To establish a geosynchronous orbit at a distance of 8.6 105 m, the spacecraft must orbit the planet in the same period as the planet's rotation.
This means that the spacecraft must complete one orbit every T = 31 hours. The orbital period is related to the orbital radius by the equation T2 = 4π2R3/GM, where G is the gravitational constant and M is the mass of the planet.
Substituting in the values for T and R into this equation, we can solve for GM: GM = 4π2(8.6 105 m)3/T2 = 2.08 1017 m3/s2.
The spacecraft must then use its thrusters to adjust its speed and position until it enters an orbit with a period of 31 hours and a radius of 8.6 105 m. It can achieve this by using a combination of delta-v maneuvers to adjust its speed and trajectory. The first maneuver will be a prograde burn to increase the spacecraft's speed until it enters an orbit that is slightly more distant than the desired orbit. The spacecraft will then use a series of impulsive maneuvers to adjust its trajectory until it is in an orbit with the desired radius. Finally, the spacecraft will use a retrograde burn to reduce its speed until it reaches the desired orbital period.
Once the spacecraft has completed all of these maneuvers, it will be in a geosynchronous orbit at a distance of 8.6 105 m from the planet's surface.
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The waves in the pool where you are floating have a crest height of about 1 foot. Bobby does a cannonball dive off the side of the pool and sends waves 4
feet high toward your raft. The waves that Bobby produced have a greater
O amplitude.
compression.
frequency
wavelength
Answer:
I TNINK ITS C
Explanation:
The waves that Bobby produced have a greater amplitude. Then the correct option is A.
What are the waves?A wave is a dynamic disturbance of one or more variables that propagates in physics, mathematics, and related sciences. When waves oscillate frequently around an equilibrium value at a certain frequency, they are said to be periodic.
The wave can be represented as,
f(x) = A sin (ωt + ∅)
Where 'A' is the amplitude, 'ω' is the frequency, 't' is the time period, and '∅' is the phase difference.
The pool where you are floating has waves with crests that are roughly one foot high. Bobby performs a cannonball dive off the pool's edge, sending waves 4 feet high in your raft's direction.
Bobby generated waves with a bigger amplitude. Then, choice A is the best one.
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calculate the potential energy of 20kg object sitting on a 8meter ledge
Answer:
potential energy=mgh (weight × height)
m=20kg
g=9.8m/s2
h=8
20×9.8×8=1568
The potential energy is 1568J
Answer:
Potential energy = m × g × h
m = 20 kg
acceleration due to gravity = 9. 8 m/ s 2
height ( h ) = 8
= 20 × 9.8 × 8
= 1568
:. potential energy = 1568 Joule
a barometer reads 75cm. on admitting 0.6cm³ of air, the reading is 72.6cm. Find the volume of the space above the mercury at the end
Answer:
first to find volume you need to multiplied by itself three times to get the volume.
so it is going to be 3267cm
Explanation:
A toy car that is 0.12 m long is used to model the actions of an actual car that is 6 m long.
A toy car that is 0.12 m long is used to model the actions of an actual car that is 6 m long. So, The acceleration of the actual car is 1515.15 m/s².
The solution to this question can be achieved through the use of the equation: F = ma Where F is force, m is mass, and a is acceleration.
Step 1: Calculating the mass of the toy car using the ratio of lengths m1/m2 = l1/l2, where m1 and m2 are the masses of the toy car and actual car, and l1 and l2 are their respective lengths.
Rearranging, we have:m1 = (l1/l2)m2 = (0.12 m)/(6 m) m2 = 0.02 m2
Step 2: Using the equation, F = ma, we can determine the mass of the toy car: F = ma2 N = (0.02 m2) a a = 2 N / 0.02 m2 = 100 m/s²
Step 3: Using the same force of 5 N, the acceleration of the actual car can be calculated:F = ma5 N = ma m = m2/l2 m = 0.02 m2 / 6 m = 0.0033 kg a = F/m a = 5 N / 0.0033 kg = 1515.15 m/s²
Therefore, the acceleration of the actual car is 1515.15 m/s².
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The probable question may be:
A toy car that is 0.12 m long is used to model the actions of an actual car that is 6 m long. The toy car is pushed with a force of 5 N, causing it to accelerate at a rate of 2 m/s². Assuming the same force is applied to the actual car, calculate the acceleration of the actual car.
1. Give three examples, from the lab, where potential energy was converted to kinetic energy:
Answer:
A book on a table before it falls.
A yoyo before it is released.
A raised weight.
