any considerable variation in seismic wave velocity in the crust occurs because
Answers
Any considerable variation in seismic wave velocity in the crust occurs because there are different types of rocks in the crust.
Seismic waves are waves of energy that travel through the Earth's interior, including the crust. The speed of these waves varies depending on the type of rock they are travelling through. The Earth's crust is made up of a variety of different rocks, such as sedimentary, igneous, and metamorphic rocks, each with its own unique density, elasticity, and other properties that affect the speed of seismic waves.
As a result, seismic waves can be used to study the composition and structure of the Earth's crust, and the variation in their velocity is a crucial aspect of this study. Therefore, the correct answer is that any considerable variation in seismic wave velocity in the crust occurs because there are different types of rocks in the crust.
The complete question is:-
Any considerable variation in seismic wave velocity in the crust occurs because
Group of answer choices
there are different types of rocks in the crust
waves move slower the deeper they travel
waves move faster the deeper they travel
there is no variation of velocity in the crust.
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There are several factors that can cause significant variations in seismic wave velocity within the Earth's crust, including:
1) Rock type: Different types of rock have different physical properties, including density and elasticity, which affect the speed at which seismic waves travel through them. For example, dense, hard rocks like granite have higher seismic velocities than softer, more porous rocks like sandstone.
2) Temperature: Seismic wave velocity is also influenced by temperature, with higher temperatures generally resulting in lower velocities.
This is because hotter rocks tend to be more ductile and less rigid, which reduces their ability to transmit seismic waves quickly.
3) Pressure: Pressure can also affect seismic wave velocity, with higher pressures generally resulting in higher velocities.
This is because high pressure can cause rocks to become more compact and less porous, which increases their ability to transmit seismic waves.
4) Presence of fluids: The presence of fluids such as water or oil can also affect seismic wave velocity. Fluids tend to decrease seismic velocities by reducing the effective stress and increasing the porosity of rocks.
Overall, the complex interplay of these factors can result in significant variations in seismic wave velocity within the Earth's crust, which can provide important information about the geological structure and composition of the subsurface.
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Related Questions
we can catch a rolling ball but not a flying bullet?? give reason
Answers
Answer:
yeah this statement is tru
Explanation:
it is because the speed of the bullet is more than the speed of rolling ball .so from this reason we cannot catch a bullet.
A bullet will be moving much faster than a rolling ball. Even seeing a bullet in flight requires it to be extremely low velocity.
When is the electromotive force greatest on the electrons in a coil of wire? Select one:a.when the coil of wire is moving perpendicular to the magnetic field b.when the coil of wire is stationary in a magnetic fieldc.when the coil of wire is outside the magnetic field d.when the coil is moving parallel to the magnetic field
Answers
Explanation:
The electromotive force acts when the magnetic field is applied to a current-carrying wire.
The electromotive force is given by the formula
\(F=qvBsin\theta\)Here, v is the velocity, q is the charge and theta is the angle between the magnetic field and direction of velocity.
The electromotive force will be maximum when the coil of wire is moving perpendicular to the magnetic field.
Thus, the correct option is a
Two tuning forks are producing sounds of wavelength 34.50 cm and 33.88 cm simultaneously. Part A How many beats do you hear each second? Express your answer in beats per second. beats/s
Answers
We hear 0.003 beats per second.
The beats per second (BPS) can be calculated using the formula:
BPS = (wavelength of first fork - wavelength of second fork) / 2 * frequency of first fork
where the wavelength of the first fork is 34.50 cm and the wavelength of the second fork is 33.88 cm.
First, we need to find the frequency of the first fork:
frequency of first fork = speed of sound in air / wavelength of first fork
speed of sound in air = 343 m/s
wavelength of first fork = speed of sound in air / frequency of first fork
wavelength of first fork = 343 m/s / 2000 Hz
wavelength of first fork = 0.1715 meters
Therefore, the frequency of the first fork is 2000 Hz.
Next, we can find the beats per second:
BPS = (0.1715 meters - 0.1655 meters) / 2 * 2000 Hz
BPS = 0.006 meters / 2 * 2000 Hz
BPS = 0.003 beats/s
Therefore, we hear 0.003 beats per second.
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The table provided shows data collected during an experiment .
Which of the following claims is supported by the data?
