An op amp designed to have a low-frequency gain of 10^4 VN and a high-frequency response dominated by a single pole at 1000 rad/s acquires, through a manufacturing error, a pair of additional poles at 100,000 rad/s. Assume that the total phase shift of the open-loop gain A reaches 1800 at 10^5 rad/s (that is w180 = 10^5 rad/s). At this frequency, for what value of ß, assumed to be frequency independent, does the loop gain at w = w180 reach a value of unity? That is, find the largest feedback factor allowed, Ber. = a. 0.01 O b. 0.05 O c. 0.02 O d. 0.033

1. This system is causal, but not stable since the impulse response is unbounded.
2. This system is both causal and stable since the impulse response is bounded.
3. This system is both causal and stable since the impulse response is bounded.

What is System?
System is a collection of interrelated components that work together to complete a task or achieve a goal. It is a set of procedures that are organized and managed to complete tasks in a predetermined sequence. Systems are commonly composed of hardware, software, people, networks, processes and methods. A system can be used to control a device, process information, manage resources, or analyze data.

To know more about System
https://brainly.com/question/24788396
#SPJ4

Answer: 150m

Explanation:

The following can be depicted from the question:

Dimensions of outer walls = 9.7m × 14.7m.

Thickness of the wall = 0.30 m

Therefore, the plinth area of the building will be:

= (9.7 + 0.30/2 + 0.30/2) × (14.7 × 0.30/2 + 0.30/2)

= 10 × 15

= 150m

The plinth area will be 150m.

Given information

Dimensions of outer walls = 9.7m × 14.7m.

Thickness of the wall = 0.30 m

Plinth area of the building = (9.7 + 0.30/2 + 0.30/2) × (14.7 × 0.30/2 + 0.30/2)

Plinth area of the building = 10 × 15

Plinth area of the building = 150m

Therefore, the Option A is correct.

Read more about Area

brainly.com/question/25292087

An engine is composed of several major components; the block, the crank, the rods, the pistons, the head (or heads), the valves, the cams, the intake and exhaust systems and the ignition system. These parts work together in an exacting manner to harness the chemical energy in gasoline.

The engine block consists of a cylinder block and a crankcase. An engine block can be produced as a one-piece or two-piece unit. The cylinder block is the engine component that consists of the cylinder bore, cooling fins on air-cooled engines, and valve train components, depending on the engine design.

hope this helps

have a good day

:)

Answer:

use this, it should help you understand

Explanation:

https://www.electronics-tutorials.ws/logic/logic_5.html

The differential of this control is 50 psig, which determines its precision and responsiveness in regulating pressure and maintaining desired levels in various applications.

The differential of a control represents the gap between its cut-in and cut-out pressures. In this instance, the control's cut-out pressure is set at 500 psig, while the cut-in pressure is at 450 psig. By subtracting the cut-in value from the cut-out value, we find that the differential amounts to 50 psig. This means that the control will activate or deactivate its functions when the pressure fluctuates by 50 psig. Differential values are critical in determining the precision and responsiveness of pressure controls, enabling them to regulate systems effectively and maintain desired pressure levels. Understanding these differentials allows for proper calibration and optimization of control systems in various applications.

Learn more about cut-out pressures

brainly.com/question/32372311

#SPJ11

Yes, exceeding the dielectric strength of a capacitor means that you have applied a voltage that is too high for the capacitor to handle, and this can result in the destruction of the capacitor.

The dielectric strength refers to the maximum voltage that a capacitor's dielectric material can withstand before it breaks down and allows current to flow through it. If the applied voltage exceeds this limit, the dielectric material can become damaged or even vaporized, which can lead to a short circuit or other types of failure. Therefore, it is important to always operate capacitors within their rated voltage range to avoid damaging them and ensure their proper functioning.

Learn more about dielectric strength: https://brainly.com/question/14529872

#SPJ11

Yes, that is correct. Exceeding the dielectric strength f a capacitor means you have applied too high a voltage, and probably destroyed the capacitor. This occurs when the content loaded surpasses the capacitor's ability to withstand the electric field, resulting in potential damage to the component.

