An object is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the horizontal. (Given gravity g =9.8 , sin 25° = 0.42 and cos 25° =0.91) What is the maximum height reached by the object at B?​

Answer:

C

Explanation:

Use formable metal flashing:

Answer:

stainless steel

Explanation:

Flashing can be made from many different materials, including metal (copper, aluminum, stainless steel, lead, etc.)

Answer:

you should change that name

A car would be easier to push than a bus. The primary reason for this is the difference in mass and weight between the two vehicles. A bus would be harder to stop compared to a car. This is due to the same reason of mass and weight. The greater the mass and weight of an object, the more force is required to change its state of motion (e.g., push or stop it).

Generally speaking, a car would be easier to push than a bus. The primary reason for this is the difference in mass and weight between the two vehicles. Buses are considerably larger and heavier than cars, meaning they have greater inertia and resistance to motion. Inertia is a property of matter that describes an object's tendency to resist changes in its state of motion. The greater the mass of an object, the greater its inertia. On the other hand, a bus would be harder to stop compared to a car. This is due to the same reason of mass and weight. Buses have more momentum due to their larger mass, and stopping a vehicle with more momentum requires greater force and distance. Additionally, buses typically have larger and more powerful braking systems to handle their increased weight and inertia. Based on this example, we can formulate a general principle: The greater the mass and weight of an object, the more force is required to change its state of motion (e.g., push or stop it). This principle highlights the importance of considering mass and weight when analyzing the motion and dynamics of objects.

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Explanation:

Answer:

ω, the angular frequency of the source equals 377 rad/s

Explanation:

From the question, V(t) = V cosωt.

Now, ω = the angular frequency of the sinusoidal wave is given by

ω = 2πf where f = the frequency of the source = 60 Hz

So, the angular frequency of the source ,ω = 2π × the frequency of the source.

So, ω = 2πf

ω = 2π × 60 Hz

ω = 120π rad/s

ω = 376.99 rad/s

ω ≅ 377 rad/s

So, ω, the angular frequency of the source equals 377 rad/s

Sound waves travel through the air and can be blocked by walls. When a sound wave passes through a wall, the wall absorbs some of the sound energy, resulting in the higher-pitched sound waves being blocked more than lower-pitched sound waves.

This is because higher-pitched sound waves have shorter wavelengths, making them more susceptible to being blocked than lower-pitched sound waves, which have longer wavelengths.

This phenomenon is known as wave-particle duality, which states that sound waves have both particle-like and wave-like properties. The particle-like property of higher-pitched sound waves makes them more susceptible to being blocked by walls than lower-pitched sound waves. This is why you can hear lower-pitched sounds more clearly when they pass through a wall.

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To determine the amount of work required to pull a car a distance of 35 feet with a force of 2500 pounds at an angle of 50° with the horizontal, we need to calculate the work done by the applied force. The work done can be determined by multiplying the magnitude of the force by the displacement of the car in the direction of the force.

The work done (W) is given by the formula W = F * d * cos(theta), where F is the magnitude of the force, d is the displacement, and theta is the angle between the force and the direction of the displacement.

In this case, the magnitude of the force is 2500 pounds, and the displacement is 35 feet. The angle between the force and the direction of displacement is 50°.

To calculate the work done, we first need to convert the force and displacement to the same unit system. Converting 2500 pounds to the corresponding unit in feet (lb-ft) and using the cosine of 50°, we can then compute the work done by multiplying the force, displacement, and cosine of the angle.

By substituting the given values into the formula, we can calculate the work done to pull the car 35 feet. The result will be rounded to the nearest hundredth.  

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Answer:

Distance, S = 13m

Explanation:

Given the following data;

Initial velocity, u = 4m/s

Final velocity, v = 9m/s

Time, t = 2 seconds

To find the distance, S;

First of all, we would determine the acceleration of the shark.

Acceleration = (v - u)/t

Acceleration = (9 - 4)/2

Acceleration = 5/2

Acceleration = 2.5m/s²

Now, to find the distance we would use the second equation of motion

S = ut + ½at²

Substituting into the equation, we have

S = 4(2) + ½*2.5*2²

S = 8 + 1.25*4

S = 8 + 5

Distance, S = 13m

Answer:

The correct answers are:

C)The magnitude of angular momentum of centre of mass of the assembly about point O is 81ma²w.

