Antoine burns some charcoal, and a very small diamond, and makes the observation that the only product of both reactions is a heavy gas (carbon dioxide).
The descriptions of scientists engaging in activities that are part of the scientific method.
When Antoine burns charcoal and a small amount of diamond, then in that case, each Carbon atom will form a tetrahedral bond with the other four carbon atoms which are present in a Diamond.
Due to the formation of the tetrahedral bond the structure becomes more and more compact and rigid.
Hence, the missing word is given below.
Antoine burns some charcoal, and a very small diamond (l) and makes the observation that the only product of both reactions is a heavy gas.
Missing word:- Observation
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Explain why sugar was used in this experiment. How does the experiment relate to a baker adding yeast to bread to make it rise?
Answer:
Yeast can use oxygen to release the energy from sugar (like you can) in the process called "respiration". ... So, the more sugar there is, the more active the yeast will be and the faster its growth (up to a certain point - even yeast cannot grow in very strong sugar - such as honey).
Bio-mimetic gel was used in the study of genetics and ultimately banded by the Federation. A Ferengi transport ship is carrying a 5-centimeter [cm] radius cylindrical tank of bio-mimetic gel to sell on the black market. A hydrostatic pressure probe located at the bottom of the tank reads 60 millimeters of mercury [mm Hg]. If the specific gravity of the gel is 8.9, what is the mass of gel contained in the tank in units of kilograms [kg]
Answer:
m = 6.4 kg
Explanation:
Now, we use the following equation to find the mass of the gel:
\(P = \rho gh\)
where,
P = (60 mm of Hg)(133.3 Pa/1 mm of Hg) = 7999.2 Pa = 7.99 KPa
ρ = density of gel = \(\frac{m}{V} = \frac{m}{\pi r^2 h}\)
m = mass of gel = ?
r = radius of cylindrical tank = 5 cm = 0.05 m
h = height of tank
Therefore,
\(7999.2 Pa = (\frac{m}{\pi(0.05\ m)^2\ h})(9.81\ m/s^2)h\\\\\frac{(7999.2\ Pa)(\pi)(0.05\ m)^2}{9.81\ m/s^2} = m\\\)
m = 6.4 kg
A motorcyclist is traveling in the positive direction at a
velocity of 7.0 meters per second. She increases her
velocity to 9.0 meters per second. What additional
information is needed to calculate the acceleration of
the motorcycle?
The additional information needed to calculate the acceleration of the motorcycle is the time taken to complete the distance.
What is acceleration?Acceleration is the amount by which a speed or velocity increases (and so a scalar quantity or a vector quantity).
The acceleration of a moving body can be calculated by dividing the change in velocity of the motion (∆V) by the time taken to complete the motion as follows:
Acceleration (m/s²) = change in velocity (m/s)/time(s)
According to this question, a motorcyclist is traveling in the positive direction at a velocity of 7.0 meters per second. She then increases her velocity to 9.0 meters per second. This means that the change in velocity {∆V} is 2m/s.
However, the time taken to complete the distance is still required to compute the acceleration of the motorcycle.
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why is joule called called a derived unit?
Answer:
Joules is considered as the SI unit because it measures the capacity to do work or generate heat
Answer:
when an electric current of one ampere passes through a resistance of one ohm for one second. It is named after the English physicist James Prescott Joule
Explanation:
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A horizontal ruler from 0 to 100. An image of an upward pointing arrow in a frame, at 0. A double convex lens at 100. X marked in the center of the ruler.
What does the “X” on the horizontal line represent?
Draw the ray diagram in your notes, showing only the principal rays. Explain why you don’t need to draw more rays.
Where will the image appear? On the left or on the right of the lens? At which mark on the ruler?
How will the image look? Upright or inverted? Same size, larger, or smaller?
Horizontal lines are referred to as being parallel to a x-axis in coordinate geometry. A line is referred to as horizontal if two points on the line share the same y-coordinate points.
What does a graph's x-axis / horizontal line represent?The intersection of the vertical and horizontal (X axis) real number lines is shown on the axis graph (Y axis). The Y axis is known as the dependent variable of the data set, whereas the X axis is typically used to refer to the independent variable of the data set.
In the line graph, how does X show up?The horizontal x-axis and vertical y-axis are the two axes of a line graph (vertical). A different type of data is indicated at each of the points where the axes connect, and (0,0). The x-axis is referred to as an independent axis since the numbers it represents are not reliant on any of the variables being assessed.
