An inductor with L = 9.5 H is in a closed circuit with I = 0.45 A (see the diagram). When the switch is opened, the current goes to zero in Δt = 0.12 s. Randomized Variables L = 9.5 H I = 0.45 A Δt = 0.12 s

Part (a) Express the magnitude of the average induced emf on the inductor, εave, in terms of L, I and Δt.

εave =?

Part (b) Calculate the numerical value of εave in volts.

εave =?

The statements true in regards to heat is 3. Heat is a form of energy, can be reflected by a mirror, and cannot pass through a vacuum.

Heat is a form of energy. Heat is the transfer of thermal energy from one object to another. Thermal energy is the energy of motion of the particles in an object. Heat can be reflected by a mirror. Heat is a form of electromagnetic radiation, and electromagnetic radiation can be reflected by mirrors.

Heat cannot pass through a vacuum. Heat is a form of electromagnetic radiation, and electromagnetic radiation cannot pass through a vacuum. Heat is not an electromagnetic radiation. It is a form of energy that is transferred from one object to another because of a difference in temperature.

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Complete question:

Which of the following statements are true regarding heat?

(a) Heat is a form of energy

(b) Heat can be reflected by mirror

(c) Heat is an electromagnetic radiation

(d) Heat can pass through vacuum

Select the correct answer from the codes given below :

1. 1, 2 and 3

2. 2, 3 and 4

3. 1, 2 and 4

4. 1, 3 and 4

Answer:

V = 192 kV

Explanation:

Given that,

Charge, \(q=6.4\times 10^{-6}\ C\)

Distance, r = 0.3 m

We need to find the electric potential at a distance of 0.3 m from a point charge. The formula for electric potential is given by :

\(V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6.4\times 10^{-6}}{0.3}\\\\V=192000\ V\\\\V=192\ kV\)

So, the required electric potential is 192 kV.

Answer:

look down

Explanation:

One piece of evidence that supports the Big Bang theory is the observation of cosmic microwave background radiation. This radiation is a faint glow that fills the universe and is thought to be remnants from the early stages of the universe. Another piece of evidence is the redshift of galaxies, which suggests that the universe is expanding. The abundance of light elements like hydrogen and helium is also consistent with the predictions of the Big Bang theory.

1. Cosmic microwave background radiation:

Scientists have discovered a faint glow of radiation called cosmic microwave background radiation. This radiation is evenly distributed throughout the universe and is thought to be remnants from the early stages of the universe. It is considered a crucial piece of evidence for the Big Bang theory because it is consistent with the idea that the universe was once in a hot and dense state.

2. Redshift of galaxies:

Another piece of evidence is the observation of the redshift of galaxies. When astronomers analyze the light emitted by distant galaxies, they notice a shift towards longer wavelengths, indicating that the light is being stretched. This phenomenon is known as redshift and suggests that the universe is expanding. The further away a galaxy is, the greater the redshift, which supports the idea that the universe is continuously expanding, as predicted by the Big Bang theory.

3. Abundance of light elements:

The abundance of light elements, such as hydrogen and helium, also supports the Big Bang theory. According to the theory, during the early stages of the universe, there was a rapid expansion and cooling. This allowed for the formation of light elements. The observed abundance of these elements in the universe matches the predictions made by the Big Bang theory, providing further evidence for its validity.

In conclusion, the observation of cosmic microwave background radiation, the redshift of galaxies, and the abundance of light elements are all pieces of evidence that support the Big Bang theory. These observations provide important insights into the early stages and expansion of the universe.

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Answer:

t = 2 seconds

Explanation:

In 2nd question, the question is given the attached figure.

Initial speed of the bus, u = 0

Acceleration of the bus, a = 8 m/s²

Final speed, v = 16 m/s

We need to find the time taken by the car to reach the stop. Acceleration of an object is given by :

\(a=\dfrac{v-u}{t}\)

t is time taken

\(t=\dfrac{v-u}{a}\\\\t=\dfrac{16-0}{8}\\\\t=2\ s\)

The bus will take 2 seconds to reach the stop.

The rock weighs approximately 59.69 N on Planet X.