A. Gravitational force are proportional to the masses of the two objects.
B. Gravitational forces are strongest between objects with identical masses.
C. Gravitational forces are weakest when one object is more massive than the other.
Answers
Answer:
Explanation: the table shows during an experiment
Gravitational forces are strongest between objects with identical masses, claims are supported by the data. Option B is correct.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.
From the table, it is observed that gravitational forces are strongest between objects with identical masses, claims are supported by the data.
Hence, option B is correct.
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Determine the mass of a boat that is propelled forward by a force of 1250N at an acceleration of 3 m/s2.
Answers
Answer:
416.6 KG
Explanation:
Due to the mass being missing from the equation you divide the force by the acceleration
A 650 kg steel beam is being pulled up by a crane with a force of 7020 N. What is the upwards acceleration of the beam?
Answers
Answer: 1 m/s^2
Explanation:
n= w+ma
n= Mg+Ma
7020 = (650)(9.8)+650a
7020 = 6370+ 650a
650=650a
A= 1 m/s^2
The upward acceleration of the steel beam will be approximately 10.8 m/s².
To calculate the upward acceleration of the steel beam, we can use Newton's second law of motion:
F = m × a
Where:
F is the force applied (7020 N),
m is the mass of the steel beam (650 kg), and
a is the acceleration.
Rearranging the formula, we can solve for the acceleration:
a = F / m
Substituting the given values:
a = 7020 N / 650 kg
Calculating this expression:
a ≈ 10.8 m/s²
Therefore, the upward acceleration of the steel beam will be approximately 10.8 m/s².
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Object B is at rest when object A collides with it. The collision is one-dimensional and elastic. After the collision object B has half the velocity that object A had before the collision....
1.) Which object has the greater mass?
2.) By how much is the mass of object B greater than that of object A?
3.) If the velocity of object A before the collision was 6.0 m/s to the right, what is its velocity after the collision?
Answers
1. Object B has greater mass.
2. The mass of object B is twice the mass of object A.
3. The velocity of object A after the collision is 3.0 m/s to the right.
Since the collision is elastic, the total momentum before and after the collision is conserved. Let the masses of object A and object B be m1 and m2, respectively, and let v1 and v2 be their velocities before the collision. We know that object B has half the velocity of object A after the collision, which means that v2 = v1/2. Also, we know that momentum is conserved, so m1v1 = m1v1' + m2v2'.
Since object B was at rest before the collision, we have v2' = (2m1v1 - m1v1')/m2. Now we can substitute v2' = v1/2 and solve for m2/m1 = 2. Therefore, the mass of object B is twice the mass of object A. Finally, we can use the conservation of momentum to find the velocity of object A after the collision, which is 3.0 m/s to the right.
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An ambulance emits a sound with a frequency of 786 Hz.
If the ambulance is moving toward a stationary observer
at 20 m/s, what is the perceived frequency by the
observer?
Answers
An ambulance emits a sound with a frequency of 786 Hz and it is moving toward a stationary observer at 20 m/s. The perceived frequency by the observer is higher than 786 Hz, specifically 832 Hz.
This is because of the Doppler effect, where the frequency of sound waves appears higher when the source is moving towards the observer. The formula to calculate the perceived frequency is f' = f ((v +/- vd) / (v +/- vs)), where f is the original frequency, v is the speed of sound, vd is the speed of the source, and vs is the speed of the observer.
In this case, the ambulance is the source and the observer is stationary, so vs is 0.
Substituting the values, f' = 786 ((343 + 20) / (343 + 0)) = 832 Hz.
Therefore, the perceived frequency is higher than the original frequency due to the movement of the source towards the observer.
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parallel adaptive fluid–structure inter- action simulation of explosions impacting on building structures.
Answers
The phrase "parallel adaptive fluid–structure interaction simulation of explosions impacting on building structures" refers to a computational method used to study the effects of explosions on buildings. Let's break it down step by step:
"Parallel adaptive": This refers to the use of parallel computing techniques, where multiple processors or cores work together to solve the simulation problem faster. It allows for efficient computation of complex simulations by dividing the workload.
"Fluid–structure interaction": This term describes the interaction between a fluid (such as air or water) and a solid structure (such as a building) in a simulation. It considers how the fluid affects the structure and vice versa. In this case, it refers to how the explosion impacts the building and how the building responds to the explosion.
