ap physics 1 orbital velocity frq and what happen if mass of satellite increases and what happens if the radius increases

To find the maximum speed, we need to equate the force due to gravity with the drag force which is due to the viscosity of air at maximum speed. The force due to gravity on the particle is given by:

\(F_g = m*g\)

Where m is the mass of the particle and g is the acceleration due to gravity.

Given: Density of Styrofoam \(= 1 lbm/ft^3\)

Diameter of Styrofoam \(= d = 0.3 mm = 0.000984252 ft\)

The mass of the particle can be calculated from its volume:

m = ρV =\((1 lbm/ft^3)(4/3)\pi(d/2)^3\)

where ρ is the density of the particle, V is its volume, and d is its diameter.

Substituting the given values, we get:

m = \((1 lbm/ft^3)(4/3)\pi(0.000984252/2 ft)^3\)

m = 499.17 × 10^-12 lbm

The force due to gravity on the particle is then:

F_g = mg = \((499.17*10^{-12} lbm)(32.2 ft/s^2) = 1.6*10^{-8} lbf\)

Drag = \(F_D\) = 3πμVd

The viscosity of air = μ

At maximum speed, the drag force is equal and opposite to the force due to gravity:

F_D = 3πμV_maxd = F_g

Solving for V, we get:

V_max = F_g/(3πμd)

           = \((1.6*10^{-8} lbf)/(3\pi1.8*10^{-5} lbm/ft.s*(0.000984252 ft)) = 0.0958 ft/s\)

The time it takes to reach 95% of this speed is given by the formula,

\(t = 0.95 Vmax / g\)

Where g is the acceleration due to gravity

⇒ \(t = 0.95 * 0.0958 ft/s / 32.2 ft/s^2= 2.8*10^{-3} s\)

To plot the speed as a function of time, we can use the equation

V = (F_g/3πμd)(1 - e^(-3πμdt/m))

We can use a spreadsheet program or a graphing calculator to create the plot.

Hence the maximum speed of the Styrofoam particle is \(0.0958 ft/s\).

And the time taken to reach 95% of maximum speed is \(2.8*10^{-3} s\).

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The first hypothesis put out by the researchers holds that the fish's blindness indirectly confers some form of evolutionary advantage.

Why can't the Mexican tetra see?

The loss of eyes is largely caused by cellular deterioration in the eye lens, according to experiments . Theoretically, the emergence of these eyeless fish was caused by this process in combination with natural selection over many generations.

Regressive evolution can be shown in cave fishes. This kind of evolution involves the loss of a property within a species. That characteristic is vision in cave fishes.

In conclusion, a finding supporting the theory that "blindness affords the fish some evolutionary advantage, although not directly" may be a greater fitness in fish relatives.

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The electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.

Electrical power is the rate at which electrical work is done.

The unit of electrical power is Watts.

The experiment will require a 24V Battery, a Lamp marked 24V, 100 W, a key, wires, a rheostat, a voltmeter and an ammeter.

The circuit is completed and the rheostat is adjusted to provide until the voltmeter reads 24V.

The ammeter reading is taken as well.

When the voltmeter reading is 24V, it can be seen that' the ammeter reading for current is approximately 4.2 A.

Calculating, the power of the lamp:

Power = 24 × 4.2 = 100 W

Therefore, the electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.

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Nuisance static charges are more likely to occur when the air is dry.

When the air is dry, it is not able to hold a sufficient amount of moisture or humidity. When the moisture content of the air is low, the air has a low electrical conductivity, which increases the likelihood of static charges.Static electricity can be created by the rubbing of two objects. When these objects are separated after rubbing, they are left with a static electric charge. The strength of the electric charge is determined by the materials used to create the two objects. Some materials are better at holding static charges than others.

Dry air only exacerbates the situation. Static charges can be a nuisance for a variety of reasons. They can cause shocks, interfere with electronic devices, and can even cause damage to sensitive equipment. In order to reduce the occurrence of static charges, it is important to ensure that the air in your environment is sufficiently humid. This can be achieved by using a humidifier or by simply placing bowls of water around the room. Additionally, anti-static products, such as sprays and mats, can be used to reduce the occurrence of static charges.

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(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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A resistor can get hot when a current flows through it, and the unit of resistance is the Ohm.

What are some properties of electrical current?

When an electric current flows through a resistor, it can generate heat. This phenomenon occurs due to the resistance offered by the resistor to the flow of electrons. When the electrons pass through the resistor, they collide with atoms and molecules, transferring their kinetic energy and resulting in an increase in temperature. This heating effect is commonly observed in various electronic devices, such as heaters or incandescent light bulbs.

Additionally, the unit of resistance in the International System of Units (SI) is the Ohm, represented by the symbol Ω. Resistance is a fundamental property of electrical components, describing their ability to impede the flow of electric current. It is calculated by dividing the voltage across a component by the current passing through it, according to Ohm's law.

Learn more about electrical current, resistance, and Ohm's law to deepen your understanding of these essential concepts in electrical engineering and physics.

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The horizontal distance at which the parcel should be dropped away from the island in order to be landed there is 697.5 m.