We can use the kinematic equation for the vertical motion of the rock to find the gravitational acceleration on Planet X, which will allow us to calculate the weight of the rock:

y = yo + vot + 1/2at^2

where

Rearranging the equation:

a = 2(y - yo - vot) / t^2

Substituting the values:

a = 2(0 - 0 - 12.7 m/s × 1.80 s) / (1.80 s)^2

a = -12.7 m/s^2

The negative sign indicates that the acceleration due to gravity on Planet X is in the opposite direction of the initial velocity of the rock.

To find the weight of the rock on Planet X, we can use the formula:

w = mg

where

Substituting the values:

w = 4.70 kg × (-12.7 m/s^2)

w = -59.69 N

The negative sign indicates that the weight is in the opposite direction of the initial velocity of the rock, which is consistent with the direction of the acceleration due to gravity. Therefore, the rock weighs approximately 59.69 N on Planet X.

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The speed of wave with a wavelength of 4 m and a frequency of 85 Hz is 340m/s

The speed of a wave is the product of the frequency of the wave and its wavelength. Mathematically, it is expressed as:

\(v = f \lambda\) where:

f is the frequency

\(\lambda\) is the wavelength

Given the following:

f =85Hz

\(\lambda\) = 4 m

Substitute the given parameter into the formula:

v = 85 × 4

v = 340m/s

Hence the speed of wave with a wavelength of 4 m and a frequency of 85 Hz is 340m/s

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The amplitude of a wave is proportional to the amount of energy it carries. When the amplitude of a wave is increased, the energy carried by the wave also increases. This can result in several potential outcomes, depending on the specific wave system being considered.

In mechanical wave systems, such as a vibrating string or a loudspeaker, using very large amplitude can cause the system to become nonlinear, meaning that the wave behavior deviates from the expected linear relationship between the wave amplitude and energy. Nonlinearities can cause the wave to generate harmonics, which are higher frequency components in the wave spectrum. They can also cause the wave to become distorted, producing a sound that is different from the original waveform. In extreme cases, the system can become mechanically unstable and break or stop functioning altogether.

In electromagnetic wave systems, such as radio waves or light waves, very large amplitudes can cause similar nonlinear distortions. They can also cause unwanted interference with other signals in the system, as well as increase the risk of damage to the transmitting or receiving equipment.

It is important to use appropriate amplitudes for the specific wave system being considered, as excessive amplitudes can result in unwanted side effects and potentially cause damage to the system.

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The height of the pendulum bob above the lowest point (0), where its velocity is zero, is approximately 2.046 meters

To calculate the height of the pendulum bob above the lowest point (0) where its velocity is 0, we can use the principle of conservation of mechanical energy.

Given:Maximum speed of the pendulum bob = 4.5 m/s

The lowest point (0) represents the reference point for height measurements.

At the lowest point (0), the pendulum bob has maximum kinetic energy and zero potential energy. As the pendulum bob swings upwards, it loses kinetic energy and gains potential energy. At the highest point, its potential energy is maximum, and its kinetic energy is zero.The total mechanical energy (E) of the pendulum bob remains constant throughout its motion:E = Kinetic energy + Potential energy. At the lowest point (0), the entire energy is in the form of kinetic energy, given by: E_lowest = Kinetic energy_lowest .E_lowest = (1/2)mv^2, where m is the mass of the bob and v is the velocity at the lowest point.At the highest point where the velocity is zero, the entire energy is in the form of potential energy: E_highest = Potential energy_highest

E_highest = mgh, where m is the mass of the bob, g is the acceleration due to gravity, and h is the height above the reference point (0). Since the mechanical energy is conserved, we can equate the energies at the lowest and highest points: (1/2)mv^2 = mgh

Simplifying and solving for h:

h = (v^2) / (2g)

Substituting the given values:

v = 4.5 m/s (maximum speed)

g = 9.8 m/s^2 (acceleration due to gravity)

h = (4.5 m/s)^2 / (2 × 9.8 m/s^2)

h = 2.046 m.

Therefore, the height of the pendulum bob above the lowest point (0), where its velocity is zero, is approximately 2.046 meters.

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Yes, an object can have zero displacement even if it has moved through a distance.

