An object is placed in front of a diverging lens with a focal length of 10 cm at a distance of 30 cm, producing an image distance of 15 cm. How strongly an optical system converges is determined by the focal length.
It is the optical power of the system's inverse. A system's light converges when the focal length is positive, while it diverges when the focal length is negative.
The definition of a diverging lens is a lens that is thick in the middle and thin on the edges. Because it causes the light beam that strikes it to condense, a convex lens is also known as a diverging lens .
Where u = 30.0 cm and f = 10.0 cm, the equation is 1/v - 1/u = 1/f.
Solve for v :
1/v = 1/f + 1/u
1/v = 1/(10.0 cm) - 1/(30.0 cm)
1/v = 0.0666 cm^-1
v = 1/0.666cm^-1
v = 15.0cm
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Light from an atomic hydrogen source is incident on a diffraction grating with 600 lines /mm. What is the second-order diffraction angle for the emission line at 656.5 nm?
a) 86.1o
b) 0.040
c) 6.6o
d) 23.2o
e) 52.0o
The second-order diffraction angle for the emission line at 656.5 nm is 52°.
The diffraction grating equation relates the wavelength of light to the angle at which the light is diffracted by the grating. The equation is given by:
nλ = d sin(θ)
where,
d = spacing between the lines on the grating,
θ = diffraction angle,
n = order of diffraction, and
λ = wavelength of the light.
In this problem, the diffraction grating has a spacing of,
d = 1/600 mm
= 1.67 × 10⁻⁶ m.
Converting the wavelength to meters, we get:
λ = 656.5 nm
= 656.5 × 10⁻⁹ m
Now,
Substituting the values into the diffraction grating equation for the second-order diffraction i.e., n = 2, we get:
2 × (656.5 × 10⁻⁹ m) = 1.67 × 10⁻⁶ m {sin(θ)}
Simplifying and solving for the diffraction angle, we get:
sin(θ) = (2 * 656.5 × 10⁻⁹ m) / (1.67 × 10⁻⁶ mm)
∴ θ = sin⁻¹ [(2 * 656.5 × 10⁻⁹ m) / (1.67 × 10⁻⁶ mm)]
θ ≈ 52°
Therefore, the second-order diffraction angle for the emission line at 656.5 nm is 52°.
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Is this right. Please help me ITS SOCIOLOGY
Answer:
Yes
Explanation:
sorry if im wrong
One mole of titanium contains how many atoms?
O A. 60.2 x 1024
O B. 6.02 x 10-23
O C. 1.0
O D. 6.02 x 1023
SUBMIT
Answer:
\(\boxed {\boxed {\sf D. \ 6.02*10^{23} \ atoms}}\)
Explanation:
One mole of a substance contains the same amount of representative particles. These particles can be atoms, molecules, ions, or formula units. In this case, the particles are atoms of titanium.
Regardless of the particles, there will always be 6.02*10²³ (also known as Avogadro's Number) particles in one mole of a substance.
Therefore, the best answer for 1 mole of titanium is D. 6.02*10²³ atoms.
Answer:
D) 6.02 x 1023
Explanation:
A.P.E.X
A 0.230-kg baseball is thrown with a speed of 41 m/s.What is the ball's momentum?
The momentum of the 0.230-kg baseball thrown with a speed of 41 m/s is 9.53 kg m/s. This means that if the ball were to collide with an object with equal and opposite momentum, the combined momentum of the two objects would be zero.
Momentum is a measure of an object's motion and is calculated by multiplying its mass and velocity. In physics, it is an important concept as it is conserved in many cases and helps to predict how objects will interact with each other.
The momentum of an object can be calculated using the formula: p = mv, where p is momentum, m is the mass of the object, and v is its velocity. In this case, the mass of the baseball is 0.230 kg, and its velocity is 41 m/s. Therefore, the momentum of the baseball can be calculated as follows:
p = mv = 0.230 kg * 41 m/s = 9.53 kg m/s.
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What is the life cycle of our sun?