D)The centre of mass of the assembly rotates about the z axis with an angular speed of w/5 .​

Explanation:

Let the angle of axis with horizontal be θ.

cosθ = \(\frac{I}{\sqrt{l^{2} + a^{2} } } = \frac{\sqrt{24} }{5}\)

Velocity of point P (center of lower disk) aω=lΩ

Then Ω= \(\frac{aw}{1}\)

Angular velocity of C.M. w.r.t z axis =Ωcosθ

\(^{w}cm_{-z} = \frac{aw}{1} \frac{\sqrt{24} }{5} = \frac{w}{5}\)

\(L_{D} -cm \frac{ma^{2} }{2} w + \frac{4m(2a^{2}) }{2} w = \frac{17ma^{2}w }{2}\)

Thus the answer to your problem is, C and D.

The correct statements are:

A) The magnitude of the z component of L is 55ma².

B) The magnitude of the angular momentum of the assembly about its centre of mass is 17ma²/2.

What is Radii?

The plural of radius. It refers to the distance from the center of a circle or sphere to its edge. In other words, it is the length of a line segment that connects the center of a circle or sphere to any point on its circumference or surface, respectively.

The angular momentum of the assembly about point O is the sum of the angular momentum of each disc about point O. The discs are spinning about their own axes and are also revolving around point O. The z component of the angular momentum is given by Lz = Iω, where I is the moment of inertia of the disc about its own axis and ω is the angular velocity of the disc. The z component of the angular momentum of the smaller disc is (1/2)ma²(2ω), and that of the larger disc is (1/2)(4m)(2a)²(ω/2a) = 8ma²ω/4a = 2ma²ω. Therefore, the total z component of the angular momentum is 2ma²ω + (1/2)ma²(2ω) = 5ma²ω = 55ma², since ω = 11.

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The approximate value of the added resistance is 1566.67 Ω.

Let's call the value of the added resistance R. When a resistance is added in parallel, the equivalent resistance is given by:

1/Req = 1/R1 + 1/R2

where Req is the equivalent resistance, R1 is the original resistance, and R2 is the added resistance.

In this case, we know that the original resistance is 470 Ω and the equivalent resistance is 330 Ω. We can plug these values into the formula and solve for the added resistance:

1/Req = 1/R1 + 1/R2

1/330 = 1/470 + 1/R

R = 1566.67 Ω (rounded to two decimal places)

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The final temperature of the water at the given conditions is 2 ⁰C.

The given parameters:

Apply the principle of conservation of energy to determine the final temperature of the water as follows;

\(Q _{cold} = Q _{warm}\\\\mc (t_i - t_f) = mc (t_f - t_i)\\\\mc(1- 0) = mc(t_f - 1)\\\\1 = t_f - 1\\\\t_f = 1+1 \\\\t_f = 2 \ ^0C\)

Thus, the final temperature of the water at the given conditions is 2 ⁰C.

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How do you write a letter to the editor?

Open the letter with a simple salutation. ...

Grab the reader's attention. ...

Explain what the letter is about at the start. ...

Explain why the issue is important. ...

Give evidence for any praise or criticism. ...

State your opinion about what should be done. ...

Keep it brief. ...

Sign the letter.

In this problem all the kinetic energy of the bullet is converted to potential 308.25∼308m/s.

Using the conservation of momentum

Therefore we have

By substitution to find the speed of the bullet

v= m bm b+m d

​2gh=0.012.01

2(9.8)(0.12)

​ =308.25∼308m/s.

Ballistic pendulum, a tool for determining a projectile's velocity, such as a bullet's. The pendulum bob is a large wooden block hung by two ropes. A bullet's momentum is transferred to the bob when it is shot into it. The pendulum swing's amplitude may be used to calculate the momentum of the bullet.

In this experiment, a ball shot from a spring pistol will have its velocity measured. Police laboratories have been measuring the muzzle velocities of weapons using ballistic pendulums for many years. Large block hanging by ropes made up the ballistic pendulum.

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Now use the simulator to find the value of mercury's greatest elongation be setting the observed planet back to mercury. greatest elongation of mercury (just the angle, no direction): 20.7 degrees.

