The values of x and y of the equiangular triangle is; x = 6 and y = 7
An equiangular triangle is one that has it's 3 sides and three interior angles equal.
We are given the length of the sides as;
6x + 1
6y - 5
7y - 2x
Thus;
6x + 1 = 6y - 5
6y - 6x = 6 ---- (eq 1)
Also;
6y - 5 = 7y - 2x
y = 2x - 5 ----(eq 2)
Put 2x - 5 for y in eq 1 to get;
6(2x - 5) - 6x = 6
12x - 30 - 6x = 6
6x = 36
x = 6
Put 6 for x in eq 2 to get;
y = 2(6) - 5
y = 12 - 5
y = 7
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Find the area of the triangle having the indicated angle and sides. A = 7°45', b = 9.5, c = 28
The area of the triangle, given the angle A = 7°45', side b = 9.5, and side c = 28, is approximately 18.03 square units. To find the area of a triangle given an angle and two sides.
We can use the formula for the area of a triangle:
Area = (1/2) * b * c * sin(A)
A = 7°45'
b = 9.5
c = 28
First, we need to convert the angle A from degrees and minutes to decimal degrees:
A = 7°45' = 7 + (45/60) = 7.75 degrees
Now we can substitute the values into the area formula:
Area = (1/2) * 9.5 * 28 * sin(7.75°)
Calculating:
Area ≈ (1/2) * 9.5 * 28 * sin(7.75°)
Area ≈ 133.6 * sin(7.75°)
Using a calculator or trigonometric table, we find that sin(7.75°) ≈ 0.1349.
Area ≈ 133.6 * 0.1349
Area ≈ 18.03
Therefore, the area of the triangle is approximately 18.03 square units.
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What is the median of the following set of scores 19 5 12 13 14?
The median for the given set of scores is 13.
The median is the middle point in a dataset—half of the data points are smaller than the median and half of the data points are larger.
Given,
A set of scores 19, 5, 12, 13, 14.
Arranging the set of numbers in ascending order,
=> 5,12,13,14,19
For a total of an odd number of outcomes, the median is defined as the middlemost value after sorting the data in ascending (OR) descending order.
For a total of an even number of outcomes, the median is calculated as the average of the two middlemost values after sorting the data in ascending (OR) descending order.
The total number of terms in the given data is 5, Hence the middlemost value is (5+1)/2 rd value is considered as the median,
Median= 3rd term = 13
Therefore, the median for the given set of scores is 13
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A parachute is descending at a rate of 28 feet per minute. Find the total change in altitude of the parachute after 4 minutes.
Answer:
The parachute descended 112 feet
Step-by-step explanation:
Solve each system by substitution: -3x + 5y = -4
x - 5y = 18
To solve the system by substitution, we can solve one of the equations for one of the variables, and then substitute that expression into the other equation.
From the second equation, we can solve for x:
x - 5y = 18
x = 5y + 18
Now we can substitute this expression for x into the first equation:
-3x + 5y = -4
-3(5y + 18) + 5y = -4
-15y - 54 + 5y = -4
-10y = 50
y = -5
Now that we know y = -5, we can substitute this value back into the expression we found for x:
x = 5y + 18
x = 5(-5) + 18
x = -7
Therefore, the solution to the system of equations is x = -7 and y = -5.
Answer:
\(x=-7,\,y=-5\)
Step-by-step explanation:
Elimination
\(-3x+5y=-4\\x-5y=18\\\\-3x+x=-4+18\\-2x=14\\x=-7\\\\x-5y=18\\(-7)-5y=18\\-5y=25\\y=-5\)
In the first step, you add the two equations to eliminate "y", and then it's easy to find x. Then, you substitute "x" back into either original equation and get "y" that way.
Substitution
\(-3x+5y=-4\\x-5y=18\\\\x=5y+18\\\\-3x+5y=-4\\-3(5y+18)+5y=-4\\-15y-54+5y=-4\\-15y+5y=50\\-10y=50\\y=-5\\\\x=5(-5)+18=-25+18=-7\)
In the first step, you solve the second equation for "x" and then plug that into the first equation, and then it's easy to find "y", and then "x".
