Analyze the data to identify the mathematical relationship between the
amplitude and energy of a mechanical wave. If mechanical wave A has an
amplitude of 4 cm and mechanical wave B has an amplitude of 5 cm, what
will be the relationship between the energy carried by the two waves?
Amplitude
Energy
A. Wave A has about 1.25 times more energy than wave B.
ОО
B. Wave A has about 1.6 times more energy twan wave B.
C. Wave B has about 1.6 times more energy than wave A.
O D. Wave A has about 1.15 times more energy than wave B.
Answers
Answer:
Its C
Explanation:
Because I got it wrong for you
Wave B has about 1.6 times more energy than wave A.
What is energy?
Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
The amplitude and energy of a mechanical wave. If mechanical wave A has an amplitude of 4 cm and mechanical wave B has an amplitude of 5 cm wave B has about 1.6 times more energy than wave A.
Wave B has about 1.6 times more energy than wave A.
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Related Questions
Describe how radiant energy, light energy, and solar energy are related. ( Please ❤️ )
Answers
Answer:
L’énergie solaire récolte l’énergie radiante portée par la lumière de notre soleil en la convertissant en électricité.Biomasse des plantes. Les plantes sont capables d’exploiter et d’utiliser l’énergie lumineuse dans un processus appelé photosynthèse.
Answer:
Radiant energy, light energy, and solar energy are related because The Sun produces a lot of radiant energy that is transmitted to Earth as light. Plants convert the electromagnetic energy in sunlight into chemical energy for their food, through a process called photosynthesis. Waves of radiant electromagnetic energy can be visible or invisible.
Explanation:
A 1.10-kg object slides to the right on a surface having a coefficient of kinetic friction 0.250 (Figure a). The object has a speed of vi = 2.60 m/s when it makes contact with a light spring (Figure b) that has a force constant of 50.0 N/m. The object comes to rest after the spring has been compressed a distance d (Figure c). The object is then forced toward the left by the spring (Figure d) and continues to move in that direction beyond the spring's unstretched position. Finally, the object comes to rest a distance D to the left of the unstretched spring (Figure e).
The right end of a horizontal spring labeled k is attached to a wall. Five images show five configurations as a block labeled m approaches, compresses, and then moves away from the spring.
In figure a, the block is to the left of the spring, and an arrow above the block points to the right.
In figure b, the block is just touching the uncompressed spring, and an arrow labeled vector vi above the block points to the right.
In figure c, the block has compressed the spring by a distance d, and a label indicates vector vf = 0.
In figure d, the block is just touching the uncompressed spring, and an arrow labeled vector v above the block points to the left.
In figure e, the block is a distance D away from the spring, and a label indicates vector v = 0.
(a)
Find the distance of compression d (in m).
m
(b)
Find the speed v (in m/s) at the unstretched position when the object is moving to the left (Figure d).
m/s
(c)
Find the distance D (in m) where the object comes to rest.
m
(d)
What If? If the object becomes attached securely to the end of the spring when it makes contact, what is the new value of the distance D (in m) at which the object will come to rest after moving to the left?
m
Answers
Answer:
(a) Approximately \(0.335\; \rm m\).
(b) Approximately \(1.86\; \rm m\cdot s^{-1}\).
(c) Approximately \(0.707\; \rm m\).
(d) Approximately \(0.228\; \rm m\).
Explanation:
\(v_i\) denotes the velocity of the object in the first diagram right before it came into contact with the spring. Let \(m\) denote the mass of the block. Let \(\mu\) denote the constant of kinetic friction between the object and the surface. Let \(g\) denote the constant of gravitational acceleration.Let \(k\) denote the spring constant of this spring.(a)Consider the conversion of energy in this object-spring system.
First diagram: Right before the object came into contact with the spring, the object carries kinetic energy \(\displaystyle \frac{1}{2}\, m \cdot {v_{i}}^2\).
