means all the ohmic conductor materials shows a linear character in the V-I characteristic graph.
So, the examples of ohmic conductors are:
Silver(Ag), copper(Cu), aluminium(Al) etc.
All the conductors we mentions here, they all show a linear line in the V-I characteristic graph.
From the above discussion we can conclude that, Silver(Ag), copper(Cu), aluminium(Al) etc. these are the ohmic conductors.
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A phone with a mass of 0.2 kg is dropped from a height of 30 m what is it’s speed when it hits the ground?the acceleration of gravity is 9.8ms
Answer:
24.2 m/s
Explanation:
Mass is irrelevant in this situation....
Displacement: ( to find time)
x = xo + vo t - 1/2 at^2
30= 0 + 0 - 1/2 (9.8)t^2
t = 2.47 seconds
Velocity:
vf = a t = 9.8 (2.473) = 24.2 m/s
On a frictionless horizontal air table, puck A (with mass 0.251 kg ) is moving toward puck B (with mass 0.371 kg ), which is initially at rest. After the collision, puck A has velocity 0.120 m/s to the left, and puck B has velocity 0.654 m/s to the right.
What was the speed vAi of puck A before the collision?
Calculate ΔK , the change in the total kinetic energy of the system that occurs during the collision.
(a) The speed of puck A before the collision is determined as 0.847 m/s.
(b) The change in the total kinetic energy of the system that occurs during the collision is 0.009 J.
Speed of puck A before the collisionThe speed of puck A before the collision is calculated from the principle of conservation of linear momentum as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.251u₁ + 0.371(0) = 0.251( -0.12) + 0.371(0.654)
0.251u₁ = 0.2125
u₁ = 0.2125/0.251
u₁ = 0.847 m/s to the right
Change in the total kinetic energy of the systemInitial kinetic energy = ¹/₂ x 0.251 x (0.847)² + ¹/₂ x 0.371 x (0) = 0.09 J
Final kinetic energy = ¹/₂ x 0.251 x (-0.12)² + ¹/₂ x 0.371 x (0.654)² = 0.081 J
ΔK.E = 0.081 - 0.09 = 0.009 J ≈ 0 J
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Cells use nutrients and oxygen to supply the body with the energy it needs. What three-body systems are working together in this situation?
A
nervous, digestive, and circulatory systems
B
digestive, circulatory, and excretory systems
C
circulatory, immune, and respiratory systems
D
digestive, respiratory, and circulatory systems
Answer:
The respiratory system provides oxygen for cells, while the circulatory system transports oxygen to cells.
Explanation:
so the answer is D
True of false
The graduated cylinder is empty before using the overflow container to fined volume
Answer:
True
Explanation:
A long straight wire carrying a current of 3A flowing in a direction parallel to the unit vector 1 (i+j+ k) is placed in a √√3 --↑ this is the a magnetic field of (0.75i + 0.4k)T. What is the magnetic force per unit length of the wire? A. (0.69i-0.61j - 1.3k )N/m.. B. (0.39i-0.4j-2.3 k )N/m C.(0.49i-0.51j - 1.37k )N/m D. (0.59-0.71j-0.13k )N/m
The magnetic force per unit length of the wire is (C) (0.49i - 0.51j - 1.37k) N/m.
To calculate the magnetic force per unit length of the wire, we can use the formula:
F = I * (L x B),
where F is the force, I is the current, L is the length vector of the wire, and B is the magnetic field.
Given:
Current, I = 3A
Length vector, L = √√3 * (i + j + k)
Magnetic field, B = 0.75i + 0.4k
Let's calculate the cross product of L and B:
L x B = | i j k |
|√√3 √√3 √√3|
|0.75 0 0.4|
To evaluate this cross product, we calculate the determinants:
(i) component: (√√3 * 0 - √√3 * 0.4) = -0.4√√3
(j) component: (-√√3 * 0.75 - √√3 * 0) = -0.75√√3
(k) component: (√√3 * 0.75 - √√3 * 0) = 0.75√√3
Now, multiply the cross product by the current:
F = 3A * (-0.4√√3i - 0.75√√3j + 0.75√√3k)
Simplifying this expression gives:
F = (-1.2√√3i - 2.25√√3j + 2.25√√3k) N
Therefore, the magnetic force per unit length of the wire is approximately (-1.2√√3i - 2.25√√3j + 2.25√√3k) N/m.