Displacement is a vector quantity that represents the change in position from the initial point to the final point.Yes, an object can have zero displacement even if it has moved through a distance. It takes into account the direction of motion as well as the magnitude.To illustrate this, consider a scenario where an object moves in a circular path and returns to its initial position. In this case, the object has covered a certain distance along the circumference of the circle. However, since it ends up at the same position it started, the displacement is zero because there is no change in its position relative to the initial point.

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In conclusion, the acceleration of the hollow spherical shell as it rolls down the slope is equal to the net force acting on it divided by its mass. The exact value of the acceleration depends on the radius of the shell, which is not provided in the problem.

To solve this problem, we can apply the principles of rotational motion and the concept of torque.

Given:

Mass of the hollow spherical shell (m) = 1.50 kg

Angle of the slope (θ) = 31.0°

We need to determine the acceleration of the shell as it rolls down the slope.

First, let's calculate the gravitational force acting on the shell. The gravitational force can be determined using the formula:

F_gravity = m * g

where g is the acceleration due to gravity, which is approximately 9.8 m/s^2.

F_gravity = 1.50 kg * \(9.8 m/s^2\) = 14.7 N

Next, let's analyze the forces acting on the shell as it rolls down the slope. There are two main forces involved: the gravitational force (F_gravity) acting vertically downward and the normal force (N) acting perpendicular to the surface of the slope.

The component of the gravitational force parallel to the slope can be calculated as:

F_parallel = F_gravity * sin(θ)

F_parallel = 14.7 N * sin(31.0°) = 7.73 N

Since the shell rolls without slipping, the friction force (f) can be calculated as:

f = μ * N

where μ is the coefficient of static friction. However, since the shell is rolling without slipping, the friction force is zero, as there is no relative motion between the surface and the shell.

Since there is no friction force, the net force acting on the shell is the parallel component of the gravitational force:

Net force (F_net) = F_parallel = 7.73 N

Finally, we can use Newton's second law for rotational motion to determine the angular acceleration (α) of the shell:

F_net = I * α

where I is the moment of inertia of the hollow spherical shell.

The moment of inertia of a hollow spherical shell can be calculated as:

I = (2/3) * m * R^2

where R is the radius of the shell.

Since the radius is not given in the problem, we cannot calculate the exact value of the angular acceleration. However, we can analyze the rotational motion of the shell.

As the shell rolls down the slope, it experiences a torque due to the net force acting on it. The torque can be calculated as:

τ = F_net * R

where R is the radius of the shell.

Since the shell rolls without slipping, the linear acceleration (a) can be related to the angular acceleration (α) as:

a = R * α

Combining these equations, we have:

τ = m * a * R

F_net * R = m * a * R

F_net = m * a

Therefore, the net force is equal to the mass of the shell times its linear acceleration.

In conclusion, the acceleration of the hollow spherical shell as it rolls down the slope is equal to the net force acting on it divided by its mass. The exact value of the acceleration depends on the radius of the shell, which is not provided in the problem.

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Answer:

Derivation of Conservation of Momentum

Applying Newton's third law, these two impulsive forces are equal and opposite i.e. is equal to the change in momentum of the first object. is equal to the change in momentum of the second object. This relation suggests that momentum is conserved during the collision.

Explanation:

Hope it helps!!!

The kind of plate boundary found where the Caribbean and North American meet is a transform plate boundary.

This is due to the way that the North American and Caribbean tectonic plates move in relation to one another. The North American Plate moves in a westerly direction, while the Caribbean Plate moves in an easterly direction. The boundary where they meet is characterized by a significant amount of seismic activity, as the two plates move and grind against each other. This movement results in the formation of a fault line, known as the North American-Caribbean Plate Boundary, which extends from the eastern edge of the Caribbean Plate to the northern coast of South America.

Transform plate boundaries occur where two tectonic plates slide past one another in opposite directions. This is in contrast to convergent boundaries, where two plates move towards one another, or divergent boundaries, where two plates move away from each other. At transform boundaries, the movement of the plates is characterized by a significant amount of friction, as the two plates rub against each other. This can cause earthquakes and other geological activity in the region.