Second diagram: As the object moves towards the position in the third diagram, the spring gains elastic potential energy. At the same time, the object loses energy due to friction.
Third diagram: After the velocity of the object becomes zero, it has moved a distance of \(D\) and compressed the spring by the same distance.
Energy lost to friction: \(\underbrace{(\mu \cdot m \cdot g)}_{\text{friction}} \cdot D\). Elastic potential energy that the spring has gained: \(\displaystyle \frac{1}{2}\,k\, D^2\).The sum of these two energies should match the initial kinetic energy of the object (before it comes into contact with the spring.) That is:
\(\displaystyle \frac{1}{2}\, m \cdot {v_{i}}^{2} = (\mu\cdot m \cdot g) \cdot D + \frac{1}{2}\, k \cdot D^2\).
Assume that \(g = 9.81\; \rm m \cdot s^{-2}\). In the equation above, all symbols other than \(D\) have known values:
\(m =1.10\; \rm kg\).\(v_i = 2.60\; \rm m \cdot s^{-1}\).\(\mu = 0.250\).\(g = 9.81\; \rm m \cdot s^{-2}\).\(k = 50.0\; \rm N \cdot m^{-1}\).Substitute in the known values to obtain an equation for \(D\) (where the unit of \(D\!\) is \(m\).)
\(3.178 = 2.69775\, D + 25\, D^2\).
\(2.69775\, D + 25\, D^2 + 3.178 = 0\).
Simplify and solve for \(D\). Note that \(D > 0\) because the energy lost to friction should be greater than zero.
\(D \approx 0.335\; \rm m\).
(b)The energy of the object-spring system in the third diagram is the same as the elastic potential energy of the spring:
\(\displaystyle \frac{1}{2}\,k\, D^2 \approx 2.81\; \rm J\).
As the object moves to the left, part of that energy will be lost to friction:
\((\mu \cdot m \cdot g) \, D \approx 0.905\; \rm J\).
The rest will become the kinetic energy of that block by the time the block reaches the position in the fourth diagram:
\(2.81\; \rm J - 0.905\; \rm J \approx 1.91\; \rm J\).
Calculate the velocity corresponding to that kinetic energy:
\(\displaystyle v =\sqrt{\frac{2\, (\text{Kinetic Energy})}{m}} \approx 1.86\; \rm m \cdot s^{-1}\).
(c)As the object moves from the position in the fourth diagram to the position in the fifth, all its kinetic energy (\(1.91\; \rm J\)) would be lost to friction.
How far would the object need to move on the surface to lose that much energy to friction? Again, the size of the friction force is \(\mu \cdot m \cdot g\).
\(\displaystyle (\text{Distance Travelled}) = \frac{\text{(Work Done by friction)}}{\text{(Size of the Friction Force)}} \approx0.707\; \rm m\).
(d)Similar to (a), solving (d) involves another quadratic equation about \(D\).
Left-hand side of the equation: kinetic energy of the object (as in the fourth diagram,) \(1.91\; \rm J\).
Right-hand side of the equation: energy lost to friction, plus the gain in the elastic potential energy of the spring.
\(\displaystyle {1.91\; \rm J} \approx (\mu\cdot m \cdot g) \cdot D + \frac{1}{2}\, k \cdot D^2\).
\(25\, D^2 + 2.69775\, D - 1.90811\approx 0\).
Again, \(D > 0\) because the energy lost to friction is greater than zero.
\(D \approx 0.228\; \rm m\).