Answer:
the sun is currently a mian sequence star
and will remain so for another 4-5 billion
A radar antenna is rotating and makes one revolution every 29 s, as measured on earth. However, instruments on a spaceship moving with respect to the earth at a speed v measure that the antenna makes one revolution every 46 s. What is the ratio v/c of the speed v to the speed c of light in a vacuum
The ratio v/c of the speed v to the speed of light c in a vacuum, given that the radar antenna makes one revolution every 29 seconds on Earth and one revolution every 46 seconds on a spaceship is 0.6.
To solve this problem, we need to use the concept of time dilation from special relativity. Time dilation predicts that time appears to run slower for a moving observer relative to a stationary observer.
In this case, the radar antenna appears to make one revolution every 46 s for the moving spaceship, but one revolution every 29 s for the stationary observer on Earth.
We can calculate the ratio of the spaceship's speed v to the speed of light c by using the formula for time dilation:
t' = t / √(1 - v²/c²)
where t is the time measured by the stationary observer on Earth, t' is the time measured by the moving observer on the spaceship, and v is the speed of the spaceship.
Setting t = 29 s and t' = 46 s, we get:
46 = 29 / sqrt(1 - v²/c²)
Solving for v/c, we get:
v/c = √(1 - (29/46)²) = 0.6
Therefore, the ratio of the spaceship's speed v to the speed of light c is 0.6.
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a piano wire with mass 3.45 gg and length 80.0 cmcm is stretched with a tension of 30.0 nn. a wave with frequency 120 hzhz and amplitude 1.60 mmmm travels along the wire.
The average power carried by the wave is 0.262. When amplitude is halved, the average power decreases by 4 to 0.065W.
a) The averaged power of a wave on a string is given by Pavg = 1/2 (√(µF)) A^2 w^2
According to the given data,
Mass of piano wire m = 3g = 0.00345kg
Length of piano wire l = 80cm = 0.8m
Tension F = 30 N
Frequency f = 120 Hz
Amplitude A = 1.6mm = 0.0016m
Angular frequency ω = 2πf = 2π (120) = 240π s^-1
Linear mass density μ = m/l = 0.00345/0.8 = 0.00431 kg/m
Hence,
Pavg = 1/2 (√(0.00431*30)) 〖0.0016〗^2 〖(240π)〗^2
Pavg = 0.262W
b) As the average power is always proportional to the square of amplitude, hence
Pavg1/Pavg2 = (A1/A2)^2
0.262/Pavg2 = (0.0016/0.0008)^2
0.262/Pavg2 = 4
Pavg2 = 0.065W
Note: The question is incomplete. The complete question probably is: A piano wire with mass 3.45g and length 80.0 cm is stretched with a tension of 30.0 N. A wave with frequency 120.0 Hz and amplitude 1.6 mm travels along the wire. (a) Calculate the average power carried by the wave. (b) What happens to the average power if the wave amplitude is halved.
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Hey!!
I need help in a question...
• Different types of fuels and the amount of pollutants they release.
Please help me with the question.
Thankss
Answer: Different types of fuels have varying compositions and release different amounts of pollutants when burned. Here are some common types of fuels and the pollutants associated with them:
Fossil Fuels:
a. Coal: When burned, coal releases pollutants such as carbon dioxide (CO2), sulfur dioxide (SO2), nitrogen oxides (NOx), and particulate matter (PM).
b. Petroleum (Oil): Burning petroleum-based fuels like gasoline and diesel produces CO2, SO2, NOx, volatile organic compounds (VOCs), and PM.
Natural Gas:
Natural gas, which primarily consists of methane (CH4), is considered a cleaner-burning fuel compared to coal and oil. It releases lower amounts of CO2, SO2, NOx, VOCs, and PM.
Biofuels:
Biofuels are derived from renewable sources such as plants and agricultural waste. Their environmental impact depends on the specific type of biofuel. For example:
a. Ethanol: Produced from crops like corn or sugarcane, burning ethanol emits CO2 but generally releases fewer pollutants than fossil fuels.
b. Biodiesel: Made from vegetable oils or animal fats, biodiesel produces lower levels of CO2, SO2, and PM compared to petroleum-based diesel.
