an irs auditor randomly selects 3 tax returns from59returns of which7contain errors. what is the probabilitythat she selects none of those containing errors?

The values of the expressions are: 5x, -5, 18 - z , -5,  16/m, 4, 36n, 3k +4 , 2,

Recall that a mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context. Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation and grouping to help determine order of operations and other aspects of logical syntax.

1a. the product of 5 and a number x.

= 5*x = 5x

b  Evaluate when x = -1.

= 5*-1 = -5

2a   18 decreased by a number z

this implies 18 - z

b Evaluate when z = 23.

18-23 = -5

3a The quotient of 16 and a number m

= 16/m

b  Evaluate when m=4

this means 16/4 = 4

4. aThe product of 8 and twice a number n

= 18*2(n)

= 36n

b. Evaluate when n = 3

= 36*3 = 108

5.aThe sum of 3 times a number k and 4

= 3(k) + 4

= 3k +4

b. Evaluate k= -2

= 3*-2 + 4

-6+4 = 2

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Therefore , the solution of the given problem of ratio comes out to be

CD:DE = 1:2. and AB:BC = 2:1 .

Use the simple formula "a / b" to create a group of linked variables "a" and "b," where "b" may also be higher than zero. One ratio is created by combining two equation ratios. If there were only one man and three ladies, the ratio would be 1:1. There are 1/4 males and 3/4 girls in the group. A division between two or more objects, a number, or even a portion of a component's volume are all examples of parts.

Here,

Ratio 1: AB:BC = 2:1

Let's use the midpoint formula to find the coordinates of point C, which is the midpoint of line segment AB:

C = ((5+x)/2, (0+y)/2) = ((5+x)/2, y/2)

Since AB:BC = 2:1, we know that the distance from A to B is twice the distance from B to C. Using the distance formula, we can write:

2 * BC = AB

2 * √((x+1)² + y²) = √((x-5)^2 + y^2)

Simplifying this equation, we get:

4 * (x+1)² + 4y² = x² - 10x + 25 + y²

Simplifying further, we get:

3x²+ 8x - 16y² - 75 = 0

Ratio 2: CD:DE = 1:2

Let's use the midpoint formula to find the coordinates of point E, which is the midpoint of line segment CD:

E = ((p-1)/2, (q-4)/2)

Since CD:DE = 1:2.

Therefore , the solution of the given problem of ratio comes out to be

CD:DE = 1:2. and AB:BC = 2:1 .

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Answer:

(-4, 6) (-1, 0)

Source:

Took test. ✌

With a 99% confidence level, we can say that the true proportion of all homes that have electrical/environmental problems is at least 8.3%.

To calculate a lower confidence bound using a confidence level of 99% for the percentage of all homes that have electrical/environmental problems, we need to have a sample of data on this issue. Let's assume that we have a random sample of 100 homes, and 20 of them were found to have electrical/environmental problems.

To calculate the lower confidence bound, we can use the formula:

Lower bound = p - zα/2 * sqrt(p * (1-p) / n)

where:

p = proportion of homes in the sample that have electrical/environmental problems = 20/100 = 0.2

zα/2 = z-score for the given confidence level of 99% = 2.576 (obtained from a standard normal distribution table or calculator)

n = sample size = 100

Plugging in these values, we get:

Lower bound = 0.2 - 2.576 * sqrt(0.2 * 0.8 / 100) = 0.083

Therefore, with a 99% confidence level, we can say that the true proportion of all homes that have electrical/environmental problems is at least 8.3%.

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This means we can be 99% confident that the true percentage of all homes with electrical/environmental problems is

at least 17.5%.

To calculate a lower confidence bound using a confidence level of 99% for the percentage of all homes that have

electrical/environmental problems, you would need a sample of homes and the number of homes in the sample that

have such problems. Using this information, you could calculate the sample proportion (p-hat) of homes with

electrical/environmental problems.

Then, using a formula or calculator, you could find the lower confidence bound by subtracting the margin of error (ME)

from the sample proportion.

The margin of error can be calculated using the sample proportion, sample size, and the chosen confidence level (in

this case, 99%).

For example, if the sample proportion is 0.25 and the sample size is 100, the margin of error would be 0.075 and the

lower confidence bound would be 0.175 (0.25 - 0.075).

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The measure of the angle is x = 42.71°

In the right triangle we know the hypotenuse and the adjacent cathetus to angle x, so we can use the trigonometric relation:

cos(x) = (adjacent cathetus)/hypotenuse

Here we have:

adjacent cathetus = 12

Hypotenuse = 13

Then:

tan(x) = 12/13

x = Atan(12/13)

x = 42.71°

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Answer:

Plugging in the values into the formula, we have:

z = (675 - 700) / 100

z = -25 / 100

z = -0.25

So, the z-score of a person who scored 675 on the exam is -0.25.