Derek wants to order some roses online. Fibrst A charges $4.75
per blue rose plus $40 delivery charge. Florist B charges$5.15
per red rose plus $25 delivery charge. If Florist B increases the
cost per rose to $5.20, for what number of roses is it less
expensive to order from Florist A? From Florist B?
I wrote down an answer but idk I came up with 33.33
Answer:from florist A=34 roses
From florist b (you can really pick any number less than 34 and it proves to be less expensive)
Step-by-step explanation:
Florist a:
4.75(34)+40= $201.50
Florist b:
5.20(34)+25=$201.80
Bob wanted to study college students at UCLA and levels of homesickness. To do this, he did a random sample and wound up surveying 200 students out of all of UCLA students. Please pick the population:
The population in this scenario is all the students at UCLA.
In this case, the population refers to the entire group of individuals that Bob wanted to study, which is all the students at UCLA. The population represents the larger group from which the sample is drawn. The goal of the study is to investigate levels of homesickness among college students at UCLA.
Bob conducted a random sample by selecting 200 students out of the entire student population at UCLA. This sampling method aims to ensure that each student in the population has an equal chance of being included in the study. By surveying a subset of the population, Bob can gather information about the levels of homesickness within that sample.
To calculate the sampling proportion, we divide the size of the sample (200) by the size of the population (total number of students at UCLA). However, without the specific information about the total number of students at UCLA, we cannot provide an exact calculation.
By surveying a representative sample of 200 students out of all the students at UCLA, Bob can make inferences about the larger population's levels of homesickness. The results obtained from the sample can provide insights into the overall patterns and tendencies within the population, allowing for generalizations to be made with a certain level of confidence.
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In order to investigate treatments for morbid obesity, obese subjects satisfying fairly strict requirements were randomly assigned to one of three groups: gastric bypass surgery; participation in a diet and exercise program; or both gastric bypass surgery and participation in the diet and exercise program. Researchers carefully observed the amount of weight lost five years after the study began. Reference: Ref 9-1 This study uses the principles of A. randomization. B. confounding. C. blocking. D. All of the above Which of the following are principles of experimental design?
A. randomization B. replication C. blinding D. All of the above
Since all three principles of experimental design are likely to have been used in the study described, Therefore option D is correct.
All of the above are principles of experimental design. Randomization helps to ensure that groups are similar in all aspects except for the treatment received, reducing the effects of confounding variables. Replication allows for assessing the variability and consistency of results. Blinding reduces the risk of bias by preventing participants or researchers from knowing which treatment was received. The study described in the question uses all of these principles of experimental design.
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Show work for each rule and
explain if possible. Thank you.
3. Find the derivative. (10 pts) a) \( y=2 e^{-x}+x e^{3 x} \) b) \( y=\frac{3 x+\tan 2 x}{x \sec x} \)
a) Find the derivative of the function: y = 2e^(-x) + xe^(3x).
The rules used here are as follows:
The sum rule: [f(x) + g(x)]' = f'(x) + g'(x).The product rule: [f(x)g(x)]' = f'(x)g(x) + f(x)g'(x).
The chain rule: [f(g(x))] = f'(g(x))g'(x).Differentiate the function with respect to x; y = 2e^(-x) + xe^(3x)dy/dx = d/dx (2e^(-x)) + d/dx (xe^(3x))Using the sum rule, [f(x) + g(x)]' = f'(x) + g'(x)dy/dx = d/dx (2e^(-x)) + d/dx (xe^(3x))= -2e^(-x) + e^(3x) + 3xe^(3x)Using the product rule, [f(x)g(x)]' = f'(x)g(x) + f(x)g'(x)dy/dx = d/dx (2e^(-x)) + d/dx (xe^(3x))= -2e^(-x) + 3xe^(3x) + xe^(3x)(3)dy/dx = d/dx (2e^(-x)) + d/dx (xe^(3x))= -2e^(-x) + 3xe^(3x) + 3xe^(3x)
The final answer is dy/dx = -2e^(-x) + 4xe^(3x).
