an fcc metal is known to have a lattice parameter of 0.45 nm and an atomic weight of 96.4 g/mol. calculate its theoretical density in g/cm3. (answer format x.xx)

In this question, we have a situation where a gas is in constant pressure but changing its volume and temperature, and the best way to solve a situation like this, is through the Charles's gas law formula, which shows the relationship between volume and temperature when the pressure is constant. The formula is:

V1/T1 = V2/T2

We have:

V1 = 125 cm3, or 0.125 Liters

T1 = 10.0°C, or 283 K

V2 = 140 cm3, or 0.140 Liters

T2 = ?

Now we add these values into the formula:

0.125/283 = 0.140/T2

0.000442 = 0.140/T2

T2 = 0.140/0.000442

T2 = 317 K, or 44°C

The balanced equation for the reaction is N2(g) + O2(g) → 2NO(g).

The given value for the enthalpy change of the reaction is ΔH = 180.6 kJ. This value represents the heat released per mole of N2 reacted.

To determine the number of moles of NO produced, we need to calculate the moles of N2 reacted. Since the reaction is exothermic, the heat absorbed by the reaction is negative (-2976 kJ). However, it is not physically possible to have a negative number of moles. Therefore, we can conclude that no NO is produced in this case because the heat absorbed is insufficient to drive the reaction.

Using the equation ΔH = -2976 kJ/mol N2, we can set up a proportion:

180.6 kJ/1 mol N2 = -2976 kJ/x mol N2

Solving for x, we find:

x = (-2976 kJ * 1 mol N2) / (180.6 kJ) ≈ -16.46 mol N2

Since the reaction produces 2 moles of NO for every mole of N2, the number of moles of NO produced is twice the number of moles of N2:

Moles of NO = 2 * (-16.46 mol) ≈ -32.92 mol

The given reaction is N2(g) + O2(g) → 2NO(g), and the enthalpy change of the reaction is ΔH = 180.6 kJ. If the reaction absorbs 2976 kJ of heat, the number of moles of NO that can be produced can be calculated. By setting up a proportion, we find that approximately -16.46 moles of N2 are reacted. Since the reaction produces 2 moles of NO for every mole of N2, the calculated moles of NO would be approximately -32.92. However, negative moles are not physically possible, indicating that no NO can be produced in this case due to insufficient heat absorbed by the reaction.

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the universe formed through the big bang explosion, all of the elements on Earth have been cooked for billions of years in stars and then released in the universe through super- nova explosions.

The first one appear to be a pan with some liquid heating up.

The beginning state is liquid, the phase change type is a vaporization and its ending state is gas.

The second one seems to be a ice cube melting.

Its beginning phase is solid, the phase change type is fusion, and its ending state is liquid.

The third one is water, or other liquid, making clouds.

The beginning state is liquid, the phase change type is a vaporization and its ending state is gas.

The fourth illustration seems to be an aluminium can. There aren't really a phase change happening, but when we open the aluminium can containing gaseous drink, there are molecules of gas diluted into the liquid and some of it encouter each other to make a bubble of the gas and is released. It is not an actually phase change, it is the reverse process of diluting gas into liquid. Initially it is diluted gas, it gets released and in the end it is in gas phase.

Answer:

A lion preys on a herd of gazelle.

Explanation:

lions and gazelles are both biotic factors since they are living organisms.

A total of 1909 grams of sodium are in 5. 0 x 10²⁵ atoms of sodium

The moles of a substance are given as,

Moles = Mass/Molar mass

Molar mass of sodium is 23 g/mol. We also know that the moles are given as the number of entities divided by Avogadro number.

The atoms of sodium are 5.0 x 10²⁵. The Avogadro number is 6.02 × 10²³

Moles = Number of entity/Avogadro number

So, it should be right to write,

Mass/Molar mass = Number of entity/Avogadro number

Putting all the values,

5.0 x 10²⁵/6.02 x 10²³ = Mass/23

0.83 x 10² = Mass/23

Mass = 1909 grams.

So, 1909 grams of sodium will be contained in 5.0 x 10²⁵ atoms of sodium.

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The molecular equation for the reaction between BaBr2(aq) and H2SO4(aq) can be written as:

BaBr2(aq) + H2SO4(aq) → BaSO4(s) + 2HBr(aq)

What is Molecular Mass?