The energy transferred between the object and the spring as a closed system, therefore, conserved are;
(a) The distance of compression, d ≈ 0.3354 meters
(b) The speed in the un-stretched position wen the object is sliding to the left, v ≈ 1.8623 m/s
(c) The distance where the object comes to rest, D ≈ 0.7071 m
(d) The distance the object will come to rest attached to the spring, D ≈ 0.2278 m
The reason the above values are correct are as follows;
The known parameters are;
Mass of the object, m₁ = 1.10 kg
Coefficient of friction, μ = 0.250
The initial speed of the object, \(v_i\) = 2.60 m/s
Force constant of the spring, K = 50.0 N/m
Distance the spring is compressed by the object = d
(a) Conservation of energy principle
\(Kinetic \ energy = \dfrac{1}{2} \cdot m\cdot v^2\)
Work done = Force × Distance
Friction force, \(F_f\) = W × μ
Weight, W = m·g
Weight = Mass × Acceleration
Energy transferred by object = Work done by spring + Work done by friction
\(Energy \ transferred \ by \ object = Kinetic \ energy = \dfrac{1}{2} \times 1.10\times 2.60^2 = 3.718\)
Energy transferred by object = 3.718 J
\(Work \ done \ by \ spring = \dfrac{1}{2} \cdot k\cdot x^2\)
\(Work \ by \ spring \ to \ bring \ object \ to \ rest, \ W_{spring} = \dfrac{1}{2} \times 50\times d^2\)
\(W_{spring}\) = 25·d²
Work done by friction, \(W_{friction}\) = 1.10×9.81×0.250×d = 2.69775·d
Therefore;
3.718 = 25·d² + 2.69775·d
25·d² + 2.69775·d - 3.718 = 0
Solving gives
The distance of the compression d ≈ 0.3354 m
(b) The energy given by the spring = 25·d²
The work done by friction, \(W_{friction}\) = 2.69775·d
Kinetic energy given to object = 0.55·v²
0.55·v² = 25·d² - 2.69775·d
0.55·v² = 25×0.3354² - 2.69775×0.3354
∴ v = √(3.4682) = 1.8623
The velocity of the object at the un stretched position, v ≈ 1.8623 m/s
(c) The kinetic energy, K.E. of the object on the way left is given as follows;
K.E. = 0.5 × 1.10 kg × 3.4682 m²/s² = 1.90751 J
The work done by friction before object comes to rest = 2.69775·D
\(D = \dfrac{1.90751 \, J}{2.69775 \, N} \approx 0.7071 \, m\)
The distance where the object comes to rest, D ≈ 0.7071 m
(d) The work done on spring, \(W_{spring}\) = 25·D'²
Work done on friction, \(W_{friction}\) = 2.69775·D'
Kinetic energy of object, K.E. ≈ 1.90751 J
K.E. = \(W_{spring}\) + \(W_{friction}\)
1.90751 ≈ 25·D'² + 2.6775·D'
25·D'² + 2.6775·D' - 1.90751 = 0
Solving with a graphing calculator gives;
D' ≈ 0.2278 m
The new value of the distance D = 0.2278 m
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Please help!!! I will give brainliest,
Answers
Answer:
C. a liter of salt water.
Explanation:
Defination of Solution =>
a liquid mixture in which the minor component (the solute) is uniformly distributed within the major component (the solvent).
Two objects are held close together. When they are released, they move toward one another. Which conclusion is supported by this evidence? O The objects are both positively charged. O The objects are both negatively charged. O The objects have no charge. O The objects have opposite charges. Mark this and return Save and Exit 02:48:18 Next Submit
Answers
Two objects are held close together. When they are released, they move toward one another. The conclusion is supported by this evidence is the objects have opposite charges.
An electric charge is a physical property that causes matter to experience a force when in close proximity to other electrically charged matter. There are two types of electric charges: positive and negative. Protons, which are positively charged, and electrons, which are negatively charged, are subatomic particles that make up matter.
In general, the protons and neutrons in the nucleus of an atom have a net positive charge, while electrons, which orbit the nucleus, have a net negative charge. The charges of these subatomic particles are indicated by the symbols "p" for proton, "n" for neutron, and "e" for electron.
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Saturn is moving with uniform angular speed of 2πf along the circumference of it's orbit around the sun with radius R, having centre O. At any time, the angular position of Saturn is (2πf)t and the displacement in SHM at that time t is given by x(t)=Rcos(2πf)t. Find it's acceleration.
