An iron anchor of density 7730 kg/m3 appears 290 N lighter in water than in air.

(a) What is the volume of the anchor?
(b) What is its mass

Answer:

1 km

Explanation:

displacement =velocity ×time

displacement =40m/s ×25s

displacement =1000m equivalent to 1km

Answer:

Aluminum foil is negatively charged and gold fillings are positively charged.

Hope this helps :)

Answer:

100N.

Its 100n. :)

Graph of area under force vs displacement shows work done. Thus A. is 30J, B. is -12J, C. 18J.

Amount of energy required for the displacement of an object at certain distance, is called work done.

Given,

along y(m) axis, each unit is 2m.

along Fy(N) axis, each unit is 2N.

A. Distance between y = A to y = B

W(AB) = 1/2×base×height

W(AB) = 1/2×10m×6N

W(AB) = 30J

B. Distance between y = B to y = C

W(BC) = 1/2×base×height

W(BC) = 1/2×6m×-4N

W(BC) = -12J

C. Distance between y = A to y = C

W(AC) =  W(AB)+W(BC)

W(AC) = 30J+(-12J)

W(AC) = 18J.

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The question is incomplete, but most probably the complete question is, attached in image:

Answer:

Explanation:

The tank is half full so height of water level is at 1 m . Centre of gravity of water will be at height of .5 m . Pressure will act at this point .

Pressure = h d g where h is height of centre of mass of water column , d is density of water and g is acceleration due to gravity .

Pressure of water column  = .5 x 10³ x 9.8 = 4.9 k Pa .

Air is pressurized to 5 kPa so

resultant pressure  on one side of the tank due to the air and water

= 4.9 + 5 kPa = 9.9 kPa .

Total force on one face = pressure x area of one face under water

= 9.9 x 10³ x .5 x 2²

= 19.8 kN .

The acceleration of the cart

a=1.2431m/s^2

Generally, The equation for Newton's second law of motion is

2nd law of motion,

Fnet=m a

on hanging mass,

m_1 g-T=m_1 a

m_1 g-m_2 a=m_1 a

Acceleration, \($a=\frac{m_1 g}{m_1+m_2}$\)

\(&a=\frac{0.077 \mathrm{~kg} \times 9.8 \mathrm{~m} / \mathrm{s}^2}{0.077 \mathrm{~kg}+0.53 \mathrm{~kg}} \\\)

a=1.2431m/s^2

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Graphical analysis of motion gives the graphical the relationships between position, velocity, and acceleration, versus time

2. Please find attached the required position versus time and acceleration versus time graphs

3. Please find attached the required velocity versus time and position versus time graphs

The reasons the attached graphs are correct are given as follows:

2. The given coordinates of the vertex points obtainable from the graph is first written as follows:

\(\begin{array}{|c|c|c|c|c|}\underline {Time, \ t}&\underline {Velocity, \ v}&Acceleration, a&\underline {Distance , \ s =v\cdot \Delta t+\dfrac{1}{2} \cdot a \cdot (\Delta t)^2}&Position\\0&-1&0&0&0\\2&1&1&0&0\\4&-1&-1&0&0\\6&1&1&0&0\\10&1&0&4&4\\12&0&-0.5&1&5\end{array}\)The distance covered between time intervals of time, s, is given as follows;

\(s = v \cdot \Delta t + (1/2) \cdot a \cdot ( \Delta t)^2\)

The position, Pₙ = s₁ + s₂ + s₃ + ... + sₙ

Other values on the graph obtained by calculation on a spreadsheet are;

\(\begin{array}{|l|cl|}Time \ (s)&&Position \ (m)\\0.5&&-0.375\\1&&-0.5\\1.5&&-0.375\\2.5&&0.375\\3&&0.5\\3.5&&0.375\\4.5&&-0.375\\5&&-0.5\\5.5&&-0.375\\6.5&&0.5\\7&&1\\7.5&&1.5\\8&&2\\8.5&&2.5\\9&&3\\10&&4\\10.5&&4.4375\\11&&4.75\\11.5&&4.9375\\12&&5\end{array}\right]\)