The z-score tells us how many standard deviations a score is away from the mean. In this case, a z-score of -0.25 means that the score of 675 is 0.25 standard deviations below the mean.

Step-by-step explanation:

Greetings.

The range is the set of y-value.

The range starts from the minimum point to maximum point.

Our minimum point starts at 0 and maximum point starts less than infinity.

Therefore the range is 0<=y<+inf

However, we do not often write that, although it is right.

Therefore we write as y≥0

Thus, the answer is B choice.

Answer:

As Sophie has just taken the medicine, the quantity of drug present in her body is 500mg

Amount left from 1st dose = 4.5/100 × 500 = 22.5mg

Amount of Drug after 2nd dose = Amount left from 1st dose + 2nd dose taken.

Amount of Drug after 2nd dose = 22.5mg + 500mg

Amount of Drug after 2nd dose = 522.5mg

Amount left from 2nd dose = 4.5/100 × 522.5 = 23.513 mg

Amount of Drug after 3rd dose = Amount left from 2nd dose + 3rd dose taken.

Amount of Drug after 3rd dose = 23.513mg + 500mg

Amount of Drug after 3rd dose = 523.513 mg

Amount left from 3rd dose = 4.5/100 × 523.513 = 23.558mg

Amount of Drug after 4rth dose = Amount left from 3rd dose + 4rth dose taken.

Amount of Drug after 4rth dose = 23.558mg + 500mg

Amount of Drug after 4rth dose = 523.558 mg

The pattern formed above can be written in the form of sum of finite geometric series:

Sₙ = 500 + 500(0.045) +500(0.045)² + ........................500(0.045)ⁿ

Sₙ = 500(1 + 0.045 + 0.045² ........................0.045ⁿ)

Where

Sₙ = Sum till nth term

a = 500

r = 0.045

As Sophia takes medicines 2 times a day, she takes medicine 20 times in 10 days. So substitute n=20 in the formula for the sum of finite geometric series

\(S_n=a\frac{(1-r^n)}{1-r}\\S_{20}=500(\frac{1-0.045^{20}}{1-0.045})\\S_{20}=523.5602~\text{mg}\)

Greatest amount of antibiotic present = 523.5602 mg

This amount is almost constant after 3rd dose, so it will occur after every dose after 3rd dose

After 1st dose = 500mg

After 2nd dose = 522,5mg

After 3rd dose = 523.513 mg

After the the amount left in the body almost remains constant.

Which means that after each dose, the amount in body is maximum, at the end of the 12 hours, the amount reduces to 4.5%, which reaches almost the same maximum after taking another dose.

Answer:

Step-by-step explanation:

The system of equations is:

x^2 = y

x^2 + y^2 = 9

Substituting the first equation into the second, we get:

x^2 + (x^2)^2 = 9

x^4 + x^2 - 9 = 0

Using the quadratic formula, we can solve for x^2:

x^2 = (-1 ± sqrt(37))/2

Taking the positive root, we get:

x^2 = (-1 + sqrt(37))/2

Substituting this back into the first equation, we get:

y = (-1 + sqrt(37))/2

So the solution is the point (sqrt((-1 + sqrt(37))/2), (-1 + sqrt(37))/2)

Looking at the graphs, only graph (d) contains the point (sqrt((-1 + sqrt(37))/2), (-1 + sqrt(37))/2), so the answer is (d).

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QUESTION: Which graph shows the system (x^2 = y =2 x^2 + y^2 = 9

    |     /|

    |    / |

    |   /  |

    |  /   |

    | /    |

    |/     |

_____|______|______

    |

    |

    |

    |

    |

    |

Answer:

E - (28, 25)

Hope this helps!

Answer:

hi kenma-san!!!!!!

Step-by-step explanation:

A trapezoid with height 6.4 cm and parallel base is 12.9 cm and 8.6 cm.

We have to find the area of area of this trapezoid.

Area of trapezoid =

Given : Height = 6.4 cm

and parallel base is 12.9 cm and 8.6 cm.

Substitute, we have,

Area of trapezoid =

Simplify, we have,

Area of trapezoid =

Area of trapezoid = 68.8 cm²

Thus, The area of given trapezoid is 68.8 cm²

In multiple regression analysis, a variable that cannot be measured in numerical terms is called a categorical independent variable.