Answers
Answer:Sir haymo knows
Explanation:
he gave as homework
The acceleration of the Saturn is - (2πf)²x(t).
What is Simple harmonic motion?A motion in which the restoring force is directly proportional to the body's displacement from its mean position is known as a simple harmonic motion, or SHM. This restoring force always moves in the direction of the mean position. A particle moving in simple harmonic motion accelerates as a(t) = - ω² x (t). Here, ω denotes the particle's angular velocity.
The acceleration of the particle at any position is directly proportional to the displacement from the mean position in simple harmonic motion, which is an oscillatory motion.
Given that:
at any time, the angular position of Saturn is (2πf)t.
the displacement in SHM at that time t is given by x(t)=R cos(2πf)t.
Hence, speed in SHM at that time t is given by
\(v(t) = \frac{dx(t)}{dt} =R \frac{d }{dt} cos(2\pi f)t = -(2\pi f) sin(2\pi f)t\)
it's acceleration is
\(a(t) = \frac{dv(t)}{dt} =-(2\pi f) R \frac{d }{dt} sin(2\pi f)t = -(2\pi f)^2 Rcos(2\pi f)t = -(2\pi f)^2 x(t)\)
hence, at any time t, the acceleration of the Saturn is - (2πf)²x(t).
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A
cook
holds a 3.2 kg carton of milk at arm's length.
75.9
w
25,5 cm
What force FB must be exerted by the bi-
ceps muscle? The acceleration of gravity is
9.8 m/s2. (Ignore the weight of the forearm.)
Answer in units of N.
Answers
Answer:
Explanation:
From the given information:
From the rotational axis, the distance of the force of gravity is:
d_g = 25+5.0 cm
d_g = 30.0 cm
d_g = 30.0 × 10⁻² m
However, the relative distance of FB cos 75.9° from the axis is computed as:
d_B = 5.0 cm
d_B = 5.0 × 10⁻² m
The net torque rotational equilibrium = zero (0)
i.e.
\(\tau_g -\tau_B = 0 \\ \\ F_gd_g -F_gcos 75.9^0 d_B = 0 \\ \\ F_B = \dfrac{F_g d_g}{F_g cos 65.6} \\ \\ F_B = \dfrac{(3.2)(9.8)(30*10^{-2})}{(5.0*10^{-2} * cos 75.9)} \\ \\ \mathbf{F_B = 772.4 N}\)
= 772.4 N
Thus, the force exerted = 1772.4 N
5
Select the correct answer.
What is the current in a parallel circuit which has two resistors (17.2 ohms and
22.4 ohms) and a power source of 6.0 volts?
ОА.
0.30 amps
OB.
9.8 amps
OC.
0.61 amps
D.
1.2 amps
Reset
Next
Answers
Answer:
Current in a parallel circuit = 0.61 amps (Approx)
Explanation:
Given:
Voltage V = 6 volt
Two resistors = 17.2 , 22.4 in parallel circuit
Find:
Current in a parallel circuit
Computation:
1/R = 1/r1 + 1 / r2
1/R = 1/17.2 + 1 / 22.4
R = 9.73 ohms (Approx)
Current in a parallel circuit = V / R
Current in a parallel circuit = 6 / 9.73
Current in a parallel circuit = 0.61 amps (Approx)
A dog walks 50m east and then 23 m west. What is the displacement
Answers
The dog's displacement is 27m towards east.
What is displacement?
Displacement is the distance between two points in a given space. It is a vector quantity that measures the difference between the initial and final positions of an object. Displacement is the shortest distance between two points and it is always directed from the initial position to the final position. It is measured in meters, centimeters, or other units of length. Displacement is related to velocity, which is the rate at which an object changes its position over time, and acceleration, which is the rate of change in velocity. Displacement can also be used to measure the progress of a boat, the length of a journey, or the distance between two cities.