Renewable Energy Sources:
Renewable energy sources like solar, wind, and hydropower do not produce pollutants during electricity generation. However, the manufacturing, installation, and maintenance of renewable energy infrastructure can have environmental impacts.
It's important to note that the environmental impact of a fuel also depends on factors such as combustion technology, fuel efficiency, and emission control measures. Additionally, advancements in clean technologies and the use of emission controls can help mitigate the environmental impact of burning fuels.
A wave along a guitar string has a frequency of 440 hz and the wavelength of 1. 25m. What is the speed of the wave?
Answer:
550 m/s
Explanation:
Speed of wave = wl * f wl = 1,25 m f = 440 Hz (given)
1.25 m * 440 = 550 m/s
An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 201 m/s2 . What is the direction of the electric field
The force on a charge in an electric field is E = 1*10^-9 N/C.
F = QE
and according to newton's second law, the acceleration the charge will undergo is :
a = F / m
Putting these two equations together we get
E = m/q
For an electron with mass m= 9.11*10^-31 kg and charge Q= 1.60*10^-19 C.
E = 9.11*10^-31 kg / 1.60*10^-19 C
E = 1*10^-9 N/C.
Electric discipline, electric-powered assets associated with each point in space when the price is present in any form. The magnitude and direction of the electrical subject are expressed with the aid of the value of E, called electric area power or electric powered discipline intensity or certainly the electrical area.
An electric-powered discipline is a place of the area around an electrically charged particle or objects wherein an electric charge might feel pressure. An electric-powered field is a vector amount and can be visualized as arrows going towards or far from expenses.
Examples of electric fields consist of the field produced in the dielectric of a parallel-plate capacitor (which creates an electrostatic discipline) and the electromagnetic wave produced by a radio broadcast monopole antenna (which creates a time-various area)
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The first spacecraft which did not merely fly bya jovian (or giant) planet, but actually went into orbit around it for an extended period of time was
a. Galileo
b. Einstein
c. Voyager
d. the Hubble Space Telescope
e. Cassini
Answer:The first spacecraft which did not merely fly by a jovian (or giant) planet, but actually went into orbit around it for an extended period of time was option a, Galileo. The Galileo spacecraft was launched in 1989 and orbited Jupiter for almost eight years, from 1995 to 2003.
Explanation:
Please help ASAP!
If you were to push a brick wall with 100 N of force, how much force would the wall push back towards you?
Answer:
100 newton
Explanation:
newton third law of motion says to every action there is an always an equal and opposite reaction so the magnitude will stay equal but opposite direction
Answer:
- 100N is the answer of this question
A 12kg object experiences a net force of 120 N. What is the acceleration will this object experience?
Answer:
a = 10m/s^2
Explanation:
Recall that F=ma, therefore, to find acceleration, we need to rearange the equation in such a manner that it would equal acceleration:
\(F=ma\\\frac{F}{m} =a\\\\\frac{120N}{12kg}=a\\10m/s^2=a\)
A box is sliding with a speed of 4.50 m/s on a horizontal surface when, at point P, it encounters a rough section. On the rough section, the coefficient of friction is not constant, but starts at 0.100 at P and increases linearly with distance past P, reaching a value of 0.600 at 12.5 m past point P.1)Use the work-energy theorem to find how far this box slides before stopping.2)What is the coefficient of friction at the stopping point?3)How far would the box have slid if the friction coefficient didn't increase, but instead had the constant value of 0.100?
1) The box slides 23.6 m before stopping.
2) The coefficient of friction is 0.600.
3) If the friction coefficient had a constant value of 0.100, then the box would have slid a distance of 12.5 m
1)Using the work-energy theorem, we can find how far the box slides before it stops. The theorem states that the work done by all forces acting on the object is equal to the change in its kinetic energy, or:
W = ΔKE
Where W is the work done by all forces, and ΔKE is the change in kinetic energy. Since the work done by all forces is equal to the friction force, the work done by friction is equal to the change in kinetic energy. Therefore, the equation can be rewritten as:
Wfriction = ΔKE
In this situation, the friction force increases linearly with distance, so the work done by friction (Wfriction) is the integral of the friction force over the distance. The integral is equal to the area under the graph of friction force versus distance. Therefore, the equation can be rewritten as:
∫Ffriction(x)dx = ΔKE
The integral is equal to the area under the graph of friction force versus distance from 0 to the stopping point. Since the coefficient of friction increases linearly from 0.100 at P to 0.600 at 12.5 m past point P, we can calculate the stopping point using the equation:
0.100x + 0.500(x-12.5) = ΔKE
Solving the equation for x, we find that the box stops at x = 23.6 m.
2)At the stopping point, the coefficient of friction is 0.600.
3) This is because the integral of the friction force with a constant coefficient of 0.100 is equal to 0.100x, where x is the distance traveled.
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The half-life of iodine-131 is 8.07 days. If 0.25 g are left after 40.35 days, how many gramswere in the original sample?
Given data
*The half-life of iodine-131 is t = 8.07 days
*The amount of quantity left is N = 0.25 g
*The number of days is T = 40.35 days
The expression for the radioactivity decay is given as
\(N=N_0(\frac{1}{2})^{\frac{T}{t}}\)Substitute the values in the above expression as
\(\begin{gathered} \text{0}.25=N_0(\frac{1}{2})^{\frac{40.35}{8.07}} \\ N_0=8\text{ g} \end{gathered}\)Answer:
See below
Explanation:
40.35 days / (8.07 day per half life) = 5 half lives
.25 = x ( 1/2)^5
.25 / ( 1/2)^5 = x = 8 gm originally
A boy pulls a wovon with a force or 6 Neast as another boy pushes it
with a force of 4 N east. What is the net force?
Answer:
The net force is 10 N.
Explanation:
A "net force" occurs when a particular object accelerates. It refers to the total number of forces that act on an object.
The boy pulling the cart and the other pushing it do their actions in the same direction. The force of pulling is 6 N while the force of pushing is 4 N. This means that the total force will not be cancelled.
To get the net force, add both forces since they are in the same direction (east).
Net force = 6 N + 4 N
Net force = 10 N (Newtons)
Ke Min is driving at 23 m/s in a 1200-kg car. He sees a tree branch lying across the road. He slams on the brakes when the branch is 60.0 m in front of him. If the coefficient of kinetic friction between the car’s locked tires and the road is 0.41, how much distance is required for the car to come to a stop?
Answer:
x = 65.82877053 m
Explanation:
Fnet = -F f = ma
-μ Fnorm = ma
(-μ) mg = ma
(-μ) (g) = a
\(a = -(mu) g = -(0.41)(9.80 m/s^2) = -4.018 m/s^2\\\\v^2 = vinitial^2 + 2ax\\x = \frac{v^2 - vinitial^2}{2a} = \frac{0 - (23m/s)^2}{2(-4.018 m/s^2}\\x = 65.82877053 m\)
The distance required to stop by car is 65.96 m.
Given data:
The initial speed of Ke Min is, u = 23 m/s.
The mass of car is, m = 1200 kg.
The distance between the branch and Ke Min is, d = 60.0 m.
The coefficient of kinetic friction between the car’s locked tires and the road is, \(\mu =0.41\).
Here in the given problem, the frictional force will oppose the motion of the car. So, the linear force causing the acceleration is,
F = f
\(ma = -\mu \times m \times g\\\\a = -\mu \times g\\\\a = -0.41 \times 9.8\\\\a =-4.01 \;\rm m/s^{2}\)
Now, apply the third kinematic equation of motion to obtain the stopping distance (s) as,
\(v^{2} = u^{2} +2as\\\\0^{2} = 23^{2} +2(-4.01)s\\\\s = \dfrac{529}{8.02}\\\\s =65.96 \;\rm m\)
Thus, we can conclude that the distance required to stop by car is 65.96 m.
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Please help if you have the time
A string is stretched between fixed supports 2.0 meters apart. When set in transverse vibration at a frequency of 120 Hz the string vibrates in four segments, as shown. What is the wave speed in the string?
