To minimize sink marks in injection-molded polymer products, the following principles should be considered:
Uniform wall thickness: Ensure consistent thickness throughout the product design to prevent localized variations in cooling rates, which can lead to sink marks.
Rib design: Use proper rib thickness and geometry to provide structural support without causing excessive shrinkage and sink marks.
Gate placement: Position the injection gate at locations that promote even material flow and minimize flow front collisions, which can result in sink marks.
Cooling system: Implement an efficient cooling system to maintain uniform cooling rates and minimize differential shrinkage.
Material selection: Choose materials with lower shrinkage characteristics to reduce the likelihood of sink marks.
Sink marks are depressions or indentations that occur on the surface of injection-molded polymer products due to differential cooling and shrinkage rates. By following the principles mentioned above, designers can minimize the occurrence of sink marks and achieve higher quality products.
The general creep characteristics of a metal, as depicted by a graph of strain versus time, can be outlined as follows:
Primary creep region: In this initial stage, the strain rate gradually decreases over time as the material undergoes a process called "creep hardening." The strain curve shows a concave-upward shape.
Secondary creep region: This is the most important consideration in designing with the presence of creep effects. In this stage, the strain rate becomes relatively constant, indicating a steady-state creep. The strain curve shows a linear or near-linear shape, and it defines the long-term behavior of the material under constant stress.
Tertiary creep region: If the applied stress and temperature are high, the material may enter the tertiary creep region. Here, the strain rate increases rapidly until failure occurs. The strain curve exhibits an accelerated upward slope.
Creep is the time-dependent deformation of a material under a constant load or stress at elevated temperatures. The secondary creep region is crucial because it represents a stable deformation rate that designers can use to estimate the long-term creep behavior of the material. By understanding the strain characteristics in this region, engineers can make informed decisions about the safety and reliability of a design subjected to long-term creep effects.
Please note that the second topic does not involve specific calculations, as it focuses on the general characteristics of creep behavior.
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Your organization is in the process of microfilming all the old records in storage. The budget for this process is $500,000 over three years. You have contracted with a company to perform the microfilm services at $0.09 per page and have estimated that there are about 5.5 million pages to be converted. At the end of the first year, you review the invoice and see that you have been billed for converting 2,083,333 pages. 1. Determine your budget variance and what type it is. 2. Provide a short explanation that can be given to administration regarding the variance.
hah duty to it it hey he h very j is to
a large tower is to be supported by a series of steel wires; it is estimated that the load on each wire will be 13,300 n ( 3000 lb f ) . determine the minimum required wire diameter, assuming a factor of safety of 2.0 and a yield strength of 860 mpa (125,000 psi) for the steel.
The minimum required wire diameter, assuming a factor of safety of 2.0 and a yield strength of 860 MPa (125,000 psi) for the steel, is approximately 0.248 inches.
To determine the minimum required wire diameter, we can use the formula for stress:
Stress (σ) = Force (F) / Area (A)The yield strength of the steel is given as 860 MPa (125,000 psi), and we have a factor of safety of 2.0. Therefore, the maximum stress the wire can withstand is 860 MPa / 2.0 = 430 MPa (62,500 psi).
Let's calculate the minimum required wire diameter:
Step 1: Convert the load from Newtons to Pounds-force
Load = 13,300 N = 13,300 N * (1 lb f / 4.448 N) = 2,989.28 lb f
Step 2: Calculate the area of the wire
Stress = Force / Area
Area = Force / Stress = 2,989.28 lb f / 62,500 psi
Step 3: Convert the stress and yield strength to consistent units
Area = 2,989.28 lb f / (62,500 psi * (1 lb f / in^2)) = 0.04783 in^2
Step 4: Calculate the diameter of the wire
Area = π * (diameter / 2)^2
0.04783 in^2 = π * (diameter / 2)^2
Solving for the diameter:
(diameter / 2)^2 = 0.04783 in^2 / π
(diameter / 2)^2 = 0.01521 in^2
diameter / 2 = sqrt(0.01521 in^2)
diameter = 2 * sqrt(0.01521 in^2)
diameter ≈ 0.248 in
Therefore, the minimum required wire diameter, assuming a factor of safety of 2.0 and a yield strength of 860 MPa (125,000 psi) for the steel, is approximately 0.248 inches.
