An object is thrown horizontally off a cliff with an initial velocity of 5.0 meters per second. The object strikes the ground 3.0 seconds later. (i) What is the vertical speed of the object as it reaches the ground? a) – 29.4 m/s b) zero. c) 15 m/s.
d) 29.4 m/s
(ii) How far from the base of the cliff will the object strike the ground? a) – 44.1 m/s b) zero. c) 15 m/s. d) 29.4 m/s

In order to answer the question of where the arrows of the magnetic domains point, one must consider the properties of the magnets' poles: A) The arrows line up and point upward.

Iron or cobalt is a common component of permanent magnets. An alloy composed of aluminum is called alnico. Involves a systematic process minerals are capable of making powerful electromagnets. They are widely utilized in industrial and consumer electronics applications.

The word "lithos magnes" from classical Greek is where the name first appeared. According to Pliny's explanation in his "Naturalis Historia," the term is derived from the myth of the Greek shepherd Magnes on Mount Ida, whose iron staff and the nails in his shoes were drawn to the magnetite stones.

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Answer:

POINTS LEFT

Explanation:

just did it

Answer:

a

Explanation:

you take 32,000kg ÷2.0m

The potential difference across the each bulb and the current entering each bulb.

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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The minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

Deceleration is defined as  the decrease in speed as the body moves away from the starting point.

The minimum deceleration required can be calculated using the equation of motion:

d = v^2 / (2 * a)

where d is the distance, v is the initial velocity, and a is the acceleration.

Rearranging the equation to solve for a:

a = v^2 / (2 * d) = (3500 m/s)^2 / (2 * 35 m) = 40000 m/s^2

In conclusion, , the minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

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Answer:

Explanation:

Angle:

β = - 23°

( From the symmetry condition)

Answer: Must have the cross of mass & velocity

Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

Answer:

effort arm mean the use of any work by using your hand force motion or by hand power

Answer: The capacitor is fully charged when the voltage of the power supply is equal to that at the capacitor terminals. This is called capacitor charging; and the charging phase is over when current stops flowing through the electrical circuit.

The distance of your hometown from school is 318.64 km.

Given data

Distance S = 190 km

Speed v = 97 km / h

Now, the time taken to travel S distance is calculated as,

t = S / v

t = 180 / 95

t = 1.958 hrs

Now, the total time is given as

Total time T = 4.0 h

So, remaining time t ' = T - t = 4 hrs - 1.958 hrs = 2.042 hrs

Now, the velocity after travel 190 km is v ' = 63 km/ h

Distance travel in this velocity S ' = v ' t '

= 128.6 km

Now, the distance of your hometown from school , S " = S + S '

= 190 km + 128.6 km = 318.64 km

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Answer:

cook some hamburgers and go fishing

Explanation:

Answer:

go to the baseball game and have fun

Explanation:

The resulting wave has the largest possible amplitude when Wave-1 and Wave-2 are exactly in step ... their peaks both happen at the same time and their troughs both happen at the same time.

This means that Wave-1 and Wave-2 have the same frequency, and the phase shift from one wave to the other is zero.

When all of that happens, the amplitude of the resulting wave is the sum of the amplitudes of Wave-1 and Wave-2.  If Wave-1 and Wave-2 have the same amplitude, then the resulting wave will have double that amplitude.

The correct answer is C. The inner planets are also called terrestrial planets.

Explanation:

Our solar system includes a total of eight planets. Additionally, planets are classified into broad categories including inner planets and outer planets. The inner planets category applies to planets such as Earth, Mercury, or Mars because these are located within the asteroid belt (region of asteroids between Mars and Jupiter). Moreover, inner planets differ from others due to their composition as they are composed of rocks and metals. Also, due to this composition, these are known as terrestrial planets. According to this, the statement that best describes inner planets is "The inner planets are also called terrestrial planets".

Answer:

The answer is c.) The inner planets are also called terrestrial planets.

Explanation:

24 volts is the voltage drop across each of the resistors in the parallel configuration.

When resistors are connected in parallel, they share the same voltage across them. Therefore, the voltage drop across each resistor in this scenario would be the same.