Comparing the given answer options, the closest match is C. (0.49i - 0.51j - 1.37k) N/m.
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Differences between LED and CFL bulb..
Explanation:
CFL bulbs were made to take the place of incandescent bulbs, which generate light as a result of heat. ... LED (light-emitting diode) is a type of bulb that produces light using a narrow band of wavelengths. LED lighting is more energy efficient than CFL bulb.
Please help me and thank you
Answer:
536.56 m/s
Explanation:
We'll begin by calculating the momentum of the Porsche. This can be obtained as follow:
Mass (m) of Porsche = 1361 kg
Velocity (v) of Porsche = 26.82 m/s
Momentum of Porsche =?
Momentum = mass × velocity
Momentum = 1361 × 26.82
Momentum of Porsche = 36502.02 Kgm/s
Finally, we shall determine the velocity you need to be running with in order to have the same momentum as the Porsche. This can be obtained as follow:
Your Mass = 68.03 kg
Your Momentum = Momentum of Porsche = 36502.02 Kgm/s
Your velocity =?
Momentum = mass × velocity
36502.02 = 68.03 × velocity
Divide both side by 68.03
Velocity = 36502.02 / 68.03
Velocity = 536.56 m/s
Thus you must be running with a speed of 536.56 m/s in order to have the same momentum as Porsche.
as one tectonic plate slides under another , a string of volcanoes called a "volcanic arc" often results. Diorite is formed as magma at a volcanic arc cools beneath earths surface.
what type of rock is diorite
A.metamorphic
B.extrusive igneous
C.sedimentary
D.instrusive igneous
Answer:
D. instrusive igneous
Explanation:
Answer: it’s intrusive igneous
Explanation:
I got it right.
explain why something falling reaches a top speed, draw free diagrams
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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2) A ray of light in air is approaching the boundary with water at an
angle of 52 degrees. Determine the angle of refraction of the light
ray. (Refractive index of air = 1, water = 1.33)
=
Answer:
Explanation:
ASSUMING the 52° is the angle of incidence measured from the perpendicular to the surface
n₁sinθ₁ = n₂sinθ₂
1 sin52 = 1.33sinθ₂
θ₂ = arcsin(sin52 / 1.33)
θ₂ = 36°
as measured from the perpendicular to the surface
1. The air inside a tire pump occupies a volume of 130. cm at a pressure of one atmosphere. If the volume decreases to 40.0 cm", what is the pressure, in atmospheres, inside the pump?
Answer:
3.25 [atm.]
Explanation:
1) pV=const, where p - pressure, V - volume.
2) According to this formula: 1*130=40*p=const, then p=130/40=3.25 [atm.]
PS. if it is possible check the suggested solution in other sources.
The pressure - volume relation can be determined using Boyle's law. The pressure of the air after the decrease of volume will be 3.25 atm.
What is Boyle's law?According Boyle's law, at constant temperature, the volume of a gas is inversely proportional to the pressure of the gas.
Thus, PV = a constant.
Let P1 and V1 be the initial pressure and volume of the gas and P2 and V2 be the final pressure and volume. Then,
P 1 V1 = P2 V2.
Given that, V1 = 130 cm³
P1 = 1 atm
V2 = 40 cm³.
then P2 = P 1V1/V2
= 130 cm³× 1 atm / 40 cm³
= 3.25 atm.
Therefore, the pressure inside the pump will be 3.25 atm.
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When an automobile moves towards a listener, the sound of its horn seems relatively
a. Low pitched (low frequency) b. High Pitched (high frequency)
c. Normal (no change in frequency)
Answer:
Higher Pitched! (b)
Explanation:
The Doppler effect makes it seem high pitched, as the sound waves are mushed together at a higher frequency, while moving away, the sound waves spread out like a lower frequency wave!
What is the difference between a circuit and a current?
Question 8 options:
a circuit is a complete loop that carries a current in the form of electrons from negative to positive
a current is a complete loop that carries a circuit in the form of electrons from negative to positive.
a current is a light bulb connected to a battery and a circuit is something that slows the electricity down.
a circuit is a light bulb connected to a battery and a current is the wire connecting it.