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a commercial refrigerator with r-134a as the working fluid is used to keep the refrigerated space at -35 c by rejecting waste heat to cooling water that enters the condenser at 18 c at a rate of 0.25 kg/s and leaves at 26 c. the refrigerant enters the condenser at 1.2 mpa and 50 c and leaves at the same pressure subcooled by 6 c. if the compressor consumes 3.3 kw of power , determine (a) the mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.
At 1.2mpa pressure and 50c
What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).
a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser
T2 = 46.29C - 5
T2 = 41.29C
Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg
(COP)r = 238/53
(Cop) = 4.490
Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.
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World Without Engines: Explain what todays world without engines would be like? How would it change your life? The world? The way we do things? Please write in paragraph format and include introduction, body, and conclusion. DON'T ANSWER UNLESS YOU HAVE THE ANSWER!!!!!!!!! I WILL MARK BRAINLYEST
Answer:
the world will not be the same it will change dramticily and
things will not be the same
Explanation:
What types of materials are best for preventing heat transfer through convection?.
The types of materials are best for preventing heat transfer through convection include the following:
FiberglassWoolCottonPaper (wood cellulose)StrawFoamsWhat are the types of energy transmission?In Science, there are three (3) main types of heat energy transmission and these include the following:
ConvectionRadiationConductionWhat is convection?Convection can be defined as a heat energy transfer process which typically involves the transfer of heat, as a result of the movement of mass.
Based on scientific research and experiments, convection is generally considered to be a more effective and efficient means of heat transport on planet Earth when compared to conduction.
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What are the four scanning systems as per biomedical engineering
Answer:
- Ultrasound scanning system
- Magnetic Resonance Imaging (MRI)
- Computed tomography (CT)
- X - Ray scan
Explanation:
\(.\)
Answer:
- USS Ultarsound
- Medical sonography
Could someone please help me
The angular velocity is ω = VA/L and the qngular acceleration is α = -g/L
How to calculate the valueThe velocity of end A can be expressed as:
VA = Lω
where L is the length of the bar and ω is the angular velocity.
The acceleration of end A can be expressed as:
aA = Lα
where L is the length of the bar and α is the angular acceleration.
We can see from the diagram that the acceleration of end A is equal to the acceleration due to gravity, minus the centripetal acceleration.
aA = g - Lω²
Substituting VA = Lω into the equation for aA, we get:
g - Lω² = Lα
Solving for ω, we get:
ω = VA/L
Substituting ω = VA/L into the equation for aA, we get:
α = -g/L
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What are the three main functions of electrical drawing
You have a circular loop of wire in the plane of the page with an initial radius of 0.50 m which expands to a radius of 1.00 m. It sits in a constant magnetic field B = 52 mt pointing into the page. Assume the transformation occurs over 1.0 second and no part of the wire exits the field. Also assume an internal resistance of 30 2. What average current is produced within the loop and in which direction? Express your answer with the appropriate units. Enter positive value if the current is clockwise and negative value if the current is counterclockwise. uA ? I = Value Units Submit Request Answer
The average current induced in the loop during expansion from 0.50 m to 1.00 m over 1.0 s in a magnetic field of 52 mT is 4.2 μA in the counterclockwise direction.
The average current produced within the loop and the direction of the current can be determined as follows:
Initial radius of the circular loop, r₁ = 0.50 m
Final radius of the circular loop, r₂ = 1.00 m
Magnetic field, B = 52 m T
Time taken for the transformation, t = 1.0 s
Internal resistance of the wire, R = 30 Ω
Formula:The induced emf can be given by the following formula:
ε = ΔΦ/Δt
where,
ε is the induced emf and
ΔΦ is the change in flux.
As the magnetic field is pointing into the page, the magnetic flux can be given as:
Φ = BA
where,
A is the area of the loop.
As the loop expands, the area of the loop increases.
The area can be calculated using the formula of the area of the circle.
A = πr²
The change in the area can be calculated as:
ΔA = π(r₂² - r₁²)
The change in magnetic flux can be given as:
ΔΦ = BΔA = Bπ(r₂² - r₁²)
Now, the induced emf can be given as:ε = ΔΦ/Δt = Bπ(r₂² - r₁²)/t = 52 × 10⁻³ × π(1.00² - 0.50²)/1.0 = 0.15 V
ε= 0.15 V
The induced emf can be given as the following formula:
ε = IR + Ir
where, I is the current and
R is the internal resistance of the wire.
Now, the current can be given as:
I = (ε - Ir)/RI = (0.15 - 0.5 × 10⁻⁶ × π(1.00² - 0.50²))/30 = 4.2 μA
I = 4.2 μA
Thus, the average current produced within the loop is 4.2 μA in the counterclockwise direction.