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Angle R in the picture below is the angle of...
The angle I can rightly be called the angle of reflection.
What is the law of angle of reflection?The incident ray, the reflected ray, and the normal all reside on the same plane, according to the angles of reflection. This suggests that reflection may occur when two angles are in the same plane as the normal.
The angle I and depicted can appropriately be referred to as the angle of reflection in light of the aforementioned information.
Lastly, it is obvious from the image that angle I is the angle of reflection.
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A particle performs simple harmonic motion with period Pi/2 seconds and amplitude 12 m. What is the maximum velocity (in m/s)?
The maximum velocity is 48π m/s.
To solve this problem
The equation: can be used to determine the maximum velocity of a particle in simple harmonic motion.
Vmax = ω * A
Where
Vmax is the maximum velocityω (omega) is the angular frequencyA is the amplitude of the motionThe following formula can be used to get the angular frequency:
ω = 2π / T
Where
T is the motion's period.
Given that the period is π/2 seconds (T = π/2) and the amplitude is 12 m (A = 12), we can find the angular frequency:
ω = 2π / (π/2) = 4π rad/s
Now we can calculate the maximum velocity:
Vmax = ω * A = (4π rad/s) * (12 m) = 48π m/s
Therefore, the maximum velocity is 48π m/s.
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1. The development of what anatomical structure is one current idea for how the Cambrian Explosion began (the so-called Evolutionary Big Bang)? The
Answer:
One idea is how, on an astronomical level, the planets can be observed to spread apart continuously.
Explanation:
Throughout various studies, many have observed that the planets continuously grow distant from each other. In fact, it is observed through our technological advances that the very galaxies are slowly drifting apart. Thus, indicating there must have been some big bang to set these galaxies and planets in motion.
A steel wire in a piano has a length of 0.540 m and a mass of 4.800 ✕ 10−3 kg. To what tension must this wire be stretched so that the fundamental vibration corresponds to middle C (fC = 261.6 Hz on the chromatic musical scale)?
Answer:
T = 708.81 N
Explanation:
Given that,
Length of a steel wire in a piano, l =0.54 m
Mass, \(m=4.8\times 10^{-3}\ kg\)
We need to find the tension must this wire be stretched so that the fundamental vibration corresponds to middle C, fc = 261.6 Hz
The equation for fundamental frequency is given by :
\(f=\dfrac{1}{2l}\times \sqrt{\dfrac{T}{\mu}} \\\\f=\dfrac{1}{2l}\times \sqrt{\dfrac{T}{\dfrac{m}{l}}} \\\\261.6=\dfrac{1}{2\times 0.54}\times \sqrt{\dfrac{T}{\dfrac{4.8\times 10^{-3}}{0.54}}} \\\\261.6\times 2\times 0.54=\sqrt{\dfrac{T}{\dfrac{4.8\times 10^{-3}}{0.54}}}\\\\282.528=\sqrt{\dfrac{T}{0.00888}} \\\\(282.528)^2=\dfrac{T}{0.00888}\\\\T=708.81\ N\)
So, the required tension in the wire is 708.81 N.
What causes the poles of the electromagnet in an audio speaker to repeatedly switch directions?
a metal striker that pulls on the magnet
a diaphragm that vibrates around the magnet
a current that rapidly switches direction
a device that opens and closes a circuit
Answer:
he is right its c
Explanation:
Answer:
a current that rapidly switches direction
Explanation:
What is mass divided by volume
Answer:
mass/volume is the density of an object
1. What is the distance covered by a T-Rex that goes from 0 m/s to 9 m/s in 6.78 seconds? (10
points)
With the use of first and third equation of motion, the distance covered by a T-Rex is 30.51 m
Linear MotionWhen a body is in linear motion, the body is moving in a straight line. some of the parameters to consider are:
Distance coveredSpeedVelocityAccelerationE.T.CGiven that a T-Rex move from 0 m/s to 9 m/s in 6.78 seconds, the distance covered can be found by calculating the acceleration.
Let us use equation 1
V = U + at
9 = 0 + 6.78a
a = 9 / 6.78
a = 1.33 m/\(s^{2}\)
Now let us use equation 3
\(v^{2}\) = \(u^{2}\) + 2as
\(9^{2}\) = 2 x 1.33 x S
81 = 2.655S
S = 81/2.655
S = 30.51 m
Therefore, the distance covered by a T-Rex is 30.51 m.