We know, length of segment wave is half the wavelength .
Let, wavelength of wave is \(\lambda\).
So, length of segment will be \(\dfrac{\lambda}{2}\) .
Now, it is given that the string vibrates in four segments.
So,
\(L = 4\times \dfrac{\lambda}{2}\\\\L = 2\lambda\\\\\lambda = 1\ m\)
Speed can be given by :
\(speed = wavelength \times frequency\\\\speed = 1\times 120\ m/s\\\\speed = 120\ m/s\)
Therefore, the wave speed in the string is 120 m/s.
‼️‼️EMERGENCY ITS DUE SOON‼️‼️
A box weighing 2000N is sliding across a cement floor. The force pushing the box is 500N, and the coefficient of sliding friction between the box and the floor is 0.20. What is the acceleration of the box? 
Answer:
1.96m/s^2
Explanation:
According to Newtons second law;
F = ma
a = F/m
a = nR/m
a = nmg/m
a = ng
n is he coefficient of friction = 0.2
g = 9.8m/s^2
a = 0.2 * 9.8
a = 1.96m/s^2
Hence the acceleration of the box is 1.96m/s^2
Deanna and Kelly were lifting weights. Kelly was easily doing the exercise and she didn't feel like the exercise was very intense. Deanna suggested she increase the weight stack amount by 50 percent. Kelly was using 8 pounds initially. What amount should she use based on Deanna's suggestion? (2 points)
if you reverse the poles of battery what will happen to the direction Of the lines?
Answer: The battery casing will explode
Explanation: Hydrogen gas will be released because of the heat which may cause an explosion.
What term is used for the tendency to attribute your own behavior to external causes while attributing the behavior of others to internal causes?
hindsight bias
discrimination bias
self-serving bias
Actor-observer bias
The term used for the tendency to attribute your own behavior to external causes while attributing the behavior of others to internal causes is "self-serving bias."
This bias refers to the common human tendency to take credit for our successes and to blame external factors for our failures, while doing the opposite for others. In other words, we tend to see ourselves in a more positive light than we do others. This bias can be observed in many aspects of life, including work, relationships, and even politics.
For example, if we receive a promotion at work, we might attribute it to our hard work and skills, while if a colleague receives the same promotion, we might attribute it to luck or favoritism. The self-serving bias can lead to misunderstandings, conflicts, and unfair treatment of others, so it's important to be aware of it and to try to overcome it through empathy, perspective-taking, and self-reflection.
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At the time of the founding of the country, most Americans worked as
A.shopkeepers
B.soldiers
C.ship builders
D.farm workers
Answer:
Farmers
Explanation:
At the time of founding our country most soldiers in the revolutionary war were farmers who were inexperienced.
Answer:
D. farm workers
Explanation:
It is because when they started founding the country, people needed food and everything was based on agriculture and economy, and the main economy wat cotton and tobacco.
HELP ME PLEASE WITH MY HOMEWORK ILL GIVE BRAINLIEST
Answer: Mass
Explanation:
The world's longest continuous mountain ridge is under the ocean.
True
False
Please hurry!!!
Answer:
True
Explanation:
11. (a)What downward force is acting on you when you go down a waterslide? (b)What type of friction is
present? (c)If the waterslide were dry explain what type of friction in would be and (d)how that
changes your speed? (4 points)
Answer:
a) "gravitation" is the force causing you to go down a waterslide
b) It is "fluid friction" as a solid object (our body) moves over a fluid (the water)
c) It would become "sliding friction" since two solid surfaces slide over each other
d) fluid friction being the weakest friction, switching to sliding friction means a higher decrease in speed and therefore removing the water from a slide will decrease our speed
What is ∑F2x, the sum of the x components of the forces acting on block 2? Take forces acting up the incline to be positive. Express your answer in terms of some or all of the variables tension T, m2, the magnitude of the acceleration of gravity g, and θ.
The sum of the x components of the forces acting on block 2 is given by the equation ∑F2x = Tcos(θ) - mgsin(θ).
