An inexpensive and accurate method of measuring the quantity of electricity flowing through a circuit is to pass the current through a solution of a metal ion and weigh the metal deposited. A silver electrode immersed in an Ag⁺ solution weighs 1.7854 g before the current has passed and weighs 1.8016 g after the current has passed. How many coulombs have passed?

Answer:69

Explanation:cause ima boss

The hydrogen molecule is being oxidized in the fuel cell.

In a fuel cell, the hydrogen molecule (H₂) acts as the fuel. During the operation of a fuel cell, a redox (reduction-oxidation) reaction takes place. In this reaction, hydrogen is oxidized, which means it loses electrons. The oxidation of hydrogen occurs at the anode of the fuel cell.

In a fuel cell, hydrogen gas is supplied to the anode, where it is split into protons (H⁺) and electrons (e⁻) through a process called electrolysis. The electrons are then forced to travel through an external circuit, creating an electric current that can be used to power devices. Meanwhile, the protons move through a proton exchange membrane (PEM) to the cathode.

At the cathode, an oxidizing agent (typically oxygen from the air) combines with the electrons and protons to form water (H₂O). This reduction process at the cathode involves the gain of electrons by the oxidizing agent, which in this case is oxygen. Therefore, the reduction of oxygen is occurring at the cathode.

The hydrogen molecule is being oxidized in the fuel cell, meaning it is losing electrons. This oxidation process provides the electrons necessary for the reduction of the oxidizing agent, which is typically oxygen.

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-2832.79 kJ heat is produced by combustion of 125 g of methanol under standard state condition.

The typical enthalpy of methanol combustion,

It implies that:

When methanol is burned, it produces 726.1 kJ of energy.

Methanol's molar mass is 32.04 g/mol.

So,

When methanol is burned, 32.04 g of it produces 726.1 kJ of energy.

When methanol is burned, it produces 726.1/32.04 kJ of energy.

125 g of methanol is released during burning (726.1/32.04)

energy of 125 kJ

kilojoules (kJ) released: 2832.79

The basic aliphatic alcohol and an organic compound, methanol has the chemical formula CH3OH. It has a pronounced alcoholic odor resembling that of ethanol and is a colorless, colorless, light, volatile liquid that is combustible.

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The increase in the diversity of species in an ecosystem  definitely lead to an increase in the productivity from that ecosystem. Hence, the statement is true.

An ecosystem is the regions in earth where  a group of living things and their essential non living things reside. There are various kind of ecosystems such as aquatic systems, forests, deserts etc.

The biodiversity refers to the diverse species of plants , animals and all other kind of livings there. By raising the possibility that species would use complementary resources and by increasing the likelihood that a highly productive or efficient species is present in the population, increasing species diversity can impact ecosystem functions, such as production.

For instance, greater use of soil resources can boost ecosystem production when there is a large diversity of plants. Similarly, when diverse plants populate more dependent animal variants survives more.

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Answer:

A. True

Explanation:

Got it right on Edge 2023.

The formate ion, HCO2, is an anion composed of a hydrogen atom, a carbon atom, and two oxygen atoms.

Resonance structures are alternative ways of representing the same molecule with different arrangements of single and double bonds. In the case of the formate ion, there are three possible resonance structures.

The first structure is the most common one and it is represented as HCO2−, with a single bond between the hydrogen and carbon, and two double bonds between the carbon and the oxygen atoms.

The second structure is represented as HCO-O−, with a single bond between the hydrogen and oxygen, and two double bonds between the carbon and the oxygen atoms.

The third structure is represented as HC=O−, with a double bond between the hydrogen and carbon, and a single bond between the carbon and the oxygen atom. All three of these resonance structures exist for the formate ion and represent the same molecule.

The three resonance structures for the formate ion help to explain its unique properties. For example, the extra electron density provided by the double bonds gives the molecule a negative charge, which is why it is a strong acid. Additionally, the different bonding arrangements in the resonance structures help to explain why the formate ion is relatively stable and unreactive.

