Answer 5750$

Given below are lease terms at the local dealership. What is the total cash
due at signing?
.
.
Terms:
Length of lease = 24 months
MSRP of the car = $36,600
Purchase value of the car after lease = $30,200
Down payment = $4800
Monthly payment = $525
$445 security deposit
$505 acquisition fee
A. $6275
B. $5750
C. $5770
D. $5830

Answer:

ok im telling people to help u because i dont know that xd

Step-by-step explanation:

Answer:

3 songs

Step-by-step explanation:

25% more songs: 12 x 1.25 = 15

80% removed: 15 x 0.2 = 3

Answer:

A negative exponent flips the fraction and turns the exponent positive, and vice versa.

1/121 = 1/1211 = 121-1

As an example, 5-2 = 1/25, and 1/5-2 = 25.

Answer:

A c must not be finite.

A ∪ B must be infinite.

A ∩ B must not be infinite.

Step-by-step explanation:

Must A c be finite?

Suppose

U = {....-4,-3,-2,-1,0,1,2,3,4.......}

A = {....-4,-2,0,2,4.......} which is infinite set

B = {....-3,-1,0,1,3.......} which is also infinite set

So We need to calculate the A compliment

\(A^{c}\) = U - A = {....-4,-3,-2,-1,0,1,2,3,4.......} - {....-4,-2,0,2,4.......} = {....-3,-1,0,1,3.......}

Hence \(A^{c}\) is also an infinite set.

The statement "Must A c be finite?" is incorrect.

Must A ∪ B be infinite?

In AUB all the elements of set A and set B are combined into a single set to get the union of A and B. If A and B are the infinite set then their union must also be an infinite set because all the elements of infinite sets will be there so the union of these infinite sets will also be an infinite set.

The Statement "Must A ∪ B be infinite?" is correct.

Must A ∩ B be infinite?

In A∩B the common elements of both sets will be the answer to the intersection of A and B set. If we consider the A and B are the infinite subsets of a Universal set that carry all the elements then there will not be any common element in both sets A and B.

The Answer of A∩B is { } or empty set.

The statement "Must A ∩ B be infinite? " is incorrect.

Answer:

sum of

Step-by-step explanation:

sum of  = adding

As a result, the rectangle's perimeter is 230 cm as the rectangle's base has a 69 cm width.

Four straight sides that are aligned and equal in length make up a rectangle, a two-dimensional geometric object. A rectangles has four right-angled angles (90 degrees). A rectangle can be thought of as a quadrilateral with all angles equal to 90 degrees, or as a trapezoid with two pairs of parallel sides. By multiplying the rectangle's length and breadth, the area of the rectangle may be determined. By summing the measurements of all four sides, one may get a rectangle's perimeter. In many commonplace items like window, book covers, and screens, rectangles are frequently used.

given

According to the information provided, the rectangle's base has a 69 cm width.

We also know that the height is equal to the base by two thirds. As a result, the rectangle's height can be determined as follows:

Height equals 2/3 of base height, or 69 cm.

size = 46 cm

Knowing the rectangle's base and height, we can use the following formula to get its perimeter:

P = 2l + 2w

P = 2(69 cm) + 2(46 cm) (46 cm)

P = 230 cm if P = 138 cm plus 92 cm.

As a result, the rectangle's perimeter is 230 cm as the rectangle's base has a 69 cm width.

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The complete question is: - In a rectangle the base measures 69 cm and the height is 2/3 of the base. Calculate the perimeter.[230] Please help with a photo

The values of x and y after solving this system of equations will be 32/35 and -88/105 respectively.

System of equations are a set of two or more equations that contain variables. The values of the variables can be calculated using either method of elimination or substitution. The values of the variables must then satisfy all the equations.

For a set of two equations, in elimination we make the coefficient of any one variable equal to the coefficient of the same variable in the other equation. This can be done by multiplying or dividing the whole equation accordingly. Then we subtract the equations from each other and solve for one variable.

6x - 3y = 8 (multiplying this equation by -2 to make the coefficient of y equal to that of in the equation 23x + 6y = 16)

Now are equations are

-12x + 6y = -16 and 23x + 6y = 16

subtracting eq 1 from eq 2 gives,

35x = 32 (Note that y has now been eliminated)

x = 32/35

Substituting this value of x in any one of the equations will then give the value of y to be -88/105

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The consumer surplus is approximately $145.83.

To find the consumer surplus, we first need to find the demand function's inverse, which gives us the willingness to pay for each unit of the product. The demand function is:

D(x) = √(739 - 3x)

Setting D(x) equal to the equilibrium price of $25, we get:

25 = √(739 - 3x)

Squaring both sides, we get:

625 = 739 - 3x

Solving for x, we get:

So at a price of $25 per unit, the consumer is willing to buy 38 units per month.

Now we can calculate the consumer's surplus.