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A park ranger driving on a back country road suddenly sees a deer in hisheadlights 20 m ahead. The ranger, who is driving at 11.4 m/s, immediatelyapplies the brakes and slows down with an acceleration of 3.80 m/s2. Howmuch distance is required for the ranger's vehicle to come to rest? Onlyenter the number, not the units.
Answer:
17.1 m
Explanation:
To know how much distance is required to get a final velocity of 0 m/s, we need to use the following equation:
\(v^2_f=v^2_0+2a(\Delta x)\)Where vf is the final velocity, v0 is the initial velocity, a is the acceleration and Δx is the distance required. So, replacing vf by 0 m/s, v0 by 11.4 m/s, and a by -3.8 m/s² we get:
\(\begin{gathered} 0^2=(11.4)^2+2(-3.8)(\Delta x) \\ 0=129.96-7.6(\Delta x) \end{gathered}\)Then, solving for Δx, we get:
\(\begin{gathered} 7.6\Delta x=129.96 \\ \Delta x=\frac{129.96}{7.6} \\ \Delta x=17.1\text{ m} \end{gathered}\)Therefore, the vehicle required 17.1 m to come to rest.
Which of the following is most likely the caption for the illustration that was scratched out of the textbook?
A. An electrically-charged object can attract an uncharged object with magnetic properties.
B. An electrically-charged object is stronger than a magnet.
C. A dry cell battery has magnetic properties.
D. An electric circuit can only have one dry cell battery.
IMAGE DOWN BELOW OR UP
The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.
A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.
The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.
So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.
Therefore, The correct answer is option C.
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A 0.050 kg bullet strikes a 5.0 kg wooden block with a velocity of 909 m/s and embeds itself in the block which fies off its stand. what was the final velocity of the bullet?
Answer:
The final velocity of the bullet is 9 m/s.
Explanation:
We have,
Mass of a bullet is, m = 0.05 kg
Mass of wooden block is, M = 5 kg
Initial speed of bullet, v = 909 m/s
The bullet embeds itself in the block which flies off its stand. Let V is the final velocity of the bullet. The this case, momentum of the system remains conserved. So,
\(mv=(m+M)V\\\\V=\dfrac{mv}{m+M}\\\\V=\dfrac{0.05\times 909}{0.050+5}\\\\V=9\ m/s\)
So, the final velocity of the bullet is 9 m/s.
¿Es posible que un objeto se mueva en
una dirección distinta de la dirección de la fuerza neta
que actúa sobre el objeto?
Answer:
translate it to English plss
A point charge is positioned inside an imaginary cubic box (Gaussian surface) whose side length is L. The smaller cube is placed inside a larger cube whose side length is 2L. Which of the following is true regarding the electric flux going through the two cubic Gaussian surfaces?
a. The flux through the large cube is twice that through the small cube.
b. The flux through the large cube is eight gimes that through the small cube.
c. Cannot determine the relationship between flux through the two cubes because the exact location of point charge is unknown.
d. The flux through the two cubes are the same.
e. None of the other answers are true
The flux through the large cube is four times that through the small cube.
Electric flux is the rate at which the electric field flows through a given area. The electric flux is directly proportional to the number of electric field lines going through the virtual surface.
i.e. Flux is directly proportional to Area.
For an electric field, the mathematical relation between an enclosed charge and electric field is given by Gauss’s Law. It is one of the core law in electromagnetism. The Gauss law states that the total electric flux through a hypothetical closed surface is always equal to (1/ε0) times the net charge enclosed by the surface.Let A1 = Area of gaussian surface with length L.
A2= Area of gaussian surface with length 2L.
Since this is a cube, area of cube = \(6L^{2}\) , where L = length of side
So, A1 = \(6L^{2}\) and A2 = \(24L^{2}\)
On dividing these two, we get A1/A2 = 1/4
i.e. A2 = 4 A1
Hence the flux through the large cube is four times that through the small cube.
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what must be the mass of a rock if a boy applies a 64N force and causes it to accelerate at 4.51m/s2
first of all the formula of force is F=ma,so we are searching for m,so we can divide a on both sides F/a=m, after this substitute the values given above 64N/4.51=14.2°Kg
7. Apply Concepts: suppose the dog walked at a constant speed the whole way. What
would the graph look like then? Explain.
If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.
What is the speed about?A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.
