It takes 1.4 seconds for the object to reach a height of 7.0 m on the way up.
The initial velocity (u) of the object = 16 m/s, the final velocity (v) at the maximum height = 0 m/s, and acceleration (a) = -9.81 m/s² (as the object is moving upwards, the acceleration due to gravity acts downwards, therefore negative) and displacement (s) = 7 m.
We can use the following kinematic equation to calculate the time taken by the object to reach a height of 7.0 m on the way up:
s = ut + 1/2at²
where s is the displacement, u is the initial velocity, a is the acceleration, and t is the time taken. Rearranging the above formula, we get:
t = √2s/a
Substituting the values of s and a in the above formula, we get:
t = √(2 × 7 / 9.81) ≈ 1.4 seconds.
Hence, it takes 1.4 seconds for the object to reach a height of 7.0 m on the way up.
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The total momentum of a ______ remains constant through time,
regardless of changes within the system.
open system
closed system
generic system
all of the above
none of the above
in an ice show a 43.7 kg skater leaps into the air and is caught by an initially stationary 65.7 kg skater. (a) what is their final velocity assuming negligible friction and that the leaper's original horizontal velocity was 4.02 m/s? 4.02 m/s 2.41 m/s 2.67 m/s 1.61 m/s (b) how much kinetic energy is lost? 197 j
Final velocity is 1.61m/s. assuming negligible friction and that the leaper's original horizontal velocity was 4.02 m/s and The lost kinetic energy is 197 j
first skater Mass = 43.7 Kg
second skater Mass = 65.7 kg
Initial velocity = 4.02 m/s
conservation of momentum
\(m_1u_1+m_2u_2=(m_1+m_2)v\)
175.6+0=109.4v
v=1.61m/s
The lost kinetic energy
\([\Delta E=E_2-E_1],[\Delta E)1/2(m_1u_1^2+m_2u_2^2)-1/2(m_1+m_2v^2)\)
by putting data
KINETIC ENERGY=197 j
A vector number known as velocity describes "the pace at which an item changes its location." Imagine a person moving quickly, taking one stride ahead, one step back, and then beginning from the same place each time. A vector quantity is velocity.
As a result, velocity is aware of direction. One must consider direction while calculating an object's velocity. Saying that an item has a velocity of 55 miles per hour is insufficient. The direction must be included in order to adequately characterize the object's velocity. Simply said, the velocity vector's direction corresponds to the motion of an item.
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How do I solve this? Note, option C is not the answer.
The correct statement is the the acceleration of object 1 is greater than the acceleration of object 2.
What is the velocity time graph?The velocity time graph shows the motion of an object. The velocity is plotted on the vertical axis and the time is plotted on the horizontal axis. We know that the slope of the velocity time graph is the acceleration of the motion.
Let us recall that we would focus our answer on the ideas that can be immediately derived from the graph as we have it in the question. Let us consider the acceleration of object 1 and object 2.
For object 1;
m = y2 - y1/x2 - x1
m = 0 - 40/ 4 - 0
m = - 10 m/s^2
For object 2;
m = y2 - y1/x2 - x1
m = 40 - 0/ 4 - 0
m = 10m/s^2
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Johnny lets a 0.5kg ball roll on
the floor of the classroom. The ball gradually slows down. The coefficient
of friction between the floor and the ball is 0.18. Draw a free body diagram and calculate the acceleration
of the ball.
When Johnny lets a 0.5kg ball roll on the classroom floor, it gradually slows down due to friction. A free body diagram would include two main forces: gravitational force (Fg) acting downward and the normal force (Fn) acting upward.
Since the ball is on a horizontal surface, Fn and Fg cancel each other out. The other force acting on the ball is the frictional force (Ff), which opposes its motion. To calculate Ff, use the formula: Ff = μ * Fn, where μ is the coefficient of friction (0.18). As Fg and Fn are equal, Ff = μ * Fg = 0.18 * (0.5kg * 9.81m/s²) = 0.18 * 4.905 N = 0.8829 N. To find the acceleration of the ball (a), use Newton's second law: F = m * a. Rearrange the formula to find a: a = F / m. Since Ff is the only horizontal force acting on the ball, F = -Ff (the negative sign indicates that the force opposes motion). Therefore, a = -0.8829 N / 0.5 kg = -1.7658 m/s². In summary, the ball experiences an acceleration of -1.7658 m/s² due to friction, causing it to gradually slow down.