Molecular mass (also known as molecular weight) is the sum of the atomic masses of all the atoms in a molecule. It is usually expressed in atomic mass units (amu) or in grams per mole (g/mol). The molecular mass is used in stoichiometry calculations, which involve determining the amount of reactants and products in a chemical reaction.

In this equation, the barium cation (Ba2+) from barium bromide (BaBr2) combines with the sulfate anion (SO42-) from sulfuric acid (H2SO4) to form barium sulfate (BaSO4) as a precipitate. At the same time, the hydrogen cations (H+) from sulfuric acid combine with the bromide anions (Br-) from barium bromide to form hydrogen bromide (HBr) in aqueous solution.

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The little dots that move between fuel rods represent steam.

What are the fuel rods?

A long, thin zirconium metal tube that holds the pellets of fuel for nuclear reactors made of fissionable material.

The fuel rods are bundled together into fuel assemblies, which are then put one at a time into reactor core.

The fuel rod's main functions are to maintain the fuel in a precise geometry and to act as the first line of defense between the fission products and the outside world.

Therefore, maintaining its integrity is main objective of fuel design and operating procedures for reactors.

Small ceramic pellets of low-enriched uranium oxide are the fuel used today's commercial reactors.

These fuel rods are bundled into the tall fuel assemblies, which are then put inside reactor.

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A) The reaction of ΔGο at 648 K is apprοximately -73.6 kJ.

B) The spοntaneity οf the reactiοn changes at absοlute zerο (0 K).

C) The value οf ln(K) fοr the reactiοn at 589 K is apprοximately -0.0442.

D) ΔGο fοr the reactiοn at 357 K is apprοximately 106.5 kJ.

A chemical prοcess in which substances act mutually οn each οther and are changed intο different substances, οr οne substance changes intο οther substances.

Part A:

Tο calculate ΔGο at 648 K, we can use the equatiοn:

ΔGο = ΔHο - T * ΔSο

Given:

ΔHο = -141 kJ

ΔSο = -104 J/mοl K

T = 648 K

Cοnverting ΔSο tο kJ/mοl K:

ΔSο = -104 J/mοl K * (1 kJ/1000 J) = -0.104 kJ/mοl K

Substituting the values intο the equatiοn:

ΔGο = -141 kJ - 648 K * (-0.104 kJ/mοl K)

ΔGο = -141 kJ + 67.392 kJ

ΔGο = -73.608 kJ

Therefοre, ΔGο at 648 K is apprοximately -73.6 kJ.

Part B:

Tο determine the temperature at which the spοntaneity οf the reactiοn changes, we can use the equatiοn:

ΔGο = -RT * ln(K)

Given:

ΔHο = -158 kJ

ΔSο = -383 J/mοl K

T = 298 K

Cοnverting ΔSο tο kJ/mοl K:

ΔSο = -383 J/mοl K * (1 kJ/1000 J) = -0.383 kJ/mοl K

Substituting the values intο the equatiοn:

-158 kJ = -R * 298 K * ln(K)

Simplifying the equatiοn:

ln(K) = -158 kJ / (-R * 298 K)

ln(K) = 0.5299

Tο determine the temperature at which the spοntaneity changes, we need tο find the temperature at which ln(K) is zerο (K = 1):

0 = -R * T * ln(1)

0 = -R * T * 0

This means that the spοntaneity οf the reactiοn changes at absοlute zerο (0 K).

Part C:

Tο calculate the value οf ln(K) at 589 K, we can use the equatiοn:

ΔGο = -RT * ln(K)

Given:

ΔGο = 226.9 kJ

T = 589 K

Sοlving the equatiοn fοr ln(K):

ln(K) = ΔGο / (-RT)

ln(K) = 226.9 kJ / (-8.314 J/mοl K * 589 K)

ln(K) = -0.0442

Therefοre, the value οf ln(K) fοr the reactiοn at 589 K is apprοximately -0.0442.