"Simulation of explosions impacting on building structures": This means that the simulation aims to model the effects of explosions on buildings. It can help researchers and engineers understand how buildings behave under explosive forces, and can be used to design safer structures or develop strategies to mitigate the damage caused by explosions.
The phrase refers to a computational method that uses parallel computing techniques to simulate the interaction between fluids and structures, specifically focusing on explosions impacting building structures. This simulation can provide valuable insights into the behavior of buildings under explosive forces.
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A big olive (* - 0.50 kg) lies at the origin of an xy coordinate system, and a big BrazlI nut (M - 1.5^kg) lie^s at the point (1 .0,2.0) m. At t : 0, a force Fo : Q.Oi 3.0j ) N begins to act on the olive, and a force Fn: (-3.0i - 2.0i) N begins to act on the nut. In unit-vector notation, what is the displacement of the center of mass of the olive
Answers
The estimated displacement of the center of mass of the olive is \(\overrightarrow{\Delta r} = -0.046\,\hat{i} -0.267\,\hat{j}\,[m]\).
Procedure - Estimation of the displacement of the center of mass of the oliveIn this question we should apply the definition of center of mass and difference between the coordinates for dynamic (\(\vec r\)) and static conditions (\(\vec r_{o}\)) to estimate the displacement of the center of mass of the olive (\(\overrightarrow{\Delta r}\)):
\(\vec r - \vec r_{o} = \left[\frac{\Sigma\limits_{i=1}^{2}r_{i,x}\cdot(m_{i}\cdot g + F_{i, x})}{\Sigma \limits_{i =1}^{2}(F_{i,x}+m_{i}\cdot g)} ,\frac{\Sigma\limits_{i=1}^{2}r_{i,y}\cdot(m_{i}\cdot g + F_{i, y})}{\Sigma \limits_{i =1}^{2}(F_{i,y}+m_{i}\cdot g)} \right]-\left(\frac{\Sigma\limits_{i=1}^{2}r_{i,x}\cdot m_{i}\cdot g}{\Sigma \limits_{i= 1}^{2} m_{i}\cdot g}, \frac{\Sigma\limits_{i=1}^{2}r_{i,y}\cdot m_{i}\cdot g}{\Sigma \limits_{i= 1}^{2} m_{i}\cdot g}\right)\) (1)
Where:
\(r_{i, x}\) - x-Coordinate of the i-th element of the system, in meters.\(r_{i,y}\) - y-Coordinate of the i-th element of the system, in meters. \(F_{i,x}\) - x-Component of the net force applied on the i-th element, in newtons.\(F_{i,y}\) - y-Component of the net force applied on the i-th element, in newtons. \(m_{i}\) - Mass of the i-th element, in kilograms.\(g\) - Gravitational acceleration, in meters per square second.If we know that \(\vec r_{1} = (0, 0)\,[m]\), \(\vec r_{2} = (1, 2)\,[m]\), \(\vec F_{1} = (0, 3)\,[N]\), \(\vec F_{2} = (-3, -2)\,[N]\), \(m_{1} = 0.50\,kg\), \(m_{2} = 1.50\,kg\) and \(g = 9.807\,\frac{kg}{s^{2}}\), then the displacement of the center of mass of the olive is:
Dynamic condition\(\vec{r} = \left[\frac{(0)\cdot (0.50)\cdot (9.807)+(0)\cdot (0) + (1)\cdot (1.50)\cdot (9.807) + (1)\cdot (-3)}{(0.50)\cdot (9.807) + 0 + (1.50)\cdot (9.807)+(-3)}, \frac{(0)\cdot (0.50)\cdot (9.807) + (0)\cdot (3) + (2)\cdot (1.50)\cdot (9.807) +(2) \cdot (-2)}{(0.50)\cdot (9.807) + (3)+(1.50)\cdot (9.807)+(-2)} \right]\)\(\vec r = (0,704, 1.233)\,[m]\)Static condition\(\vec{r}_{o} = \left[\frac{(0)\cdot (0.50)\cdot (9.807) + (1)\cdot (1.50)\cdot (9.807)}{(0.50)\cdot (9.807) + (1.50)\cdot (9.807)}, \frac{(0)\cdot (0.50)\cdot (9.807) + (2)\cdot (1.50)\cdot (9.807)}{(0.50)\cdot (9.807)+(1.50)\cdot (9.807)} \right]\)\(\vec r_{o} = \left(0.75, 1.50)\,[m]\)Displacement of the center of mass of the olive\(\overrightarrow{\Delta r} = \vec r - \vec r_{o}\)
\(\overrightarrow{\Delta r} = (0.704-0.75, 1.233-1.50)\,[m]\)
\(\overrightarrow{\Delta r} = (-0.046, -0.267)\,[m]\)
The estimated displacement of the center of mass of the olive is \(\overrightarrow{\Delta r} = -0.046\,\hat{i} -0.267\,\hat{j}\,[m]\). \(\blacksquare\)
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please help me asdrtyuio
Answers
Answer:
9. The Sun's Gravity
10. The core is the densest layer
Jupiter’s moon, Ganymede takes 7.15 Earth days to orbit Jupiter. Ganymede is measured to be 7.1 X 10-3 AU from Jupiter’s center. A second moon of Jupiter, Callisto, takes 16.69 Earth days to orbit Jupiter. How far away is Callisto from the center of Jupiter?