The horizontal distance travelled by the plane is calculated as follows;

X = vt

where;

h = ut + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

h = ¹/₂gt²

2h = gt²

t = √(2h/g)

t = √(2 x 100 / 9.8)

t = 4.5 seconds

Horizontal distance = 155 m/s x 4.5 s

Horizontal distance = 697.5 m

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Answer:

The length of time between each transit is the planet's "orbital period", or the length of a year on that particular planet. Not all planets have years as long as a year on the Earth! Some planets discovered by Kepler orbit around their stars so quickly that their years only last about four hours!

I hope it helps.

Answer:

Explanation:

Lighter elements are fused into elements more massive than iron in the core of massive stars during stellar nucleosynthesis, specifically during supernova explosions.

Lighter elements are fused into elements more massive than iron through a process called nucleosynthesis. This process occurs in the extreme conditions found within the cores of massive stars during their late stages of evolution. The fusion reactions that lead to the formation of heavier elements require extremely high temperatures and pressures.

In the core of a massive star, hydrogen is fused into helium through the process of nuclear fusion. As the star evolves, the core becomes denser and hotter, allowing for the fusion of helium into elements like carbon and oxygen. This continues with successive fusion reactions, where heavier elements are synthesized.

However, the fusion process reaches a limit when it comes to iron. Iron has the highest binding energy per nucleon, making it energetically unfavorable to fuse iron nuclei further. Instead, in the cores of massive stars, when iron begins to accumulate, the fusion reactions cease, and the star undergoes a catastrophic event known as a supernova.

During a supernova explosion, the tremendous energy released enables the synthesis of elements more massive than iron through a rapid process called r-process nucleosynthesis. Neutrons are rapidly absorbed by atomic nuclei, creating unstable, neutron-rich isotopes that undergo radioactive decay, leading to the formation of elements higher on the periodic table.

In summary, the fusion of lighter elements into elements more massive than iron primarily occurs in the cores of massive stars and during the explosive events of supernovae.

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Answer:

Scientific theories attempt to explain how events occur in the natural world.

Answer:

The answer is option  A. Scientific theories attempt to explain an entire group of related phenomena.

Explanation:

I got it right on the test

Hope it helps!

NC means North Carolina.

Answer:

The temperatures will increase.

Explanation:

What will happen is that the temperature will increase. This is because, in wind direction and weather forecasting, a wind that shifts from the south means that warmer air/temperatures are approaching whereas a wind shift from the north implies that cooler air/temperatures are approaching.

Answer:

1.55

Explanation:

that it is the standard refractive index.

(a) The speed of the ball at the lowest point is 1.97 m/s.

(b) The tension in the rod at the lowest point is 1.29 N since the ball is weightless at that instant.

(c) The angle at which the tension in the rod equals the weight of the ball is 81.4 degrees.

(d) The answer to (c) remains the same if the mass of the ball is increased.

(a) To find the speed of the ball at its lowest point, we can use the conservation of energy. At the highest point, the ball has potential energy equal to mgh, where m is the mass of the ball, g is the acceleration due to gravity (9.81 m/s²), and h is the height of the ball above its lowest point. At the lowest point, all of this potential energy is converted into kinetic energy, so we can set mgh = (1/2)mv², where v is the speed of the ball at its lowest point.

Solving for v, we get:

mgh = (1/2)mv²

v² = 2gh

v = √(2gh)

Plugging in the values, we get:

v = √(2 x 9.81 x 0.62) = 1.97 m/s

Therefore, the speed of the ball at its lowest point is 1.97 m/s.

(b) To find the tension in the rod at the lowest point, we can use Newton's second law. At the lowest point, the ball is moving in a circular path with a constant speed, so the net force on the ball is the centripetal force:

F_net = mv²/r

where r is the length of the rod. The only force acting on the ball at the lowest point is tension in the rod, so we can write:

T - mg = mv²/r

Solving for T, we get:

T = mv²/r + mg

Plugging in the values, we get:

T = (0.092 kg) x (1.97 m/s)² / 0.62 m + (0.092 kg) x (9.81 m/²) = 1.29 N

Therefore, the tension in the rod at the lowest point is 1.29 N.

(c) To find the angle at which the tension in the rod equals the weight of the ball, we can use trigonometry. Let θ be the angle between the rod and the vertical. At this angle, the tension in the rod is equal to the weight of the ball, so we can write:

T = mg sin(θ)

where m is the mass of the ball and g is the acceleration due to gravity.

Solving for θ, we get:

θ = \(sin^{(-1)\)T/mg)

Plugging in the values, we get:

θ = \(sin^{(-1)\)(1.29 N / (0.092 kg x 9.81 m/s²)) = 81.4 degrees

Therefore, the angle at which the tension in the rod equals the weight of the ball is 81.4 degrees.

(d) If the mass of the ball is increased, the answer to (c) will remain the same. This is because the tension in the rod and the weight of the ball both increase by the same factor, so their ratio remains the same.