Part D:

Tο calculate ΔGο in kJ fοr the reactiοn at 357 K, we can use the equatiοn:

ΔGο = -RT * ln(Kp)

Given:

Kp = 6.14 x 10^25

T = 357 K

Sοlving the equatiοn fοr ΔGο:

ΔGο = -8.314 J/mοl K * 357 K * ln(6.14 x 10^25)

ΔGο = 106.5 kJ

Therefοre, ΔGο fοr the reactiοn at 357 K is apprοximately 106.5 kJ.

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At equilibrium, the pressure in the container is 5.83 atm.

When dry ice (solid CO2) is placed in the container, it will start to sublimate and convert to gaseous CO2 until equilibrium is reached. At equilibrium, the rate of sublimation will be equal to the rate of deposition and the pressure inside the container will remain constant.

To calculate the pressure at equilibrium, we can use the ideal gas law which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant and T is the temperature in Kelvin.

We know that the initial mass of dry ice is 10.0 g, which is equivalent to 0.248 moles of CO2. Since the container is closed, the number of moles of CO2 at equilibrium will remain constant. Therefore, we can rearrange the ideal gas law to solve for the pressure:

P = nRT/V

Substituting the values, we get:

P = (0.248 mol) x (0.08206 L atm/mol K) x (298 K) / (12.0 L) = 5.83 atm

Therefore, the pressure in the container at equilibrium is 5.83 atm.

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Answer:

It solved the issue of depending on too many base units

Explanation:

It was first adopted by the French government. Metric system was developed by Gabriel Mouton of Lyons, he is called the founding father of the metric system. He proposed the decimal system of measurement that was refined by the scientists.

The metric system is simple for making measurements, you just need to know few metric units. There are seven base units in this system of measurement while there are twenty base units in inch-pound system of measurement. Metric system is easier to remember. The metric system follows the decimal number system and it decreases and increases in size by 10.

It has been adopted by all the countries of the world except Myanmar and US.  

False. C++ has a built-in data type called std::string, which is designed to store strings of data. It is a class defined within the standard C++ library, and it is a part of the C++ Standard Template Library (STL).

The Standard Template Library (STL) is a collection of data structures, algorithms, and other programming tools for use in software development. It is a library of generic programming components that can be used to implement various data structures and algorithms, such as vectors, lists, maps, and queues. The STL is written in the C++ programming language and is included in most C++ compilers. The STL consists of four components: containers, iterators, algorithms, and functions. Containers are used to store and manipulate data, iterators are used to traverse data, algorithms are used for common operations such as searching and sorting, and functions provide additional functionality. The STL is designed to be efficient, flexible, and extensible. It is also designed to be portable, meaning that the same code can be used on different types of computers. By using the STL, developers can save time and effort in creating their own custom data structures and algorithms.

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Answer:

the taste and how clean the product gets your teeth, would most likely be the most important factors in making a tooth paste.

The piece of styrofoam will float and the piece of oak and gold ring will sink. This is because the density of an object determines whether it will float or sink in a fluid. Density is the amount of mass an object has in relation to its volume. Objects that are less dense than the fluid they are in will float, while objects that are more dense will sink.

In this scenario, styrofoam is less dense than water, so it will float. Oak and gold are more dense than water, so they will sink. The gold ring, in particular, has a high density due to its composition of a heavy metal. Even though it is small in size, its density is greater than that of water, causing it to sink. Density is an important concept in understanding buoyancy and how objects behave in fluids.

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Answer:

30 grams

Explanation:

I got 40 wrong so I picked 30

Answer:

30 grams

Explanation:

I did the ck12

Answer:

The hydrophobic core of the globin fold favors heme binding, but it is the proximal F8 (helix F, position 8) histidine that actually binds the heme cofactor to the protein by coordinating to the heme iron's fifth coordinate. Gaseous ligands bind to the iron's sixth coordinate at the opposite side of the heme plane.

Incorrect question .

Corrected question- Write the chemical symbol for three different atomic cations that all have 12 electrons.

The number of protons inside the nucleus always remains constant.

∴Chemical symbol of three different atomic cation that have 12 electrons:

Atomic cation is the ion with positive electric charge on it, it means it should have more protons than electrons.

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Al⁺, Si²⁺ ,P³⁺ are the atomic cations with 12 electrons.

∵The nucleus always contains the same number of protons.

∴Three distinct atomic cations with 12 electrons each have the following chemical symbol:

1. Al⁺

2. Si²⁺

3. P³⁺

An ion or atomic cation with a positive electric charge is thought to have more protons than electrons.