This type of variable is usually represented by non-numerical data, such as names, categories, or labels. Unlike numerical variables, categorical variables cannot be measured in units or values, but rather they represent different groups or categories. For instance, a categorical independent variable could be gender, race, or occupation.

These variables are included in regression analysis as dummy variables, which take on the value of 0 or 1, depending on whether the observation belongs to a specific category or not. It is important to note that while categorical variables cannot be measured numerically, they still play an important role in predicting the dependent variable in regression models.

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Answer:

x = all real values

y = all real values

Step-by-step explanation:

The domain is the input values

f(x) = 4x+52 which is a line

The input or x values can be any value so the domain is all real values of x

The range is the output values

f(x) = 4x+52 which is a line

The output or y values can be any value so the domain is all real values of y  

Answer:

C. HL

Step-by-step explanation:

The diagram given shows that the hypotenuse length and the length of a leg of one right triangle is congruent to the hypotenuse and corresponding leg length of the other. Based on Hypotenus-Leg criterion, the two right triangles is proved to be congruent because it meets the criterion of HL.

Answer:

$34.78

Step-by-step explanation:

first,  we need to find the value of 1 HCF, so we divide $48.70 by 14, giving us the result of 3.47857143. (rounding that turns out to be 3.48.

next, we need to multiply the cost of 1 HCF by 10, so 3.48 * 10 = 34.78

Answer :

Evaluate

Isolate the variable by dividing each side by factors that don't contain the variable.

x = 2 i √ 5 , − 2 i √ 5

Step-by-step explanation:

The correct option is b which tells that an optimal solution to a linear programming problem must lie at the intersection of at least two constraints.

Linear programming is an optimization technique that is fine for the purpose of getting the best solution such as maximizing profit or certain 4th-era quantities.

When there are just two choice variables, the graphic method of solving a linear programming issue can be employed.

It is fine by modelling real-life problems into mathematical models that have linear relationships or constraints such as in the form of objective functions.

In linear programming, an objective function defines the formula for quantity optimization and the goal from this is to determine variable values that maximize or minimize the objective function depending on the problem robbery solved.

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Answer:

11x+2

Step-by-step explanation:

The initial position of the point W (-13, 9)

The transformed position of the point W' (-9, -13)

when transformed 90 degrees counterclockwise, the coordinates of the original position is swapped and the y-coordinate is negated

That is if the W coordinate is (x,y), the transformation W coordinate in 90 degrees counter-clockwise will be (-y, -x )

Since W is (-13, 9)

Then W' will be ( -9 , -13)...In 90 degrees counterclockwise

Answer:

a

Step-by-step explanation:

The value of cos2x when sine of x equals negative 15 over 17 and cos x > 0 is -161/289.

The ratio of the neighboring side's length to the longest side, or hypotenuse, in a right triangle is known as the cosine. Let's say that the hypotenuse of a triangle ABC is written as AB, and the angle between the hypotenuse and base is written as.

It's interesting to see that cos's value varies depending on the quadrant. As observed in the above table, cos 0°, 30°, etc. have positive values while cos 120°, 150°, and 180° have negative values. Cos will have a good value in the first and fourth quadrants.

Given that, sin x equals negative 15 over 17.

Using the Pythagoras theorem we have:

(17)² = (- 15)² + y²

y = 8

The value of cos x = 8/17

Then the value of cos2(x) is calculated using the formula:

cos2x = cos²x - sin²x

cos2x = (8/17)² - (15/17)²

cos2x = -161/289

Hence, the value of cos2x when sine of x equals negative 15 over 17 and cos x > 0 is -161/289.

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σ(aX+bY) = sqrt(a²Var(X) + b²Var(Y)) The given data is as follows: E(X) = $77σX = $58Y = $51 + 1.04XTo find: The standard deviation of Y We know that the standard deviation of a linear equation is given as follows:σy = | 1.04 | σX

Here, 1.04 is the coefficient of X in Y, and σX is the standard deviation of X.σy = 1.04 × $58= $60.32 Therefore, the standard deviation of Y is $60.32.

How was this formula determined? The variance of linear functions of random variables is given by the formula below: Var(aX+bY) = a²Var(X) + b²Var(Y) + 2abCov(X,Y)Here, X and Y are two random variables, a and b are two constants, and Cov(X,Y) is the covariance between X and Y. When X and Y are independent, the covariance term becomes 0, and the formula reduces to the following: Var(aX+bY) = a²Var(X) + b²Var(Y)Therefore, the variance of the sum or difference of two random variables is the sum of their variances. The standard deviation is the square root of the variance. Hence,σ(aX+bY) = sqrt(a²Var(X) + b²Var(Y))

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Answer:

58°

Step-by-step explanation:

Answer:

18, 20, 20, 22, 24, 26, 30

Step-by-step explanation:

We know that the largest number of the list is 30 and the smallest number is 12 less than that, which is 30 - 12 = 18.