The greatest elongation of Mercury is the largest angular separation between Mercury and the Sun as observed from the Earth. Greatest elongation can be determined by using a simulator that allows you to set viewing perspectives to position a planet in its actual observed location, and then projecting it back to the point where it would appear at its greatest distance from the Sun.

By doing this, an observer can accurately determine the angle of greatest elongation for Mercury. This angle is calculated relative to the Sun, and is measured by comparing the current ecliptic longitude of Mercury with the ecliptic longitude of Mercury when it is at its greatest elongation from the Sun. The angle of greatest elongation for Mercury is 27 degrees.

Using a simulator to calculate the angle of greatest elongation for a planet like Mercury is a helpful tool for astronomers who need to accurately measure the distance between these objects.

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The energy transformations in a projectile launcher involve the conversion of potential energy stored in the spring into kinetic energy of the ball, which is then transformed into other forms of energy as the ball moves through the air and interacts with other objects.

When a projectile launcher uses a spring to launch a ball, there are several energy transformations that occur:

1.Potential energy is stored in the spring as it is compressed. The amount of potential energy stored is given by the equation PE = (1/2) k x², where k is the spring constant and x is the distance that the spring is compressed.

2.When the spring is released, the potential energy is transformed into kinetic energy as the spring expands and pushes the ball forward. The kinetic energy of the ball is given by the equation KE = (1/2) m v², where m is the mass of the ball and v is its velocity.

3.As the ball travels through the air, it loses some of its kinetic energy due to air resistance, which is a form of non-conservative force. This energy is transformed into heat and sound energy.

4.When the ball hits a surface, some of its kinetic energy is transferred to the surface, causing it to deform or move. The remaining kinetic energy of the ball is transformed into other forms of energy, such as heat and sound energy.

Overall, the energy transformations in a projectile launcher involve the conversion of potential energy stored in the spring into kinetic energy of the ball, which is then transformed into other forms of energy as the ball moves through the air and interacts with other objects.

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The following are the different types (modes) of heat transfer:ConductionHeat conduction (or thermal conduction) is the process of transferring heat between objects in contact with each other. It occurs when heat flows from an object with a higher temperature to an object with a lower temperature.

This can be represented by the following equation:Q = kA (T2 - T1)/L

where,

Q is the heat transferred,

k is the thermal conductivity of the material,

A is the surface area of the object,

T1 and T2 are the temperatures of the two objects,

L is the distance between them.

ConvectionHeat convection (or thermal convection) is the transfer of heat between a surface and a fluid (such as air or water) that is in motion. It occurs when the fluid carries heat away from the surface and replaces it with cooler fluid. This can be represented by the following equation:Q = hA (T2 - T1)where Q is the heat transferred, h is the heat transfer coefficient, A is the surface area of the object, T1 and T2 are the temperatures of the two objects, and L is the distance between them.RadiationHeat radiation (or thermal radiation) is the transfer of heat between two objects without any contact or movement between them. It occurs when objects emit electromagnetic waves that are absorbed by other objects. This can be represented by the following equation:Q = εσA (T2^4 - T1^4)where Q is the heat transferred, ε is the emissivity of the material, σ is the Stefan-Boltzmann constant, A is the surface area of the object, and T1 and T2 are the temperatures of the two objects.

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Answer:

20 yards East

Explanation:

The question states he starts at the 50 yard line, and didn't imply that he'd ran for 50 yards already. Effectively, that said 50 yard would not count.

The question proceeded to saying he ran leftwards for 20 yards. This is the distance, or displacement that we would use as the first measurement. Running 20 yards in the Eastern direction.

The question then proceeded again, to saying he ran rightwards for another 40 yard. By so doing, he eclipsed the initial 20 yards he'd ran. And added few more yards..

40 - 20 = 20, meaning, he ran 20 more yards in the rightward direction.

Therefore, his displacement would be 20 yards to his right or say, Eastern direction.

The magnitude of reaction at the beam due to the distributed load of 25 kN/m is 625 N.

The magnitude of reaction at the beam can be determined by calculating the total force exerted by the distributed load. In this case, the distributed load is given as 25 kN/m. To find the magnitude of reaction, we multiply the distributed load by the length of the beam.

Therefore, the magnitude of reaction is 25 kN/m multiplied by the length of the beam in meters. By performing the calculation, we obtain the value of 625 N as the magnitude of reaction at the beam due to the distributed load. This represents the total force exerted by the distributed load on the beam.