Exceeding the dielectric strength of a capacitor means that you have applied a voltage that is too high for the capacitor to handle, which can cause the insulation material (dielectric) to break down and the capacitor to fail or even be destroyed. It is important to always follow the manufacturer's specifications for voltage ratings and avoid exceeding them to prevent damage to the capacitor.Dielectric strength is defined as the electrical strength of an insulting material. In a sufficiently strong electric field the insulating properties of an insulator breaks down allowing flow of charge. Dielectric strength is measured as the maximum voltage required to produce a dielectric breakdown through a material.
.

learn more about dielectric strength here:

https://brainly.com/question/9617400

#SPJ11

Answer:

I think its A

Explanation:

Answer:

The voltage gain is 2.07.

Explanation:

Given that,

Resistance \(R_{1}=14\ k\Omega\)

Resistance \(R_{2}=13\ k\Omega\)

We need to calculate the voltage gain

Using formula of voltage source

\(V_{s}=\dfrac{V_{o}\times R_{2}}{R_{1}+R_{2}}\)

\(\dfrac{V_{o}}{V_{s}}=\dfrac{R_{1}+R_{2}}{R_{2}}\)

Where, \(R_{1}\) = first resistance

\(R_{2}\) =second resistance

\(V_{s}\) = source voltage

\(V_{o}\) = output voltage

Put the value into the formula

\(\dfrac{V_{o}}{V_{s}}=\dfrac{14+13}{13}\)

\(\dfrac{V_{o}}{V_{s}}=2.07\)

Hence, The voltage gain is 2.07

Tailgating is one of the most common methods of social engineering, in which an attacker gains entry into a secure location or system by following a legitimate individual through a secure door or into a restricted area, making it appear that they have the right to be there.

Tailgating is a form of social engineering in which an attacker follows a legitimate person into a secured area or system in order to gain access. The attacker could be a thief, a spy, a con artist, or a malicious insider. Social engineering is the art of manipulating people in order to obtain sensitive or confidential information that can be used to gain unauthorized access to computer systems, data networks, or physical facilities.

Tailgating is a method of social engineering in which an attacker gains access to a restricted area by following an authorized individual through a secure door or gate. It may also be known as piggybacking or "tagging along." Tailgating is the act of following someone through a secured door or gate without providing proper identification or authorization.

To learn more about Social engineering :

https://brainly.com/question/29024098

#SPJ11

Answer:

A

Explanation:

Making all the schedules

The task within an airline company that are related to operations is;

Option A: Crew scheduling.

In airline operations there are numerous tasks carried out which includes;

Now, looking at the given options, the only task that falls into the list given of airline operations tasks is Crew scheduling.

Read more about airline operations tasks at; https://brainly.com/question/17074890

The critical value of the angular velocity obtained just before the slipping starts is the answer to this question and it is \(\bold{\omega = \sqrt{\frac{\mu.g}{r}}}\).

                                         \(\begin{aligned}\\\\F &= ma\\\\f_{max} &\geq ma\\\\ \mu_s.mg &\geq m.r\omega^2\\\\\omega &\leq \sqrt{\frac{\mu_sg}{r}}\\\\\omega_{critical} &= \sqrt{\frac{\mu_sg}{r}}\end{aligned}\)

#SPJ4

true

the answer to this question is true

To determine the average number of workers at the trailer, we can use the M/M/1 queuing model, where arrivals follow a Poisson process and service times follow an exponential distribution.So, the correct answer is:2 workers

Given that workers arrive at an average rate of 8 per hour, the arrival rate (λ) is 8 per hour. The average service time (1/μ) is 6 minutes, which can be converted to hours by dividing by 60, resulting in μ = 1/10 per hour.

Using the M/M/1 queuing formula for the average number of workers (N) in the system:

N = λ / (μ - λ)

Substituting the values, we have:

N = 8 / (1/10 - 8) = 8 / (1/10 - 80) = 8 / (-79/10) = -80/79 ≈ -1.01

Since the number of workers cannot be negative, we take the absolute value, resulting in approximately 1.01 workers.

However, since the question asks for the average number of workers at the trailer, including the one whose permit is being worked on, we need to consider at least one worker. Therefore, we round up the result to the nearest whole number, which gives us an average of 2 workers at the trailer.

To know more about Poisson click the link below:

brainly.com/question/31797796

#SPJ11

Answer:

There is conversion of energy from one form to another and this justifies the law of conservation of energy, which states that energy can neither be created nor destroyed but can be converted from one form to another.