The North American-Caribbean Plate Boundary is a particularly important transform boundary, due to its location in the Caribbean Sea. The boundary extends for around 5000 kilometers, from the eastern edge of the Caribbean Plate to the northern coast of South America. It is one of the most seismically active regions in the world, due to the constant movement of the two tectonic plates. The Caribbean Plate is moving eastward at a rate of around 2 cm per year, while the North American Plate is moving westward at around the same rate.

In conclusion, the kind of plate boundary found where the Caribbean and North American meet is a transform plate boundary. This boundary is characterized by the movement of two tectonic plates in opposite directions, resulting in a significant amount of seismic activity in the region. The North American-Caribbean Plate Boundary is one of the most seismically active regions in the world, due to the constant movement of the two plates.

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After stating a hypothesis, next step that a physicist is most likely

to take is A. Planning and performing an experiment to answer the question

It is a tentative statement about the possible outcome of a scientific research study on a particular topic.

There are two parts of a physics problem , one is theoretical and the other is practical proof of that theory . So, after hypothesis scientists conduct an experiment to test its validity

hence correct answer is A. Planning and performing an experiment to answer the question

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Answer:

The way the body resist it's state in motion is called inertia. Its directly proportional to it's mass.

Explanation: This is what we call Newton's First Law and "State Of Motion".

Answer:

it reduces friction

Explanation:

if you put oil or any liquid between the tool it will shift and change the shape as much as it needs to. It will smooth the bumps between the tools gears as they squeeze together making the friction reduce. It will slide and that reduces the friction.

i hope this helps im lowkey just guessing tho so sorry if it doesnt. lmk tho

You must give the box the minimum speed of 4.56 m/s  at the bottom of the incline so that it will reach the skier.

Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another.

From the  work-energy theorem, it can be written that

μ × mg × sinθ × h/sinθ + mgh = 1/2 mv²

v²/2 = gh (1 + μ)

v = √{2gh (1 + μ)}

= √{ 2 × 9.81 × ( 1 + 0.06)}

= 4.56 m/s

Hence, you must give the box the minimum speed of 4.56 m/s .

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Given data:

* The initial velocity of the rabbit is u = 0 m/s.

* The acceleration of the rabbit is,

* The time taken is t = 3 s.

Solution:

By the kinematics equation, the final velocity of the rabbit is,

Substituting the known values,

Thus, the velocity of the rabbit is 22.5 m/s.

The golf ball spends approximately 1.46 seconds in the air before hitting the water. Just before striking the water, its speed is approximately 18.84 m/s.

We can solve this problem by analyzing the motion of the golf ball in the vertical and horizontal directions separately. In the vertical direction, the ball falls a distance of 12.3 m due to gravity. We can use the equation of motion for vertical motion, which is given by:

\(h = (1/2)gt^2\)

where h is the vertical distance, g is the acceleration due to gravity (approximately 9.8 \(m/s^2\)), and t is the time. Rearranging the equation, we can solve for t:

\(t = \sqrt(2h / g) = \sqrt(2 * 12.3 / 9.8)\) ≈ 1.46 s

Therefore, the ball spends approximately 1.46 seconds in the air.

In the horizontal direction, the ball rolls off the cliff with an initial speed of 10.2 m/s. Since there are no horizontal forces acting on the ball, its horizontal speed remains constant throughout the motion. Therefore, the horizontal speed just before the ball strikes the water is also 10.2 m/s.

Combining the vertical and horizontal components of motion, we can find the resultant velocity just before the ball hits the water using the Pythagorean theorem:

\(v = \sqrt(v_{horizontal}^2 + v_{vertical}^2) = \sqrt(10.2^2 + 0)\) ≈ 10.2 m/s

Therefore, the speed of the ball just before it strikes the water is approximately 18.84 m/s.

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So that neither the patient nor the researchers can subconsciously alter the results.

The ratio of their speeds is 2:1 .

As we know that from question, Alphonse and Beryl always pass each other at the same three places on the track and since they each run at a constant speed, then the three places where they pass must be equally spaced on the track. It means that the three places divide the track into three equal parts. Since, it is not told which runner is faster, so it can be assumed that Beryl is the faster runner.