b) Find the derivative of the function: y = (3x + tan2x)/(xsecx).The rules used here are as follows:The sum rule: [f(x) + g(x)]' = f'(x) + g'(x).The quotient rule: [(f(x))/(g(x))] = [(f'(x))(g(x)) - (f(x))(g'(x))]/[g(x)]^2.
The chain rule: [f(g(x))] = f'(g(x))g'(x).Differentiate the function with respect to x; y = (3x + tan2x)/(xsecx)dy/dx = [(d/dx (3x + tan2x))(xsecx) - (3x + tan2x)(d/dx (xsecx))]/(xsecx)^2= [(3 + 2sec^2 2x)(xsecx) - (3x + tan2x)(secx tanx)]/(xsecx)^2Using the product rule, [(f(x))/(g(x))] = [(f'(x))(g(x)) - (f(x))(g'(x))]/[g(x)]^2dy/dx = [(d/dx (3x + tan2x))(xsecx) - (3x + tan2x)(d/dx (xsecx))]/(xsecx)^2= [(3 + 2sec^2 2x)(xsecx) - (3x + tan2x)(secx tanx)]/(xsecx)^2
The final answer is dy/dx = (2sec^2 2x - 3x tanx - 2x)/(x^2 cos^2 x).
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3/5 + 5/7 = ____
6/12 + 9/12 ____
1/4 + 4/4 = ____
2/3 + 5/3 = ____
(fractions please explain step by step how u got your answer)
The answers are 46/35 ,5/4, 5/4, 7/3
What is a fraction in math?A fraction is a part of a whole. In arithmetic, the number is expressed as a quotient, in which the numerator is divided by the denominator. In a simple fraction, both are integers. A complex fraction has a fraction in the numerator or denominator. In a proper fraction, the numerator is less than the denominator.
Given here: 3/5 + 5/7 = 46/35
6/12 + 9/12=5/4
1/4 + 4/4 = 5/4
2/3 + 5/3 = 7/3
Hence, The answers are 46/35 ,5/4, 5/4, 7/3
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Rebecca bought a square rug for her office. If the area of the rug is 65ft estimate the side length of the rug to the nearest tenth.
Answer:16.3 ft
Step-by-step explanation:
The estimated value of the side length of the square rug is : 8.062 feets
Given that the area of the square rug = 65 ft²
Recall :
Area of a square = s²
Where, s = side length
Therefore,
Area of rug = s²
65 ft² = s²
65 = s²
Square both sides
√65 = s
8.062 = s
The estimated side length of the rug is 8.062 feets.
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centers of adjacent faces of a unit cube are connected to form a regular octahedron. what is the volume of this octahedron?
The volume of octahedron when centers of adjacent faces of a unit cube are connected to form a regular octahedron is 1/16 unit ³.
Let the side length of a cube is 1unit.
Therefore length of all edges of the regular octahedron =2√2 unit .
Now the base of the pyramids is a square are will be (2√2)² =12 unit.
Now clearly the height of the pyramid is half the height of the cube, i.e.,1/2.
So volume of the Pyramid will be ⇒ 1/3× (Base area) × (height) = 1/3×1/2×1/2 = 1/12.
Therefore, the volume of the octahedron= 2 × volume of Pyramid= 2 ×1/12=1/6 unit³.
Hence, the volume of octahedron when centers of adjacent faces of a unit cube are connected to form a regular octahedron is 1/16 unit ³.
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PLEASE HELP! EASY MATH!!
Rosie measures the heights and arm spans of the girls on her basketball team. She plots the data and makes a scatterplot comparing heights and arm spans, in inches. Rosie finds that the trend line that best fits her results has the equation y = x + 2. If a girl on her team is 69 inches tall, what should Rosie expect her arm span to be?
