An oven takes in 1200J of energy
and transfers 375J as useful energy.
Caculate the efficiency

The correct answer is 107.9 g of Ag is produced from a reaction of 31. 75 gram of Copper.

Molar mass of a substance is the mass in grams of one mole of the compound. A mole is the measurement of the number of things, such as atoms, molecules, and ions, that are present in a substance. Any material has 6.022 x 1023 molecules in a mole, it is known as Avogadro's number . The mole is used to determine the size of the tiniest entities quantitatively, just as we use a standard value to quantify many things, such as 1 dozen = 12 items.

Formula - Molar mass = mass in grams/mole = g/mol

Molar mass of a substance can be calculated as:

Given,

n = W/M, where

W = required mass

M= molar mas

Given chemical reaction is:

Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

From the stoichiometry of the reaction,

1 mole of Cu = produce 2 moles of Ag

Given mass of Cu = 31.75g

Molar mass of Cu = 63.5g/mol

Moles of Cu = 31.75g / 63.5g/mol = 0.5 moles

0.5 moles of Cu = produce 2×0.5 = 1 mole of Ag

Molar mass of Ag = 107.9g/mol

Required mass of Ag = 1mol × 107.9g/mol = 107.9 g

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Answer:

to collect measurable, empirical evidence in an experiment related to a hypothesis the results aiming to support or contradict a theory.

Explanation:

Answer:

0.6145M

Explanation:

Based on the chemical equation, 2 moles of MnO₄⁻ reacts with 5 moles of H₂C₂O₄.

To solve this problem, we need to find moles of MnO₄⁻, with the chemical equation the moles of H₂C₂O₄ and, the concentration of this solution.

Moles MnO₄⁻:

24.98mL = 0.02498L * (0.1968mol / L) = 4.916x10⁻³ moles MnO₄⁻

Moles H₂C₂O₄:

4.916x10⁻³ moles MnO₄⁻* (5 moles H₂C₂O₄ / 2 moles MnO₄⁻) =

0.01229 moles H₂C₂O₄

Molarity H₂C₂O₄:

0.01229 moles H₂C₂O₄ / 0.0200L =

The matter cannot be created or destroyed in a chemical reaction. So that answer is No

According to the law of conservation of mass, matter can neither be created nor destroyed in a chemical reaction. The total mass of the reactants must be equal to the total mass of the products, meaning that atoms are rearranged and combined in different ways, but no atoms are lost or gained.

The law of conservation of mass is a fundamental principle in chemistry, and it highlights the notion that matter is conserved throughout chemical reactions. This understanding allows chemists to accurately predict and balance chemical equations, ensuring that the total number of atoms on each side of the reaction remains constant.

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Carbon electrodes are changed frequently in electrolysis as the carbon in the carbon electrodes burns to give out Carbon-di-oxide.

Carbon electrodes are used in electrolysis to facilitate the transfer of electrons between the anode and the cathode. The carbon electrode is usually in the form of a rod or plate and is electrically connected to the anode.

The carbon electrode may also be used to help reduce the overall resistance of the electrolytic cell.

Carbon electrodes are used in electrolysis because they are chemically inert and have a high electrical conductivity.

However, carbon electrodes must be changed frequently because they become corroded and lose their electrical conductivity over time.

This is because carbon burns out in the Carbon electrodes to give out Carbon-di-oxide. That is why the carbon anodes should be changed frequently.

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No, the silicon structure is not the same as diamond. Both silicon and diamond have a tetrahedral crystal structure, but there are some key differences between the two.

First, silicon atoms are larger than carbon atoms, which make up diamond. This means that the bond lengths in silicon are longer than those in diamond, and the crystal structure of silicon is less compact.

Second, silicon has a lower electronegativity than carbon, which means that the bonds between silicon atoms are less strong than those between carbon atoms. This makes silicon less hard and less brittle than diamond.

Finally, silicon has a lower band gap than diamond, which means that it is a semiconductor rather than an insulator. This gives silicon different electrical properties than diamond, and makes it useful in electronic devices.

In summary, while silicon and diamond have similar crystal structures, they have different physical and chemical properties due to the differences in their atomic size, electronegativity, and band gap.

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Answer:

Flash Flood

Explanation:

On July 31, 1976, during the celebration of Colorado's centennial, the Big Thompson Canyon was the site of a devastating flash flood that swept down the steep and narrow canyon, claiming the lives of 143 people, 5 of whom were never found.