The consumer\(x = (739 - 625) / 3 = 38\) surplus is the difference between the total amount that consumers are willing to pay for a certain quantity of a good and the total amount they actually pay. In this case, the consumer's surplus can be calculated as:

\(CS = \int_0^{38} [D(x) - 25] dx\)

where D(x) is the demand function, and the integral is taken over the range of 0 to 38, which represents the quantity demanded at a price of $25 per unit.

Evaluating this integral, we get:

\(CS = \int_0^{38} [\sqrt{(739 - 3x)} - 25] dx\\\\= [1/6 (739 - 3x)^{(3/2)} - 25x]_0^{38}\\\\= \$ 145.83\)

Therefore, the consumer surplus is approximately $145.83.

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Answer:you have to round the numbers

Step-by-step explanation:

Answer:

We need the figure

Explanation:

Can't describe a figure with no knowledge on what is it like.

Answer:

It has no rotational symmetry

Answer:1/40

Step-by-step explanation: If the Smiths bought 25 raffle tickets, and there were 1000 sold in total, it would mean they have a 25/1000 chance. we can simplify 25/1000 into 1/40. Therefore, the answer is (3)

Answer:

47 inches

Step-by-step explanation:

45 + 48 + 49 + 40 + 53 = 235

235/5 = 47

Answer:

.1554

.6709

Step-by-step explanation:

p(20<x<22)= p(x<22)-p(x<20)

p(x<22)=(22-20)/5= .4 = .6554

p(x<20)= (20-20)/5= 0 = .5

.6554-.5= .1554

p(12<x<23)= p(x<23)-p(x<12)

p(x<23)= (23-20)/5= .6= .7257

p(x<12)= (12-20)/5= -1.6 = (1-.9452)= .0548

.7257-.0548= .6709

Answer:

x = 4.8

Step-by-step explanation:

Since quadrilateral JKLM and PQRS are similar toe ach other, therefore the ratio of their corresponding sides are equal.

Thus:

QP/KJ = PS/JM

Substitute

8/5 = x/3

Cross multiply

5*x = 3*8

5x = 24

x = 24/5

x = 4.8

a) The distance of the stone above ground level at time t :

d(t)= -4.9t² + 950

b) It takes 13.92 seconds the stone to reach the ground

c)  With 136.42 m/s velocity the stone strikes the ground.

d) If the stone is thrown downward with a speed of 8 m/s, it will take 13.13 seconds to reach the ground

Here, a  stone is dropped from the upper observation deck of a tower, 950 m above the ground.

(a)  the distance of the stone above ground level at time t would be,

d(t)  = 0.5 (-9.8) t² + v(0) t + d(0)

      = (-4.9)t² + 0t + 950

      = -4.9t² + 950

(b) Now we find the time the stone takes to reach the ground.

i.e., the value of 't' when d = 0

Substituting d(t) = 0 in the above equation.

-4.9t² + 950 = 0

t² = (-950) / (-4.9)

t² = 193.88

t = 13.92 seconds

(c) We need to find the velocity the stone takes to strike the ground

i.e., the velocity when t  = 13.92 seconds

v(t) = v(0) + gt      

v(13.92) = 0 + (9.8)(13.92)

v = 136.42 m/s

(d) here, v(0) = -8 m/s  

Velocity is negative because stone is being thrown downward.

d(t) = 0

(-4.9)t² + v(0) t + d(0) = 0

(-4.9)t² -8t + 950 = 0

Using the quadratic formula we solve above equation for,

t = -14.76, 13.13

We can disregard the negative solution

So, we get t = 13.13 seconds.

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she could have scored the 10 points in 302400 ways.

The given parameters are

n= total points =10

r1 =one-point free throw = 1

r2 = two-point field goals = 2

r3 =  three-point field goals = 3

The number of ways (k) she could have scored the points is:

k=(n!)/(r1!×r2!×r3!)

The factorial function is a mathematical formula represented by an exclamation mark "!".

k= 10!/(1!×2!×3!)

k= 3628800/(1×2×6)

k= 302400

so.. she could have scored the 10 points in 302400 ways.

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Answer:

28

Step-by-step explanation:

F=2.25+0.20(m-1)

7.65=2.25+0.20(m-1)

5.4=0.20(m-1)

5.4/0.20=0.20(m-1)/0.20

27=m-1

28=m

Answer:

i dont know dude

Step-by-step explanation:

(i) \(\lim_{x \to \pi/3}\) f(x) = 1 + √3.

(ii) \(\lim_{x \to \frac{\pi}{4}} f(x)\) does not exist.

For λ = 2.5, the function f(x) will be continuous at x = 0.

Given the function is,

f(x) = 1.5, when x = 0

    = 1 -2 sin x, when x < π/4

    = 1 + 2 sin x, when x > π/4

    = 1 + (sin λx/sin 5x)

Now,

\(\lim_{x \to \pi/3}\) f(x) = \(\lim_{x \to \pi/3}\) (1 + 2 sin x) [Since, π/3 > π/4]

                    = 1 + 2 sin (π/3)

                    = 1 + 2√3/2 = 1 + √3

Hence, \(\lim_{x \to \pi/3}\) f(x) = 1 + √3.