Answer:
a circuit is a complete loop that carries a current in the form of electrons from negative to positive
Explanation:
The difference between current and circuit is that a circuit is a complete loop that carries a current in the form of electrons from negative to positive .
In a circuit, there are difference elements or components such as the battery, wire, resistor. The goal of a circuit arrangement is to completely carry current from one end to another.
The current is the quantity of charge that flows within the circuit per unit of time.
So, the battery supplies the electromotive force to move the current round the circuit.
what is diffusion and osmosis
Answer:
In explanation
Explanation:
DIFFUSION:
The movement of particles from a region where they are in higher concentration to a region where they are in lower concentration until the equilibrium is achieved is known as the process of "Diffusion". It occurs in all three states of matter, that is solid, liquid and gas.
OSMOSIS:
When the particles of a solvent move from a region of higher concentration to a region of lower concentration through a semi-permeable membrane until the concentration of the solution is balanced, is known as "Osmosis". It occurs in liquids only.
The age and crisis of the stage trust vs. mistrust
Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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A pinball machine launches a .045 kg ball at a speed of 9.2 m/s. Determine the potential energy of the spring just before it launched the pinball
Given :
A pinball machine launches a .045 kg ball at a speed of 9.2 m/s.
To Find :
The potential energy of the spring just before it launched the pinball.
Solution :
We know, their is no external force applied on system.
It means that kinetic energy will remains constant.
Initial Energy = Final Energy
\(K.E_i + P.E_i = K.E_f + P.E_f\\\\0 + P.E_i= \dfrac{mv^2}{2}+ 0\\\\P.E_i = \dfrac{0.045 \times 9.2^2}{2}\ J\\\\P.E_i = 1.9044\ J\)
Therefore, the potential energy of the spring just before it launched the pinball os 1.9044 J.
Exercise 24.28
For the capacitor network shown in (Figure 1), the potential difference across ab is 48 V.
Part A
Find the total charge stored in this network.
Express your answer with the appropriate units.
Q = ___ ____
Part B
Find the charge on the 150nF capacitor.
Express your answer with the appropriate units.
Q₁ = 7.2uC
Part C
Find the charge on the120nF capacitor.
Express your answer with the appropriate units.
Q₂ = 5.76 uC
Part D
Find the total energy stored in the network.
Express your answer with the appropriate units.
U = ____ ____
Part E
Find the energy stored in the 150nF capacitor.
Express your answer with the appropriate units.
U₁ = ______
Part F
Find the energy stored in the 120nF capacitor.
Express your answer with the appropriate units.
U₂= _____
Part G
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₁= ____
Part H
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₂ = ____
The evaluation of the capacitor (in series) network is as follows;
Part A
Q = 3.2 μC
Part B
Q₁ = 3.2 μC
Part C
Q₂ = 3.2 μC
Part D
U = 76.8 μJ
Part E
U₁ = 34 2/15 μJ
Part F
U₂ = 53 1/3 μJ
Part G
V₁ = 21 1/3 V
Part H
V₂ = 26 2/3 V
What is a capacitor?A capacitor consists of pairs of conductors separated by insulators. Capacitors are used to store electric charge.
The specified parameters are;
The voltage across ab = 48 V
The capacitance of the first capacitor, C₁ = 150 nF
Capacitance of the second capacitor, C₂ = 120 nF
Part A
The total charge in a capacitor network can be found as follows;
\(C_{eq} = \left(\dfrac{1}{150} + \dfrac{1}{120} \right)^{-1} nF = \left(\dfrac{3}{200} \right)^{-1}nF\)
\(C_{eq} =\left(\dfrac{3}{200} \right)^{-1}nF=66\frac{2}{3} \, nF\)
\(Q_{eq} = C_{eq}\times V_{ab}\)
Therefore;
\(Q_{eq}\) = 66 2/3 nF × 48 V = 3,200 × 10⁻⁹ C = 3.2 μC
The total charge in the circuit is 3.2 μCPart B
The charge in the 150 nF capacitor is obtained from the formula for the charge in a capacitor; Q = C × V as follows;
Q = C₁V₁ = C₂V₂
The charge in the capacitors, C₁ and C₂ are the same as the total charge of 3.2 μC
The charge, Q₁ on the 150 nF capacitor, C₁ is therefore, 3.2 nC
Q₁ = 3.2 nCPart C
The capacitors, C₁ and C₂ are in series, therefore, the charge in each capacitor is equivalent to the charge in the circuit, which is 3.2 μC.
