Part A: When a steady state is finally reached, the temperature reading T_2 of the outlet thermometer is T_1 + ∆T.
T_2 = 68.9°C
Part C: The power P at which the heater operates is 1800 W.
Part A:
At steady state, the power input (VI) equals the power used to heat the water. The power used to heat the water can be calculated as the product of mass flow rate (F), specific heat capacity (C), and the change in temperature (∆T).
VI = F * C * ∆T
To find the outlet temperature (T_2), we need to solve for ∆T:
∆T = (VI) / (F * C)
T_2 = T_1 + ∆T
Part B:
Given the specific values for T_1, I, V, and F, we can calculate T_2:
T_1 = 18°C, I = 15.0 A, V = 120 V, F = 0.500 kg/min, and C = 4200 J/(kg*K)
First, convert the flow rate F to kg/s:
F = 0.500 kg/min * (1 min / 60 s) = 0.00833 kg/s
Now, calculate the power input (VI):
VI = 15.0 A * 120 V = 1800 W
Next, find ∆T:
∆T = (1800 W) / (0.00833 kg/s * 4200 J/(kg*K)) = 50.9 K
Finally, find T_2:
T_2 = 18°C + 50.9 K = 68.9°C
Part C:
The power P at which the heater operates is equal to the power input (VI):
P = VI = 1800 W
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Theo made a dog out of modeling clay. Which type of model is this?
i give 60 points to anyone who answers
Answer: I think it's C.
Explanation:2D is only one side and 3D has length width and height
Answer:
3d
Explanation:
Which of the following is an example of an energy transfer?
Elastic energy becomes kinetic energy as a ball bounces
OA billiard ball collides with a second billiard ball which is initially at rest, making it move.
Elastic potential energy is initially at rest, making it move.
Elastic potential energy is what causes a ball to bounce or rebound because it is transformed into kinetic energy and used to raise the ball back up. However, because some of the ball's energy was transferred to the ground or changed into sound (in the noise it makes upon impact) and heat energy, the ball won't go as high as it did at first (friction with the table). Additionally, even though we cannot see it, the ball alters once it strikes the ground or a table, energy is needed to take shape for a brief period of time.
Because of this, each bounce has a slightly lower height than the one before it. The ball has some kinetic energy when it hits the floor, but some of it is changed, so it loses some of it each time it bounces. After a few bounces, the ball has so little kinetic energy remaining that it stops bouncing.
Thus the correct answer is option A.
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An airport screens bags for forbidden items, and an alarm is supposed to be triggered when a forbidden item is detected. Suppose 5% of bags contain forbidden items. If a bag contains a forbidden item, there is a 98% chance that it triggers the alarm. If it doesn't contain a forbidden item, there is an 8 % chance that it triggers the alarm. Given a randomly chosen bag triggers the alarm, what is the probability that it contains a forbidden item
A randomly chosen bag triggers the alarm, the probability that it contains a forbidden item can be calculated using Bayes' theorem. The probability is approximately 80.56%.
What is the probability that a bag contains a forbidden item if it triggers the alarm?To determine the probability that a bag contains a forbidden item given that it triggers the alarm, we can use Bayes' theorem. Let's denote event A as "bag contains a forbidden item" and event B as "bag triggers the alarm." We are given that the probability of event A is 5% (0.05) and the probability of event B given A is 98% (0.98). Additionally, the probability of event B given not A (i.e., the alarm being triggered by a bag without a forbidden item) is 8% (0.08). Using these probabilities, we can apply Bayes' theorem:
\(P(A|B) = (P(B|A) * P(A)) / (P(B|A) * P(A) + P(B|not A) * P(not A))\)
Substituting the given values, we get:
\(P(A|B) = (0.98 * 0.05) / (0.98 * 0.05 + 0.08 * 0.95) = 0.8056\)
Therefore, the probability that a bag contains a forbidden item, given that it triggers the alarm, is approximately 80.56%.
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a pump draws water through an 8.0 in. suction pipe and discharges it through a 4.0 in. pipe in which the velocity is 12 ft/s. the 4.0 in. pipe discharges horizontally into air at c. to what height h (in feet) above the water surface at a can the water be raised if 25 hp is delivered to the pump? assume that the pump operates at 60% efficiency and that the head loss in the pipe between a and c is equal to 2uc2/2g.
The water can be raised to a height of approximately 15.7 m above the water surface at point A.
To solve this problem, we need to use the principles of fluid mechanics, specifically the Bernoulli's equation and the continuity equation.