Explanation:
These are all examples of potential energy. So I hope you can find something that is comparable from the lab.
Describe the difference between continuous reinforcement and intermittent reinforcement.
Answer:
Continuous reinforcement delivers the reinforcement every single time the target behavior is delivered. (For example, if the target behavior for the dog is sitting when the owner says "sit", the treat (reinforcement) would be given whenever the dog follows the command). It follows a schedule-like reinforcement.
Intermittent reinforcement delivers the reinforcement to responses but are not consistent.
What kind of acceleration occurs when an object speeds up?
positive
negative
neutral
zero
Positive acceleration speeds the object up. Negative acceleration, aka deceleration, slows the object down. Zero acceleration means the object either keeps the same speed or isn't moving at all (we can say the speed is 0).
When an object speeds up, the positive acceleration occurs.
The acceleration is the time rate of change of velocity.
a = dv /dt
If the velocity is increased, the acceleration also increases, time remains same to cover a fixed distance.
Speeding up the object means positive acceleration. Negative acceleration also called deceleration slows the speed. Zero acceleration represents that the object is moving with constant velocity.
Thus, the positive acceleration occurs.
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Secret materials may be transmitted y the same methods as Confidential materials.
The statement is false that Secret materials may be transmitted by the same methods as confidential materials is False.
There are three characterization levels for the information system in the US: Highly classified, Secret, and Confidential. The term "secret" should allude to data whose unapproved disclosure could sensibly be expected to significantly affect the public safety.
Data that could sensibly be anticipated to hurt public safety whenever unveiled without approval will be marked as "classified.". Confidential material might be sent by U.S. Certified mail as opposed to by U.S. Enlisted mail. It can't be shipped off workers for hire by means of Top of the line mail.Highly confidential data will not be replicated or repeated without endorsement from the Highly classified Control Official.
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what makes something magnetic?
which atomic particle has no charge?
A. Electron
B. Neutron
C. Nucleus
D. Proton
Answer:
B. Neutron has no charge
Answer:
B. Neutron
Explanation:
Firstly, the nucleus is what contains the protons and electrons, so it is not an atomic particle. The electron has a negative charge, and the proton has a positive charge (you can remember this by looking at its prefix 'pro'). This means the neutron has no charge (think of it as neutral).
A person standing on a hill throws a ball horizontally with a velocity of 12m / s The ball lands 10.1 m away from the hill. How tall is the hill? Assume no air resistance
A.3.5
B.6.9
C.0.84
D.0.42
The height of a hill from which the person throws a ball horizontally with a velocity of 12 m/s and the ball lands 10.1 m away from the hill is 3.47 m.
What is the height of a hill from which the person throws a ball horizontally with a velocity of 12 m/s and the ball lands 10.1 m away from the hill?The height of a hill from which the person throws a ball horizontally with a velocity of 12 m/s and the ball lands 10.1 m away from the hill is calculated as follows;
The ball was projected horizontally from the top of a hill, therefore, there is no vertical component of the velocity of projection and the object is considered to be undergoing free fall under gravity from a height, h.
The height from which an object falls freely under gravity is calculated with the formula below:
H = gt²/2
where g is the acceleration due to gravity = 9.81 m/s²
t is time.
the time taken for the fall = horizontal distance / velocity
t = 10.1 / 12
t = 0.841 s
Therefore;
h = 9.81 * (0.841)² / 2
h = 3.47 m
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When you put a 9. 0 V battery across a bulb, 0. 1 A of current
flows through the bulb. Calculate the resistance of the bulb
When a 9.0 V battery is connected to a bulb and 0.1 A of current flows through it, the resistance of the bulb is 90 ohms.
When a 9.0 V battery is connected to a bulb and 0.1 A of current flows through the bulb, we can calculate the resistance of the bulb using Ohm's Law. Ohm's Law states that the current flowing through a conductor is directly proportional to the voltage applied across it and inversely proportional to its resistance.
To find the resistance, we can rearrange Ohm's Law equation (V = IR) to solve for R, where V is the voltage, I is the current, and R is the resistance.
First, let's plug in the given values:
V = 9.0 V (voltage)
I = 0.1 A (current)
Now, we can rearrange the equation to solve for R:
R = V / I
Substituting the given values:
R = 9.0 V / 0.1 A
Dividing 9.0 V by 0.1 A, we get:
R = 90 ohms
Therefore, the resistance of the bulb is 90 ohms.
In summary, when a 9.0 V battery is connected to a bulb and 0.1 A of current flows through it, the resistance of the bulb is 90 ohms.
