Using proportions, it is found that Ankita's share is of \(\frac{x}{4}\), considering that the total rent is of x Rp.r.
This question is solved by proportions, using a rule of three.Considering that there are 4 people and the rent is of x Rp.r, 4 people pay x, how much does Ankita, which is one person, pay?The rule of three is:
4 people - x
1 people - a
Applying cross multiplication:
\(4a = x\)
\(a = \frac{x}{4}\)
Ankita's share is of \(\frac{x}{4}\), considering that the total rent is of x Rp.r.
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7) Determine if the polynomials below are in the point polynomial time Justynach an! (points ==-+ 2022 in Riel (b) 3 points / 20021011.101 +2022 in C[x]. (c) 3 points] /= x+ 2022 in F7649[*] (Note that 7649 is prime. (d) pon-2 +3 in (e) [4 points] / -6° - 21x + 700 in Q[*]. (f) 14 points) f = 625x3 - 6633r2 + 86- 8855 in Qlur).
Let us check the given polynomials for point polynomial time as follows:
(a) Justynach an! (points ==-+ 2022 in Riel) This polynomial is not in point polynomial time because there is no condition on the polynomial and points.
(b) 3 points / 20021011.101 +2022 in C[x] This polynomial is not in point polynomial time because the given points are not on the polynomial.
(c) /= x+ 2022 in F7649[*] This polynomial is in point polynomial time because it is a monic polynomial and the given point is on the polynomial.
(d) pon-2 +3 This polynomial is not in point polynomial time because it is a constant polynomial and there are no points to verify.
(e) [4 points] / -6° - 21x + 700 in Q[*] This polynomial is in point polynomial time because all the points are on the polynomial.
(f) f = 625x3 - 6633r2 + 86- 8855 in Qlur. This polynomial is in point polynomial time because all the points are on the polynomial.
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Suppose each license plate in a certain state has three digits followed by three letters. The digits 4 and 5 are not used. So, there are 26 letters and 8 digits that are used. Assume that the letters and digits can be repeated. How many license plates can be generated using this format?
The required, there are 8998912 possible license plates that can be generated using this format.
Here, we have,
There are 8 digits that can be used for each of the three digits on the license plate, with two digits (4 and 5) that cannot be used.
Therefore, there are 8 choices for each of the three digits,
giving us 8 x 8 x 8 = 512 possible combinations for the digits.
Similarly, there are 26 letters that can be used for each of the three letters on the license plate.
Therefore, there are 26 choices for each of the three letters, giving us 26 x 26 x 26 = 17576 possible combinations for the letters.
Total number of license plates = number of choices for the digits x number of choices for the letters
= 512 x 17576
= 8998912
Therefore, there are 8998912 possible license plates that can be generated using this format.
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A 2-column table with 4 rows. Column 1 is labeled Time (minutes), x with entries 4, 5, 6, 7. Column 2 is labeled Bags Remaining, y with entries 36, 32, 28, 24.
Razi is filling bags with party favors for his birthday party. The table to the right shows the number of bags he still needs to fill after 4, 5, 6, and 7 minutes. If he is working at a constant rate, what was the initial number of party favor bags Razi had to fill?
36
48
52
56
Therefore, the initial number of party favor bags Razi had to fill is 20.
To determine the initial number of party favor bags Razi had to fill, we need to analyze the relationship between the time and the number of bags remaining.
Looking at the table, we can observe that the number of bags remaining decreases by 4 for every additional minute of work. This suggests a constant rate of filling the bags.
From the given data, we can see that at the starting time (4 minutes), Razi had 36 bags remaining. This implies that for each minute of work, 4 bags are filled.
To calculate the initial number of bags, we can subtract the number of bags filled in 4 minutes (4 x 4 = 16) from the number of bags remaining initially (36).
36 - 16 = 20
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1. explain how and why the area under a curve can be described using an integral. what is an integral??
4. The state of strain at the point on the bracket has components εx = 200(10-6), εy = -350(10-6), Yxy = 150(106). Use the strain-transformation equations to determine the equivalent in-plane strains on an element oriented at an angle of 40 degrees clockwise from the original position.
Therefore, the equivalent in-plane strains on an element oriented at an angle of 40 degrees clockwise from the original position are εx′= -98.05 × 10⁻⁶ and εy′= -407.38 × 10⁻⁶.