Besides density, the physical properties that can you use to confirm that the gold is indeed real gold are the conduction of heat and electricity, malleability, ductility, lustrous nature, ductility, etc.

Gold is a type of chemical element which is classified into the category of precious metal. In the modern periodic table, it belongs to Group 11 and period 6. The chemical symbol which represents gold is Au.

The conduction of a test in order to confirm the identity of a given sample of gold is as follows:

Therefore, apart from density, several other physical properties are also used to confirm that the gold is indeed real gold.

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The reaction of 1-ethylcycloheptene with MCPBA (meta-chloroperoxybenzoic acid) followed by sodium methoxide in methanol leads to the formation of an epoxide.

MCPBA is a peracid that is commonly used to convert alkenes into epoxides through an epoxidation reaction. It adds an oxygen atom to the double bond of the alkene, resulting in the formation of an oxirane ring.

In this case, when 1-ethylcycloheptene reacts with MCPBA, an epoxide is formed. The specific product will depend on the regiochemistry and stereochemistry of the starting compound. Without further information on the exact structure and conditions of the reaction, it is difficult to determine the exact product.

However, the general product can be represented as an epoxide derived from 1-ethylcycloheptene:

Epoxide

1−ethylcycloheptene+MCPBA+NaOMe/MeOH→Epoxide

The exact position and stereochemistry of the epoxide ring would be determined by the specific structure of 1-ethylcycloheptene and the reaction conditions used.

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The medication can treat people who have the disease described. According to the commercial, the drug has FDA approval to treat a condition whose symptoms are listed.

Additionally, the narrator notes that the medication only comes with a prescription and has 1% of the active substance. We can deduce from this information that the drug can effectively treat persons who have the condition generating these symptoms, but obtaining it requires a prescription. The commercial provides no support for the other possibilities.

Therefore, the correct option is D.

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answer is simple to is iron

The regular use of a car causes the exhaust pipe to rust more quickly owing to heat, moisture, and environmental variables. Vegetables cook more quickly and with better flavour when they have been chopped because it increases surface area.

The exhaust system is frequently directly exposed to snow, ice, and salt while you drive during the winter because of its placement. With time, this mixture causes the undercarriage of your automobile to corrode quickly.

To ensure your safety and the functionality of your car, the exhaust system directs the dangerous exhaust gases away from the engine and the cabin. Although reducing emissions is the main goal, a proper exhaust system will also accomplish this.

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Answer:

H2 + CuO======Cu + H2O

Explanation:

Cu is copper

H is hydrogen

H2O is water

O is oxygen

CuO is copper 11 oxide

Answer:

\({ \bf{H _{2(g)} + CuO _{(s)} → Cu _{(s)} + H _{2} O _{(g)} }}\)

It's balancing, hope it helps

Answer:  A. 28

If we aren't talking about an isotope, then the number of neutrons and the number of protons in the nucleus are the same. Each proton weighs one atomic unit, and the same can be said about a neutron as well. So half of the weight is from the protons and half is from the neutrons. The electrons are extremely small relative to the protons that their weight is negligible.

Most hydrocarbons in the atmosphere in rural areas arise from evaporation of gasoline. The correct answer is option (B).

While automobiles and industrial emissions can contribute to hydrocarbons in the atmosphere, studies have shown that in rural areas, the largest contributor is typically the evaporation of gasoline from fuel storage and use.Evaporation of gasoline is a significant source of hydrocarbon emissions in rural areas. Gasoline contains volatile hydrocarbons that can evaporate into the atmosphere, especially during refueling, storage, and other handling processes. This process releases hydrocarbons such as volatile organic compounds (VOCs) into the air.

Additionally, agricultural activities in rural areas can also contribute to hydrocarbon emissions. Certain agricultural practices, such as the use of certain fertilizers and livestock management, can release hydrocarbons into the atmosphere. This is due to the use of gasoline-powered equipment and vehicles, which can release hydrocarbons into the atmosphere through exhaust as well as evaporation from fuel tanks and spills. Hence option (B) is the correct answer.

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Answer:

Propane

Explanation:

Answer:

A noble gas configuration of an atom consists of the elemental symbol of the last noble gas prior to that atom, followed by the configuration of the remaining electrons. So for sodium, we make the substitution of [Ne] for the 1s22s22p6 part of the configuration. Sodium's noble gas configuration becomes [Ne]3s1. That is the answer.