Now, Start at one place where Alphonse and Beryl meet. that we know the relative positions of where they meet, but we do not actually have to know where they started at the very beginning.

Now, To get to their next meeting place, Beryl runs farther than Alphonse ,since she runs faster than he does,

So Beryl must run 2/3 of the track while Alphonse runs 1/3 of the track in the opposite direction, since the meeting places are spaced equally at 1/3 intervals of the track. Since Beryl runs twice as far in the same length of time, then the ratio of their speeds is 2:1.

Hence the ratio of their speeds is 2:1 .

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The cart's increased speed is the same as when it first took off.

Rate is the speed from which an object travels along a path over time, whereas velocity is the speed and orientation of an item's motion.

At first, the cart is at rest.

So, u = 0 m/s.

A brief period of time is spent with a constant force applied.

The final speed that the force gives the cart is what we'll call v.

Newton's first equation of motion yields the following results:

v = u + at

Where;

The ultimate speed =v.

The starting speed =u.

Acceleration = a.

Time = t

u = 0 m/s, therefore we now have;

v = 0 + at

v = at

Let's now use Newton's second rule of motion to construct a formula to introduce force;

F = ma

Where;

Force = f.

Mass = m.

Acceleration = a.

So,

= a = F/m.

Substituting in v = at,

= v = (F/m)t

The final speed, v, is evidently exactly related to the force. So, if the force is constant, the end speed will also stay constant.

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The complete question is -

A constant force is exerted for a short time interval on a cart that is initially at rest on an air track. This force gives the cart a certain final speed. Suppose we repeat the experiment but, instead of starting from rest, the cart is already moving with constant speed in the direction of the force at the moment we begin to apply the force.

After we exert the same constant force for the same short time interval, the increase in the cart's speed:

A. is equal to two times its initial speed.

B. is equal to the square of its initial speed.

C. is equal to four times its initial speed.

D. is the same as when it started from rest.

E. cannot be determined from the information provided.

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

We have

\(a = \frac{20}{4} = 5 \\ \)

We have the final answer as

Hope this helps you

The heat equation is Q = mcT

Q is the total amount of heat transferred to or from something.

ANSWER

2304 mg

EXPLANATION

The rate is given in mg per minute. To find how much the brain's mass increases in one day we have to find how many minutes are in a day.

Assuming that a day has 24 hours and 1 hour has 60 minutes:

One day has 1440 minutes. Then, in one day the brain's mass increases:

The newborn baby's brain's mass increases 2304 mg in one day.

Answer:

I think he answer is C but I could be wrong

Explanation:

brainliest plz

Answer:

d mark brainlyest

Explanation:

Answer:

11760 J

Explanation:

cuz potential engery is PE = MHG

SO 80×15×9.8= 11760 J

Answer:

11769j

Explanation:

here,

mass(m)=80 kg

height(h)=15m

acceleration due to gravity(g)=9.8m/s^2

now,

potential energy = m×g×h

= 80×9.8×15

= 11760j

Explanation:

F x d = work

490 N * 50 m = 24 500 J  of work

Answer is A 2.8 x 10^-8 N, to the right

The net gravitational force on mass A due to masses B and C is required.

The correct option is a. \(2.8\times 10^{-8}\ \text{N}\) to the right.

G = Gravitational constant = \(6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2\)

\(r_{AB}\) = Distance between A and B = 0.4+0.1 = 0.5 m

\(r_{AC}\) = Distance between A and C = 0.1 m

\(m_A=m_B=m_c\) = Mass of each particle = 2 kg

The required force is

\(F_A=F_{AB}+F_{AC}\\ =\dfrac{Gm_Am_B}{r_{AB}^2}+\dfrac{Gm_Am_C}{r_{AC}^2}\\ =Gm^2\left(\dfrac{1}{r_{AB}^2}+\dfrac{1}{r_{AC}^2}\right)\\ =6.674\times 10^{-11}\times 2^2\left(\dfrac{1}{0.5^2}+\dfrac{1}{0.1^2}\right)\\ =2.8\times 10^{-8}\ \text{N}\)

The magnitude of force will be \(2.8\times 10^{-8}\ \text{N}\)

The direction will be towards the right since C is closer to A.

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