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what period of oscillation would you expect if the mass of the glider were doubled? assume no damping
If the mass of a glider in an oscillatory system is doubled while assuming no damping, the period of oscillation would remain unchanged.
The period of oscillation (T) is the time taken for one complete cycle of oscillation, which is independent of the mass of the object in simple harmonic motion. The period is determined by other factors such as the stiffness of the system and the restoring force acting on the object.
In a simple harmonic oscillator, the period is given by the equation:
T = 2π * √(m/k)
Where m is the mass of the object and k is the spring constant or the stiffness of the system.
Doubling the mass of the glider would increase the numerator of the equation by a factor of 2, but it would also increase the denominator by the same factor since the spring constant remains constant. As a result, the ratio of mass to stiffness remains the same, and the square root of that ratio (which represents the period) also remains the same.
Therefore, doubling the mass of the glider would not affect the period of oscillation, and it would remain unchanged.
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What is needed in a market for a good to be considered elastic?
If the amount demand of a product changes more than proportionally as its price rises or falls, then it is said to be elastic.
How is a market made elastic?The more replacements there are for an item, more elastic the good is, according to definition of an elastic good, which is where change in price results in a large movement in demand. Price elasticity of demand is determined by dividing percentage change in quantity required by the percentage change in price.
Products like cars, appliances, and luxury items that are rarely purchased are examples of elastic commodities. In the event that the cost of these products is momentarily high, consumers may decide to put off buying.
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you are called to the scene of an overturned tanker truck. arriving at the scene, you notice a fluid draining from the underside of the truck. you use your binoculars to look on the placard on the back of the vehicle so that you can identify the material from your:
Northern American Emergency Response Guide.The main goal of the ERG Handbook is to help first responders immediately identify any unique or general risks associated with the material(s) at issue.
What does ERG guide 111 entail?There is also Guide 111, which is for "hazardous" materials.When using generic information, make sure to replace it with more detailed instructions as soon as new information becomes available.
What is the number on my ERG Guide?The orange panel next to the diamond-shaped sign or on the extremities and sides of the a cargo tank, vehicle, or rail car may also display the 4-digit ID Number.
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which is the correct relative order of push/pull boundary locations moving in an upstream direction?
In an upstream direction, the push/pull boundaries will be encountered in the reverse order as they appear in the supply chain, moving from the final customer back towards the initial supplier.
To answer your question regarding the correct relative order of push/pull boundary locations moving in an upstream direction:
1. Start at the downstream end of the supply chain.
2. Identify the push/pull boundary closest to the downstream end.
3. Move upstream to the next push/pull boundary in the supply chain.
4. Continue moving upstream, identifying push/pull boundaries in order.
The push/pull boundaries will be encountered travelling from the end client back towards the first supplier in an upward orientation, in the supply chain's reverse sequence.
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What are matter, particle and atom? How can you explain matter using the terms particle and atom?
Answer:
Matter is matter. Particles are particles. Atoms are atoms. You can explain matter using particles and atoms.
JK!
Real Answer:
The term matter refers to anything that occupies space and has mass—in other words, the “stuff” that the universe is made of. An atom is the smallest unit of matter that retains all of the chemical properties of an element. Most atoms contain all three of these types of subatomic particles—protons, electrons, and neutrons.
Hope this helps!
Analyze data table #1 and then create a line graph comparing speed and time.
TEST INTRO 20
The fact that a pen drops when you let it go is an example that can help explain ...
A: the hypothesis of gravity.
B: the theory of gravity.
C: the gravity of the situation.
D: the law of gravity:
Answer:
D
Explanation:
A sled and a rider slide down a snow-covered hill that makes
an angle of 30° with the horizontal. The total mass of the sled
and the rider is 70 kg. Neglecting friction, their acceleration is
m/s2. Round to the nearest tenth.
Answer: 4.9 m/s
Explanation:
In the following figure identify ‘A’ and ‘B’ which represents different colours of the spectrum. Why does this phenomenon occur?
Answer:
A is red
B is violet
Explanation:
A has a high penetration power hence greatest frequency and short wavelength in accordance to the diagram above.
The color with greatest frequency is red.
B has the least penetration power as it is greatly refracted in accordance to the diagram which shows that it has least frequency and high wavelength.
The color of least frequency is violet.
a straight wire has a current of 0.504 amps flowing through it and this wire is placed at an angle of 71.7 degrees to a magnetic field produced by other objects. what would the magnitude of this magnetic field need to be in tesla to exert a force of magnitude 6.16 newtons on a 0.864 meter length of this wire.