• Aluminum (Al) contains 13 electrons, hence Al+ will have = 13 - 1→ 12 electrons (1 electron will be lost for every additional charge).

• Si2+ will have = 14 - 2→ 12 electrons since silicon (Si) has 14 electrons. (+2 charge signifies electron loss of 2);

• Because phosphorus (P) has 15 electrons, P3+ will have 12 electrons because 15-3. (+3 charge indicates that 3 electrons will be lost.)

Hence, Aluminium, Silicon and phosphorus cations have 12 electrons.

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Your question is incorrect. The correct question is -Write the chemical symbols for three different atomic cations that all have 12 electrons.

Single Replacement

Given

Reaction

Mg(s) + 2 HCl(aq) → MgCl2 (aq) + H2 (g)

Required

Type of reaction

Solution

A single replacement reaction is a chemical reaction in which one element replaces the other elements of a compound to produce new elements and compounds

General formula :

A + BC ⇒ AC + B

Not all of these reactions can occur. We can use the activity series(the Volta series)

The more left the position of a metal in the series, the more reactive metal (easy to release electrons, the stronger the reductor)

The water retained by some salts when isolated by evaporation is called water of hydration. Salts that contain water of hydration are called hydrates.

Water of hydration is also called water of crystallization. It is the water that remains inside the framework of the salt or crystal after evaporation and can only be removed by heating, but by doing this, one risks losing the structure of the crystal.

An example of a hydrate is copper tetraoxosulphate (VI). When hydrated, it becomes copper tetraoxosulphate (VI) pentahydrate. When it is without its water of hydration, it has a white colour but when it is hydrated, it is blue in colour.

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In the second experiment, it would take 60 minutes to produce the same amount of product (25 mmol).

We can start by using the Michaelis-Menten equation to determine the initial reaction rate in the first experiment, where the substrate concentration is initially a thousand times greater than the KM:

v₀ = Vmax × [S]/(KM + [S])

Since the substrate concentration is initially a thousand times greater than the KM, we can assume that [S] >> KM, and simplify the equation to:

v₀ = Vmax × [S] / KM

The amount of substrate converted to product after 15 minutes is 1% of the initial substrate concentration, so the remaining substrate concentration is 99% of the initial concentration. Let's define [S]0 as the initial substrate concentration, then:

[S] = 0.99 [S]₀

The amount of product formed in 15 minutes is 25 mmol, so we can calculate the initial reaction rate as:

v₀ = (25 mmol / 15 min) / (0.01 mol / mol) = 1666.7 nmol/min

where we have converted the units to nmol/min and used the molecular weight of the product to convert from moles to millimoles.

Now, let's consider the second experiment, where one-fourth as much enzyme and twice as much substrate are used.

Since the amount of product formed is the same in both experiments, we can write:

v₁ × t₁ = v₂ × t₂

where v₁ and t₁ are the initial reaction rate and reaction time in the first experiment, and v₂ and t₂ are the corresponding values in the second experiment.

Let's use the Michaelis-Menten equation to relate the initial reaction rate to the enzyme and substrate concentrations:

v₁ = Vmax × [S]₁ / (KM + [S]₁) × E₁

v₂ = Vmax × [S]₂ / (KM + [S]₂) × E₂

We can rearrange these equations to solve for [S]1 and [S]2 in terms of v1, v₂, E₁, E₂, and KM:

[S]₁ = (v₁ × KM) / (Vmax × E₁) - [S]₂

[S]₂ = (v₂ × KM) / (Vmax × E₂) - [S]₁

Substituting these expressions into the equation for the reaction time, we get:

t₂ = (v₁ × t₁ × Vmax × E₂) / (v₂ × Vmax × E₁ + v₁ × E₂ × KM / (Vmax × E₁) - v₁ × KM / (Vmax × E₁))

Substituting the values from the first experiment, we get:

t₂ = (1666.7 nmol/min × 15 min × 1/4 × 2) / (1666.7 nmol/min × 1/2 × 1/1000 mol/L + 1666.7 nmol/min × 2 × 0.01 mol/L / (1/1000 mol/L) - 1666.7 nmol/min × 0.01 mol/L / (1/1000 mol/L))

Simplifying, we get:

t₂ = 60 min

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Answer:

semiconducting,tellurium

Explanation:

just completed the assignment

semiconducting, tellurium

The equilibria studied in the lab procedure include (CoC14)^2- and  Fe^3+

A chemical reaction between the reactants that maintains a stable state both before and after the reaction is complete is called an equilibrium reaction.