Explanation:

The fuel added to automobile is a chemical energy, which provides thermal energy of the combustion engine of the automobile, which is then converted to mechanical energy of the moving parts of the automobile. Thus, there is conversion of energy from one form to another. This justifies the law of conservation of energy, which states that energy can neither be created nor destroyed but can be converted from one form to another.

Statements (a) and (b) are implied by the P != NP conjecture. Therefore, the correct answer is:

a) Every algorithm that solves an NP-hard problem runs in super-polynomial time in the worst case.
b) Every algorithm that solves an NP-hard problem runs in exponential time in the worst case.

Here's how the implications of the P ≠ NP conjecture break down:

a) Every algorithm that solves an NP-hard problem runs in super-polynomial time in the worst case.

NP-hard problems are a class of problems that are at least as hard as the hardest problems in NP. These problems are known to be difficult to solve, and no polynomial-time algorithm is currently known for them. The P ≠ NP conjecture implies that there is no polynomial-time algorithm for solving NP-hard problems, and the best algorithms we have for solving them take super-polynomial time in the worst case.

b) Every algorithm that solves an NP-hard problem runs in exponential time in the worst case.

Exponential time is a type of time complexity where the running time of an algorithm grows exponentially with the size of the input. The P ≠ NP conjecture suggests that NP-hard problems cannot be solved in polynomial time, which means that the best algorithms for solving them take time that grows faster than any polynomial. This includes exponential time, but also includes other time complexities that grow even faster than exponential.

c) Every algorithm that solves an NP-hard problem always runs in super-polynomial time.

Option c is incorrect because it suggests that every algorithm for solving NP-hard problems always takes super-polynomial time, which is not necessarily true. While the P ≠ NP conjecture implies that there is no polynomial-time algorithm for solving NP-hard problems, it does not mean that all algorithms for solving them take super-polynomial time for every instance of the problem. There may be some instances where the algorithm runs in polynomial time, but these instances are rare and do not change the fact that NP-hard problems are generally hard to solve.

d) Every algorithm that solves an NP-hard problem always runs in exponential time.

Option d is incorrect for the same reason as option c. While the P ≠ NP conjecture suggests that there is no polynomial-time algorithm for solving NP-hard problems, it does not mean that all algorithms for solving them take exponential time for every instance of the problem. There may be some instances where the algorithm runs in polynomial time or even faster, but these instances are rare and do not change the fact that NP-hard problems are generally hard to solve.

Know more about the conjecture click here:

https://brainly.com/question/24881803

#SPJ11

Slope 1 is  the slope of the line when a change of state is occurring.

The slopes of the slanted strains represent the unique warmth potential. The sharper the slope, the smaller the unique warmth potential of the substance is. This is extensive due to the fact the sharper the slope, the greater fast the temperature rises while the substance is heated. A slope of one approach it rises simply as rapid because it is going forward. A terrible slope approach that variables are negatively related; that is, while x increases, y decreases, and while x decreases, y increases. If the graph of a line rises from left to proper, the slope is positive. If the graph of the road falls from left to proper the slope is terrible.

Learn more about cooling curve at https://brainly.com/question/12505139

#SPJ4

The way to properly engage the safety latches on the Stan Design Pit Jack is:

This refers to the machination which makes use of pit jacks to execute tire rotation in a fast lube pit.

We can note that based on the design, this machine is put in the pit of a car and then rolls back and forth and perform their operations on both the front and real axles.

Hence, it is important to note that the safety latches are designed to prevent work accidents and it is important to properly lubricate the parts to prevent damage.

Read more about safety latches here:
https://brainly.com/question/24573204

A double that is larger than 0 and less than 1 is what the Math.random() function produces. This number evaluates to a double that is more than or equal to 0 and less than 10 when multiplied by 10.

Similar to that, if you require random numbers between 5 and 10, you must call nextInt(5, 11), as 5 is inclusive but 11 is exclusive, and this will return any result between 5 and 10.

Math.random() The floating-point, pseudo-random number that is returned by the Math.random() function has a roughly uniform distribution over the range from larger than or equal to 0 to 1.

To know more about Math.random visit :-

https://brainly.com/question/17586272

#SPJ4

Answer:

The moment of inertia is basically a physical quantity which describes how easy it is for a body to rotate itself around a given axis.

In easier wording: Moment of Inertia is a body and when it starts rotating or moving, it will keep doing so until we stop it by force.