A1v1 = A2v2
We know that the diameter of the 8.0 in. pipe is 8 in. = 0.6667 ft, so its cross-sectional area is:
A1 = \(π/4 x (0.6667 ft)^2 = 0.349 ft^2\)
Similarly,
A2 = \(π/4 x (0.3333 ft)^2 = 0.0873 ft^2\)
v1 = (A2v2)/A1 = \((0.0873 ft^2 x 12 ft/s)/0.349 ft^2\) = 2.39 ft/s
Next, we can use the Bernoulli's equation between points A and C to relate the pressure difference to the velocity difference:
P/ρ +\(v^2/2g\) + h = constant
h = (P/ρ - Patm)/g + z
We are given that the pump delivers 25 hp with 60% efficiency, so the power input to the pump is:
Pin = 25 hp/0.6 = 41.7 hp = 31.1 kW
Pin = QP/η
The volumetric flow rate can be calculated from the continuity equation:
Q = A1v1 = \(0.349 ft^2 x 2.39 ft/s = 0.834 ft^3/s\)
Substituting this into the above equation, we get:
P = Pinη/Q = \((31.1 kW x 0.6)/0.834 ft^3/s\) = 1773 Pa
Finally, we can substitute the known values into the Bernoulli's equation:
h = \((P/ρ - Patm)/g + z = (1773 Pa/1000 kg/m^3 - 101325 Pa)/9.81 m/s^2 + 0 m\)
h ≈ 15.7 m
Therefore, the water can be raised to a height of approximately 15.7 m above the water surface at point A.
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Variation #1: Create analytical maps of historical ownership, paved areas for cars, parks & natural amenities. areas,community Street Design
• Streets are public space, just like parks. How do we measure who a street is designed for?
Analytical maps can be created to depict historical ownership, paved areas for cars, parks, natural amenities, and community street design. Streets, being public spaces, require measurement to determine their intended beneficiaries.
Analytical maps offer a valuable tool for visualizing and understanding various aspects of urban planning. By creating maps that showcase historical ownership patterns, paved areas designated for cars, locations of parks and natural amenities, and community street design, it becomes easier to assess the distribution of resources and infrastructure within a city.
In this context, streets hold a significant role as public spaces. They are not solely meant for vehicular traffic but should also prioritize the needs and activities of pedestrians, cyclists, and the wider community. Analyzing street design through mapping can help evaluate whether streets are primarily designed to cater to cars or if they accommodate a balanced and inclusive approach that considers the needs of all users.
To achieve equitable urban environments, it is crucial to assess the intended beneficiaries of street design and identify any discrepancies or biases in the allocation of public space. By utilizing analytical maps, planners, policymakers, and communities can have a clearer understanding of the current state of street design and work towards creating more people-centric and sustainable cities.
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1. given that the work function for gold metal is 5.17 ev, what is the longest-wavelength electromagnetic radiation that can eject a photoelectron from gold? is this in the visible range?? g
The longest-wavelength electromagnetic radiation that can eject a photoelectron from gold is 475.6 nm and this is in visible range.
To calculate the longest-wavelength electromagnetic radiation that can eject a photoelectron from gold, we need to determine the threshold energy required to overcome the work function of gold.
The energy (E) of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant (approximately 4.1357 × 10^(-15) eV·s), c is the speed of light (approximately 2.998 × 10^8 m/s), and λ is the wavelength of the radiation.
To eject a photoelectron from gold, the energy of the incident photon must be greater than or equal to the work function (Φ) of gold. Given that the work function for gold is 5.17 eV, we can convert it to joules by multiplying by the conversion factor 1.602 × \(10^{-19}\) J/eV.
Φ = 5.17 eV × 1.602 × \(10^{-19}\) J/eV ≈ 8.29 × \(10^{-19}\) J
Now, we can calculate the longest wavelength λ that corresponds to this threshold energy:
E = hc/λ
8.29 × \(10^{-19}\) J = (4.1357 × \(10^{-15}\) eV·s) × (2.998 × \(10^{8}\)m/s) / λ
Solving for λ, we find:
λ ≈ 4.756 × \(10^{-7}\)m or 475.6 nm
Therefore, the longest-wavelength electromagnetic radiation that can eject a photoelectron from gold is approximately 475.6 nm. This falls within the visible range of the electromagnetic spectrum, specifically in the yellow-green region. So, the ejected photoelectron would not be visible, but the incident radiation would appear yellow-green to the human eye.