The dog starts its journey towards east for 50m and then goes in the opposite direction (west) towards the starting point for 23m. Hence the distance is 50 - 23 = 27.
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The current source has an EMF of 14 V and an internal resistance of 1Ω. Two resistors with resistances of 3Ω are connected to the current source. How much current flows in the circuit?
Answers
Answer:
Explanation:
To find the current flowing in the circuit, we can use Ohm's Law and Kirchhoff's circuit laws.
Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):
I = V / R
In this case, the voltage (V) is the electromotive force (EMF) of the current source, which is 14 V. The total resistance (R) in the circuit is the sum of the internal resistance (r) and the resistances of the two resistors (R1 and R2):
R = r + R1 + R2
Given that the internal resistance (r) is 1Ω and each resistor (R1 and R2) has a resistance of 3Ω, we can substitute these values into the equation:
R = 1Ω + 3Ω + 3Ω = 7Ω
Now we can calculate the current (I):
I = V / R = 14 V / 7Ω = 2 A
Therefore, the current flowing in the circuit is 2 Amperes.
A ball is projected at an angle of 53°. If the initial velocity is 48 meters/second, what is the vertical component of the velocity with which it was launched?
A.) 31 meters/second
B.) 38 meters/second
C.) 44 meters/second
D.) 55 meters/second
Answers
Answer:
The vertical component of the velocity can be found using the formula:
V₀y = V₀ * sin(θ)
where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.
Substituting the given values, we have:
V₀y = 48 * sin(53°)
Using a calculator, we can evaluate sin(53°) to be approximately 0.799:
V₀y = 48 * 0.799
V₀y ≈ 38.352
Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.
Answer:
B.) 38 meters/second
Explanation:
1. Which of the choices will make a brass band?
A. Angklung
B. Bumbong, Kalatok, Tongatong
C. Bamboo, woodwind instrument
D. Woodwind, percussion, brass wind
2. Which is a woodwind instrument?
A. Bass Drum
B. Cymbals
C. Flute
D. Snared Drum
3. Which is a percussion instrument?
A. Bass Drum
B. Flute
C. Sousaphone
D. Trombone
Answers
Explanation:
1.
C. Bamboo woodwind instrument
2.
C. Flute
3.
A. Bass Drum
how is newtons first law of motion related to the concept of inertia?
Answers
Using something as a medium of exchange in transactions (money)
Answers
We can use currency as a medium of exchange in transactions because of its easy availability.
What is the basic medium of exchange for transaction?Currency is the most common medium of exchange accepted as a standard by all parties for settling economic transactions because every region or country has its specific type of currency in which they do transactions and carried out their economic activities world wide. Currency is also considered as a medium of exchange for goods and services. It is money that is present in the form of paper and coins which is issued by a government. Currency is generally accepted because of high value as a method of payment. U.S. dollars ($), euros (€), Japanese yen (¥), and pounds sterling (£) are the examples of currencies of different countries around the world.
So we can conclude that We can use currency as a medium of exchange in transactions because of its easy availability.
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You are a passenger in a truck that gets stuck in mud. You and the driver use a tree branch as a lever to lift up the truck. You apply an effort force of 600 N to the branch. The back of the truck weighs 2400 N. What is the mechanical advantage of the branch-lever?
Answers
The truck's cargo weighs 2400 N. The department has a mechanical advantage of 4.
What do mechanical talents entail?Combining hard and soft abilities in areas like arithmetic, computing, design, and interaction make up the talents required for mechanical engineering. Because they operate in a variety of fields, such as the manufacturing, science, and automotive manufacturing, engineers in the mechanical technology profession have one of the broadest scopes.
What three categories of mechanical are there?Longitudinal, transversal, as well as pressure waves are the three different forms of physical phenomena. They differ based on how the medium's atomic constituents behave when the stage's energy goes through. Wind farms that are powered by steam, water, winds, gas, or hydrocarbons are a few examples of this. Other sources of energy are frequently produced through machinery.