Explanation:

For example, a car that is moving and active will continue to move even if you were to switch the engine off.

Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

Article 430 that is found in  National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .

Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.

Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

Learn more about motor- overload from

https://brainly.com/question/20738481

#SPJ1

Answer:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)

Explanation:

Given

\(0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38,\ 0.40,\ 0.40,\ 0.40,\ 0.41,\)

\(0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.43,\ 0.44,\ 0.45,\ 0.46,\)

\(0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49,\ 0.51,\ 0.54,\ 0.54,\ 0.55,\)

\(0.58,\ 0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68,\ 0.78.\)

Required

Plot a steam and leaf display for the given data

Start by categorizing the data by their tenth values:

\(0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38.\)

\(0.40,\ 0.40,\ 0.40,\ 0.41,\ 0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\)

\(0.43,\ 0.44,\ 0.45,\ 0.46,\ 0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49.\)

\(0.51,\ 0.54,\ 0.54,\ 0.55,\ 0.58.\)

\(0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68.\)

\(0.78.\)

The 0.3's is will be plotted as thus:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \ \end{array}\)

The 0.4's is as follows:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \ \end{array}\)

The 0.5's is as follows:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \ \end{array}\)

The 0.6's is as thus:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \ \end{array}\)

Lastly, the 0.7's is as thus:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)

The combined steam and leaf plot is:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)

Answer:

ee

Explanation:

This is an over the top question

The program requires a sequence control structure; First, we get input for the variables, and then use the formula to calculate the amount of calories burnt.

The program in python is as follows, where comments (in italics) are used to explain each line.

#This gets input for age, in years

age = int(input("Age (years): "))

#This gets input for weight, in pounds

weight = int(input("Weight (pounds): "))

#This gets input for heart rate, in beats per minutes

heart_rate = int(input("Heart Rate (beats per minutes): "))

#This gets input for time, in minutes

time = int(input("Time (Minutes) : "))

#This calculates the calories burnt for men

calories_man = ((age * 0.2017) - (weight * 0.09036) + (heart_rate * 0.6309) - 55.0969) * time / 4.184

#This calculates the calories burnt for women

calories_woman = ((age * 0.074) - (weight * 0.05741) + (heart_rate * 0.4472) - 20.4022 ) * time / 4.184

#This prints the calories burnt for men

print('Men: %0.2f calories' % calories_man)

#This prints the calories burnt for women

print('Women: %0.2f calories' % calories_woman)

Please note that the program does not check for valid inputs

See attachment for program output

Read more about Python programs at:

https://brainly.com/question/22841107

Answer:

a) the mass flow rate of the steam is  \(\mathbf{m_1 =6.92 \ kg/s}\)

b) the exit velocity of the steam  is \(\mathbf{V_2 = 562.7 \ m/s}\)

c) the exit area of the nozzle is  \(A_2\) = 0.0015435 m²

Explanation:

Given that:

A steam with 5 MPa and 400° C enters a nozzle steadily

So;

Inlet:

\(P_1 =\) 5 MPa

\(T_1\) = 400° C

Velocity V = 80 m/s

Exit:

\(P_2 =\) 2 MPa

\(T_2\) = 300° C

From the properties of steam tables  at \(P_1 =\) 5 MPa and \(T_1\) = 400° C we obtain the following properties for enthalpy h and the speed v

\(h_1 = 3196.7 \ kJ/kg \\ \\ v_1 = 0.057838 \ m^3/kg\)

From the properties of steam tables  at \(P_2 =\) 2 MPa and \(T_1\) = 300° C we obtain the following properties for enthalpy h and the speed v

\(h_2 = 3024.2 \ kJ/kg \\ \\ v_2= 0.12551 \ m^3/kg\)

Inlet Area of the nozzle = 50 cm²

Heat lost Q = 120 kJ/s

We are to determine the following:

a) the mass flow rate of the steam.

From the system in a steady flow state;

\(m_1=m_2=m_3\)

Thus

\(m_1 =\dfrac{V_1 \times A_1}{v_1}\)

\(m_1 =\dfrac{80 \ m/s \times 50 \times 10 ^{-4} \ m^2}{0.057838 \ m^3/kg}\)

\(m_1 =\dfrac{0.4 }{0.057838 }\)

\(\mathbf{m_1 =6.92 \ kg/s}\)

b) the exit velocity of the steam.