Therefore, the charge, Q₂, in the 120 nF capacitor, C₂ is 3.2 μC
Q₂ = 3.2 μF
Part D
The total energy stored in the network can be obtained using the formula;
U = (1/2)·C·V²
Where;
U = The energy in the capacitor
C = The equivalent capacitance of the network = 66 2/3 nF
V = The voltage
Therefore;
\(U = \dfrac{1}{2} \times C_{eq}\times V^2\)
\(U = \dfrac{1}{2} \times 66\frac{2}{3} \times 10^{-9}\times 48^2 = 76.8\)
The total energy in the circuit, U = 76.8 μJPart E
The energy stored in the 150 nF capacitor is found as follows;
\(Q_{eq}\) = Q₁ = C₁ × V₁
V₁ = \(Q_{eq}\) ÷ C₁
Therefore;
V₁ = 3.2 μC ÷ 150 nF = \(21\frac{1}{3}\) V
U₁ = 0.5×C₁×V₁²
U₁ = 0.5 × 150×10⁻⁹ × \(\left(21\frac{1}{3} \right)^2\) = 34\(\frac{2}{15}\) μJPart F
The energy stored in the 120 nF capacitor, U₂, can be found as follows;
V₂ = 3.2 μC ÷ 120 nF = \(26\frac{2}{3}\) V
U₂ = 0.5 × 150 nF × \(\left(26\frac{2}{3} \, V\right)^2\) = \(53\frac{1}{3}\, \mathrm{ \mu J}\)
The energy in the 120 nF capacitor is; U₂ = 53 1/3 μJPart G;
The potential difference across the 150 nF, obtained in Part E, is 21 1/3 V
V₁ = 21 1/3 VPart H
The potential difference across the 120 nF, obtained in part F, is 26 2/3 V
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If the Moon did not rotate at the same rate that it revolved, which of the following would be true?
Answer:
There will be no tides
Explanation:
The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double the specific heat of iron. If the temperature of the Aluminum's mass changes by /\T, what is the change in the Iron's mass temperature?
Answer:
it is double the temperature change of iron
A charge of +80 µC is placed on the x axis at x = 0. A second charge of –50 µC is placed on the x axis at x = 50 cm. What is the magnitude of the electrostatic force on a third charge of 4.0 µC placed on the x axis at x = 30 cm?
Answer:
Explanation:
77
The magnitude of the electrostatic force on a third charge of 4.0 µC placed on the x-axis at x = 30 cm is equal to 77 N.
What is coulomb's law?According to Coulomb’s law, the force of repulsion or attraction between two charged bodies is the multiplication of their charges and is inversely proportional to the square of the distance between them.
The magnitude of the electric force can be written as follows:
\(F =k \frac{q_1q_2}{r^2}\)
where k has a value of 9 × 10⁹ N.m²/C².
Given, the first charge, q₁ = + 80 ×10⁻⁶ C
The second charge , q₂ = - 50 × 10⁻⁶ C
The third charge, q₃ = + 4 ×10⁻⁶ C
The distance between these two charges (q₁ and q₃) , r = 0.30 m
The distance between these two charges (q₂ and q₃) , r = 0.20m
The magnitude of the electrostatic force on the third charges will be:
\(F =9\times 10^9 (\frac{80\times 10^{-6}C\times 4 \times 10^{-6}C}{(0.30)^2} ) +9\times 10^9 (\frac{50\times 10^{-6}C\times 4 \times 10^{-6}C}{(0.20)^2} )\)
F = 77 N
Therefore, the magnitude of the electrostatic force is equal to 77 N.
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Which two factors affect the electric force between two particles?
A. The distance between them
B. Their charges
C. The strong nuclear force
D. Gravitational force
E. Their mass
Answer:
a the distance between the