Given:

Power supply voltage (V) = 12 V

Resistance of each resistor (R) = 30 Ω

Since the resistors are in parallel, the total resistance (R_total) can be calculated using the formula:

1/R_total = 1/R1 + 1/R2

Substituting the values:

1/R_total = 1/30 Ω + 1/30 Ω

1/R_total = 2/30 Ω

R_total = 15 Ω

Now, we can find the current flowing through the resistors (I) using Ohm's Law:

I = V / R_total

I = 12 V / 15 Ω

I = 0.8 A

Since the voltage drop across each resistor is the same, we can find it using Ohm's Law:

V_drop = I * R

V_drop = 0.8 A * 30 Ω

V_drop = 24 V

Therefore, the voltage drop across each of the resistors in the parallel configuration is 24 volts.

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To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:

Lenses:

Place an object at different distances to the left of a lens with a focal length (f).

a) Object placed beyond 2f:

In this case, the object is placed far beyond twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.

SALTS:

Size: The image will be smaller than the object.

Attitude: The image will be inverted.

Location: The image will be located between the focal point and twice the focal length.

Type: The image will be real.

b) Object placed at 2f:

In this case, the object is placed at twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens at twice the focal length.

SALTS:

Size: The image will be the same size as the object.

Attitude: The image will be inverted.

Location: The image will be located at twice the focal length.

Type: The image will be real.

c) Object placed between f and 2f:

In this case, the object is placed between the focal point and twice the focal length of the lens.

In this case, the object is placed far beyond twice the focal length of the mirror.

Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.

Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.

Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.

The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.

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The friction of a 5 kg block that is on a table when a 15 N force is exerted on the side of the block, the acceleration is 2 m/s² is 5 N

∑F = m a

F - f = m a

F = Applied force

f = Frictional force

m = Mass

a = Acceleration

F = 15 N

m = 5 kg

a = 2 m / s²

f = F - m a

f = 15 - ( 5 * 2 )

f = 15 - 10

f = 5 N

Frictional force is a type of force that resists the motion of an object. There are two types of frictional force. They are:

Therefore, the friction of the block is 5 N

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An acidic solution is indicated by values between 0 and 7. A basic answer is indicated by values between 7 and 14. A solution is neutral when its pH value is exactly 7, meaning it is neither acidic nor basic.

By taking into account the reactivity of both the cation and the anion with water, we may determine whether a salt solution will be acidic, basic, or neutral. Water will not react with either species, leaving a neutral solution.

Since phenolphthalein's colour change is easier to see, it is typically preferred. It would be wise to utilize phenolphthalein, which is used and undergoes a sharp change at the equivalency point.

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Values between 0 and 7 suggest an acidic solution. Values between 7 and 14 indicate a basic response. When a solution's pH is exactly 7, it is considered neutral and is neither acidic nor basic.

We can tell whether a salt solution will be acidic, basic, or neutral by considering how the cation and anion react with water. Both species will not interact with water, leaving a neutral solution.

It is often used because phenolphthalein's color change is simpler to see. It is advisable to use phenolphthalein, which has a strong change at the equivalence point and is widely utilized. When a solution's pH is exactly 7, it is considered neutral and is neither acidic nor basic.

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Answer:

4 m/s

Explanation:

From the question given above, the following data were obtained:

Mass of 1st cart (m₁) = 20 kg

Initial velocity of 1st cart (u₁) = +6 m/s

Mass of 2nd cart (m₂) = 30 kg

Finally velocity of both cart (v) = 0 m/s

Initial velocity of 2nd cart (u₂) =?

The initial velocity of the 2nd cart can be obtained as follow:

m₁u₁ – m₂u₂ = v(m₁ + m₂)

(20 × 6) – (30 × u₂) = 0 (20 + 30)

120 – 30u₂ = 0(50)

120 – 30u₂ = 0

Collect like terms

– 30u₂ = 0 – 120

– 30u₂ = – 120

Divide both side by –30

u₂ = –120 / –30

u₂ = 4 m/s

Thus, the 2nd (i.e the 30 kg) cart was initially moving with a velocity of 4 m/s.

Adding globes in parallel makes no difference to their brightness because all the bulbs glowed with the same brightness indicating that the current flowing through the bulbs had the same value.

The current in each light bulb was the same.

An electric current is a flow of electrons as a result of a potential difference between two points in conductor.