Explanation:

Brainliest Please.

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wpazsebu

The molar mass of insulin is approximately 0.798 g/mol, calculated using the equation for osmotic pressure and the given values of mass and volume.

To calculate the molar mass of insulin, we can use the equation for osmotic pressure:

π = (n/V)RT

where π is the osmotic pressure, n is the number of moles of solute, V is the volume of the solution in liters, R is the ideal gas constant, and T is the temperature in Kelvin.

First, convert the given values to appropriate units:

25.0 mg = 0.025 g
5.00 mL = 0.005 L

Next, rearrange the equation to solve for n (number of moles):

n = (πV) / (RT)

Substituting the given values:

n = (15.5 mmHg * 0.005 L) / ((0.0821 L·atm/(mol·K)) * 298 K)

Calculate n:

n ≈ 0.0313 mol

Finally, divide the mass of insulin (0.025 g) by the number of moles (0.0313 mol) to find the molar mass:

Molar mass = 0.025 g / 0.0313 mol

Molar mass ≈ 0.798 g/mol

So, the molar mass of insulin is approximately 0.798 g/mol.


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The major 1,2- and 1,4-addition products formed when a diene reacts with HBr are as follows:

1. For the 1,2-addition product: The diene reacts with HBr, and one of the double bonds undergoes addition with the hydrogen of HBr at the 1,2-position. This results in the formation of a monosubstituted alkyl bromide.

2. For the 1,4-addition product: The diene reacts with HBr, and the two double bonds undergo a concerted reaction with HBr. This leads to the formation of a cyclohexane ring, with the bromine atom attached at the 1,4-position.

In the 1,2-addition product, the HBr adds directly to one of the double bonds, resulting in a monosubstituted alkyl bromide. This is known as the Markovnikov addition. On the other hand, in the 1,4-addition product, the diene undergoes a concerted reaction, where both double bonds react simultaneously with HBr.

This results in the formation of a cyclohexane ring with the bromine atom attached at the 1,4-position. The 1,4-addition product is known as the anti-Markovnikov addition. The selectivity of these additions is determined by the stability of the carbocation intermediate formed during the reaction.

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Answer:

chemical

Explanation:

Answer:

A: Chemical

Explanation:

I hope this helps

Ag+ ions are often chosen as a tracer because they are relatively easy to detect and analyze.

In a diffusion in a solid experiment, the purpose of introducing Ag+ (silver ions) is to serve as a tracer or marker to track the diffusion process within the solid material. diffusion refers to the movement of particles or molecules from an area of higher concentration to an area of lower concentration. In solid materials, diffusion typically occurs at a much slower rate compared to liquids or gases. By introducing Ag+ ions into the solid material, researchers can monitor the movement and spread of these ions over time, which provides insights into the diffusion behavior of other species or elements within the solid.Researchers can use various analytical techniques such as spectroscopy or microscopy to measure the concentration and distribution of Ag+ ions at different points within the solid material. By studying the diffusion of Ag+ ions, researchers can gain valuable information about the diffusion mechanisms, pathways, and rates within the solid, which can have implications in materials science, engineering, and other fields of study.

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Explanation:

A compound's empirical formula tells you the smallest whole number ratio ,The molar mass tells you what the total mass of one mole

Answer:

0.50 mols Ag

Explanation:

Given the data, we have:

mass= 54g

molar mass of Silver (Ag): 107.8 g/mol

We want moles, we can convert grams > moles using the molar mass as a "bridge" between the 2.

\(54g * \frac{1 mol}{107.8 g}= 0.50 mols Ag\)

Keeping an eye on the units, we'll see 54g get cancelled out by 107.8 g/mol and we'll be left with moles of Silver.

When a sucrose, is added to a solvent, it affects the boiling point of the solvent. This phenomenon is known as boiling point elevation.

Given information,

Mass of water = 1 kg

Moles of sucrose = 2 mol

The boiling point elevation: ΔTb = Kb × m

Where:

ΔTb is the change in boiling point and Kb is the molal boiling point elevation constant, and m is the molality of the solute.

m = (number of moles of solute) / (mass of solvent in kg)

m = 2.0 mol / 1.0 kg = 2.0 mol/kg

The value of Kb for water is approximately 0.512 °C/m.