The strain transformation equation is given as:
εx′=εxcos2θ+εysin2θ+γxysin2θεy′
=εycos2θ+εxsin2θ−γxysin2θγxy′
=−12(εx−εy)sin2θ+γxycos2θ
Here, εx = 200(10-6),
εy = -350(10-6),
Yxy = 150(10-6).
θ = 40 degrees
The angle is measured clockwise from the original position.
Therefore,θ = -40° (measured anticlockwise)
cos θ = cos(-40)
= 0.7660
sin θ = sin(-40)
= -0.6428
εx′=εxcos²
θ+εysin^2 θ+γxy
sin2θ= 200 × (0.7660)² + (-350) × (0.6428)² + 150 × (0.7660) × (-0.6428)
= -98.05 × 10^-6εy′
=εycos² θ+εxsin² θ−γxysin2θ
= (-350) × (0.7660)² + 200 × (0.6428)² - 150 × (0.7660) × (-0.6428)
= -407.38 × 10⁻⁶γxy
=−12(εx−εy)sin2θ+γxycos2θ
= -0.5 × (200 + 350) × (0.7660) + 150 × (0.6428)
= 33.8 × 10⁻⁶
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6. What is the measure of ZDAB?
Answer:
118 degrees
Step-by-step explanation:
To solve this, you need to know some things.
There are 180 degrees in a straight line, and 180 degrees in a triangle (or a few other polygons).
If there are 180 degrees in a triangle, we can subtract the given degrees to find the missing degree.
180- 85 - 33 = 62
We can subtract that from 180 again, because we want to find the angle of the other side of the straight line of DAC, which is called supplementary angles (when two angles add up to 180 degrees or a straight line).
180 - 62 = 118
DAB is 118.
How are the properties of exponents used when dividing a polynomial by a monomial?
Answer:
a couple different obes
Step-by-step explanation:
there are five
which of the following statements is true about a rational function of the form where g and h are polynomial functions?
The true statement about the function is that (c) the domain of f(x) consists of all values of x such that g(x) does not equal 0 and h(x) does not equal 0.
How to determine the true statement of the function f(x)?The complete question is added at the end of this solution
From the complete question, we have the following equation
f(x) = g(x)/h(x)
The above equation means that
The function f(x) is the quotient of the functions g(x) and h(x)
For the function f(x) to have real values, the function h(x) must not equal 0
i.e. h(x) ≠ 0
This is so because
A number or an expression divided by 0 is not a real number
Hence, the true statement is that the domain of f(x) consists of all values of x where h(x) does not equal 0.
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Complete question
which of the following statements is true about a rational function of the form where g and h are polynomial functions?
A. If the rational function has a removable discontinuity, then it cannot have a vertical asymptote. g(x)
B. The rational function f(x) h(x) will have a removable discontinuity at x = a if g(a) = 0. g(x)
C. The domain of f(x) consists of all values of x such that g(x) does not equal 0 and h(x) does not equal 0.
D. If the rational function has a removable discontinuity, then it cannot have a horizontal asymptote.
Mr. Townsend needs to make 13 pairs of butterfly wings for costumes for a play. Each pair of
wings is made with 3/4 yard of fabric. The fabric costs $8 perlyard. You'll apply properties of
Multiplication in the following steps to find the total cost of fabric
Question: Use multiplication to write an expression for the amount of fabric needed to make 13 pairs of
wings.
Answer:
3/4 * 13 = 9.75
Step-by-step explanation:
if you need to make 13 pairs of wings and don't know how much fabric you need, you need to multiply 13 and 3/4 together to get the answer you want.
3/4 * 13 = ?
3/4 [divide 3 by 4] = 0.75
so 0.75 * 13 = 9.75
so you need 9.75 yards of fabric to create 13 pairs of wings.
as a fraction it would be I think -> 39/4
Hope this helps, and sorry if you get it wrong.
if you constructed 100 90% confidence intervals based on 100 different simple random samples of size n, how many of the intervals would you expect to include the unknown parameter?
90 intervals are expected to include the unknown parameter.
Given that,
If 100 separate simple random samples of size n were used to create 100 90% confidence intervals,
What is confidence interval ?
The mean of your estimate plus and minus the range of that estimate constitutes a confidence interval. This is the range of values you expect your estimate to fall within if you repeat the test, within a given level of confidence. Confidence is another name for probability in statistics.
90 % Confidence Interval means that we are 90% confident that true parameter lies between that interval.
If we construct 100, 90% confidence interval based on 100 random samples.
So, 90 of the intervals include the true parameter.