A) 69 = x + 2
x = 67 inches
B) y = 69 - 2 = 67 inches
C) y = 69 inches
D) y = 69 + 2 = 71 inches
Answer:
Your answer would be D. I know this is kind of late, but maybe other people that come up here could get some help
Step-by-step explanation:
0.60792 liters x ________ = 607.92 mL
0.60792 liters x 1000 = 607.92 mL
Multiplying the volume in liters by 1000 converts it to milliliters.
If you go twice as fast, will your stopping distance increase by: A. Two times. B. Three times. C. Four times. D. Five times
If you go twice as fast, your stopping distance will increase by four times (option C).
This relationship is based on the laws of physics and the principles of motion.
When an object is in motion, its stopping distance is influenced by its initial speed, reaction time, and braking capabilities. The stopping distance consists of two components: the thinking distance (the distance traveled during the reaction time) and the braking distance (the distance needed to bring the object to a complete stop).
According to the laws of physics, the braking distance is directly proportional to the square of the initial speed. This means that if you double your speed, the braking distance will increase by a factor of four. In other words, going twice as fast will require four times the distance to come to a stop.
It is important to note that this relationship assumes other factors, such as road conditions and braking efficiency, remain constant. However, in real-world scenarios, these factors may vary and can affect the stopping distance to some extent.
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Solve for the value of a.
Answer: A= pp popo
Step-by-step explanation:
Answer: a = 22
Step-by-step explanation:
(2a + 3) +(6a +1 ) = 180
8a + 4 = 180
-4 -4
8a = 176
8 8
a = 22
They are supplementary angles, so they add up to 180 degrees.
Which expression can be used to approximate the expression below, for all positive numbers a, b, and x, where a not-equals 1 and b not-equals 1?
The following logarithmic expression can be used to approximate the given expression,
\(\frac{log_{b} x}{log_{b} a}\)
Finding the Logarithmic Expression
It is given that for all positive numbers a, b, and x on the condition that a≠1 and b≠1.
Now, for positive values of m and n, we have the following logarithmic expression,
\(\frac{log_{m} x}{log_{n} a}\)
Here, m, n and x are all positive numbers.
The logarithmic property imposes that m and n are not equal to 1.
So, by substituting the values m and n by a and b respectively, we get the following logarithmic expression,
\(\frac{log_{b} x}{log_{b} a}\)
Therefore, \(\frac{log_{b} x}{log_{b} a}\) is the required expression.
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Suppose f is a linear function with slope 2 and f(1)=3. Find f(2). must be sold?
According to the question the 5 must be sold.
Since f is a linear function with a slope of 2, we can write its equation in slope-intercept form as f(x) = mx + b, where m is the slope and b is the y-intercept.
We know that the slope, m, is 2. Thus, the equation for the function f(x) becomes f(x) = 2x + b.
To find the value of b, we can use the given information that f(1) = 3. Substituting x = 1 and f(x) = 3 into the equation, we have:
3 = 2(1) + b
Simplifying, we get:
3 = 2 + b
Subtracting 2 from both sides, we find:
b = 1
So, the equation for the linear function f(x) is f(x) = 2x + 1.
To find f(2), we substitute x = 2 into the equation:
f(2) = 2(2) + 1
f(2) = 4 + 1
f(2) = 5
Therefore, f(2) = 5.
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find sin A
a 4/5
b 5/4
c 3/5
d 5/3
e 3/4
f 4/3
Answer: 4/5 (first choice)
=========================================
Work Shown:
sin(angle) = opposite/hypotenuse
sin(A) = BC/AC
sin(A) = 24/30
sin(A) = (6*4)/(6*5)
sin(A) = 4/5
Please solve this problem please ASAP !
Answer:
3/x+2 = 4/y
then y equals
3y = 4(x+2)
y = 4x + 8 / 3
Please help me with my math!