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Answer in the proper number of significant numbers
23.4 x 14
Answer:
327.6 is the answer but there is 2 sig figs in 14 so change it to 330
so 330 is the final answer
hope this helps
have a good day :)
Explanation:
The multiplication product of 23.4 × 14 is 327.6. However, there is only two significant figures in 14. So we have to take the answer in 2 significant figure. Hence, the product can be written as 3.3 × 10².
What are significant figures ?Significant figures are number of digits which can be counted as certain values associated with some uncertainties as well. There are certain rules regrading the count of significant figures in a number.
The zeros after a non-decimal number cannot be taken as significant. For eg, in 4500, there are only two significant figures. The common rule for all the arithmetic operation is that, the significant figures in the product have to be equal to the number of significant figure in the number in the operation with least significant figures.
Here, the one with least significant figures is 14. It have two significant figures. Now, product of the two numbers is :
23.4 × 14 = 327.6
But the rounded product for correct significant figure is 3.3 × 10².
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Elliot is going to start strength training at home. He does not have any weights and is
brand new to strength training but is young and healthy. What would be a good
household object to use to for strength training? (1 point)
O a can of soup
O a box of tissues
O a gallon of water
O a paperback book
Answer:
A gallon of water would be a good household object to use for strength training.
Explanation:
Gallon jugs of water typically weigh around 8.3 lbs, which can provide a good amount of resistance for strength training exercises such as bicep curls, shoulder presses, and tricep dips. Additionally, the handle on the jug of water makes it easy to grip and use for various exercises. Cans of soup and boxes of tissues are generally too light to provide enough resistance for strength training, and a paperback book may not be sturdy enough to use for certain exercises.
A wooden block with mass 1.15 kg is placed against a compressed spring at the bottom of a slope inclined at an angle of 29.0° (point A). When the spring is released, it projects the block up the incline. At point B, a distance of 7.55 m up the incline from A, the block is moving up the incline at a speed of 6.25 Im/s and is no longer in contact with the spring. The coefficient of kinetic friction between the block and incline is 0.45. The mass of the spring is negligible.
Constants Part A Calculate the amount of potential energy that was initially stored in the spring. Take free fall acceleration to be 9.80 m/s^2.
To calculate the amount of potential energy initially stored in the spring, we need to consider the conservation of mechanical energy.
The mechanical energy of the block-spring system is conserved when no external forces other than gravity and friction are acting on it. At point A, the mechanical energy is stored entirely as potential energy in the compressed spring. The potential energy stored in the spring can be calculated using the formula: Potential Energy (PE) = (1/2)kx^2
where k is the spring constant and x is the displacement of the spring from its equilibrium position.
To find the spring constant, we need to know the force constant of the spring (k) or the spring's compression distance (x). Unfortunately, this information is not provided in the given question. If you have any additional information about the spring constant or the compression distance, please provide it so that I can assist you further.
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A dog with an initial velocity of 2 m/s, runs after a ball accelerating at a rate of 10 m/s2 for 4
I got this questions for physics
Initial velocity (u) = 2 m/s
Acceleration (a) = 10 m/s^2
Time taken (t) = 4 s
Let the final velocity be v.
By using the equation,
v = u + at, we get
or, v = 2 + 10 × 4
or, v = 2 + 40
or, v = 42
The final velocity is 42 m/s.
which of these correctly compares the masses of different objects in the universe?
In comparison to a galaxy and a planet, a star is heavier. an accurate comparison of the cosmological masses of various objects.
Do stars have more mass than planets and less mass than galaxies?A galaxy has a mass that is between that of a moon and that of a planet. A planet has more mass than a star, which has less mass than a galaxy. The stars need a lot of mass to maintain nuclear fusion, which requires resulted in the production of each.
What is the proper ranking of the universe's elements, from smallest to largest?Planets and stars, solar systems, galaxies, and the cosmos are some key concepts to keep in mind in the following order: smallest to largest. Each phrase is a part of the following.
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How do you do this problem on Analyzing an L-R-C Circuit.?
Exercise 31.21: Analyzing an L-R-C Circuit.
You have a 195 ohm resistor, a 0.396 henry inductor, a 4.98 microfarad capacitor, and a variable-frequency ac source with an amplitude of 3.10 V . You connect all four elements together to form a series circuit.
___________________________________
Part A
At what frequency will the current in the circuit be greatest?
omega =
______________________________________…
Part B
What will be the current amplitude at this frequency?