Now, (ΔTb):

ΔTb = Kb × m

ΔTb = 0.512 °C/m × 2.0 mol/kg

ΔTb = 1.024 °C

Therefore, when 2.0 mol of sucrose is added to 1.0 kg of water, the boiling point of the water will increase by approximately 1.024 °C.

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The estimated temperature at the center of the Sun is approximately 2.23 × 10¹⁵ Kelvin.

To calculate the temperature at the center of the Sun using the ideal gas law, we can use the following equation:

PV = nRT

Where; P = Pressure

V = Volume

n = Number of moles of gas

R = Ideal gas constant

T = Temperature

Given;

Molar mass (average) = 2.00 g/mol

Density = 1.4 g/cm³

Pressure = 1.3 × 10⁹ atm

Convert density to molar volume.

To do this, we need to calculate the molar volume (V_m) using the molar mass (M) and density (ρ) relationship

V_m = M/ρ

V_m = 2.00 g/mol / 1.4 g/cm³

V_m ≈ 1.43 cm³/mol

Convert pressure to SI units (Pascal).

1 atm = 101325 Pa

Pressure (P) = 1.3 × 10⁹ atm × 101325 Pa/atm

P ≈ 1.317 × 10¹⁴ Pa

Calculate the number of moles of gas.

Using the molar volume and the density, we can calculate the number of moles (n) of gas in the given volume

n = V / V_m

n = 1 cm³ / 1.43 cm³/mol

n ≈ 0.699 moles

Plug in the values into the ideal gas law and solve for temperature (T).

PV = nRT

T = PV / nR

T = (1.317 × 10¹⁴ Pa) × (1 cm³) / (0.699 moles × 8.314 J/(mol×K))

T ≈ 2.23 × 10¹⁵ K

Therefore, the temperature will be 2.23 × 10¹⁵ Kelvin.

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It takes 24 years for 16.0 ng of tritium to decay to the point where 2.0 ng remains.

Tritium has a half-life of 12 years, which means that in each 12-year period, half of the tritium atoms will decay. To calculate the time it takes for a specific amount of tritium to decay, we can use the concept of half-life.

Step 1:

In the first 12 years, half of the tritium will decay, leaving 8.0 ng remaining (16.0 ng / 2).

Step 2:

In the next 12 years (the second half-life), half of the remaining tritium will decay again, leaving 4.0 ng (8.0 ng / 2).

Step 3:

Continuing this pattern, after another 12 years (the third half-life), we have 2.0 ng remaining (4.0 ng / 2).

Therefore, it takes 24 years for 16.0 ng of tritium to decay to the point where 2.0 ng remains.

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Answer:

Number of electrons differ from one elements to other elements .means that each elements have different numbers of electrons

for ex Hydrogen has only one electron whereas helium has 2 electrons

Number of electrons = Atomic number

Atomic number of an element tells the no. of electrons in it.

For ex

Hydrogen ( atomic no. 1 ) ---- 1 electron

helium ( atomic no 2 ) ---- 2 electron

Lithium (atomic no.3 ) ---- 3 electron

The term "Lewis base" refers to a molecule or ion that can donate a pair of electrons to form a coordinate bond with a metal or metalloid center. In the given options, CH3NH2 (methylamine) is a Lewis base because it has a lone pair of electrons on the nitrogen atom that can act as a donor. BeCl2 (beryllium chloride) can also act as a Lewis base because it has two empty orbitals that can accept a pair of electrons from a Lewis acid.

Therefore, options C and E are correct, and the answer is either C) CH3NH2, BeCl2 or E) CH3NH2 only, depending on whether BeCl2 is considered a Lewis base or not. Cr3+ and SO3 are not Lewis bases because they do not have any lone pair of electrons to donate.

A Lewis base is a molecule or ion that can donate an electron pair to form a coordinate covalent bond with a Lewis acid. Among the given options, we need to find which ones can act as a Lewis base.

Cr3+ is a cation and does not have an electron pair to donate, so it cannot act as a Lewis base.

SO3 is a molecule with all its oxygen atoms double-bonded to the sulfur atom, so it does not have any lone pair to donate, and thus, cannot act as a Lewis base.

CH3NH2 (methylamine) has a lone pair of electrons on the nitrogen atom, making it a good candidate to donate an electron pair and act as a Lewis base.

BeCl2 is an electron-deficient molecule and would rather accept a lone pair of electrons, acting as a Lewis acid, not a base.

Considering these explanations, the correct answer is:

E. CH3NH2 only

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