If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.
In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.
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Please help!! An astronaut passes out when the centrifuge reaches an acceleration of 12 g. If the centrifuge has
a radius of 11.5 m, at what speed will the astronaut pass out?
Answer:
the speed of the astronaut is 36.78 m/s.
Explanation:
Given;
centripetal acceleration of the astronaut, \(a_c\) = 12 g = 12 x 9.8 m/s² = 117.6 m/s²
radius of the centrifuge, r = 11.5 m
The speed of the astronaut is calculated as follows;
\(a_c = \frac{v^2}{r} \\\\v^2 = a_c r\\\\v = \sqrt{a_c r} \\\\v = \sqrt{117.6 \times 11.5} \\\\v = 36.78 \ m/s\)
Therefore, the speed of the astronaut is 36.78 m/s.
selasie2. A particle is displaced from the point (-8 m, -10 m) to the point (1 m, 1 m).Calculate the magnitude of its displacement vector. (1 point)A. O14.213 mB. O 202 mC. O 12.728 mD. O 11.402 mE. O 130 m3. A particle is displaced from the point (-4 m, -8 m) to the point (9 m, -1 m) in 30 secCalculate the magnitude of its average velocity. (1 point)A. O 0.409 m
A)14.213 m
Explanationthe distance between 2 points can be found by usign the formula:
\(\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ where \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}\)This formula is derived from the Pythagorean theorem.
Step 1
given
\(\begin{gathered} P1(-8,-10) \\ P2(1,1) \end{gathered}\)now, replace in the formula
\(\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt{(1-(-10))^2+(1-(-8))^2} \\ d=\sqrt{(11)^2+(9)^2} \\ d=\sqrt{121+81} \\ d=\sqrt{202} \\ d=14.213 \end{gathered}\)therefore, the answer is
A)14.213 m
I hope this helps you
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Two football players collide inelastically in a tackle, initially moving with the same speed in opposite directions (as indicated in the picture). If Player A has a mass of 90 kg and Player B has a mass of 75 kg, which direction will the move after the collision?
If Player A has a mass of 90 kg and Player B has a mass of 75 kg, Player B will move in the opposite direction.
What is collision?A collision is defined in physics as any occurrence in which a number of bodies exert forces on one another over relatively brief period of time. Although the most popular meaning of the term collision refers to occurrences wherein two or even more objects crash violently.
Two football players collide in elastically in a tackle, initially moving with the same speed in opposite directions (as indicated in the picture). If Player A has a mass of 90 kg and Player B has a mass of 75 kg, Player B will move in the opposite direction.
Therefore, if Player A has a mass of 90 kg and Player B has a mass of 75 kg, Player B will move in the opposite direction.
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A battery has an emf of 3.15 V and produces a current of 12 A when connected across its terminals. What is its internal resistance
According to Ohm's Law, if the voltage applied to a circuit is V and a current I flows through it, then the resistance R of the circuit is given by:
\(R=\frac{V}{I}\)Replace V=3.15V and I=12A to find the resistance of the circuit:
\(R=\frac{3.15V}{12A}=0.2625\Omega\)Therefore, the internal resistance of the battery is approximately 0.26 ohms.
On a warm summer day, a large mass of air (atmospheric pressure 1.01×105Pa) is heated by the ground to a temperature of 25.0 ∘C and then begins to rise through the cooler surrounding air. Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×104 Pa. Assume that air is an ideal gas, with γ=1.40. (This rate of cooling for dry, rising air, corresponding to roughly 1 ∘C per 100 m of altitude, is called the dry adiabatic lapse rate.)
The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.
Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.
Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:
(1.01×10⁵ Pa)×V = (nR/T1)×T1(8.70×10⁴ Pa)×V = (nR/T2)×T2Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:
(T2/T1) = [(P2/P1)^(γ-1)/γ] = [(8.70×10⁴ Pa)/(1.01×10⁵ Pa)]^(1.4/1.4) = 0.813Solving for T2, we get:
T2 = T1×(P2/P1)^(γ-1)/γ = (25+273) K×0.813 ≈ 287.3 K ≈ 14.3°CThus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.
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You run to your home to a friend's home that is 8 miles away. You then walk home. What was your displacement ? Remember to include the correct units .
Answer:
Explanation:
0!!!!!! There was no displacement. That was the point of the question.
You run 8 miles in one direction. You walk - 8 miles on the return to home. You have not moved in terms of displacement. Displacement is distance that has direction.