Answer:
I believe it's A. but that's just what I think sorry I can't really back it up much
The answer is the third option, because the range is -6 and the third option says its greater than or equal to -2.
Help Me And If ITs Right Ill Give Brainliest to you
Answer: I thınk so aswer ıs B
Step-by-step explanation:
Mark, Jessica, and Nate each downloaded music from the same website. Mark downloaded 10 songs in total consisting of pop, rock, and hip hop. Jessica downloaded five times as many pop songs, twice as many rock songs, and three times as many hip hop songs as Mark. She downloaded 28 songs total. Nate downloaded 20 songs total with three times as many pop songs, three times as many rock songs, and the same number of hip hop songs as Mark. Which system of equations represents their music choices? x y z = 10 5x 2y 3z = 28 3x 3y z = 20 x y z = 10 2x 5y 3z = 28 3x 3y z = 20 x y z = 10 5x 2y 3z = 28 3x 3y 3z = 20 x y z = 10 2x 3y 5z = 28 x 3y 3z = 20.
Thus, the answer is the fourth option which is, x y z = 10 5x 2y 3z = 28 3x 3y 3z = 20.
Mark, Jessica, and Nate each downloaded music from the same website and this music consists of pop, rock, and hip hop songs.
Mark downloaded a total of 10 songs in total, with a combination of pop, rock, and hip hop songs.
Jessica downloaded five times as many pop songs, twice as many rock songs, and three times as many hip hop songs as Mark, with a total of 28 songs.
Nate downloaded 20 songs in total with three times as many pop songs, three times as many rock songs, and the same number of hip hop songs as Mark.
The system of equations that represents their music choices are:
x + y + z = 10
Equation 1 - 5x + 2y + 3z = 28
Equation 2 - 3x + 3y + z = 20
Equation 3 -Let x be the number of pop songs that Mark downloaded.
Let y be the number of rock songs that Mark downloaded.
Let z be the number of hip hop songs that Mark downloaded.
From the given information, Mark downloaded a total of 10
songs, so: x + y + z = 10 Equation 1 Jessica downloaded five times as many pop songs, twice as many rock songs, and three times as many hip hop songs as Mark.
She downloaded 28 songs total, so:
5x + 2y + 3z = 28
Equation 2 Nate downloaded 20 songs in total with three times as many pop songs, three times as many rock songs, and the same number of hip hop songs as Mark,
so: 3x + 3y + z = 20 Equation 3
Therefore, the system of equations that represents their music choices are:
x + y + z = 10
5x + 2y + 3z = 28
3x + 3y + z = 20
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find two unit vectors that are orthogonal to both i −k and i − 3j 2k.
The two unit vectors that are orthogonal to both i −k and i − 3j + 2k are:i - j / √2- i + j / √2
Given i - k and i - 3j + 2k.
Find two unit vectors that are orthogonal to both i −k and i − 3j 2k.
The two unit vectors orthogonal to both i - k and i - 3j + 2k are as follows:
First we find the cross product between i - k and i - 3j + 2k.
(i - k) × (i - 3j + 2k) = i × i - i × 3j + i × 2k - k × i + k × 3j - k × 2k= 0 + 2j - 3j - 0 + 0 + i = i - j
The cross product is (i - j).
Let v be any vector orthogonal to (i - j).
Let v = ai + bj + ck where (a, b, c) is a non-zero vector such that ai + bj + ck is orthogonal to (i - j).
We know that the dot product of two orthogonal vectors is zero. i.e (ai + bj + ck) • (i - j) = 0
(ai + bj + ck) • (i - j) = ai + bj + ck - aj - bj= (a - c)i - (a + b)j + ck
So we need to have (a - c) = (a + b) = 0 since (a, b, c) is non-zero implies ai + bj + ck is non-zero.
Therefore a = c and a = - b and a ≠ 0.
So a = - b and c = a.
Thus v = ai - aj + ak or v = -ai + aj + ak, both of which are unit vectors.