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Explanation:

KE = ½ mv²

= ½ x 5 x 2² joule

= 10 joule

Answer:

I think it's positive charge

But why is love so important? Scientific studies have shown that being in love causes our body to release feel-good hormones and neuro-chemicals that trigger specific, positive reactions. We love our children, relatives and friends, and want to be with them, and that makes our lives more meaningful.

\(CS_2\)  is the limiting reactant in the reaction.

The balanced chemical equation for the reaction is:

3 \(CS_2\) + 6 \(NaOH\) → 2 \(Na_2CS_3\) + \(Na_2CS_3\) + 3 \(H_2O\)

To determine the limiting reactant, we need to calculate the amount of product that each reactant can produce and compare it to the actual amount of product that is formed.

First, we need to convert the mass of \(CS_2\) to moles:

118.3 g \(CS_2\) × (1 mol \(CS_2\) /76.14 g \(CS_2\)) = 1.555 mol \(CS_2\)

Next, we need to calculate the amount of product that can be formed from 1.555 mol of \(CS_2\). According to the balanced equation, 3 mol of \(CS_2\) will produce 2 mol of \(Na_2CS_3\). Therefore, 1.555 mol of \(CS_2\) will produce:

(2/3) × 1.555 mol = 1.037 mol \(Na_2CS_3\)

Now, let's calculate the amount of product that can be formed from 3.12 mol of \(NaOH\). According to the balanced equation, 6 mol of \(NaOH\) will produce 2 mol of \(Na_2CS_3\). Therefore, 3.12 mol of \(NaOH\) will produce:

(2/6) × 3.12 mol = 1.04 mol \(Na_2CS_3\)

Comparing the amount of product that can be formed from each reactant, we see that 1.037 mol of \(Na_2CS_3\) can be produced from the 1.555 mol of \(CS_2\), while 1.04 mol of \(Na_2CS_3\) can be produced from the 3.12 mol of \(NaOH\). Therefore, the limiting reactant in the reaction is \(CS_2\).

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Identify the unidentified substance using densities of a known substances. Unknown material density Using mass and volume data, identify an unidentified substance and calculate it density: P = 8.6 g/cm3.

Since water served as the foundation for creating the metric system of measurement, density is defined as mass divided in volume (=m/v), meaning that one cubic centimetre (1cm3) if water weighs one gramme (1g). As a result, the density of water is simple to remember: 1g/1cm3 = 1 g/cm3.

Pour water into the a graduated cylinder, measure the volume, submerge the object, and measure the volume again. Its volume of a object is the distinction between both volume measurements. To determine the object's density, just divide its mass by the volume.

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40.22 kJ of heat are required to convert 18 grammes of water at 20°C into water vapour at the boiling point.

The boiling point of a substance is the temperature at which a liquid's vapour pressure matches the pressure around it and the liquid condenses into a vapour.  Different liquids will boil at various temperatures and pressures. The heat required to change a substance from a liquid to a gas is called the enthalpy of vaporization, or ∆Hvap. The amount of heat required to vaporize a given amount of a substance can be calculated using the equation:

q = m x ∆Hvap

here q is heat required, m is mass of the substance, and ∆Hvap is enthalpy of vaporization.

For water, the enthalpy of vaporization at its boiling point (100°C) is 40.7 kJ/mol. To convert this to kJ/g, we can divide by the molar mass of water, which is 18.015 g/mol:

= ∆Hvap

= 40.7 kJ/mol / 18.015 g/mol

= 2.268 kJ/g

So, to vaporize 18 g of water at 20°C, we need:

= q

= 18 g x 2.268 kJ/g

= 40.22 kJ

This is the amount of heat that must be added to the water to change it from a liquid at 20°C to a gas at the boiling point (100°C).

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0.494 m is the height of the liquid in the tube if the outside pressure is 0.650 atm .

Aneroid barometers are calibrated and examined using a mercury barometer. Altitude above sea level or atmospheric pressure are two examples of how calibration can be done. One kind of aviation altimeter is based on the idea of height above sea level and uses barometric pressure.

Mercury barometer:

Pa = ρgh

∴ Pa = 0.650 atm = 65861.25 Pa = 65861.25 Kg/ms²

∴ ρ = 13600 Kg/m³

∴ g = 9.80 m/s²

⇒ h = (65861.25 Kg/ms²) / (13600 Kg/m³ )(9.80 m/s²)

⇒ h = 0.494 m

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The material that forms oxide in the presence of oxygen and water only, and its suspension in water turns red litmus blue is Sodium oxide (Na2O).

Sodium oxide (Na2O) is a material that reacts with water and forms a basic solution with a pH greater than 7. It forms oxide in the presence of oxygen and water only. The chemical equation for the reaction of sodium oxide with water is given below:Na2O + H2O → 2NaOH.

The water molecules get hydrolyzed by sodium oxide to form sodium hydroxide (NaOH), which is a strong base. Sodium hydroxide gives a basic solution with a pH of about 12. It has the property of turning red litmus blue. Therefore, the material is Sodium oxide (Na2O).Hence, the main answer is Sodium oxide (Na2O).

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\(He_{2}\) has a bond order of 2. b) \(H_{2}\) has a single bond. 3) \(O_{2}\) is unstable. d) The molecules can be written in increasing stability as \(H_{2}\), \(He_{2}\), and then \(O_{2}\).

a) The molecule with a bond order of 2 is \(He_{2}\). \(He_{2}\) has two covalent bonds between its two helium atoms, each of which contains two electrons. This gives it a total of four electrons, resulting in a bond order of 2.

b) The molecule with a single bond is \(H_{2}\). This molecule contains two hydrogen atoms and one single covalent bond between them. This bond contains two electrons, giving it a bond order of 1.

c) The most unstable molecule of the three is \(O_{2}\) . This molecule contains two oxygen atoms and two double covalent bonds between them. This gives it a total of four electrons, resulting in a bond order of 2. The higher bond order makes it more unstable than the other two molecules.

d) The order of increasing stability is \(H_{2}\), \(He_{2}\), and then \(O_{2}\). \(H_{2}\) has the lowest bond order at 1, making it the most stable of the three molecules. \(He_{2}\) has a bond order of 2, making it less stable than \(H_{2}\) but more stable than \(O_{2}\). \(O_{2}\) has the highest bond order at 2, making it the least stable of the three molecules.

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The additional information that is required to obtain the enthalpy of neutralization is the density of the solution.

We know that the enthalpy of neutralization is defined as the heat that is evolved when  an acid is neutralized by a base under standard conditions. We can be able to obtain the enthalpy of the neutralization of the acid and the base by performance of some simple chemical calculations.

To carry out this calculations we need the all of the pieces of information that have been listed in the question such as the masses of the solution, the temperature of the solution in the initial and final states and so on.

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The mass of (NH4) 2S in the solution is : Mass = 0.0600 mol × 60.08 g/mol = 3.60 g.

The given molarity and volume of the solution can be used to calculate the number of moles of ammonium sulfide (NH4)2S.Then, the number of moles can be converted to mass using the molar mass of (NH4)2S.Mass of ammonium sulfide (NH4)2S in 3.00 L of a 0.0200 M solution is given by : Mass = moles × molar mass.The number of moles of (NH4)2S can be found using the equation:Molarity = Number of moles / Volume.Rearranging this equation, we get:Number of moles = Molarity × Volume Number of moles of (NH4)2S = 0.0200 M × 3.00 L.Number of moles of (NH4)2S = 0.0600 mol.The molar mass of (NH4)2S can be calculated by summing the molar masses of ammonium (NH4) and sulfide (S) ions.Molar mass of (NH4)2S = (2 × Molar mass of NH4) + Molar mass of S= (2 × 14.01 g/mol) + 32.06 g/mol= 60.08 g/mol.

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If a compound rotates plane-polarized light in a clockwise direction, the compound is called dextrorotatory, and is labeled d

If a compound rotates plane-polarized light in a anti- clockwise direction, the compound is called levorotatory compound is labeled as l.

An enantiomers rotate the plane polarized light in clockwise direction or positive direction is called dextrorotatory. given as [(+), d- ]. while enantiomers that rotates plane polarized light in anti - clock wise direction or negative direction is called levorotatory compound . given as [ (-) , l-].

Thus, If a compound rotates plane-polarized light in a clockwise direction, the compound is called dextrorotatory, and is labeled d

If a compound rotates plane-polarized light in a anti- clockwise direction, the compound is called levorotatory compound is labeled as l.

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The technique for brainstorming new ideas by asking a lot of questions is called starbursting. Option a.

This technique involves generating a lot of questions related to a particular topic and then answering each question with a set of new questions. By doing this, it helps to identify different aspects of the problem and to come up with new ideas that may not have been considered before.

This method encourages critical thinking and helps to explore different possibilities and perspectives. It is a useful tool for problem-solving, innovation, and decision-making. In summary, starbursting is a powerful technique that helps to unlock creativity and generate fresh ideas. Answer option a.

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1.89 moles of gas occupy 78.0 L at 300 Torr and 25.0 °C.

To calculate the number of moles of gas occupying 78.0 L at 300 Torr and 25.0 °C, we need to use the ideal gas law equation: PV = nRT. Here, P is the pressure of the gas, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin:
25.0 °C + 273.15 = 298.15 K.

Next, we convert the pressure from Torr to atmospheres (atm): 300 Torr/760 Torr = 0.3947 atm.

Now, we can plug in the values we have into the ideal gas law equation: (0.3947 atm) x (78.0 L) = n x (0.0821 L x atm/mol x K) x (298.15 K). Solving for n, we get n = 1.89 moles.

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Answer: Alkali metals, group 1

Explanation: Group 1 means 1 valence electron. This group is called alkali metals, which indicates that it is a metal. They are highly reactive because only 1 electron needs to move to bond with something (since it only has 1 valence electron)

the are 18.01528 grams

.....

Answer:

Neon

Explanation:

Chemical element Chemical series Electron configuration

3 . Li -Lithium Alkali metal [He] 2s1

4 . Be-Beryllium Alkaline earth metal [He] 2s2

5. B -Boron Metalloid [He] 2s2 2p1

6. C-Carbon Reactive nonmetal [He] 2s2 2p2

7 . N -Nitrogen Reactive nonmetal [He] 2s2 2p3

8. O-Oxygen Reactive nonmetal [He] 2s2 2p4

9. F -Fluorine Reactive nonmetal [He] 2s2 2p5

10. Ne-Neon Noble gas [He] 2s2 2p6

Answer:

Did you just let your cat walk on your keyboard? XD

Could you explain this a bit better please?

I'll answer the question in the replies of this comment if you can give me a bit more information.

Explanation:

May I have brainliest please? :)

Answer:

chemical weathering

Explanation:

Chemical weathering is the process responsible for changing the composition of rocks.

Weathering is the process by which rocks are broken down into smaller or tiny pieces.

There are different types of weathering namely;

Chemical weathering is the type of weathering that changes the chemical composition of rocks.

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Answer:

First 1-5 in pics

I can't upload further reactions

Explanation:

6. Lucas test

ROH + Zncl2 +HCl ---> RCl + H2O

7. esterification

R-OH +R’-COOH +H+↔ R’-COOR

Answer:

A. Exactly 1.55 ounces

When a water molecule is split, part of it is which used to make fuels is : a.) the electrons and protons from the hydrogen.

The water molecules break down into hydrogen and oxygen at the atomic level during thermolysis. For instance, around 3% of all H2O dissociates into different combinations of hydrogen and oxygen atoms at 2200 °C, primarily into H, H2, O, O2, and OH.

Water splitting is the chemical reaction where water is broken down into oxygen and hydrogen: 2 H2O → 2 H2 + O2

Efficient and economical water splitting could be a technological breakthrough that could underpin hydrogen economy, based on green hydrogen. A version of water splitting occurs in photosynthesis also but hydrogen is not produced.

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Answer:

It would be this below.

Explanation:

I am not 100% sure this is write but I did my best this is still kinda hard for me. I just did this a few years ago and i struggled with it but I have been doing better since then.

Hope this helps :))

Answer:

A Punnet Square...the second I am not sure.

Explanation:

Unfortunately the second could be many things. You'd have to have more background information.

Answer:

PUNNETT....,MAKE SURE U HAVE 2 T,s

Explanation:

punnett and cross