Please find attached the acceleration versus time graph

3. The coordinates of the points are presented as follows:

\(\begin{array}{|c|cc|}\underline{Time\ (s)}&&\underline{Acceleration\ (m/s^2)}\\0&&0.5\\2&&0.5\\2&&0\\4&&0\\4&&-0.5\\6&&-0.5\\6&&0\\8&&0\\8&&0.5\\10&&0.5\\10&&-0.5\\12&&-0.5\end{array}\right]\)

The distance covered between time intervals, s, is given as follows;

\(s = v \cdot \Delta t + (1/2) \cdot a \cdot ( \Delta t)^2\)

The position, Pₙ = s₁ + s₂ + s₃ + ... + sₙ

Using a spreadsheet application, more detailed values of the position can be found as shown in the graph created with MS Excel

0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6, 6.5, 7, 7.5, 8, 8.5, 9, 9.5, 10, 10.5, 11, 11.5, 12

0, 0.06, 0.25, 0.56, 1.00, 1.50, 2, 2.5, 3, 3.5, 3.81, 4.00, 4.06, 4.06, 4.06, 4.06, 4.06, 4.13, 4.31, 4.63, 5.06, 5.50, 5.81, 6, 6.06

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===================================================

Explanation:

vi = 5 and vf = 8 are the initial and final velocities respectively. The change in time is t = 20 seconds.

So,

x = 0.5*(vi + vf)*t

x = 0.5*(5+8)*20

x = 130 meters

represents the distance traveled. The first equation shown above is one of the four kinematics equations.

Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.

Here are the steps to be followed:

Step 1: Understanding the Assignment Requirements

Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.

Step 2: Research

Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.

Step 3: Worksheet Setup

Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.

Step 4: Fill in Row 1 - Plate Boundary (Movement)

In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.

Step 5: Fill in Row 2 - Diagram

In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.

Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)

In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.

Step 7: Fill in Row 4 - Geologic Process

In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.

Step 8: Fill in Row 5 - Real World Example

In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.

Step 9: Fill in Row 6 - References

In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.

Step 10: Review and Proofread

Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.

Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.

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when Force (N) is 10.0 Length (m) is 0.60

when Force (N) is 8.0 Length (m) is 0.40

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 2.0 Length (m) is 0.10

chatgpt

49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:

Period (T) = 2π√(Length (L) / g)

Substituting the given values:

2.3 = 2π√(L / 1.6)

To solve for L, we can rearrange the formula:

L = (2.3 / (2π))^2 * 1.6

L ≈ 0.781 meters (or 78.1 centimeters)

So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.

50. Ranking Task:

To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.

Ranking from least to greatest period:

1. A: 10 cm long, mass = 0.25 kg

2. C: 20 cm long, mass = 0.25 kg

3. B: 10 cm long, mass = 0.35 kg

There is a tie between pendulums A and C, as they have the same length but different masses.

Explanation:

The laser cauterizes as it cuts thus reducing blood loss.

Answer:

C pollutants

Explanation:

Pollutants are dangerous substances in the ecosystem that are harmful to its organisms. They are contaminants and effluents that leads to pollution in the environment.  

Answer:

c

Explanation:

Answer:

He should call a forensic pathologist to help him.

Explanation:

Since he is experienced and would know about this

When investigating a crime scene, Grant finds some evidence that could possibly be blood. He should call a forensic pathologist to help him. Option (D) is correct.

An expert in forensic pathology will examine the deceased person's medical history, crime scene evidence, witness statements, perform an autopsy to determine if the death was brought on by an illness or an injury, and collect additional evidence from the body.

The five main legally recognized causes of death are natural, homicide, accidents, and undetermined in the majority of states. A forensic pathologist is obligated to record his findings in a report following the conclusion of his investigation, and he or she may occasionally be asked to testify in court. In light of the fact that their testimony and credibility can be used to judge a defendant's guilt or innocence, forensic pathologists are frequently important witnesses in court cases involving death.