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The double number line shows that Balam has played 250 games of go.
Answer:
50 -> 20%
150 -> 60%
Step-by-step explanation:
50 is 20 % of the 250 games.
150 is 60 % of the 250 games.
What is percentage?Percentage is a part of the whole number. It is denoted by % sign.
1 %= 1/100.
Given that,
Total number of games = 250,
Also given that, percent value of 250 is 100%
Therefore, value of 50 is 20%
And value of 150 is 60%
50 is 20% and 150 is 60% of 250 games.
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A. Find the indicated number of geometric mean/s between the given two numbers.
1. 5 and 20 [ 1 term ]
2. 8 and 512 [2 terms]
3. 2 and 50 [ 1 term ]
4. 6 and 486 [3 terms]
5. 4 and 108 [2 terms]
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The ratio of the given terms is the common ratio raised to a power equal to the number of means plus 1.
1)For example, the common ratio in the sequence 5, __, 20 will be r, where ...
r^2 = 20/5 = 4 ⇒ r = 4^(1/2) = 2
Then the mean is found by multiplying 5 by this ratio: 5×2 = 10.
__
2-5)The same method is used for finding the common ratio and then the intermediate means. Each mean is the previous term multiplied by the common ratio. Results are summarized in the attached table.
_____
Additional comment
When there are a number of similar calculations to be done, it is convenient to let a spreadsheet do them.
Dados los puntos A(-7,2), B(-4,-2), hallar las ecuaciones de dos rectas que pasan por los puntos AP y BP que sean perpendiculares entre sí, sabiendo que el punto P se ubica sobre el eje de las abscisa.
La ecuación de las líneas son:
\(AP: y = -\frac{2}{7}x\)
\(BP: y = \frac{7}{2}x\)
-----------------------
La ecuación de una línea está dada por
\(y = mx + b\)
En que
m es la pendiente. Si dos líneas son perpendiculares, la multiplicación de sus pendientes es -1.-----------------------
Punto P se ubica sobre el eje de las abscisa, o sea, su coordenada y es 0, siendo P(x,0).Atribuyendo \(x = 0\), tiene-se P(0,0).En ambas ecuaciones, b = 0. La inclinación de AP, considerando los puntos A(-7,2) y P(0,0), viene dado por el cambio en y dividido por el cambio en x, por lo tanto:\(m = \frac{0 - 2}{0 - (-7)} = -\frac{2}{7}\)
La ecuación da la línea AP es:
\(AP: y = -\frac{2}{7}x\)
-----------------------
AP y BP son perpendiculares, puesto que:\(-\frac{2}{7}m = -1\)
\(m = \frac{7}{2}\)
La ecuación da la línea BP es:
\(BP: y = \frac{7}{2}x\)
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In an ABCAC research design, what does C refer to? a. a revised baseline b. a third study participant c. a new independent variable d. a new target behavior.
In an ABCAC research design, C refers to a new independent variable. The correct answer is option c. a new independent variable.
An ABCAC research design is a type of single-subject research design that is used to examine the effects of different independent variables on a target behavior. In this design, A refers to the baseline phase, B refers to the first intervention phase, and C refers to the second intervention phase. The purpose of the C phase is to introduce a new independent variable to see if it has an effect on the target behavior.
Therefore, in an ABCAC research design, C refers to a new independent variable that is introduced to examine its effect on the target behavior.
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A truck is being loaded with boxes and has a maximum capacity of 1000 lbs. According to the
scale 7 boxes weigh 114.1 lbs. How many boxes can the truck carry without going over its
weight capacity?
Answer:
8 total boxes
Step-by-step explanation:
Given the function defined in the table below, find the average rate of change, in
simplest form, of the function over the interval 5 ≤ x ≤9.
7
8
9
6
x
4
5
f(x)
4
8
16
32
64
medically explained PAINL X
128
Deltal/ath
The average rate of change, in simplest form, is -2/5.
What is average rate ?
Divide the change in y-values by the change in x-values to determine the average rate of change. Identifying changes in quantifiable parameters like average speed or average velocity calls for the knowledge of the average rate of change.
The rate of change of the function is its gradient or slope.