I =
______________________________________…
Part C
What will be the current amplitude at an angular frequency of 402 rad/s ?
I =
______________________________________…
Part D
At this frequency, will the source voltage lead or lag the current?
A) the source voltage leads the current
B) the source voltage lags the current
The frequency will the current in the circuit be greatest is 447.15 rad/s. The current amplitude at this frequency is 0.0159A. The current amplitude at an angular frequency of 402 rad/s is 0.0148A.
Resistor, R = 195 Ω
Inductor, L = 0.396 H
Capacitor, C = 4.98 μF
Source voltage, V = 3.10 V
Frequency, f = ?
Angular frequency, ω = 2πf
The formula for the impedance of a series LRC circuit is given by;
Z = R + j(XL - XC)
whereZ is the impedanceR is the resistanceXL is the inductive reactance
XC is the capacitive reactance
Reactance, X = ωL - 1/ωC
Part A
The current in the circuit is maximum when the impedance is minimum.
So, we differentiate the expression for the impedance and equate it to zero to find the frequency at which the current will be maximum.
dZ/df = 0R + j(XL - XC)
= 0XL - XC
= 0ωL - 1/ωC
= 0ωL
= 1/ωCω
= 1/√(LC)ω
= 1/√(0.396 × 4.98 × 10⁻⁶)ω
= 447.15 rad/s
ω = 447.15 rad/s
Part B
The current amplitude at this frequency,
ω = 447.15 rad/s
Z = R + j(XL - XC)Z
= 195 + j(2π × 447.15 × 0.396 - 1/2π × 447.15 × 4.98 × 10⁻⁶)
Z = 195 - j12.188Ω |Z|
= √(195² + 12.188²)
= 195.07Ω
V = IRMS × |Z|IRMS
= V/|Z|IRMS
= 3.10/195.07
IRMS = 0.0159A
= IRMS
= 0.0159A
Part C
The current amplitude at angular frequency of 402 rad/s
Z = R + j(XL - XC)Z = 195 + j(402 × 0.396 - 1/402 × 4.98 × 10⁻⁶)
Z = 195 + j78.68Ω |Z|
= √(195² + 78.68²)
= 208.89ΩV
= IRMS × |Z|IRMS
= V/|Z|IRMS
= 3.10/208.89IRMS
= 0.0148A
I = IRMS
= 0.0148A
Part D
At this frequency, ω = 402 rad/s
We know that, X = ωL - 1/ωC
At this frequency, capacitive reactance is greater than inductive reactance.
XC > XLX = XC - XL
Capacitive reactance leads the inductive reactance in this case.
So, the source voltage lags the current.
B) The source voltage lags the current.
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Q1. Describe the changes to energy stores that take place when the following happen:
a) A ball falls in the air
b) An electric heater is switched on
Answer:
Part A: kinetic energy
Part b: electrical energy
This is because "When the energy is stored it is called electric potential energy and when it is moving in an electric current it is a form of kinetic energy. Our most common form of electrical energy is found in our wall outlets. "(softschools.com)
The change in energy stores that take place when the following happen:
a) A ball falls in the air – kinetic energy.
b) An electric heater is switched on - electrical energy
What is kinetic and electrical energy?Kinetic energy is the energy used in the working of a body. Electrical energy is the energy from by the moving of charged electrons.
The energy that an object has as a result of movement is known as kinetic energy. Perhaps the most significant characteristic of kinetic energy is its capacity for work.
Electric potential energy is the title for the electricity that is stored, while kinetic energy is the word for the power that is traveling in an electric charge. Our wall outlets house the most prevalent type of electrical energy.
Thus, a = kinetic energy, b = electrical energy.
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Which bronchus is about 5cm long and slightly narrower and more horizontal than the one on the opposite side
The bronchus of 5cm long, slightly narrower and more horizontal than the one on the opposite side is the left main bronchus.
What is a bronchus?A bronchus is a tubular structure that links the trachea with the lungs in the respiratory airways.
The main function of the bronchus is to transport oxygen during gas exchange, which is required in cellular respiration.
In conclusion, the bronchus of 5cm long, slightly narrower and more horizontal than the one on the opposite side is the left main bronchus.
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Which of the following instruments measures time most accurately?
a. Sundial
b. quartz watch
c. pendulum clock
d. watch with balance wheel
Answer:
b) Quartz Clock
Explanation:
It's is a very type of clock which uses the vibration of quartz crystals to measure time accurately
If two 100 ohms resistors are placed in series, their total resistance is what?