The magnitude of this magnetic field would need to be 15.17 tesla in order to exert a force of magnitude 6.16 newtons on a 0.864 meter length of this wire.
The magnitude of this magnetic field can be found by using the equation F = ILBsinθ, where F is the force, I is the current, L is the length of the wire, B is the magnitude of the magnetic field, and θ is the angle between the wire and the magnetic field. Rearranging the equation to solve for B gives us:
B = F / (ILsinθ)
Plugging in the given values gives us:
B = 6.16 N / (0.504 A × 0.864 m × sin(71.7°))
B = 6.16 N / (0.504 A × 0.864 m × 0.944)
B = 15.17 T
Therefore, the magnitude of this magnetic field would need to be 15.17 tesla in order to exert a force of magnitude 6.16 newtons on a 0.864 meter length of this wire.
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PLEASE HELP!!
A student fires a cannonball diagonally with a speed of 34.om/s from a height of 66.0m as shown. Neglect drag. Determine all unknowns and answer the following questions.
How long did the ball rise?
What was the ball's maximum height above the ground?
How long did the ball remain in the air?
How far from the base of the building did the ball land?
How fast was the ball moving as it struck the ground?
We can use the equations of projectile motion to determine the unknowns and answer the following questions:
The time it takes for the ball to reach its maximum height can be found using the following equation:
Vy = Voy - gt
where Voy is the initial vertical velocity and g is the acceleration due to gravity. At the maximum height, the vertical velocity of the ball is zero, so we have:
0 = Voy - gt
t = Voy/g
t = (34.0 m/s)sin(73°)/9.81 m/s^2 ≈ 3.6 s
The maximum height reached by the ball can be found using the following equation:y = Voyt - 1/2 gt^2
where y is the vertical displacement of the ball. At the maximum height, the vertical displacement is equal to the initial height of the ball, so we have:
66.0 m = (34.0 m/s)sin(73°)t - 1/2 (9.81 m/s^2)t^2
t ≈ 3.6 s
y = (34.0 m/s)sin(73°)(3.6 s) - 1/2 (9.81 m/s^2)(3.6 s)^2 ≈ 117 m
The total time of flight can be found using the following equation:t_total = 2t
where t is the time it takes for the ball to reach its maximum height. Substituting the value of t from above, we get:
t_total = 2(3.6 s) ≈ 7.2 s
The horizontal distance traveled by the ball can be found using the following equation:x = Vx t
where Vx is the initial horizontal velocity of the ball. Substituting the given values, we get:
x = (34.0 m/s)cos(73°)(7.2 s) ≈ 241 m
The final velocity of the ball can be found using the following equation:Vf = sqrt(Vx^2 + Vy^2 - 2gy)
where Vx and Vy are the horizontal and vertical components of the velocity, respectively, and y is the vertical displacement of the ball. At the instant of impact, the vertical displacement is equal to the initial height of the ball, so we have:
y = 66.0 m
Substituting the given values, we get:
Vf = sqrt[(8.9 m/s)^2 + (32.7 m/s)^2 - 2(9.81 m/s^2)(66.0 m)] ≈ 29.1 m/s
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Velocity (m/s)
25
20
15
10
5
0
0
Velocity vs Time
1
2
3
Time (s)
4
5
What is the initial velocity of the object represented by
the graph?
m/s
The object depicted by the graph initially moves at a speed of 25 m/s.
The rate at which the position of an item changes with respect to time is represented by the vector quantity known as velocity. It is calculated by dividing an object's displacement by the time period during which the displacement took place.
Velocity is a phrase used to more simply define the direction and speed of an object's motion. Both the direction and the speed of an object's motion are specified. The International System of Units (SI) uses metres per second (m/s) as the standard unit for measuring velocity.
We must look at the behaviour of the graph before to time 1 second in order to ascertain the initial velocity of the object the graph represents.
From the graph provided,
From the given graph, We can see that from time 0 to time 1 second, the velocity is 25 m/s and stays that way.
As a result, the object's starting velocity is 25 m/s.
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Please help me quickly
A car moves along a curved road of diameter 2 km. If the maximum velocity for safe driving on this path is 30 m/s, at what angle has the road been banked? (Ignore friction.)
A) 11°
B) 22.6°
C) 45.2°
D) 5.26°
Hi there!
Ignoring friction, we know that the centripetal force experienced by the car is due to the normal force exerted by the road.
We can do a summation of forces in both the horizontal and vertical directions.
Vertical:
\(W = Mg\), force due to gravity
\(Ncos\theta\), VERTICAL component of the normal force.