Answers
Answer:
0.0124 AU
Explanation:
Ganymede takes 7.15 Earth days to orbit Jupiter. Ganymede is measured to be 7.1 X 10⁻³ AU from Jupiter’s center.
We need to find how far away is Callisto from the center of Jupiter if a second moon of Jupiter, Callisto, takes 16.69 Earth days to orbit Jupiter. Let it is r₂. Using third law of Kepler.
\(T^2\propto r^3\)
i.e.
\((\dfrac{T_1}{T_2})^2=(\dfrac{r_1}{r_2})^3\\\\\dfrac{r_1}{r_2}=(\dfrac{T_1}{T_2})^{2/3}\\\\r_2=\dfrac{r_1}{(\dfrac{T_1}{T_2})^{2/3}}\\\\r_2=\dfrac{7.1\times 10^{-3}}{(\dfrac{7.15}{16.69})^{2/3}}\\\\r_2=0.0124\ \text{AU}\)
So, Callisto is 0.0124 AU from the center of the Jupiter.
6. The electric field has a magnitude of 3. 0 N/C at a distance of 60 cm from a point charge. What is the charge?
Answers
The electric field has a magnitude of 3. 0 N/C at a distance of 60 cm from a point charge. The point charge has a charge of 1.0 x 10⁻⁹ C.
The equation: yields the electric field.
E = k×q/r²
where k is the Coulomb's constant, which has a value of 8.99 x 10⁹ N*m2/C2, and E is the electric field, q is the charge, r is the distance from the point charge.
At a distance of 60 cm from the point charge, the electric field has a magnitude of 3.0 N/C. We obtain r = 0.6 m by converting the distance to metres. When we enter the values, we obtain:
3.0 = (8.99 x 10⁹) ×q / (0.6)²
By calculating q, we obtain:
q = (3.0 × (0.6)²) / 8.99 x 10⁹
q = 1.0 x 10⁻⁹ C
As a result, the point charge has a charge of 1.0 x 10⁻⁹ C.
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which tags have their own transmitter and a power source (typically a battery)?
Answers
RFID (Radio Frequency Identification) tags have their own transmitter and a power source, typically a battery.
RFID tags are small electronic devices that can be attached to or embedded in various objects, allowing them to be tracked and identified using radio waves.
These tags contain a microchip that stores information about the object they are attached to, and a transmitter that sends this information wirelessly to an RFID reader.
There are two types of RFID tags: active and passive.
Active RFID tags have their own power source (typically a battery) and can transmit information over longer distances than passive tags, which rely on the energy of the RFID reader to transmit their information.
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a shopper standing 3 m from a convex security mirror sees his image with a magnification of 0.26. what is the radius of curvature (in meters) of this mirror? your answer should be a number with two decimal places, do not include unit.
Answers
The radius of curvature (R) of the convex security mirror can be calculated by using the mirror formula is found to be 2.40 m.
We can use the mirror formula, which relates the object distance (p), image distance (q), and focal length (f) of a spherical mirror as follows:
1/f = 1/p + 1/q
For a convex mirror, the focal length is negative, so we can write:
1/f = -1/p + 1/q
We also know that the magnification (M) of an image formed by a spherical mirror is given by:
M = -q/p
where a negative sign indicates that the image is inverted.