1) 10 000 ohms
2) 200 ohms
3) 100 ohms
4) 50 ohms
Answer:
add the Resistance
2(100)= 200
2) 200 ohms
If two 100 ohms resistors are placed in series, their total resistance will be 200 ohms
What is series combination ?When two or more resistors are connected end to end consecutively , they are said to be connected in series combination .Total resistance in series combination is calculated as the algebraic sum of individual resistances
General formula = R (equivalent ) = R1 + R2 + R3 + .......
let R1 = 100 ohms
R2 = 100 ohms
R(equivalent resistance in series combination )= R1 + R2
R = 100 + 100
R = 200 ohms
If two 100 ohms resistors are placed in series, their total resistance will be b) 200 ohms
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Which explanation best describes a wave?
A.
a disturbance that travels through a medium with a transfer of energy and matter
B.
a disturbance that travels through a medium without a transfer of energy and matter
C.
a disturbance that travels through a medium with a transfer of energy and without a transfer of matter
D.
a disturbance that travels through a medium with a transfer of matter and without a transfer of energy
E.
a disturbance that travels only in the absence of a material medium
Answer:
C. a disturbance that travels through a medium with a transfer of energy and without a transfer of matter
Explanation:
A wave is any disturbance that transfers energy from one location to the other via a substance called medium. It is important to note that a wave only conveys energy and not matter. For example, sound wave is a type of wave that carries sound energy from one place to another via mediums such as water, air etc.
Hence, according to this question, a wave can be described as a disturbance that travels through a medium with a transfer of energy and WITHOUT A TRANSFER OF MATTER.
A 0.149 kg glider is moving to the right on a frictionless, horizontal air track with a speed of 0.710 m/s . It has a head-on collision with a 0.308 kg glider that is moving to the left with a speed of 2.27 m/s . Suppose the collision is elastic.1. Find the magnitude of the final velocity of the 0.157kg glider.
2. Find the magnitude of the final velocity of the 0.306kg glider.
Answer:
v1 = −2.201946 m/s ( to the left)
v2 = 0.7780534 m/s ( to the right)
Explanation:
Given the following :
Mass of first glider (m1) = 0.149kg
Initial Speed of first glider (u1) = 0.710 m/s
Mass of second glider (m2) = 0.308kg
Initial Speed of second glider (u2) = 2.27m/s
For elastic collision:
m1u1 + mu2u2 = m1v1 + m2v2
Where V1 and v2 = final velocities if the body after collision.
Taking right as positive ; left as negative
u1 = 0.710m/s ; u2 = - 2.27m/s
u1 - u2 = - (v1 - v2)
0.710 - - 2.27 = - v1 + v2
v2 - v1 = 2.98 - - - - (1)
From:
m1u1 + mu2u2 = m1v1 + m2v2
(0.149 * 0.710) + ( 0.308 * - 2.27) = (0.149 * v1) + (0.308 * v2)
0.10579 + (-0.69916) = 0.149 v1 + 0.308v2
−0.59337 = 0.149 v1 + 0.308v2
Dividing both sides by 0.149
v1 + 2.067v2 = −0.59337 - - - - - (2)
From (1)
v2 = 2.98 + v1
v1 + 2.067(2.98 + v1) = −0.59337
v1 + 6.16 + 2.067v1 = −0.59337
3.067v1 = −0.59337 - 6.16
3.067v1 = −6.75337
v1 = −6.75337 / 3.067
v1 = −2.201946 m/s ( to the left)
From v2 = 2.98 + v1
v2 = 2.98 + (-2.201946)
v2 = 0.7780534 m/s ( to the right)
on the way to school the bus speeds from 20 m/s to 36 m/s in 4 seconds. what distance does the bus cover in this time frame
Answer:
d=s
t
d=36
4
d=10m/s
Explanation:
distance is equal to speed over t therefore 36 divide by 4 is 10
What observational evidence supports the idea that mercury once shrank by some 20 kilometers in radius?
As the train in the image moves to the right, which person hears the train horn at a lower pitch?
Answer:
Answer: Explanation: Person A's velocity relative to the train is 0. Therefore, the pitch of the horn will not change.
Explanation:
The person who hears the train horn at a lower pitch is A.
What is pitch?Pitch of any sound wave is directly proportional to the frequency. The higher frequency instruments have higher pitch.