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Applying a force of 20 N to a 0.4 kg puck as it slides along to frictionless surface from rest to 10 ms-1 in 0.2 s. Calculate the work done by the puck.A. 2000 JB. 200 JC. 20 J
Answers
Given,
The force applied on the puck, F=20 N
The mass of the puck, m=0.4 kg
The initial velocity of the puck, u=0 m/s
The final velocity of the puck, v=10 m/s
The time duration, t=0.2 s
The work done is given by the product of the force applied to the object and the distance to which the force was applied.
That is,
\(W=F\times d\text{ }\rightarrow\text{ (i)}\)Where d is the distance traveled by the puck.
From the equation of motion,
\(d=ut+\frac{1}{2}at^2\)Where a is the accleration of the puck due to the applied force F.
But, the puck was at rest initially. Therefore,
\(d=\frac{1}{2}at^2\text{ }\rightarrow\text{ (ii)}\)From Newton's second law of motion,
\(\begin{gathered} F=ma \\ \Rightarrow a=\frac{F}{m}\text{ }\rightarrow\text{ (iii)} \end{gathered}\)On substituting the equation (iii) in equation (ii),
\(\begin{gathered} d=\frac{1}{2}\times\frac{F}{m}\times t^2 \\ =\frac{Ft^2}{2m}\text{ }\rightarrow(\text{iv)} \end{gathered}\)On substituting equation (iv) in equation (i),
\(\begin{gathered} W=F\times\frac{Ft^2}{2m} \\ =\frac{F^2t^2}{2m} \end{gathered}\)On substituting the known values in the above equation,
\(\begin{gathered} W=\frac{20^2\times0.2^2}{2\times0.4} \\ =20\text{ J} \end{gathered}\)Therefore, the work done by the puck is 20 J
A machine is applying a torque to rotationally accelerate a metal disk during a manufacturing process. An engineer is using a graph of torque as a function of time to determine how much the disk’s angular speed increases during the process.
The graph of torque as a function of time starts at an initial torque value and is a straight line with positive slope. What aspect of the graph and possibly other quantities must be used to calculate how much the disk’s angular speed increases during the process?
Answers
The aspect of the graph and possibly other quantities must be used to calculate how much the disk’s angular speed increases during the process, the engineer must use the area under the graph of torque as a function of time and the disk's moment of inertia.
To calculate how much the disk’s angular speed increases during the process, the engineer must use the area under the graph of torque as a function of time and the disk's moment of inertia. The area under the graph represents the change in angular momentum, which is equal to the product of the disk's moment of inertia and the change in angular speed. By dividing the area under the graph by the disk's moment of inertia, the engineer can determine the increase in angular speed.
In mathematical terms, the change in angular speed can be calculated using the following equation:
Δω = (1/I) ∫τ dt
Where,
Δω is the change in angular speed
I is the moment of inertia of the disk
τ is the torque, and
t is time.
Therefore, the engineer must use the area under the graph of torque as a function of time and the disk's moment of inertia to calculate how much the disk’s angular speed increases during the process.
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Leticia leaves the grocery store And walks 150 M’s to parking lot then she turns 90° to the right and walks an additional 70 M’s to her car what is the magnitude of displacement of her car from the grocery store at exit
Answers
Answer:
Explanation:
Its 165.5m
In terms of electric pressure, describe a charged capacitor.
Answers
Answer: The capacitor is fully charged when the voltage of the power supply is equal to that at the capacitor terminals. This is called capacitor charging; and the charging phase is over when current stops flowing through the electrical circuit.
It is the source and summit of the whole Christian Life."
Answers
Answer:
CRISTO
Explanation:
UWU
Answer:
The Eucharist
Explanation:
In The Catechism of the Catholic Church (1324-1327), it states that The Eucharist is the source and summit of the whole Christian Life.