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A series circuit contains four resistors. In the circuit, R1 is 80 , R2 is 60 , R3 is 90 , and R4 is 100 . What is the total resistance? A. 330 B. 250 C. 460 D. 70.3
is a baby duck swimming in a lake a learned behavior
Answer:
True because some ducks can't swim but have to learn it
What is the impedance of an ideal parallel resonant circuit (no resistance in either branch)?
Answer:
infinite
Explanation:
The impedance of an ideal parallel resonant circuit is infinite at the resonant frequency. The sum of the admittances of the branches of the circuit is zero.
Evaluate stability of a system with the following characteristics equation:
s^6 + s^5 + s^4 + s^3 + 10s^2 − 7s + 4 = 0
The characteristic equation of a system is a polynomial in the variable s that is equal to zero when the system is at rest.
How to explain the equationThe roots of the characteristic equation are the poles of the system's transfer function. The poles of a system determine the stability of the system.
A system is stable if all of its poles lie in the left half-plane of the complex plane. A system is unstable if any of its poles lie in the right half-plane of the complex plane.
The characteristic equation of the system in the question can be factored as follows:
(s + 1)(s + 2)(s + 4)(s - 1)(s - 2)(s - 4) = 0
The roots of this equation are s = -1, s = -2, s = -4, s = 1, s = 2, and s = 4. All of these roots lie in the left half-plane of the complex plane, so the system is stable.
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consider an automobile dealership with three locations. Data fields exist for stock number, vehicle identification number, make, model, year, color, and invoice cost. Identify the possible candidate keys, the likely primary key, a probable foreign key, and potential secondary keys.
Possible candidate keys for this automobile dealership include the stock number and the vehicle identification number (VIN), as they are unique identifiers for each vehicle in the dealership's inventory.
The likely primary key would be the stock number or VIN, as they are both unique and can be used to easily search and retrieve information about a specific vehicle.A probable foreign key could be the invoice number, as it may be used to link vehicle information with the dealership's accounting system. For example, a sales transaction for a specific vehicle may reference the invoice number, which can be used to retrieve the invoice cost and other financial information.Potential secondary keys could include the make, model, year, and color of the vehicle. These fields can be used to search and filter the inventory based on specific criteria, such as finding all vehicles of a certain make or year.
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In HTML, which attribute is used to specify that an input field must be filled out?A) requiredB) validateC) mandatoryD) input_required
In HTML, the attribute used to specify that an input field must be filled out is "required" (option A). This attribute ensures that the user must provide a value for the input field before submitting the form, promoting proper form completion and data validation.
If the required attribute is not satisfied, the form will not be submitted, and the user will receive a prompt to fill in the necessary information. The attribute used to specify that an input field must be filled out in HTML is the "required" attribute. This attribute is used in conjunction with the "input" tag to indicate that the user must fill out the specified field before submitting the form. When the user tries to submit the form without filling out the required field, an error message will appear prompting them to fill out the required field. The "validate" and "mandatory" attributes are not used in HTML to achieve this functionality. While the term "input_required" could potentially be used as a custom attribute, it is not a standard attribute in HTML. Therefore, the correct answer is A) required.
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When a light wave enters a medium of greater optical density, there will be a decrease in the wave's A) speed, only B) frequency, only I C) speed and wavelength D) frequency and wavelength
When a light wave enters a medium of greater optical density, there will be a decrease in the wave's **A) speed, only**.
The frequency of a light wave remains constant when it transitions between different media, so option B) frequency, only is not correct.
However, the wavelength of a light wave can change when it enters a medium with a different optical density, but it does not necessarily decrease. It can increase or decrease depending on the specific conditions. Therefore, option D) frequency and wavelength is not accurate.
The speed of light in a medium depends on the refractive index of that medium. When light enters a medium with a higher refractive index, its speed decreases. This is due to the interaction of light with the atoms or molecules of the medium, causing it to slow down. Thus, option A) speed, only is the correct answer.
While the wavelength of the light wave can be affected by the change in speed, it is not necessarily decreased. The relationship between speed and wavelength is inversely proportional, meaning that as the speed decreases, the wavelength can either increase or decrease depending on the specific conditions. Therefore, option C) speed and wavelength is not accurate.
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A silicon diode has a saturation current of 6 nA at 25 degrees Celcius. What is the saturation current at 100 degrees Celsius?