\(\Sigma F_y = Ncos\theta - Mg\\\\Mg = Ncos\theta\)
Horizontal:
\(Nsin\theta = F_{Hnet}\)
The net horizontal force is equivalent to the centripetal force:
\(Nsin\theta = \frac{mv^2}{r}\)
We can solve for theta by dividing:
\(\frac{Nsin\theta = \frac{mv^2}{r}}{Ncos\theta = mg}\)
Simplify:
\(tan\theta = \frac{ \frac{v^2}{r}}{ g}\\\\tan\theta =\frac{v^2}{rg}\)
Solve:
\(\theta = tan^{-1}(\frac{v^2}{rg}) = tan^{-1}(\frac{30^2}{(1000)(9.8)}) = \boxed{5.26^o}\)
How fast is a cat that runs 50 meters in 10 seconds?
Answer:
50 m in 10 sec….divide 50 by 10 to convert to metres per second = 5 m/s. Then multiply by 3.6 (3600 seconds in an hour divided by 1000) to convert to kilometres per hour =18 m/s. To convert to mph divide by 1.609 =11.18 mph.
Explanation:
Answer:
5 meters per second
Explanation:
1) Set up a proportion.
\(\frac{50}{10}\) = \(\frac{x}{1}\)
2) Solve the proportion.
x = 5 because 50 ÷ 10 is 5.
Suppose an object is accelerated by a force of 100 N. Suddenly a second force of 100 N in the opposite direction is exerted on the object, so that the forces camel. The object... A)is brought to rest rapidly B) decreases gradually to rest C) continues with the velocity it had before the second force was applied D) is brought to rest and then accelerates in the direction of the second force
The opposite direction is exerted on the object, so that the forces camel The object is is brought to rest rapidly.
What is direction ?Direction is a term used to describe the way something is moving or pointing. It is often used in reference to the orientation of objects, or the path something is taking. Direction can be described in terms of three-dimensional coordinates, including length, width, and height. Direction can also be described in terms of four cardinal directions (north, south, east and west), and eight ordinal directions (north-east, south-east, south-west and north-west). Direction can also be expressed in terms of angles and compass bearings. Direction is an important part of navigation, and is used to calculate distances. It is also essential for planning journeys and understanding the environment.
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What are the 4 characteristics of a concave mirror?
Concave mirrors can create both actual and virtual pictures. Mirrors can be enlarged, shrunk, or the exact size as the item. They can just be upright (if online) or reversed (unless real); front of the glass (unless real); or behind the glass (if virtual).
What distinguishes a convex mirror?Convex mirrors are not utilized to focus light since they diverge light rays by reflecting light outward. Virtual, upright, and initially smaller than the item, the image grows to a maximum size equal to the thing as it approaches the mirror. Diverging mirrors are another name for such mirrors.
What features distinguish concave?Spherical mirrors include both concave and convex mirrors.
Property 1: The incoming ray that is perpendicular to the main axis travels through the concave mirror's focus.
Property 2: The incident light will be reflected parallel toward the major axis if it passes through the focus.
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Please help ASAP!
If you were to push a brick wall with 100 N of force, how much force would the wall push back towards you?
Answer:
100 newton
Explanation:
newton third law of motion says to every action there is an always an equal and opposite reaction so the magnitude will stay equal but opposite direction
Answer:
- 100N is the answer of this question
What questions do you still have about supermassive black holes after watching this Ted Talk? Do you feel that you have a deeper understanding of what they are and why they are important, like was asked of you in the third question? Explain and discuss.
After watching the Ted Talk, there were still a few questions that I had about supermassive black holes. Firstly, I wanted to know more about the event horizon and what it exactly entails. Although the speaker briefly touched upon this subject, I would have appreciated a more in-depth explanation. Additionally, I would have liked to know more about the role of supermassive black holes in the universe.
While the speaker did mention that these black holes are responsible for the creation of galaxies, I wanted to know more about how this process works and why it is so important.Despite these questions, I do feel that I have a deeper understanding of supermassive black holes and their importance.From the Ted Talk, I learned that supermassive black holes are some of the largest objects in the universe and are essential for the formation of galaxies. I also learned that these black holes are incredibly powerful and have the ability to affect the trajectory of stars and planets.Overall, I think that the Ted Talk did a great job of explaining supermassive black holes in a way that was easy to understand. While there were still a few questions that I had after watching the video, I feel that I now have a better grasp of what supermassive black holes are and why they are so important.For such more question on supermassive
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A 1,200-kilogram car traveling at 10. meters per second hits a tree and is brought to rest in 0.10 second. What is the magnitude of the average force acting on the car to bring it to rest? angle of 15.0° above the horizontal. What are the horizontal (vx) and vertical (vy) components of this velocity? the law of universal gravitation?