A 12 V battery is connected to a device and 24 mA of current is measured. If the device obeys Ohm's law, how much current is present when a(n) 108 V battery is used?
Answers
Answer:
Correct answer: Ic₂ = 48 mA = 48 · 10⁻³ A
Explanation:
U₁ = 12 V DC first battery voltage
Ic₁ = 24 mA = 24 · 10⁻³ A Intensity of current with the first battery
U₂ = 24 V DC second battery voltage
Ic₂ = ? Intensity of current with the second battery
The formula that applies to a simple electric circuit under the Ohm's law is:
R = U / Ic
where R is the total resistance in the electrical circuit and it is constant.
R = U₁ / Ic₁ = U₂ / Ic₂ ⇒ U₁ / Ic₁ = U₂ / Ic₂ ⇒ Ic₂ = (U₂ · Ic₁) / U₁
Ic₂ = (24 · 24) / 12 = 48 mA
Ic₂ = 48 mA = 48 · 10⁻³ A
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Explain why force, acceleration, and velocity are vectors.
Answers
Answer:
simply because they all have direction
Explanation:
vector quantities are quantities which have both magnitude and direction.Force,acceleration and velocity have both magnitude and direction.
The mass of the moon is 7.2 × 10^22 kg and its radius is 1.7×10^6 m.What will be the gravity of the moon to a body of the mass 1 kg on the surface of the moon.
Answers
Answer:
1.66 N
Explanation:
The force of gravity of the moon on the body is given by
F = GMm/R² where G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of moon = 7.2 × 10²² kg, m = mass of body = 1 kg and R = radius of moon = 1.7 × 10⁶ m
Substituting the values of the variables into the equation, we have
F = GMm/R²
F = 6.67 × 10⁻¹¹ Nm²/kg² × 7.2 × 10²² kg × 1 kg/(1.7 × 10⁶ m)²
F = 48.024 × 10¹¹ Nm²/2.89 × 10¹² m²
F = 16.62 × 10⁻¹ N
F = 1.662 N
F ≅ 1.66 N
So, the gravity on the moon is 1.66 N
An ant is crawling along a straight wire, which we shall call the x axis, from A to B to C to D (which overlaps A), as shown in the figure below. O is the origin. Suppose you take measurements and find that AB is 31 cm , BC is 12 cm , and AO is 7 cm .(Figure 1)
A. What is the ant’s position at point A?
B. What is the ant’s position at point B?
C. What is the ant’s position at point C?
D. What is the ant’s position at point D?
Answers
Answer:
Ants position at point A = -7 cm
Ants position at point B = 38 cm
Ants position at point C = 26 cm
Ants position at point D = -7 cm
Explanation:
In this question, we are dealing with displacement which is the change in position of an object.
Now, we are told the journey began from A to B and then from C to D.
Now, AB = 31 cm and AO = 7cm
But along AB, we have the origin O.
Since A is on the left hand side of the origin, it means it is negative. Thus, position A = -7cm
Then position B = 31 - (-7) = 31 + 7 = 38 cm
Since BC = 12cm, then position C = 38 - 12 = 26 cm
Position D is same as position A = -7cm
The Mars Rover Curiosity has a mass of 900 kg. Taking the gravitational field strength to be 9.8 N/kg
on Earth and 3.7 N/kg on Mars, give the value of the weight of the Rover on earth and mars
Answers
The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.
Weight of objects on Earth and on MarsThe weight of an object is given by the product of its mass and the gravitational field strength at its location.
On Earth:
Weight = mass x gravitational field strengthWeight = 900 kg x 9.8 N/kgWeight = 8820 NOn Mars:
Weight = mass x gravitational field strengthWeight = 900 kg x 3.7 N/kgWeight = 3330 NTherefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.
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Consider a regular solution, for which energy
w =5 kJ/mol
At what temperature, in K, will a miscibility limit emerge?