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a stone is thrown horizonttaly from a cliff of a hill with an initial velocity of 30m/s it hits the ground at a horizontal distance of 80m from the foot of the hill how long does a stone travel? what is the height of the hill? (please show the process)
Answer:
a) Time = 2.67 s
b) Height = 35.0 m
Explanation:
a) The time of flight can be found using the following equation:
\( x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2} \) (1)
Where:
\( x_{f}\): is the final position in the horizontal direction = 80 m
\( x_{0}\): is the initial position in the horizontal direction = 0
\(v_{0_{x}}\): is the initial velocity in the horizontal direction = 30 m/s
a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)
t: is the time =?
By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:
\( t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s \)
b) The height of the hill is given by:
\( y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} \)
Where:
\( y_{f}\): is the final position in the vertical direction = 0
\( y_{0}\): is the initial position in the vertical direction =?
\(v_{0_{y}}\): is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)
g: is the acceleration due to gravity = 9.81 m/s²
Hence, the height of the hill is:
\( y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m \)
I hope it helps you!
lamp power with what is the current through the lamp when it is connected to a battery ?
Answer:
lamp power with what is the current through the lamp when it is connected to a battery ?
Explanation:
If the light bulbs are connected in parallel, the current flowing through the light bulbs combine to form the current flowing in the battery, while the voltage drop is 6.0 V across each bulb and they all glow. One bulb burning out in a series circuit breaks the circuit.
what has mobed to produce the charge on the plates
Charges need to be transferred from one plate to the other to generate a charge on a capacitor's plates. Electrons are usually moved from one plate to the other by attaching the plates to a power source, such as a battery.
The plate attached to the negative terminal of the battery becomes negatively charged and the plate connected to the positive terminal of the battery becomes positively charged when the power source is connected.
Until the potential difference between the plates equals the potential difference between the battery connections, electrons move from the negative plate to the positive plate. The flow of electrons stops at this moment, and the capacitor is fully charged.
In an electric field that is created between the plates of a capacitor, the charges on the plates are retained. The potential differential between the plates is produced by this electric field and is inversely proportional to the charge on the plates and their separation from one another.
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Objects with masses of 232 kg and 538 kg are separated by 0.342 m. a 60.6 kg mass in placed midway between them. 538 kg 1232 kg 60.6 kg - 0.342 m. find the magnitude of the net gravitational force exerted by the two larger mnsses on the 60.6 kg mass. the value of the univorsal gravi tational constant is 6.672 × 10-in- m°/kg? answer in units of n 017.leaving che distance botron the 242 kg and che 538 koenasses fixed. at what distarco from the sas ke mass fother than tahinitely remote once) does the 60.6 ka mass experienco a net fored of pay?
No net force is experienced. To find the magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass, we can use the equation for gravitational force.
Gravitational force equation:
F = G * (m1 * m2) / r^2
Where F is the gravitational force, G is the universal gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.
In this case, m1 = 232 kg, m2 = 538 kg and r = 0.342 m.
So, F = G * (232 kg * 538 kg) / (0.342 m)^2
Plugging in the values, we get:
F = 6.672 x 10^-11 N*(m^2)/(kg^2) * (232 kg * 538 kg) / (0.342 m)^2
The magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass is 0.092 N.
To find the distance at which the 60.6 kg mass experiences a net force of zero, we can use the equation for the gravitational force between two masses. Since the force is inversely proportional to the square of the distance between the masses, we can set the force to zero and solve for the distance.
F = G * (232 kg * 60.6 kg) / (r)^2 = 0
r = √((232 kg * 60.6 kg) / (G))
r = √((232 * 60.6) / (6.672 * 10^-11))
r = 2.36*10^-5 m
At this distance, the 60.6 kg mass experiences no net force from the two larger masses, as the gravitational force exerted by the 232 kg mass balances out the gravitational force exerted by the 538 kg mass.
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One of the many isotopes used in cancer treatment is 19879Au, with a half-life of 2.70 d. Determine the mass of this isotope that is required to give an activity of 215 Ci. Answer in mg.
The mass of 19879Au required to give an activity of 215 Ci is approximately 12.1 mg. Solving for m gives us approximately 12.1 mg of 19879Au.
To calculate the mass of 19879Au needed to give an activity of 215 Ci, we can use the following equation:
Activity = (ln2 x N x m) / t
Where N is Avogadro's number, m is the mass of the isotope in grams, t is the half-life in seconds, and ln2 is the natural logarithm of 2.