Electrons are negatively-charged particles that are one of the fundamental particles of an atom. The flow of electrons through a conductor is able to do work.

Two or more globes in a simple parallel circuit do not experience any drop in the voltage, thus allowing the maximum flow of electric current. Also, connecting devices in a parallel circuit ensures that if one of the component lops is disconnected, the flow of current through the other loops remains intact.

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Despite the possibility of a strong magnetic field being produced by the stationary magnet, no EMF can be formed because the flux flowing through the coil is constant.

The magnetic field that surrounds the coil's top and bottom alternates between a north and a south pole as the magnet rotates. According to Faraday's law of electromagnetic induction, this rotational movement of the magnetic field induces an alternating emf into the coil.

Only when the magnetic flux changes and while the change is happening is there an induced emf. The induced emf is constant and is zero.

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a) The tension is 76.9 lb when the balloon rises with v=0.8t ft/s and b) The tension is 74.1 lb when the balloon descents with v = 0.4t ft/s.

Newton's second law, states that the net force on an object is equal to its mass times its acceleration.

We can apply Newton's second law to the man and the balloon separately to determine the tension in each of his hands.

a) The net force on the balloon is equal to its mass times its acceleration, which is given by:

F(b) = mg + ma = mg + m(dv/dt)

= mg + m(d/dt(0.8 ft/s)

= (mg + 0.8m)/2

= [150 lb + (150b/32 ft/s²)(0.8 ft/s)]/2

T = 76.86 lb or 76.9 lb

b) When the balloon descends with a velocity of 0.4t ft/s, its acceleration is -0.4 ft/s² (negative because it is descending).

The net force on the man is still equal to the tension in his hands, which we can call T. Therefore:

T = m(m) × g - F(b)

where m(b) is the mass of the balloon, r is its radius, and ρₐ is the density of air,.

T = 150 lb × 32.2 ft/s² - (4/3)πr³ × ρₐ × 0.4 ft/s²

Dividing the tension equally between the man's hands, we get:

T(h) = T/2 = 75 lb × 32.2 ft/s² - (2/3)πr³× ρₐ × 0.4 ft/s²

Substituting the value of r and ρₐ, we get:

T(h) = 74.1 lb

Therefore, the answer is option 4) a) T=76.9 lb, b) T=74.1 lb.

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Answer:

v₃ = 3.33 [m/s]

Explanation:

This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.

In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.

\((m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}\)

where:

m₁ = mass of the car = 1000 [kg]

v₁ = velocity of the car = 10 [m/s]

m₂ = mass of the truck = 2000 [kg]

v₂ = velocity of the truck = 0 (stationary)

v₃ = velocity of the two vehicles after the collision [m/s].

Now replacing:

\((1000*10)+(2000*0)=(1000+2000)*v_{3}\\v_{3}=3.33[m/s]\)

The tension in the string holding the tassel and the vertical will the tension in the string

Generally, the equation for Tension is  mathematically given as

\(TCos\theta = mg\)

Therefore

\(TCos6.58^{o} = 19.8*10^{-3}*9.8\)

T = 0.1953 N

b).

Where

\(T* sin \theta = ma\)

\(0.1953*Sin6.58 \textdegree = 19.8*10^{-3}*a\)

a = 1.13 m/s^2

In conclusion

T* sinФ = ma

2msinФ = ma

2sinФ = a

\(sin\theta = \frac{a}{2}\)

\(\theta = sin^{-1}\frac{a}{2} \\\\\theta= sin^{-1}\frac{1.13}{2}\)

Ф = 34.4 °

In conclusion, The tension in the string holding the tassel and the vertical will the tension in the string

T = 0.1953 N

Ф = 34.4 °

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Answer:

A, c, d

Explanation:

edge 2022

The actions which will increase friction such as scratching a surface to make it rougher, increasing the size of a flying object, and the adding extra weight to an object. Thus, the correct options are A, C, and D.

Friction is the force which is resisting the relative motion of two solid surfaces, fluid layers, and the material elements which are sliding against each other. There are several types of friction including dry friction, which is a force that opposes the relative lateral motion of two solid surfaces in contact.

The actions which will increase the friction include scratching a surface to make it rougher, increasing the size of a flying object, and the adding extra weight to an object.