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Answer:

True

Explanation:

The energy carried by a wave is proportional to its amplitude squared. The larger the strength of the electric and magnetic fields, the more work they can do and the greater the energy the electromagnetic wave carries. A wave's energy is proportional to its amplitude squared (E2 or B2).

The Earth's outermost layer is the crust and the brittle upper part of the mantle, are together known to as the lithosphere. The asthenosphere below and the atmosphere above it define its boundaries.

Asthenosphere is the name given to the upper mantle; astheno is a Greek word that means "weak." Because of its liquid state, where rock material deforms more easily and magma production occurs, the weak layer is so named.

Any fluid, including boiling water, soup (where the cells may be recognized by the particles they transport, like as rice grains), the ocean, or the surface of the Sun, can produce convection cells, also known as Hadley cells.

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Answer:

x = 3.6 10⁷ m

Explanation:

The speed of an electromagnetic wave is constant, in a vacuum its value is    c = 3 10⁸ m / s, this speed decreases when entering a material medium,

         v = c / n

where n is the refractive index, but in this case the refractive index of air is n = 1.00002. The refractive index of a vacuum is n = 1, so we can assume that the change in velocity is negligible.

For the calculation we can use the relations of the uniform motion

        v = x / t

        x = v t

let's calculate

        x = 3 10⁸ 0.12

        x = 3.6 10⁷ m

Answer:

the warm air rises, cools and condenses to form clouds

c) both direct and alternating current

Because Ampere's Law, a magnetic field is produced whenever an electrical charge is in motion. So, both kind of currents produces a magnetic field when electrical current is flowing through a wire.

Managers do the crucial duty of controlling when they create precise measuring and monitoring methods to assess how well the firm has achieved its goals.

Software that assists system administrators in monitoring their infrastructure is known as a monitoring system. These tools keep an eye on the hardware, software, and traffic of the system and raise the alarm in the event of errors or disturbances. There are several monitoring systems available, ranging from commercial software to freeware.

The monitoring system broadcasts a signal and logs information about the signal, including whether it was received, how long it took the host to receive it, whether any signal data was lost, and other details.

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Answer:

Force = mass × acceleration

Acceleration:

\({ \tt{15 = (22 \times a)}} \\ { \tt{a = \frac{15}{22} \: {ms}^{ - 2} }}\)

From first Newton's equation of motion:

\({ \bf{v = u + at}} \)

Change = v - u:

\({ \tt{v - u = (a \times t)}} \\ { \tt{v - u = ( \frac{15}{22} \times 1.2) }} \\ { \tt{v - u = 0.82 \: {ms}^{ - 2} }}\)

The fatal flaw in Copernicus' heliocentric model was his assumption that the planets move in perfectly circular orbits around the Sun. Copernicus proposed that the planets move in circular paths called epicycles, which were themselves moving along larger circles around the Sun.

The fatal flaw in Copernicus' heliocentric model was his assumption that the planets move in perfectly circular orbits around the Sun. However, in reality, the planets do not move in perfect circles but rather in elliptical orbits around the Sun. This elliptical shape of planetary orbits was later described by Johannes Kepler's laws of planetary motion. Copernicus' reliance on circular orbits led to inaccuracies in predicting the exact positions of the planets.

Additionally, Copernicus' model still retained some elements of the geocentric model, such as the assumption that the planets move at a uniform speed throughout their orbits. However, Kepler's laws later demonstrated that the planets actually move at varying speeds, with their orbital velocities changing as they move closer to or farther away from the Sun.

These inaccuracies in the assumed circular orbits and uniform speeds of the planets in Copernicus' model prevented it from accurately predicting the observed positions of the planets. It wasn't until Kepler's laws and the adoption of elliptical orbits that a more precise model of the solar system was developed.

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False, center of gravity and center of mass is not always the same.

Center of gravity is a point from which the weight of a body or system may be considered to act.

This is the point of concetration of the mass of the object with respect to a frame of reference.

Thus, we can conclude that center of gravity and center of mass is not always the same.

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Answer:

Explanation:

 Investigators  thought this meant that oxygen was eight times more massive than hydrogen. They presumed the  chem-ical form-ula for water to be H-O

Hope this helped!!!  .