Using Energy Balance equation:

\(\Delta E _{system} = E_{in}-E_{out}\)

In a steady flow process;

\(\Delta E _{system} = 0\)

\(E_{in} = E_{out}\)

\(m(h_1 + \dfrac{V_1^2}{2})\) \(= Q_{out} + m (h_2 + \dfrac{V_2^2}{2})\)

\(- Q_{out} = m (h_2 - h_1 + \dfrac{V_2^2-V^2_1}{2})\)

\(- 120 kJ/s = 6.92 \ kg/s (3024.2 -3196.7 + \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(- 120 kJ/s = 6.92 \ kg/s (-172.5 + \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(- 120 kJ/s = (-1193.7 \ kg/s + 6.92\ kg/s ( \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(V_2^2 = 316631.29 \ m/s\)

\(V_2 = \sqrt{316631.29 \ m/s\)

\(\mathbf{V_2 = 562.7 \ m/s}\)

c) the exit area of the nozzle.

The exit of the nozzle can be determined by using the expression:

\(m = \dfrac{V_2A_2}{v_2}\)

making \(A_2\) the subject of the formula ; we have:

\(A_2 = \dfrac{ m \times v_2}{V_2}\)

\(A_2 = \dfrac{ 6.92 \times 0.12551}{562.7}\)

\(A_2\) = 0.0015435 m²

Answer:

b. American Society of Mechanical Engineers

Explanation:

The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.

The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.

Technical practice incorporates build-time identification of security vulnerabilities in the code is  Penetration testing.

A penetration test, sometimes referred to as a pen test or ethical hacking, is a legitimate simulated cyberattack on a computer system that is carried out to analyze the system's security. This is distinct from a vulnerability assessment.

In order to identify and illustrate the financial effects of a system's vulnerabilities, penetration testers employ the same tools, strategies, and procedures as attackers. Reconnaissance, scanning, vulnerability assessment, exploitation, and reporting are the five stages of a penetration test.

Penetration testing is a technical activity that includes build-time discovery of security vulnerabilities in the code.

Penetration tests are essential to an organization's security because they teach staff members how to respond to any kind of intrusion from a malicious party. Pen tests are a method of determining whether a company's security procedures are actually effective.

To learn more about Penetrating Testing, refer to:

https://brainly.com/question/26555003

#SPJ4

Explanation:

The main sources of error in the collection of data are as follows : Due to direct personal interview. Due to indirect oral interviews. Information from correspondents may be misleading. Mailed questionnaire may not be properly answered. Schedules sent through enumerators, may give wrong information.

a)  The initial and final temprature are 99.61°C and T3 = 259.07°C

b)   The mass of liquid water when the piston first start moving is 0g

Using the data provided:

Initial Pressure = P1 = 125kPa

Mass of Saturated Vapor Liquid = m = 5kg

Initial Mass of Liquid water = mf = 2kg

Initial Mass of Vapor = mg = 3kg

The temperature for a mixture of liquid steam saturated with water according to the thermodynamic table is:

T₁ = 99.61°C

The specific volume is:

vf = 0.001043m³/kg

And the saturated volume is:

vg = 1.6941m³/kg

Therefore, the volume in state 1 will be equal to:

V1 = mfvf + mgvg

V1 = (2kg)(0.001043m³/kg) + (3kg)(1.6941m³/kg)

V1 = 5.084m³

In state 3 then the volume will be equal to:

V3 = 1.2V1

V3 = 1.2(5.084m³)

V3 = 6.1008m³

Then the specific volume will be equal to:

v3 = V₃/m

v3 = 6.1008m³/5kg

v3 = 1.2202m³/kg

For a pressure of 300 kPa and the previous specific volume found through the thermodynamic table, the value of the temperature is:

T3 = 259.07°C

Question b) When the piston first stats moving at P₂ = 300kPa and V₂ = V₁ = 5.084m³

v₂ =V₂/m

v₂ = 5.084m³/5kg

v2 = 1.0168m³/kg

While at 300 kPa the value of the vapor saturated vg = 0.88578m³/kg This implies that the condition is met:

v2 > vg

Therefore, no liquid is there in-cylinder when piston stats moving, mf = 0kg

Learn more on solving problems on heat transfer from:

https://brainly.com/question/15289827?referrer=searchResults

#SPJ4