Therefore, the correct options are A, C, and D.

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Answer:

1. 2160 J

2. 2940 J

3. 64 J

Explanation:

1. Determination of the work done.

Weight (W) = 180 N

Height (h) = 12 m

Workdone =?

Wd = W × h

Wd = 180 × 12

Wd = 2160 J

Thus, the Workdone is 2160 J

2. Determination of the work done.

Mass (m) = 50 Kg

Height (h) = 6 m

Acceleration due to gravity (g) = 9.8 m/s²

Workdone =?

Wd = mgh

Wd = 50 × 9.8 × 6

Wd = 2940 J

Thus, the Workdone is 2940 J

3. Determination of the work done.

Force (F) = 16 N

Distance (d) = 4 m

Workdone =?

Wd = F × d

Wd = 16 × 4

Wd = 64 J

Thus, the Workdone is 64 J

Answer:

Approximately \(4.7\; {\rm s}\).

Explanation:

Acceleration is the rate of change in velocity.

The initial velocity of this vehicle was \(v_{0} = 24\; {\rm m\cdot s^{-1}}\). After stopping, the velocity will be \(v_{1} = 0\; {\rm m\cdot s^{-1}}\). Hence, the change in the velocity of this vehicle will be:

\(\begin{aligned}\Delta v &= v_{1} - v_{0} \\ &= 0\; {\rm m\cdot s^{-1}} - 24\; {\rm m\cdot s^{-1}} \\ &= (-24)\; {\rm m\cdot s^{-1}} \end{aligned}\).

It is given that the vehicle decelerates at a constant rate of \(5.1\; {\rm m\cdot s^{-2}}\). Thus, the rate of change in the velocity of this vehicle (acceleration) will be negative (velocity is decreasing) at \(a = (-5.1)\; {\rm m\cdot s^{-2}}\).

To find the time required for this change in velocity, divide the change by the rate of change:

\(\begin{aligned}(\text{time required}) &= \frac{(\text{change})}{(\text{rate of change})} \\ &= \frac{\Delta v}{a} \\ &= \frac{(-24)\; {\rm m\cdot s^{-1}}}{(-5.1)\; {\rm m\cdot s^{-2}}} \\ &\approx 4.7\; {\rm s}\end{aligned}\).

1.5 grams  of Iodine-131 is left after 32 days

The half life of a substance is given by:

No (1/2 ) ^ t / (t*1/2)

Where No is the substance remaining after the period

t(1/2) is the half life

t(1/2) = 8 days

t = 32 days

No =  24 grams

N = 24 x (1/2)^ 32/ 8

N = 1.5 grams

Half-life is  described as the length of time it takes for half of the radioactive atoms of a specific radionuclide to decay.

A good rule of thumb is that, after seven half-lives, you will have less than one percent of the original amount of radiation.

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The temperature remains constant while the substance is changing state.The correct answer is option C.

When a substance undergoes a change of state, such as melting, boiling, or condensing, the temperature of the substance remains constant during the phase transition. The process of changing state requires the absorption or release of heat energy without a change in temperature.

For example, when a solid is heated, its temperature increases until it reaches the melting point. At this point, the substance starts to change from a solid to a liquid, but the temperature remains constant until all the solid has melted.
The absorbed heat energy is used to break the intermolecular forces holding the particles together, rather than increasing the kinetic energy of the particles.

Similarly, during the process of condensation or freezing, a substance releases heat energy as it changes state. This released energy is used to form intermolecular forces and convert the substance from a gas to a liquid or a liquid to a solid. The temperature remains constant until the phase transition is complete.
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Answer:

Explanation:

The magnitude of the force is known as the resultant.

R = √Fx²+Fy²

Fx = 80cos 20 + 40cos70

Fx = 80(0.9397)+40(0.3420)

Fx = 75.176 + 13.68

Fx = 88.856N

Fy = 80sin 20 + 40sin70

Fy = 80(0.3420)+40(0.9397)

Fy = 27.36 + 37.588

Fy = 64.948N

R = √88.586²+64.948²

R = √7,847.48+4,218.24

R = √12,065.72

R = 109.5

R = 110N

Hence the magnitude of the forces is 110N