Using the given information, we can write:
M = -q/p = 0.26 and p = 3 m
Substituting these values in the magnification equation, we get:
q = M × p = 0.26 × 3 m = 0.78 m
Now, using the mirror formula, we can solve for the focal length as follows:
1/f = -1/p + 1/q = -1/3 m + 1/0.78 m
Simplifying this expression, we get:
1/f = -0.447 + 1.282
1/f = 0.835
Therefore, the focal length of the convex mirror is:
f = 1/0.835 m ≈ 1.20 m
The radius of curvature (R) of the mirror is twice the focal length, so we have:
R = 2f ≈ 2 × 1.20 m ≈ 2.40 m
Therefore, the radius of curvature of the convex security mirror is approximately 2.40 meters.
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When a wave moves from one medium into another at an angle other than 90o the wave will change direction and continue to follow a new straight-line path. This is known as and is responsible for the of white light into its component colors when it passes through a prism.
Answers
Answer:
Mono-chromatic, Poly-chromatic. When a wave moves from one medium into another at an angle other than 90 degrees the wave will change direction and continue to follow a new straight-line path
Thank you
Which is true of high resistance wires?
A. The longer the wire the higher the resistance.
B. The shorter the wire the higher the resistance.
C. The longer the wire the lower the resistance.
Answers
How long will it take a person walking at 2.1 m/s to travel 13 m?
Answers
Answer:
I gonna give you the number so but you need to round 6.19047619048
Explanation:
This is a speed formula so you would use the formula speed=distance/timeYou need to rearrange it to time=distance/speedSo you need to divide 13m by 2.1 m/s2.Write the formula associating energy with power
3.Write the formula associating potential energy with height.
4. By substitution of the formula on question 3 for the formula in question 2, rewrite the formula for power.
(PLEASE PLEASE HELP ASAP ILL MARK BRAINLIEST)
Answers
Answer:
\( Power = \frac {mgh}{time} \)
Explanation:
2. Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
\( Power = \frac {Energy}{time} \)
3. Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
\( P.E = mgh\)
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
4. Substituting the equation in 3 into equation in 2 above, we have;
\( Power = \frac {mgh}{time} \)
Jimmy is cooking pasta in a pot of water on the stove. He uses a stopwatch to see how long the pasta takes to cook depending on the temperature of the water in the pot. What is the independent variable and why?
Answers
Answer:
stove
Explanation:
The stove is the independent variable in this question as it does not depend on anything like other variables such as pot, water, temperature and of cause pasta.
The pot depends on the stove, the water depends on the pot and stove, the pasta depends on the water and its temperature.
Cheers.
write short notes one effect of friction on efficiency of machine
Answers
Answer:
Friction reduces efficiency because when two surfaces slide past each other, friction resists their motion, and in real machines, some input work is always used to overcome friction.
Please give the brainliest.
A chemical reaction is the only way to an
A: Element
B: Pure Substance
C: Mixture
D: Solution
Answers
Answer:
B: Pure Substance
Explanation:
How much force (in Newtons) acts on a 1700 kg car going around a
80 m radius turn at a speed of 15 m/s?
a) 375
b) 4781
c) 1167
d) 319
Answers
Answer:
b) 4781 N
Explanation:
Because there is a redius do this question is talking about the acceleration force which= mv^2/r
so a=15^2/80=2.8125 m^2/s
so the force will be = m.a
F =1700×2.8125=4781.25 N
At what altitude does 1% of the mass of the atmosphere lies above and 99% of the mass lies below? Assume that the global mean surface pressure is about 1000hPa, and the scale height H is 8km. State your assumptions.
Answers
At 0.0804 km altitude the 1% of the mass of the atmosphere lies above and 99% of the mass lies below. Assumptions made are the global mean surface pressure of 1000 hPa is a representative value and the scale height is assumed to be constant throughout the entire atmosphere.
First, we need to calculate the pressure at the desired percentiles (1% and 99%) relative to the surface pressure.
For 1% of the mass lying above, we consider the pressure to be 1% of the surface pressure:
1% of 1000 hPa = 0.01 × 1000 hPa
= 10 hPa.
For 99% of the mass lying below, we consider the pressure to be 99% of the surface pressure:
99% of 1000 hPa = 0.99 × 1000 hPa
= 990 hPa.