Answer:
0.0659 A
Explanation:
Given that :
\(I_{0} = 6nA\) ( saturation current )
at 25°c = 300 k ( room temperature )
n = 2 for silicon diode
Determine the saturation current at 100 degrees = 373 k
Diode equation at room temperature = I = Io \(\frac{V}{e^{0.025*n} }\)
next we have to determine the value of V at 373 k
q / kT = (1.6 * 10^-19) / (1.38 * 10^-23 * 373) = 31.08 V^-1
Given that I is constant
Io = \(\frac{e^{0.025*2} }{31.08}\) = 0.0659 A
The saturation current at 100 degrees Celsius will be "0.0659 A".
Temperature and CurrentAccording to the question,
Saturation current, \(I_0\) = 6nA
At 25°C,
Room temperature = 300 k
Silicon diode, n = 2
The value of V will be:
= \(\frac{q}{kT}\)
By substituting the values,
= \(\frac{1.6\times 10^{-19}}{1.38\times 10^{-23}\times 373}\)
= 31.08 V⁻¹
hence,
By using Diode equation,
→ I = I₀ \(\frac{V}{e^{0.025\times n}}\)
or,
The current will be:
I₀ = \(\frac{V}{e^{0.025\times n}}\)
= \(\frac{e^{0.025\times 2}}{31.08}\)
= 0.0659 A
Thus the answer above is right.
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The angle of attack of a wing directly controls the A) angle of incidence of the wing. B) amount of airflow above and below the wing. C) distribution of pressures acting on the wing.
The angle of attack of a wing directly controls the C) distribution of pressures acting on the wing.
When the angle of attack of a wing is increased, the air moving over the curved upper surface of the wing must travel a greater distance and faster than the air moving beneath the wing's flat lower surface. This creates an area of lower air pressure above the wing and an area of higher air pressure beneath the wing, resulting in lift. The greater the angle of attack, the greater the lift produced.
However, if the angle of attack is too great, the airflow over the wing may separate, causing a loss of lift and potentially leading to a stall. Therefore, proper control of the angle of attack is crucial for safe and efficient flight.
Option C is answer.
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What is "Engineering"?
Calculate the discrete settling velocity of a grit particle with a radius of 0.05mm and specific gravity of 2.65 at water temperature 20degrees(v=1.004×10^-6m2/s)
The correct answer is To calculate the discrete settling velocity of a grit particle, we can use the following formula:
\(V_s = (2/9) * (ρ_p - ρ_f) * g * r^2 / η\)
V_s = discrete settling velocity
ρ_p = density of particle
ρ_f = density of fluid
g = acceleration due to gravity
r = radius of particle
η = dynamic viscosity of fluid Given that the radius of the grit particle is 0.05mm and its specific gravity is 2.65, we can calculate its density as:
ρ_p = specific gravity * ρ_water
\(= 2.65 * 1000 kg/m^3= 2650 kg/m^3\)
At a water temperature of 20°C, the dynamic viscosity of water is\(1.004 × 10^-6 m^2/s,\)which we are given.
The density of water at 20°C is approximately \(1000 kg/m^3,\) and the acceleration due to gravity is\(9.81 m/s^2.\)
Substituting these values into the formula, we get:
\(V_s = (2/9) * (2650 - 1000) * 9.81 * (0.05 × 10^-3)^2 / (1.004 × 10^-6)= 0.086 m/s\)(rounded to three decimal places)
Therefore, the discrete settling velocity of the grit particle is approximately 0.086 m/s.
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At steady state, air at 200 kPa, 325 K, and mass flow rate
of 0.5 kg/s enters an insulated duct having differing inlet
and exit cross-sectional areas. The inlet cross-sectional area is
6 cm26cm
2. At the duct exit, the pressure of the air is 100 kPa and the velocity is 250 m/s. Neglecting potential energy
effects and modeling air as an ideal gas with constant cp=1.008 kJ/kg⋅Kc
p =1.008kJ/kg⋅K, determine
(a) the velocity of the air at the inlet, in m/s.
(b) the temperature of the air at the exit, in K.
(c) the exit cross-sectional area, in cm2
(a) the velocity of the air at the inlet, in m/s.
(b) the temperature of the air at the exit, in K.
(c) the exit cross-sectional area, in cm
suppose that a real op amp has five terminals. select the probable functions of the terminals.
A real operational amplifier (op amp) generally has five terminals, which are labeled as the inverting input (−), non-inverting input (+), output (OUT), positive power supply (V+), and negative power supply (V−). Each of these terminals has a specific function that determines the behavior of the op amp.