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Answer: 7 - Transpiration, 6 - Infiltration, 5 - Runoff, 4 - Evaporation, 3 - Precipitation, 2 - Condensation, 1 - Sublimation,

Explanation:

Answer:

With no water displacement it's 2000m.

Explanation:

400 × 500

4 × 5

Add the zeros

Answer:

The answer is 2000m

Explanation:

I hope it helps

The process of charging a conductor by bringing it near another charged object and then grounding the conductor is called Induction. The correct option is C.

The process described, in which a conductor is charged by bringing it near another charged object and then grounding the conductor, is known as induction. Induction involves the redistribution of charges within the conductor without direct contact between the two objects.

Here's how the process works: When a charged object is brought close to the conductor, the charges in the conductor are rearranged.

This occurs due to the electric field of the charged object influencing the distribution of charges within the conductor. However, the conductor itself remains electrically neutral overall.

If the conductor is then grounded, allowing it to make contact with the Earth or a large reservoir of charge, any excess charges in the conductor are neutralized or redistributed, resulting in the conductor becoming charged with the opposite polarity to that of the inducing object.

Therefore, the correct term for this process is c, induction.

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Answer:modeled as an electromagnetic wave. In this model, a changing electric field creates a changing magnetic field.

Explanation:

The speed of the puck after the force is applied for 0.050 s is approximately 0.75 m/s to the left. Note that the negative sign indicates the direction

To find the speed of the hockey puck after the applied force, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:

F_net = m * a

In this case, the net force acting on the puck is the applied force of 12.0 N directed to the left. The mass of the puck is 0.160 kg. We need to calculate the acceleration of the puck.

The acceleration can be calculated using the equation:

a = F_net / m

a = 12.0 N / 0.160 kg

a = 75 m/s²

Since the initial speed of the puck is to the right, and the force applied is to the left, the net force acts to oppose the motion. Therefore, the acceleration is negative (-75 m/s²).

To find the final speed of the puck, we can use the equation:

v_final = v_initial + a * t

where:

v_final is the final speed,

v_initial is the initial speed,

a is the acceleration,

t is the time.

Plugging in the given values:

v_final = 3.00 m/s + (-75 m/s²) * 0.050 s

v_final = 3.00 m/s - 3.75 m/s

v_final ≈ -0.75 m/s

The speed of the puck after the force is applied for 0.050 s is approximately 0.75 m/s to the left. Note that the negative sign indicates the direction, which in this case is opposite to the initial motion of the puck.

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Answer:

get it done for free on www.brainly.com

Explanation:

Answer:

I will give you $0

Explanation:

I have hardly any money and I don't feel like giving you any.

You can do my work for $0

Thanks! :)

Five activities that will see the application of relation between pressure and area include:

When the handle of a pump is squeezed, the pressure inside the tire increases, causing the tire to inflate. By adjusting the size of the opening in the showerhead, the water pressure can be increased or decreased.

When a car is placed on a hydraulic lift, the pressure in the lift's cylinder is increased, causing the lift to raise the car off the ground. When a hydraulic jack is used to lift a heavy object, the pressure in the jack's cylinder is increased, causing the jack to lift the object.

A blood pressure cuff uses pressure to measure the blood pressure in a person's artery. The pressure in the cuff is increased until it is high enough to stop the flow of blood, and then the pressure is slowly released. The pressure readings at various points during this process can be used to determine a person's blood pressure.

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Each coulomb of charge passing through a V battery is given an energy of V joules. The energy given to each coulomb of charge passing through a battery is determined by the voltage (V) of the battery.

Voltage represents the electrical potential difference between the positive and negative terminals of the battery, and it is measured in volts (V).

The relationship between energy (E), charge (Q), and voltage (V) can be described by the equation:

E = Q * V

In this case, as we are considering the energy given to each coulomb of charge, the charge (Q) is 1 coulomb. Therefore, the energy (E) given to each coulomb of charge passing through a V battery can be simplified to:

E = 1 coulomb * V

Thus, each coulomb of charge passing through a V battery is given an energy of V joules. This relationship shows the fundamental connection between electrical energy and voltage in a circuit.

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The tension does no (zero) work

F· S = W

Since the tension is perpendicular to the direction of motion, and there is no change in S the work done is zero.

The force is  1.1 * 10^-32 N

Coulomb's law is a fundamental law in physics that describes the electrostatic interaction between charged particles. It states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, Coulomb's law can be written as:

F = k * q1 * q2 / r^2

where F is the electrostatic force between the charges q1 and q2, r is the distance between the charges, and k is the Coulomb constant, which is approximately equal to 9 x 10^9 N * m^2 / C^2. The force F is a vector quantity, meaning that it has both magnitude and direction, and is directed along the line joining the two charges.

We have that;

F = Kq1q2/r^2

F = 9 * 10^9 * 1.6*10^ -19 * 3.2*10^ -19/(0.02)^2

F = 1.1 * 10^-32 N

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Answer:

cannot do diagrams on here sorry :)

A. Controlled Variable.

I hope this helps!

Answer:

the answer is different

Explanation:

i took the test

Answer:

Zero

Explanation:

When it reaches max height, it stops and begins to fall back down....at this point the velocity = 0