The distance that you have travelled during the day is 8 + 8 = 16 miles. Distance does not account for direction. That's why your car has gone a distance of more than 0 miles. If the car measured displacement it would always read 0 when you returned home -- kind of a useless piece of information. You would never know when to get an oil change.
Una anciana camina 0.30 km en 10 minutos dando la vuelta un centro comercial calcule su rapidez media 
The average speed of the elderly woman walking around the shopping center is 1.80 km/h.
To calculate the average speed of the elderly woman, we can use the formula for velocity, which is equal to the distance traveled divided by the time taken. In this case, the distance traveled is 0.30 km and the time taken is 10 minutes. However, average speed is generally expressed in units of distance per unit of time, so we need to convert minutes to hours.
There are 60 minutes in one hour, so 10 minutes is equal to 10/60 = 1/6 hours.
Now we can calculate the average speed by dividing the distance traveled (0.30 km) by the time taken (1/6 hours):
Average speed = 0.30 km / (1/6 h)
= 0.30 km * (6/1 h)
= 1.80 km/h
Therefore, the average speed of the elderly woman walking around the shopping center is 1.80 km/h.
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The figure above shows Case 1 of an experiment, in which the following events occur.
At time t1
, block A slides to the right along a horizontal surface toward identical block B, which is at rest.
At time t2
, block A collides elastically with block B and block A comes to rest.
At time t3
, the right side of block B reaches an ideal, horizontal spring with negligible mass and spring constant k1
. The spring is initially at its relaxed (uncompressed) length and fixed to a wall.
At time t4
, the spring is compressed a maximum distance d1
and block B is instantaneously at rest.
Assume there is negligible friction between each block and the surface. For parts (a)-(d), consider the system consisting of block A, block B, and the spring.
(a) Indicate whether the linear momentum of the two-block–spring system is either constant or not constant during the time interval from t1
to immediately before t3
, and explain why.
Over the time period from t₁ to just before t₃, the two-block-spring system is linear momentum does not change because there are no external forces acting on the system to change its momentum.
Explain why the linear momentum of the two-block–spring system is either constant or not during the time period between t₁ and the time just before t₃?
The linear momentum of the two-block-spring system remains constant from t₁ until just before t₃.
Prior to the collision at time t₂, block A has a momentum to the right that is Pa = ma ×va, whereas block B has a momentum that is Pb = 0 because it is at rest. Because there is no external force acting on the system, its overall momentum is conserved.
All out Ptotal = Dad + Pb = mama × va
Expect there is immaterial erosion between each block and the surface. Take into consideration the spring, block A, and the system for parts (a) to (d).
Following the collision at time t₂, block B experiences a velocity of vb to the right and comes to a stop. Because the collision is elastic, all of the system's kinetic energy is conserved, but momentum is still conserved:
The two-block system is moving to the right at a constant velocity vb from time t₂ to just before time t₃, so the momentum of the system is constant. Ptotal = ma₀ plus mbvb plus mb ×vb
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A convex mirror has a focal length of -12 cm. A lightbulb with
a diameter of 6.0 cm is placed 60.0 cm in front of the mirror.
Locate the image of the lightbulb. What is its diameter?
Answer:
PLEASE MARK AS BRAINLIEST!!
Explanation:
ANSWER IS IN THE IMG BELOW
An electric current through neon gas produces several distinct wavelengths of visible light. What are the wavelengths (in nm) of the neon spectrum, if they form first-order maxima at angles of 49.67°, 50.65°, 52.06°, and 52.89° when projected on a diffraction grating having 11,000 lines per centimeter? (Round your answers to the nearest nanometer. Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign. Enter your answers from smallest to largest.)
Answer:
Explanation:
If a be grating element
a = 1 x 10⁻² / 11000
= .0909 x 10⁻⁵
= 909 x 10⁻⁹ m
for first order maxima , the condition is
a sinθ = λ where λ is wavelength
909 x 10⁻⁹ sin 49.67 = λ₁
λ₁ = 692.95 nm .
λ₂ = 909 x 10⁻⁹ sin 50.65
= 702.91 nm
λ₃ = 909 x 10⁻⁹ sin 52.06
= 716.88 nm
λ₄ = 909 x 10⁻⁹ sin 52.89
= 724.90 nm
692.95 nm , 702.91 nm , 716.88 nm , 724.90 nm .