As the train in the image (attached) moves to the right, Person A and B are sitting in the train. Person C and D are standing outside the train.
Person A's velocity relative to the train is 0. So, the pitch of the horn will not change.
Therefore, the person A will hear the train at lower pitch.
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it is now believed the majority of mass for most galaxies lies in their dark halos. True or False
The statement "It is now believed the majority of mass for most galaxies lies in their dark halos" is true.
Galaxies are vast systems of stars, gas, dust, and other celestial objects bound together by gravity. They are the building blocks of the universe and come in a variety of shapes, sizes, and compositions. Galaxies can range from small dwarf galaxies with a few million stars to massive galaxies with trillions of stars. They are distributed throughout the universe, forming clusters and superclusters. The Milky Way, which is the galaxy containing our solar system, is just one among billions of galaxies in the observable universe. Galaxies play a crucial role in the evolution and structure of the universe, and the study of galaxies helps us understand the formation, composition, and dynamics of celestial objects on a grand scale.
It is believed that the majority of mass in most galaxies lies in their dark halos. Dark matter, which is a hypothetical form of matter that does not interact with light or other forms of electromagnetic radiation, is thought to make up a significant portion of these dark halos. The presence of dark matter is inferred from its gravitational effects on visible matter and the dynamics of galaxies. While the exact nature of dark matter is still a subject of scientific investigation, its existence is widely accepted based on various observational evidence and theoretical models.
Hence, the statement is true.
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someone plz help me with this question and help fast
Which processes require the input of energy to overcome intermolecular forces?
Endothermic reactions like melting, evaporation, and sublimation need heat to escape intermolecular forces.
What is the easiest way to define energy?Energy is referred to by scientists as the capacity for work. People have figured out how to transform transformed from one medium to the next and then use it to accomplish tasks, making modern civilization possible.
What are energy and its measure?The capacity to perform labor is referred to as energy. A body's capacity for energy is determined by how much work it can accomplish when it is released. A scalar quantity, energy. The SI unit for energy is called a joule. One joule of energy is the amount of energy needed to perform one joule of work.
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What are some examples of objects or substances that are magnetic?
Answer:
iron,Cobalt and nickel
Rita is a salon owner. She notices that her salon charged one of her clients, Linda, extra for a service that the clent did not request. What do you think Rita should do? Α. Remaln qulet about the extra money. B. Distribute the money equally among the staff. C. Call the client and Inform her that she was incorrectly charged. D. Try overcharging the next client too and check if it goes unnoticed.
Answer:
C hope it helps
call the client and inform her that she was incorrectly charged.
Answer:
The answer is C. call the client and inform her that she was incorrectky charged
Explanation:
Calculate the net force on particle q₁.First, find the direction of the force particle q2 isexerting on particle q₁. Is it pushing to the right (+),or to the left (-)?
All we need to do in order to find out the direction is to take into account the sign of the charge. As they are both positive, the particles will repel each other, which can be seen on the following drawing:
Thus, particle q2 will try to push particle q1 to the left
The answer is: -
4. Hijackers are taking over a plane, They tell the pilot to get to Spain as fast as possible. The plane goes from 900
km/hr (beginning speed) to 1140 km/hr (final speed) in just 6 seconds. What is the acceleration of the plane?
What is a real world example of the Law of Conservation of Momentum?
Answer:
The thrust that you feel at the time of firing is one of the real-life example of the conseriation nomentum
A marble is thrown horizontally with a speed of 8. 50 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 58. 0o with the horizontal. With what speed does the marble hit the ground?
A marble is thrown horizontally with a speed of 8.50 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 58.0o with the horizontal. A marble is thrown horizontally with a velocity of 8.50 m/s from the top of a building and strikes the ground at an angle of 58.0° to the horizontal.
The initial velocity in the horizontal direction is u = 8.50 m/s and the angle it makes with the horizontal is θ = 0°. This means that in the vertical direction, it has an initial velocity of zero (v = 0 m/s) because it was thrown horizontally.The velocity v of the marble at the point of impact can be resolved into two components: one in the horizontal direction and the other in the vertical direction.
The velocity in the horizontal direction is the same as the initial velocity u, and the velocity in the vertical direction is v sinθ. So the velocity of the marble when it hits the ground is:v = √(u² + v sin²θ)v = √(8.50² + 16.7²)v = √(72.25 + 278.89)v = √351.14v = 18.73 m/sTherefore, the marble hit the ground with a speed of 18.73 m/s.
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