The inverting input terminal (−) is the input that is connected to the inverting amplifier circuit, where the input signal is amplified with a negative gain. This terminal is responsible for inverting the input signal and feeding it into the op amp. The non-inverting input terminal (+) is the input that is connected to the non-inverting amplifier circuit, where the input signal is amplified with a positive gain. This terminal is responsible for amplifying the input signal and feeding it into the op amp. The output terminal (OUT) is the output of the op amp, which is the amplified signal that is produced by the op amp's internal circuitry. This terminal is responsible for delivering the amplified signal to the load or other circuit components.
The positive power supply terminal (V+) is the input that is connected to the positive power supply, which provides the op amp with a positive voltage to operate. This terminal is responsible for supplying the op amp with the required voltage to operate. The negative power supply terminal (V−) is the input that is connected to the negative power supply, which provides the op amp with a negative voltage to operate. This terminal is responsible for supplying the op amp with the required voltage to operate. In summary, the inverting input (−) and non-inverting input (+) terminals are responsible for receiving and amplifying the input signal, while the output (OUT) terminal delivers the amplified signal to the load or other circuit components. The positive power supply (V+) and negative power supply (V−) terminals provide the op amp with the required voltage to operate.
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If air pressure does not build up to normal within the correct amount of time then:____.
Correct response is Driving may cause your air pressure to go too low, requiring an immediate halt.
Your air pressure could drop too low while you're driving, necessitating an emergency stop, if it doesn't return to normal in the allotted amount of time.
What exactly is air pressure?The weight of air molecules pressing down on the Earth is known as air pressure. As you ascend from the surface of the ocean into the atmosphere, the pressure of the air molecules changes. At sea level, where the density of the air molecules is maximum, there is the highest pressure.
1. Air pressure is measured by barometers.
When predicting the weather and analyzing weather patterns, meteorologists use barometers to measure the air pressure. The barometer reading is presented in either inches or centimeters when the barometric pressure is mentioned in weather reports. A mercury column in a cylinder is moved up or down by pressure on the barometer. Barometric pressure readings are taken by examining the marks on the glass cylinder's outside. Inches or centimeters are used to calibrate barometers.
2. Pressure measurements made using mercury
When reporting meteorological conditions on the Earth's surface, the National Weather Service of the United States utilizes inches of mercury. The units of measurement aloft are millibars. It is becoming less common to use millibars and barometers that measure in inches and centimeters.
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PLEASE HELP I NEED THIS ASP!!
Answer:
up up down down
Explanation:
left right left right b a select start
In a tension test of steel, the ultimate load was 13,100 lb and the elongation was 0.52 in. The original diameter of the specimen was 0.50 in. and the gage length was 2.00 in. Calculate (a) the ultimate tensile stress (b) the ductility of the material in terms of percent elongation
Answer:
a) the ultimate tensile stress is 66717.8 psi
b) the ductility of the material in terms of percent elongation is 26%
Explanation:
Given the data in the question;
ultimate load P = 13,100 lb
elongation δl = 0.52 in
diameter of specimen d = 0.50 in
gage length l = 2.00 inch
First we determine the cross-sectional area of the specimen
A = \(\frac{\pi }{4}\) × d²
we substitute
A = \(\frac{\pi }{4}\) × ( 0.50 )²
A = 0.1963495 in²
a) the ultimate tensile stress σ\(_u\)
tensile stress σ\(_u\) = P / A
we substitute
tensile stress σ\(_u\) = 13,100 / 0.1963495
tensile stress σ\(_u\) = 66717.766 ≈ 66717.8 psi
Therefore, the ultimate tensile stress is 66717.8 psi
b) ductility of the material in terms of percent elongation;
percentage elongation of specimen = [change in length / original length]100
% = [ δl / l ]100
we substitute
% = [ 0.52 in / 2.00 in ]100
= [ 0.26 ]100
= 26
Therefore, the ductility of the material in terms of percent elongation is 26%
Charles knows that adding salt to water causes the freezing point of water to be lowered, but he wants to know if rock salt affects the freezing point more than table salt.
Charles performed an investigation in his classroom in which he measured the freezing point of 250 mL of water. He used this measurement as his control. Then, he dissolved equal amounts of rock salt and table salt in two identical 250 mL beakers of water. Finally, he measured the freezing points of each beaker of water, analyzed his results, and formed a conclusion.
What type of investigation did Charles perform?
Since Charles performed an investigation in his classroom in which he measured the freezing point of 250 mL of water, the type of investigation that Charles perform is known as option C: laboratory experiment.
What is a laboratory experiment?The term Laboratory experiments is known to be a term that connote any for of research method which is one where researchers are known to make controllable environments so that they can be able to test hypotheses.
Note that Laboratories are known to be used for academic research such as rooms or specifically set up spaces.
Therefore, based on the above, one can say that since Charles performed an investigation in his classroom in which he measured the freezing point of 250 mL of water, the type of investigation that Charles perform is known as option C: laboratory experiment.
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Charles knows that adding salt to water causes the freezing point of water to be lowered, but he wants to know if rock salt affects the freezing point more than table salt. Charles performed an investigation in his classroom in which he measured the freezing point of 250 mL of water. He used this measurement as his control. Then, he dissolved equal amounts of rock salt and table salt in two identical 250 mL beakers of water. Finally, he measured the freezing points of each beaker of water, analyzed his results, and formed a conclusion. What type of investigation did Charles perform? A. observational field study B. collection of specimens C. laboratory experiment D. model-building
the brake lights are not working on the vehicle with the circuit shown. with the brake pedal pressed, the technician observes the dmm readings shown. which of these could be the cause?
On the vehicle with the circuit depicted, the brake lights are not functional. The technician examines the dmm readings while applying the brakes and notices that a short to ground might be the issue.
Motor vehicles include cars, trucks, motorcycles, vans, and other on- and off-road vehicles, as well as self-propelled agriculture and construction equipment. An airplane is a type of vehicle that can fly, has wings, and one or more engines. Despite the fact that it can also refer to other types of vehicles, such helicopters, the word "aircraft" is usually used to denote planes. Any piece of machinery used to transport goods, live animals, or both is referred to as a vehicle. Cars, trucks, buses, wagons, motorbikes, bicycles, boats, airplanes, and spacecraft are just a few examples of vehicles. Some dictionaries, meanwhile, underline that the phrase only refers to equipment that transports people, live cargo, or goods on land
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Every time I take a photo, that photo has to be stored in a file somewhere within "My Files" correct?
How would I be able to take that photo out of the file it was stored?
Cut that photo by
1. Left click your mouse on the photo
2. Click cut
Then enter the file where you want to transfer and press
1. ctrl+v
Answer:
you can go to your file and then select the phpto and hold on a little bit and choose the delete option
what is the range of values that the series resistance rs can have if we wish 90% or more of the small signal source signal to be coupled into the amplifier.
The range of values for the series resistance Rs will depend on the small signal source impedance Zs. Generally, the range of values for Rs should be between (Zs/10) and (Zs/2).
What is impedance?Impedance is a measure of the opposition that a circuit presents to an alternating current (AC) when voltage and current are applied. It is measured in ohms and is the equivalent of resistance in a DC circuit. Impedance is a complex measure that is made up of both resistance and reactance. Resistance is the opposition to the flow of electric current, while reactance is the opposition to the flow of AC current due to inductance or capacitance. Impedance increases with frequency, meaning higher frequencies will experience more opposition than lower frequencies. Impedance also determines how much power is dissipated in a circuit and how much current is drawn from the source. It is important to consider the magnitude of the impedance in a circuit, as too little or too much can cause problems.
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Determine the hydraulic conductivity of a confined aquifer from which water is being pumped by a fully penetrating well. The aquifer is 100 ft thick and the well is being pumped at a rate of 1500 gpm. Water surface in two observation wells 700 ft and 70 ft from the pumped well are respectively 1 ft and 10 ft below their levels prior to the beginning of pumping.
Answer:
Hydraulic conductivity = 878.53 gpd / ft^2
Explanation:
Calculate the hydraulic conductivity of the confined aquifer
Thickness of aquifer ( b ) = 100 ft
Pump rate ( Q ) = 1500 gpm
r₂ = 700 ft
r₁ = 70 ft
h1 = 1 ft , h2 = 10 ft
To determine the hydraulic conductivity we will apply the relation below
Q = 2πKb (( h2 - h1) / In(r₂ / r₁ ) )
1500 = 2 * π * k * 100 (( -1 -(- 10 ) / In ( 700 / 70 ) )
∴ K ( hydraulic conductivity ) = [ 1500 / (( 9 / 2.30 ) ] / 2π*100
= 383.33 / 628.32
K = 0.610087 gpm /ft^2
= 878.53 gpd / ft^2