The formula for calculating the gradient of a function is expressed as:
\(m=\frac{d y}{d x}=\frac{y_2-y_1}{x_2-x_1}$$\)
Using the coordinate points from the table (0,41) and (15,35)
Substitute the coordinate into the expression:
\($$\begin{aligned}& m=\frac{35-41}{15-0} \\& m=\frac{-6}{15} \\& m=\frac{-2}{5}\end{aligned}$$\)
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HURRY I NEED THIS IN 20 mins please help me
Write an equation for the function g whose graph is the graph off
f(x) = -100(1.05)
translated to the right 5 units and up 50 units.
Answer:
f(x) = -100(1.05)^(x+5) + 50
Step-by-step explanation:
Here, we want to write an equation that represents the transformation
5 units right means 5 units on the positive x-axis
50 units up means we add this to the total y value
So the resulting equation will be;
f(x) = -100(1.05)^(x+5) + 50
For sixth-grade field day, 6 students in Alice's class are playing volleyball, 5 students are playing soccer, and 9 students are playing basketball. Alice said that the ratio of students playing volleyball to basketball was 6:9 Alex said that the ratio of students playing basketball to volleyball was 9/6.Who is correct? Explain
Answer:
Both are correct
Step-by-step explanation:
since there are 6 students playing volleyball, and 9 are playing basketball. the ratio of students playing basketball to volleyball is 6:9 and the ratio of students playing volleyball to basketball is 9/6. they didint get the same answer because they have reversed ratios.
hope this helped! :)
Write the equation of the line that is parallel to y=-3x - 1 and passes through (2, -1)
Answer:
Step-by-step explanation:
y + 1 = -3(x - 2)
y + 1 = -3x + 6
y = -3x + 5
which of these is the best example of the product of powers law 
The best example of the product of powers law is when multiplying two powers with the same base.
The product of powers law, states that when two powers have the same base, their product is the base raised to the sum of the exponents.
Mathematically, this can be expressed as:\(an^{m}*an^{n}=an^{(m+n)}\)
Where a is the base and m and n are the exponents.
For example, \(3^{4}*3^{2}\)can be simplified using the product of powers law to be \(3^{(4+2)}=3^{6}\)
Therefore, the best example of the product of powers law is when multiplying two powers with the same base.
The product of powers law is one of the laws of exponents.
The law states that if two powers have the same base, we can multiply the powers and keep the base.
In other words, we add the exponents.
This means that if we have the product of powers with the same base, we can easily simplify it by adding the exponents.
If there is no common base, we cannot use this law and must instead use other exponent laws.
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6(3−y) simplified plz help meeeeeee
Answer:
18 - 6y
Step-by-step explanation:
6(3 - y) ← multiply each term in the parenthesis by 6
= 18 - 6y
Answer:
18-6y
Step-by-step explanation:
6(3-y)
you multiply 6x3 and 6xy
-10 plus - 3/4
Hurry please!
Can someone please help me with these 4 questions?
The total length of a road trip was 19.2 hours. If highway signs are posted every 0.08 hours, including one at the end of the road trip, how many highway signs will there be on the road trip?
please help, thanks
Answer:
Radius: 4
Center(5,-2)
Step-by-step explanation:
Equation of circle is (x-h)² + (y-k)² = r²
(x-5)² + (y+2)² = 4²
-(-5): x-coordinates of the center
-(+2) : y-coordinates of the center
4: radius
Ut = 4uxx, 0 < x < 2,t > 0 u(0,t) = 1, u(2,t) = 2, u(x,0) = sin(17x) — 4 sin(Tt x/2) u = =
The solution of the given equation is\(u(x,t) = ∑(-1)n+1 4/(nπ) sin(nπ/4) sin(nπx / 2) exp(-n^2 π^2 t / 4)\)
The given equation is Ut = 4uxx, 0 < x < 2,t > 0u(0,t) = 1, u(2,t) = 2, u(x,0) = sin(17x) — 4 sin(Tt x/2)
The general form of the solution is given as:
\(u(x,t) = B0 + B1 x + ∑[Bn cos(nπx / L) + Cn sin(nπx / L)] exp(-n^2 π^2 t / L^2)\)
Where,\(Bn = (2/L) ∫f(x) cos(nπx / L) dx; from x = 0 to L . . . . . (1)\)
\(Cn = (2/L) ∫f(x) sin(nπx / L) dx; from x = 0 to L . . . . . (2)\)
\(L = 2Bn\)
First we need to find the values of B0 and B1.