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The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Answer:

I believe you have everything correct :)

Answer:

The average acceleration is about 8.51 m/s

Explanation:

     We can use the formula for acceleration to solve.

a = \(\frac{velocity_{final} -velocity_{start} }{time}\)

a =  \(\frac{80-0}{9.4}\)

a =  \(\frac{80}{9.4}\)

a ≈ 8.51

Answer:

Explanation:

Yes, when a ball rolls down a ramp, it possesses kinetic energy. Kinetic energy is the energy associated with an object's motion. As the ball rolls down the ramp, it gains speed and its motion increases, resulting in an increase in its kinetic energy. The amount of kinetic energy the ball has depends on its mass and velocity.

Hope this answer your question

Please rate the answer and

mark me ask Brainliest it helps a lot

Answer:

Yes, when a ball rolls down a ramp, it possesses kinetic energy.

Explanation:

Kinetic energy is the energy associated with an object's motion. As the ball rolls down the ramp, it gains speed and its motion increases, resulting in an increase in its kinetic energy. The amount of kinetic energy the ball has depends on its mass and velocity.

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a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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ANSWER

EXPLANATION

Parameters given:

Mass of skier, m = 72.5 kg

The angle of the slope, θ = 21.7°

Coefficient of kinetic friction, μk = 0.120

Force exerted, F = 383 N

Let us first make a sketch of the problem:

The net force acting on the skier is equal to the difference in the force exerted on the skier by the rope, the component of the weight parallel to the slope, and the force of friction:

That is:

The free-body diagram is given below:

The normal force to the surface is given by:

Therefore, the net force is:

The net force is equal to the product of the mass of the skier and the acceleration of the skier. This implies that:

Solving for a:

That is the acceleration of the skier.

Answer:

C. a = 15 N, b = 14 N

Explanation:

since a is pushing the box to the right and b to the left, it would only work if the force applied by a is the stronger so the only answer with the stronger force being a is C. a = 15 N, b = 14 N since the final resultant force would be 1 N to the right

Answer:

Its C

Explanation:

I did it on my own and it was correct.

the second question for this, the answer is 100 N

The tractor is in linear motion but the wheels of the tractor are in rolling motion.

When the sudden turn comes then it wants to continue in rolling motion due to conservation of angular momentum.

But the angular momentum is applied and due to inertia, the weight and friction shifts on the bigger wheels causing difference in the angular speed.

Thus, the bigger rear wheels of the tractor rotate more slowly as compared to front small wheels because the bigger wheels have greater moment of inertia due to their mass as compared to front small wheels. That’s why the rear wheels are bigger than the front wheels.

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Answer: a

Explanation:

Impact force

Impact force is the force exerted by bodies when they come in contact. Impact force has same unit as force. it is similar to impulse the difference is that impulse considers time.

hope it helps...

Answer:

1.4 m/s2

Explanation:

i took the test

Answer:

I'm not 100% sure, but I'd say adrenaline

Explanation:

adrenaline gets higher the more excited or nervous you get. Since Byron was happy, proud, and, nervous I'd say it was his adrenaline. hope this helps!

Answer:

4.9 km

Explanation:

\(\sqrt{4.2^2+2.6^2}=4.9 km\)

Answer:

mass =  0.5679 Kg

hope this helps!

Answer:

Energy = 30J

Explanation:

Energy = Force x Distance

Energy = 120 x 0.250m

Energy = 30J

A nova or supernova may be the most catastrophic occurrence in all of nature.

A negatively charged subatomic particle called an electron can either be free or attached to an atom (not bound). One of the three main types of particles in an atom is an electron that is attached to it; the other two are protons and neutrons.

For creating cross-platform desktop apps using HTML, CSS, and JavaScript, GitHub developed the open source library called Electron. Chromium and Node are combined to create Electron, which does this. Apps may be produced for Mac, Windows, and Linux and combined with JavaScript into a single runtime.

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