Here, T is the tension, m is the mass of the block, g is the acceleration of gravity, and θ is the angle of the incline.
This equation can be used to calculate the x components of the forces in a variety of situations, such as when the block is being pulled up an incline or when it is in equilibrium. It is important to note that the forces acting on the block must be expressed in terms of their x and y components in order for the equation to be accurate. Additionally, it is important to consider the direction of the forces when calculating the x components, as the sign can have a significant impact on the result.
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Answer:
The answer is T-m2gsin(theta)
Explanation:
An electroscope is a device that detects charge on
What methods of charging does John use?
objects that touch it or are brought near it. John rubs a
piece of cotton fabric on a plastic rod and then louches
John charges the rod through induction, then charges
the rod to the electroscope.
the electroscope through friction.
• John charges the rod through conduction, then
charges the electroscope through induction.
• John charges the rod through friction, then charges
the electroscope through induction.
John charges the rod through friction, then charges
the electroscope through conduction.
John charges the rod through friction, then charges the electroscope through induction.
What is induction charging?A charging technique called induction charging involves charging a thing without actually contacting it to another charged object.
The charged particle is held close to an uncharged conductive substance that is grounded on a neutrally charged material during the charging by induction process. When a charge is transferred between two objects, an uncharged conductive substance produces an oppositely polarized charge.
The rod is firstly charged by friction with the cotton fabric then John charges the rod through induction, then charges the rod to the electroscope.
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The only force acting on a 2.3 kg body as it moves along the positive x axis has an x component Fx = −4×N, where x is in meters. The velocity of the body at x=1.4 m is 9.1 m/s. (a) What is the velocity of the body at x=4.6 m ? (b) At what positive value of x will the body have a velocity of 5.5 m/s ? (a) Number ________________ Units _________________
(b) Number ________________ Units _________________
(a)
The velocity of the body at x = 4.6 m is -2.69 m/s.
Number: -2.69
Units: m/s
(b)
The positive value of x where the body will have a velocity of 5.5 m/s is 9.6 m.
Number: 9.6
Units: m
Mass of the body, m = 2.3 kg
Force acting on the body, Fx = −4 N
Initial velocity of the body, u = 0 m/s
Velocity of the body at x = 1.4 m, v = 9.1 m/s
Let's find the acceleration of the body at x = 1.4 ma
= F/m
= (-4 N)/2.3 kg
= -1.74 m/s²
(a)
Now, let's find the velocity of the body at x = 4.6 m
Final position of the body, x = 4.6 m
Initial position of the body, x = 1.4 m
Distance covered by the body, s = x - u = 4.6 - 1.4 = 3.2 m
Using the second equation of motion,
v² = u² + 2as
v² = 0 + 2 × (-1.74) × 3.2
v = -2.69 m/s
The velocity of the body at x = 4.6 m is -2.69 m/s.
Number: -2.69
Units: m/s
(b)
Now, let's find the positive value of x where the body will have a velocity of 5.5 m/s.
Final velocity of the body, v = 5.5 m/s
Initial velocity of the body, u = 0 m/s
Let the distance covered by the body be s meters.
Using the third equation of motion,v² = u² + 2as
5.5² = 0 + 2a × s
We know, a = -1.74 m/s²
5.5² = 2 × (-1.74) × s
s = 8.2 m
Therefore, the positive value of x where the body will have a velocity of 5.5 m/s is 1.4 + 8.2 = 9.6 m.
Number: 9.6
Units: m
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PLEASE ANSWER WILL MAKE BRAINLIEST IF YOU EXPLAIN HOW YOU GOT THE ANSWER!!!!
An object moving at a constant velocity is in equilibrium.
Explain Newton's first law of motion.A moving object is in equilibrium if it is moving with constant velocity (that is, no acceleration). According to Newton's first law of motion, the net force must be zero. Objects at rest will remain stationary, and objects in motion will continue to move in a straight line at a constant speed unless an unbalanced force acts on them.
Other major factors such as friction therefore do not affect the speed of this moving object. Without acceleration, an object can move and remain in equilibrium.
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