Next, we use the exponential relationship between pressure and altitude:
P = P0 × exp(-z/H),
where P is the pressure at a given altitude, P0 is the surface pressure, z is the altitude, and H is the scale height.
To find the altitude z at which the pressure is equal to 10 hPa (1% of the surface pressure), we rearrange the equation:
10 hPa = 1000 hPa × exp(-z/H).
Taking the natural logarithm (ln) of both sides, we have:
ln(10 hPa / 1000 hPa) = -z / H.
ln(0.01) = -z / 8 km.
z = -8 km × ln(0.01).
Evaluating the expression:
z = -8 km × (-4.605)
= 36.84 km.
Therefore, 1% of the mass of the atmosphere lies above an altitude of approximately 36.84 km.
Similarly, to find the altitude z at which the pressure is equal to 990 hPa (99% of the surface pressure), we follow the same procedure:
990 hPa = 1000 hPa × exp(-z/H).
ln(990 hPa / 1000 hPa) = -z / H.
ln(0.99) = -z / 8 km.
z = -8 km × ln(0.99).
Evaluating the expression:
z = -8 km × (-0.01005)
= 0.0804 km.
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what are the two components of any vector
Answers
Answer:
U^U
Explanation:
Two-dimensional vectors have two components: an x vector and a y vector. Each of these vector components is a vector in the direction of one axis. The sum of the components of vectors is the original vector. Three-dimensional vectors have a z component as well.
1. What is the mass of an object moving at 13 m/s and having 3042 J of kinetic energy?
Answers
Answer: 36 Kg
Explanation:
Ke= 1/2MV^2
Plug in the kinectic energy (3042 J) and solve for M.
3042= 1/2 (M) (13^2)
M= 36 Kg
The BBB is a law-enforcement agency, so it can force a business to resolve a complaint of a customer. True or False.
Answers
Answer:
ITS FALSE
Explanation:
I just did the quest and I wrote true and I was wronged so put False.
an athlete at the gym holds a 3.5 kg steel ball in his hand. his arm is 70 cm long and has a mass of 4.0 kg . what is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor?
Answers
The magnitude of the torque about an athlete shoulder is 51.45N-m if he is holding steel ball in his hand.
We know that torque is defined as the cross product of distance of point from applied point to the force applied by the external source at that point, in simpler words
Torque=distance × Force
=>τ = r × F
Total mass hold by the athlete is = 3.5+4=7.5kg.
Now, we need to focus on the force acting on an athlete. So we are assuming an athlete is standing on the surface, so acceleration due to gravity have some role to exert some amount of force on athlete.
∴ Force=mg
=>F=7.5×9.8
=>F=73.5Kg-m/sec²
Now, distance of force from applied point is 70cm=0.7m
Therefore, Torque=0.7×73.5
=>Torque= 51.45N-m
Hence, value of Torque is 51.45N-m.
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Q1.
Figure 1 shows a car travelling at a constant speed on a straight, level road
Figure 1
6
Figure 2 shows a free body diagram for the car.
Figure 2
Normal contact force
Forward
force
Air resistance
Weight
(a) Explain how the free body diagram shows that the resultant force on the car is zero.
Answers
The lengths of the arrows that show the forces that act on the car are equal hence no net force acts on the car.
What is the free body diagram?The free body diagram is the image that shows us the forces that are acting on a body. We know that the greater the magnitude of the forces that act on a body, the longer the line that shows the force that acts on a body, the greater the magnitude of the force.
Now we have the free body image of the car. If we look at the forces that act in the vertical direction which are the weight and the normal reaction we can see that those forces are balanced since the arrows are of equal length. The forces that acts in the horizontal direction, forward force and air resistance also have lines of equal length which show that the forces are balanced.
Since the lengths of the arrows that show the forces that act on the car are equal in length, the forces are balanced and there is no net force that acts on the car.
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A car of weight 300N moved through a distance of 10m when pushed by 3 students
a. Calculate the work done by the three students
b. Explain the energy transfer involved
Answers
The work done by the three students is 3,000 J.
The energy transferred in the process is 3,000 J.
What is work done?Work done is the product of force and distance moved by the object.W = Fd
The work done by the three students is calculated as follows;
W = 300 x 10
W = 3,000 J
What is energy transfer?This is means by which energy is converted from one form to another.The energy transferred in the process is determined by work energy theorem.
E = W
E = 3,000 J
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