Now left hand limit is,

\(\lim_{x \to \frac{\pi^+}{4}}\) f(x) = \(\lim_{x \to \frac{\pi^+}{4}}\) (1 + 2sin x) = 1 +2 sin(π/4) = 1 + 2*(1/√2) = 1 + √2

and right hand limit is,

\(\lim_{x \to \frac{\pi^-}{4}}\) f(x) = \(\lim_{x \to \frac{\pi^-}{4}}\) (1 - 2 sin x) = 1 - 2*(1/√2) = 1 - √2

Since left hand limit and right hand limit are not equal so value of \(\lim_{x \to \frac{\pi}{4}} f(x)\) does not exist.

\(\lim_{x \to 0}\) f(x) = \(\lim_{x \to 0}\) (1 + (sin λx/sin 5x)) = 1 + \(\lim_{x \to 0}\) ((sin λx/λx)/(sin 5x/5x))*(λ/5) = 1 + λ/5

Since f(x) is continuous at x = 0.

So, \(\lim_{x \to 0}\) f(x) = f(0)

1 + λ/5 = 1.5

λ/5 = 1.5 - 1 = 0.5

λ = 2.5

Hence the value of λ will be 2.5.

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Answer:

y = 7

Step-by-step explanation:

3y + (y+1) + (4y-3) = 54

3y + y + 4y + 1 - 3 = 54

8y - 2 = 54

8y = 54 + 2

8y = 56

y = 56/8

y = 7

Check:

3*7 + (7+1) + ((4*7)-3) = 54

21 + 8 + 28-3 = 54

29 + 25 = 54

Answer:

Problem 13: NO

Problem 14: YES

Step-by-step explanation:

HOPE IT HELPS YOU IN YOUR LEARNING PROCESS.

The common ratio of the resulting sequence is 1.4.

Given that, the three terms are 60, 100 and 180.

A geometric sequence is a special type of sequence where the ratio of every two successive terms is a constant. This ratio is known as a common ratio of the geometric sequence.

Let the same constant is added to the given number is x.

60+x, 100+x and 180+x

Now, the common ratio is

(100+x)/(60+x) = (180+x)/(100+x)

⇒ (100+x)(100+x)=(180+x)(60+x)

⇒ (100+x)²=10800+180x+60x+x²

⇒ 10000+200x+x²=10800+180x+60x+x²

⇒ 10000+200x=10800+180x

⇒ 20x=800

⇒ x=40

The three number are 100, 140 and 220

The common ratio is 140/100 =1.4

Therefore, the common ratio of the resulting sequence is 1.4.

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The probability that a randomly selected student will like pizza but not chicken nuggets is (28n - 8)/(28n + 7), where 28n is the students who like pizza and 8 is students who like both pizza and chicken nuggets.

To find the probability that a randomly selected student will like pizza but not chicken nuggets.

Let P = the number of students who like pizza but not chicken nuggets

Then, P = the number of students who like pizza - the number of students who like both pizza and chicken nuggets

P = 28n - 8

So, the probability that a randomly selected student will like pizza but not chicken nuggets is:

P(Pizza but not nuggets) = P/(Total number of students)

We can find the total number of students who like either pizza or chicken nuggets by adding the number of students who like pizza and the number of students who like chicken nuggets, and then subtracting the number of students who like both:

Total number of students = 28n + 15 - 8 = 28n + 7

So, the probability that a randomly selected student will like pizza but not chicken nuggets is:

P(Pizza but not nuggets) = P/(Total number of students) = (28n - 8)/(28n + 7)

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Decimals are multiplied as if they were whole numbers, and then the decimal point is placed in the product.

Answer:

The relationship will be a solid line.

Step-by-step explanation:

The relationship between the number of $4 lunches you buy with a $100 school lunch card and the money remaining on the card.

The relationship will be a solid line as it is a linear and common slope. Each time you buy lunch, the amount in the card will decrease by $4.

Let the number of lunches you buy be = x

Let the amount remaining in the card be = y

So, equation forms:

When you buy 1 lunch, or x = 1

When x = 2

When x = 3

We can see that the decrease is gradual and same.

You can also see the graph attached that a straight line is formed.

Answer:

93

Step-by-step explanation:

70 + 85 + 77 + 93 = 325

325/4 = 80

She needs to score a 93 if she wants to have a average of 80.

Check the picture below.

\(\stackrel{ \textit{\LARGE Areas} }{\stackrel{ triangle }{\cfrac{1}{2}(26)(17)}~~ + ~~\stackrel{ rectangle }{(26)(9)}}\implies 221+234\implies \text{\LARGE 455}\)