(a) The magnitude of the average force acting on the car to bring it to rest is 120,000 N.
(b) The horizontal (vx) and vertical (vy) components of this velocity is 9.66 m/s and 2.59 m/s respectively.
What is the average force acting on the car?
The magnitude of the force acting on the car is calculated as follows;
F = mv / t
where;
m is the mass of the carv is the speed of the cart is the time of motion of the carF = ( 1200 kg x 10 m/s ) / ( 0.1 s )
F = 120,000 N
The horizontal and vertical component of the velocity of the car is calculated as follows;
Vx = V cosθ
Vy = V sinθ
where;
θ is the direction of the speedVx = 10 m/s x cos (15) = 9.66 m/s
Vy = 10 m/s x sin (15) = 2.59 m/s
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URGENT!!! What factors could slow your reaction time?
Answer:
neurons
Explanation:
i hope this works
A 3.5 m long frictionless pendulum of mass 2.0 kg is released from point A at an angle θ of 10 degrees. What is the speed of the pendulum at point D, half the height up to point E?
Answer:
5
Explanation:
melsun slemalawkew melsun asawkecn
a flatbed truck is carrying a crate along a level road. the coefficient of static friction between the load and the bed is 0.40. the truck accelerates forward and the crate stays in its place on the truck bed. in what direction is the force that the bed exerts on the crate?
The direction is the force that the bed exerts on the crate Forward.
Friction between the track and the crate holds the crate in place and allows the crate to move with the vehicle. As a result, the crate's frictional force is directed north, in the same direction as the truck's velocity. As mentioned earlier, both the horizontal and vertical forces have a magnitude of 0 so there is no net force on the box. Therefore, the force on the box has no direction.
The net force always has the same direction as the acceleration. For an object in a circular motion with constant velocity, the net force is directed toward the center of the circle around which the object is moving. The frictional force acts on a moving object, and its direction is opposite to the direction of movement. As we walk, our feet are pushed backward so friction works in the opposite direction to counteract the push.
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Una sirena que emite un sonido de f=100Hz se mueve alejandose de un observador en reposo y dirigiendose hacia un acantilado con velocidad constante de v1=20 m/s.
Given that,
Frequency = 100 Hz
Velocity = 20 m/s
Suppose, Determinar la diferencia de frecuencia entre la onda que recibe el observador directamente de la sirena y la onda que le llega reflejada en el acantilado.
We need to calculate the frequency heard by the observer directly from source
Using formula of frequency
\(f_{1}=f\times(\dfrac{v}{v-v_{s}})\)
Where, v = speed of sound
\(v_{s}\) = speed of source
f = frequency of source
Put the value into the formula
\(f_{1}=100\times\dfrac{340}{340-20}\)
\(f_{1}=106.25\ Hz\)
We need to calculate the frequency heard by the observer coming after reflection from cliff
Using formula of frequency
\(f_{2}=f\times(\dfrac{v}{v+v_{s}})\)
Put the value into the formula
\(f_{2}=100\times\dfrac{340}{340+20}\)
\(f_{2}=94.4\ Hz\)
We need to calculate the difference of frequency
Using formula for difference of frequency
\(\Delta f=f_{1}-f_{2}\)
Put the value into the formula
\(\Delta f=106.25-94.4\)
\(\Delta f=11.85\ Hz\)
Hence, The difference of frequency is 11.85 Hz.
A 1994 Ford Mustang is driving down a road with a constant speed of 30 31/5, The engine must
exert a 5000 N force to maintain this speed,
a, What is the power rating of the engine?
The power rating of the engine is 150000 W.
What is power?Power can be defined as the rate at which energy is used or consumed by a body.
To calculate the power of the engine, we use the formula below.
Formula:
P = FV............. Equation 1Where:
P = Power of rating of the engineF = Force of the engineV = Velocity of the engine.From the question,
Given:
F = 5000 NV = 30 m/s.Substitute these values into equation 1
P = 5000×30P = 150000 W.Hence, The power rating of the engine is 150000 W.
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What is SI unit for distance
Answer:
meter
The SI unit of distance and displacement is the meter [m].
Explanation:
have advancedd
Answer:
meter
Explanation:
it is meter I hope this is helpful