Chemical equilibrium refers to the situation in a chemical reaction where both the reactants and products are present in concentrations that have no further tendency to change over time, preventing any discernible change in the system's properties.

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Answer:

273.15

Explanation:

Alkenes are a group of unsaturated hydrocarbons (i.e., molecules with solely carbon and hydrogen) that include at least one double bond from carbon to carbon. Olefins is a different name for alkenes. Due to the double bond, alkenes are more reactive than alkanes.

What is Hydrocarbon?

A hydrocarbon is an organic compound made entirely of the two atom kinds of carbon and hydrogen. Hydrocarbons are typically colourless gases with barely perceptible odours. The four subcategories that are generally used to classify hydrocarbons are alkanes, alkenes, alkynes, and aromatic hydrocarbons. These chemicals' structures could be quite simple or extremely intricate. The study of hydrocarbons can provide insight into the chemistry and behavior of other functional groups. For commercial purposes, liquefied petroleum gas, which is produced from hydrocarbons like propane and butane, is also used as a fuel source (LPG). Benzene, one of the most fundamental aromatic hydrocarbons, serves as the building block for many synthetic drugs.

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Complete question

Name The Alkenes Below. Name The Alkenes Below. A) Ball& Sticklabels B) Ball & Stick ▼

2.5 X 10²⁴ atoms of copper is equivalent to 266.7g of Cu.

HOW TO CALCULATE MASS:

Therefore, 2.5 X 10²⁴ atoms of copper is equivalent to 266.7g of Cu.

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If 14g of calcium oxide (CaO) is produced,25 gram of calcium carbonate must there have been to begin with.

The term molar mass is defined as the mass in grams of one mole of the compound. In a substance, the amount of entities present e.g., atoms, molecules, ions, is defined as a mole.

A mole of any substance is 6.022×10²³ molecules.

Given:

Mass of CaCO₃ decomposed = ?

Mass of CaO produced = 14 g

The chemical equation is as follows:

CaCO₃        →       CaO + CO₂

Number of moles of CaO

Number of moles = mass/molar mass

Number of moles = 14 g/ 56 g/mol

=0.25 mol

Then,we will compare the moles of CaO with CaCO₃.

                     CaO            :          CaCO₃

                        1               :               1

                     0.25           :            0.25

Mass = number of moles × molar mass

Mass = 0.25 mol × 100 g/mol

Mass = 25 g

Thus, 25 gram of calcium carbonate must there have been to begin with.

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The elasticity coefficient for an enzyme in the multistep pathway will depends on the concentration of the enzyme itself and the amounts of the substrate molecules present at each step. Option D is correct.

The elasticity coefficient is a measure of the sensitivity of the rate of the overall reaction to changes in the concentrations of the individual enzymes or substrates in the pathway. A higher elasticity coefficient indicates that the reaction rate is more sensitive to changes in that particular component.

In a multistep pathway, the elasticity coefficient of each enzyme depends on its own concentration as well as the concentrations of the substrates and products that it interacts with in its particular step of the pathway.

Therefore, both the concentration of the enzyme and the amounts of substrate molecules present at each step can affect the elasticity coefficient of an enzyme in a multistep pathway. The levels of regulatory molecules (option B) may also affect the elasticity coefficient of an enzyme, but this is not the only factor that determines it.

Hence, D. is the correct option.

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t = 57 min., Therefore, we can say that it takes 57 minutes for cyclopropane's partial pressure to drop from 1 atm to 0.125 atm at 500°C.

Propene (CH3CH=CH2) is produced by the isomerization of cyclopropane, which is a first-order process. A sample of cyclopropane converts to propene in 79 minutes at 760 K.

The reaction is a first-order reaction because it is an isomerization reaction, and its rate constant is expressed in terms of minutes. The sum of the powers or exponents that the concentration terms are raised in the rate law expression can be used to define the order of a reaction.

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