The two unit vectors that are orthogonal to both i −k and i − 3j + 2k are:i - j / √2- i + j / √2
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Two families go to a zoo. The Smith family of two adults and three children pay £61. The Jones family of three adults and five children pay £96. Work out the cost of an adult ticket and the cost of a child ticket. In your working, let 'a' stand for an adult ticket and 'c' stand for a child ticket.
The cost of an adult ticket is £17 and a child ticket is £9.
Let's assume 'a' for an adult ticket and 'c' for a child ticket
The cost of tickets for the Smith family of 2 adults and 3 children is £61
Equating, \(2a+3c=61\)
\(2a=61-3c\)
Dividing by 2, \(a=30.5-1.5c\) (equation 1)
Now, the cost of tickets for the Jones family of three adults and five children is £96
Equating, \(3a+5c=96\) (equation 2)
Using equation 1, \(3(30.5-1.5c)+5c=96\)
\(91.5-4.5c+5c=96\)
\(91.5+0.5c=96\)
\(0.5c=96-91.5\)
\(0.5c=4.5\)
\(c = \frac{4.5}{0.5}\)
\(c=9\)
Similarly, putting the answer of equation 2 in equation 1
we get, \(a=30.5-1.5c\)
\(a=30.5-1.5(9)\)
\(a=17\)
Therefore, adult tickets cost £17 and child tickets cost £9
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Give an example of a pair of series an and bn with positive terms where limn rightarrow infinity (an/bn) = 0 and bn diverges, but an converges. (Note this demostrates the contrapositive of the limit comparison test: "If one of an and bn converges and the other diverges, then limn rightarrow infinity (an/bn) = 0 or infinity or DNE. ")
Example that demonstrates the contrapositive of the limit comparison test. Let's consider a pair of series an and bn with positive terms, where lim(n→∞)(an/bn) = 0, bn diverges, but an converges.
Let's define the series an and bn as follows:
- an = 1/\(n^2\)
- bn = 1/n
Now, let's examine the limit:
lim(n→∞)(an/bn) = lim(n→∞)((1/\(n^2\)) / (1/n))
To simplify the limit expression, we multiply both numerator and denominator by \(n^2\):
lim(n→∞)(\(n^2\)(1/\(n^2\)) / \(n^2\)(1/n)) = lim(n→∞)(n/\(n^2\)) = lim(n→∞)(1/n)
As n approaches infinity, the limit becomes:
lim(n→∞)(1/n) = 0
Now, let's check the convergence of the series an and bn:
- an = Σ(1/\(n^2\)) is a convergent p-series with p = 2 > 1.
- bn = Σ(1/n) is a divergent p-series with p = 1.
Thus, we have provided an example of a pair of series an and bn with positive terms, where lim(n→∞)(an/bn) = 0, bn diverges, but an converges. This demonstrates the contrapositive of the limit comparison test, as requested.
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Solve for x in this equation: |2.5x – 6.8| = 12.9
i will make you brainliest
Answer:
x= 7.88
Step-by-step explanation:
2.5x - 6.8 = 12.9 add 6.8 to the right side
2.5x = 19.7 divide by 2.5
x = 7.88
A firm is expected to pay a dividend of $6.69 next year and $7.02 the following year and financial analysts believe the stock will be at thei tarhet price of $69.74 in two years. Compute the value of this stock assuming a erquired return of 10.50%
a. $92.21
b. $58.92
c. $83.45
d. 76.16
e. $62.37
f. $75.52
g. $63.49
The value of this stock, assuming a required return of 10.50%, is approximately $81.90. None of the given options match this value.
To compute the value of the stock, we can use the dividend discount model (DDM) formula. The DDM formula states that the value of a stock is equal to the present value of its future dividends.
Using the formula, we can calculate the present value of the dividends as follows:
PV(dividends) = D1 / (1 + r) + D2 / (1 + r)^2
where D1 is the dividend to be paid next year, D2 is the dividend to be paid in two years, r is the required return.