Given initial conditions are\(u(x,0) = sin(17x) — 4 sin(Tt x/2)\)
We can write \(u(x,0) = B0 + B1 x + ∑[Bn cos(nπx / L) + Cn sin(nπx / L)]\)
From the given function, comparing the coefficients of the Fourier series, we have
\(B0 = 0, B1 = 0, Bn = (2/L) ∫f(x) cos(nπx / L) dx; from x = 0 to L = 0; for n = 1, 2, 3, .......\)
\(Cn = (2/L) ∫f(x) sin(nπx / L) dx; from x = 0 to L = (-1)n+1 4/(nπ)sin(nπ/4); for n = 1, 2, 3, .......L = 2.\)
Using the values of Bn and Cn, we can write the solution as \(u(x,t) = ∑(-1)n+1 4/(nπ) sin(nπ/4) sin(nπx / 2) exp(-n^2 π^2 t / 4)\)
Therefore, the solution of the given equation is\(u(x,t) = ∑(-1)n+1 4/(nπ) sin(nπ/4) sin(nπx / 2) exp(-n^2 π^2 t / 4)\)
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a hot-air balloon has a 1414-foot diameter that is being deflated at a rate of 0.250.25 feet per minute. how many minutes, xx, will it take before the balloon has shrunk to a diameter of 88 feet?
The amount of time it would take for the balloon's diameter to decrease to 8 feet is 56 minutes.
What is an example of diameter?
If you look at the cycle wheel, the spikes that run through the center from one end to the other are an illustration of diameter. This is comparable to a circle's diameter, which is a line segment that extends from one end of the circle to the other end while passing through the center.
In how long would the diameter have decreased to 8 feet?
A circle's diameter is determined by drawing a line across its center, touching both ends of its circumference.
Minutes are calculated as diameter/decline.
56 minutes from 14/0.25
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You are given \( f=10 \) meissurements: \( 3,5,4,6,10,5,6,9,2,13 \). (D) Calculate \( x_{2} \) \( \frac{2}{x}= \) (b) Firud m. \( m= \) (c) Find the mode. (If these is more than one mode, enter your answer
Two values have frequency 2, so both are modes. They are 5 and 6. Therefore, the mode is 5 and 6.
Given measure: 3, 5, 4, 6, 10, 5, 6, 9, 2, 13.(D) To calculate \(x_2\), first we need to sort the data in ascending order: 2, 3, 4, 5, 5, 6, 6, 9, 10, 13
Now, we need to find the median, which is the middle value of the data. Since the data has even number of values, we will calculate the mean of middle two values, that is:(5+6)/2 = 5.5 Therefore, \(x_2 = 5.5\).\( \frac{2}{x}= \) To find the value of x, we will first cross-multiply and then take the reciprocal of both sides:\[\frac{2}{x} = y \Rightarrow 2 = xy \Rightarrow x = \frac{2}{y}\] Therefore, \( \frac{2}{x}= \frac{2}{y}\).
(b) To calculate Fried m, we will use the formula: \[f_m = L + \frac{(n/2 - F)}{f} \times c\]where L is the lower limit of the modal class, F is the cumulative frequency of the class preceding the modal class, f is the frequency of the modal class, c is the class interval, and n is the total number of values.
First, we will calculate the class interval:c = (upper limit of class - lower limit of class) = (7-6) = 1 Next, we will construct a frequency table to find the modal class:| Class Interval | Frequency ||-------------------|------------|| 2-3 | 1 || 3-4 | 1 || 4-5 | 1 || 5-6 | 2 || 6-7 | 2 || 7-8 | 1 || 9-10 | 1 || 10-11 | 1 || 13-14 | 1 |The modal class is the class with highest frequency.
Here, two classes have frequency 2, so both are modes. They are 5-6 and 6-7.
Therefore, L = 5, F = 2, f = 2, n = 10, and c = 1. Substituting the values, we get:\[f_m = L + \frac{(n/2 - F)}{f} \times c = 5 + \frac{(10/2 - 2)}{2} \times 1 = 7\] Therefore, Fried m = 7.
(c) To find the mode, we look for the value(s) with highest frequency. Here, two values have frequency 2, so both are modes. They are 5 and 6. Therefore, the mode is 5 and 6.
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A plane flew 360km in 3 hrs when flying with the wind.With no change in the wind,the return trip took 4 hrs.Find the speed of the wind and the speed of the plane
how many horseshoes are needed to fit 5 horses
Answer:
20 horseshoes
Step-by-step explanation:
How many horseshoes are needed to fit 5 horses?
5 horses with 4 hooves each:
5 × 4 = 20 horseshoes