Answers
At room temperature,300 K, will a miscibility limit emerge. At the temperature less than, the miscibility will fall below 1%.
What is temperature?Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.
Hence, at room temperature,300 K, will a miscibility limit emerge. At the temperature less than, the miscibility will fall below 1%.
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A vector is 9.55m long and points in a -48.0 degree direction. find the x component
Answers
Answer:
x=6.39 m
Explanation:
Rectangular Components of a Vector
Vectors can be expressed in several forms, including the magnitude-angle form, and the rectangular-coordinates form.
If the magnitude r and angle β are given, we can find the rectangular coordinates (x,y) as follows:
\(x=r\cos\beta\)
\(y=r\sin\beta\)
The vector of the question has a magnitude of r=9.55 m and an angle β=-48°. The x-component is:
\(x=9.55\cdot\cos(-48^\circ)\)
Using a digital calculator:
x=6.39 m
The bulldog and skateboard have a combined mass of 20 kg. In case B (the middle of the three pictures of the bulldog and the well), the bulldog and skateboard have a KE of 380 J at the bottom of the well. How deep is the well in meters?
Answers
Answer:
h = 1.94 m
Explanation:
When the bull dog and skate board reach the bottom of the well, all of its potential energy is converted to the kinetic energy:
Kinetic Energy Gained by Bull Dog and Skate Board = Potential Energy Lost by Bull Dog and Skate Board
K.E = P.E
K.E = mgh
h = K.E/mg
where,
h = depth of well = ?
K.E = Kinetic Energy at bottom = 380 J
m = mass of bull dog and skate board = 20 kg
g = 9.8 m/s²
Therefore,
h = 380 J/(20 kg)(9.8 m/s²)
h = 1.94 m
You are standing outside with two speakers. The temperature is 0 degrees C. The two speakers are playing sound of the same frequency: a pure sinusoidal sound of the same frequency at the same phase. The speakers are playing at different amplitudes. One speaker is 1.230 meters from you and one is 1.425 meters from you. You hear no sound. Which of the following is a possible frequency of the sound being played?
a. 993 Hz
b. 331 Hz
c. 4965 Hz
d. 1655 Hz
e. 662 Hz
Answers
Answer:
Explanation:
No sound is heard , that means there is destructive interference at the place where sound is heard .
Path difference of the source of sound = 1.425 m - 1.230 m
= 0.195 m
Let frequency of sound be n .
wave length = velocity of sound at 0°C / n
λ = 330 / n
for destructive interference ,
path difference = ( 2m+1) λ /2 , where λ is wave length of sound.
0.195 m = ( 2m+1) λ /2
0.195 m = ( 2m+1)330 / 2n
2n = 1692.3 (2m+1)
If m = 0
n = 846 . which is nearest to given frequency of 993 Hz
So 993 Hz is the answer.
in coming to a stop, an old truck leaves skid marks 45 m long on the highway. assuming a deceleration of 6m/s2 , estimate the speed of the truck just before braking.
Answers
The speed of the truck just before braking is 23.24 m/s.
What is the speed of the clock before braking?
The speed of the truck before braking is calculated by applying the third kinematic equation as shown below.
v² = u² - 2as
where;
v is the final velocity of the truck when it stopsa is the acceleration of the trucks is the distance travelled by the truckWhen the truck stops, the final velocity = 0
0 = u² - 2as
u² = 2as
u = √2as
u = √ ( 2 x 6 x 45 )
u = 23.24 m/s
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As SCUBA divers go deeper underwater, the pressure from the weight of all the water above them increases tremendously which compresses the gases in their blood. What happens to the volume of gas in their blood as the diver rises quickly to the surface?
Answers
Answer:
The volume of gas in an early diving bell full of air at sea level is halved at 10 m according to Boyle’s law
Explanation:
;at 20 m pressure is 300 kPa absolute and the gas is compressed into one third the volume.
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