This is our list so far: 18, __ , __ , __ , __ , __ , 30

The median of a set is the middle number of the set. In this case, since there are 7 terms in the set, the median, which the problem states is 22, must be the 4th number, since the 4th number is in the middle.

This is our list now: 18, __ , __ , 22, __ , __ , 30

Now, let's deal with the mode. The mode of a set is the term that shows up the most. Since the set is in ascending order and 20 < 22, we know that the two numbers in between 18 and 22 must be 20 and 20. This means that no term can show up more than once, with the exception of 20 because it is the mode.

This is our list now: 18, 20, 20, 22, __ , __ , 30

Finally, we'll deal with the last two numbers. We know that they must be even and that they both must be in between 22 and 30 (since the set is in ascending order). We also know that the two numbers must be different (see last paragraph) and that they sum to 50. The only two numbers that satisfy all of these conditions are 24 and 26, so they must be our last two numbers.

Therefore, the answer is 18, 20, 20, 22, 24, 26, 30. Hope this helps!

1)The pdf of U is f(u) = (1/(2√u)) exp(-u/2) for u > 0 and f(u) = 0 otherwise.

2)U follows a gamma-distribution with parameter a = 3/2 or a = 1/2.

3)x = (y²/2) and dx = y dy using exponential distribution

We can rewrite the integral as:

I(1/2) = ∫₀^∞ y exp(-y²) dy

       = 1/2 ∫₀^∞ exp(-u/2) du

This is the same as the integral for f(u) when u = 1/2.

Therefore, we have:

I(1/2) = V1

(1) For U = Z², we can use the method of transformations.

Let g(z) be the transformation function such that

U = g(Z)

   = Z².

Then, the inverse function of g is given by h(u) = ±√u.

Thus, we can apply the transformation theorem as follows:

f(u) = |h'(u)| g(h(u)) f(u)

     = |1/(2√u)| exp(-u/2) for u > 0 f(u) = 0 otherwise

Therefore, the pdf of U is given by:

f(u) = (1/(2√u)) exp(-u/2) for u > 0 and f(u) = 0 otherwise.

(2) We are given that f(1/2) = VT, where V is a constant.

We can substitute u = 1/2 in the pdf of U and equate it to VT.

Then, we get:VT = (1/(2√(1/2))) exp(-1/4)VT

                            = √2 exp(-1/4)

This gives us the value of V.

Now, we can use the pdf of the gamma distribution to find the parameter a such that the gamma distribution matches the pdf of U.

The pdf of the gamma distribution is given by:

f(u) = (u^(a-1) exp(-u)/Γ(a)) for u > 0 where Γ(a) is the gamma function.

We can use the following relation between the gamma and the factorial function to simplify the expression for the gamma function:

Γ(a) = (a-1)!

Thus, we can rewrite the pdf of the gamma distribution as:

f(u) = (u^(a-1) exp(-u)/(a-1)!) for u > 0

We can now equate the pdf of U to the pdf of the gamma distribution and solve for a.

Then, we get:

(1/(2√u)) exp(-u/2) = (u^(a-1) exp(-u)/(a-1)!) for u > 0 a = 3/2

Therefore, U follows a gamma distribution with parameter

a = 3/2 or equivalently,

a = 1/2.

(3) We need to show that I(1/2) = V1.

Here, I(1) = ∫₀^∞ exp(-x) dx is the integral of the exponential distribution with rate parameter 1 and V is a constant.

We can use the change of variables y = √(2x) to simplify the expression for I(1/2) as follows:

I(1/2) = ∫₀^∞ exp(-√(2x)) dx

Now, we can substitute y²/2 = x to obtain:

x = (y²/2) and

dx = y dy

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Answer:  its 2

Step-by-step explanation:

14 can only = 1 x 14

                  & 2 x 7

Based on the table, a possible taxable income for a taxpayer that's filing with the Single filing status in the 33% federal income tax bracket is $300,000.

Taxation is the involuntary fees that are levied on individuals or business firms by the government of a particular country, so as to generate revenues that can be used to fund public projects, institutions and activities.

In this scenario, we can infer and logically deduce that a possible taxable income for a taxpayer that is filing with the Single filing status in the 33% federal income tax bracket is $300,000.

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Answer:

x > -4

Step-by-step explanation:

Answer:

x is greater than -2

Step-by-step explanation: