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Answer:

phosphoric

Explanation:

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Answer:

hydrochloric acid is a substance that is a binary acid .

Therefore, at 1.82 atm and 22°C, 218 mol of H2 will fill a volume of 888 L.

1 mole of any gas will take up 22.4 L of space at Standard Temperature and Pressure (STP). The quantity may be determined using the Ideal Gas Law and a balanced chemical equation.

The ideal gas law can be used to resolve this issue:

PV = nRT

The temperature must first be converted to Kelvin by adding 273.15:

T =22°C+273.15

= 295.15 K

After that, we may enter the following values:

P = 1.82 atm

n = 218 mol

R = 0.0821 L·atm/mol·K (gas constant)

So the equation becomes:

V = nRT / P

V = (218 mol)(0.0821 L·atm/mol·K)(295.15 K) / (1.82 atm)

V = 888 L.

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Answer:

The composition of a water molecule is one of the first chemical compounds we learn—H2O—two hydrogen atoms and one oxygen atom. The atoms connect in a slightly offset or triangular structure, which creates a positive charge on one side of the molecule and a negative charge on the other.

Explanation:

Water is essential to life—we learn this early in our elementary school years. This information is often accompanied by the fact that over 50% of our bodies are made up of water. However, the lesson does not always go on to explain what it is about water that makes it so essential.  

(Hope this was helpful!)

Answer:

32.2 g of Na will produce 43.4 g of Na2O.

Explanation:

The balanced chemical equation for the reaction between sodium and oxygen shows that 4 moles of sodium react with 1 mole of oxygen to produce 2 moles of sodium oxide:

4Na(s) + O2(g) → 2Na2O(s)

To solve this problem, we can use the following steps:

Step 1: Convert the mass of Na given in the problem to moles using the molar mass of Na.

molar mass of Na = 23 g/mol

moles of Na = mass of Na / molar mass of Na

moles of Na = 32.2 g / 23 g/mol

moles of Na = 1.4 mol

Step 2: Use the mole ratio from the balanced chemical equation to determine the moles of Na2O produced.

From the balanced chemical equation, we can see that 4 moles of Na react to produce 2 moles of Na2O.

moles of Na2O = (moles of Na / 4) x 2

moles of Na2O = (1.4 mol / 4) x 2

moles of Na2O = 0.7 mol

Step 3: Convert the moles of Na2O to grams using the molar mass of Na2O.

molar mass of Na2O = 62 g/mol

mass of Na2O = moles of Na2O x molar mass of Na2O

mass of Na2O = 0.7 mol x 62 g/mol

mass of Na2O = 43.4 g

Therefore, 32.2 g of Na will produce 43.4 g of Na2O.

(a) The empirical formula of the compound is \(C_{29}H_ {36}O\)

(b) The molecular formula of the compound is approximately \(C_{8}H_{118}O_{3}\)

To determine the empirical formula of the organic compound, we need to find the simplest whole-number ratio of the elements present.

(a) The given percentages of carbon, hydrogen, and oxygen can be converted into moles by dividing them by their respective atomic masses:

Carbon: 0.624 g / 12.01 g/mol = 0.052 mol

Hydrogen: 0.065 g / 1.008 g/mol = 0.064 mol

Oxygen: 0.028 g / 16.00 g/mol = 0.0018 mol

Next, we divide each of the mole values by the smallest mole value (0.0018 mol in this case) to obtain the mole ratio:

Carbon: 0.052 mol / 0.0018 mol ≈ 29

Hydrogen: 0.064 mol / 0.0018 mol ≈ 36

Oxygen: 0.0018 mol / 0.0018 mol = 1

Therefore, the empirical formula of the compound is \(C_{29}H_ {36}O\)

(b) To find the molecular formula, we need the relative molecular mass of the compound, which is given as 1940 g/mol. The empirical formula mass can be calculated by summing the atomic masses in the empirical formula:

Empirical formula mass: (29 × 12.01 g/mol) + (36 × 1.008 g/mol) + (1 × 16.00 g/mol) = 588.94 g/mol

To find the multiplier, we divide the relative molecular mass by the empirical formula mass:

Multiplier: 1940 g/mol / 588.94 g/mol ≈ 3.29

Rounding to the nearest whole number, the molecular formula of the compound is approximately 3 times the empirical formula, resulting in \(C_{8}H_{118}O_{3}\).

In summary, the empirical formula of the compound is\(C_{29}H_ {36}O\), and the molecular formula is approximately \(C_{8}H_{118}O_{3}\).

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Answer:

the de Broglie wavelength of one of the electrons is 5.3787 × 10⁻¹¹ m

Explanation:

Given the data in the question;

we know that; ( electron volt ) 1 eV = 1.602 × 10⁻¹⁹ J

so given that Kinetic Energy KE = 520 eV

KE = 520 × 1.602 × 10⁻¹⁹ = 8.3304 × 10⁻¹⁷ J

we know that;

Kinetic Energy = 1/2 × mv²

where m is the electron mass

and mass of electron is  9.109 × 10⁻³¹ kilograms

so

8.3304 × 10⁻¹⁷ = 1/2 × 9.109 × 10⁻¹⁷× v²

v = √[(8.3304 × 10⁻¹⁷) / (1/2 × 9.109 × 10⁻³¹)]

v = 1.3524 × 10⁷ m/s

speed of the electron v = 1.3524 × 10⁷ m/s

now, de Broglie equation;

wavelength λ = h / mv

where h is Planck constant ( 6.626 × 10⁻³⁴ m² kg / s )

so we substitute

wavelength λ = 6.626 × 10⁻³⁴ / ( 9.109 × 10⁻³¹ × 1.3524 × 10⁷)

wavelength λ = 5.3787 × 10⁻¹¹ m

Therefore, the de Broglie wavelength of one of the electrons is 5.3787 × 10⁻¹¹ m

Answer:

3HCl(aq)+Al(OH)3(s)=AlCl3(aq)+3H2O(l)

Explanation:

This is a double replacement reaction.

Step One: Write down the compound from the name.

Aluminum Hydroxide Al(OH)3

Hydrochloric Acid HCL

Step Two: Perform the double replacement reaction.

AB+CD=AD+CB

Step Three: Balance the equation

Final step: Write in physical states.

The physical state will either be (aq), (s), (l) or (g).

The experiment uses spectrophotometry to explore the basics of enzyme kinetics.

Spectrophotometry is an analytical technique used to measure the amount of light absorbed or emitted by a sample. It is a powerful tool for measuring the concentration of a chemical solution, as well as the purity of a compound. Spectrophotometry utilizes a spectrophotometer, which is an instrument that measures the intensity of light as it passes through a sample. This instrument is used to measure the amount of light absorbed by the sample at different wavelengths.

T - The experiment uses spectrophotometry to explore the basics of enzyme kinetics.

T - You must have a basic understanding of spectrophotometry and Beer's Law for this experiment.

T - You will generate an absorbance versus wavelength (nm) plot to determine the wavelength absorbance maximum of p-nitro aniline.

T - The absorbance of p-nitro aniline will be monitored to generate absorbance versus time graphs to determine the rate of reaction.

F - The experiment will determine the order of reaction for breaking peptide bonds in a substrate.

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Answer:

Rutherford used scientific investigation to study atoms.

Scientist who used scientific investigations to study atoms is Rutherford.

Atoms are the basic fundamental or functional unit of any substance present in the nature.

Rutherford is also known as the father of nuclear physics and he did scientific investigation on the massive part of atom called nucleus he discovered that there are two types of radiation, coming from the uranium atom are alpha and beta particles.

Scientific investigation is a method in which scientist will study, perform and observe results for the experiment.

Hence Rutherford used scientific investigation.

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Answer:

c

Explanation:

BaSO4 (s) + Cu(NO3)2 (aq)  and KCl (s) + Mg3(PO4)2 (s) is the product of given precipitation reactions.

Ba(NO3)2 (aq) + CuSO4 (aq) → BaSO4 (s) + Cu(NO3)2 (aq)

 K3 PO4 (aq) + MgCl2 (aq) → KCl (s) + Mg3(PO4)2 (s)

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Answer:

Add to a 500mL volumetric flask 300mL of water, the 129mL of the 11.6M HCl solution and then complete to volume with water

Explanation:

To make 500mL = 0.500L of a 3M HCl from the 11.6M HCl stock we need first to find the moles of HCl we need:

Moles HCl:

0.500L * (3mol / L) = 1.5 moles of HCl are needed

These moles are obtained from the 11.6M HCl solution. The volume required is:

1.5mol * (1L / 11.6moles HCl) = 0.129L = 129mL must be added to the solution.

That means to prepare the 500mL of the 3M HCl you need to:

Add to a 500mL volumetric flask 300mL of water, the 129mL of the 11.6M HCl solution and then complete to volume with water

Answer:

Calculation: 11.6 M × V = 3.0 M × 0.500 liters

V = 0.13 liters

Steps for dilution:

Measure out 0.13 liters of the concentrated solution of 11.6 M HCl using a volumetric pipet.

Transfer this into solution into a 500 milliliter volumetric flask.

Add water to the flask until it reaches a total volume of 500 milliliters.

Solution: V = 0.13 liters

Explanation:

Answer:

D

Explanation:

just did the test

Answer:

d

Explanation:

switch the stages evaluate the solution and design a solution

Answer:

Answer: 3.45 moles Li contains 2.08 × 10 (to the power of)24 atoms . Explanation: The relationship between atoms and moles is:. 1 mole atom. =6.022

Answer:

\(\boxed {\sf 5.63 \times 10^{24} \ atoms \ Li}}\)

Explanation:

We are asked to find how many atoms are in 9.35 moles of lithium (Li)

Moles are converted to atoms using Avogadro's Number or 6.022×10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of lithium.

We convert using dimensional analysis, so we set up a conversion factor using Avogadro's Number.

\(\frac {6.022 \times 10^{23} \ atoms \ Li}{1 \ mol \ Li}\)

We are converting 9.35 moles of lithium to atoms, so we multiply the conversion factor by this value.

\(9.35 \ mol \ Li *\frac {6.022 \times 10^{23} \ atoms \ Li}{1 \ mol \ Li}\)

The units of moles of lithium cancel.

\(9.35 *\frac {6.022 \times 10^{23} \ atoms \ Li}{1 }\)

\(9.35 *{6.022 \times 10^{23} \ atoms \ Li}\)

\(5.63057\times10^{24} \ atoms \ Li\)

The original value of moles (9.35) has 3 significant figures, so our answer must have the same. For the number we found that is the hundredth place. The 0 in the thousandth place tells us to leave the 3 in the hundredth place.

\(5.63 \times 10^[24} \ atoms \ Li\)

9.35 moles of lithium contains approximately 5.63×10²⁴ atoms of lithium.

Ksp is a constant that gives the following:

For the solution of AgBr:

So, given an initial pure water, let s be the solubility of AgBr. If we add s of AgBr, it will dossiciate into s Ag⁺ and s Br⁻, so, for a saturated solution of AgBr, we have:

So, the solubility of AgBr is approximately 7.1 x 10⁻⁷ M.

There are actually no disproportionation reaction in the question. They are all incomplete and unbalanced.

Example of a disproportionate reaction:

For this reaction the chlorine atom on the reactant side as an oxidation state of 0. It gets reduced to -1 in Cl- and oxidized to +1 in ClO3-

Answer:

B people control how plants or animals reproduce to get desired traits

Explanation:

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Answer:

I would say maybe a stove? only if it's a gas stove tho- because of course you would need gas for a gas stove-

The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.

Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.

Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.

It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.

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Answer:

Mg₂P₂O₇ · 3 H₂O

Explanation:

(Step 1)

First, you need to convert each mass to moles via the molar masses of each element/compound.

Molar Mass (Mg): 24.305 g/mol

4.86 grams Mg              1 mole
------------------------  x  ------------------------  = 0.200 moles Mg
                                   24.305 grams

Molar Mass (P): 30.974 g/mol

6.20 grams P              1 mole
---------------------  x  ------------------------  =  0.200 moles P
                                30.974 grams

Molar Mass (O): 15.998 g/mol

11.20 grams O               1 mole
-----------------------  x  -----------------------  =  0.700 moles O
                                  15.998 grams

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

5.40 grams H₂O               1 mole
--------------------------  x  -----------------------  =  0.300 moles H₂O
                                     18.014 grams

(Step 2)

To find the amount of each element/compound in the formula, you need to divide each molar value by the smallest molar value. This allows you to determine the accurate molar ratio the hydrated salt should have. In this case, 0.200 moles is the smallest value.

0.200 moles Mg / 0.200  =  1 mole Mg

0.200 moles P / 0.200  =  1 mole P

0.700 moles O / 0.200  =  3.5 moles O

0.300 moles H₂O / 0.200  =  1.5 moles H₂O

There can only be whole number amounts of each element/compound in the formula. Therefore, you need to multiply each amount by 2.

1 mole Mg x 2 = 2 moles Mg

1 mole P x 2 = 2 moles P

3.5 moles O x 2 = 7 moles O

1.5 moles H₂O x 2 = 3 moles H₂O

(Step 3)

Now that we know the amount of each element/compound, we can build the formula. The amount of each element is represented by subscripts and the amount of each compound (H₂O) is represented by coefficients.

Mg₂P₂O₇ · 3 H₂O

The mole of the substance, given the data from the question is 0.0014 mole

This is simply defined as the mole of solute per kilogram of water. Mathematically, it is expressed as

Molality = mole / mass (Kg) of water

Mole = molality × mass of water

Mole of substance = 0.056 × 0.0254

Mole of substance = 0.0014 mole

Thus, the mole of the substance is 0.0014 mole

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• We are given the following :

P = 10 Atm

V= 50 L

R=0.0821atm/mole-k)

T= 27°C = 273.15 + 27°C = 300 .15 K = 300K

• We will use the following formula in order to find moles of hydrogen gas

PV = nRT

n = PV /RT

=( 10 * 50 )/ ( 0.0821 * 300)

n = 500/24.63

n = 20.3 moles

Therefore ; moles of hydrogen gas present = 20.3 moles

How much of the original sample will still be there at the end of the second year if the half-life of a radioactive isotope sample is one year? by the third year's end?

when the fourth year comes to an end? Answer The balance at the conclusion of the second year equals 1 4 times the initial amount. The balance at the conclusion of the third year is equal to 1/8 of the initial amount. Radioactive isotopes that are unstable usually undergo radioactive decay in order to become stable. The nucleus of the isotope undergoes a spontaneous nuclear transition during this event, and particles and energy are released. The decay process causes half of the isotope's initial mass to disintegrate at a specific point in time known as the half-life.

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