Given:
D1 = $6.69
D2 = $7.02
r = 10.50% or 0.105
Plugging in these values into the formula:
PV(dividends) = $6.69 / (1 + 0.105) + $7.02 / (1 + 0.105)^2
PV(dividends) = $6.05 + $6.11
PV(dividends) = $12.16
Finally, to compute the value of the stock, we add the present value of the dividends to the future target price of the stock in two years:
Value of stock = PV(dividends) + Future target price
Value of stock = $12.16 + $69.74
Value of stock = $81.90
Therefore, the value of this stock, assuming a required return of 10.50%, is approximately $81.90. None of the given options match this value.
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Can someone help me with these 3 questions please
Answer:
1. 1.5. 2.negitive 3. reciprocal hope it helps so sorry if its wrong
Two gamblers play a version of roulette with a wheel as shown in the file P05_63.xlsx. Each gambler places four bets, but their strategies are different, as explained below. For each gambler, use the rules of probability to find the distribution of their net winnings after four bets. Then find the mean and standard deviation of their net winnings. The file gets you started.
a. Player 1 always bets on red. On each bet, he either wins or loses what he bets. His first bet is for $10. From then on, he bets $10 following a win, and he doubles his bet after a loss. (This is called a martingale strategy and is used frequently at casinos.) For example, if he spins red, red, not red, and not red, his bets are for $10, $10, $10, and $20, and he has a net loss of $10. Or if he spins not red, not red, not red, and red, then his bets are for $10, $20, $40, and $80, and he has a net gain of $10.
b. Player 2 always bets on black and green. On each bet, he places $10 on black and $2 on green. If red occurs, he loses all $12. If black occurs, he wins a net $8 ($10 gain on black, $2 loss on green). If green occurs, he wins a net $50 ($10 loss on black, $60 gain on green).
The mean is 65.0646 and standard deviation is 39.082 when we can see the complete form of the table in the picture.
Given that,
As seen in the spreadsheet file P05 63.xlsx, two gamblers engage in a game of wheel-based roulette. Each gambler lays four bets, but each uses a different strategy, as will be seen later. Use the probabilities to determine the distribution of each gambler's net earnings after four bets. Then calculate their net wins' mean and standard deviation. You can get going with the file.
We have to find the mean and standard deviation.
We know that,
In the picture we can see the complete table.
Here, we calculated probability as,
For example take a first row
P(red=4, black=0, green=0) = (18/37)⁴ + 0 + 0 = 0.056
So the mean is 65.0646 and standard deviation is 39.082.
Therefore, The mean is 65.0646 and standard deviation is 39.082 when we can see the complete form of the table in the picture.
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find the shortest distance, d, from the point (1, 0, −4) to the plane x + y + z = 4.
The shortest distance from the point (1, 0, −4) to the plane x + y + z = 4 is approximately 0.577 units.
To determine the shortest distance, d, from the point (1, 0, −4) to the plane x + y + z = 4, we can use the formula for the distance between a point and a plane.
Let's first find a point on the plane.
To do that, we can set two of the variables equal to zero, then solve for the third variable.
For example, if we let x = 0 and y = 0, we can solve for z:0 + 0 + z = 4z = 4
So the point (0, 0, 4) lies on the plane x + y + z = 4.Now we can use the distance formula:d = |ax + by + cz + d| / sqrt(a² + b² + c²)
where (a, b, c) is the normal vector of the plane, and d is any point on the plane (in this case, (0, 0, 4)).
The normal vector of the plane x + y + z = 4 is (1, 1, 1), since the coefficients of x, y, and z are all 1.
So we can plug in these values to get:d = |1(1) + 1(0) + 1(-4) + 4| / sqrt(1² + 1² + 1²)d = 1/√3
(Note: √3 is the square root of 3)
Therefore, the shortest distance from the point (1, 0, −4) to the plane x + y + z = 4 is approximately 0.577 units.
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