Rearranging this equation to solve for mass, we get:
m = (Activity x t) / (ln2 x N)
Substituting the given values, we get:
m = (215 x 24 x 3600) / (ln2 x 6.022 x 10^23 x 198)
Solving for m gives us approximately 12.1 mg of 19879Au.
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If two runners cover the same distance in different amounts of time, how do there speeds compare
4. A 2.00 kg object is accelerated uniformly from rest to 3.00 m/s while moving 1.5 m across a
level frictionless surface. Calculate the power output.
The power output of 2.00 kg object is accelerated uniformly from rest to 3.00 m/s while moving 1.5 m across a level frictionless surface is 24.09 watts.
What is power?In science, power is the time required to do work or provide energy, expressed as work done W or energy transferred divided by the time interval t - or W/t. A fixed amount of work can be done for a long time with a low-powered engine, or for a short time with a high-powered engine. The unit of power is work (or energy) per unit of time. Such as foot pounds per minute, joules (or watts) per second, and ergs per second. Force can also be expressed as the product of the force required to move an object and the object's velocity in the direction of the force. If the magnitude of the force F is measured in pounds and the velocity ν is measured in feet per minute, then the power is equal to Fν foot pounds per minute.
Given,
Mass of object (m) = 2.00 kg
Distance covered (s) = 1.5 m
Velocity of object (v) = 3.00 m/s
For calculation of acceleration:
v² = u² + 2as
3² = 0 + 2 × a × 1.5
9 = 3a
a = 2 m/s²
For calculation of time:
s = ut + ¹/₂at²
1.5 = 0 × t + ¹/₂ × 2 × t²
1.5 = t²
t = 1.22 sec.
For calculation of gravitational force:
F = mg
F = 2 × 9.8
F = 19.6 N
For calculation of work done:
W = F × s
W = 19.6 × 1.5
W = 29.4 J
For calculation of power output:
P = W/t
P = 29.4/1.22
P = 24.09 watts
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Please help! Will give brainliest!
A cyclist changes its speed going down hill from 22 m/s to 37 m/s in 2 seconds. Calculate the acceleration of the cyclist.
Answer:
7 1/2m/s/s
Explanation:
37-22=15
15/2=7 1/2
Which statement describes the wave interactions in sound navigation and ranging (SONAR)? Sound is transmitted through the water and diffracted by hard surfaces.
In Sound Navigation and Ranging (SONAR), the sound wave is transmitted through water and it will reflect by hard surfaces. Option B) is correct.
SONAR is used to create nautical charts, find underwater navigation hazards, search for and map things on the seafloor such as shipwrecks and map the seafloor itself, waves are transmitted into the waver and reflected by hard surfaces.
The transmission and receiving of sound waves are involved in active sonar. For example, when a submarine is used to map the topography of the ocean floor.
It emits sound pulses known as pings towards the bottom of the ocean in its area.
Thus, 'Sound is transmitted through water and reflected by hard surfaces is the correct option'.
The question is incomplete. The options are missing in the question. They are A) Sound is transmitted through the water and diffracted by hard surfaces. B) Sound is transmitted through the water and reflected by hard surfaces. C) Sound is diffracted through the water and transmitted by hard surfaces. D) Sound is diffracted through the water and reflected by hard surfaces.
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What does the acronym stand for?
Answer:
an abbreviation formed from the initial letters of other words and pronounced as a word (e.g. ASCII, NASA ).
Explanation:
....
Answer:
Definition of acronym:a word (such as NATO,radar or laser)formed from the initial letter or letters of each of the successive parts or major parts of a compound term also :an abbreviation (such as FBI formed from initial letters:intialism.
Explanation:
Hope it helps
breakout edu space simulation need help with questions 2 and 4?
None of the games we publish on the website have answer keys available. It's Time for Something Different is one of Breakout EDU's catchphrases. By demonstrating that teachers don't always know the answers, we hope to prove this. Nothing has to be set up; the game is ready to start.
What are the breakout EDU space simulation?Hints are merely some information to help your group get over a barrier or view the data differently; they are not solutions. When the box is opened, Breakout EDU doesn't end.
Therefore, The game's facilitator, who is watching and observing the group, provides you with these tips.
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gas to liquid pls fast answer
Answer:
wet farts, JK its condensation.
what should you do before aiming and firing on a target?
Answer:
Below
Explanation:
Be sure of your target and what is in front of AND beyond it. Do not point your weapon at anything you do not want to shoot. Make sure your armament is properly maintained/loaded and functioning. Hearing and eye protection for you and those around you is in place.
What is the objects average velocity?
Answer:
answer should be 10 because the line goes from (0,0) then to (1,10) and so on
Which term is used to describe the highest point on a transverse wave?
A. frequency
B. crest
C. trough
D. amplitude
Answer:
B. Crest
Explanation:
The high point of a transverse wave is a called the crest.
The student investigates how the resistance of a thermistor varies with temperature. The student has a power supply, a thermistor, an ammeter, a voltmeter and some connecting leads. Describe an investigation the student could carry out to measure the resistance of a thermistor between –10 °C and 70 °C.
Your answer should include:
1. Any other apparatus the student will need
2. The measurements to be taken
3. How the data should be processed.
(This question is worth 6 marks on my assignment so I just really want to get down the best possible answer for it.)
The characteristics of the thermistors allow to design an experiment to analyze the dependence of resistance with temperature;
1) We set up the circuit
2) We look for the current of the circuit and we keep it fixed.
3) We look for the thermistor resistances for each temperature.
4) Plot Resistance versus Temperature.
A Thermitor is an element whose resistance changes with temperature, for example a platinum resistance.
An experiment that we can carry out to measure is to set up the attached circuit where we have:
A DC power supply. A resistor to control the maximum current in the circuit and avoid thermal problems in the thermistor. A thermistor. A thermometer placed next to the thermistor. A source of heat under the thermistor under a glass with ice and water, but without affecting the other elements of the circuit.
Let's start by looking for the current in the circuit.
In thermistors, the resistance for room temperature is given, so if we measure the voltage across the fixed resistor, we can shrink the voltage across the thermistor.
\(V_{source} = V_R + V_{therm} \\V_{therm} = V_{source} - V_R \\ i = \frac{V_{therm} }{R_{therm}}\)
This current remains fixed, since the fixed resistance is greater than the resistance of the thermistor throughout the range.
Second step.
Now we can change the temperature that is measured in the thermometer, for each temperature the voltage in the fixed resistance is measured, the resistance in the thermistor is calculated.
\(R_{therm} = \frac{V_{source} - V_R}{i}\)
Third step.
We end with a graph of resistance versus temperature of the curve obtained, it is possible to understand the behavior of the resistance of the thermistor with temperature.
In conclusion with the characteristics of thermistors we can design an experiment to analyze the dependence of resistance with temperature:
1) We set up the circuit
2) We look for the current of the circuit and we keep it fixed.
3) We look for the thermistor resistances for each temperature.
4) Plot Resistance versus Temperature.
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Describe specifically why a one-time pad is completely unbreakable. What happens if we try and brute-force
something encrypted with a one-time pad?
Encrypt the message "yellowstone" using the key "wolf" using the vignere cipher.
A one-time pad is a type of encryption that is completely unbreakable if it is done correctly. It works by generating a random key that is at least as long as the message being encrypted. The key is then combined with the message using an XOR operation.
This produces a ciphertext that cannot be decrypted without the key. The key is used only once and then discarded, hence the name "one-time pad". A one-time pad is completely unbreakable because there is no pattern to the key that can be used to decrypt the message. Each character in the key is generated randomly and independently of the other characters. Therefore, the key is completely unpredictable. Even if an attacker knows the key length and has access to the ciphertext, they cannot use any techniques to decrypt it.
This is because there is no pattern to the ciphertext that can be used to determine the key.The only way to decrypt a one-time pad is to have the key. If an attacker tries to brute-force the encryption by trying all possible keys, they will generate every possible message that is the same length as the original message. This means that the ciphertext is completely meaningless without the key. It is therefore important to keep the key secret and ensure that it is only used once. ,Message: yellow stone Key: wolf To encrypt the given message using the vigenere cipher, we follow the steps below:Step 1: Write the message and key in a tabular form as shown below. To keep the process organized, we use the letters of the key to label the columns.
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Examine the cross-sectional slice of a stem of a mint plant. Which statement most specifically describes mint?
The available options are:
Mint is a dicot.
Mint is a monocot.
Mint is an angiosperm.
Mint is a bulb plant.
Answer:
Mint is a dicot.
Explanation:
Given the fact that Mint is considered to be a member of Lamiaceae, an angiosperm plant which is characterized by typically having leaves that consist of reticulate vacation and appears like veins in structure. It also has a seed that contains two cotyledons.
Hence, it is considered a DICOT PLANT due to these characteristics. The botanical name of Mint is referred to as Mentha arvensis.
Answer: A
Explanation: